A 3.87mg sample of an organic compound gave 5.80mg CO² and 1.58mg h²O on combustion. Deduce the empirical formula of the compound.​

Answer:

will be lower than the true value.

Explanation:

So, the value of the estimated concentration of acetic acid will be lower than the true value.

Answer:

1) 1.235 g.

2) 0.61 g.

Explanation:

Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O.

1.0 mol of Al(OH)₃ reacts with 3.0 moles of HCl to produce 1.0 mol of AlCl₃ and 3.0 moles of H₂O.

1) How many grams of HCl can a tablet with 0.880 g of Al(OH)₃ consume?

no. of moles of Al(OH)₃ = mass/molar mass = (0.880 g)/(78.0 g/mol) = 1.13 x 10⁻² mol.

∵ Every 1.0 mol of Al(OH)₃ needs 3.0 moles of HCl to be consumed.

∴ 1.13 x 10⁻² mol of Al(OH)₃ needs (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of HCl.

The no. of grams of HCl = no. of moles of HCl x molar mass of HCl = (3.385 x 10⁻² mol)(36.5 g/mol) = 1.235 g.

2) How much H₂O?

∵ Every 1.0 mol of Al(OH)₃ produces 3.0 moles of H₂O.

∴ 1.13 x 10⁻² mol of Al(OH)₃ produces (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of H₂O.

The no. of grams of H₂O = no. of moles of H₂O x molar mass of H₂O = (3.385 x 10⁻² mol)(18.0 g/mol) = 0.6092 g ≅ 0.61 g.

The job duties of a forensic toxicologist include: Evaluating determinants or contributory factors in the cause and manner of death. Performing human-performance forensic toxicology, determining the absence or presence of drugs and chemicals in the blood, hair, tissue, breath, etc

Answer:

c- parallel circuit

Explanation:

C

Circuits with multiple paths between the power source and devices are called parallel circuits.

I am assuming you forgot to include the unit of molarity, M, at the end of 0.500.

Molarity's formula is M=moles solute/liters solution.

We are given molarity and liters so we can rearrange the equation to solve for moles solute. Therefore:

moles solute=molarity * liters solution

moles solute= 0.500M * 0.035L = 0.0175

Thus there are 0.0175 mols of H2SO4 in 0.035L of a 0.500M solution.

Phosphorus tribromide

PBr₃ is a covalent compound consisting of phosphorus and three bromine atoms, named phosphorus tribromide. It is classified as covalent because both elements are nonmetals.

Naming PBr₃ involves understanding the types of bonds present and the rules for naming compounds:

Prefixes for Covalent Compounds: Since there's only one phosphorus atom, no prefix is needed for the phosphorus part. For bromine, the prefix "tri-" is used because there are three bromine atoms in PBr₃.

Putting it all together, the name for PBr₃ is phosphorus tribromide.

Answer:

[H₃O⁺] = 0.05 M & [OH⁻] = 2.0 x 10⁻¹³.

Explanation:

HNO₃ + H₂O → H₃O⁺ + NO₃⁻.

[H₃O⁺] = 0.05 M.

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/0.05 = 2.0 x 10⁻¹³.

Hi :)

20 mol NH3 x 6 H2O/4 NH3 = 30 mol H2O

Hope this helped :)

The Sun's layer extending into space in the associated picture is most likely the Corona, defined by its high temperatures and visible halo during a solar eclipse.

The layer of the Sun that is depicted as extending into space in the picture above is most likely the Corona. This is the Sun's outermost layer and it extends millions of kilometers into space. The Corona is distinctive for its high temperatures (over 1 million Kelvin) and its white, halo-like appearance during a solar eclipse. It's important to note that the other layers - Radiative zone, Convective zone, and Photosphere, are located within the Sun and thereby not visible or extensible into space.

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The statement is an atom consists of protons, electrons, and neutrons.

I think the answer is the first one.

Hope this helps.

The scientist that was the first to use the telescope in astronomy was Newton

Answer:

1. Heterogeneous: Mixtures in which composition is not uniform throughout. For example, soil.

2. Homogeneous: Mixtures that have uniform composition throughout. For example, air.

3. Solute: the component of a solution which is present in smaller quantity. For example, Sugar in water

4. Solvent: the component of a solution which is pr3esent in larger quantity. For example, water

5. Solution: A solution is a homogeneous mixture of two or more substances. For example brass.

6. Mixture: When two or more compounds or elements mix up physically they from a mixture.

7. Colloid: Solutions in which particles are large and possess the characteristics of the Tyndall effect. For example milk.

8. Dissociation: the splitting of a molecule into smaller molecules is called dissociation.

9. Pure substance: A pure substance is a type of matter having definite properties.

10. Suspension: Suspensions are heterogeneous mixtures of undissolved particles. For example milk of magnesia.

11. Element: element is a substance made up of the same number of atoms.For example hydrogen

12. Compound: Compound is a substance made up of two or more elements. For example water.

12. Compound is defined as a substance formed when two or more atoms are chemically bonded together.

These atoms can be of the same or different elements, and they create a unique chemical structure with properties distinct from the individual elements. Compounds cannot be separated into their constituent elements through physical means; rather, they require chemical reactions to break the bonds between the atoms.

Because compounds are formed through chemical bonding, they are considered pure substances, as they exhibit consistent and uniform properties throughout. An example of a compound is water (H₂O), which consists of two hydrogen atoms and one oxygen atom bonded together.

D, air bags protect people during car crashes

Answer: Option (c) is the correct answer.

Explanation:

A chemical reaction is defined as the reaction that leads to formation of new substances through exchange of electrons.

For example, [tex]2Al + 3CuCl_{2} \rightarrow 2AlCl_{3} + 3Cu[/tex]

Here, aluminium on displacing copper from copper chloride leads to the formation of a new compound, that is, aluminium chloride.

Hence, it shows that atoms of reactant molecules rearrange themselves to form new substances.

Thus, we can conclude that during a chemical reaction atoms of reactants rearrange to form new substances .

Givens

m = 2.26 g

c = 4.19 J/(g * oC)

Δt = 23.5oC - 0 = 23.5oC

hf = heat of fusion for ice = 334 J/g

Equation

H = m*c*Δt +  hf * m

H = m*(c*Δt + hf)

Solution

H = 2.26 * (4.19 * 23.5  + 334)

H = 2.26 * (432.5)

H = 977.4 J

The liquid water is being converted to ice and heat is being released by the system. To calculate the amount of heat released, use the formula Q = mc∆T. Given the mass of water and the specific heat capacity, you can calculate the heat released.

In this process, the liquid water is being converted to ice. The change in temperature from 23.5 ℃ to 0 ℃ indicates that heat is being released by the system. To calculate the amount of heat released, we can use the formula Q = mc∆T, where Q is the heat released, m is the mass of water, c is the specific heat capacity of water, and ∆T is the change in temperature. Given that the mass of water is 2.26 g and the specific heat capacity of water is 4.184 J/g ℃, we can calculate the heat released.

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Each element or compound has a molar mass, which is calculated by multiplying the atomic mass of each element by the amount of atoms of that element, and summing the results of each element. The molar mass is measured in g/mol. So you divide the mass in grams by the molar mass to get the amount of moles.

Example:

There are 5g of water.

Calculate the amount of moles.

The water's formula is H2O, so the molar mass of it is

[tex]2 \times 1 + 1 \times 16 = 18[/tex]

g/mol.

The amount of moles is:

5g ÷ 18g/mol ~ 0.28mol

To convert grams to moles, determine the molar mass of the substance, then divide the mass in grams by the molar mass to find the number of moles.

Converting from grams to moles is a fundamental skill in chemistry that involves using the molar mass of a substance as a conversion factor. The molar mass can be found on the periodic table and is commonly expressed in grams per mole (g/mol). Here’s how you can convert grams to moles:

For instance, to convert from grams to moles of I2, you would divide the given mass of I2 by its molar mass, resulting in the number of moles (e.g., 0.363 mol).

These steps can be part of a more extensive mole-mass calculation, but this simple conversion involves only the molar mass to convert between grams and moles directly.

The theoretical percentage of oxygen in the calcium chlorate compound Ca(ClO3)2 is calculated by first finding the total molar mass of the compound and the molar mass of the oxygen within it. The molar mass of the entire compound is 206.98 g/mol, while the cumulative oxygen mass is 96.00 g/mol. The percentage of oxygen is therefore about 46.38%.

To calculate the theoretical percentage of oxygen in Ca(ClO3)2, you first have to know the molar mass of the compound and the molar mass of the oxygen in it. The molar mass of Ca(ClO3)2 is 206.98 g/mol, and oxygen appears 6 times (3 atoms per chloride ion and 2 chloride ions per formula unit), so the cumulative oxygen mass is 6*16.00 g/mol, or 96.00 g/mol. The percentage of oxygen can thus be calculated as (mass of oxygen / total mass) * 100%, or (96.00 g/mol / 206.98 g/mol) * 100% = approximately 46.38%.

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First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

c=5.85 mol/L

n=V×c=0.06×5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2×Ar(H) + Ar(S) + 4×Ar(O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

m=0.351 × 98 = 34.398 g

The mass of H2SO4 contained in 60.00 mL of a 5.85 M solution is 34.57 grams.

To find the mass of H2SO4 in the solution, we can use the molarity equation, which is:

[tex]\[ M = \frac{n}{V} \][/tex]

First, we need to calculate the number of moles of H2SO4 in the solution using the given molarity and volume:

[tex]\[ n = M \times V \][/tex]

 The volume given is 60.00 mL, which we need to convert to liters:

[tex]\[ V = 60.00 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.06000 \text{ L} \][/tex]

Now, we can calculate the number of moles of H2SO4:

[tex]\[ n = 5.85 \text{ M} \times 0.06000 \text{ L} = 0.351 \text{ moles} \][/tex]

Next, we need to find the molar mass of H2SO4, which is the sum of the atomic masses of hydrogen (1.008 g/mol, twice because there are two hydrogen atoms), sulfur (32.065 g/mol), and oxygen (15.999 g/mol, four times because there are four oxygen atoms):

[tex]\[ \text{Molar mass of H2SO4} = 2 \times 1.008 \text{ g/mol} + 32.065 \text{ g/mol} + 4 \times 15.999 \text{ g/mol} \][/tex]

[tex]\[ \text{Molar mass of H2SO4} = 2.016 \text{ g/mol} + 32.065 \text{ g/mol} + 63.996 \text{ g/mol} \][/tex]

[tex]\[ \text{Molar mass of H2SO4} = 98.077 \text{ g/mol} \][/tex]

Finally, we can calculate the mass of H2SO4 using the number of moles and the molar mass:

[tex]\[ \text{Mass} = n \times \text{Molar mass} \][/tex]

[tex]\[ \text{Mass} = 0.351 \text{ moles} \times 98.077 \text{ g/mol} \][/tex]

[tex]\[ \text{Mass} = 34.57 \text{ grams} \][/tex]

Therefore, the mass of H2SO4 in the solution is 34.57 grams.

Answer:

Explanation:

Group 2 metals

Answer:

strontium

Explanation:

Ionic compounds have high enthalpy of fusion and high enthalpy of vaporization. High heat is required to melt and vaporize ionic compounds because ionic compounds are formed between cation and anion and the oppositely charged ions are held by strong electrostatic force of attraction.  

Ionic compounds form crystal lattice in which there is alternate arrangement of cation and anion in an array of three dimensional space. Ionic compounds do not form amorphous solids.  

1. u divide the mass 20.0g by its molar mass of 44.01g/mol = 0.454mol

2. using the formula PV=nRT

105kPa x V = 0.454mol (use the non rounded value) x 8.314Lkpa/molK x 298K

V= 10.7L :)

The volume that 20.0g of CO2 would occupy at a temperature of 298k and a pressure of 105 kPa is approximately 10.5 liters. The ideal gas law (PV=nRT) was used to calculate this.

To answer this question, we would use the ideal gas law, which states that the pressure of a gas times its volume is equal to the number of moles of the gas times the gas constant times the temperature in Kelvin.

PV = nRT

You can think of it as the pressure and volume of a gas is directly proportional to its temperature and the number of particles (moles) of gas.

First, we need to find out how many moles of CO2 we have. We have 20.0 g of CO2, and the molar mass of CO2 is about 44 g/mol. So, we have: 20.0g / 44 g/mol = 0.455 moles of CO2

Next we plug this into the ideal gas law equation:

105 kPa * V = 0.455 moles * 8.31 J/(mol*K) * 298 K

Solving for V, we find that the volume is about 10.5 liters

So, 20.0 g of CO2 would occupy a volume of about 10.5 liters at a temperature of 298 K and a pressure of 105 kPa.

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The answer is B.

Hope this helped you!

B. mass is the correct answer

Can you send the attachment please so i can help you

Answer:

hi your question lacks the required options and diagram here is the complete question and diagram.

What must be true of the two highlighted triangles in the image? Check all that apply. | 1. The speed of the planet is the same for both triangles. | 2. The time frame is the same for both triangles. | 3. The area is the same for both triangles. | 4. The gravitational force is the same for both triangles.

Answer : The time frame is the same for both triangles ( 2 )

               The area is the same for both triangles ( 3 )

Explanation:

according to Kepler's second law of  planetary  motion which states that "That the line segment joining the planet and the sun sweeps equal areas during equal intervals of time"

according to Kepler's second law of planetary motion the highlighted triangles in the image the time frame and the area is the same for both of them and this is because they have line segments that joins the sun to the planet which is moving around the sun in a elliptical orbit. hence option 2 and option 3 is true for the highlighted triangles.

gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

It depends on the type of solid. All molecules in solid form have what is called vibration movement, meaning the move in fixed positions. In some solids the forces of attraction between the molecules are strong enough to keep the molecules in a relatively fixed position but allow some moment of molecules past one another.  but they also move to where you cant feel them.

hope this helped :)

Polar bears float on ice floes to hunt for food.

Water's unique property of having lower density in its solid form allows ice to float on water. The orientation of hydrogen bonds during freezing causes water molecules to spread out, making ice less dense than liquid water. This unique property is vital for the survival of aquatic organisms in freezing conditions.

One example of the unique density property of water is how ice floats on water. This is due to water's lower density in its solid form, a result of the way hydrogen bonds are oriented as water freezes: the water molecules are pushed farther apart compared to liquid water. This is different from most other liquids, where solidification involves an increase in density.

Thus, when water freezes, it expands and becomes less dense than its liquid form, causing ice to float on water. This provides an insulating layer, preserving the lives of aquatic organisms in freezing conditions. This is a feature unique to water and is a consequence of its abnormal density behavior.

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CuSO4(s)*5H2O(s) = CuSO4(s) + 5 H2O(g)

Reaction type: decomposition

To balance the equation CuSO4(s) + H2O(l) → CuSO4 · 5 H2O(s), you need to ensure that the number of atoms on both sides of the equation are the same. Follow the steps mentioned above to balance the equation.

To balance the equation: CuSO4(s) + H2O(l) → CuSO4 · 5 H2O(s), you need to ensure that the number of atoms on both sides of the equation are the same. To do this, you can start by balancing the elements individually.

Cu: There is 1 Cu atom on the left and 1 Cu atom on the right, so it is already balanced.

S: There is 1 S atom on the left and 1 S atom on the right, so it is already balanced.

O: There are 4 O atoms on the left (1 from CuSO4 and 3 from H2O) and 9 O atoms on the right (4 from CuSO4 · 5 H2O and 5 from H2O). To balance the O atoms, you can multiply H2O(l) on the left by 9/5, which will give you 9 O atoms on both sides.

Finally, the balanced equation becomes: CuSO4(s) + 9/5 H2O(l) → CuSO4 · 5 H2O(s).

The answer is C a primary source

Answer: C. A primary source, because it will contain more details.

Explanation:

A primary source is the source which provides the first hand experience of an experiment, methodology, event and it considered to be authoritative, as it comes from the owner of the research piece. The primary source represents the thinking, discoveries and events which are original.

A secondary source includes the information which generates after the analysis, interpretation and evaluation of the information, or data from the primary source.

According to the given situation, as the botanist wants to learn about the new method of crossbreeding orange trees. The new method will be latest and may not be applied much by other scientist. Therefore, the source of information will be primary. It will contain more details.  

The final temperature of the air transferred from the tank to the tire can be determined by applying the ideal gas law equation rearranged to solve for the final temperature.

The question is dealing with the concepts of pressure, volume, and temperature in relation to gases, which can be analyzed using the ideal gas law. In this case, the air is being transferred from a larger tank to a smaller tire, with a decrease in pressure.

This forms the premise of an ideal gas law problem, with the formula PV = nRT (Pressure x Volume = n (number of moles) x R (gas constant) x Temperature). It's important to note that this law assumes the gas behaves 'ideally,' meaning it follows this law at all temperature and pressure conditions.

Given the initial condition of the tank (P1 = 125 psi, V1 = 75 L, T1 = 288 K) and the final conditions after the air is transferred to the tire (P2 = 25 psi, V2 = 6.1 L), and knowing both the initial and final state of the gas, we are supposed to find the new temperature (T2). Our unknown in this case is the final temperature inside the tire after the air has been transferred.

By rearranging the ideal gas law, we can express the final temperature as: T2 = (P2 x V2 x T1) / (P1 x V1) By substituting the given values into this equation, we can find the final temperature after the transfer of air.

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"The correct final temperature of the air in the tire is approximately 35.6 K.

To solve this problem, we can use the ideal gas law, which states that for a given amount of gas, the product of pressure (P) and volume (V) divided by the temperature (T) is constant:

[tex]\[\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\][/tex]

Here, the subscript 1 refers to the initial conditions in the tank, and the subscript 2 refers to the final conditions in the tire.

[tex]\(P_1 = 125\)[/tex] psi (initial pressure in the tank)

[tex]\(V_1 = 75\) L[/tex] (initial volume in the tank)

[tex]\(T_1 = 288\)[/tex]K (initial temperature in the tank)

[tex]\(P_2 = 25\)[/tex]psi (final pressure in the tire)

[tex]\(V_2 = 6.1\)[/tex] L (final volume in the tire)

We need to find [tex]\(T_2\),[/tex] the final temperature in the tire.

First, we convert the pressures from psi to Pa (Pascals) because the ideal gas law requires consistent units, and the standard unit for pressure in the SI system is the Pascal. The conversion factor is 1 psi = 6894.76 Pa.

[tex]\(P_1 = 125 \times 6894.76\) Pa \(P_2 = 25 \times 6894.76\) Pa[/tex]

Now we can set up the equation using the ideal gas law:

[tex]\[\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\][/tex]

Substitute the given values:

[tex]\[\frac{(125 \times 6894.76) \times 75}{288} = \frac{(25 \times 6894.76) \times 6.1}{T_2}\][/tex]

Now, solve for [tex]\(T_2\)[/tex]:

[tex]\[T_2 = \frac{(25 \times 6894.76) \times 6.1 \times 288}{(125 \times 6894.76) \times 75}\][/tex]

Simplify the equation by canceling out the common factors:

[tex]\[T_2 = \frac{25 \times 6.1 \times 288}{125 \times 75}\] \[T_2 = \frac{25 \times 6.1}{125} \times \frac{288}{75}\] \[T_2 = \frac{1}{5} \times 6.1 \times \frac{288}{75}\] \[T_2 = \frac{6.1}{5} \times \frac{288}{75}\] \[T_2 = 1.22 \times 3.84\] \[T_2 = 4.6928\] \[T_2 \approx 35.6\) K[/tex]

Therefore, the new temperature in the tire is approximately 35.6 K."