1. How much time will it take a car travelling at 88 km/hr (55 mi/hr) to travel 500km? Show work for credit and include final units

Answers

Answer 1

divide miles by speed to get the time

500km/88km/hr = 5.68 hours

Answer 2

Answer : The time taken by the car will be 5.68 hours.

Explanation :

Speed : It is defined as the distance traveled by the object per unit time.

Formula used :

[tex]Speed=\frac{Distance}{Time}[/tex]

Given:

Speed of car = 88 km/hr

Distance covered = 500 km

Now put all the given values in the above formula, we get:

[tex]88km/hr=\frac{500km}{Time}[/tex]

[tex]Time=\frac{500km}{88km/hr}[/tex]

[tex]Time=5.68hr[/tex]

Therefore, the time taken by the car will be 5.68 hours.


Related Questions

A man swims at a speed of 0.4 m/s. How long will it take him to cross a pool of length 50 m?

Answers

Distance = speed * time, then time = distance / speed.

time = 50 / 0.4 = 125 s

A man stands on a scale in an elevator as shown here. the force of his weight when the elevator is still is fg downward. suppose the elevator's acceleration downward is 1/4 g. the weight of the man, fs, is what

Answers

When the elevator moves downward, the man weighs less because of the inertia.
Force of Weight:Fg=m×g
Fs=m×g-m×1/4g=m×(g-1/4g)=m×3/4g
If He Went Up you would have to add 1/4g

The weight of the man in the  elevator is [tex]\frac{3}{4} f_g[/tex].

What is weight?

Weight of a body is the force with which the earth attracts it. due to having both magnitude and direction, Weight is a vector quantity. Si unit of weight is Newton.

Given parameter:

The force of his weight in still elevator is = [tex]f_g[/tex]

And, the elevator's acceleration downward is 1/4 g.

Let, the mass of the man is = m.

So, his weight in still elevator = [tex]f_g[/tex] = mg.

Where, g = acceleration due to the gravity.

When the elevator moves downward, the experienced weight of the man will change and magnitude of it will be equal to the difference of his weight in still elevator and pseudo force due to the elevator's acceleration downward is 1/4 g   .

The pseudo force due to the elevator's acceleration = mass × acceleration

= m× 1/4 g

= 1/4 mg

Fs=m×g-m×1/4g=m×(g-1/4g)=m×3/4g

Now, the weight of the man experienced during the elevator's acceleration downward is 1/4 g is, [tex]f_s[/tex] = [tex]f_g -\frac{1}{4}[/tex]mg = 3/4 mg = [tex]\frac{3}{4}[/tex] [tex]f_g[/tex].

Hence, the net weight of the man is  [tex]\frac{3}{4}[/tex] [tex]f_g[/tex].

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a speeding car traveling north at 80mph passes the tramway intersection when the police begin pursuit. The police start 6 miles south of tramway traveling at 100mph. How many miles north of tramway will they be when they catch up with the speeding car?

Answers

Refer to the diagram shown below.

Define
x =  distance, miles, that the speeding car travels before the police catch up.
t = time, hrs, before the police catch up.
Then
(80 m/h)*(t h) = (x mi)
80t = x                 (1)

(100 mi/h)*(t h) = (x+6 mi)
100t = x + 6          (2)

Subtract (1) from (2).
100t - 80t = x+6 - x
20t = 6
t = 6/20 = 0.3 h

From (1), obtain
x = 80*0.3 = 24 mi.

Answer:  24 miles

At what speed do a bicycle and its rider, with a combined mass of 100 kg , have the same momentum as a 1600 kg car traveling at 5.2 m/s ?

Answers

[tex]Given:\\m_b=100kg\\m_c=1600kg\\v_c=5.2 \frac{m}{s} \\p_b=p_c\\\\Find:\\v_b=?\\\\Solution:\\\\p_b=p_c\\\\p=mv\\\\m_bv_b=m_cv_c\Rightarrow v_b= \frac{m_cv_c}{m_b} \\\\v_b= \frac{1600kg\cdot5.2 \frac{m}{s} }{100kg} =83.2 \frac{m}{s} [/tex]

Many scientists do not believe in astrology because

Answers

Many scientists don't believe in astrology because there is no proof or evidence to support the premises described and set in place in astrology.

What are some ways that scientists would collect data and make observations to help them learn more about the severity of the lion fish problem

Answers

experiments, tests, and trials

Which statement best describes the difference between acceleration and deceleration?

Answers

Final answer:

Deceleration is a type of acceleration where an object slows down, always acting opposite to the direction of motion. Negative acceleration, on the other hand, refers to acceleration in a negative direction as per the coordinate system and may not involve slowing down. Correctly distinguishing between these terms requires understanding both the motion's direction and the chosen coordinate system.

Explanation:

The difference between acceleration and deceleration relates to the direction of the change in velocity relative to the object's current motion. While acceleration refers to a change in velocity, either in magnitude or direction, deceleration specifically refers to acceleration that occurs in the opposite direction of an object's motion and results in a reduction of the object's speed. It is a common misconception to equate deceleration with negative acceleration; although related, they are not always the same because negative acceleration refers to acceleration in a negative direction in the chosen coordinate system, which might not necessarily mean the object is slowing down.

Deceleration always reduces speed, whereas negative acceleration can occur when an object is speeding up in a direction defined as negative by a coordinate system. Therefore, deceleration is a form of acceleration that always acts in the opposite direction to the velocity, causing the object to slow down. On the other hand, negative acceleration is coordinate-dependent and may either represent an object slowing down or speeding up, depending on its initial direction of motion.

It is advisable to avoid the use of the term 'deceleration' when referring to negative acceleration, as one must also consider the sign of the object's velocity to determine if the object is slowing down.

A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial speedof 37 m/s. if a force slows them to a stop at a constant rate of 2.0m/s2, (a) what magnitude f is required for the force, (b) what distanced do they travel while slowing, and (c) what work w is doneon them by the force? what are (d) f, (e) d, and (f) w if they, instead,slow at 4.0 m/s2?

Answers

(1)   Through the Second Law of motion, the equation  for Force is:

                                 F = m x a

Where m is mass and a is acceleration (deceleration)

 

(2)   Distance is calculated through the equation,

                             D = Vi^2 / 2a

Where Vi is initial velocity

(3)   Work is calculated through the equation,

                          W = F x D

 

Substituting the known values,

Part A:

(1)     F = (85 kg)(2 m/s^2) = 170 N

(2)     D = (37 m/s)^2 / (2)(2 m/s^2)  = 9.25 m

(3)     W = (170 N)(9.25 m) = 1572.5 J

 

Part B:

(1)    F = (85 kg)(4 m/s^2) = 340 N

(2)   D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

(3)    W = (340 N)(4.625 m) = 1572.5 J

If a flea can jump straight up to a height of 0.550 m , what is its initial speed as it leaves the ground?

Answers

Final answer:

The initial speed of a flea as it leaves the ground to reach a height of 0.550 meters is approximately 3.29 meters per second, calculated using the formula v = √{2gh}, where g is the acceleration due to gravity and h is the height.

Explanation:

The question asks us to find the initial speed of a flea as it leaves the ground to reach a height of 0.550 meters. To solve this, we can use the physics concept of kinematic equations, specifically the one that relates initial velocity, acceleration due to gravity, and maximum height achieved by a projectile. The formula we will use is: v = √{2gh}, where v is the initial velocity, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the maximum height (0.550 m).

Substituting the given values into the formula, we get:
v = √{2*9.81*0.550} = 3.29 m/s.

Therefore, the initial speed of the flea as it leaves the ground is approximately 3.29 meters per second.

You need to include:

An explanation of gravity
An explanation of how mass determines (or affects) the force of gravity
An explanation of the part air resistance plays
An example of the force of gravity (be creative)

Answers

Gravity, the force that attracts a body toward the center of the earth. 

Basically, the larger the mass the greater the pull of gravity. Weight is actually a measurement of gravitational force between two masses

Gravity is a force attracting two masses, with strength depending on their mass and distance apart. Air resistance affects how objects fall, especially lighter ones. A creative example is traveling by balloons, where releasing air and gravity interact to influence descent.

Explanation of Gravity

Gravity is a fundamental force that causes two objects with mass to be attracted to one another. It is why objects fall to the ground when released, and it keeps planets in orbit around stars. The force of gravity depends on the mass of the objects and the distance between them. According to Newton's law of gravity, the more mass an object has, the more powerful its gravitational pull. According to Einstein's theory of general relativity, gravity is the result of massive objects causing a curvature in spacetime.

Effect of Mass on Gravity

The force of gravity is directly proportional to the mass of the objects involved, meaning that larger masses will exert a stronger gravitational pull. If you were to calculate the gravitational pull between two objects, you would use the equation F = G (m1 * m2) / r², where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers of mass.

Role of Air Resistance

Air resistance acts against the force of gravity, especially on light or low-density objects. It is this resistance that explains why a feather falls more slowly than a bowling ball, despite gravity pulling on all objects equally. Air resistance depends on the speed and surface area of the falling object, as well as the density of the air.

Creative Example of the Force of Gravity

Imagine a world where everyone travels by balloons. The only way to move downward is by releasing some of the air from your balloon. Here, the force of gravity and the mass of the person in the balloon interact to determine how quickly they descend, with air resistance playing a part depending on the size and shape of the balloon.

ben(55 kg) is standing on very slippery ice when junior(25kg) bumps into him. junior was moving at a speed of 8m/s before the collision and ben and junior embrace after the collision. find the speed of ben and junior as they move across the ice after the collision .

Answers

Define
m₁= 55 kg, mass of Ben
m₂ = 25 kg, mass of Junior

v₁ = 0, initial speed of Ben (he was stationary)
v₂ = 8 m/s, speed of Junior

Consider the motion of Ben and Junior as occurring within a closed system.
Because momentum is preserved, the initial momentum of the system is equal to the final momentum of the system.

Refer to the figure shown below.
The initial momentum is
P₁ = m₁v₁ + m₂v₂
    = (55 kg)*(0 m/) + (25 kg)*(8 m/s)
    = 200 (kg-m)/s

Let V =   the speed of Ben and Junior (in an embrace) after the collision.
The final momentum is
P₂ = (m₁ + m₂)V
    = (55+25 kg)*(V m/s)
    = 80V (kg-m)/s

Equate P₁ and P₂ to obtain
80V = 200
    V = 2.5 m/s

Answer:  2.5 m/s

Which energy conversion occurs in a battery-powered flashlight?

Answers

Answer: The correct answers are "chemical energy into electrical energy" and then "the electrical energy into light energy".

Explanation:

In the battery-powered flashlight, the battery supplies the chemical energy which makes the electrons to flow in the circuit and constitutes the current.

Then, the flashlight flashes the light in this way.

In the battery-powered flashlight, firstly, the chemical energy gets converted into electrical energy and then the electrical energy  gets converted into light energy.

PLEASE GO ANSWER MY 3 MOST RECENT QUESTION I NEED HELP!!!!!!!!!!!!!!
3. Compare how a positively charged object and a negatively charged object interact with a neutral object.

4. What happens to the composition of an atom to cause it to become positively or negatively charged?

5. If you rub a balloon on a piece of fabric or carpeting and then hold it against your head, your hair can stand on end. Use what you have learned in this lesson to explain why this happens

Answers

Positive or negative charged will induce a dipole on the neutral charge, causing it to attract to either charge. Adding protons to an atom causes positive charge and adding electrons to an atom adds negative charge. Your hair and the gallon are naturally charged, so they induce a dipole in each other and cause themselves to mutually attract. Inducing a dipole is when a neutral charge has some of its positive or negative charges dragged to one side creating net positive charge on one side and net negative charge on the other.

The roller-coaster car shown in fig. 6-41 (h1 = 45 m, h2 = 16 m, h3 = 26 m), is dragged up to point 1 where it is released from rest. assuming no friction, calculate the speed at points 2, 3, and 4.

Answers

There are many ways to solve this but I prefer to use the energy method. Calculate the potential energy using the point then from Potential Energy convert to Kinetic Energy at each points.

PE = KE

From the given points (h1 = 45, h2 = 16, h3  = 26)

Let’s use the formula: 

v2= sqrt[2*Gravity*h1]  where the gravity is equal to 9.81m/s2

v3= sqrt[2*Gravity*(h1 - h3 )] where the gravity is equal to 9.81m/s2

v4= sqrt[2*Gravity*(h1 – h2)] where the gravity is equal to 9.81m/s2

Solve for v2

v2= sqrt[2*Gravity*h1]      

    = √2*9.81m/s2*45m

v2= 29.71m/s

v3= sqrt[2*Gravity*(h1 - h3 )   

    =√2*9.81m/s2*(45-26)

    =√2*9.81m/s2*19 

v3=19.31m/s

v4= sqrt[2*Gravity*(h1 – h2)]        

    =√2*9.81m/s2*(45-16)

    =√2*9.81m/s2*(29)

v4=23.85m/s

Final answer:

To calculate the speed at points 2, 3, and 4 of the roller-coaster car, we can use the principle of conservation of mechanical energy. At point 1, the car is released from rest, so its initial velocity is 0 m/s. Therefore, its potential energy at point 1 is equal to its total mechanical energy at point 1. Using the principle of conservation of mechanical energy again, we can find the speed at points 2, 3, and 4.

Explanation:

To calculate the speed at points 2, 3, and 4 of the roller-coaster car, we can use the principle of conservation of mechanical energy. At point 1, the car is released from rest, so its initial velocity is 0 m/s. Therefore, its potential energy at point 1 is equal to its total mechanical energy at point 1:



PE1 = KE1 + PE2 + PE3 + PE4
mgh1 = 0 + mgh2 + mgh3 + mgh4
45m = 0 + 16m + 26m + h4
h4 = 3m


Using the principle of conservation of mechanical energy again, we can find the speed at point 2:



KE2 = PE1 - PE2
KE2 = 45m - 16m
KE2 = 29m
v2 = sqrt(2g * KE2)
v2 = sqrt(2 * 9.8 m/s^2 * 29m)
v2 = sqrt(568.4) ≈ 23.8 m/s


Similarly, we can find the speed at point 3 using the same principle:



KE3 = PE1 - PE3
KE3 = 45m - 26m
KE3 = 19m
v3 = sqrt(2g * KE3)
v3 = sqrt(2 * 9.8 m/s^2 * 19m)
v3 = sqrt(372.4) ≈ 19.3 m/s


Finally, the speed at point 4 can be found:



KE4 = PE1 - PE4
KE4 = 45m - 3m
KE4 = 42m
v4 = sqrt(2g * KE4)
v4 = sqrt(2 * 9.8 m/s^2 * 42m)
v4 = sqrt(823.2) ≈ 28.7 m/s

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Calculate the average velocity of the car for the time interval t=0 to t1 = 2.00 s .

Answers

bem difícil espera que eu te respondo

Among all the given options, the correct option is option A. Distance, displacement, or acceleration can be used to describe motion.

What is average velocity?

Physical quantity concepts like velocity, velocity, distance, displacement, or acceleration can be used to describe motion. Sir Isaac Newton provided the correct definition of motion. These quantities are all explained in terms of the same parameter, time.

The proportion of the total all quantities to the entire number of quantities is what is simply meant by the word "average." In Physics, an alternative strategy is used. Let's first define velocity precisely as well as speed and how the two are related before moving on to average velocity.

Total Displacement = Area under v-t graph

=πr²/2

=π×1²/2

=π/2m

Average velocity = Total Displacement / total time

= π/2/2 = π/4m/s

Therefore, the correct option is option A.

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Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. the heat capacity of object a is three times the heat capacity of object b and the initial temperature of object a (ta) is twice the initial temperature of object b (tb). 1) what will the final temperature of the two-object system be?

Answers

At thermal equilibrium, when the colder object has a higher heat capacity than the hotter object, the final temperature of the system will be closer to the initial temperature of the colder object.

Thermal Equilibrium of Two Objects

When two objects with different initial temperatures are placed in thermal contact and isolated from their surroundings, they will exchange heat until reaching thermal equilibrium. Specifically, the zeroth law of thermodynamics states that if two systems are in thermal contact and no heat flows between them, they are at the same temperature, implying they have reached thermal equilibrium.

The object with the higher heat capacity can absorb more heat without a significant increase in temperature.

The concept of thermal equilibrium in thermodynamics states that objects in contact will approach the same temperature, following the zeroth law of thermodynamics.

In the scenario, where the heat capacity of the colder object B is much greater than that of the hotter object A, and both objects are allowed to reach thermal equilibrium, the final temperature of the system will be closer to the initial temperature of object B, the colder object. This is because the object with the greater heat capacity will undergo a smaller change in temperature for the same amount of heat exchange, compared to the object with the smaller heat capacity.

A ball of mass 0.5 kg is released from rest at a height of 30 m. How fast is it going when it hits the ground? Acceleration due to gravity is g = 9.8 m/s²

Answers

The answer is attached.

The ratio of the distance a bullet travels to the amount of time it takes to travel is known as the _____ of the bullet, depending on whether we need to know the direction or not.

Answers

Unit!

The ratio of the distance a bullet travels to the amount of time it takes to travel is known as the UNIT of the bullet, depending on whether we need to know the direction or not.

Answer:

speed or velocity

Explanation:

The ratio of distance travels to the time taken is called speed.

Speed = distance traveled / time taken

Speed is a scalar quantity and its SI unit is m/s.

If the direction of distance given then it is velocity.

Velocity is defined as the ratio of displacement to the time taken.

Velocity is a vector quantity and its SI unit is m/s.

A metal smith pours 3.00 kg of lead shot at 99oc into 1.00 kg of water at 25oc in an isolated container. what is the final temperature of the mixture?

Answers

The answer is in attachment.

Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The center of mass of the two block system is moving with velocity of?

Answers

Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.

We have that the velocity  two block system   is mathematically given as

vcm= -16 m/s

Velocity  two block system

Question Parameters:

With a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s.

Generally the equation for the Velocity   is mathematically given as

vcm = (m1*v1) + (m2*v2)

vcm = ((4*2)-(8*3))

vcm= -16 m/s

And the direction is

dcm = in the direction of block B

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If you double the radius of the earth and keep the mass of the earth the same, the acceleration of gravity on the surface of the earth will be approximately ...

Answers

Even though the mass of the earth stays the same, the force gravity has on us will double because there is less space in the atmosphere for the gravity to pull anything in towards its center. Let me know if I'm correct!

If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?

Answers

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

[density * volume]_salt water = [density * volume]_fresh water                 ---> 1

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

h = 0.72 m        (ANSWER)

Final answer:

Based on Archimedes' principle, the rectangular barge will sit at the same depth of 0.70m in both the harbor and the river, if the river and the harbor have the same type of water.

Explanation:

The depth at which the rectangular barge will sit in the river relates to the concept of buoyancy and the principle of Archimedes. According to this principle, the weight of the water displaced by the barge is equal to the weight of the barge itself.

Provided that the river and the harbor have the same type of water (salt water or fresh water), the barge will sit at the same depth in both, which is 0.70m deep. This is because the barge, with dimensions of 3.0m by 20.0m, will displace an equal volume of water to balance its own weight in any body of water it is placed in.

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A piston has an external pressure of 15.0 atm. how much work has been done in joules if the cylinder goes from a volume of 0.150 liters to 0.640 liters?

Answers

Work, in thermodynamics, is the amount of energy that is transferred from one system to another system without transfer of entropy. It is equal to the external pressure multiplied by the change in volume of the system. It is expressed as follows:

W = PdV

Integrating and assuming that P is not affected by changes in V or it is constant, then we will have:

W = P (V2 - V1)
W = 15 (101325) N/m^2 ( 0.640 - 0.150 ) (1/1000) m^3
W = 744.74 N-m or 744.74 J

It is important to remember that pressure here is assumed to be independent of the volume. However, if this is not the case the formula of work would change accordingly.

Therefore, the work done on the cylinder is equal to 744.74 J.
Final answer:

In Physics, the work done on a system is calculated using the formula W = P∆V. Using a conversion factor to change atmospheres to Joules/liter, the total work done by the piston as the cylinder's volume changed was approximately 744.55 Joules.

Explanation:

The work done on a system in physics is given by formula W = P∆V, where P is pressure and ∆V is the change in volume. Considering the conversion factor of 1 atm equaling 101.3 J/liter in this context, we apply this formula to find the work done. Given that the pressure equals 15.0 atm, which is equal to 1519.5 Joules per liter, and the change in volume equals 0.490 liters (0.640 liters - 0.150 liters), we multiply these values together to determine the work to be approximately 744.55 Joules.

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The current estimate for the age of earth of 4.57 ga comes from _____.

Answers

The estimation of the age of the Earth comes from scientists who studied the rock formation under the Earth's crust. They believe that during the Big Bang, the Earth, together with the other celestial bodies in the universe, were formed. Under the Earth's soil contain radioactive materials that have known decay rates. Using these rate, they undergo tests like rock dating to find the time of its existence.

A steam engine absorbs 4 x 105 J and expels 3.5 x 105 J in each cycle. What is its efficiency?

100%
12.5%
75%
33%

Answers

Input heat, Qin = 4 x 10⁵ J
Output heat, Qout = 3.5 x 10⁵ J

From the first Law of thermodynamics, obtain useful work performed as
W = Qin  -  Qout
     = 0.5 x 10⁵ J

By definition, the efficiency is
η = W/Qin
   = 100*(0.5 x 10⁵/4 x 10⁵)
   = 12.5%

Answer: The efficiency is 12.5%

A proton is placed in an electric field of intensity 500 n/c what is the magnitude and direction of the acceleration of this proton due to this field

Answers

Calculate the magnitude and direction of the acceleration of a proton placed in an electric field of 500 N/C.

Magnitude of Acceleration: The magnitude of the acceleration of the proton can be calculated using Newton's second law, F = ma, where F is the force experienced by the proton in the electric field. Given that the electric field intensity is 500 N/C and the charge of a proton is 1.6 x 10^-19 C, you can find the acceleration.

Direction of Acceleration: The direction of the acceleration will be the same as the direction of the force experienced by the proton in the electric field, which is determined by the positive charge of the proton relative to the field lines.

The acceleration of a proton in a 500 N/C electric field is calculated using the charge of the proton and its mass, along with the given field intensity. The proton's charge is 1.60 x 10^-19 C, and its mass is 1.67 x 10^-27 kg. The proton accelerates in the same direction as the electric field.

To calculate the magnitude and direction of the acceleration of a proton in an electric field, we can use the formula for force F exerted on a charge q in an electric field E: F = qE. Next, we use Newton's second law of motion, which states that the force F on an object is equal to its mass m times its acceleration a: F = ma. Since the two expressions are both equal to the force F, we can set them equal to each other to find the acceleration: ma = qE. For a proton, the charge q is equal to the elementary charge, which is approximately 1.60 x 10-19 C. Hence, the acceleration a is found by rearranging the formula to a = qE/m.

The mass of a proton is approximately 1.67 x 10-27 kg. Substituting the given electric field intensity of 500 N/C, the charge of a proton, and the mass into the formula, we get:

a = (1.60 x 10-19 C) \\* (500 N/C) / (1.67 x 10-27 kg)

Calculating this, we get the acceleration a of the proton. Since the proton is positively charged, it will accelerate in the same direction as the electric field. This gives us both the magnitude of the acceleration and its direction.

Starting from rest, a disk takes 8 revolutions to reach an angular velocity ω at constant angular acceleration. how many additional revolutions are required to reach an angular velocity of 3 ω ?

Answers

w^2 = 2 A 8 where A is the angular acceleration.
(3w)^2 = 2 A R where R is the number of revolutions.
Note that you are asked for the additional revolutions.
Final answer:

To find the additional revolutions required to reach an angular velocity of 3ω, we can use the equations of rotational motion.

Explanation:

To find the solution to this problem, we can use the equations of rotational motion. The first step is to find the initial angular velocity, ω0. Given that the disk takes 8 revolutions to reach an angular velocity ω, we can calculate that ω0 = 2π * 8 / 8 = 2π rad/s.

Next, we can use the equation ω = ω0 + αt to find the angular acceleration, α. Rearranging the equation, we get α = (ω - ω0) / t = (3ω - 2π) / t.

Finally, we can use the equation ω = ω0 + αt to find the additional time, t', required to reach an angular velocity of 3ω. Rearranging the equation, we get t' = (3ω - ω0) / α = (3ω - 2π) / ((3ω - 2π) / t).

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What is the maximum amount by which the wavelength of an incident photon could change when it undergoes compton scattering from an atom or molecule with a 36.0 u mass? (1 u = 1.66 × 10-27 kg)?

Answers

Final answer:

The maximum amount by which the wavelength of an incident photon could change in Compton scattering depends on the angle of scattering and can be calculated using the given formula.

Explanation:

In Compton scattering, the wavelength of an incident photon can change. The maximum change in wavelength, or shift, can be determined by using the formula:

Change in wavelength (Δλ) = Compton wavelength (λc) * (1 - cosθ)

Where λc is the Compton wavelength, given by:

In this formula, h is Planck's constant, m is the mass of the scattering particle (in this case, the atom with a mass of 36.0 u), and c is the speed of light.

The maximum amount by which the wavelength of an incident photon could change depends on the angle of scattering (θ) and can be calculated using the formula mentioned above.

After an average acceleration of 3.95 m/s2 during 2.25 s, a car reaches a velocity of 15.3 m/s. find the car\'s initial velocity.

Answers

Since,
We have avg. acceleration it can be put in place of accelaration in the given time period.

v=15.3m/s
a= 3.95m/s
t= 2.25 s

by using,
a=(v-u)/t
3.95=(15.3-u)/2.25
(3.95*2.25)-15.3= -u
8.8875-15.3= -u
 -6.4125= -u
⇒ u= 6.4125 m/s

Suppose you are an astronaut and you have been stationed on a distant planet. you would like to find the acceleration due to the gravitational force on this planet so you devise an experiment. you throw a rock up in the air with an initial velocity of 11 m/s and use a stopwatch to record the time it takes to hit the ground. if it takes 7.0 s for the rock to return to the same location from which it was released, what is the acceleration due to gravity on the planet?

Answers

Answer: g = -3.143 m/s²

Explanation: To determine acceleration due to the gravitational force, it can be used the following formula:

v = v₀ + gt, where:

v₀ is the initial velocity;

g is acceleration due to gravity

t is the time to return to the point of origin

When the rock return to the point of origin, there is no velocity, so v = 0.

The time to go up is the same to go down, so t = [tex]\frac{t}{2}[/tex] = [tex]\frac{7}{2}[/tex].

Substituing in the formula:

v = v₀ + gt

0 = 11 + g.[tex]\frac{7}{2}[/tex]

g = [tex]\frac{(0 - 11).2}{7}[/tex]

g = - 3.143

The acceleration due to the gravitational force is g = - 3.143 m/s².

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