6. Which of the following is an example of a vector quantity?

Answer:

These 5 principles can be better understood from the past events as well as from formation of the sedimentary rocks

Explanation:

Principle of original horizontal- the sedimentary rocks are found to be horizontal during the initial deposits phase. If  tilted this is due to the subsequent geological event.

Principle of original lateral continuity- The sedimentary beds are originally laterally continuous into their environment of deposition. Faulting in the severe folding and also erosion may leads to the separation of the originally lateral continuous beds which in later becomes separate units.

Principle of cross cutting- The younger features can get cuts across the older features. That's why faults,  erosion, volcanoes etc can be seen. The above mentioned are younger than those materials that is faulted intruded, or eroded.

Principle of inclusion- Inclusion itself means (a rock fragment another rock fragment) they must be older than the materials in.

Principle of uniformity-  Those are the physical process that are been seen today, were also worked in the same way in the geologic past, thus modern methods helps us to understand the ancient events.

Answer:

Kinetic energy of the girl and her bike is 5.544 kJ

Explanation:

Given that a girl is riding bike at speed of 12m/s

Also, mass of Girl is 55kg and mass of bike is 22kg

Let, Total mass of girl and bike be M=22+55=77kg

Now, Kinetic energy is given by K=[tex]\frac{1}{2} Mv^{2}[/tex]

Hence, Kinetic energy of the girl and her bike will be

K=[tex]\frac{1}{2} Mv^{2}[/tex]

K=[tex]\frac{1}{2} (77)(12)^{2}[/tex]

K=5544J

Thus, Kinetic energy of the girl and her bike is 5.544 kJ

2.38Ω

We are given;

We are required to calculate the resistance of the iPhone battery;

R = V/I

Therefore;

R = 5.0 V ÷ 2.1 A

  = 2.38 Ω

Thus, the resistance of the iPhone battery is 2.38Ω

For the resistance of an iPhone battery connected to a 5.0V charger at 2.1A, you can use Ohm's Law to calculate the resistance as approximately 2.38 ohms.

The resistance of a battery is determined using Ohm's Law, where resistance (R) equals voltage (V) divided by current (I). In this case, a 5.0V charger at 2.1A results in a resistance of 2.38 ohms.

Answer:

volume = 0.47 [tex]m^{3}[/tex].

Explanation:

Density:

[tex]d = \frac{m}{v}[/tex]

We have that d = 2700 kg/[tex]m^{3}[/tex] and that we have 1280 kg of Al.

[tex]2700 = \frac{1280}{V}[/tex]

V = 0.47 [tex]m^{3}[/tex]

Answer:

The correct answer is 0.47 m³

Explanation:

The formula for density (d) is

Mass (m) ÷ volume (v)

Hence

d = m ÷ v

The density of aluminium (as provided in the question) is 2700  kg/m³ and the mass of aluminium is 1280 kg, the volume is however unknown.

Thus, from the formula earlier

2700 = 1280 ÷ v

v = 1280 ÷ 2700

v = 0.47 m³

The volume of aluminium when the density is 2700  kg/m³ and the mass is 1280 kg is 0.47 m³

Answer: 13.6 N

Explanation:

The equation of motion for the rabbit is:

[tex]\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2}[/tex] (1)

Where:

[tex]\Delta x=0.85 m[/tex] is the distance traveled by the rabbit

[tex]V_{ox}=0 m/s[/tex] is the rabbit's initial velocity, assuming it started from rest

[tex]t=0.5 s[/tex] is the time

[tex]a_{x}[/tex] is the acceleration

Isolating [tex]a_{x}[/tex]:

[tex]a_{x}=\frac{2 \Delta x}{t^{2}}[/tex] (2)

[tex]a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}}[/tex] (3)

[tex]a_{x}=6.8 m/s^{2}[/tex] (4)

On the other hand, the force [tex]F_{x}[/tex] is given by:

[tex]F_{x}=m.a_{x}[/tex] (5)

Where [tex]m=2 kg[/tex] is the mass of the rabbit

Substituting (4) in (5):

[tex]F_{x}=(2 kg)(6.8 m/s^{2})[/tex] (6)

Finally:

[tex]F_{x}=13.6 N[/tex]

Answer:

400 m/s

Explanation:

From the question;

We are required to calculate the speed of the wave;

Speed of the wave = 200 Hz × 2 m

                               = 400 m/s

Answer:

0. 1226495726kg

Explanation:

Force is the product of mass and acceleration.

Mathematically,

Force(F) = mass (m)×acceleration(a)

Substituting the values into the equation

2. 87=m×23. 4

2. 87=m (23. 4)

2. 87/23. 4=m (23. 4)/23. 4

2. 87/23. 4=m

0. 1226495726=m

Answer:

Answer:

0. 1226495726kg

Explanation:

Force is the product of mass and acceleration.

Mathematically,

Force(F) = mass (m)×acceleration(a)

Substituting the values into the equation

2. 87=m×23. 4

2. 87=m (23. 4)

2. 87/23. 4=m (23. 4)/23. 4

2. 87/23. 4=m

0. 1226495726=m

Explanation:

The arguments for and against the theory that animals have the capacity for language, like humans, revolve around communication abilities and linguistic complexity. Some argue that animals can communicate using complex systems of signs, sounds, and gestures, while others claim that their communication lacks the complexity and structure of human language.

There are arguments both for and against the theory that animals have the capacity for language, like humans. Some argue that animals do have the capacity for language based on their ability to communicate with each other and with humans using complex systems of signs, sounds, and gestures. For example, dolphins use a system of clicks and whistles to communicate with each other. Some primates have been taught sign language and can use it to communicate with humans.

On the other hand, some argue that animals do not have the same capacity for language as humans. They point out that while animals can communicate, their communication lacks the complexity and structure found in human language. Animal communication is often limited to simple signals or gestures, rather than the complex syntax and grammar of human language.

Additionally, animals do not exhibit the same level of linguistic creativity and symbolic thought as humans. For example, humans can use language to discuss abstract concepts, tell stories, and express emotions, whereas animals typically use communication for more practical purposes such as signaling danger or finding food.

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Answer:

[tex]0.01132 g/mm^{3}[/tex]

Explanation:

Density, [tex]\rho=\frac {m}{v}[/tex]

Where m is the mass of the object and v is the volume of the same object

Given the dimensions, we can make them in mm hence 45 mm by 52 mm by 60 mm

Volume=45*52*60= 140400 mm^{3}

Density, [tex]\rho=\frac {1590}{140400}=0.011324786 g/mm^{3}\approx 0.01132 g/mm^{3}[/tex]

Answer:

Your mother can tell you that answer

Explanation:

Answer:

When light is reflected, the "outgoing" ray is also called the reflected ray.

Explanation:

when an light ray is incident on a boundary of two mediums it an reflect or refract.

reflected ray is the part of the ray that gets back with same mediu that it was coming from. angle of reflection and incident are equal . angle of reflection and incident are the angle made by the reflected and incident ray with the normal.

total internal reflection occurs when the incident angle is greater than the critical angle of pair of given medium and when light travels from denser to rarer medium . in total internal reflection ray gets reflected with no loss at all.

in refracted ray the the light ray passes to the other medium angle of incidence and refraction are not same.

Answer:

9.05 W

Explanation:

The given formula is [tex]r=\sqrt {\frac {P}{0.02\pi}}[/tex] where r is in centimeters and P is in Watts

Making Power, P the subject from the above formula

[tex]P=0.02\pi r^{2}[/tex]

Substituting r with 12 cm then

[tex]P=0.02\pi 12^{2}= 9.047786842  W\approx 9.05 W[/tex]

Final answer:

A cell with a radius of 12 cm produces approximately 2.88π watts of power.

Explanation:

The given equation relates the power P produced by a circular solar cell to the radius r of the cell. To find the power produced by a cell with a radius of 12 cm, you can substitute this radius value into the equation.

Using the equation r = √(p / (0.02π)), we have r = √(p / (0.02π)). Plugging in r = 12 cm, we can solve for P.

12 = √(p / (0.02π)) ⇒ [tex]12^2[/tex] = p / (0.02π),

or 144 = p / (0.02π).

Multiplying both sides of the equation by (0.02π), we get:

2.88π = p.

Therefore, a cell with a radius of 12 cm produces approximately 2.88π watts of power.

322.5 joules

Data given;

We are supposed to determine the amount of heat required.

In this case, specific heat, c of gold is 0.129 J/g/°C

Mass of gold in grams is 100 g

Therefore;

Q = 100 g × 0.129 J/g/°C × 25°C

   = 322.5 joules

Thus, the amount of heat required is 322.5 Joules

The object that I did choose to put on the skateboard ​ is a sticky ball.

A sports scientists is said to have confirmed that skateboarding is seen to be a very goof and complete workout.

Note that  It not only functions along the cardiovascular system and it also helps to create muscular strength. The core of a skateboarder is seen as very crucial role.

The object that I did choose to put on the skateboard ​ is a sticky ball and it is one where i can measure the velocity as well as the speed taken.

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The magnitude of the total momentum of the system of two cars, each with a mass of 1100 kg and moving east at 30 m/s and 15 m/s respectively, is 49500 kg·m/s east.

To calculate the total momentum of the system consisting of two cars driving east, you need to use the formula for momentum, which is the product of mass and velocity (p = mv). The momentum of each car is calculated separately and then added together since they are moving in the same direction (east).

For the first car with a mass of 1100 kg moving at 30 m/s, its momentum is:

p1 = m1 * v1 = 1100 kg * 30 m/s = 33000 kg·m/s.

For the second car with the same mass of 1100 kg but moving at 15 m/s, its momentum is:

p2 = m2 * v2 = 1100 kg * 15 m/s = 16500 kg·m/s.

The total momentum of the system is the sum of the momenta of both cars:

total p = p1 + p2 = 33000 kg·m/s + 16500 kg·m/s = 49500 kg·m/s.

Therefore, the magnitude of the total momentum of the system is 49500 kg·m/s to the east.

1) The acceleration of the plane is 1.89 times the acceleration of gravity

2) The force acting on the airplane is [tex]2.22\cdot 10^5 N[/tex]

Explanation:

1)

The acceleration of the plane is given by

[tex]a=\frac{v-u}{t}[/tex]

where

v is the final velocity of the plane

u is the initial velocity

t is the time elapsed

For the airplane in this problem, we have:

[tex]u=0[/tex] (it starts from rest)

[tex]v=200 km/h \cdot \frac{1000 m/km}{3600 s/h}=55.6 m/s[/tex] is the final velocity

[tex]t=3 s[/tex] is the time

Substituting, we find

[tex]a=\frac{55.6-0}{3}=18.5 m/s^2[/tex]

The acceleration of gravity is

[tex]g=9.8 m/s^2[/tex]

So, the acceleration of the plane relative to [tex]g[/tex] is

[tex]\frac{a}{g}=\frac{18.5}{9.8}=1.89[/tex]

2)

The average force exerted on the plane is given by Newton's second law:

[tex]F=ma[/tex]

where

F is the force

m is the mass of the airplane

a is the acceleration

In this problem, we have

[tex]m=12000 kg[/tex] is the mass of the plane

[tex]a=18.5 m/s^2[/tex] is the acceleration

Substituting, we find:

[tex]F=(12000)(18.5)=2.22\cdot 10^5 N[/tex]

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The actual volume of the liquid is [tex]50 cm^2[/tex]

Explanation:

When doing a measurement, there are two types of errors that we can define:

In this problem we have:

[tex]E_a=0.6 cm^2[/tex] (absolute error)

[tex]E_r = 1.2\%[/tex] (relative error)

Using the formula for the relative error, we can find the actual value of the volume of the liquid:

[tex]V=\frac{E_a}{E_r}\cdot 100 = \frac{0.6}{1.2}\cdot 100 =50 cm^3[/tex]

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Answer:

Its C waxing gibbous

Explanation:

Answer:

Overall net force is zero.

Explanation:

Given:

Susan exercise for 1 hour at constant velocity and constant speed.

So, there is no change in the velocity for 1 hour.

We know that, acceleration is the quantity that measures the change in velocity over a given time interval. If there is no change in velocity or if velocity remains constant for a given time interval, then the acceleration of the body is zero.

Now, from Newton's second law, we know that, the net force acting on a body is directly proportional to its acceleration. Therefore, for a body to experience zero acceleration means that the body will have zero net force.

Susan here exercises at constant velocity and so, her net acceleration is zero. Therefore, the overall net force acting on her will also be zero as net force is directly proportional to the acceleration.

Final answer:

In an ideal scenario ignoring external factors, the overall net force acting on Susan while she runs at a constant speed and velocity is zero, as per Newton's first law of motion.

Explanation:

The question is concerned with a scenario where Susan is running at a constant speed and velocity, implying that she is not accelerating. According to Newton's first law of motion, also known as the law of inertia, an object in motion at a constant velocity will remain in motion at that velocity unless acted upon by a net external force. Since Susan is running at a constant speed and velocity, this means there is no net external force acting on her because all forces are balanced.

Based on Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (Fnet = ma), and given that Susan is not accelerating (acceleration is zero), the net force acting on her is also zero. This assumes ideal conditions where external factors like air resistance and friction are negligible or perfectly balanced by Susan’s forward force.

Answer:

4.4 m/s

Explanation:

Angular momentum is:

L = Iω

For a point mass, this can also be written as:

L = mvr

Angular momentum is conserved, so:

L₁ = L₂

m₁ v₁ r₁ = m₂ v₂ r₂

(2 kg) (1.1 m/s) (0.6 m) = (2 kg) v (0.15 m)

v = 4.4 m/s

If light refracts toward the normal when passing from water to an unknown medium, it indicates that the unknown medium has a higher index of refraction than water.

When light waves travel through water and encounter a boundary with another medium at a non-normal angle, they undergo refraction. If the medium has an index of refraction higher than that of water, the light waves slow down, bending toward the normal due to the change in speed. According to Snell's law, the path of light is dependent on the indices of refraction of the two media and the angle of incidence. In this case, if the angle of refraction is closer to the normal compared to the angle of incidence, it indicates that the unknown medium has a higher index of refraction than water.

Answer:

c. Velocity

Explanation:

Velocity is a measure of change of position of the body with time. Change of position means the distance traveled by the object in a given interval of time but in a particular direction.

We know that speed is given as the distance traveled over a given time interval without taking into account the direction of motion. So, the magnitude of velocity is same as its speed. Velocity, being a vector quantity, has both magnitude and direction.

Therefore, the velocity of an object consists of its speed and direction.

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

The relationship between velocity and centripetal force is a nonlinear square relationship.

The centripetal force is given by;

F = mv^2/r

The centripetal force is the force required to keep an object moving in a circular path.

If we take the relationship between the centripetal force and velocity as we can see in the equation above, we realize that it is a nonlinear square relationship. Therefore, the relationship between velocity and centripetal force is a nonlinear square relationship.

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Answer:

8100 J

Explanation:

KE = ½ mv²

KE = ½ (50 kg) (18 m/s)²

KE = 8100 J

Work is the amount of energy transferred

Explanation:

In physics, work is a measure of the energy transfer occurring in a process. Typically, we talk about work when energy is converted from one form into another.

For instance, work is done when a force is applied on an object. The work done on the object is given by:

[tex]W=Fd cos \theta[/tex]

where

where

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

We notice the following:

Whenever work is done, there is also an energy transfer taking place. For instance, in the previous example, when the force is applied to the object, the object will accelerate (assume there is no friction), and will gain kinetic energy: therefore, there is a transfer of energy to the object.

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Answer:

KSHE [tex]94.7[/tex]

Explanation:

Given stations WIL [tex]92.3[/tex] and KSHE [tex]94.7[/tex]

The station number represents the frequency that waves of radio emit. They are measured in megahertz (MHZ).

Using the formula  

[tex]E=h\nu[/tex]

Where [tex]E[/tex] is energy.  

[tex]h[/tex] is Planck's constant.

[tex]\nu[/tex] is frequency.

We can see energy is directly related to frequency. A higher frequency will give higher energy.  

As channel KSHE [tex]94.7[/tex] has more frequency than channel WIL [tex]92.3[/tex].  

So, channel KSHE [tex]94.7[/tex] will have more energy.

The horizontal velocity D. remains constant throughout the fall.

Explanation:

The motion of the rock off the cliff is a projectile motion, which consists of two independent motions:

Here in this problem, we are only interested in the horizontal velocity. We said that the horizontal acceleration of the rock is zero: therefore, the horizontal velocity of the rock remains constant during the fall. (if the air drag was not negligible, then it would affect the horizontal velocity, which would decrease as the rock falls).

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Answer: 286.33

Explanation:

multiplay them

1) It means that the ratio [tex]\frac{\Delta L}{L}[/tex], where [tex]\Delta L[/tex] is the change in length of the material and L is the original length, change by 0.000017 units for an increase in temperature of 1 Kelvin.

2) The safety gap between two successive bars is 0.33 mm

Explanation:

1)

When a solid material is heated and its temperature increases, the material expands. The linear expansivity of the material gives a measure of how much the length of the material increases per unit temperature change.

For instance, the linear expansivity of copper is

[tex]\alpha = 0.000017/K[/tex]

which means that the ratio [tex]\frac{\Delta L}{L}[/tex], where [tex]\Delta L[/tex] is the change in length of the material and L is the original length, change by 0.000017 units for an increase in temperature of 1 Kelvin.

In formula, this can be rewritten as

[tex]\frac{\Delta L}{L} = \alpha \Delta T[/tex]

where [tex]\Delta T[/tex] is the change in temperature of the material.

2)

To solve this part of the problem, we can use the formula given in the previous part:

[tex]\frac{\Delta L}{L} = \alpha \Delta T[/tex]

Which can be rewritten as

[tex]\Delta L =L \alpha \Delta T[/tex]

where in this case, we have:

L = 3 m is the original length of the steel bar

[tex]\alpha = 1.0\cdot 10^{-5} /K[/tex] is the linear expansivity of steel

[tex]\Delta T = 40^{\circ}C-29^{\circ}C=11^{\circ}C[/tex] is the increase in temperature of the steel bar

Therefore, by solving the formula for [tex]\Delta L[/tex], we find the increase in length of the steel bars when the temperature increases to 40 degrees:

[tex]\Delta L = (3)(1.0\cdot 10^{-5})(11)=3.3\cdot 10^{-4} m = 0.33 mm[/tex]

This means that the safety gap between two successive bars must be 0.33 mm.

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It travels faster at higher temperature. Longitudinal wave is a wave in which the vibration of the particles travels in the parallel direction to the propagation of wave. Therefore, the common characteristic between transverse wave and longitudinal is both move faster at higher temperature.

Transverse waves and longitudinal waves are both types of mechanical waves that propagate through a medium.

Wavelength is a fundamental property of waves, including electromagnetic waves like light and radio waves, as well as other types of waves, such as sound waves or water waves.

One commonality between transverse and longitudinal waves is that they both involve the transfer of energy through a wave. In both cases, the energy is carried by the disturbance of the medium, whether it is a series of crests and troughs in a transverse wave or a series of compressions and rarefactions in a longitudinal wave.

Another commonality is that both types of waves can exhibit properties such as reflection, refraction, diffraction, and interference. These phenomena occur as the wave interacts with boundaries, obstacles, or other waves, and they can affect the behavior and properties of the wave.

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