(05.01 MC)

The table and the graph each show a different relationship between the same two variables, x and y:

A table with two columns and 5 rows is shown. The column head for the left column is x, and the column head for the right column is y. The row entries in the table are 3,210 and 4,280 and 5,350 and 6,420. On the right of this table is a graph. The x axis values are from 0 to 10 in increments of 2 for each grid line. The y axis values on the graph are from 0 to 550 in increments of 110 for each grid line. A line passing through the ordered pairs 2, 110 and 4, 220 and 6, 330 and 8, 440 is drawn.

How much more would the value of y be in the table than its value on the graph when x = 11?
100
165
395
440

Answer with explanation:

It is given that, coordinates of Isosceles trapezoid J K L M are J(-b, c), K(b,c), L(a,0), and M(-a,0).

To Prove: The diagonals of an isosceles trapezoid are congruent.

Proof:

  Distance formula , that is distance between two points in x y plane is given by

       [tex]=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]

Where, [tex](x_{1},y_{1}),(x_{2},y_{2})}[/tex] are coordinates of two points in the plane.

Length of Diagonal J L

                  [tex]=\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}[/tex]

Length of Diagonal K M

           [tex]=\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}[/tex]

So, we can see that,

  J L = KM  [tex]=\sqrt{(a+b)^2+(c)^2}[/tex]

Hence,The diagonals of an isosceles trapezoid are congruent.

So ,

  [tex]KM=\sqrt{(a+b)^2+c^2}[/tex]

Option C

Answer:

Area will increase by 4 times

Step-by-step explanation:

Given: A rectangle has a base of 3 inches and a height of 9 inches.  

To find: If the dimensions are doubled, what will happen to the area of the rectangle?

Solution:

It is given that a rectangle has a base of 3 inches and a height of 9 inches.

Now, to find if the dimensions are doubled what will happen to the area, first we need to find the original area.

Original area of rectangle, when base is 3 inches and height 9 inches is

[tex]9\times3=27[/tex] square inches

Now, when dimensions are doubled , the base becomes 6 inches and height becomes 18 inches

So, new area becomes [tex]6\times18=108[/tex] square inches.

Now,

[tex]\frac{\text{new area}}{\text{original area} }=\frac{108}{27}[/tex]

[tex]\implies\frac{\text{new area}}{\text{original area} }=\frac{4}{1}[/tex]

Hence, the area will increase by 4 times.

Answer:

Step-by-step explanation:

The difference between 14 and 0 is 14, and the difference between 0 and -10 is 10. 14+10=24 for total change. For the average over 8 hours, we have 24/8=3 degrees

Answer:

60 miles.

Step-by-step explanation:

We have been given that the scale map is 0.5 inch : 20 miles. On the map, the distance between two cities is 1.5 inches. We are asked to find the actual distance between the two cities.

We will use proportions to solve for the actual distance between both cities as:

[tex]\frac{\text{Actual distance}}{\text{Map distance}}=\frac{20\text{ miles}}{\text{0.5 inch}}[/tex]

[tex]\frac{\text{Actual distance}}{\text{1.5 inches}}=\frac{20\text{ miles}}{\text{0.5 inch}}[/tex]

[tex]\frac{\text{Actual distance}}{\text{1.5 inches}}*\text{1.5 inches}=\frac{20\text{ miles}}{\text{0.5 inch}}*\text{1.5 inches}[/tex]

[tex]\text{Actual distance}=20\text{ miles}*3[/tex]

[tex]\text{Actual distance}=60\text{ miles}[/tex]

Therefore, the actual distance between both cities is 60 miles.

The test result is not significant at α = 0.05 or α = 0.01.

For a hypothesis test of H0:p1 − p2 = 0 against the alternative Ha:p1 − p2 ≠ 0, the test statistic is found to be 2.2. Given the information provided, the result is not significant at either α = 0.05 or α = 0.01. This conclusion is drawn based on the p-value and the 95% confidence interval.

On compared the test statistic to critical values for α = 0.05 and α = 0.01. Since the test statistic falls within the critical region for α = 0.05 but not for α = 0.01, we concluded that the result is significant at α = 0.05 but not at α = 0.01. The correct options B.

To determine the significance of the test statistic at different levels of significance, we need to compare it to critical values associated with the chosen alpha levels.

Given that the test statistic is 2.2, we need to refer to the critical values of the test statistic for a two-tailed test at α = 0.05 and α = 0.01. These critical values are typically obtained from statistical tables or software.

Let's assume the critical value at α = 0.05 is [tex]\( z_{\alpha/2} = \pm 1.96 \)[/tex]and the critical value at α = 0.01 is [tex]\( z_{\alpha/2} = \pm 2.58 \)[/tex](for a standard normal distribution).

If the test statistic falls within the range defined by these critical values, we can conclude that the result is significant at the corresponding alpha level. Otherwise, the result is not significant.

Since the test statistic of 2.2 falls between the critical values of [tex]\( \pm 1.96 \)[/tex] for α = 0.05 but outside the critical values of [tex]\( \pm 2.58 \)[/tex] for α = 0.01, we can conclude that:

The result is significant at α = 0.05 but not at α = 0.01.

Final answer: The result is significant at α = 0.05 but not at α = 0.01.

We compared the test statistic to critical values for α = 0.05 and α = 0.01. Since the test statistic falls within the critical region for α = 0.05 but not for α = 0.01, we concluded that the result is significant at α = 0.05 but not at α = 0.01. This interpretation aligns with standard hypothesis testing procedures.

Complete question

For a hypothesis test of H0:p1 − p2 = 0 against the alternative Ha:p1 − p2 ≠ 0, the test statistic is found to be 2.2. Which of the following statements can you make about this finding?

A)The result is significant at both α = 0.05 and α = 0.01.

B)The result is significant at α = 0.05 but not at α = 0.01.

C)The result is significant at α = 0.01 but not at α = 0.05.

D)The result is not significant at either α = 0.05 or α = 0.01.

E)The result is inconclusive because we don't know the value of p.

The largest number of goody bags that Kara can make are [tex]18[/tex] .

Highest or greatest Common Factor is the largest common factor that all the numbers have in common.

We have,

Number of Lollipops [tex]=90[/tex]

Number of chocolate bars [tex]=36[/tex]

Number of gumballs [tex]=72[/tex]

So,

To find the number of bags;

First find out the Highest Common Factor of [tex]90,36,72[/tex];

[tex]90=2*3*3*5[/tex]

[tex]36=2*2*3*3[/tex]

[tex]72=2*2*2*3*3[/tex]

So, from the factors of all numbers we have,

Highest Common Factor [tex]=18[/tex]

Now,

Lollipops [tex]=\frac{90}{18} =5[/tex]

Chocolate bars [tex]=\frac{36}{18} =2[/tex]

Gumballs [tex]=\frac{72}{18} =4[/tex]

So, the largest number of goody bags that Kara can make are [tex]18[/tex] so that each goody bag has [tex]5[/tex] number of lollipops, [tex]2[/tex] number of chocolate bars, and [tex]4[/tex] number of gumballs.

Hence, we can say that the largest number of goody bags that Kara can make are [tex]18[/tex] .

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Answer with Step-by-step explanation:

We are given an inequality:

x+2y≤4

We have to determine its correct graph

(since, 0+2×4=8 which is not less than or equal to 4)

Hence, A and C are not the graph of this inequality

Hence, D is also not the graph of this inequality

Hence, correct graph of x+2y≤4 is:

Graph B

Answer:

[tex]x=\frac{7}{3} , \frac{7}{2}[/tex]

Step-by-step explanation:

[tex]6= \frac{35}{x} - \frac{49}{x^2}[/tex]

Now we need to solve for x

To get 'x' alone we make the denominators same

LCD = x^2

WE multiply the whole equation by x^2

[tex]6x^2 = 35x - 49[/tex]

Now we the equation =0, move all the terms to left hand side

[tex]6x^2-35x + 49=0[/tex]

Now we apply quadratic formula to solve for x

a= 6, b= -35 , c= 49

[tex]x= \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x= \frac{-(-35)+-\sqrt{(-35)^2-4(6)(49)}}{2*6}[/tex]

[tex]x= \frac{35+-\sqrt{49}}{12}[/tex]

[tex]x= \frac{35+-7}{12}[/tex]

Now frame two equations , one with +  and another with -

[tex]x= \frac{35+7}{12}[/tex]                                  [tex]x= \frac{35-7}{12}[/tex]

[tex]x= \frac{42}{12}[/tex]                                       [tex]x= \frac{28}{12}[/tex]  

[tex]x= \frac{7}{2}[/tex]                                           [tex]x= \frac{7}{3}[/tex]  

So value of x= {7/3, 7/2}

Answer:- The area of base is 52900 square meters. The volume is 2654000 cubic meters.

Explanation:-

Base length of right pyramid (square) a =230m

Height of right pyramid = 150m

Area of base of right pyramid[tex]=a^2=(230)^2=52900\ m^2[/tex]

Volume of right pyramid with square base[tex]=\frac{1}{3}a^2h\\=\frac{1}{3}\times52900\times150=2645000\ m^3[/tex]

Thus, the area of base is 52900 square meters and the volume is 2654000 cubic meters.

The area of the base of the pyramid is 52900 m²

The volume of the square base pyramid of Giza is 2645000 m³

The pyramid is a square base pyramid. Therefore,

where

B = base area

h = height

h = 150 m

Therefore,

area of the base = l²

where

l = length of side

area of the base = 230² = 52900 m²

Volume = 1  / 3 × 52900 × 150

volume = 7935000 / 3

volume = 2645000 m³

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The area of smaller triangle is 59 square feet

Two triangles are similar if they have the same ratio of corresponding sides and equal pair of corresponding angles.

The formula for the area of triangle is

[tex]Area = \frac{1}{2} \times base \times \ height[/tex]

According to the given question.

The area of the larger triangle is 105 square feet.

And the one side of the larger triangle and the smaller traingle is 16 and 12 feet respectively.

Suppose the height of thesmaller triangle be x feet and the height of the larger triangle be y feet.

Since, the corresponding edges of similar triangles are proportional.

Therefore,

[tex]\frac{y}{x} = \frac{16}{12}[/tex]

[tex]\implies y = \frac{4}{3} x[/tex]

Also, the area of larger triangle is 105 square feet.

[tex]\implies \frac{1}{2} \times \frac{4}{3} x \times 16 = 105[/tex]

The above euqtaion can be written as

[tex]\implies \frac{1}{2}\times \frac{4}{3} x \times \frac{4}{3} \times 12 = 105[/tex]

[tex]\implies \frac{1}{2} \times (\frac{4}{3} )^{2} \times x \times 12 = 105[/tex]

[tex]\implies \frac{1}{2} \times x \times 12 = 105 \times \frac{9}{16}[/tex]

[tex]\implies \frac{1}{2} \times x \times 12 = 59[/tex]

⇒ Area of smaller triangle  = 59 square feet

Hence, the area of smaller triangle is 59 square feet.

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Answer:

There are two solutions [tex]x=\frac{5}{2},-\frac{5}{2}[/tex]

Step-by-step explanation:

Given : Equation [tex]16x^2=100[/tex]

To find : How many solutions will there be to the following equation?      

Solution :

Equation [tex]16x^2=100[/tex]

Solve the equation,

Divide by 16 both side,

[tex]\frac{16x^2}{16}=\frac{100}{16}[/tex]

[tex]x^2=\frac{100}{16}[/tex]

Taking root both side,

[tex]x=\sqrt{\frac{100}{16}}[/tex]

[tex]x=\sqrt{\frac{10^2}{4^2}}[/tex]

[tex]x=\pm\frac{10}{4}}[/tex]

[tex]x=\pm\frac{5}{2}}[/tex]

Therefore, There are two solutions [tex]x=\frac{5}{2},-\frac{5}{2}[/tex]

The length of the third side of the triangle would be 106.5 units approx.

A triangle is a two - dimensional figure with three sides and three angles.

The sum of the angles of the triangle is equal to 180 degrees.

∠A + ∠B + ∠C = 180°

Given is that in triangle ABC, angle B = 30°, a = 210, and b = 164.

The cosine formula is given as follows -

c² = a² + b² + 2abcos(α)

c = √(a² + b² + 2abcos(α))

c = √(210)² + (164)² + 2(210)(164)cos(30°)

c = 106.5 units approx.

Therefore, the length of the third side of the triangle would be 106.5 units approx.

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Answer:

Option a) They are adjacent angles

Step-by-step explanation:

Given is a picture of a graph with angles 1 to 6 around it.

Out of these angle 2 and 5 are right angles.

1 and 2 are adjacent to each other.

They are not complementary because 1+2 not equals 90

They are neither supplementary since sum does not equal 180

They cannot be vertical because they are not formed by intersection of two lines.

Hence only option a is right

Option a) They are adjacent angles

the equivalent equation of the equation 4s=t+2 is s = [tex]\frac{t+2}{4}[/tex] .

Equivalent equations are algebraic equations that have identical solutions or roots. Adding or subtracting the same number or expression to both sides of an equation produces an equivalent equation. Multiplying or dividing both sides of an equation by the same non-zero number produces an equivalent equation.

According to the question

The equation  

4s=t+2

Now,

its Equivalent equations  is  :

Dividing equation by 4 both side  

i.e

s = [tex]\frac{t+2}{4}[/tex]

Hence , the equivalent equation of the equation is s = [tex]\frac{t+2}{4}[/tex] .

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The product of (x-2i)²=x²-4+i4x

The product or multiplication of two complex numbers is also a complex number. The formula for multiplying complex numbers is: (a + ib) (c + id) = (ac - bd) + i(ad + bc).

Given here  (x-2i)² =(x-2i) (x-2i)

                              =x²-4+i4x

Hence, the product is x²-4+i4x

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