1,289 ÷22 is 58 r13 (yes) or (no)

Answers

Answer 1
yes it is right hope it help
Answer 2
1,289 divided by 22 is 58 r13

Related Questions

Jesse ate 100 donughts i 5 days each day she ate 6 more then the day before how many did she eat each day

Answers

506. donuts


hoped it helped! :D



MATH PLEASE HELP 50 POINTS 1 QUESTION
Complete the reasons in the proof below.

Given: ∠1 and ∠5 are supplementary.
Prove: a ∥ b


Statements
1. ∠1 and ∠5 are supplementary
2. ∠1 ≅ ∠2
3. ∠2 and ∠5 are supplementary
4. a ∥ b

Answers

For 1, ∠1 and ∠5 are supplementary is a given, so you can just write 'Given'
For 2, due to that 1 and 2 are vertical angles (angles that are opposite to each other when two lines cross according to Math is Fun)
For 3, since ∠1=∠2, ∠1 can be substituted by ∠2 in ∠1+∠5=180 to get ∠2+∠5=180. Therefore, they are supplementary.

For 4, due to that we have Consecutive Interior Angles (they are angles that are on one side of a transversal, which is the line that cuts through a and b,but inside the two lines according to Math is Fun) adding up to 180 degrees, a  || b

Feel free to ask if you have any questions!

Write the polynomial in factored form. 4x3 + 8x2 – 96x

Answers

 4x^3+8x^2-96x = 4x(x-4)(x+6) 

Explanation: 

4x^3, 8x^2 and 96x have 4x as a common factor. Hence 

4x^3+8x^2-96x = 4x*(x^2+2x-24) 

Furthermore, (x^2+2x-24)= (x-4)(x+6) 
because 6-4=2 and 6*(-4) = -24. 
So 4x^3+8x^2-96x = 4x*(x^2+2x-24) = 4x(x-4)(x+6).

Given:
AC = BC
∠3 = ∠4

Based on the given information and the algebraic and geometric properties presented or proven thus far, choose the congruence theorem that could be used to prove that triangle ACM is congruent to triangle BCM. If it is not possible to prove the triangles are congruent, choose "not possible".

Choices:
SSS
SAS
ASA
not possible

Answers

SAS You've been given that AC = BC. So that's the first side or S of the proof. Then you've been given â 3 = â 4, which is the angle. And finally, CM = CM, which is the second S. So you have AC=BC, and â 3 = â 4, and finally CM = CM. So SAS can be used to prove that triangle ACM is congruent to triangle BCM.

Answer:

SAS Postulate

Step-by-step explanation:

Please help! I need to show my work

Answers

You can graph the 4 points.
Notice that sides AB and CD are horizontal, so they are parallel with different lengths.
Sides BC and Ad are not parallel.
A quadrilateral with two parallel sides and two non-parallel sides is a trapezoid.

If 6 1/2is the lesser number in an inequality, which statement is true about the other number in the inequality?

Answers

Wouldn't it be that the other number is greater and so it would be x> 6 1/2 because it says that 6 1/2 is the lesser number so it can't be greater than and equal to so it has to just be greater than.

I KNOW ITS NOT A. But i think it is B. HOPE THIS HELPS!

Find the 20th term in arithmetic sequence -4, 1, 6, 11, 16,

Answers

91, I just kept adding 5 until I got to the 20th term

which exponential functions have been simplified correctly check all that apply

Answers

Answer:

Option A, C, D, are the correct options.

Step-by-step explanation:

To check the exponential functions which have been simplified correctly we will take option one by one.

A). [tex]f(x)=5(\sqrt[3]{16})^{x}=5(\sqrt[3]{2^{4}})^{x}=5(2\sqrt[3]{2})^{x}[/tex]

B). [tex]f(x)=2.3(8^{\frac{1}{2}})^{x}=2.3(2.\sqrt{2})^{x}\neq 2.3(4^{x})[/tex]

C). [tex]f(x)=81^{\frac{x}{4}}=(3^{4})^{\frac{x}{4}}=(3^{\frac{4}{4}})^{x}=3^{x}[/tex]

D). [tex]f(x)=\frac{3}{4}(\sqrt{27})^{x}=\frac{3}{4}(\sqrt{3^{3}})^{x}=\frac{3}{4}.(3\sqrt{3})^{x}[/tex]

[tex]f(x)=(24)^{\frac{1}{3}x}=(2^{3}.3)^{\frac{1}{3}x}=(2.3^{\frac{1}{3}})^{x}\neq 2(\sqrt[3]{3})^{x}[/tex]

Final answer:

Exponential functions and their inverses like the natural logarithm are inverse functions, meaning they can undo each other. Simplifications like ln(e^x) result in x, and e^(ln x) simplifies to x. This property is integral to correctly simplifying exponential functions.

Explanation:

The exponential functions and their inverses, like the natural logarithm (ln), have specific properties where they can "undo" each other. This relationship allows us to simplify expressions involving exponentials and logarithms. For example, when you have ln(ex), this simplifies to x because the natural logarithm and the exponential function are inverse functions.

Similarly, when applying the exponential function to a natural logarithm, like eln(x), the result is just x. Furthermore, when taking square roots of exponentials, you can adjust the exponent to be evenly divisible by 2 and then take the square root of the base number, followed by dividing the exponent by 2. Also, while dividing exponentials, you subtract the exponents when the bases are the same.

Here is an example of this simplification: to compute the square root of e4, we can write it as e4/2, which simplifies to e2.

What’s the ratio of 42¢ to $1.25? (Change dollars to cents)

Answers

42:125, 42/125 or 42 to 125

Answer:

42 125 becuase i got um right bozzzzzzzz

Step-by-step explanation:

If f(x)=5x^0+4x^-3 then f(a)=?

Answers

x=a
f(a)=5(a^0)+4a^-3          a^0=1
=5(1)+4/a^3
=5+4/(a^3)
Final answer:

To find f(a) for the given function, substitute a for x in the function and simplify the expression.

Explanation:

Given the function f(x) = 5x0 + 4x-3, we need to find f(a). To find f(a), we substitute a for x in the function. Plugging in a, we get f(a) = 5a0 + 4a-3. Since any number raised to the power of 0 is equal to 1, we have f(a) = 5(1) + 4a-3. Simplifying further, we get f(a) = 5 + 4/a3.

Learn more about Functions here:

https://brainly.com/question/21145944

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given a line whose slope is, m, is -6/5, and passes through point (-5,3), the graph will?

Answers

Using the point-gradient form y - y₁ = m ( x - x₁ )
y₁ = 3;  x₁ = -5;  m =  [tex]- \frac{6}{5} [/tex]

 ⇒  y - 3 =  [tex]- \frac{6}{5} [/tex] ( x - (-5))
 ⇒  y - 3 =  [tex]- \frac{6}{5} [/tex] (x + 5)

Now, you can approach here in two ways: put it in the y-intercept form or the general form.

In the y-intercept form;
      y - 3 = [tex]- \frac{6}{5} [/tex]x + ([tex]- \frac{6}{5} [/tex] (5))
      y - 3 =  [tex]- \frac{6}{5} [/tex]x - 6
           y =  [tex]- \frac{6}{5} [/tex]x - 3

In the general form;
    y - 3 =  [tex]- \frac{6}{5} [/tex] (x + 5)
       by multiplying through by 5
⇒    5 ( y - 3 ) = -6 ( x + 5)
⇒       5y - 15 = -6x - 30
⇒      5y + 6x = -15

∴ the line that passes through (-5, 3), with gradient [tex]- \frac{6}{5} [/tex] is 
 y =  [tex]- \frac{6}{5} [/tex]x - 3 (y-intercept form)  OR  5y + 6x = -15 (general form).

Solve x ym = y x3 for m.

Answers

xym-yx3m = 0
xym (1-1x2) = 0
xym (1 (un cuadrado)-1x2)=0
xym(1+x)(1-x)=0
1+x=0
1-x=0
m= 0
x=-1
x=1
Is true 
m=0;x= -1;1

The inequality x2 + 12x + 35 ≥ 0 has two critical points and three possible intervals for solutions. Choose each set of possible test points for the three intervals.


–8, –6, –4

–10, –6, 0

–6, 0, 6

–6, 0, 10

Answers

-8,-6,-4

-10,-6,0

these are the possible test points for your three intervals

The given inequality is, x² + 12 x+35≥0

→ x²+7 x +5 x+5×7≥0

→ x (x+7) +5(x+7)≥0

→ (x+5)(x+7)≥0

→ x+5=0  ∧ x+7=0 gives x= -7 ∧ x= -5

Now drawing the number line and marking point ,-5 and -7 on it.

Now the three intervals are (-∞ , -7], [-7,-5] and [-5,∞).

The solution set of inequality (x+5)(x+7)≥0 is  (-∞ , -7] and [-5,∞).

The set of possible test points for

⇒ (-∞ , -7] → -8,  -10

⇒ [-7,-5] → -6

⇒ [-5,∞) → -4, 0

Option (1) -8,-6,-4 and Option (2) -10,-6,0 satisfies the given condition.

Find three consecutive odd integers whose sum is negative 465

Answers

465 / 3 = 155

so -153 + -155 + -157 = -465

An automobile manufacturing organization noted a drop in sales after an incident occurred due to the lack of a safety feature in their cars. Many customers began considering other brands of cars after this incident. How can the organization avoid losing customers

Answers

By paying the person who was involved in the incident

Recalling the effected car and fixing the issue

Answer:

introducing customer retention strategies

Step-by-step explanation:

Is 9.103 greater than 9.13

Answers

Answer:

false 9.13 is greater

Step-by-step explanation:

103 thousanths are smaller then 13 hundreths

with decimals the farther you go the lower you get bc its half a number

1/2 to 1/4 to  1/8 it gets smaller

Which postulate or theorem proves that these two triangles are congruent?

Answers

the answer would be AAS (angle angle side) theorem

Answer:

option B  

Step-by-step explanation:

Given in the question are ∠x ≅ ∠y and ∠zwx ≅ ∠ ywz and wz is common in both.

These angles are adjacent angles of triangles.

We know theorem for congruence is Angle - Angle - Side

Therefore, for the congruence of these two triangles option B, AAS congruence theorem is the answer.

What does it mean when u cant find the mean of a set of numbers?

Answers

The mean or better known as the average is all of the numbers combined and then divided by how many numbers there were. You should be able to find the mean of any set of numbers. There might be a mistake in the calculations some where.

Answer:

Another word for mean is the "average", your goal is to find the average of the following data set, it's pretty easy, you just have to add up all the numbers in the data set and divide it with the total numbers in the data set.

For example:

Find the mean of the following data set:

4, 1, 8, 5, 7, 3

Mean: 4 + 1 + 8 + 5 + 7 + 3 = 28

then we divide 28 with 6 since there are 6 numbers in the following data set.

Mean: 4 + 1 + 8 + 5 + 7 3 = 28/6 = 4.6

We get the final answer of 4.6!

The lenght of a rectangleis 6 inches more thans its width the area of a rectangle is 91 inches find the dimernins

Answers

Length is 13 and the width is 7

Which postulate or theorem proves that △JHG and △EFG are congruent?



​ SAS Congruence Postulate ​

​ ASA Congruence Postulate ​

​ HL Congruence Theorem ​

​ AAS Congruence Theorem ​

Answers

the asa congruence postulate

The postulate that proves that △JHG and △EFG are congruent is;

Option B; ​ ASA Congruence Postulate ​

From the given image, we can see two triangles namely;

△JHG and △EFG

Now, we can see that;

FG = GH

That is given because we see that G has divided FH into 2 equal parts.

Also, we see the right angle sign at ∠F and ∠H of both triangles.

Thus, since they are both right angles, then we can say that;

∠EFG = ∠JHG

Also, at point G, we have two vertically opposite angles which are;

∠EGF and ∠JGH

Now, from vertically opposite angle theorem, vertically opposite angles are always equal;

Thus; ∠EGF = ∠JGH

So far, we have;

FG = GH

∠EFG = ∠JHG

∠EGF = ∠JGH

This is 2 corresponding equal angles and 1 corresponding equal side. The side is included between the two angles and as such the proof that  △JHG and △EFG are congruent is the ASA Congruence Postulate.

Read more at; https://brainly.com/question/19413244

does anyone know how to do this?

Answers

You're looking for values to factor this equation into (x+p)(x+q)
such that pq=12 and p+q=b

Assuming we're looking for simple values, you can start by factorizing 12:

12 = 3*4 = 2*6 = 12*1 = -3*-4 = -2*-6 = -12*-1

For 3 and 4, b would be 7
2 and 6 => b=8
12 and 1 => b=13

and for the negatives

b can be -7, -8 or -13

So the total set is -13, -8, -7, 7, 8, 13
It is factorable if you can solve it when it equals 0. 
There are many ways to do this. 

X^2+bx+12=0 

[tex](-b +- \sqrt{ b^{2} -4*12 } )/2 [/tex]

This equation gives a good answer if 
[tex]b ^{2} \geq 48[/tex]

Find the value of x so that the line passing through (10, 5) and (x, 9) has a slope of -2.

Answers

Ok, so here, we need to use the slope formula which is:

(y2 - y1)/(x2-x1)

y2 = 9
y1 = 5

x2 = x
x1 = 10

So:

(9-5)/(x-10) = -2

Now, we just solve for x,

9-5  =  -2(x-10)

4  =  -2x+20

2x  =  16

x  =  8

PLZ HELP ILL GIVE A BRAINLIEST SHOW ALL WORK!!!!

Answers

Step 1. Collect like terms
(√3 + 2√3) + √7
Step 2. Simplify 
3√3 + √7
That's all.

apply the distributive property and the greatest common factor to write an equivalent expression.

32k + 24 = _ (_)

what numbers should be in place of the underscores?

Answers

You need to see what is the highest number that goes into 32 and 24. the only number that works here is 8. 32/8 is 4 and 24/8 is 3. so the solution to your problem is 8(4k+3).

Two integers with the sum of -17 and the product of 52?

Answers

let the integers be x and y
you have x+y=-17 ---------(1)
xy=52 ---------(2)
from eqn (1) x=-17-y --------(3)
, so subsitute eqn (3) in to eqn(2)
(-17-y)y=52
-17y-y²=52
:
-y²-17y-52=0 same as y²+17y+52=0
y²+13y+4y+52=0
y(y+13)+4(y+13)=0
(y+4)(y+13)=0
therefore y=-4 or -13
now substitute y=-4 or -13 in eqn (3)
x=-17-(-4) or -17-(-13)
x= -13 or -4
so when x=-13 ,y=-4 and when x=-4 ,y=-13

so the integers are -13 and -4

Which expression is a perfect cube?

A. -8x21y8

B. -64x64y64

C. -125x9y20

D. -216x9y18

Answers

Finding the cube root of each expression

Expression A:

[tex] \sqrt[3]{-8x^{21}y^{8}} [/tex]
[tex] \sqrt[3]{-8} [/tex] [tex] \sqrt[3]{x^{21}[tex] \sqrt[3]{y^8} [/tex]} [/tex] 
[tex]-2x^ \frac{21}{3} y^ \frac{8}{3} [/tex]
[tex]-2 x^7 y^ \frac{8}{3} [/tex]

the term [tex]y^ \frac{8}{3} [/tex] is not a perfect cube, therefore expression A is not a perfect cube.

--------------------------------------------------------------------------------------------------------------

Expression B
[tex] \sqrt[3]{-64x^{64}y^{64}} [/tex]
[tex] \sqrt[3]{-64} \sqrt[3]{x^{64}} \sqrt[3]{y^{64}} [/tex]
[tex]-4 x^ \frac{64}{3} y^ \frac{64}{3} [/tex]

The term [tex]x^ \frac{64}{3} [/tex] and [tex]y^ \frac{64}{3} [/tex] are not perfect cube because 64/3 doesn't give whole number
----------------------------------------------------------------------------------------------------------------

Expression C

[tex] \sqrt[3] {-125x^9y^{20}} [/tex]
[tex] \sqrt[3]{-125} \sqrt[3]{x^9} \sqrt[3] {y^{20}} [/tex]
[tex]-5 (x^ \frac{9}{3}) (y^ \frac{20}{3})[/tex]
[tex]-5 (x^3) (y^ \frac{20} {3}) [/tex]

The term [tex]y^ \frac{20}{3} [/tex] are not perfect cube because 20/3 doesn't give whole number
---------------------------------------------------------------------------------------------------------------

Expression D

[tex] \sqrt[3]{ -216 x^{9} y^{18} } [/tex]
[tex] \sqrt[3]{-216} \sqrt[3]{x^9} \sqrt[3]{y^{18}} [/tex]
[tex]-6 ( x^ \frac{9} {3} ) ( y^ \frac{18} {3} ) [/tex]
[tex]-6 (x^3) (y^6)[/tex]

All terms are perfect cubes

ANSWER: OPTION D

Which ordered pair comes from the table ? HELPPP!

Answers

It's (4,2). Can you comment why you're having a struggle with this? I might be able to help you.
The answer is B.(4,2). Hope this helps.

Mrs. simms told her class to find two consecutive even integers such that twice the lesser of two integers is 4 less than two times the greater integer.
a. write and solve an equation to find the integers.
b. does the equation have one solution, no solutions, or is it an identity? explain.

Answers

Final answer:

To find two consecutive even integers, we can set up and solve an equation. The equation in this case is an identity, meaning it is true for all values of x. Therefore, there are infinitely many solutions.

Explanation:

To find two consecutive even integers, let's represent the first integer as x and the second integer as x + 2. Now, according to the given information, twice the lesser of the two integers is 4 less than two times the greater integer. We can write this as:

2x = 2(x + 2) - 4

Simplifying the equation:

2x = 2x + 4 - 4

2x = 2x

This equation is an identity, meaning it is true for all values of x. Therefore, there are infinitely many solutions. In this case, there are infinitely many pairs of consecutive even integers that satisfy the given conditions.

The length of a rectangular plot of land is 10 yards more than its width. If the area of the land 600 square yards , find the dimensions

Answers

Let the width of the rectangular plot of land be 'x' yards. Given that the length of the rectangular plot of land is 10 yards more than its width. So, width of the rectangular plot of land = (x + 10) yards. Also given that the area of the rectangular plot of land is 600 square yards. We know that, area of a rectangle = length * width That is, (x+10) * x = 600 x^2 + 10x = 600 x^2 + 10x - 600 = 0 x^2 + 30x - 20x -600 = 0 x(x + 30) - 20(x + 30) = 0 (x +30)(x -20) =0 Therefore, either (x + 30) = 0 or (x - 20) = 0 If x + 30 = 0, then x = -30 and If x - 20 = 0, then x = 20 Since 'x' represents the width of a rectangular plot of land it cannot be negative. Therefore, width of the rectangular plot of land = 20 yards length of the rectangular plot of land= x + 10 = 30 yards

Final answer:

The dimensions of the rectangular plot of land, where the length is 10 yards more than its width and the area is 600 square yards, are 20 yards by 30 yards. We arrived at this by setting up a quadratic equation and solving for the width.

Explanation:

To find the dimensions of a rectangular plot of land where the length is 10 yards more than its width and the area is 600 square yards, we can set up an equation. Let w be the width of the plot. Then the length is w + 10 yards. The area of a rectangle is given by the formula length × width, which in our case is (w + 10) × w = 600.

Setting up the equation, we get:

w(w + 10) = 600

w^2 + 10w - 600 = 0

To solve the quadratic equation, we can factor it, use the quadratic formula, or complete the square. Factoring the equation, we find that:

(w - 20)(w + 30) = 0

Thus, the width w can be either 20 yards or -30 yards. Since a width cannot be negative, we take w = 20 yards. Then, the length is:

w + 10 = 20 + 10 = 30 yards

The dimensions of the rectangular plot of land are 20 yards by 30 yards.

Emily has 32 grams of a 25% sugar syrup, but this is just too sweet for her! How much pure water should she add to have a 10% syrup?

Answers

32 grams = water mass + sugar mass . 100% syrup=75% water+ 25%sugar 
original water content= 32*75/100=24 grams
original sugar content= 32*25/100= 8grams 

total mass at 10% syrup:
8grams/total mass=10%=0.1
total mass=8/0.1=80grams
total mass of water=80grams- 8grams of sugar content= 72 grams
total mass of water added=72grams- 24grams original water content= 48grams.

answer: 48grams

By this information, we know: (just so you know, when I will write the equation, the multiplication sign will be ^)

25%+0%=10%
32g    xg   (32+x)g
Now, we create an equation:

(0.25^32)+(0^x)=0.1^(32+x)
8+0=3.2+0.1x
8=3.2+0.1x
4.8=0.1x
48=x
Answer: 48 gram.
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