2/3x + 1/6 = -3/4 x + 1

Rate of speed is rate of change of distance with respect to time, If Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h.

Car A traveled 22 mph faster than Car B. 55mph fast car A travel.

Rate of speed is rate of change of distance with respect to time.

Let the distance be D miles

Car A:-  D = 2.4R   and

for Car B:-   D = 4(R- 22)

therefore 2.4R = 4(R-22)

4R - 88 = 2.4R

4R-2.4R=88

1.6R = 88

R =  55mph  Answer

Therefore car A travels 55mph faster than car B.

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The subject of this question is Physics as it involves the concept of temperature and the change in temperature over time.

The subject of this question is Physics as it involves the concept of temperature and the change in temperature over time.

Step 1: At 1:00, the temperature in Jonestown and Cooperville was the same.

Step 2: By 2:00, the temperature in Jonestown dropped 10 degrees and the temperature in Cooperville dropped 6 degrees.

Step 3: By 3:00, the temperature in Jonestown dropped an additional 8 degrees and the temperature in Cooperville dropped an additional 2 degrees.

Therefore, the subject of this question is Physics and the grade is High School.

The quotient of dividing 18,198 by 27 is 674, as 27 times 674 equals 18,198, leaving no remainder.

The student has asked to find the quotient of the division of 18,198 by 27. To find the quotient, one would typically use long division. After setting up the long division, it turns out that 27 can be divided into 18,198 exactly 674 times, because 27 times 674 equals 18,198.

To solve this, you would write 18,198 as the dividend and 27 as the divisor. Then you would see how many times 27 can go into 181 (the first three digits of 18,198), which is 6 (since 27 x 6 = 162). You write the 6 above the third digit of 18,198, subtract 162 from 181, and bring down the next digit from the dividend, which is 9, making 198. Now you find how many times 27 can go into 198, which is 7 times exactly since 27 x 7 gives you 189. Subtract 189 from 198, and the result is 9, bringing down the last digit 8 to get 98. Finally, you divide 27 into 98 which is 3 times (since 27 x 3 = 81), subtract 81 from 98 to get 17. Since there are no more digits to bring down, we are left with a remainder of 17. Therefore, the quotient is 673 and the remainder is 17.

Answer:

Step-by-step explanation:

Jinni deposited $87.60 every month for 10 months, this represents a total of

[tex]\$87.60(10)=\$876[/tex]

But, she used $25.60 every month to pay for music classes, the total money spent is

[tex]\$25.60(10)=\$256[/tex]

So, she has in her bank account

[tex]\$876 - \$256 = \$620[/tex]

Then, she uses 1/4 of the total money left ($620) to go to a summer camp, which is

[tex]\frac{1}{4}(\$620)=\$155[/tex]

Therefore, she spent $155 to go to the summer camp. So, the right answer is the third option.

The multiplication operation  "attaches" r and t in this formula and division will undo the operation.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

Given the expression,

d = rt

Now rt is the multiplication of r and t it that r × t = rt so by multiplication its attaches.

Now in order to separate both.

Divide by r or t ⇒ d/r = t or d/t = r

Hence "The multiplication operation  "attaches" r and t in this formula and division will undo the operation".

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To find the length of each of the three entertainment segments in a 20-minute TV program with commercials, we subtract the total time of the commercials from the total time of the program and divide the remaining time by the number of segments. This gives a length of 5.5 minutes for each segment.

To determine the length of each entertainment segment in this 20-minute TV program, we first need to subtract the total length of the commercials from the overall program length. The two commercials, each 1 3/4 minutes long, add up to 3 1/2 minutes.

20 minutes (total program length) - 3.5 minutes (total commercial time) = 16.5 minutes left for the entertainment segments.

As there are three equal‐length entertainment segments, we simply divide the remaining time by the number of segments:

16.5 minutes / 3 = 5.5 minutes.

Therefore, each entertainment segment is 5.5 minutes long.

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Each entertainment segment is 5.5 minutes long.

To find the length of each entertainment segment, we need to subtract the total time of the commercials from the total duration of the TV program.

The total time of the commercials is given as 1 3/4 minutes each, which is equivalent to 7/4 minutes each.

So, the total time of the commercials is 2 * 7/4 = 14/4 = 3.5 minutes.

Since we know that the TV program is 20 minutes long, the total time of the entertainment segments can be found by subtracting the time of the commercials from the total duration: 20 - 3.5 = 16.5 minutes.

Since there are three equal-length entertainment segments, we can divide the total time of the entertainment segments by 3: 16.5 / 3 = 5.5 minutes.

Therefore, each entertainment segment is 5.5 minutes long.

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