A bag contains 80 marbles: 40 are red, 20 are blue, and 20 are black. what is the probability of selecting a red or blue marble at random

Answers

Answer 1
40 % out of 80 for red
20% out of 80 for blue

Related Questions

Anthony has 115 book in his room .He is storing them in boxes .Each box holds 17 book .How many boxes does Anthony need?

Answers

Anthony need 7 boxes to hold 115 books.

What is Division method?

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.

For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

Anthony has 115 books in his room.

And, He is storing them in boxes.

Each box holds 17 books.

Now,

Since, Total number of books = 115

And, Each box holds 17 books.

Hence, Number of boxes to cover 115 books = 115 ÷ 17

                                                                      = 7

Since, We get the quotient after divide 115 by 17 is 13.

So, Anthony use 1 box extra to keep 13 remaining books.

Thus, Anthony need 7 boxes to hold 115 books.

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what is the slope of the line (2,5) and 7,25)

Answers

To get slope from these two points, you have to do

25-5 divided by 7-2.
20 divided by 5
=4

The slope of the line would be 4.

What is the equation of the line that is perpendicular

Answers

The answer should be C

Choose the correct answer.

You are offered an item for $22.85. If the seller states he normally sells the same item for $29.95, what percentage discount is he offering you
A. 24.22
B.23.96
C.23.71

Answers

29.95 - 22.85 = 7.10

7.10 / 29.95 = 0.23706 = 23.71 percent


Answer is C

Answer:

23.71%

Step-by-step explanation:

Given :You are offered an item for $22.85. If the seller states he normally sells the same item for $29.95,

To Find :what percentage discount is he offering you

Solution :

The original price is $29.95

The offered price is $22.85

So the discount percentage = [tex]\frac{\text{original price-offered price}}{\text{original price}}*100[/tex]

= [tex]\frac{29.95-22.85}{29.95}*100[/tex]

= [tex]\frac{7.1}{29.95}*100[/tex]

= 23.71%

Thus the percentage of discount is  23.71%

Write an equation in point-slope form of the line through point J(-8,10) with slope -5.

A. y + 10 = -5(x + 8)
B. y - 10 = 5(x + 8)
C. y - 10 = -5(x + 8)
D. y - 10 = -5(x - 8)

Answers

Point-slope form is y - y1 = m(x - x1). If you apply that point and the slope to the formula (hence the name point-slope), you'd get y - 10 = -5(x + 8).

Hope this helps! :)

REVISE: I accidently put y instead of x in the -5(x + 8) part. It's fixed now.

Which choices are equivalent to the fraction below? Check all that apply.

Answers

= 3(9-9) = 3^0 = 1
answer is C and E

A student has some 1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. how many of each type of bill does he have?

Answers

*Given
Total number of bills    - 15
Total value of the bills - $47
Bills                             - $1 and $5

*Solution
Let:
  x - number of $1 bills
  y - number of $5 bills

1. The total number of bills comprising of $1 and $5 bills is 15. Thus, 

                         x + y = 15                                      (EQUATION 1)

2. The total value of the bills is $47. Thus, 
 
                   $1 (x) + $5 (y) = $47                           (EQUATION 2)

3. There are 2 ways to solve this (system of linear equations) mathematically. You can use the elimination method or the substitution method. Using the elimination method to eliminate the variable x... (subtract Equation 1 from Equation 2)

                    1x      +   5y      = 47
                 _
                     x       +     y      = 15
                     0       +   4y      = 32

4. Thus, the value of y, which is the number of $5 bills is, 

                     4y       =   32 
                      4              4

                      y       =    8

5. The number of $1 bills (x) can then be solved using either Equations 1 or         2. Using Equation 1 to determine x, 
 
                         x + y = 15    
                               x = 15 - y
                               x = 15 - 8
                               x = 7

From the solution, we have determined that there are 8 pieces of $5 bills and 7 pieces of $1 bills. 

Answer:

B. seven $1 bills and eight $5 bills.

Step-by-step explanation:

n = number of $1 bills

m = number of $5 bills

 

Given:

 

n + m = 15

n($1) + m($5) = $47

 

Just solve 2 equations in 2 unknowns n and m:

 

(i)  n + m = 15

(ii) n + 5m = 47

 

Subtract (i) from (ii) and get

 

4m = 32

m = 32/4 = 8

 

Then from (i) get

 

n = 15 - m = 15 - 8 = 7

 

There are 7 $1 bills and 8 $5 bills.

The equation y=-5.131x^2 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am what is the best estimate for the number of people in line at 9am

Answers

41 is the best estimate for the number of people in line at 9am

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

y equal to minus five point one three one x square plus Thirty one point eight two one x minus three point three three three.

y=-5.131x²+ 31.821x-3.333 approximates the number of people standing in line to catch commuter train x hours after 5am.

There is 4 hours in between 9 am and 5 am. so x=4

Substitute x=4 into the equation

y=-5.131(4)²+ 31.821(4)-3.333

y=-5.131(16)+127.284-3.333

y=-82.096+127.284-3.333

y=41.855

Hence 41 is the best estimate for the number of people in line at 9am

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How to prove system of nonlinear equations has finite solutions?

Answers

this is what you could do

If r^n=a, then which of the following are true statements? Check all that apply.

a. a^1/n=r b. a^r=n c. n sq a =r d. n^1/r=a

Answers

a. This is correct. When you transfer n to the other side, that would be the reciprocal power of a.

b. This is incorrect, because this contradicts with choice a.

c. This is correct. When a number is raised to a "1/n" fraction, that is equivalent to the nth root of the number.

d. This is incorrect, because it is not equivalent to the given equation.

Thus, the answers are A and C.

Which graph describes the open sentence –1 ≤ n + 2 ≤ 6?

A. Number line showing range from negative four to four. There are two rays on the graph. The first has a right end point with a closed dot at negative two with a ray pointing left past negative four. The second has a left end point with an open circle at three with a ray pointing right past four.

B. Number line -5 to +5 in single-integer increments - assessment graphic

C. Number line showing range from negative three to three The left end point is an open circle halfway between negative one and zero. There is a closed dot at three, and a ray points past three.

D. Number line showing range from negative eight to eight. There are two rays on the graph. The first has a right end point with an open circle halfway between negative six and negative four with a ray pointing left past negative eight. The second has a left end point with an open circle at four with a ray pointing right past eight.

Answers

The value of n≥-3 and n≤4 describes the open sentence -1≤n+2≤6

What will be the range of n for  -1 ≤ n+2 ≤ 6 ?

If we follow the above condition for the different values of n

At value of n=-3 we will get n+2=-3+2=-1

similarly at n=-2 we will get n+2=-2+2=0

and at n=-1 we will get n+2=-1+2=1

all three (-1,0,1) follow the condition -1 ≤ n+2

Similarly at n=(0,1,2,3,4) condition n+2 ≤ 6  is followed

Hence value of n≥-3 and n≤4 describes the open sentence -1≤n+2≤6

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The correct graph is option C.

Sure, let's break down the steps to understand why option C is the correct graph for the open sentence [tex]\(-1 \leq n + 2 \leq 6\)[/tex]:

1. Identify the Middle Term: The middle term in the open sentence is [tex]\(n + 2\)[/tex]. This means our focus is on the expression [tex]\(n + 2\)[/tex].

2. Understand the Inequality: The inequality [tex]\( -1 \leq n + 2 \leq 6\)[/tex] can be understood as "n + 2 is greater than or equal to -1 and less than or equal to 6".

3. Subtract 2 from Each Part: To isolate [tex]\(n\)[/tex], subtract 2 from each part of the inequality:

[tex]\[ -1 - 2 \leq n + 2 - 2 \leq 6 - 2 \][/tex]

  Which simplifies to:

[tex]\[ -3 \leq n \leq 4 \][/tex]

4. Draw the Number Line: Draw a number line ranging from -3 to 4, inclusive.

5. Plot the Endpoints: On the number line, mark endpoints at -3 and 4.

6. Determine the Endpoints: Since the inequality includes "equal to" signs, the endpoints should be marked with closed dots (indicating inclusion).

7. Determine the Direction of the Ray: Since the inequality does not include strict inequality signs (< or >), the rays should extend in both directions from the endpoints.

8. Indicate the Rays: Draw rays to the left of -3 and to the right of 4, indicating the range extends indefinitely in both directions.

9. Mark the Open Circle: Since the inequality involves strict inequality at -1 and 6, mark an open circle at the points halfway between -1 and -3, and 6 and 4, respectively.

10. Verify the Result: The resulting graph should have closed dots at -3 and 4, indicating the range includes those values, and open circles at -1 and 6, indicating exclusion.

Option C correctly represents these steps, making it the correct graph.

The graph is given below:

The gasoline prices in seven states are $1.96, $2.09, $1.79, $1.61, $1.75, 2.11, and $1.84 what is the median gas price and the difference of the first and third quartiles

Answers

first we must put them in order

1.61, [1.75], 1.79, (1.84), 1.96, [2.09], 2.11

the median (the middle number) = 1.84 <=

the difference of the first and 3rd quartiles (the IQR) = 
2.09 - 1.75 = 0.34 <=

Answer:

Median = $1.84

The difference of the first and third quartiles = $0.34

Step-by-step explanation:

Median

How to calculate the median of a small data or ungrouped data;

1. Arrange the data in ascending or descending order.

2. Choose the middle value. The middle value can be a single value or two value. If the middle value is a single value, then, that value is the median but if the middle values are two, the mean of the two middle values is evaluated to get the median.

Arranging the gasoline prices given in ascending order;

$1.61,  $1.75, $1.79,  $1.84,  $1.96, $2.09, $2.11

The middle value is a single number $1.84 in bold. Therefore, the median is $1.84.  

                         Median = $1.84

First (Lower) Quartile

To calculate for the First (Lower) quartile,

1. Arrange the data give in ascending order.

2. The First (Lower) quartile, Q1 is then calculated using;  

                 [tex]Q1 =\frac{1}{4} (n + 1)^{th}[/tex] term

where n is the total number of terms of the data. In the given question, the total number of terms, n = 7

                 [tex]Q1 =\frac{1}{4} (7 + 1)^{th}[/tex] term

                 [tex]Q1 =\frac{8}{4}^{th}[/tex] term

                 Q1 = 2nd term

3. Select the 2nd term of the given data already arranged in ascending order.

                 $1.61,  $1.75, $1.79,  $1.84,  $1.96, $2.09, $2.11

                 The First Quartile, Q1 = $1.75

Third (Upper) Quartile

To calculate for the third (upper) quartile,

1. Arrange the data give in ascending order.

2. The third (upper) quartile (Q3) is then calculated using;  

                 [tex]Q3 =\frac{3}{4} (n + 1)^{th}[/tex] term

where n is the total number of terms. In the given question, the total number of terms, n = 7

                 [tex]Q3 =\frac{3}{4} (7 + 1)^{th}[/tex] term

                 [tex]Q3 =\frac{24}{4}^{th}[/tex] term

                 [tex]Q3 = 6^{th} term[/tex]

3. Select the [tex]6^{th} term[/tex] of the given data already arranged in ascending order.

                 $1.61,  $1.75, $1.79,  $1.84,  $1.96, $2.09, $2.11

The third (upper) quartile Q3 = $2.09

The difference between the first and third quartiles is called interquartile range.

Now, calculating the difference of the first and third quartiles

                  Interquartile Range = Q3 - Q1

                              $2.09 - $1.75 = $0.34

The difference of the first and third quartiles, Interquartile Range = $0.34

Given equal probabilities of the birth of a boy or girl, what is the probability that a group of four siblings includes all boys? all girls? all boys or all girls?

Answers

The probability of a group of four siblings being all boys or all girls is 1/8, with each individual probability being 1/16.

Probability of All Boys:

Probability of a boy birth: 1/2

Probability of all boys among 4 siblings:

(1/2) × (1/2) × (1/2) × (1/2) = 1/16

Probability of All Girls:

Probability of a girl birth: 1/2

Probability of all girls among 4 siblings:

(1/2) × (1/2) × (1/2) × (1/2) = 1/16

Probability of All Boys or All Girls: Since these are mutually exclusive events, add their probabilities:

1/16 (all boys) + 1/16 (all girls) = 1/8

If cats prowl, mice will scatter. Mice are scattering

Answers

The cat prowled and the mice scattered

Identify the degree of the polynomial 6xy2 − xy + 8 + 12y.

Answers

6xy^2 - xy + 8 + 12y is a polynomial of degree 3

Write an equation of the circle with center , −45 and radius 6 .

Answers

The general equation for a circle, [tex]x^2+y^2=1[/tex], falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like [tex] a^2+b^2=c^2[/tex], where and b are the legs of a right triangle and is its hypotenuse. When we fix c in place and let and vary (in a sense, at least; their values are still dependent on c), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.

How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like [tex]x^2+y^2=6^2[/tex], or [tex] x^{2} +y^2=36[/tex].

Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read:

[tex](x-a)^2+(y-b)^2[/tex]

△FEB≅△CNB.

What is length of BN¯¯¯¯¯¯ ?

Answers

3.8
You simply match them up in corresponding order and use CPCTC

we know that

The CPCTC states that corresponding parts of congruent triangles are congruent

so

△FEB≅△CNB

that means

[tex]FE=CN\\FB=CB\\EB=NB[/tex]

we have

[tex]FE=6.1\ units\\FB=4.8\ units\\EB=3.8\ units[/tex]

therefore

[tex]BN=3.8\ units[/tex]

the answer is

the length of BN is [tex]3.8\ units[/tex]



There are 20 counters in a box. A counter is chosen and replaced 100 times, the results are 32 blue and 68 red. How many of each color do you think there are in each box ?

Answers

45/ 360 = 6/x
45x = 2160
x - 2160/45 = 48 people

2)
n = (n - 1) - 5

3)
7x - 11 = 19 - 3x
add 3x to both sides:
10x - 11 = 19
add 11 to both sides:
10x = 30
divide both sides by 10:
x = 30/10 = 3

4)
4(8)(11) - 64 = 288

5)
(5, 0)

6)
-4x -3 + 2x - 6 = -2x - 9

7)
1.8(-20) + 32 = -4F

8)
Exterior angle add to 360
360/6 = 60 degrees

10)
2x/9 = 12
2x = 108
x = 108/2 = 54

11)
x = 0

12)
8 + 3 + 1 = 12
240/12 = 20
8(20) = 160
3(20) = 60
1(20) = 20

160 pounds, 60 pounds, 20 pounds


Please help me with 3 math questions!!! I will give 30 points and brainliest to whoever answers the best!

1. Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.

ƒ -1(x) = (answer) x (answer)(answer)

ƒ -1(4) = (answer)

2. Match each function with the expression representing its inverse function. Match one of the numbers with the correct letter.
1. y = x - 4
2. g(x) = -0.5x
3. k(x) = x
4. p(x) = x + 4
5. h(x) = 4x
6. ƒ(x) = x/2

a. 2x
b. x + 4
c. x - 4
d. -2x
e. 0.25x
f. x

3. The graph of a function g is shown below.

Find its inverse.
(picture below, my answer is NOT correct)

Answers

to find inverse, switch x and f(x) and solve for the new f(x), the new f(x) is the inverse. 
original function: f(x)=(1/2)x+4
switch: x=(1/2)f(x)+4
f(x)=2x-8, this is the answer for question 1

answer for question 2: 1-b, 2-d, 3-f, 4-c, 5-e, 6-a

question 3
From the given graph, we know the slope is 2/5, the y intercept is -2, so the original function is f(x)=(2/5)x-2
switch x and f(x): x=(2/5)f(x)-2
solve for f(x): (2/5)f(x)=x+2
multiply both side by 5/2: f(x)=(5/2)x+5,
so the second choice is the correct answer.




SOMEONE PLEASE HELP ME ASAP!!!



1. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.


Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4


Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.


Convert Ken's chest, waist, and hips measurements to z-scores. Which of those measures appears to be the most different from Ken's reference group (human males)? Justify your response with an appropriate statistical argument.




2. In recent years, there has been considerable discussion about the appropriateness of the body shapes and proportions of the Ken and Barbie dolls. These dolls are very popular, and there is some concern that the dolls may be viewed as having the "ideal body shape," potentially leading young children to risk anorexia in pursuit of that ideal. Researchers investigating the dolls' body shapes scaled Ken and Barbie up to a common height of 170.18 cm (5'7") and compared them to body measurements of active adults. Common measures of body shape are the chest (bust), waist, and hip circumferences. These measurements for Ken and Barbie and their reference groups are presented in the table below.


Ken Barbie
Chest Waist Hips | Chest Waist Hips
Doll: 75.0 56.5 72.0 | 82.3 40.7 72.7
Human x-bar: 91.2 80.9 93.7 | 90.3 69.8 97.9
Human S: 4.8 9.8 6.8 | 5.5 4.7 5.4


Suppose that the researchers' scaled-up dolls suddenly found themselves in the human world of actual men and women.


Convert Barbie's chest, waist, and hips measurements to z-scores. Do these z-scores provide evidence to justify the claim that the Barbie doll is too thin of a representation of adult women? Justify your response with an appropriate statistical argument.




3. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.

Find the standardized scores for both students.



4. Jill scores 680 on the mathematics part of the SAT. The distribution of SAT scores in a reference population is normally distributed with the mean 500 and standard deviation 100. Jack takes the ACT mathematics test and scores 27. ACT scores are normally distributed with mean 18 and standard deviation 6.

Assuming that both tests measure the same kind of ability, who has the higher score, and why?



5. A lunch stand in the business district has a mean daily gross income of $420 with a standard deviation of $50. Assume that the daily gross income is normally distributed.

If a randomly selected dat has a gross income of $520, then how many standard deviations away from the mean is that day's gross income?

Answers

1.)
zChest -> (91.2-75)/4.8=-3.4zWaist -> (80.9-56.5)/9.8≈-2.5zHips  -> (93.7-72)/6.8≈-3.2It would be Ken's chest because the difference between the doll and an averaged human male is the greatest

2.)
zChest -> (82.3-90.3)/4.7≈-1.45zWaist -> (40.7-69.8)/4.7≈-6.19zHips  -> (72.7-97.9)/5.4≈-4.7
Yes because the waist is far too thin compared to an averaged human woman

3.)
zJill -> (680-500)/100=1.8zJack -> (27-18)/6=1.5

4.)
It would be Jill because she has the higher z-score

5.)
$520-420=80$50=SDs$80(1 SD/50)=1.6 SD

Question Down Below...

Answers

5/12 equals to 20/48.

48÷12=4
5×4=20
Hello there!

First, you need to replace that empty space by a letter. As usual, we replace that empty space by x or y. I pick X :)

[tex] \frac{5}{12} = \frac{x}{48} Now, we do something called cross-multiply 12*x = 48 * 5 12x = 240 x = 240/12 x= 20 [/tex]

The missing number is 20
----------------------

We can check if we got the answer right. Replace the hole by 20
so it will be
5/12 = 20/48

when divided 5 by 12, it equals to 0.41
when we divided 20 by 48, it equals 0.41

So yes, 20 is the missing number.


I hope this helps you. Please let me know if you have more questions.

Best of luck! 

Cameron bought four begonias in 6-in pots and a $19 fern at a fundraiser. he spent a total of $63. how much is each begonia?

Answers

Each of the begonias are $11

The cost of each begonia is $11 at a fundraiser.

What is the equation?

The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.

Let's assume the cost of each begonia x.

Since Cameron bought four begonias, the total cost of the begonias was 4x.

The total cost of the plants was the cost of the begonias plus the cost of the fern, or 4x + 19.

As per the question, the total cost was $63, so we can set up the equation:

4x + 19 = 63

To solve for x, we need to get x by itself on one side of the equation. We can do this by subtracting 19 from both sides:

4x + 19 - 19 = 63 - 19

This simplifies to:

4x = 44

To solve for x, we need to divide both sides by 4:

4x / 4 = 44 / 4

This simplifies to:

x = 11

Therefore, each begonia cost $11.

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Krista is planning to mow her grandparents lawn the rectangular yard is 10 yards by 12 yards but there is a square patio that has 12 foot sides in the middle of Krista kenmo 15 square feet per minute about how long will it take to finish the yard

Answers

First fine the total area of the yard 10 yards x 12 yards = 120 yards^2 Now find the area of the patio in yards 1 yard = 3 ft and each side of the patio is 12 ft --> 4 yards so the patio sides are 4 yds 4 yrds x 4 yrds = 16 yards To find the area of the yard only: 120 yards^2 - 16 yards^2 = 104 yards^2 Krista needs to mow 104 yards^2 total. And she can do 15 ft^2 per minute need the same units so convert the yards to feet 104 yards^2 x 3 ft/yard X 3 ft/yard = 936 ft^2 To find the minutes, divide the total by the amount she can do in one minute: 936 ft^2/15 ft^2 = 62.4 62.4 minutes

Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 = 16

Answers

The local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18  at points (0, 4) and (0, -4).

To find the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] using Lagrange multiplier techniques, we need to set up the Lagrangian function:

[tex]\[ L(x, y, \lambda) = f(x, y) - \lambda(g(x, y) - c) \][/tex]

where [tex]\( g(x, y) \)[/tex] is the constraint, c is a constant, and [tex]\( \lambda \)[/tex] is the Lagrange multiplier.

In this case, [tex]\( g(x, y) = x^2 + y^2 \)[/tex] is the constraint, and c = 16 .

So, the Lagrangian function is:

[tex]\[ L(x, y, \lambda) = x^2 - y^2 - 2 - \lambda(x^2 + y^2 - 16) \][/tex]

Now, find the partial derivatives of L with respect to ( x, y, ) and[tex]\( \lambda \)[/tex] and set them equal to zero to find critical points:

[tex]\[ \frac{\partial L}{\partial x} = 2x - 2\lambda x = 0 \]\[ \frac{\partial L}{\partial y} = -2y - 2\lambda y = 0 \]\[ \frac{\partial L}{\partial \lambda} = x^2 + y^2 - 16 = 0 \][/tex]

Solving the system of equations, we get two critical points:

1. When [tex]\( x = 0, y = 4, \lambda = -\frac{1}{4} \)[/tex]

2. When [tex]\( x = 0, y = -4, \lambda = -\frac{1}{4} \)[/tex]

Now, evaluate f(x, y) at these critical points:

1. f(0, 4) = 0 - 16 - 2 = -18

2. f(0, -4) = 0 - 16 - 2 = -18

Therefore, the local extreme values of [tex]\( f(x, y) = x^2 - y^2 - 2 \)[/tex] subject to the constraint [tex]\( x^2 + y^2 = 16 \)[/tex] are -18  at points (0, 4) and (0, -4).

The average rate of change of the function ​f(x)=4x^3 + 4 over the interval ​[66​,88​] is

Answers

Average rate of change =[f (x₂)-f (x₁)]/(x₂-x₁)

Interval [66,88] which is x₁=66, x₂=88

f (x)=4x³+4
f (x₁)=f (66)=4 (66)³+4=1149988
f (x₂)=f (88)=4 (88)³+4=2725892

Average rate of change =2725892-1149988/88-66
=1575904/22
=71632

The following temperatures were recorded in Pasadena for a week in April: 87, 85, 80, 78, 83, 86, 90. Determine the interquartile range

Answers

first, we put them in order

78,[80],83,(85),86,[87],90

Q1 = 80
Q2 (median) = 85
Q3 = 87

Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==


first, we put them in order

78,[80],83,(85),86,[87],90

Q1 = 80
Q2 (median) = 85
Q3 = 87

Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==

Factor out the greatest common factor. 2s4 - 4s2

Answers

Greatest common factor in this case is 2s^2. The resulting polynomial would be 2s^2(s^2-2)

Assume that you pay $2,849.84 in state property taxes every year. If your property has an assessed value of $41,302, what is your state’s property tax rate? a. 0.077 b. 0.032 c. 0.014 d. 0.069

Answers

the answer would be D

Answer:

Therefore, The correct option is D. 0.069

Step-by-step explanation:

Amount of the money paid in the state property taxes every year = $2849.84

The property owned has an assessed value.

Now, the assessed value of the property is $41302

We need to find the state's property tax rate.

[tex]\text{So, State's property tax rate = }\frac{\text{state's property tax}}{\text{assessed value}}\\\\\text{State's property tax rate = }\frac{2849.84}{41302}\approx 0.069[/tex]

Therefore, The correct option is D. 0.069

An article considered the use of a uniform distribution with A = 0.20 and B = 4.25 for the diameter X of a certain type of weld (mm).

Answers

Using the formula f(x) = 1/(b-a), where B is 4.25 and A is 0.20. Substituting these values to the formula, we get f(x) = 1/(4.25-0.2) = 0.24691358. Therefore, we get the answer f(x) = 0.24691358, 0.20<x<4.25. Otherwise, it is 0.

Using the formula f(x) =1/(b-a)

B is 4.25 and A is 0.20.

Put these values to the

We get f(x) = 1/(4.25-0.2) = 0.24691358.  

f(x)= 0.24691358, 0.20<x<4.25.

Further Explanation:

uniform distribution:

A uniform distribution, some of the time otherwise called a rectangular circulation, is a dispersion that has steady likelihood. The likelihood thickness work and combined circulation work for a nonstop uniform appropriation on the interim are (1) (2).  

we use uniform distribution:  

The uniform circulation gets its name from the way that the probabilities for all results are the equivalent. Rather, every result is similarly prone to happen. Not at all like a chi-square dissemination, there is no skewness to a uniform dispersion. Accordingly, the mean and middle concur.  

diameter:  

In geometry, a breadth of a circle is any straight line portion that goes through the focal point of the circle and whose endpoints lie on the circle. It can likewise be characterized as the longest harmony of the circle. The two definitions are likewise substantial for the measurement of a circle.  

formula of diameter:  

In the event that you know the zone of the circle, separate the outcome by π and locate its square root to get the sweep; at that point increase by 2 to get the distance across. This returns to controlling the equation for finding the zone of a circle, A = πr2, to get the distance across. You can change this into r = √(A/π) cm.

Subject: mathematics

Level: High School

Keywords: uniform distribution, we use uniform distribution, diameter, formula of diameter.  

Related links:  

Learn more about evolution on

https://brainly.com/question/4770892

https://brainly.com/question/1563227

what is the answer to algebra with pizzazz page 100; what should you say if you see a tall, wrought-iron tower in paris, france?
there are 24 blanks

Answers

Part 1:

Given

[tex]3n^2-17n+24 \\ \\ \Rightarrow3n^2-9n-8n+24 \\ \\ \Rightarrow3n(n-3)-8(n-3) \\ \\ \Rightarrow(3n-8)(n-3)[/tex]



Part 2:

Given

[tex]4x^3y-49xy^3 \\ \\ \Rightarrow xy(4x^2-49y^2) \\ \\ \Rightarrow xy(2x-7y)(2x+7y)[/tex]



Part 3:

Given

[tex]5x^2+20xy-60y^2 \\ \\ \Rightarrow5x^2-10xy+30xy-60y^2 \\ \\
\Rightarrow5x(x-2y)+30y(x-2y) \\ \\ \Rightarrow(5x+30y)(x-2y) \\ \\ \Rightarrow5(x+6y)(x-2y)[/tex]



Part 4:

Given

[tex]3x^3-x^2y+12x-4y \\ \\ \Rightarrow3x^3+12x-x^2y-4y \\ \\ \Rightarrow3x(x^2+4)-y(x^2+4) \\ \\ \Rightarrow(3x-y)(x^2+4)[/tex]



Part 5:

Given

[tex]2x^4y-3x^3y-20x^2y \\ \\ \Rightarrow x^2y(2x^2-3x-20) \\ \\ \Rightarrow x^2y(2x^2-8x+5x-20) \\ \\ \Rightarrow x^2y[2x(x-4)+5(x-4)] \\ \\ \Rightarrow x^2y(2x+5)(x-4)[/tex]



Part 6:

Given

[tex]9x^3y+33x^2y^2+30xy^3 \\ \\ \Rightarrow3xy(3x^2+11xy+10y^2) \\ \\ \Rightarrow3xy(3x^2+6xy+5xy+10y^2) \\ \\ \Rightarrow3xy[3x(x+2y)+5y(x+2y)] \\ \\ \Rightarrow3xy(3x+5y)(x+2y)[/tex]



Part 7:

Given

[tex]16a^3b^4+40a^2b^5+8ab^3 \\ \\ \Rightarrow8ab^3(2a^2b+5ab^2+1)[/tex]



Part 8:

Given

[tex]t^4-37t^2+36 \\ \\ \Rightarrow(t-1)(t-36)[/tex]



Part 9:

Given

[tex]2a^7b^3-288ab \\ \\ \Rightarrow2ab(a^6b^2-144) \\ \\ \Rightarrow2ab(a^3b-12)(a^3b+12)[/tex]



Part 10

Given

[tex]35a^2b-5a-7ab^2+b \\ \\ \Rightarrow35a^2b-7ab^2-5a+b \\ \\ \Rightarrow7ab(5a-b)-(5a-b) \\ \\ \Rightarrow(7ab-1)(5a-b)[/tex]



Part 11:

[tex]6a^4b^2-11a^3b^3+4a^2b^4 \\ \\ \Rightarrow a^2b^2(6a^2-11ab+4b^2) \\ \\ \Rightarrow a^2b^2(6a^2-3ab-8ab+4b^2) \\ \\ \Rightarrow a^2b^2[3a(2a-b)-4b(2a-b)] \\ \\ \Rightarrow a^2b^2(3a-4b)(2a-b)[/tex]



Part 12:

Given

[tex]t^2(t+3)+6t(t+3)+9(t+3) \\ \\ \Rightarrow(t^2+6t+9)(t+3) \\ \\ \Rightarrow(t+3)(t+3)(t+3) \\ \\ \Rightarrow(t+3)^3[/tex]

Answer: That’s really quite an eyeful

Step-by-step explanation:

The bottom answer to all of it is

That’s really quite an eyeful.

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