40 POINTS CORRECT ANSWER
What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons/meter?

91 newtons

63 newtons

–35 newtons

–19 newtons

Answers

Answer 1
F=-kx
so multiple the two numbers together and put a negative sign in front
 F=-19.25

Related Questions

What significant contribution did Lavoisier make to chemistry?

Answers

the answer to this question is He was the first to use scientific experiments to learn about atoms.
Before Lavoisier;s experiment, the concept of atom does not necessarily agreed upon by the chemistry experts because of no concrete proof for it.
This creates a chaotic situation in chemistry field when many scientists believed that they could change the core matters of certain objects. (They spent a huge amount of time trying to transform stones into gold due to unawareness of Atom)

He was the first to use scientific experiments to learn about atoms.

just confirming, all credits go to the other answer

Please help me!
Larry and Balky set up an experiment to analyze the motion of a marble as it rolled down an incline. They started the marble at the top of the ramp and set up photogates to collect data as the marble rolled down the ramp. Which graph format will allow Larry and Balky to calculate instantaneous acceleration from the slope of the graph?

A) Velocity on the y-axis, time on the x-axis
B) Distance on the y-axis, time on the x-axis
C) Time on the x-axis, distance on the y-axis
D) Velocity on the y-axis, distance on the x-axis

Answers

It is A. Im taking the test right now.

Answer :(A) Velocity on the y-axis, time on the x-axis

Explanation :

It is given that, Larry and Balky started the marble at the top of the ramp and set up photogates to collect data as the marble rolled down the ramp.

Acceleration is defined as the rate of change of velocity.

Instantaneous acceleration is defined as the slope of the tangent line. It is also defined as the rate of change of velocity at a particular instant.

To find instantaneous acceleration, it should be a velocity - time graph with velocity on the y-axis and time on the x-axis.

So, the correct option is (A) "Velocity on the y-axis, time on the x-axis".

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with an acceleration of 25.60 m/s2 for 4.20 s, making straight skid marks 62.4 m long, all the way to the tree. With what speed does the car then strike the tree?

Answers

For this problem, we use the formula for rectilinear motion at constant acceleration. The equations are:

x = v₀t + 0.5at²
a = (v - v₀)/t
where
x is the distance
v and v₀ are the final and initial velocities, respectively
a is the acceleration
t is the time

62.4 m = (v₀)(4.20 s) + 0.5(-25.60 m/s²)(4.20 s)²
v₀ = 68.617 m/s

-25.60 m/s² = (v - 68.617 m/s)/4.20 s
v = 38.9 m/s

What kind of front means air masses and their boundaries stop moving?

Answers

Answer:  "a stationary front" .
___________________________________

How could you write an equation for average velocity that would work for finding the average velocity of any object?

Answers

We can define average velocity as,
"the total distance displacement of an object divided by total time taken."

We can say that an object has had displacement if its final position is different from its initial position. Therefore, the formula becomes:

average velocity = total displacement / total time

Keep in mind that displacement is a vector quantity, so it is possible for an object to have covered a distance but if its starting and final positions are the same, then it has had no displacement.

Final answer:

To find the average velocity of any object, use the formula Vavg = (Vo + V) / 2 for constant acceleration or calculus methods for variable acceleration. Average velocity is a vector quantity that represents the total displacement per unit time and is directly proportional to displacement, highlighting its linear relationship.

Explanation:

To write an equation for average velocity that would work for finding the average velocity of any object, we need to understand that average velocity is a vector quantity defined as the total displacement divided by the total time taken for that displacement.

The formula for average velocity, Vavg, when acceleration is constant can be written as Vavg = (Vo + V) / 2, where Vo is the initial velocity and V is the final velocity. For variable acceleration, calculus is used to find the instantaneous velocity at any given point, which can be then integrated over a time interval to get the average velocity.

The relationship between displacement (x), average velocity (Vavg), and time (t) can be demonstrated by the linear equation x = xo + Vavg t, where xo represents initial position. This indicates that displacement is a linear function of average velocity.

The frequency of the middle f note on a piano is 349.23 hz. what is the wavelength of this note in centimeters? the speed of sound in air is 343.06 m/s.

Answers

We are given that: 
Speed of sound in air = 343.06 m/s and frequency f = 349.23Hz. 
Calculating for wavelength using the formula:

Wavelength λ = c / f

wavelength λ = 343.06 / 349.23 = 0.98233 m = 98.233 cm

help with Order of Magnitude question?

The rate of motion of the earth at its equator is about 1,038 mi/h because of its rotation. From this information, estimate the earth's circumference using an order-of-magnitude estimate.

Question 21 options:

2,000 mi


20,000 mi


200,000 mi


2,000,000 mi

Answers

The rotation of Earth is equivalent to one day which is comprised of 24 hours. To determine the number of miles in Earth's circumference, one simply have to multiply the given rate by the appropriate conversion factor and dimensional analysis. This is shown below.
 
                  C = (1038 mi/h)(24 h/1 day)
                   C = 24,912 miles

From the given choices, the nearest value would have to be 20,000 mile. The answer is the second choice. 

In what order do the effort, fulcrum, and resistance appear on a second class lever?

Answers

it should be the effort resistance fulcrum

Estimate the speed at which the average oxygen molecule is moving in the room that you are in

Answers

Using the formula V = (3RT)/M, where "V" is the velocity, "R" is the ideal gas constant, an "M" the molecular mass (expressed in g/mol), and "T" is the temperature (in Kelvin, because I will use an "R" expressed in Kelvin). I would calculate the data as required

V = sqrt((3RT)/M)

The data of my room is:

R= 8,31447 kg * m^2 * s^-2 * K^-1 * mol^-1
M (O2) = 0,032 kg/mol
T = 77 °F - 25 °C - 298 K

Calculating (avoiding units)

V = sqrt((3*8,31447*298)/0,032)
V= 481,96 m/s
Final answer:

The speed of an average oxygen molecule in a room can be estimated using the root-mean-square velocity formula, which indicates that at a room temperature of 300 K, the average speed of oxygen molecules is a few hundred meters per second.

Explanation:

To estimate the speed of an average oxygen molecule in the room at room temperature, we use the concept of root-mean-square (rms) velocity, which is derived from the kinetic theory of gases. At a temperature of about 300 K (room temperature), the kinetic energy of all gas molecules is the same, meaning that lighter molecules move faster than heavier ones. While the molar mass of oxygen is 32.0 g/mol, nitrogen, which composes the majority of air, has a molar mass of 28.02 g/mol. Thus, at the same temperature, oxygen molecules will move more slowly on average than nitrogen molecules.

For oxygen at 300 K, the average speed can be found using the root-mean-square velocity formula: v_rms = \sqrt{(3kT/m)}, where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of a single oxygen molecule. Since the ratio of the molar masses of oxygen and nitrogen is 16.00 to 14.01 and knowing that nitrogen molecules are lighter, they will have a higher average speed compared to oxygen molecules at the same temperature. By using the rms velocity equation, one can calculate that oxygen molecules have an average speed of a few hundred meters per second at room temperature.

How to change meters to kilometers

Answers

There are 1000 meters to kilometers, and so divide x meters with 1000 to get your answer in kilometers

hope this helps
here how to convert metres into kilometres and metres. Dive the number of metres by by 1000, the quotient represents kilometres and remainder represents metres.

An electron travels 1.64 m in 4.32 × 10−8 s. How fast is it traveling? Answer in units of m/s

Answers

Speed = (distance) / (time)

= 3.796 x 10^7 m/s.

Speedy little fella. That's almost 13% of the speed of light.

A football quarterback is moving straight backward at a speed of 3.00 m/s when he throws a pass to a player 20.0 m straight downfield. (a) if the ball is thrown at an angle of 25.0° relative to the ground and is caught at the same height as it is released, what is its initial speed relative to the ground

Answers

16.0 m/s Split the velocities into vertical and horizontal component v = sin(25)*V h = cos(25)*V Since the ball will be caught at the same height as it was released, it's upward and downward movement distances will be the same. And both will take the same amount of time. That time will be the vertical velocity divided by the acceleration due to gravity. So the total time available for the ball will be T = 2*v / 9.8 T = v/4.9 The distance the ball travels is 20.0 meters. And the time it will take is that distance divided by the velocity. So T = 20.0/h We can now set those two equations equal to each other. 20.0/h = v/4.9 Substitute the equations we have to v and h 20.0/(cos(25)*V) = sin(25)*V/4.9 And solve for V 20.0/(cos(25)*V) = sin(25)*V/4.9 98/(cos(25)*V) = sin(25)*V 98/cos(25) = sin(25)*V^2 98/(cos(25)sin(25)) = V^2 255.8598287 = V^2 15.99561905 = V Let's verify. v = sin(25)*15.99561905 = 6.76 m/s h = cos(25)*15.99561905 = 14.50 m/s T = 6.76 / 9.8 * 2 = 1.379591837 s D = 14.50 * 1.379591837 = 20.00 m So if the ball is thrown at a velocity of 16.0 m/s at an angle of 25.0° relative to the ground, it can be caught 20.0 meters away at the same height upon which it was released.
Final answer:

The initial speed of the football can be determined using the equations from projectile motion, considering the horizontal distance of the throw and the angle at which the ball is thrown.

Explanation:

The question is asking to determine the initial speed of the football when thrown by the quarterback. This is a projectile motion question and it involves two dimensions. Given that the quarterback is throwing the ball at an angle of 25.0 degrees and the ball lands at the same height, we can find the initial speed using the horizontal distance of the throw (20.0 m) and the equation for horizontal displacement in projectile motion: x = V0 * t * cos(θ).

Here, we do not have the throwing time (t), and hence, we use another equation from projectile motion where time (t) = [2 * V0 * sin(θ)] / g; where g is the gravity. Substituting this time (t) in the first equation, and solving for V0, we will get the initial speed of the thrown football.

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Problem 2.26 MasteringPhysics 10 of 16 Problem 2.26 When striking, the pike, a predatory fish, can accelerate from rest to a speed of 3.9 m/s in 0.11 s Part B How far does the pike move during this strike? .

Answers

final velocity = initial velocity + (acceleration x time) 
3.9 m/s = 0 m/s + (acceleration x 0.11 s) 
3.9 m/s / 0.11 s = acceleration 
30.45 m/s^2 = acceleration 

distance = (initial velocity x time) + 1/2(acceleration)(time^2) 
distance (0 m/s x 0.11 s) + 1/2(30.45 m/s^2)(0.11s ^2) 
distance = 0.18 m

Answer:

(a). The acceleration is  35.5 m/s².

(b). The distance is 0.214 m.

Explanation:

Given that,

Speed = 3.9 m/s

Time = 0.11 s

We need to calculate the acceleration

Using formula of acceleration

[tex]a = \dfrac{v_{f}-v_{i}}{t}[/tex]

Put the value into the formula

[tex]a =\dfrac{3.9-0}{0.11}[/tex]

[tex]a=35.5\ m/s^2[/tex]

We need to calculate the distance

Using equation of motion

[tex]s = ut+\dfrac{1}{2}at^2[/tex]

Put the value in the equation

[tex]s =0+\dfrac{1}{2}\times35.5\times(0.11)^2[/tex]

[tex]s=0.214\ m[/tex]

Hence, (a). The acceleration is  35.5 m/s².

(b). The distance is 0.214 m.

One sphere has a radius of 5.10 cm; another has a radius of 5.00 cm. What is the difference in volume (in cubic centimeters) between two spheres?

Answers

volume of spher can be calculated using the following rule:
volume of sphere = (4/3) * pi * r^3

for sphere 1:
volume = (4/3)(22/7)(5.1*10^-2)^3
= 5.558*10^-4 m^3

for sphere 2:
volume = (4/3)(22/7)(5*10^-2)^3
= 5.238*10^-4 m^3

it is clear that volume of sphere 1 is greater than volume of sphere 2 with a difference of:
5.558*10^-4 - 5.238*10^-4 = 3.2*10^-5 m^3

A car drives horizontally off a 73-m-high cliff at a speed of 27 m/s. Ignore air resistance. How long will it take the car to hit the ground?

Answers

At the edge of the cliff, the speed of the car will have two components. The x-component, horizontal, is equal to 27 m/s while the y-component, vertical, is equal to zero. With this, the car is seemingly in free-fall.

 The equation that would allow us to answer the question above is,

    d = (V₀)t + 0.5gt²

where d is distance, V₀ is the initial velocity, g is the acceleration due to gravity and t is the time. Substituting the known values,

    73 = (0)(t) + 0.5(9.8 m/s²)(t²)

Vo  equals zero because we only consider the y-component of the vector. Solving for the value of t will give us an answer of 3.86 s.

Answer: 3.86 seconds

Final answer:

To calculate the time it takes for the car to hit the ground when driving horizontally off a cliff, you can use the equation of motion for vertical motion and solve for time. The equation is y = yo + vot + 1/2at^2, where yo is the initial vertical position, vo is the initial vertical velocity, a is the acceleration due to gravity, and t is the time taken. Plug in the given values and solve for t.

Explanation:

To calculate the time it takes for the car to hit the ground, we can use the equation of motion for vertical motion: y = yo + vot + 1/2at^2. Since the car is driving horizontally, the initial vertical velocity vo is equal to zero, and the initial vertical position yo is equal to the height of the cliff, which is 73 meters. The acceleration due to gravity a is approximately -9.8 m/s^2 (negative because it acts in the opposite direction of the car's motion). Plugging in these values, we get:

y = 73 + 0t - 1/2(9.8)t^2

We can solve this equation for t by setting y equal to zero (since the car hits the ground), and solving the resulting quadratic equation. The positive solution will give us the time it takes for the car to hit the ground.

Let me calculate that for you.

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The acceleration produced by a net force on a body is inversely proportional to the mass of the body. true or false

Answers

Hi! This is true because F = mA. If we increase mass, we should expect acceleration to be lower. If we decrease mass, we should expect acceleration to increase. Think of it this way - it is harder to make a heavier person go faster then slower and faster again.

The acceleration produced by a net force on a body is inversely proportional to the mass of the body is true.

What is acceleration?

A net force acting on an object causes it to accelerate, which would be inversely proportional to such mass of the object and therefore directly proportional to the force's size as well as direction.

What is mass?

A physical body's mass would be the total amount of matter it contains. Inertia, or the body's susceptibility to acceleration when a net force would be applied, is another property that may be measured.

It is known that F = ma, hence the acceleration produced by a net force on a body is inversely proportional to the mass of the body.

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Only some shortwave radiation from the sun reaches earth’s surface. what is the leading cause of this radiation loss?

Answers

Final answer:

Only a portion of shortwave radiation from the sun reaches earth's surface mainly due to atmospheric scattering and absorption. The atmosphere's molecules, dust, and aerosols scatter radiation, while gases like oxygen and ozone absorb particularly harmful ultraviolet rays.

Explanation:

Only some of shortwave radiation from the sun reaches the earth's surface due to daily and seasonal variations in the sun's angle above the horizon, the distance between the sun and the earth, and the atmosphere's composition. The leading cause of this radiation loss is atmospheric scattering and absorption.

The atmosphere is made up of molecules, dust, and aerosols which scatter the incoming radiation in different directions. Some of this scattered radiation ends up traveling back out into space. Moreover, atmospheric gases such as oxygen and ozone also absorb a significant portion of shortwave radiation, particularly harmful ultraviolet (UV) rays. This combination of scattering and absorption prevents a significant amount of shortwave radiation from reaching the earth's surface.

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Atmospheric absorption and scattering cause the loss of short wave radiation from the sun, preventing some of it from reaching Earth's surface.

The leading cause of the loss of shortwave radiation from the sun reaching Earth's surface is atmospheric absorption and scattering. When sunlight passes through the Earth's atmosphere, various gases, aerosols, and clouds absorb and scatter shortwave radiation. Water vapor, carbon dioxide, ozone, and particulates absorb specific wavelengths of solar radiation. Additionally, molecules and small particles in the atmosphere scatter sunlight in different directions, leading to diffuse sky radiation.

This absorption and scattering phenomenon cause a significant portion of shortwave radiation to be dispersed or absorbed by the atmosphere before it reaches the Earth's surface. The remaining radiation, once it penetrates the atmosphere, contributes to heating the Earth's surface and drives various processes, such as weather patterns and the Earth's climate system.

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Determine the maximum height and range of a projectile fired at a height of 4 feet above the ground with an initial velocity of 600 feet per second and at an angle of 45° above the horizontal. (round your answers to three decimal places.)

Answers

The maximum height is approximately 602.878 feet, and the range is approximately 1,204.755 feet, rounded to three decimal places.

Certainly, let's calculate the maximum height and range of the projectile.

Given:

Initial height (h₀) = 4 feet

Initial velocity (v₀) = 600 ft/s

Launch angle (θ) = 45 degrees

Acceleration due to gravity (g) = 32 ft/s² (assuming downward as positive)

Vertical Motion:

h = h₀ + v₀ sin(θ) t - 1/2 gt²

At the maximum height, v_y = 0:

v_y = v₀ sin(θ) - gt = 0

Solving for t, we get the time of flight. Once we have t, we can substitute it back into the vertical motion equation to find the maximum height (h).

t = v₀ sin(θ) / g

h = h₀ + v₀² sin²(θ) / (2g)

Horizontal Motion:

R = v₀ cos(θ) * time of flight

R = v₀ cos(θ) * v₀ sin(θ) / g

Now, let's perform the calculations:

t = 600 sin(45°) / 32

t ≈ 5.774 seconds

h = 4 + 600² sin²(45°) / (2 * 32)

h ≈ 602.878 feet

R = 600 cos(45°) * 5.774

R ≈ 1,204.755 feet

the momentum of a moving car can be calculated by multiplying the car's mass by the cars velocity. Which of the following quantities could be correctly calculated momentum.

Answers

Final answer:

The formula for calculating the momentum of a moving object is P = mv, where P is momentum, m is mass, and v is velocity. Momentum is a vector, having both magnitude and direction, and is measured in kg m/s. A larger or faster-moving object will have greater momentum.

Explanation:

The momentum of a moving object, including a car, can indeed be calculated by multiplying the mass of the object by its velocity, as encapsulated in the formula P = mv, where P represents momentum, m represents mass, and v represents velocity. Momentum is a vector quantity, meaning it has both magnitude and direction.

As such, if a car's velocity is in a negative direction (i.e., opposite to the direction of motion), its momentum will also be in a negative direction. Conversely, if the car's velocity is positive, its momentum will also be positive. The SI unit for momentum is kg m/s.

To illustrate this concept, consider a car of mass 1400 kg moving at a speed of 15 m/s. The momentum of this car would be calculated as 1400 kg * 15 m/s = 21000 kg m/s. This example demonstrates that a larger, faster-moving object will have greater momentum than a smaller, slower-moving object.

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Marcus drove his Honda Prelude for 4 hours at a rate of 55 miles per hour. How far did he travel?

Answers

To solve this, you’d multiply 55 by 4, because he is travelling 55 miles every hour, for four hours, which means 55 miles every hour. The answer would be 220.

Answer : Distance covered is 220 miles.

Explanation :

It is given that,

Speed of Marcus's Honda Prelude, [tex]v=55\ miles/hour[/tex]

Time duration, [tex]t=4\ hours[/tex]

We know that the speed of an object is defined as the distance travelled per unit time.

[tex]v=\dfrac{d}{t}[/tex]

or

[tex]d=v\times t[/tex]

[tex]d=55\ miles/hour\times 4\ hours[/tex]

[tex]d=220\ miles[/tex]

Hence, this is the required solution.      

When a certain element is excited with electricity, we see three main lines in its emission spectrum: two red lines and one orange line. what would the absorption spectrum of this element look like?

Answers

the absorption spectrum would have all the wavelengths of the light source but would have black lines where the two red and one orange lines were in the emission spectrum

please help.
four ways of making a network of five capacitors of the same value are shown here. three out of four are identical. the one which is different is

explain your answer

Answers

This is a tough one.
In A, B, and C, there are various routes to get from one end to the other end through 2 or 3 capacitors.
D is the only configuration where it's possible to get from one end to the other through only 1 of them.
I'm not totally confident, but I think D is the one that's not like the others.

How much volume (in cm3) is gained by a person who gains 11.4 lbs of pure fat?

Answers

Final answer:

The volume gained by a person who gains 11.4 lbs of pure fat is approximately 5746.06 cm³, calculated by converting the weight to kilograms and using the density of body fat to find the volume.

Explanation:

To determine the volume gained by a person who gains 11.4 lbs of pure fat, we must first convert the weight gained into kilograms knowing that 1 lb = 0.453592 kg. Therefore, 11.4 lbs equals approximately 5.17145 kg.

Next, we use the fact that the density of body fat is typically around 0.9 g/cm³ (or 900 kg/m³). Thus, the volume V of the fat gained can be found using the formula for density ρ = mass (m) / volume (V), or V = m / ρ.

Substituting the values:

V = 5171.45 g / (0.9 g/cm³)

V ≈ 5746.06 cm³

Therefore, the volume increase from gaining 11.4 lbs of pure fat is approximately 5746.06 cm³.

a long jumper jumps at a 20 degree angle and attains a maximum altitude of 0.6 m

Answers

Refer to the diagram below.

Assume g = 9.8 m/s² and ignore air resistance.

Let V =  the launch velocity.
The horizontal component of the launch velocity is
Vx = V cos(20°) = 0.9397V m/s
The vertical component of the launch velocity is
Vy = V sin(20°) = 0.342V m/s

Let t =  the time to attain the maximum height of 0.6 m.
At maximum height, the vertical velocity is zero, therefore
Vy - 9.8 t = 0
Vy = 9.8t                   (1)

Also,
Vy*t - (1/2)*9.8*t² = 0.6               (2)

Substitute (1) into (2).
(9.8t)*t - 0.5*9.8*t² = 0.6
4.9t² = 0.6
t = 0.35 s

Therefore,
Vy = 9.8*0.35 = 3.43 m/s
V = Vy/0.342 = 10.0292 m/s
Vx = 0.9397V = 9.4244 m/s

The total time of travel is 2t = 2*0.35 = 0.7 s.
The horizontal travel is
d = 9.4244 *0.7 = 6.597 m

Answers:
The time for the jump is 0.7 s.
The length of the jump is 6.6 m (nearest tenth)

a bowling ball has a mass of 5kg. what happens to tis momentum when its speed increases from 1 m/s to 2 m/s

Answers

to find the momentum of an object, you use the equation P=M*V.(p=momentum, m=mass, v=velocity/speed/acceleration.) So, the equation here is P=5kg*2m/s or p=5*2.                                                                                            5*2=10                                                                                                                  P=10: So the momentum of the bowling ball is 10p.

The electric field between two parallel plates has a magnitude of 875 N/C. The positive plate is 0.002 m away from the negative plate. What is the electric potential difference between the plates? 2.3 × 10-6 V 1.8 × 100 V 8.8 × 102 V 4.4 × 104 V

Answers

Given:
E = 875 N/C electric field
d = 00.002 m, distance between parallel plates

Note that
1 V = 1 J/C

The electric potential difference is
[tex]V=E*d \\\\ =(875 \, \frac{N}{C})*(0.002 \, m) \\\\ = 1.75 \, \frac{J}{C} \\\\ =1.75 \, V[/tex]

Answer: 1.8 V (nearest tenth)

Answer : Electric potential, [tex]V=1.8\times 10^0\ V[/tex]

Explanation :

It is given that,

Magnitude of electric field, [tex]E=875\ N/C[/tex]

Distance between two plates, [tex]d=0.002\ m[/tex]

The relation between the electric field and the electric potential is given by :

[tex]E=\dfrac{V}{d}[/tex]

[tex]V=E\times d[/tex]

[tex]V= 875\ N/C\times 0.002\ m[/tex]

[tex]V=1.75\ V[/tex]

or

[tex]V=1.8\times 10^0\ V[/tex]

So, the magnitude of electric potential is given by option (2).

Hence, this is the required solution.                                                                                                

A conducting sphere contains 6.08 trillion excess electrons. what is the magnitude of the charge on the sphere? (in c)

Answers

6.08 Trillion electrons = 6.08x10^12
1electron = 1.6x10^-19c
6.08x10^12e × 1.6x10^-19c = 9.728x10-7 coulomb

This question involves the concept of charge.

The magnitude of the charge on the sphere is "9.728 x 10⁻⁷ C".

Magnitude of Charge

The magnitude of charge on the sphere can be given by the product of the number of excess electrons present on the sphere and the charge on the single electron. Mathematically,

q = ne

where,

q = charge on sphere = ?n = no. of excess electrons = 6.08 trillion = 6.08 x 10¹² electronse = charge on one electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.08 x 10¹²)(1.6 x 10⁻¹⁹ C)

q = 9.728 x 10⁻⁷ C

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A 1776 kg car has a speed of 10.3 m/s when it hits a tree. the tree doesn’t move and the car comes to rest. find the change in kinetic energy of the car. answer in units of j.

Answers

To Calculate the change in kinetic energy based on this formula K.E=1/2mv^2
where m is the mass=1776 kg, and v= the velocity m/s
so, it should =1/2(1776kg)(10.3^2)=94208 j

Answer:

The guy above me is incorrect

Explanation:

What factors affect the speed of a wave? Check all that apply.

Answers

The speed of a wave is dependent upon the properties of the medium through which the wave is moving. An alteration in the properties of the medium will result in a change in the speed at which the wave moves through that medium.The speed of a wave is independent of its frequency and wavelength. A change in the frequency value will not result in a change in the speed value. Rather, changing frequency will result in a change in the wavelength in such a manner that the speed value turns out the same.

It is the last 3.

the temperature of the medium

the type of wave

the type of medium

1. What is the difference between the plasma and gaseous states of matter?
a. The gaseous and plasma states are electrically neutral
b. The gaseous state is electricity positive, while the plasma state is electrically negative.
c. The gaseous state is electricity negative, while the plasma state is electrically negative.
d. The gaseous state is electrically neutral, while the plasma state can be either electrically positive or negative.

2. How is pressure of a gas related to its concentration of particles?
a. Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles.
b. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.
c. Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.
d. Pressure will accelerate a gas, extending its volume and allowing a smaller density and concentration of particles.

Answers

The appropriate answer for number 1 is d. the gaseous state is electrically neutral while the plasma state can be either electrically positive or negative. The appropriate answer for number 2 is c. pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles. 
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