Solve 5(y - 4) = 7(2y + 1)
what is 1.18 repeating as a fraction
-4 1/2, -5.6, -2 3/8, 2.35 from least to greatest
Rebecca ran 12 1/4 miles in 2 1/2 hours. What was your average speed in miles per hour
5. At a local store you find the following prices listed: Tape 2 rolls for $1.28 Notepads 3 pads for .87 Highlighters 1 for 1.59 Pens 2 for 1.98 How much would you pay for one roll of tape, two note pads, two highlighters, and two pens? A. $5.72 B. $6.38 C. $4.50 D. $8.07
Read the proposition and the implication shown below. "If the lights are off, there is no one inside." Which statement is a contrapositive to the proposition and logically equivalent to it?
The contrapositive of the proposition 'If the lights are off, then there is no one inside' is 'If there is someone inside, then the lights are not off'. Contrapositives are formed by negating and interchanging the hypothesis and conclusion of a conditional statement, and is a key concept in mathematics.
Explanation:In logic, the contrapositive of a conditional statement is formed by negating both the hypothesis and the conclusion, and then interchanging the resulting negations. So, the contrapositive of the given proposition 'If the lights are off, then there is no one inside' would be 'If there is someone inside, then the lights are not off'.
This implies that, in the context of this statement, if we know that there is someone inside, we can deduce that the lights must not be off as per the contrapositive. Thus, contrapositives are a helpful way to understand conditional statements from another perspective, and are an integral concept in logic and mathematics.
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Solve (−3) ⋅ 2.
−6
−5
5
6
(1-x)y"-4xy'+5y=cosx
A candle is 6 inches tall and burns at a rate of one half an inch per hour. Write an equation to represent the situation.
Answer: [tex]y=6-0.5x[/tex]
Step-by-step explanation:
Given : The initial height of candle = 6 inches
Amount of candle burn each hour = one half an inch per hour.
[tex]=\dfrac{1}{2}\text{ inch per hour}[/tex]
Now , the height of candle = ( initial height ) -( Rate of burning) (Numb er of hours)
Let y be the height of the candle after x hours.
Then, the equation to represent the situation will be :
[tex]y=6-\dfrac{1}{2}x\\\\\Rightarrow\ y=6-0.5x[/tex]
The equation to represent the situation will be, [tex]y=6-\frac{1}{2} \times x[/tex].
Given A candle is 6 inches tall.
The candle burns at a rate of one half an inch per hour.
Let [tex]x[/tex] be the number of hours candle burn and [tex]y[/tex] be the height of the candle after [tex]x[/tex] hours.
Now , the height of candle = ( initial height ) -( Rate of burning) (Number of hours)
So, the equation to represent the situation will be, [tex]y=6-\frac{1}{2} \times x[/tex].
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joe's cell phone costs him $21 per month plus $3 for every 1GB of data downloaded. What is the limit to the number of GBs he can download to stay within his monthly budget of $30.
joe can only use 3gb of data . bill is 21
21+9+30
1gb=3
3*9=9
3(3)+21=30
In solving the inequality -3x < 9, you would divide both sides of the inequality by -3 and flip over the inequality symbol. true or false
Answer: true.
Step-by-step explanation: do you really want an explanation?
A ticket agency charges 9.5% fee on all tickets sold .if a ticket cost 40$ what is the fee
Amber has a 4/5 pound bag of colored sand, she uses 1/2 of the bag for an art protect. How much sand does she uses for the protect?
what is the area of a rectangle with a length of 6 2/5 feet and width of 4 1/6 feet
Which of the angles are congruent, select all that apply
A students work to solve 2 6/7 / 2/7 is shown below.
Which of the following statements do you agree with.
2 6/7 / 2/7 =
19/7 / 2/7 =
7/19 x 2/7 =
1/19 x 2/1 = 2/19
A. The only mistake is changing the mixed number to an improper fraction.
B. There's a mistake with the multiplicative inverse 2/7 .
C. The problem looks correct.
D. There's a problem with changing the mixed number to an improper fraction, as well as changing the division problem to multiplication.
Answer:
D. There's a problem with changing the mixed number to an improper fraction, as well as changing the division problem to multiplication.
Step-by-step explanation:
We have shown work of a student to solve a division of fractions. We are asked to check student's work.
Let us check
[tex]2\frac{6}{7}\div\frac{2}{7}[/tex]
Convert mixed fraction into improper fraction:
[tex]2\frac{6}{7}\Rightarrow \frac{2\times 7+6}{7}=\frac{14+6}{7}=\frac{20}{7}[/tex]
[tex]\frac{20}{7}\div\frac{2}{7}[/tex]
Convert division problem to multiplication problem by flipping the 2nd fraction:
[tex]\frac{20}{7}\times\frac{7}{2}[/tex]
[tex]\frac{20}{1}\times\frac{1}{2}[/tex]
[tex]\frac{20}{2}[/tex]
[tex]10[/tex]
Therefore, the student made two mistakes and option D is the correct choice.
i am a fraction in the simplest form. i am greater than 4/5. the sum of my terms is 25. what fraction am i?
The length of a rectangle is 8 more than the width. The area is 825 square inches. Find the length and width of the rectangle
Let width be x then
Length is x+8
Therefore area which is given by L*W will be
Area=x*(x=8)
But area =825 sq inches
x*(x+8)=825
x^2+8x-825=0
we use quadratic formula to solve this
and get our x=25 therefore
our width is 25
and length is 33
Pizza World has a specialty cheese pizza that can be cut into 10 slices, and they have a specialty pepperoni pizza that can be cut into 16 slices. If Pizza World serves combos of one slice of cheese and one slice of pepperoni pizza with no slices left over, what is the smallest number of combos that Pizza World can prepare?
The smallest number of combos that Pizza World can prepare with one slice of cheese and one slice of pepperoni pizza with no slices left over is 80.
The student is asking how many combos of one slice of cheese and one slice of pepperoni pizza Pizza World can prepare with no slices left over given that a cheese pizza has 10 slices and a pepperoni pizza 16 slices. This question is looking for the least common multiple (LCM) of two numbers, which is the smallest number that is a multiple of both numbers. To find the LCM of 10 and 16, we list the multiples of each number until we find a common multiple. The multiples of 10 are 10, 20, 30, 40, 50, 60, ... and the multiples of 16 are 16, 32, 48, 64, 80, .... The smallest common multiple of 10 and 16 is 80. Therefore, we can prepare 80 combos using 8 cheese pizzas (because 8 x 10 = 80) and 5 pepperoni pizzas (because 5 x 16 = 80).
163water bottles in 9 cases=
Factor out the coefficient of the variable.
The expression 38d+34 factored is
The highest common factor of 38 and 34 is 2. Dividing both coefficients by 2 gives us 19d and 17. Therefore, the factored expression of 38d + 34 is 2(19d + 17).
Explanation:Factoring out the coefficient of a variable in the expression 38d + 34 involves finding a number that divides both coefficients exactly. The highest common factor (HCF) of 38 and 34 is 2. So, we divide 38 and 34 by 2 to get 19d and 17 respectively.
Therefore, the expression, when factored out, becomes 2(19d + 17). This means that the expression 38d + 34 can thus be factored into 2 times the expression (19d + 17).
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My number has 2 hundreds. The tens digit is 9 more than the ones digit
Can someone help me pls ?
Which equation demonstrates the distributive property? A) 20 + 36 = 56 B) 20 x 36 = 36 x 20 C) 20 + 36 = 4(5 + 9) Eliminate D) (5 + 9)4 = 4(5 + 9)
the music for Alyssa's dance routine last exactly 4 min. when she dances her routine, she starts with her music and finishes 12 seconds before the music ends. what percent of the time the music is playing is Alyssa dancing.
PLZZZ HELP. LOOK IN THE PICTURE BELOW TO ANSWER MY QUESTION.
Solve the system of equations: 12x + 6y = 60 and 3y = -6x + 30
a) (10,0)
b) (0,10)
c) Infinite Solutions
d) No solutions
Please solve this equation 2/5h +g =d for h
PLEASE HELP. Which is the best interpretation of the solution set for the compound inequality? 3/2x-1<2x + 4 or 3(2/3x + 1) < 11 A. no solution B. x > -10 C. x<4 D. all real numbers.
Answer:
D
Step-by-step explanation:
Just did it
If triangle JKL s congruent to triangle RST which congruences are true by CPCTC
the true statements by CPCTC are options A, B, and C. [tex]\( \overline{KL} \cong \overline{ST} \)[/tex] ,[tex]\( \overline{JK} \cong \overline{RS} \)[/tex], [tex]\( \angle K \cong \angle S \)[/tex].
CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent." It means that if two triangles are congruent, then their corresponding parts are also congruent.
Given that △ JKL ≌ △ RST, let's examine each option:
A. [tex]\( \overline{KL} \cong \overline{ST} \)[/tex] - True by CPCTC, corresponding sides of congruent triangles are congruent.
B. [tex]\( \overline{JK} \cong \overline{RS} \)[/tex] - True by CPCTC, corresponding sides of congruent triangles are congruent.
C. [tex]\( \angle K \cong \angle S \)[/tex] - True by CPCTC, corresponding angles of congruent triangles are congruent.
D. [tex]\( \angle L \cong \angle R \)[/tex] - This statement cannot be determined solely from the fact that △ JKL ≌ △ RST. The corresponding angles may or may not be congruent, depending on the specific congruent triangles.
E. [tex]\( \overline{JL} \cong \overline{RS} \)[/tex] - This statement cannot be determined solely from the fact that △ JKL ≌ △ RST. The corresponding sides may or may not be congruent, depending on the specific congruent triangles.
F. [tex]\( \angle J \cong \angle S \)[/tex] - This statement cannot be determined solely from the fact that △ JKL ≌ △ RST. The corresponding angles may or may not be congruent, depending on the specific congruent triangles.
Therefore, the true statements by CPCTC are options A, B, and C.
The complete question is:
If △ JKL≌ △ RST, which congruences are true by CPCTC? Check all that apply.
A. [tex]\( \overline{KL} \cong \overline{ST} \)[/tex]
B. [tex]\( \overline{JK} \cong \overline{RS} \)[/tex]
C. ∠ K≌ ∠ S
D. ∠ L≌ ∠ R
E. [tex]\( \overline{JL} \cong \overline{RS} \)[/tex]
F. ∠ J≌ ∠ S