Answer:
The gravitational field strength on Mars is 3.7 N/kg.
Explanation:
Given that,
Mass of the object, m = 4 kg
Weight of the object on Mars, F = W = 14.8 N
We need to find the gravitational field strength on Mars. It is given by gravitational force per unit mass of an object. Mathematically, it is given by
[tex]G=\dfrac{F}{m}[/tex]
[tex]G=\dfrac{14.8\ N}{4\ kg}[/tex]
G = 3.7 N/kg
So, the gravitational field strength on Mars is 3.7 N/kg. Hence, this is the required solution.
What is the angular position in radians of the minute hand of a clock at 2:55?
Which one of the following scenarios accurately describes a condition in which resonance can occur?
A. A column of air has a height equal to 1 ⁄ 8 of the wavelength of the sound waves produced by a tuning fork vibrating over the column of air in an open pipe that's partially immersed in water.
B. A vibrating tuning fork is struck and begins to vibrate as the object used to strike it is placed away from the tuning fork.
C. A pipe's length is equal to 1 ⁄ 2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open to the air at both ends.
D. A person is holding a tuning fork on one end of a football field and another person is holding a separate tuning fork on the opposite end of the field.
Final answer:
Scenario C correctly describes resonance, where a pipe open at both ends has a length equal to half the wavelength of the sound from the tuning fork, allowing for a standing wave and resonant sound.
Explanation:
The scenario that accurately describes a condition in which resonance can occur is scenario C: A pipe's length is equal to 1 ⁄ 2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open at both ends. In this case, the half-wavelength of the sound matches the length of the pipe, allowing a standing wave to be set up with antinodes at both ends and a node in the middle. This results in constructive interference and a resonant amplification of the sound.
What kind of energy does a microwave use to cook food? Select one: Elastic potential energy Electomagnetic energy Kinetic energy Chemical energy
Question 25
Astronauts orbiting the earth in the space shuttle experience a force of gravity that is
several times greater than the Fgrav experienced on Earth's surface.
several times smaller than the Fgrav experienced on Earth's surface.
a fraction greater than the Fgrav experienced on Earth's surface.
a fraction smaller than the Fgrav experienced on Earth's surface .
... nonsense! Orbiting astronauts do not experience any gravitational pull from the earth.
Astronauts orbiting earth experience a fraction smaller gravitational force (Fgrav) as compared to the force on Earth's surface. They are in a state of continuous freefall which gives the impression of weightlessness, not because gravity is absent.
Explanation:The force experienced by astronauts orbiting the Earth, notably, is actually a fraction smaller than the gravitational force (Fgrav) experienced on Earth's surface. However, it is a common misunderstanding that astronauts in orbit experience zero gravity. Though it might appear they are weightless and therefore not subject to gravity, this is not the case. They are in a state of continuous freefall towards the Earth. The sensation of weightlessness is because they're in freefall, not because gravity is absent. The effect of gravity diminishes as distance from the Earth increases, hence why the gravitational force is a fraction smaller.
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how do you find acceleration
Answer:
Acceleration is given by the formula :
a = (v - u)/t
a is the acceleration , u is the initial velocity , v is the final velocity , t is the time in seconds
When two objects are touching and transfer heat, it is called _____?
PLEASE HELP!!!
If an airplane were flying west at 100 km/hr and encountered a strong gale blowing east at 100 km/hr, what would be the plane's velocity relative to the ground?
***By the way, theres no picture***
on a distant planet, a freely falling object gains speed at a steady rate of 20 m/s during each second of fall. Calculate its acceleration
The acceleration of a freely falling object is 20 m/s if the distant planet, a freely falling object gains speed at a steady rate of 20 m/s during each second of fall.
What is linear acceleration?It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
It is given that:
on a distant planet, a freely falling object gains speed at a steady rate of 20 m/s during each second of fall.
As we know, from the acceleration the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
The acceleration of an item is the amount of speed it gets or loses per second when only its speed is changing and not its direction.
Thus, the acceleration of a freely falling object is 20 m/s if the distant planet, a freely falling object gains speed at a steady rate of 20 m/s during each second of fall.
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How would our society be affected if there was a shortage of copper?
What would we need to know to calculate both work and power?
A -energy, force, and time
B -force, distance, and time
C -force, mass, and distance
D -mass, force, and energy
Thermal energy produced by friction cannot usually be used to do work. true/false
Answer:
false
Explanation:
Work may be done in positive or negative direction. When a work is done in positive direction, it is called useful work, when work is done in negative direction, it is known as useless work. Any energy associated with friction produces useless work. That is, the work is done in negative direction.
Therefore, thermal energy produced by friction can be used to do work but in negative direction.
The correct option is false.
In the four-stroke internal combustion engine, fuel is ignited during the ____ stroke.
Which of the following statements about an apple falling from a tree is true? A) Its kinetic energy decreases and its potential energy increases. B) Its potential energy decreases and its kinetic energy increases. C) Its kinetic and potential energies remain constant. D) Its mechanical energy increases.
What is the frequency of radiation whose wavelength is 2.40x10-5 cm?
This problem can be answered using the equation below:
c = frequency x wavelength
where: c is the speed of light, which is equal to 3.00 x
10^8 m / s
frequency = c / wavelength
= (3.00 x 10^8m /s) / (2.40 x 10^-5 cm x 1 m /100cm)
= (3.00 x 10^8 m/s) / 2.40 x 10^-7m
= 1.25 x 10^15/s 1 / s = 1Hz
Frequency = 1.25 x 10^15Hz
Who would be a member of the American dental association?
A) a practicing dentist
B) a retired dentist
C) a dental student
D) a dental patient
Answer:
The correct answer is A)practicing dentist
Explanation:
Hello!
Let's solve this!
The American Dental Association (ADA) is an association of practicing dentists. They are dedicated to promoting dental health and giving assistance to those who need it.
They also give recommendations and talks about oral health.
The correct answer is A)practicing dentist
A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0 seconds. What is the average acceleration of the car during those 12.0 seconds?
48. Protons have ___ charge, neutrons have ___ charge, and electrons have ___ charge.
A. negative; positive; no
B. positive; no; negative
C. positive; negative; no
D. negative; no; positive
E. no; negative; positive
A rightward-moving truck skids to a stop from a very high speed with its wheels locked. What forces are exerted on the object?
Answer
Friction between the wheels and the ground, normal force, and friction force in the brakes.
Explanation
A truck moves on the surface simply because the driving force is greater than frictional force. The is always the normal force acting perpendicularly on the ground. The frictional force will be applying in two areas that is in the brakes and between the road and the wheels.
So, the forces exerted on the object are; friction and the normal force.
Final answer:
The pram starts moving when the applied force reaches 75 N due to static friction, and then it can be kept moving with a force of 37.5 N due to kinetic friction. The coefficients of static and kinetic friction are 0.75 and 0.375, respectively.
Explanation:
When the pram's brakes are locked, it requires a certain amount of force to overcome the static friction and get it moving. According to the question, the pram starts moving when the applied force is three-quarters of the normal force, which is 100 N.
Therefore, the force required to start moving the pram is (3/4) × 100 N = 75 N. Static friction is what prevents the pram from starting to move until this force is applied.
Once the pram starts moving, the force required to keep it moving drops to half of the force required to start moving it, which is (1/2) × 75 N = 37.5 N, indicating the kinetic friction between the pram and the surface is now in effect.
The coefficient of static friction (μs) is calculated using the formula μs = (force of static friction)/(normal force) = 75 N / 100 N = 0.75. Similarly, the coefficient of kinetic friction (μk) = (force of kinetic friction)/(normal force) = 37.5 N / 100 N = 0.375.
If it requires 5.0 j of work to stretch a particular spring by 1.8 cm from its equilibrium length, how much more work will be required to stretch it an additional 3.7 cm ?
What is the standard unit used to measure mass?
cubic meters
gram
liter
meter
Answer:
The standard unit used to measure of mass is gram.
(2) is correct option.
Explanation:
S.I is the standard international system of unit.
The S.I unit of mass is kilogram.
1 kg = 1000 gm
So, We can say that,
The standard unit used to measure mass is gram.
Cubic meter is the unit of volume.
Liter is the unit of water.
Meter is the unit of length.
Hence, The standard unit used to measure of mass is gram.
A hydraulic arrangement consists of a water-filled u-tube that is wider on one end than on the other. pistons are fitted in both ends. to multiple an input force, the input end should be the one having the ___
Final answer:
To multiply an input force in a hydraulic system, the input end should have a smaller area. This allows for a larger output force through Pascal's law, which is a principle used in hydraulic systems to provide a mechanical advantage.
Explanation:
To multiply an input force in a hydraulic system, the input end should be the one having the smaller area. When a force is applied to a small area, the resulting pressure is transmitted through the hydraulic fluid to a larger area on the output end, resulting in a greater output force. This principle is based on Pascal's law, which states that pressure in an enclosed fluid is transmitted undiminished in all directions.
Your hydraulic system will give you a mechanical advantage by applying the input force on a smaller area to output a greater force on a larger area. For example, applying a 100-N force on the smaller input piston can produce a 500-N force on the output piston if the output piston is five times larger in area.
Hydraulic systems are often compared to simple levers, but have the benefit that they can transmit forces through complex paths, allowing diverse applications from brakes in vehicles to heavy lifting in industrial settings.
A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2 . How big is the frictional force on the block? What is the coefficient of friction between the chair and floor?
What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth is 1/40 of its value at the earth's surface?
It measures 7,926 miles (ca. 12,756 km) in diameter (the distance from one side to the other via the centre of the Earth) (about 12,756 kilometres). When the diameter of Earth is calculated between the North and South Poles, it is somewhat smaller at 7,907 miles (ca. 12,725 km).
What centres to a point outside the earth?Joseph Louis Lagrange, a mathematician, developed the so-called Lagrangian points, one of which is L2. Lagrangian's points are places in space where the interaction between a body's orbital motion and gravity forces is balanced. As a result, spaceships can use them to “hover.”
Therefore, The gravity at the equator would be zero if the earth were roughly 36,000 km in circumference, the same mass, and the same length of day. This is where geostationary orbits are located.
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Final answer:
To find the point where the Earth's gravitational acceleration is 1/40 of the surface value, we use Newton's law of gravitation and solve for r', yielding a distance of approximately 40225 km from the Earth's center.
Explanation:
To determine the distance from the Earth's center to a point where the gravitational acceleration is 1/40 of its value at the Earth's surface, we can use the law of universal gravitation. The force of gravity according to Newton's law of gravitation is given by F = GMm/r², where G is the gravitational constant, M is the mass of the Earth, m is the mass of the object, and r is the distance from the center of the Earth.
The gravitational acceleration g at the surface of the Earth is g = GM/r². If we want to find the point where this acceleration is 1/40 of its surface value g0, we set g = g0/40, which leads to GM/(r')² = GM/(R² * 40), where R is the radius of the Earth and r' is the new distance from the Earth's center. Solving for r', we get r' = R * √40. Using the mean radius of the Earth R ≈ 6371 km, we find:
r' ≈ 6371 * √40 km ≈ 6371 * 6.32 km ≈ 40225 km.
This means the distance from the Earth's center to the point where gravitational acceleration is 1/40 of its surface value is approximately 40225 km.
A ball is thrown straight up into the air, with an initial speed of 18.2 m/. How far has it gone after 1.00 s?
Answer: 13.3 m
I got it right on Acellus
Some instruments differentiate individual quanta of electromagnetic radiation based on their energies. assume such an instrument has been adjusted to detect quanta that have 3.50× 10–16 j of energy. what is the wavelength of the detected radiation? give your answer in nanometers.
If a tube is placed vertically into a container of water, and the water level inside the tube is the same as the water level on the outside, what can we determine about the pressure inside the tube?
A net force of 55 N acts due west on an object. What single force on the object produces equilibrium?
The force that will make this into equilibrium would be equal to the force of equal amount yet applied on the opposite direction.
So we are given that a force of 55 N due west was applied, so the equilibrium force would be 55 N due east.
Final answer:
To achieve equilibrium against a 55 N force acting due west, a single equal and opposite force of 55 N must be applied due east. In various scenarios, the equilibrium force must have the same magnitude but opposite direction to the acting force. Pythagorean theorem helps calculate net force when forces are perpendicular.
Explanation:
For an object to be in equilibrium, the net force acting on it must be zero. This means that to counteract a force of 55 N acting due west, an equal and opposite force must be applied. The single force that would produce equilibrium in this case is a 55 N force acting due east.
Applying this principle, we can understand the scenarios presented:
A point in equilibrium with a force F₁ having components 15 N south and 13 N west must be countered by a force F₂ with components 15 N north and 13 N east.For the given free-body diagram showing a northward force of 64 N and a westward force of 38 N, the net force can be calculated using the Pythagorean theorem to assess the magnitude of the resultant force.If two forces of 5 N to the right and 7 N to the left act on an object, the net force is 2 N to the left, and the object cannot be in static equilibrium since there is a resultant force.When forces of 50 N and 80 N act in the same direction, the net force is simply their sum, 130 N, in the direction of the greater force.Lastly, a charge in an electric field experiencing a net force of 100 N eastward when the field points north is impossible, since the electric force on a charge by a field is in the direction of the field. Therefore, the force must be perpendicular to the direction of the electric field strength of 50 N/C pointing north.
What happens to the pressure inside a container when you reduce the volume?
A wave has a frequency of 8500HZ and a wavelength of 1.5 m what is the speed of the wave?
What type of bonding is represented in Figure 2-2???