324 calories in a 3-ounce serving in a unit rate

Answer:

[tex]-7\geq x<12[/tex] and [tex][-7,12)[/tex] in interval notation.

Step-by-step explanation:

We have been given a compound inequality [tex]-7x-50\leq -1\text{ and }-6x+70>-2[/tex]. We are supposed to find the solution of our given inequality.

First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.

[tex]-7x-50\leq -1[/tex]

[tex]-7x-50+50\leq -1+50[/tex]

[tex]-7x\leq 49[/tex]

Dividing by negative number, flip the inequality sign:

[tex]\frac{-7x}{-7}\geq \frac{49}{-7}[/tex]

[tex]x\geq -7[/tex]

[tex]-6x+70>-2[/tex]

[tex]-6x+70-70>-2-70[/tex]

[tex]-6x>-72[/tex]

Dividing by negative number, flip the inequality sign:

[tex]\frac{-6x}{-6}<\frac{-72}{-6}[/tex]

[tex]x<12[/tex]

Upon merging both intervals, we will get:

[tex]-7\geq x<12[/tex]

Therefore, the solution for our given inequality would be [tex]-7\geq x<12[/tex] and [tex][-7,12)[/tex] in interval notation.

Answer:

Step-by-step explanation:

Given is the polynomials as

1) [tex]f(x) = x^3+2x^2-x-2[/tex]

The graph of this function has x intercepts as

-2, -1 and 0

Since f(x) =0 has solutions equivalent to x intercepts we see that the roots are

-2,-1 and 0

2) Given is a polynomial as

[tex]f(x) = 2x^3+5x^2-8x-20 =0[/tex]

Using rational roots theorem we find that

the roots possible are ±1.±2,±4,±5,±10,±20,±1/2,±5/2

Using remainder theorem we see that

f(2) =f(-2)=0

By using division, we find that the other factor is 2x+5

Hence roots are 2,-2, -2.5

The Answer is C 5/6

250/300 reduced and simplified is 5/6

Answer:

The probability that the student is right-handed given that the student is a girl is:

[tex]\dfrac{5}{6}[/tex]

Step-by-step explanation:

From the tree diagram we have to find the probability that the students is right handed given that the student is a girl.

Let A denote the event that the student is a girl.

and B denote the event that the student is right handed.

We are asked to find the probability:

P(B|A)

We know that P(B|A) is calculated as:

[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]

There are a total of 500 students.

Out of which 300 are girls.

( i.e. [tex]P(A)=\dfrac{300}{500}=\dfrac{3}{5}[/tex]    )

and out of 300 girls 250 are right handed.

( i.e. [tex]P(A\bigcap B)=\dfrac{250}{500}=\dfrac{1}{2}[/tex]  )

Hence,

[tex]P(B|A)=\dfrac{\dfrac{1}{2}}{\dfrac{3}{5}}\\\\\\P(B|A)=\dfrac{5}{6}[/tex]

Hence,The probability that the student is right-handed given that the student is a girl is:

[tex]\dfrac{5}{6}[/tex]

1. intersection is all the numbers both sets have in common

 so 3, ,7 , 13

2. union is all the numbers from both sets so 1, 5, 8, 12, 17

Final answer:

To find the decibel rating of sound b, we calculate the decibel difference between sound a and sound b, which is 9.031 decibels. Adding this to the decibel rating of sound a gives us an approximate decibel rating of 34 for sound b.

Explanation:

To find the decibel rating of sound b, we need to determine how many decibels louder it is compared to sound a. We know that sound b is 8 times as loud as sound a, so we can use the formula for decibel difference:

Decibel difference = 10 * log10(intensity ratio)

Since sound b is 8 times as loud as sound a, the intensity ratio is 8. Plugging this into the formula gives:

Decibel difference = 10 * log10(8) = 10 * 0.9031 = 9.031 decibels

To find the decibel rating of sound b, we add the decibel difference to the decibel rating of sound a:

Decibel rating of sound b = Decibel rating of sound a + Decibel difference = 25 + 9.031 ≈ 34 decibels

Answers:

  A. If two angles are linear pairs, the angles are supplementary. The two angles are linear pairs. Therefore, the angles are supplementary.  

 B. If an object is a square, it is a parallelogram. The object is a square. The object is a parallelogram.

 C. If it is snowing, the play will be cancelled. It is snowing. Therefore, the play is cancelled.

  These are right.

Answer:

Law of detachment:

Statement 1: If a, then b

Statement 2: a

Conclusion: b

(A)

1. If two angles are linear pairs, then the angles are supplementary.

2. The two angles are linear pairs.

Let a be the statement " two angles are linear pairs"

let b be the statement "the angles are supplementary"

then, 1 and 2 can be written as;

1. if a , then b

2. a

So, by the law of detachment we can deduce that b is true.

i.e, The angles are supplementary.

(B)

1. If an object is a square, then it is a parallelogram.

2. The object is a square.

Let a be the statement " an object is a square"

let b be the statement "The object is a square"

then, 1 and 2 can be written as;

1. if a , then b

2. a

So, by the law of detachment we can deduce that b is true.

i.e, The object is a parallelogram.

(C)

1. If  it is snowing, then the play will be cancelled.

2. It is snowing.

Let a be the statement "it is snowing"

let b be the statement "the play will be cancelled"

then, 1 and 2 can be written as;

1. if a , then b

2. a

So, by the law of detachment we can deduce that b is true.

i.e, The play is cancelled.

Only option A, B and C  are examples of the Law of Detachment.

Answer: [tex]\angle WXY=125^{\circ}[/tex]

Explanation: Since, a kite has one pair of congruent angles and its main diagonal bisects its opposite angles.

Therefore, According to the given figure,

[tex]\angle WXY=\angle WZY[/tex]

And, WY is the main diagonal which bisects angles ZWX and XYZ.

So, [tex]\angle ZWX =2\times \angle ZWY= 2\times 43^{\circ}=86^{\circ}[/tex]

And, [tex]\angle XYZ =2\times \angle XYW= 2\times 12^{\circ}=24^{\circ}[/tex]

Since, Sum of all angles of a quadrilateral is equal to [tex]360^{\circ}[/tex]

Therefore, [tex]\angle WXY+\angle WZY+\angle XYZ+\angle ZWX=360^{\circ}[/tex]

⇒[tex]2\times \angle WXY+ 86^{\circ}+24^{\circ}=360^{\circ}[/tex]

⇒[tex]2\times \angle WXY=360^{\circ}-110^{\circ}=250{\circ}[/tex]

⇒ [tex]\angle WXY=125^{\circ}[/tex]

fisher has x cars

 sawyer has 3 times as many so he has 3x cars

Answer is B

Answer:     Between $3 and $5, inclusive

Step-by-step explanation:

The total cost of fencing is $996.

Given that David wants to install a fence fence around his garden, and the garden is rectangular and has an area of 240 square feet, and one side of the garden is along the street and is 12 feet long, and for this side of the garden , David will use fencing that costs 18$ per linear foot, while for the other three sides of the garden, David will use fencing that costs 15$ per linear foot, to determine what is the total cost of fencing the following calculation must be made :

Therefore, the total cost of fencing is $996.

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