1) At the top of the building, the ball has more potential energy
2) When the ball is halfway through the fall, the potential energy and the kinetic energy are equal
3) Before hitting the ground, the ball has more kinetic energy
4) The potential energy at the top of the building is 784 J
5) The potential energy halfway through the fall is 392 J
6) The kinetic energy halfway through the fall is 392 J
7) The kinetic energy just before hitting the ground is 784 J
Explanation:
1)
The potential energy of an object is given by
[tex]PE=mgh[/tex]
where
m is the mass
g is the acceleration of gravity
h is the height relative to the ground
While the kinetic energy is given by
[tex]KE=\frac{1}{2}mv^2[/tex]
where v is the speed of the object
When the ball is sitting on the top of the building, we have
[tex]h=40 m[/tex], therefore the potential energy is not zero[tex]v=0[/tex], since the ball is at rest, therefore the kinetic energy is zeroThis means that the ball has more potential energy than kinetic energy.
2)
When the ball is halfway through the fall, the height is
[tex]h=20 m[/tex]
So, half of its initial height. This also means that the potential energy is now half of the potential energy at the top (because potential energy is directly proportional to the height).
The total mechanical energy of the ball, which is conserved, is the sum of potential and kinetic energy:
[tex]E=PE+KE=const.[/tex]
At the top of the building,
[tex]E=PE_{top}[/tex]
While halfway through the fall,
[tex]PE_{half}=\frac{PE_{top}}{2}=\frac{E}{2}[/tex]
And the mechanical energy is
[tex]E=PE_{half} + KE_{half} = \frac{PE_{top}}{2}+KE_{half}=\frac{E}{2}+KE_{half}[/tex]
which means
[tex]KE_{half}=\frac{E}{2}[/tex]
So, when the ball is halfway through the fall, the potential energy and the kinetic energy are equal, and they are both half of the total energy.
3)
Just before the ball hits the ground, the situation is the following:
The height of the ball relative to the ground is now zero: [tex]h=0[/tex]. This means that the potential energy of the ball is zero: [tex]PE=0[/tex]The kinetic energy, instead, is not zero: in fact, the ball has gained speed during the fall, so [tex]v\neq 0[/tex], and therefore the kinetic energy is not zeroTherefore, just before the ball hits the ground, it has more kinetic energy than potential energy.
4)
The potential energy of the ball as it sits on top of the building is given by
[tex]PE=mgh[/tex]
where:
m = 2 kg is the mass of the ball
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
h = 40 m is the height of the building, where the ball is located
Substituting the values, we find the potential energy of the ball at the top of the building:
[tex]PE=(2)(9.8)(40)=784 J[/tex]
5)
The potential energy of the ball as it is halfway through the fall is given by
[tex]PE=mgh[/tex]
where:
m = 2 kg is the mass of the ball
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
h = 20 m is the height of the ball relative to the ground
Substituting the values, we find the potential energy of the ball halfway through the fall:
[tex]PE=(2)(9.8)(20)=392 J[/tex]
6)
The kinetic energy of the ball halfway through the fall is given by
[tex]KE=\frac{1}{2}mv^2[/tex]
where
m = 2 kg is the mass of the ball
v = 19.8 m/s is the speed of the ball when it is halfway through the fall
Substituting the values into the equation, we find the kinetic energy of the ball when it is halfway through the fall:
[tex]KE=\frac{1}{2}(2)(19.8)^2=392 J[/tex]
We notice that halfway through the fall, half of the initial potential energy has converted into kinetic energy.
7)
The kinetic energy of the ball just before hitting the ground is given by
[tex]KE=\frac{1}{2}mv^2[/tex]
where:
m = 2 kg is the mass of the ball
v = 28 m/s is the speed of the ball just before hitting the ground
Substituting the values into the equation, we find the kinetic energy of the ball just before hitting the ground:
[tex]KE=\frac{1}{2}(2)(28)^2=784 J[/tex]
We notice that when the ball is about to hit the ground, all the potential energy has converted into kinetic energy.
Learn more about kinetic and potential energy:
brainly.com/question/6536722
brainly.com/question/1198647
brainly.com/question/10770261
#LearnwithBrainly
Answer:
Quest ions
(Score for Question 1: ___ of 7 points)
1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?
Answer: The bowling ball has more potential energy as it sits on top of the building because the force necessary to take the object from greater height will be more than from a lower height. Potential energy is stored energy, so when an object's height changes, its potential falls and becomes lower.
(Score for Question 2: ___ of 7 points)
2. Does the bowling ball have more potential energy or kinetic energy as it is half way through its fall? Why?
Answer: The potential and kinetic energy are the same as it is half way through its fall. The height is 20m half way through the fall, that also means that the potential energy is half of when the ball was at the top of the building.
E= PE + KE,
E= PE at the top,
E= PE half way + KE half way = PE at the top / 2 + KE half way = E / 2 + KE half way,
PE half way= PE at the top / 2 = KE half way = E / 2,
So when the ball is half way the kinetic energy and potential energy are equal, and each is half of the total energy.
(Score for Question 3: ___ of 7 points)
3. Does the bowling ball have more potential energy or kinetic energy just before it hits the ground? Why?
Answer: The bowling ball has more kinetic energy just before it hits the ground because it’s moving faster, and the faster something moves, the more kinetic energy it has.
(Score for Question 4: ___ of 4 points)
4. What is the potential energy of the bowling ball as it sits on top of the building?
Answer:
PE= mgh
Given:
mass= 2 kg,
gravity= 9.8m/s2,
height (where it’s located) = 40m,
PE= (2) (9.8) (40) = 748J
(Score for Question 5: ___ of 4 points)
5. What is the potential energy of the ball as it is half way through the fall, 20 meters high?
Answer:
PE= mgh
Given:
mass= 2 kg,
gravity= 9.8m/s2,
height (where it’s located) = 20m,
PE= (2) (9.8) (20) = 392J
(Score for Question 6: ___ of 3 points)
6. What is the kinetic energy of the ball as it is half way through the fall?
Answer:
KE= ½mv2
Given:
m= 2kg
v (the speed of the ball when it is halfway through the fall) = 19.8m/s
KE= ½ (2) (19.8)2 = 392J
(Score for Question 7: ___ of 3 points)
7. What is the kinetic energy of the ball just before it hits the ground?
Answer:
KE= ½mv2
Given:
m= 2kg
v (the speed of the ball when it is halfway through the fall) = 28m/s
KE= ½ (2) (28)2 = 784J
A block of mass 3.3 kg, sliding on a horizontal
plane, is released with a velocity of 1.8 m/s.
The blocks slides and stops at a distance of
1.5 m beyond the point where it was released.
How far would the block have slid if its
initial velocity were quadrupled?
Answer:
24 m
Explanation:
initial velocity is u = 3.5 m/sec
final velocity is v = 0 m/sec
distance traveled is S = 1.5 m
From kinematic equation [tex]v^{2}-u^{2} = 2as[/tex]
Making acceleration the subject,
[tex]a=\frac {v^{2}-u^{2}}{2s}[/tex]
Acceleration [tex]a = \frac {0^2-3.5^2}{(2*1.5)}= -4.083333333m/s^{2}[/tex]
When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s
V = 0 m/s
[tex]a = -4.083333333m/s^{2}[/tex]
then [tex]S = \frac {v^{2}-u^{2}}{2} = \frac {0^{2}-14^{2}}{2\times -4.083333333} = 24 m[/tex]
What subjects combine to make the field of physical science?
Biology and Physics
Chemistry and Biology
Physics and Chemistry
Earth Science and Chemistry
Final answer:
The field of physical science mainly combines the subjects of Physics and Chemistry, with significant interdisciplinary overlap where these subjects connect with others like Biology and Earth Science. Chemistry, serving as the 'central science,' bridges various areas within the physical and life sciences.
Explanation:
The field of physical science primarily combines the subjects of Physics and Chemistry. Physical science is a broad term that encompasses various sciences dealing with inanimate natural objects and the laws that govern them. It is distinct from the life sciences (like Biology), which concern living organisms. In the interdisciplinary nature of scientific study, there is significant overlap among various fields; Chemistry is often termed the "central science" due to its integral role in connecting physical, earth, and life sciences. Fields such as biochemistry combine principles of Biology and Chemistry, while geophysics might combine Geology with Physics.
Earth Science and Chemistry also have significant overlap, for example in geochemistry. However, when referring specifically to the major branches that make up physical sciences, Physics and Chemistry are the core focus. Additionally, mathematics plays a crucial role across all scientific disciplines, as it provides the language in which scientific laws and phenomena are expressed. This interconnected nature of sciences leads to the creation of various interdisciplinary fields, illustrating the difficulty in drawing distinct boundaries between each scientific discipline.
13. If you have 800 radioactive atoms, and they undergo
14 half-lives, how many will remain? Show your math.
There will be zero radioactive atoms left
Explanation:
The amount of radioactive atoms left of a radioactive sample after a certain time t is given by the equation
[tex]N(t) = N_0 (\frac{1}{2})^{-\frac{t}{\tau}}[/tex]
where
N(t) is the number of radioactive atoms left after time t
[tex]N_0[/tex] is the initial number of radioactive atoms
[tex]\tau[/tex] is the half-life of the sample
In this problem we have:
[tex]N_0 = 800[/tex] (initial number of radioactive atoms)
[tex]t=14 \tau[/tex] (we want to evaluate the number of atoms left after 14 half-lives)
Substituting, we find:
[tex]N(14\tau) = (800)(\frac{1}{2})^{-\frac{14\tau}{\tau}}=0.049[/tex]
This means that there will be zero atoms left, since atoms can't be split in fractional parts.
Learn more about radioactive decay:
brainly.com/question/4207569
brainly.com/question/1695370
#LearnwithBrainly
The catastrophic event shown in this picture formed over water, produced high winds and heavy rains, and brought a large storm surge to New Orleans. The natural disaster displayed in this picture is a:
Group of answer choices
volcano
hurricane.
water spout.
continental drift
Answer:
the answer is b.
Explanation:
cause i took the test
A ball is projected horizontally from a table 1.0 m high and hits the ground after falling from a time t=0.45s. If the ball travels horizontally a distance x = 3.0 m in that time it’s initial velocity was equal to
The initial velocity is [tex]6.7 m/s[/tex]
Explanation:
The motion of the ball is a projectile motion, therefore it consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction
In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by
[tex]x=v_x t[/tex]
where
[tex]v_x[/tex] is the horizontal velocity
t is the time of flight
Here we have:
t = 0.45 s
x = 3.0 m
And so solving for [tex]v_x[/tex], we find
[tex]v_x = \frac{3.0}{0.45}=6.7 m/s[/tex]
And since the ball was initially projected horizontally, this is also the initial velocity.
Learn more about projectile motion:
brainly.com/question/8751410
#LearnwithBrainly
The initial velocity of the ball is 6.67 m/s.
Explanation:To determine the initial velocity of the ball, we need to use the horizontal motion equation, which states that the horizontal distance traveled equals the product of the initial velocity and the time of flight. In this case, the horizontal distance traveled is 3.0 m and the time of flight is 0.45 s. Rearranging the equation, we find that the initial velocity is equal to the horizontal distance divided by the time of flight.
Initial velocity = horizontal distance / time of flight = 3.0 m / 0.45 s = 6.67 m/s
Therefore, the initial velocity of the ball is 6.67 m/s.
Learn more about initial velocity here:
https://brainly.com/question/35479651
#SPJ3
A student is performing an investigation of energy transformation. She places a 500-gram car at point X on a wooden racetrack.
What would be the most likely outcome of a 700-gram car being placed on the racetrack at starting point X?
Group of answer choices
It would have more kinetic energy at the start, resulting in greater potential energy at the bottom of the track.
It would have more potential energy at the start, resulting in greater kinetic energy at the bottom of the track.
It would have less kinetic energy at the start, resulting in less potential energy at the bottom of the track.
It would have less potential energy at the start, resulting in less kinetic energy at the bottom of the track.
It would have more kinetic energy at the start, resulting in greater potential energy at the bottom of the track.
Answer: Option A.
Explanation:
The car at the race track will accelerate at point X. It will have more kinetic energy at the start because the car is at the slope and with time it will result in greater potential energy at the bottom.
As we go down towards the bottom of the track, the kinetic energy will get converted into potential energy because here the body starts coming at rest and is not moving.
Answer:
yall its A
Explanation:
need help today please
6) True: the car is exerting an equal and opposite force on the truck
7) True: the astronaut can drift back by throwing the tool forward
8) True: the bug exerts an equal and opposite force on you
9) Second Law
Explanation:
6)
This problem can be solved by applying Newton's third law of motion, which states that:
"When an object A exerts a force (action) on another object B, then object B exerts an equal and opposite force (reaction) on object A"
In this problem, we can identify the car and the truck as object A and object B. Here we are told that the truck is exerting a force on the car: therefore, according to Newton's third law, the car is also exerting an equal and opposite force on the truck.
Therefore, the statement is true.
7)
This problem can be also solved by thinking in terms of the Newton's third law of motion.
In fact, at the beginning the astronaut is drifting away from the space station. When he throws away the tool, in the forward direction (away from the space station), he exerts a force on the tool: we can identify this force as the action force, and its direction is away from the space station.
As a result, according to Newton's third law, the tool will also exert a reaction force (equal and opposite) on the astronaut: therefore, the force exerted by the tool on the astronaut is toward the space station, and therefore the astronaut will be pushed back towards the station.
Therefore, the statement is true.
8)
Again, this problem can also be explained using Newton's third law.
In fact, the moment you step on the bug, your foot exerts a force (the action force) on the bug, pushing downward.
As a result, according to Newton's third law, the bug exerts back on you an equal and opposite force (upward). The reason you don't feel this force at all is that your mass is much larger than that of the bug, therefore your acceleration is negligible.
Therefore, the statement is true.
9)
This problem can be explained by using Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration. Mathematically:
[tex]F=ma[/tex]
where
F is the net force
m is the mass
a is the acceleration
In this problem, the ball slows down as it crosses the field: this means that it has an acceleration (more precisely, a negative acceleration). According to the law, this means also that there is a net, unbalanced force acting on it, in the direction opposite to the motion of the ball. In fact, this force is the force of friction between the ball and the surface.
Learn more about Newton laws of motion:
brainly.com/question/11411375
brainly.com/question/3820012
#LearnwithBrainly
What are the factors affecting surface tension
Explanation:
Factors affecting surface tension includes;
There are three factors that affect surface tension.
Temperature- the surface tension of a liquid decreases with increase in temperature.
Soluble impurities - the presence of soluble impurities may increase or decrease the surface tension.
Insoluble impurities- insoluble impurities decrease the surface tension.
If a swimmer is traveling at a constant speed of 0.85 m/s, how long would it take to swim the length of a 50-meter Olympic-sized pool?
Answer:
It takes 58.8 seconds to swim the length of a olympic-sized pool.
Explanation:
Uniform Velocity Motion
It describes the situation when an object moves in such a way that it travels equal distances at equal times in the same direction. For example, if it travels x=50 m in t=10 seconds and later it travels x=200 m in t=40 seconds, its speed is constant and equal to v=5 m/s. The relation between the variables x,t, and v is
[tex]x=v.t[/tex]
We know a swimmer is traveling at a constant speed of 0.85 m/s. We are required to find how long would it take him to swim the length of an x=50-meter Olympic-sized pool.
From the above equation, we solve for t
[tex]\displaystyle t=\frac{x}{v}[/tex]
[tex]\displaystyle t=\frac{50\ m}{0.85\ m/s}[/tex]
[tex]\boxed{t=58.8\ s}[/tex]
It takes near 59 seconds to swim the length of a olympic-sized pool
A swimmer would take about 59 seconds to swim the length of a 50-meter Olympic-sized pool when traveling at a constant speed of 0.85 m/s.
Explanation:The time it takes to cover a specific distance traveling at a constant speed can be calculated using the equation time = distance / speed.
In this question, the swimmer is traveling at a constant speed of 0.85 meters per second and the distance to be covered is a 50-meter Olympic-sized pool. To solve the problem we will use the equation stated above:
time = 50 m / 0.85 m/s = 58.82 seconds approximately.
So, at a constant speed of 0.85 m/s, it would take a swimmer about 59 seconds to swim the length of a 50-meter pool.
Learn more about Time-Distance-Speed Calculation here:https://brainly.com/question/35869086
#SPJ3
Which of the following is a free, cloud-based word processor that
allows you to create, edit and collaborate in real-time with other
users?
Select one:
O Windows
O Google Docs
O Cloud Computing
O Operating System
The second option G. Docs is a free, cloud-based word processor that allows you to create, edit, and collaborate in real-time with other users.
Which of the following is a free, cloud-based word processor?G. Docs is a web-based application offered by G.o.o.g.l.e within its suite of office tools. It allows users to create, edit, and store documents online, enabling real-time collaboration. Multiple users can simultaneously work on the same document, making it an excellent tool for collaborative projects. G. Docs automatically saves changes, reducing the risk of data loss, and offers seamless integration with G. Drive for easy storage and sharing of documents. The cloud-based nature of G. Docs eliminates the need for specific operating systems, making it accessible from various devices with internet connectivity.
In summary, the correct answer is G. Docs, a versatile cloud-based word processor that promotes efficient collaboration and accessibility across different platforms.
Read more about processor here:here:https://brainly.com/question/985406
#SPJ3
please help with this assignment paper in science.
I gotta get it done before Monday.
thx.
Explanation:
(a) The net force in the y direction is the sum of the individual forces. Taking up to be +y:
∑F = Lift − Weight
∑F = 100,000 N − 75,000 N
∑F = 25,000 N
(b) Since the net force is not 0, the forces are unbalanced.
(c) Since the lift is greater than the weight, the plane will rise.
(d) The net force in the x direction is the sum of the individual forces. Taking forward to be +x:
∑F = Thrust − Drag
∑F = 200,000 N − 23,000 N
∑F = 177,000 N
(e) Since the net force is not 0, the forces are unbalanced.
(f) Since the thrust is greater than the drag, the plane will accelerate.
A wire 0.57 m long carrying a current of 9.7 A
is at right angles to a uniform magnetic field.
The force on the wire is 0.49 N.
What is the strength of the magnetic field?
Answer in units of T
The strength of the magnetic field is 0.089 T
Explanation:
The force caused by a magnetic field on a current-carrying wire is given by the equation
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
[tex]\theta[/tex] is the angle between the direction of the field and the wire
In this problem, we have
L = 0.57 m
I = 9.7 A
F = 0.49 N
[tex]\theta=90^{\circ}[/tex] since the wire is perpendicular to the field
Solving for B, we find the strength of the field:
[tex]B=\frac{F}{ILsin \theta}=\frac{0.49}{(9.7)(0.57)(sin 90^{\circ})}=0.089 T[/tex]
Learn more about magnetic fields:
brainly.com/question/3874443
brainly.com/question/4240735
#LearnwithBrainly
1.
A person throws a shot put from height of 5 feet with an initial vertical
velocity of 40 feet per second. Use the vertical motion model,
h = -16ť+ vt +s, where v is the initial velocity in feet per
second and s is the initial height in feet, to calculate the amount of
time the shot put is in the air before it hits the ground. Round your
answer to the nearest tenth if necessary.
Time in air:
seconds
The amount of time the shot-put spent in the air before it hits the ground is 3 sec
given the data in the question;
A person throws a shot-put from height, initial height; s = 5ft
Initial vertical velocity or speed; v = 40 ft/s
Now, it is said that, vertical motion model is;
[tex]h = -16t^2 +vt + s[/tex]
so we substitute in the given values
[tex]h = -16t^2 + (40ft/s * t) + 5ft[/tex] --------------Let this be equation 1
To calculate the amount of time the shot-put spent in the air before it hits the ground.
We say: height; h = 0 i.e when the shot-put touches the ground, the height becomes zero.
so we substitute in h=0 in equation 1
[tex]0 = -16t^2 + (40ft/s * t) + 5ft[/tex]
we rearrange
[tex]16t^2 - 40t - 5 = 0[/tex]
To solve for "t", we use the quadratic equation
[tex]x = \frac{-b\±\sqrt{b^2-4ac} }{2a} \\[/tex]
as [tex]ax^2 +bx-c = 0[/tex], we take each value from its position and substitute into the quadratic equation
so
a = 16
b = -40
c = -5
so substitute
[tex]x = \frac{-(-40)\±\sqrt{(-40)^2 - (4*16*(-5)} }{2*16} \\\\x = \frac{40\±\sqrt{1600+320} }{32}[/tex]
[tex]x = \frac{40\±\sqrt{1920} }{32}\\so\\\\x = \frac{40+\sqrt{1920} }{32} or \frac{40-\sqrt{1920} }{32} \\\\x = 2.62\\or\\ x = -0.12\\[/tex]
we know that, time can not be negative,
Hence x = 2.62 ≈ 3 sec { nearest tenth }
Therefore, the amount of time the shot-put spent in the air before it hits the ground is 3 sec
To learn more; https://brainly.com/question/17452424?referrer=searchResults
why do we increase potential difference along power lines
Answer:
The primary reason that power is transmitted at high voltages is to increase efficiency. As electricity is transmitted over long distances, there are inherent energy losses along the way. ... The higher the voltage, the lower the current. The lower the current, the lower the resistance losses in the conductors.
Explanation:
A ball is tied to a 1.3 m string and whirled in a circular motion with a force of 220 N. If its speed is 6 m/s, (a) what is it centripetal acceleration? (b) What is the mass of the ball?
The centripetal acceleration is 27.692 kg m / s^2.
The mass of the ball is 7.94 kg.
Explanation:
The curved path of an object experience a force known as centripetal force. Its direction is always pointing to the motion of the body towards the center of curvature of the path.centripetal force Fc = (mass * square of velocity) / radius
where m represents mass in kg
v represents velocity
r represents radius in a meter.
The acceleration experienced in uniform circular motion is called as centripetal acceleration.It always points toward the center of rotation and is perpendicular to the linear velocity. centripetal acceleration = v^2 / r= (6 * 6) / 1.3
= 27.692 kg m / s^2.
The mass of the ball is found by using the centripetal force formula,
centripetal force Fc = m v^2 / rm = (F * r) / v^2
= (220 * 1.3) / 36
mass of the ball m = 7.94 kg.
Point charge q1 of 30 nC is separated by 50 cm from point charge q2 of -45 nC. As shown in the diagram, point a is located 30 cm from q1 and 20 cm q2. What are the magnitude and direction of the electric field at point a? Let the electrostatic constant k= 8.99 x 10^9 N x m^2/C^2
Answer:
E1 = 2996.667N/C E2 = 11237.5N/C
Explanation:
E1 = kQ1/r^2
=8.99 x 10^9 x 30 x 10^-9/(30x10^-2)^2
= 2996.667N/C
E2 = kQ2/r^2
= 8.99 x 10^9 x 50 x 10^-9/(20x10^-2)^2
= 11237.5N/C
The direction are towards the point a
What is the name for a diagram like this one?
Phytoplankton > Shrimp > Salmon > People
A.) An aquatic habitat
B.) A latitude
C.) A niche
D.) A food chain
Answer:
food chain
Explanation:
The given flow chart or diagram represents a food chain . A food chain is the flow of energy from lower level organism to higher level organism.
What is food chain?In ecology, the food chain is the flow of substance and energy from one organism to another in the form of food. Due to the fact that most species consume more than one kind of animal or plant, food chains locally entangle to form a food web.
The main source of food are plants since they use photosynthesis to turn solar energy into food.A flesh-eating animal consumes a plant-eating species in a predator chain. A smaller organism in a parasite chain takes a portion of a larger host and may also become a parasite on itself.
Here, the phytoplanktons are eaten by shrimps and they are in turen eaten by salmon which is edible to humans. Hence, the diagram represents a food chain.
To find more on food chain, refer here:
https://brainly.com/question/16065961
#SPJ2
NEED HELPP ASAP!!!!
This is when opposite poles of a magnet move toward each other and toward certain types of materials.
the answer is attraction
Ceres has an orbital semi-major axis = 2.768 AU. What is Ceres’ orbital period?
Answer: 4.6 years
Explanation:
According to Kepler’s Third Law of Planetary motion “The square of the orbital period [tex]T[/tex] of a planet is proportional to the cube of the semi-major axis [tex]a[/tex] (size) of its orbit”:
[tex]T^{2}\propto a^{3}[/tex] (1)
However, if [tex]T[/tex] is measured in Earth years, and [tex]a[/tex] is measured in astronomical units (unit equivalent to the distance between the Sun and the Earth), equation (1) becomes:
[tex]T^{2}=a^{3}[/tex] (2)
Knowing [tex]a=2.768 AU[/tex] and isolating [tex]T[/tex] from (2):
[tex]T=\sqrt{a^{3}}[/tex] (3)
[tex]T=\sqrt{(2.768 AU)^{3}}[/tex] (4)
Finally:
[tex]T=4.6 years[/tex] This is Ceres' orbital period
what does voltage describe
Answer:
Voltage describes the potential difference between the two ends of a conductor and thus , more the voltage , more will be the flow of current through the conductor ( more no of electrons and faster speed).
Explanation:
Voltage represents the potential difference between two ends of a conductor, and so the greater the voltage, the greater the current flow through the wire.
What is ohm’s law?Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law
V=IR
Voltage represents the potential difference between two ends of a conductor, and so the greater the voltage, the greater the current flow through the wire.
Hence, Voltage is described as the product of the current and the resistance.
To learn more the ohm's law refer to the link;
https://brainly.com/question/796939
#SPJ2
How does pressure affect surface tension
the effect of pressure on surface tension can be attributed in part to absorption of gas at the surface of the liquid and in part to an intrinsic decrease in density of the liquid in the neighborhood of the surface.
In the case of liquids , Owing to contact forces between the edge of the surface and the vessel, the surface acquires a curvature, and if the liquid rises up at the edges where it meets the vessel, the pressure will be less in the liquid than in the air, for points just below and just above the surface. The vessel exerts an upward force on the liquid. This is simply a matter of looking at the directions of forces acting, knowing that the surface is under tension.
A tablet draws 10.0 A when plugged into a 150-V line. If another tablet has twice as much resistance, what would the current of the second tablet be if plugged into the same line?
0.60 A
1.5 A
5 A
15 A
Answer:
5A
Explanation:
In case 1, I = 10A, V = 150volt
Using Ohms law, V = IR
R = V/I = 150/10 = 15 ohms
Case 2, when R is double
R = 15 ohms
I = V/R = 150/30 = 5A
Answer:
5 A
Explanation:
how is humidity related to air pressure
A.) air pressure is lower below sea level because of the humidity
B.) humid air is lighter, so it has lower pressure
C.) humidity and air pressure are not related
D.) humid air has higher pressure because of the heaviness of water
PLEASE HELP
Answer:
Humid air is lighter so it has lower pressure
Explanation:B.) humid air is lighter, so it has lower pressure
Explanation:
Humidity is related to air pressure in that, a humid air is lighter and it has very low pressure.
Air is heavier than water vapor.
The main component of humid air is water vapor.
Water vapor is mostly water in its gaseous form
We know that for a single mole of water, the mass is 18g
Air is a mixture of gases with Nitrogen gas dominating.
A mole of nitrogen gas has a mass of 28g.
We can see that air that is humid i.e contains more water vapor is lighter and it has a lower pressure.
Greg is in a bike race. At mile marker four (out of ten), his speed was measured at 13.5 mph.
Which best describes the measured number?
It is the average speed of the bike rider.
It is the instantaneous speed of the bike rider.
It is the instantaneous velocity of the bike rider.
It is the average velocity of the bike rider.
Answer:
B: it is the instantaneous speed of the bike rider.
Explanation:
keep it going....
Answer:
B It is the instantaneous speed of the bike rider.
Explanation:
I took the test
An 800-N man stands at rest on two bathroom scales so that his weight is distributed evenly over both scales. The reading on each scale is
400 N
The weight of the man is evenly distributed on each scale
The man's total weight of 800-N, when distributed equally over two bathroom scales, will result in each scale reading 400-N.
Explanation:The man's total weight is 800-N and he is standing on two scales, with his weight distributed evenly. This means each scale will bear half of the total weight. Therefore, the reading on each scale will be 800-N divided by 2. That calculation yields a result of 400-N per scale. So each bathroom scale will show a weight of 400-N, assuming the weight distribution remains equals.
Learn more about Weight Distribution here:https://brainly.com/question/31878218
#SPJ3
The two imaginary lines of latitude that are farthest from the equator are called the
----- and the
North Pole and South Pole.
A skydiver jumped out of a plane, determine distance he distance he descended after 5 seconds. Gravity is pulling him down at 10 m/s^2
The distance travelled in 5 seconds is 125 m
Explanation:
The motion of the skydiver is a free fall motion, since he is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, with constant acceleration downward, and we can find the distance he travels by using the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
In this problem, we have:
u = 0 (the skydiver jumps from rest)
[tex]a=g=10 m/s^2[/tex] (acceleration of gravity)
And substituting
t = 5.0 s
we find the distance travelled:
[tex]s=0+\frac{1}{2}(10)(5)^2=125 m[/tex]
Learn more about free fall:
brainly.com/question/1748290
brainly.com/question/11042118
brainly.com/question/2455974
brainly.com/question/2607086
#LearnwithBrainly
A ball of mass 100g falls from a height of 3m on to a horizontal surface and rebounds to a height of 2m. calculate the change in momentum and the kinetic energy of the ball it strikes the surface
The change in momentum is equal to 1.3928 kg.m/s².
The kinetic energy of the ball as it strikes the surface = 2.94 Joules
Explanation:Given:
Mass of the ball = 100 g = 100 × 10⁻³ kg = m = 0.1 kg
Height from which ball falls = h = 3 m
Height to which the ball rebounds = h' = 2 m
g= acceleration due to gravity = g = 9.8 m/s²
1. A ball dropped from a height of 3 m, hits the horizontal surface and bounces back. This will cause a change in momentum.
The velocity of the ball before hitting the surface and after hitting the surface is different; causing a change in momentum (Δp).
Since momentum (p) = mass (m) × velocity (v) : [tex]p=m\times v[/tex]
Δp = [tex]m\times V_\ after[/tex] [tex]-\ m\times V_\ before[/tex] = [tex]m\times (V_\ after[/tex] [tex]\ -\ V_\ before[/tex] [tex])[/tex] ...........................(1)
Velocity (v) is given by [tex]v = \sqrt{2gh}[/tex]
[tex]V_\ before[/tex] = [tex]\sqrt{2\times g\times h} = \sqrt{2\times 9.8\times 3} = \sqrt{58.8} = 7.668\ m/s^2[/tex]
[tex]V_\ after[/tex] = [tex]\sqrt{2\times g\times h'} = \sqrt{2\times 9.8\times 2} = \sqrt{39.2} = 6.2609\ m/s^2[/tex]
[tex]V_\ before[/tex] is a decreasing quantity (Ball dropped from 3 m) until it becomes equal to [tex]V_\ after[/tex] and hence is a negative vector (negative in sign and opposite in direction to [tex]V_\ after[/tex].)
[tex]V_\ before[/tex] = (-7.668 m/s²)
From (1), for m = 0.1 kg, Δp becomes;
Δp = [tex]m\times (V_\ after[/tex][tex]\ -\ V_\ before[/tex][tex])[/tex] = [tex]0.1( 6.2609 - ( - 7.668)) = 0.1\times 13.9289 = 1.3928\ kg.m/s[/tex]
2. As a ball falls to the surface, its gravitational potential energy is transformed into kinetic energy. This kinetic energy keeps on increasing with increase in momentum until it strikes the surface.
K.E of ball just before it strikes the surface from 3 m height = [tex]K.E = mgh[/tex]
[tex]K.E = 0.1\times 9.8\times 3 = 2.94\ J[/tex]
16. A 7500 kg 18-wheeler traveling at 20 m/s exits onto the runaway truck ramp on the freeway.
When it comes to a stop, it is 10 m higher than before.
How much energy was dissipated by friction?
Answer:
765,000 Joule
Explanation:
Principle of Conservation of Energy
The total energy in an isolated system cannot be created or destroyed, but transformed. Moving objects have kinetic energy, objects placed in some height above a reference level have gravitational potential energy. When they change their motion variables, one energy converts into the other, but if the numbers don't fit, we know there was some other type of energy acting into the system. The most common reason for energy 'losses' is the thermal energy, produced when objects move in rough surfaces or take friction from the air.
The 7,500 kg truck is originally traveling at 20 m/s to a certain height we'll set to 0. Thus, its total energy is
[tex]\displaystyle E_1=\frac{mv^2}{2}[/tex]
[tex]\displaystyle E_1=\frac{7,500\ 20^2}{2}[/tex]
[tex]E_1=1,500,000\ Joule[/tex]
When it comes to a stop, its speed is 0 and its height is 10 m higher than before. It means all the kinetic energy was transformed into other types of energy. The gravitational potential energy is
[tex]U=mgh=(7,500)(9.8)(10)=735,000\ Joule[/tex]
Since this number is not equal to the previous value of the energy, the difference is due to thermal energy dissipated by friction
[tex]E_t=1,500,000\ Joule-735,000\ Joule=765,000\ Joule[/tex]
A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns back to the radar station in 4.8s at a frequency of 240000 hz. How far away from the radar station is the ballon and what direction is it moving?
Answers:
a)The balloon is 68 m away of the radar station
b) The direction of the balloon is towards the radar station
Explanation:
We can solve this problem with the Doppler shift equation:
[tex]f'=\frac{V+V_{o}}{V-V_{s}} f[/tex] (1)
Where:
[tex]f=250,000 Hz[/tex] is the actual frequency of the sound wave
[tex]f'=240,000 Hz[/tex] is the "observed" frequency
[tex]V=340 m/s[/tex] is the velocity of sound
[tex]V_{o}=0 m/s[/tex] is the velocity of the observer, which is stationary
[tex]V_{s}[/tex] is the velocity of the source, which is the balloon
Isolating [tex]V_{s}[/tex]:
[tex]V_{s}=\frac{V(f'-f)}{f'}[/tex] (2)
[tex]V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}[/tex] (3)
[tex]V_{s}=-14.16 m/s[/tex] (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.
Now that we have the velocity of the balloon (hence its speed, the positive value) and the time ([tex]t=4.8 s[/tex]) given as data, we can find the distance:
[tex]d=V_{s}t[/tex] (5)
[tex]d=(14.16 m/s)(4.8 s)[/tex] (6)
Finally:
[tex]d=68 m[/tex] (8) This is the distance of the balloon from the radar station