The mechanical energy of the ball-Earth-floor system at the instant when the ball left the floor is of 7 J.
What is Mechanical Energy?At any instant, the energy of an object by virtue of its motion or position is known as the mechanical energy of the object. In other words, mechanical energy is either the potential energy or the kinetic energy at any time instant.
Given data -
The initial gravitational potential energy is, U = 10 J.
The final gravitational potential energy is, U' = 7 J.
Now, considering the given case when the ball loses energy in the rebound due to ball deformation, heat loss from the bounce. The total mechanical energy is not conserved so mechanical energy as it bounces off the floor is equal to transformed potential energy at a maximum height of second bounce which is 7 J.
Thus, we can conclude that the mechanical energy of the ball-Earth-floor system at the instant when the ball left the floor is of 7 J.
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_________is a system that uses the reflection of underwater sound waves to detect objects.
1. sounds
2. ultrasound
3. sonar
4. refraction
Answer:3-Sonar
Explanation:
Sonar system is used to detect the under water objects by using the deflection of sound waves.
Sonar is an acronym of Sound navigation ranging.Two types of sonar sets are used for working: active and passive. The active sonar system pushes out sound signals called pings, and then absorbs the return sound echo. Passive sound sets obtain sound echoes without transmitting their actual sound signals. Submarines are using sonar to track other vessels.
Unless otherwise posted, what is the speed limit for cars in a residential area?_
A) 20 mph
B) 25 mph
C) 30 mph
Final answer:
The typical speed limit in a residential area is 25 miles per hour, which corresponds with option B) 25 mph. Always check local signs as limits can vary. Over this limit, like driving 31 mph in a 30 mph zone, may be tolerated but it's best to strictly follow posted speeds to ensure safety and avoid penalties.
Explanation:
The speed limit for cars in a residential area, unless otherwise posted, is generally 25 miles per hour (mph). This means that option B) 25 mph is typically the correct choice for such a setting. However, it's important to always observe local traffic signs as speed limits can vary depending on specific city, county, or state regulations.
For instance, the information given states that 50 kilometers per hour is approximately 31 miles per hour, suggesting that some residential areas might have a speed limit close to this value. However, in the context of the United States, 25 mph is a common residential speed limit, which is enforced to ensure the safety of the neighborhood, including pedestrians, cyclists, and playing children.
It's also important to note that speedometers and radar measurements can vary in accuracy. Therefore, while you may not get in trouble for driving slightly over the speed limit, such as 31 mph in a 30 mph zone, it's safest to adhere strictly to posted limits to avoid traffic violations and fines.
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.
A) True
B) False
Answer:
False
Explanation:
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida,This is a False statement.
The law is all riders would have to wear protective eyewear when riding in Florida.
In the double-slit experiment with electrons, the electrons arrive at the screen in a
A. Wave-like way with a pattern that is particle-like
B. Wave-like way with a pattern that is wave-like
C. Particle-like way with a pattern that is particle-like
D. Particle-like way with a pattern that is wave-like
Answer:
B. Wave-like way with a pattern that is wave-like
Explanation:
The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.
In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship
p = h /λ
Where p is the amount of motion of the particle and λ the wavelength associated with this particle
In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern
Let's review the answer.
A) False. The pattern is wave type
B) True. The whole process is with undulating characteristics
C) False. A wave arrives
D) False. A wave arrives
A 1055-kg van, stopped at a traffic light, is hit directly in the rear by a 715-kg car traveling with a velocity of +2.25 m/s. Assume the transmission of the van is in neutral, the brakes are not being applied, and the collision is elastic. What is the final velocity of (a) the car (b)the van?
Answer:
1.81779 m/s in the same direction as the car
0.43220 m/s in the same direction
Explanation:
[tex]m_1[/tex] = Mass of van= 1055 kg
[tex]m_2[/tex] = Mass of car = 715 kg
[tex]u_1[/tex] = Initial Velocity of van = 0 m/s
[tex]u_2[/tex] = Initial Velocity of car = 2.25 m/s
[tex]v_1[/tex] = Final Velocity of van
[tex]v_2[/tex] = Final Velocity of car
As momentum and Energy is conserved
[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]
[tex]{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}[/tex]
From the two equations we get
[tex]v_{1}=\dfrac{m_1-m_2}{m_1+m_2}u_{1}+\dfrac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\dfrac{1055-715}{1055+715}\times 0+\dfrac{2\times 715}{1055+715}\times 2.25\\\Rightarrow v_1=1.81779\ m/s[/tex]
The final velocity of the van is 1.81779 m/s in the same direction as the car
[tex]v_{2}=\dfrac{2m_1}{m_1+m_2}u_{1}+\dfrac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\dfrac{2\times 1055}{1055+715}\times 0+\dfrac{1055-715}{1055+715}\times 2.25\\\Rightarrow v_2=0.43220\ m/s[/tex]
The final velocity of the car is 0.43220 m/s in the same direction
Answer:
(a). The final velocity of the car is -0.432 m/s.
(b). The final velocity of the van is 1.82 m/s.
Explanation:
Given that,
Mass of van = 1055 kg
Mass of car = 715 kg
Initial velocity of car= 2.25 m/s
(a). We need to calculate the final velocity of the car
Using formula of velocity
[tex]v_{c}=\dfrac{m_{v}-m_{c}}{m_{v}+m_{c}}\times u_{c}[/tex]
Put the value into the formula
[tex]v_{c}=\dfrac{715-1055}{715+1055}\times2.25[/tex]
[tex]v_{c}=-0.432\ m/s[/tex]
(b). We need to calculate the final velocity of the van
Using formula of velocity
[tex]v_{v}=\dfrac{2m_{v}}{m_{v}+m_{c}}\times u_{c}[/tex]
Put the value into the formula
[tex]v_{v}=\dfrac{2\times715}{715+1055}\times2.25[/tex]
[tex]v_{v}=1.82\ m/s[/tex]
Hence, (a). The final velocity of the car is -0.432 m/s.
(b). The final velocity of the van is 1.82 m/s.
The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.
(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?
Answer:
a. P1=200235pa
b. h=26.91m
Explanation:
The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.
(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?
pressure is the force per unit area.
force is that which tends to change a boy's state of rest or uniform motion in a straight line
rho stands for the density of water which is 1000kg/m3
p2=p1+rhogh
p1=p2-rhogh
the gauge pressure at 6.5m
will be:
2.64 x 10^5 Pa-100kg/m3*9.81*6.5
P1=200235pa
b. How high could a faucet be before no water would flow from it, even if the faucet were open?
b.h=p2-p1/(grho)
h=2.64 x 105 Pa/(1000*9.81)
h=26.91m
To find the gauge pressure and height limit of a faucet on the second floor compared to the first floor in a house with a main water line.
Explanation:(a) To find the gauge pressure at the faucet on the second floor, we can use the equation: P2 = P1 + ρgh. Here, P1 = 2.64 x 105 Pa, ρ is the density of water, g is the acceleration due to gravity, and h is the height difference between the first and second floor. Plugging in the values, we get: P2 = 2.64 x 105 + (1000 kg/m3) x (9.8 m/s2) x 6.50 m. Solving for P2 gives us the gauge pressure at the faucet on the second floor.
(b) To find the maximum height a faucet could be before no water would flow from it, we can equate the gauge pressure to zero in the equation: P2 = P1 + ρgh. Solving for h, we can find the maximum height.
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Electrolytes are considered ________ when placed in a solution and allow for adequate conduction of ________ charges.
Answer:
Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.
Explanation:
Electrolytes are substances that, when are dissolved in solution, separates into electrical positive charges (cations) and electrical negative charges (anions) which are known as ions.
These ions have an adequate capacity to conduct particle charges and, therefore electricity.
Sodium, calcium, phosphate and potassium, are examples of electrolytes.
Hence, the correct answer is:
Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.
I hope it helps you!
You are standing on a scale in an elevator. suddenly you notice your weight decreases. what do you conclude? a. the elevator is accelerating downwards. b. the elevator is accelerating upwards. c. the elevator is moving at a constant velocity upwards. d. your diet is working. e. the elevator is moving at a constant velocity downwards.
Answer:
The elevator is accelerating downwards.
Explanation:
When an elevator accelerating downward it moves together with the person inside and the weight of the person does not change, but if the person is standing on a scale the contact force between the person and the scale is reduced. The scale therefore has to push upward with less force on the person to support the person's weight. Therefore the Normal Force is smaller, so the reading on the scale becomes less than the true weight.
When you feel your weight decrease in an elevator, it means that the elevator is accelerating downwards. This is due to the equivalence principle in physics, where the downward acceleration counteracts some of gravity's pull making you feel lighter.
Explanation:If you are standing on a scale in an elevator and suddenly notice your weight decreases, you can conclude that the elevator is accelerating downwards. The weight we feel is a combination of our actual weight and the effect of the elevator's motion. The apparent reduction in weight is because the downwards acceleration of the elevator is counteracting some of the pull of gravity, causing you to feel lighter.
This is a principle of physics known as the equivalence principle, which is a key part of Einstein's theory of general relativity. When the elevator accelerates downwards, we experience a sensation of decreased weight, as the floor of the elevator 'falls' away from us at an accelerated rate.
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Suppose you are driving due east, traveling a distance of 1500 min 2 minutes. You then turn due north and travel the same distance in the same time. What can be said about the average speeds and the average velocities for the two segments of the trip?
(a) The average speeds are the same, and the average velocities are the same.
(b) The average speeds are the same, but the average velocities are different.
(c) The average speeds are different, but the average velocities are the same.
Answer:
(b) The average speeds are the same, but the average velocities are different.
Explanation:
The average speed is a scalar quantity which is calculated on the total distance travelled. Distance is the length of path traced and the speed is calculated as distance per unit time.
Mathematically:
[tex]v=\frac{d}{t}[/tex]
[tex]v=\frac{(1500+1500)}{2\times 60}\ m.s^{-1}[/tex]
While the velocity is a vector quantity calculated on the displacement and is defined as the rate of displacement.
Mathematically:
[tex]\vec v=\frac{\vec s}{t}[/tex]
[tex]\vec v=\frac{\sqrt{1500^2+1500^2} }{2\times 60}\ m.s^{-1}[/tex]
Rotor windings in wound rotor motors are connected to ? on the shaft of the motor. Brushes allow those windings to be connected to external resistors to control the speed of the motor.
Answer:
Slip Rings
Explanation:
The wound rotor motor has a three-phase winding with each one connected to seperate slip rings. These slip rings contain brushes which form a secondary circuit where resistance can be inserted and this will allow for the rotor current to run more in phase with the stator current which will result in increased torque that is created
What is the person’s displacement for the trip?
what is a vector quantity? give an example.
Answer:
+ 3.0 m
Explanation:
displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.
To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?
Answer:
T=2.94*10^-10 N/m.
Explanation:
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.
To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?
l=length of the spider silk, 14cm
velocity of wave = √(T/μ)
where T = tension and
μ = mass per unit length)
λ/2=l
for fundamental frequency λ/2 =14cm
(λ= wavelength of standing wave; as there will be no node
except the endpoints of silk strand)
λ = 28 cm = 0.28 m
and since frequency * wavelength = speed of wave. we have,
150 * 0.28 = √(T/μ) ..................(#)
now μ = mass/length = [volume * density]/length = [(length*area) * density] / length = area * density
= [π * (10 * 10^(-6))²] * 1300 = 13π * 10^(-8).
now putting this in equation (#) we get
150 * 0.28 = √(T/[13π * 10^(-8)]).
thus T = [13π * 10^(-8)] * (42)² =
2.94*10^-10 N/m.
A car traveling at 7.3 m/s accelerates at the rate of 0.82 m/s2 for an interval of 7.4 s. Find vf.
Explanation:
We have equation of motion v = u + at
Initial velocity, u = 7.3 m/s
Final velocity, v = ?
Time, t = 7.4 s
Acceleration,a = 0.82 m/s²
Substituting
v = u + at
v = 7.3 + 0.82 x 7.4
v = 13.368 m/s
Final velocity is 13.37 m/s
How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
The question is asking for the distance an object will travel given its initial speed and a coefficient of friction. However, without knowing the object's mass, we cannot calculate the exact distance.
Explanation:The question is asking you to calculate the distance an object will travel, given an initial speed and friction. This is a physics problem that can be solved using the principles of friction and kinetic energy.
Since we know the coefficient of kinetic friction (μk) and initial speed (v), we can calculate the distance travelled. The frictional force is equal to μk * m * g, where m is the mass of the object and g is the gravity. However, we do not have the mass of the object.
As we have incomplete information provided in the question, we cannot calculate the exact distance travelled. The chapter references given also do not give us the necessary information to solve the problem. With full information, we would use the formula relating kinetic energy to work done by friction to find the distance:
1/2 * m * v² = μk * m * g * d, which simplifies to d = v² / (2 * g * μk)
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Which statement is TRUE? Group of answer choices a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration. b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration. c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels. d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels. e) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
Answer:
d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.
Explanation:
a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.
It has negative acceleration in the negative x-direction.
b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.
It has a positive acceleration in the negative x-direction'
c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.
It has a positive acceleration in opposite direction.
e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
It has a positive acceleration only in opposite direction .
A pump is required to lift 800 kg of water per minute from a well 14.6 m deep and eject it with a speed of 18.2 m/s..
a. How much work is done per minute in lifting the water?b. How much in giving the water the kinetic energy it has when ejected?K =?c. What must be the power output of the pump?
Answer:
a)W = 116800 J
b)KE=132496 J
c)P=4154.93 W
Explanation:
Given that
m= 800 kg/min
h= 14.6 m
v= 18.2 m/s
a)
Work done required ,W= m g h
h=height of the well
m=mass
W= 800 x 14.6 x 10 ( take g= 10 m/s²)
W = 116800 J
b)
kinetic energy = KE
[tex]KE=\dfrac{1}{2}mv^2[/tex]
m=mass
v=velocity
[tex]KE=\dfrac{1}{2}\times 800\times 18.2^2[/tex]
KE=132496 J
c)
Pump power given as
[tex]P=\dfrac{W'}{t}[/tex]
W'=Total work done
t=time
[tex]P=\dfrac{116800+132496}{60}[/tex]
P=4154.93 W
The work done per minute in lifting the water is 114,464 J. The kinetic energy given to the water when it is ejected is 132,488 J. The power output of the pump is 4116.2 W.
Explanation:The subject of this question is Physics, specifically the topic of work, energy, and power.
To calculate the work done in lifting the water, we can use the formula:
Work = Force × Distance
The force required to lift the water can be calculated using the formula:
Force = Mass × Gravity
(a) To find the work done per minute in lifting the water, we multiply the weight of the water by the height it is lifted. The weight of the water is mass times gravity, which is
Force =800 kg * 9.8 m/s^2 = 7840 N.
So, the work done is 7840 N * 14.6 m = 114,464 J.
(b) To find the kinetic energy given to the water when it is ejected, we use the formula for kinetic energy, which is 1/2 * mass * speed^2.
So, the kinetic energy = 1/2 * 800 kg * (18.2 m/s)^2
= 132,488 J.
(c) The power output of the pump is the total work done per minute divided by the time, which is
Power =(114,464 J + 132,488 J) / 60 s
= 4116.2 W.
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Torque can cause the angular momentum vector to rotate in UCM. This motion is called ___________.
Torque can cause the angular momentum vector to rotate in UCM. This motion is called _Conservation of Angular momentum__________.
Answer:
Conservation of Angular momentum
Explanation:
The motion of an object in a circular path at constant speed is known as uniform circular motion (UCM). An object in UCM is constantly changing direction, and since velocity is a vector and has direction, you could say that an object undergoing UCM has a constantly changing velocity, even if its speed remains constant.
The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
Key Points
When an object is spinning in a closed system and no external torques are applied to it, it will have no change in angular momentum.
The conservation of angular momentum explains the angular acceleration of an ice skater as she brings her arms and legs close to the vertical axis of rotation.
If the net torque is zero, then angular momentum is constant or conserved.
Angular Momentum
The conserved quantity we are investigating is called angular momentum. The symbol for angular momentum is the letter L. Just as linear momentum is conserved when there is no net external forces, angular momentum is constant or conserved when the net torque is zero. We can see this by considering Newton’s 2nd law for rotational motion:
τ→=dL→dt, where
τ is the torque. For the situation in which the net torque is zero,
dL→dt=0.
If the change in angular momentum ΔL is zero, then the angular momentum is constant; therefore,
⇒
L =constant
L=constant (when net τ=0).
This is an expression for the law of conservation of angular momentum.
Example and Implications
An example of conservation of angular momentum is seen in an ice skater executing a spin, The net torque on her is very close to zero,
because (1) there is relatively little friction between her skates and the ice, and (2) the friction is exerted very close to the pivot point.
Conservation of angular momentum is one of the key conservation laws in physics, along with the conservation laws for energy and (linear) momentum. These laws are applicable even in microscopic domains where quantum mechanics governs; they exist due to inherent symmetries present in nature.
Precession is the rotation of the angular momentum vector in uniform circular motion (UCM) caused by torque. Torque's direction aligns with the direction of the angular momentum it produces. Any alteration in angular momentum is influenced by the average torque and the time period of its exertion, adhering to the conservation laws of angular momentum.
Explanation:The motion caused by torque making the angular momentum vector to rotate in UCM is called precession. In other words, precession is the circular motion of the pole of the axis of a spinning object around another axis due to torque. This is similar to how a spinning top wobbles as it continues to spin.
For example, if we consider a merry-go-round, torque is perpendicular to the plane formed by radius and force. This direction aligns with the direction your right thumb would point to if you curled your fingers in the direction of the force. This shows that the direction of the torque is the same as that of the angular momentum it produces.
It's important to note that angular momentum, like energy and linear momentum, is conserved when the net external torque is zero. This is a universally applicable law underlying unity in physical laws. The change in angular momentum is given by the product of average torque and the time interval during which the torque is exerted, embodying the conservation laws of angular momentum.
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950 - kg toyota collides into the rear end of a 2200-kg cadillac stopped at a red light. THe bumpers lock, the brakes are locked and the two car skid forward 4.8 meteres before stopping. The police officer, knowing the the coefficient of kinetic friction between tires and road is 0.4, calculates the speed of the toyota impact. What was the speed of the car?
Answer:
u = 20.33 m/s
Explanation:
given,
mass of Toyota car = 950 Kg
mass of Cadillac = 2200 Kg
distance to stop = 4.8 m
coefficient of friction = 0.4
initial speed of the Toyota = ?
we know,
F = ma
and frictional foce
F = μ N = μ m g
where N is normal force
now equating both the equation
ma = μ m g
a = μ g
a = 0.4 x 9.8
a = 3.92 m/s²
using equation of motion
v² = u² + 2 a s
v² = 0² + 2 x 3.92 x 4.8
v = 6.13 m/s
above given velocity is the combined velocity of the Toyota and Cadillac
now, using conservation of momentum
m u = (M + m) v
950 x u = (2200+ 950) x 6.13
u = 20.33 m/s
The speed of Toyota before impact is equal to u = 20.33 m/s
Final answer:
The speed of the Toyota at the moment of impact is 0 m/s.
Explanation:
To find the speed of the Toyota at the moment of impact, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.
The momentum of an object is given by the product of its mass and velocity. So, we can write:
massT * velocityT = massC * velocityC
where massT and velocityT are the mass and velocity of the Toyota, and massC and velocityC are the mass and velocity of the Cadillac.
The mass of the Toyota is 950 kg, and the mass of the Cadillac is 2200 kg. The velocity of the Cadillac is 0 m/s because it is stopped. Solving for the velocity of the Toyota:
velocityT = (massC * velocityC) / massT
velocityT = (2200 kg * 0 m/s) / 950 kg = 0 m/s
Therefore, the speed of the Toyota at the moment of impact is 0 m/s.
A 1000-N boulder on the right end of a seesaw is raised when the left end of the seesaw is pushed downward. If both ends of the seesaw are equal distances from the fulcrum, then to raise the boulder, the left end should be pushed downward with a minimum force of
a. 500 N
b. 750 N.
c. more than 1000 N.
d. 1000 N.
Answer:
d. 1000 N.
Explanation:
For the seesaw to be in equilibrium the moment on left of the fulcrum and the moment to the right of the fulcrum must be equal.
Let L be the distance on either side of fulcrum at which the boulder is kept
F be the minimum force used to pushdown the left end
According to principle
L×1000= L×F
F= 1000 N
Hence option D is correct
To avoid compromising your car's aerodynamic properties, you should avoid ________.A. running your air conditioning system B. taking turns at high speeds C. carrying large loads on the outside of the vehicle
Answer:
C) True carrying large loads on the outside of the vehicle
Explanation:
The aerodynamic property of an object depends on its outer shape. In general, objects should be thin in the front and not completely flat in the back, to avoid the eddies that create a great Arrate, losing all the aerodynamics of the system.
With this we can review the final statements
A) False The air conditioner is used with the glasses raised, so the exterior shape of the car does not change and its aerodynamics remains unchanged.
B) Phallus. This does not change the outer shape, I get a small inclination,
C) True. External loads dramatically change the external shape of the vehicle significantly reducing its aerodynamic characteristics.
To avoid compromising your car's aerodynamic properties, avoid carrying large loads on the outside of the vehicle and taking turns at high speeds.
Explanation:To avoid compromising your car's aerodynamic properties, you should avoid carrying large loads on the outside of the vehicle. Large loads increase drag and disrupt the flow of air around the car, negatively affecting its aerodynamics. It is also advisable to avoid taking turns at high speeds as it can create instability and affect the car's balance. Running the air conditioning system does not directly impact the aerodynamic properties of the car, so it is not necessary to avoid running your air conditioning system.
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A BASE jumper runs off a cliff with a speed of Which of the following is closest to his speed after 0.5 seconds?
A) 10 m/s
B) 8 m/s
C) 6 m/s
D) 3 m/s
E) not given
Answer:
8m/s
Explanation:
The question is incomplete.
But if the given speed is 3m/s
t= 0.5s
From Newton's equation of motion v=u+at
U= 3m/s
V= 3+ 0.5×10 a=10m/s^2
v= 8m/s
Final answer:
The BASE jumper's speed after 0.5 seconds, with gravity approximated as 10 m/s², would be 5 m/s. This is calculated using kinematic equations in physics, which are not explicitly stated in the choices, therefore the correct answer is E) not given.
Explanation:
The subject of the question involves the principles of kinematics in physics. Given that we approximate the acceleration due to gravity (g) as 10 m/s², we can calculate the BASE jumper's speed after 0.5 seconds.
The formula to calculate the speed (v) of a falling object at a given time (t) when released from rest is v = gt. Therefore, after 0.5 seconds, the BASE jumper's speed would be v = 10 m/s² × 0.5 s = 5 m/s. None of the options A) 10 m/s, B) 8 m/s, C) 6 m/s, or D) 3 m/s exactly match this result. Hence, the correct answer is E) not given.
Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right?
A) Technician A
B) Technician B
C) Both technicians
D) Neither technician
Answer:
a. Technician A
Explanation:
Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right
MAF wich stands for mass airflow sensor determines the mass of air flowing into the engine's air intake system. ... , the wire cools When air flows past the wire, decreasing its resistance, thereby more current flows through the circuit. When the MAf goes bad, it can not sense the amount of air intake into the engine.
Pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach.
A. True
B. False
Answer:
TRUE
Explanation:
It is TRUE that pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach. This minimum limit of speed varies country to country.
In America, the minimum speed limit in Rural Areas is 40 mph (miles per hour) i.e. 65km/h (kilometer per hour) while in Urban Areas it is 55mph i.e. 90km/h which cannot be met by pedestrians and by-cycles easily.
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100 feet.B. a distance of 1.5 NM to RW30.C. the RW30 waypoint.
Answer:
When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:
C. the RW30 waypoint.
Explanation:
In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.The option b is incorrect as a distance of 1.5 NM to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.The option c is correct as Missed approach point is designed to coincide with the runway threshold. The RW 30 way point is referring to the way point to the threshold for the Runway 30.The missed approach point (MAP) during an LNAV approach is indicated by reaching the RW30 waypoint.
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching the RW30 waypoint. During an LNAV approach, which is a type of non-precision instrument approach procedure, pilots use lateral navigation to align with the runway. The MAP is typically defined by a waypoint and not by reaching a particular altitude or distance to the runway. Unlike precision approaches that can bring an aircraft to a lower minimum descent altitude or decision height based on a glideslope, LNAV approaches only provide lateral guidance and rely on predetermined waypoints to establish the MAP.
As a result of the motion through the magnetic field, a charge in the rod will experience a force F⃗ =qv⃗ ×B⃗ : the usual part of the Lorentz force for charges moving through magnetic fields. This force will push the charge in the rod, and hence this force will be an electromotive force (EMF). For now, we shall say that the force that moves the charges is due to an induced electric field Einduced, which will enable us to calculate the EMF. The fact that there is an induced electric field at all is rather subtle, because there is no closed loop that encloses some changing flux. Therefore, a method that does not involve Faraday's law must be used to solve this motional EMF problem. In fact, this problem is a good introduction to some of the ideas behind Faraday's law. Find the y component of the induced electric field Einduced.
Based on the information given, it should be noted that the y component of the induced electric field will be E = -Bv.
An induced electric field simply means a nonconversative field that is generated due to a changing magnetic field.
The force that acts on the charge moving with the velocity is given. In this case, the component of the induced electric field will be E = -Bv.
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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volume of the gas? (Assume that there's no change in temperature.)A. 100 cubic inchesB. 10 cubic inchesC. 40 cubic inchesD. 5 cubic inches
Answer:
B. [tex]V_{f}= 10\,cubic\,inches [/tex]
Explanation:
Assuming we are dealing with a perfect gas, we should use the perfect gas equation:
[tex]PV=nRT [/tex]
With T the temperature, V the volume, P the pressure, R the perfect gas constant and n the number of mol, we are going to use the subscripts i for the initial state when the gas has 20 cubic inches of volume and absolute pressure of 5 psi, and final state when the gas reaches 10 psi, so we have two equations:
[tex]P_{i}V_{i}=n_{i}RT_{i} [/tex] (1)
[tex] P_{f}V_{f}=n_{f}RT_{f}[/tex] (2)
Assuming the temperature and the number of moles remain constant (number of moles remain constant if we don't have a leak of gas) we should equate equations (1) and (2) because [tex] T_{i}=T_{f}[/tex], [tex]n_{i}=n_{f} [/tex] and R is an universal constant:
[tex]P_{i}V_{i}= P_{f}V_{f} [/tex], solving for [tex]V_{f} [/tex]
[tex]V_{f} =\frac{P_{i}V_{i}}{P_{f}} =\frac{(5)(20)}{10} [/tex]
[tex]V_{f}= 10 cubic\,inches [/tex]
The instructions for a 13-foot ladder state that the bottom of the ladder must be set at least 5 feet from a building. How high can the ladder safely reach on the garage?
Answer:
The height at which the ladder safely reach on the garage is 12 meters.
Explanation:
It is given that,
Height of the ladder, H = 13 foot
Bottom of the ladder, B = 5 feet
To find,
How high can the ladder safely reach on the garage?
Solution,
The ladder and the wall follows the Pythagoras theorem. 13 foot is the height of the ladder. Distance between wall and the ladder is 5 feet. Let L is the height at which the ladder safely reach on the garage. On using Pythagoras theorem we get :
[tex]H^2=B^2+L^2[/tex]
[tex]L^2=H^2-B^2[/tex]
[tex]L^2=13^2-5^2[/tex]
L = 12 m
So, the height at which the ladder safely reach on the garage is 12 meters. Hence, this is the required solution.
During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total mass of the black residue formed was 79.6 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations
Answer:
See below explanation
Explanation:
The correspondent chemical reaction for copper carbonate decomposed by heat is:
CuCO₃ (s) → CuO (s) + CO₂ (g)
Considering all molar mass (MM) for each element ( we consider rounded numbers) :
MM CuCO₃ = 123 g/mol
MM CuO = 79 g/mol
MM CO₂ = 44 g/mol
Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.
So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which "escaped" from our system, since it is a gas compound (CO₂)
If an apprentice makes 55% of Journeyman wages, what would an apprentice make per hour if the Journeyman scale is $17.64?
Answer:
$9.702 per hour
Explanation:
The apprentice earns 55% of what the journeyman earns on a hourly scale.
Amount the apprentice makes per hour = 55% of $17.64
= (55/100) *17.64
= 0.55 *17.64
= $9.702
The apprentice would make $9.70 per hour if the Journeyman scale is $17.64, as 55% of $17.64 is $9.70.
Explanation:Given:
Journeyman scale = $17.64/hour
Apprentice wages = 55% of Journeyman wages
Calculation:
Apprentice wages = 0.55 * $17.64
Apprentice wages = $9.702
Therefore, an apprentice would make $9.70 per hour.
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A box of mass 45 kg slides down a ramp onto a flat surface. The box slides a distance of 4.9 m across the flat surface and then stops. The coefficient of friction between the flat surface and the box is 0.39. What was the speed of the box at the base of the ramp?
6.1 m/s
0.77 m/s
3.0 m/s
19 m/s
Answer:
6.1 m/s
Explanation:
Gradpoint