A ball rolls off the edge of a horizontal roof at 10 m/s. 2 seconds later, the speed of the ball will be? a. 10 m/s b. 19.6m/s c. 29.6 m/s d.22 m/s ...?

Answers

Answer 1
Final answer:

The ball will have a speed of 22 m/s after 2 seconds.

Explanation:

When the ball rolls off the edge of a horizontal roof, it becomes a projectile and begins to fall under the influence of gravity. The horizontal component of its velocity remains constant, so after 2 seconds, the ball will still have a horizontal speed of 10 m/s.

However, the vertical component of its velocity will increase due to the acceleration of gravity. The acceleration due to gravity is approximately 9.8 m/s². So after 2 seconds, the ball will have accelerated 9.8 m/s² for 2 seconds, resulting in a change in velocity of 19.6 m/s.

To find the speed of the ball after 2 seconds, we need to find the resultant velocity by using the Pythagorean theorem. The initial horizontal velocity is 10 m/s and the change in vertical velocity is 19.6 m/s. So:

Resultant velocity = sqrt((10)^2 + (19.6)^2) = 22 m/s.

Therefore, the correct answer is d. 22 m/s.

Answer 2

Final answer:

The final speed of a ball rolling off a horizontal roof with an initial horizontal speed of 10 m/s after 2 seconds will be 22 m/s, due to the additional vertical velocity it gains from gravity. So the correct option is d.

Explanation:

A ball rolls off the edge of a horizontal roof at 10 m/s. To determine the speed of the ball 2 seconds later, we use the equation for the final velocity of an object in free fall: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and t is time. Since the ball rolls off horizontally, the initial vertical velocity is 0, and the horizontal velocity remains the same since there's no air resistance. Hence, the horizontal velocity after 2 seconds is still 10 m/s. For the vertical velocity, we use u=0, a=9.8 m/s², and t=2 s:

Vertical velocity after 2 seconds = 0 m/s + (9.8 m/s² * 2 s) = 19.6 m/s

We now have both horizontal and vertical velocities. The speed of the ball will be the vector sum of these two velocities, calculated using the Pythagorean theorem:

Total speed = sqrt(10 m/s² + 19.6 m/s²) = 22 m/s

Therefore, the correct answer is (d) 22 m/s.


Related Questions

A large region of gas and dust that may contain as many as one million solar masses is called a _____.
a. galaxy
b. protostar
c. supernova remnant
d. giant molecular cloud

Answers

The correct answer that would best complete the given statement above would be option B. PROTOSTAR. A large region of gas and dust that may contain as many as one million solar masses is called a protostar or star formation. Protostar is a contracting mass of gas that represents an early stage in the formation of a star. Hope this helps.

Answer:

a giant molecular cloud.

Explanation:

two vectors A and B have components (0,1) and (-1,3), respectively. What is magnitude of the sum of these two vectors?

a) 3.2
b) 4.1
c) 3.9
d) 2.8

Answers

We first add the x and y components of the vector to get the x and y components of the resultant vector:
(0 - 1, 1 + 3)
-1 , 4
magnitude = √(1² + 4²)
magnitude = 4.12
The answer is B

What process occurs when all of the energy from light waves is transferred to a medium?

Answers

Absorption occurs when all of the energy from light waves is transferred to a medium! 

Answer:

absorption

Explanation:

Which of the following materials is likely to be the best conductor?
iron
sulfur
carbon
tin

Answers

Iron is the best conductor in this group.

Answer: Option (a) is the correct answer.

Explanation:

Metals are the substance which have excess of electrons. Therefore, they are good conductors of heat and electricity as they have mobile electrons.

Out of the given options, iron is a transition metal which are good conductors of heat and electricity.

Sulfur and carbon are non-metals, therefore, they are bad conductors of heat and electricity.

Tin is a poor metal so it will not conduct electricity effectively as compared to iron.

Thus, we can conclude that out of the given options, iron is likely to be the best conductor.

What is the gravitational force between two masses of 15kg each, when their centers are 0.25m? Could you detect this force with even sensitive equipment?

Answers

Well I don't know !
Let's work it out.

The gravitational force between two objects is

                     F  =  G  ·  M₁·M₂ / R²     .

'G'    is the 'universal gravitational constant'.  We could look it up. 
'M₁'  is the mass of one object
'M₂'  is the mass of the other object 
'R'    is the distance between their centers. 

It looks complicated, but stay with me.  We can do this !
We know all the numbers, so we can calculate the force.

'G'    is  6.67 x 10⁻¹¹ newton·meter² / kg²   (I looked it up.  You're welcome.)
'M₁'  is  15 kg
'M₂'  is  15 kg 
'R'    is  0.25 meter.

Now it's time to pluggum in.

       F  =  G  ·  M₁·M₂ / R²

           = (6.67 x 10⁻¹¹  newton·meter² / kg²) · (15 kg) · (15 kg)  /  (0.25 m²)

           = (6.67 x 10⁻¹¹  ·  15  ·  15 / 0.0625)  N·m²·kg·kg / kg²·m²

           =      2.4 x 10⁻⁷  Newton  .

That a force equivalent to about  0.00000086  of an ounce.
This is the answer to part-a.

Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos. 
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES !  THESE guys could detect and measure
a force of  0.86 micro-ounce if they felt like it !

A roller coaster car is on a track that forms a circular loop in the vertical plane. If the car is to just maintain contact with the track at the top of the loop, what is the value of its centripetal acceleration at that point?

Answers

a. The value for the centripetal acceleration is g downward.

(correct answer on plato just did the mastery for this one)


Final answer:

At the top of the loop, where a roller coaster car is just maintaining contact with the track, its centripetal acceleration equals the acceleration due to gravity, which is 9.8 m/s².

Explanation:

The value of the centripetal acceleration at the top of the loop, where a roller coaster car just maintains contact with the track, is equal to the acceleration due to gravity, which is 9.8 m/s². This can be deduced from the balancing forces at the top of the loop. In this situation, the force due to gravity is acting downwards while the centripetal force is also acting downwards - directed towards the center of the circular path. Therefore, these forces must match at the top of the loop for the car to just maintain contact with the track. This gives us the equation for centripetal acceleration, ac = g , where ac is the centripetal acceleration and g is the acceleration due to gravity.

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A bullet is fired horizontally from the top of a building with a muzzle velocity of 150 m/s.A similar bullet dropped from the top of the same building, takes 4 sec to reach the ground. How far forward does the first bullet go before it hits the ground?

Answers

Final answer:

The horizontal distance traveled by the bullet before hitting the ground is 600 meters.

Explanation:

To determine how far forward the bullet goes before it hits the ground, we can use the fact that both the horizontally fired bullet and the dropped bullet hit the ground after a certain time. The dropped bullet takes 4 seconds to reach the ground, so we can consider its vertical motion using the equation h = 0.5 * g * t^2, where h is the height, g is the acceleration due to gravity, and t is the time. Plugging in the values, we get 0 = 0.5 * 9.8 * 4^2, which gives us h = 78.4 meters.

Since the horizontally fired bullet has the same horizontal velocity as the dropped bullet, it would take the same time to reach the ground. This means that the horizontally fired bullet travels a horizontal distance equal to its horizontal velocity multiplied by the time it takes to reach the ground. Plugging in the values, we get d = 150 * 4 = 600 meters.

Therefore, the first bullet travels 600 meters forward before hitting the ground.

The bullet fired horizontally travels 600 meters before hitting the ground because it takes the same 4 seconds as the dropped bullet to reach the ground, and it travels at a horizontal velocity of 150 m/s.

Step-by-Step Explanation:

Calculate the horizontal distance using the formula: distance = velocity x time.Here, the muzzle velocity of the bullet is 150 m/s and the time is 4 seconds.Distance = 150 m/s * 4 s = 600 meters.

Conclusion:

The bullet fired horizontally travels 600 meters before it hits the ground.

Which voice can produce a pitch that has a speed of 343 m/s and a wavelength of 0.68m?

Answers

Soprano is the answer :), Hope this helps

A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2.00 m making 0.700 revolutions per second. What is the centripetal acceleration of the ball?

Answers

Centripetal acceleration = (speed)²/(radius) .

We know the radius.  We have to find the speed.

Speed around a circle = (circumference) / (time to go around)

The circumference of the circle is  (2 π) (radius) = 4 π meters.

We don't exactly know the time to go around.
We know that the ball goes around 0.7 times/second.
Flip that over, and you have  time to go around = second/0.7 .

So now, the centripetal acceleration is

                                   (speed)²/(radius) .

                             =  (4π meters · 0.7/sec)² / (2 meters)

                             =  (4π · 0.7 / 2)    m/s²

                             =      about        4.4 m/s²

The centripetal acceleration of the ball will be 38.68 meter per sq.second.

What is centripetal acceleration?

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course.

The given data in the problem;

r is the radius= 2.00m

frequency (f) = 0.7 rev/s

The angular velocity is found as;

[tex]\rm \omega = 2 \pi f \\\\ \omega = 2 \times 3.14 \times 0.7 \\\\ \omega = 4.398 \ rad/sec[/tex]

The centripetal acceleration is given by;

[tex]\rm a_c= \omega^2r \\\\\ a_c= (4.398)^2 \times 2.00 \\\\ a_c=38.68 \ m/sec^2[/tex]

Hence, the centripetal acceleration of the ball will be 38.68 meter per sq.second.

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How is light used to study space? IN YOUR OWN WORDS

Answers

Well, all the words are common, but I try to answer in my way. The way how light is used to study space is finding distance between the planets, which is called a light year. According to the scientist's beliefs the space is but a vaccum and the only body that can travel through it is light, that's why light is very importand for discovering space.
Hope you will find it helpful!

An electromagnet is a temporary magnet due to which of the following?

The magnet is only present when a current is present

The magnet is only present when the domains are not aligned

The magnet is only present when the current is turned off

The magnet is only present when the resistance is high

Answers

A is your answer The magnet is only present when a current is present

Q1. After three half-lives of an isotope, 1 billion of the original isotope's atoms still remain in a certain amount of this element. How many atoms of the daughter product would you expect to be present?

Q2. By measuring the amounts of parent isotope and daughter product in the minerals contained in a rock, and by knowing the half-life of the parent isotope, a geologist can calculate the absolute age of the rock. A rock contains 125 g of a radioisotope with a half-life of 150 000 years and 875 g of its daughter product. How old is the rock according to the radiometric dating method?

Answers

 If 1 eighth equals 1 billion 7 eighth equals 7 billion. 

The asker of the second question needs a tutorial in radiometric dating. There is little likelihood that the daughter isotope has the same atomic weight as the parent isotope. To measure the mass isotopes doesn't tell us how many atoms of each exist. To get around that let's pretend — which will likely serve the purpose ineptly intended — that the values give an the particle ratio, 125:875. 

The original parent isotope count was 125 + 875 = 1000. The remaining parent isotope is 125/1000 or 1/8. 1/8 = (1/2)^h, where h is the number of half-lives. 

h = log (1/8) ÷ log(1/2) = 3 

And 3 half-lives • 150,000 years/half-life = 450,000 years.

If two carts collide, what type of collision will conserve both momentum and kinetic energy?

a. head on

b. perfectly inelastic

c. none

d. perfectly elastic

Answers

The appropriate answer is d. perfectly elastic. When a perfectly elastic collision occurs both momentum and kinetic energy are preserved. Momentum is the mass of an object times its velocity while kinetic energy is the energy that a moving object has due to its motion. In an elastic collision kinetic energy would be converted to some other form of energy. 

The crankshaft in a race car goes from rest to 3540rpm in 2.6s. What is the crankshaft's angular acceleration? How many revolutions does it make while reaching 3540rpm?

Answers

w = wa + at

wa = 0

w = at

a = w/t

3540/ 2.6  x 2pi/1 rev x 1 min/60 sec = 142.58 rad/s

for the second part, use angular displacement formula

hope this helps

Which example provides the most complete description of an object's motion?
1. The ballerina rotated 10 times in 2 minutes.
2. Bobby threw a Frisbee 10 m through the hoop.
3. The turtle took 20 minutes to make it to the other side of the road.
4. The hiker followed a road heading north for 2 miles in 30 minutes.

Answers

Answer:

The hiker followed a road heading north for 2 miles in 30 minutes.

Explanation:

In order to describe the motion of an object, distance covered and time taken must be required. The total path covered by an object is called the distance travelled.

The hiker followed a road heading north for 2 miles in 30 minutes. This describes the motion of hiker. The motion shows how fast the hiker is moving.  

Distance, d = 2 miles = 3218.6 m

times, t = 30 minutes = 1800 seconds

So, we can say that the hiker is moving with a speed of 1.78 m/s in north direction.

Hence, this is the required solution.

Answer:

In this case in option 4:

The hiker followed a northbound road for 2 miles in 30 minutes.

Explanation:

Hello ! Let's solve this!

To know the description of a movement we have to know the distance it travels and the time it takes to travel it.

In this case in option 4:

The hiker followed a northbound road for 2 miles in 30 minutes.

Distance: 2 miles

time: 30min

Then we can calculate the speed of the hiker

Suppose a planet has twice the mass of the earth and twice the earth's radius. What is the acceleration of an object in free fall on this planet?

2.5 m/s2

4.9 m/s2

9.8 m/s2

4.9 × 106 m/s2

...?

Answers

Final answer:

The acceleration of an object in free fall on a planet that has twice the mass of the Earth and twice the Earth's radius is 4.9 m/s², half of the acceleration on Earth.

Explanation:

The acceleration of an object in free fall on a planet depends on the mass and radius of the planet. In this case, the planet has twice the mass of the Earth and twice the Earth's radius. To calculate the acceleration, we can use the formula for gravitational acceleration:

g = (G * M) / R^2

Where g is the acceleration, G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.

Since the planet has twice the mass and twice the radius of the Earth, we can substitute those values into the formula:

g = (G * 2M) / (2R)^2 = (2 * G * M) / (4 * R^2) = G * M / (2 * R^2)

So the acceleration of an object in free fall on this planet is half of the acceleration on Earth, which is 4.9 m/s².

a baseball pitcher throws a fastball at 42 meters per second. if the batter is 18 meters from the pitcher, approximately how much time does it take for the ball to reach the batter?

Answers

t = distance div time = 18/42 = 3/7 seconds = 0.4 seconds

less than half of a second

The time taken by the ball to reach the batter is 0.42 seconds

The baseball pitcher throws a fastball at 42 m/s

The batter is about 18 meters from the pitcher

Therefore the time for the ball to reach the batter can be calculated as follows;

= 18/42

= 0.42 secs

Hence the time taken by the ball to reach the batter is 0.42 seconds

Please see the link below for more information

https://brainly.com/question/13719636?referrer=searchResults

A cold beer initially at 35ºF warms up to 40ºF in 3 min while sitting in a room of temperature 70ºF. How warm will the beer be if left out for 20 min

Answers

Final answer:

Using Newton's law of cooling, we can calculate that the beer will be approximately 60.4ºF if left out for 20 minutes.

Explanation:

To calculate the final temperature of the beer after being left out for 20 minutes, we can use Newton's law of cooling. This law states that the rate of heat loss of an object is proportional to the temperature difference between the object and its surroundings. In this case, the initial temperature of the beer is 40ºF and the room temperature is 70ºF. Let's determine the constant of proportionality, k, first:

k = (T2 - T1) / t = (70 - 40) / 3 = 10

Now we can use the formula to find the final temperature, T3, after 20 minutes:

[tex]T3 - 70 = (40 - 70)e^(-10(20/3))[/tex]

[tex]T3 - 70 = -30e^(-20/3)[/tex]

[tex]T3 = 70 - 30e^(-20/3)[/tex]

Using a calculator, we can find that T3 is approximately 60.4ºF.

Which best supports the idea that the surface of the moon has changed very little?

a) If photographs of the moon were taken millions of years ago, the surface would look the same.
b) Because the moon does not have a large iron core, it is not possible for geologic events to occur on the moon.
c) Because the moon has no atmosphere, it is not possible for geologic events to occur on the moon.
d) If one considers the history of the moon, there is only one distinct phase of its development.

Answers

The correct answer is c) Because the moon has no atmosphere, it is not possible for geologic events to occur on the moon.

Atmosphere is related to geological change because of things such as wind and water erosion that over time change the landscape, and there's neither on the moon. It's just a floating rock.

A football is kicked at an 50 degree angle to the horizontal , travels a horizontal distance of 20m before hitting the ground. what is the initial speed?

Answers

let u be the initial velocity , devide it into two component x and y the angle is 50 degree given so u in x direction = u cos50 in y direction = u sine50 time period = t= (2 u sine50)/g and horizontal distance = u cos50 * t ( acceleration in x direction is zero)by putting the value of t in above eqn yuou will get s=ucos50* (2 u sine50)/g 20 g = 2 u^2 cos50 * sine50 from here u can get the value of u which is initial velocity....

Answer:

Initial speed of football=14.11m/s

Explanation:

Range is the horizontal distance travelled. Therefore using formular for Range,R to determine the speed.

R=V^2Sin2theta/g

Given: R=20m

Theta=50°

20= V^2 Sin(2×50)°/ 9.8

Cross multiply

20×9.8 = V^2 Sin100°

196= V^2×0.9848

V=Sqrt(196/0.9848)

V= 14.11m/s

A 17,000-kg airplane lands with a speed of 82 m/s on a stationary aircraft carrier deck that is 115 m long. find the work done by nonconservative forces in stopping the plane

Answers

Final answer:

The work done by nonconservative forces in stopping the 17,000-kilogram airplane landing at a speed of 82 m/s is 57,062,000 Joules. This is calculated by the change in kinetic energy of the airplane when it lands and comes to a stop.

Explanation:

The question refers to the concept of work-energy theorem in Physics, especially involving non-conservative forces. The airplane is initially moving and finally comes to rest. Its initial kinetic energy (KE) gets transferred to work done by nonconservative forces, which in this scenario includes friction due to the aircraft carrier deck and air resistance.

The initial kinetic energy of the plane is calculated using the formula 1/2 * m * v^2 where 'm' is the mass of the plane and 'v' is its speed. So, the initial kinetic energy of the plane is 1/2 * 17,000 kg * (82 m/s)^2 = 57,062,000 Joules. When the plane comes to rest, its final kinetic energy is 0. As per the work-energy theorem, the work done by nonconservative forces is equal to the change in the kinetic energy. Therefore, the work done by nonconservative forces in stopping the plane = Initial KE - Final KE = 57,062,000 Joules - 0 = 57,062,000 Joules.

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The work done by nonconservative forces in stopping the airplane is  [tex]{57,154,000 \, \text{J}}[/tex].

To find the work done by nonconservative forces (like friction and air resistance) in stopping the airplane, we can use the work-energy principle. The work done by the nonconservative forces is equal to the change in the kinetic energy of the airplane.

Step-by-Step Solution

1. Calculate the initial kinetic energy ([tex]KE_{\text{initial}}[/tex]):

[tex]KE_{\text{initial}} = \frac{1}{2} m v^2[/tex]

where:

- m is the mass of the airplane (17,000 kg),

- v is the initial speed (82 m/s).

[tex]KE_{\text{initial}} = \frac{1}{2} \times 17,000 \, \text{kg} \times (82 \, \text{m/s})^2 \\\\KE_{\text{initial}} = \frac{1}{2} \times 17,000 \times 6,724 \\\\KE_{\text{initial}} = 57,154,000 \, \text{J}[/tex]

2. Calculate the final kinetic energy ([tex]KE_{\text{final}}[/tex]):

Since the airplane comes to a stop, its final speed is 0 m/s.

[tex]KE_{\text{final}} = \frac{1}{2} m (0)^2 = 0 \, \text{J}[/tex]

3. Calculate the change in kinetic energy (ΔKE):

[tex]\Delta KE = KE_{\text{final}} - KE_{\text{initial}} \\\\\Delta KE = 0 \, \text{J} - 57,154,000 \, \text{J} \\\\\Delta KE = -57,154,000 \, \text{J}[/tex]

4. The work done by nonconservative forces (W):

The work done by nonconservative forces is equal to the negative of the change in kinetic energy (since they are doing work to stop the airplane).

[tex]W = -\Delta KE \\\\W = -(-57,154,000 \, \text{J}) \\\\W = 57,154,000 \, \text{J}[/tex]

Therefore, the work done by nonconservative forces in stopping the airplane is [tex]{57,154,000 \, \text{J}}[/tex] .

What would a drummer do to make the sound of a drum give a note of lower pitch?

a. hit the drum skin with a larger force b. hit the drum skin with a smaller force

c. hit the drum skin nearer the edge d. loosen the drum skin ...?

Answers

The best and most correct answer among the choices provided by your question is the third choice or letter C.

Hitting the drum skin nearer the edge is what would a drummer do to make the sound of a drum give a note of lower pitch.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

A soccer player kicks a soccer ball at +10.0 m/s at an angle of 60°. What are the horizontal and vertical components of velocity of the kick?

Answers

This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.

Answer:

Horizontal component: [tex]V_{x}=+5m/s[/tex]

Vertical component: [tex]V_{y}=+8.66m/s[/tex]

Explanation:

We have the launch speed [tex]V =+ 10m/s[/tex] and the angle of 60°, so the components of the speed  [tex]V_{x}[/tex] and  [tex]V_{y}[/tex] are those shown in the attached image.

[tex]V_{x}[/tex] which is the horizontal component of the velocity can be found by multiplying the cosine of the angle by the initial velocity:

[tex]V_{x}=+10m/s(cos60)\\V_{x}=+10m/s(0.5)\\V_{x}=+5m/s[/tex]

[tex]V_{y}[/tex] which is the verticalcomponent of the velocity is found by multiplying the sine of angle by the initial velocity

[tex]V_{y}=+10m/s(sin60)\\V_{y}=+10m/s(0.866)\\V_{y}=+8.66m/s[/tex]

In summary:

Horizontal component: [tex]V_{x}=+5m/s[/tex]

Vertical component: [tex]V_{y}=+8.66m/s[/tex]

Most of the Earth's volcanoes occuWhen fossils or minerals form, certain unstable elements are sometimes locked into them. The proportion of these unstable elements gradually decreases over time as they decay into other materials in a predictable way. Scientists use the rate at which such unstable elements decay to determine when the fossils or minerals formed. The technique described above is known as as

Answers

Radioactive dating, is your answer.

Which of Newton's Three Laws does the following statement satisfy?
For every action there is an equal and opposite reaction.
A
Newton’s First Law
B
Newton’s Second Law
C
Newton’s Third Law

Answers

The answer is C) Newton's Third Law
Newtons third law states that when one body exerts a force on another, the second exerts a force on the first. These two forces are always equal in magnitude and opposite in directions. Option C is the correct answer

You want to be shielded from all three types of nuclear radiation. If you find shielding that blocks radiation, then it will most likely also block the other two types.

Answers

The correct answer to the question is gamma radiation . Therefore shielding that blocks gamma radiation, then it will most likely also block the other two types.

Radiation shielding is crucial to protect against the three types of radiation emitted by radioactive elements: alpha, beta, and gamma rays. Different materials are used for shielding based on the type of radiation and its penetrating power. For example, a sheet of paper can stop alpha particles, while thick lead or concrete is needed to absorb gamma rays.

Complete question:

You want to be shielded from all three types of nuclear radiation. If you find shielding that blocks ______ radiation, then it will most likely also block the other two types.

Will a solid metal sphere hold a larger elaectric charge than a hollow sphere of the same diameter?Where does the charge reside in each case? ...?

Answers

The answer would be no. Both will have same charge, in both caes charge will reside on surface. In case of solid sphere it will be distributed evenly throughout. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

A rectangular pool has a volume of 375 m3. the pool is 10 m long and 5 m wide. how deep is the pool? 7.5 m 3,750 m 75 m

Answers

V=L•W•H. Sub in what you know: 375=10•5•H. Simplify: 375=50H. Divide by 50: 375/50=H. H=7.5 :)
the pool is 7.5m deep

The height of a triangle is 4 in. greater than twice its base. The area of the triangle is no more than 168 in.2. Which inequality can be used to find the possible lengths, x, of the base of the triangle?

Answers

The inequality x² + 2x - 168 ≤ 0 can be used to determine the possible lengths of the base of a triangle when the height is 4 inches greater than twice the base and the area is no more than 168 square inches.

To find the possible lengths of the base of a triangle where the height is 4 inches greater than twice the base and the area is no more than 168 square inches, we start with the formula for the area of a triangle:

Area = (1/2) × base × height.

Let the base be x. Thus, the height can be expressed as 2x + 4. Therefore, the area equation becomes:

(1/2) × x × (2x + 4) ≤ 168

To simplify this, multiply both sides by 2:

x(2x + 4) ≤ 336

Expanding and rearranging the terms gives:

x²  + 4x ≤ 336

Subtract 336 from both sides to form a quadratic inequality:

x²  + 4x - 336 ≤ 0

Divide the entire inequality by 2 to simplify:

x²  + 2x - 168 ≤ 0

This is the inequality that can be used to find the possible lengths of the base of the triangle.

Conceptual Question 8.09osama wadi


Part A
In a perfectly ELASTIC collision between two perfectly rigid objects
the momentum of each object is conserved.
both the momentum and the kinetic energy of the system are conserved.
the kinetic energy of the system is conserved, but the momentum of the system is not conserved.
the kinetic energy of each object is conserved.
the momentum of the system is conserved but the kinetic energy of the system is not conserved.
...?

Answers

The best and most correct answer among the choices provided by your question is the first choice or letter A.

In a perfectly ELASTIC collision between two perfectly rigid objects,
the momentum of each object is conserved.


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