Mathematics Middle School

1. How many different sets of 8 songs are possible for Janine's play list? Assume that the
order of the songs doesn't matter.

Answers

Answer 1

Answer:

40320

Step-by-step explanation:

the first song on the list could be 8 possible songs;

and the second song on the list could be 7 possible songs after the first one was set;

the third song on the list could be 6 possible songs after the first and second songs were set;;

the fourth song on the list could be 5 possible songs after the first ,second and third songs were set;;

the fifth song on the list could be 4 possible songs after four songs were set;

the sixth song on the list could be 3 possible songs after five songs were set;

the seventh song on the list could be 2 possible songs after six songs were set;

the eighth song on the list could be 1 possible songs after seven songs were set.

so THERE ARE 8X7X6X5X4X3X2X1 DIFFERENT SETS

Answer 2

Final answer:

To calculate the number of combinations, we use the combination formula in combinatorics. However, the total number of songs available is required to provide a specific answer.

Explanation:

To determine the number of different sets of 8 songs possible for Janine's play list, we have to use the combination formula of combinatorics. Combinatorics is a branch of mathematics concerning the study of countable or finite discrete structures. The combination is a selection of items where order does not matter. The formula for combination is: C(n, r) = n! / [r!(n-r)!]

where:

'n' is the total number of items (in this case, we don't know the total number of songs available),'r' is the number of items to choose (in this case, 8 songs),'!' denotes a factorial, meaning the product of an integer and all the integers below it, e.g. 4! = 4*3*2*1.

Therefore, to answer the question, we would need to know the total number of songs available to Janine. Once we know that, we can substitute that number for 'n', and use the formula to calculate.

Learn more about Combinations here:

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Related Questions

2 1/4(4x-1)=1 3/5(1+4x)?? I need help with this problem. Thanks!!

Answers

Solving [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex] we get [tex]x=\frac{77}{52}[/tex]

Step-by-step explanation:

We need to solve the problem: [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex]

Solving:

[tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)\\\frac{9}{4}(4x-1)=\frac{8}{5}(1+4x)\\9x-\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}[/tex]

Add 9/4 on both sides:

[tex]9x-\frac{9}{4}+\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}+\frac{9}{4}[/tex]

[tex]9x=\frac{8}{5}+\frac{9}{4}+\frac{32x}{5}\\9x-\frac{32x}{5}=\frac{8}{5}+\frac{9}{4}\\\frac{9x*5-32x}{5}=\frac{8*4+9*5}{20}\\\frac{45x-32x}{5}=\frac{32+45}{20}\\\frac{13x}{5}=\frac{77}{20}\\x=\frac{77}{20}\times \frac{5}{13}\\x=\frac{77}{4*13}\\x=\frac{77}{52}[/tex]

So, Solving [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex] we get [tex]x=\frac{77}{52}[/tex]

Keywords: Solving Fractions

Learn more about Solving Fractions at:

brainly.com/question/2456302 brainly.com/question/4390083 brainly.com/question/2456302

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Use the row of numbers shown below to generate 12 random numbers between 01 and 99.
25060 12315 86244 97348 36173 32710 80033 16160

Answers

Answer:

Below is the complete answer.

Step-by-step explanation:

Given the row of numbers

25060 12315 86244 97348 36173 32710 80033 16160

As we have to generate 12 random numbers between 01 and 99 from the above row of numbers.

Minimum Value = 01

Maximum Value = 99

25060

Lets take 25060 as seed in the calculator as

25060 ➡️ rand

[tex]randInt(1,99,12)[/tex]