In a calorimetry experiment, the heat released when a 1.0-g sample of a candy bar burned can be calculated using the formula q = mcΔT. The heat released is 3100 calories. Converting this to nutritional Calories and calculating the energy content (fuel value) in Cal/g gives an energy of 3.1 Cal/g. The total caloric content of the candy bar is calculated by multiplying the energy content by the mass of the candy bar.
Explanation:a. Calculate the amount of heat in calories released when the 1.0-g sample burned.
The heat released can be calculated by using the formula:
q = mcΔT
Where:
q is the heat released in caloriesm is the mass of the water (1000g)c is the specific heat capacity of water (1 cal/g°C)ΔT is the change in temperature (24.3 - 21.2 = 3.1°C)Plugging in the values into the formula:
q = (1000g)(1 cal/g°C)(3.1°C) = 3100 calories
b. Convert the heat in calories to nutritional Calories and then calculate the energy content (fuel value) in Cal/g.
Nutritional Calories are equivalent to 1000 calories. To convert from calories to nutritional Calories:
Energy in nutritional Calories = heat released in calories / 1000
Energy in nutritional Calories = 3100 calories / 1000 = 3.1 nutritional Calories
Energy content (fuel value) in Cal/g = energy in nutritional Calories / mass of the sample (1.0g)
Energy content in Cal/g = 3.1 nutritional Calories / 1.0g = 3.1 Cal/g
c. Calculate the total caloric content of the candy bar in Calories.
To calculate the total caloric content of the candy bar in Calories, we can use the formula:
Total caloric content = energy content (fuel value) in Cal/g * mass of the candy bar (75.0g)
Total caloric content = 3.1 Cal/g * 75.0g = 232.5 Calories
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A sample of an unknown liquid has a volume of 30.0 mL and a mass of 6g.What is its density?
A sample of an unknown liquid has a volume of 30.0 mL and a mass of 6g. The density will be 0.2 g/ml.
What is density?Density is defined as the mass in relation to volume. Density is denoted by the capital letter D and the symbol rho. The formula is to divide the mass by the volume.
The area occupied by a three-dimensional object is its volume. It can be determined using density and mass. Liters are used to measure it. The overall weight of a thing is its mass. M designates it.
rho = m / V
rho = density
m = mass
V = volume
Given, that the mass of the sample of unknown liquid is 6 g. Here the sample of an unknown liquid is given, and the density has to be calculated.
The volume of 30.0 mL
Putting the values in the equation
Density = 6 / 30.0 = 0.2
Thus, the density of the unknown liquid is 0.2 g/ml
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does a basketball float or sink in water
The basketball float on water.
Why does basketball floats on water?The basketball float on water because,
Since, density is the main factor which determine whether an object float or sink. Density is directly proportional to mass of the object and inversely proportional to the volumeSo, as volume of object increases the density decreases or vice versa and mass of the object increases the density increases or vice versa.Since, object which is tightly packed is more dense as compare to molecule which spread out.The object which is more dense than water that sink and object which is less dense as compare to water that float.Since, mass of the basketball is less than water . So, its density is less as compare to water. Therefore basketball floats.learn about density,
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