Explanation:
Acceleration is change in velocity over change in time:
a = Δv / Δt
a = (10 m/s - 25 m/s) / (240 s - 0 s)
a = -0.0625 m/s²
So the car decelerates at 0.0625 m/s².
Which are examples of a medium? water and air amplitude and wavelength crests and troughs compressions and rarefactions
Answer:
water and air
Explanation:
A wave is a transmission of a disturbance from one point or the source to another point.Transmission of a wave occurs through a material medium or a vacuum. Therefore a medium is the material through which a wave travels through. The medium may be in gaseous form, slid form or liquid form. Therefore water and air are example of medium of transmission of a wave.Air and water offer passage to waves so each can serve as a medium. A medium is the material through which waves pass.
What is a medium?The term medium refers to a pathway through which waves can pass. It refers to any thing that can offer a passage to waves.
Having known what a medium is, we now ask ourselves, what are the tings among the options that can serve as a medium? Clearly air and water offer passage to waves so each can serve as a medium.
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SO what exactly is beyond our atmosphere, like space, has anybody actually been in space ????? or are we just making hopeless fantasies
Answer:
The universe, milky Way even black holes. Yes the first people who went to the moon put a flag to represent America. We are not making hopeless fantasies.
Explanation:
A light ray in air is incident on an air to glass boundary at an angle of 40 degrees and is refracted in the glass of 25 degrees with the normal. What is the index of refraction of the glass? A. 1.10 B. 1.25 C. 1.33 D. 1.52 HELP PLEASE!!!!!!!!!
Answer:
D
Explanation:
Snell's law states:
n₁ sin θ₁ = n₂ sin θ₂
where n is the index of refraction and θ is the angle of incidence (relative to the normal).
The index of refraction of air is approximately 1. So:
1 sin 40° = n sin 25°
n ≈ 1.52
Theindex of refraction of glass is calculated to be 1.52, which is option D.
To find the index of refraction of glass when a light ray in air is incident on an air to glass boundary at an angle of 40 degrees and is refracted in glass at 25 degrees with the normal, we use Snell's law. Snell's law is expressed as n1 sin(θ1) = n2 sin(θ2), where n1 and n2 are the indices of refraction of the first and second mediums, respectively, and θ1 and θ2 are the angles of incidence and refraction, respectively. Given that the index of refraction of air (n1) is approximately 1, we can solve for the index of refraction of glass (n2) as follows: 1 ×sin(40 degrees) = n2 × sin(25 degrees). Solving this equation gives us n2 = 1.52, which indicates the index of refraction of the glass is 1.52, corresponding to option D.
Work and Energy
A 68 kg students runs up a flight of stairs 3.5 meters high in 11.4 seconds. The student takes 8.5 seconds to run up the same flight of stairs during a second trial. Determine the following:
a. The work done in each trial. You should identify these values as W1 and W2.
b. The power exerted by the student in each trial. You should identify these values as P1 and P2.
a) [tex]W_1 = 2332 J[/tex], [tex]W_2= 2332 J[/tex]
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
[tex]W=mg\Delta h[/tex]
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
[tex]\Delta h[/tex] is the gain in height of the student
For the first student, [tex]\Delta h = 3.5 m[/tex], so the work done is
[tex]W_1 = (68)(9.8)(3.5)=2332 J[/tex]
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
[tex]W_2 = (68)(9.8)(3.5)=2332 J[/tex]
2) [tex]P_1 = 204.6 W[/tex], [tex]P_2 = 274.4 W[/tex]
The power exerted by each student is given by
[tex]P=\frac{W}{t}[/tex]
where
W is the work done
t is the time taken
For the first student, [tex]W_1 = 2332 J[/tex] and [tex]t=11.4 s[/tex], so the power exerted is
[tex]P_1 = \frac{W_1}{t_1}=\frac{2332 J}{11.4 s}=204.6 W[/tex]
For the second student, [tex]W_2 = 2332 J[/tex] and [tex]t=8.5 s[/tex], so the power exerted is
[tex]P_2 = \frac{W_2}{t_2}=\frac{2332 J}{8.5 s}=274.4 W[/tex]
Into how many main groups are fish divided?
a. one
b. two
c. three
d. four
Answer:
Fish are divided into three main groups, which include Cartilaginous fish, Bony fish, and Lobe-finned fish.
Match the vocabulary terms to their definitions.
See the attached picture:
Answer:
the order of blanks from top to bottom is
6
3
2
4
5
1
Explanation:
Compare and contrast power and work.
Answer:
Comparison
Displacement and force are factors of both work and power
Work=Force× Displacement
power=(Force×Displacement)/time
Therefore power is the derivative of work with respect to time.
Contrast
Work is defined as a product of force and distance while power is the rate at which the work is done.
What type of relationship does this graph show?
a negative relationship
an inverse relationship
a non-linear relationship
a direct relationship
Negative because the graph goes down
Answer:
Negative because the graph goes down
Explanation:
What must be true about tow objects if heat is flowing between them?
Explanation:
They have different temperatures. Heat always flows from high temperature to low temperature.
Which of the following is not a simple machine?
A. A Wheel and axle
B. A lever
C. A pair of scissors
D. A screw
Answer:
C
Explanation:
A wheel and axle, a lever, and a screw are all simple machines.
A pair of scissors is not a simple machine.
Answer is C.
C. scissors are a TYPE of. it is not a simple machine
all the planets in the solar system have ____ except for mercury and venus?
Answer:
have moon except merc and Venus
The image shows positions of the earth and the moon in which region would an astronaut feel the lightest
Answer:
The moon region
Explanation:
This is because there is little to no gravity on the moon. That is where the astronaut would feel the lightest.
Answer:
The moon region should be right i got it right on the test
Explanation:
The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on the planet’s surface? Round your answer to the nearest whole number.
Answer:
Tangential speed of objects on the planet’s surface = 241 m/s
Explanation:
Speed is given by the ratio of distance traveled to the time.
Radius of mars, r = 3397 km = 3.397 x 10⁶ m
Distance traveled = 2πr = 2 x π x 3.397 x 10⁶ = 2.13 x 10⁷ m
Time taken = 24.6 hours = 24.6 x 60 x 60 = 88560 s
[tex]\texttt{Tangential speed =}\frac{2.13\times 10^7}{88560}=240.51m/s[/tex]
Tangential speed of objects on the planet’s surface = 240.51 m/s = 241 m/s
The tangential speed of objects on Mars' surface is approximately 242 m/s, calculated using the planet's circumference and rotation time.
To calculate the tangential speed of objects on Mars' surface, we first find the circumference of Mars using the formula:
Circumference=2π×radius=2π×3,397km≈21,371km.
Next, convert the time taken for one rotation from hours to seconds:
24.6hours×60minutes/hour×60seconds/minute≈88,560seconds.
Now, calculate the tangential speed using the formula:
Tangential Speed= Circumference / Time taken for one rotation
Tangential Speed≈ 21,371km / 88,560seconds ≈0.2417km/s≈241.7m/s.
Rounding to the nearest whole number, the approximate tangential speed of objects on Mars' surface is ≈242m/s.
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Directions: WRITE a summary of the Newton’s Laws of Motion reading.
Your summary must correctly use the following academic language:
-Motion.
- inertia .
-acceleration interaction.
Answer:
In Newton's 1st Law, a stationary body or that moving with a uniform motion, will only change its state if acted upon by other external forces.This restance to change in position/motion is called inertia. In his second law, when a body is acted upon by a force, the force will be equal to the product of mass and acceleration of the body.i.e. Force= m.a. In the third law, it explains that a body will exert an equal and opposite force when intracting with another body.Here, every action force experiences an equal and opposite reaction force, where the momentum of the bodies will be conserved.
1A, 3B, and 7A are examples of
__________
on the periodic table.
Answer:
1 A, 3 B, and 7 A are examples of group number on the periodic table.
Explanation:
The table that consists of elements arranged systematically on the basis of atomic numbers is called periodic table. Groups and periods are two important part of a periodic table. A periodic table contains seven horizontal rows, called as periods and 18 vertical columns, called group.
The groups name is given in the form of number and alphabets. It represents the columns present in the periodic table.
Hence, 1 A, 3 B, and 7 A are examples of group number on the periodic table.
Answer:
group number
Explanation:
Which of the following types of units is based on the metric system in the United States?
the mile
the ounce
the dollar
the pound
Answer:
The mile
Explanation:
this is calculated using the metric system in kilometers..
Final answer:
None of the listed units (the mile, the ounce, the dollar, the pound) are based on the metric system used in the United States; these are all part of the customary or English system, except for the dollar, which is a currency.
Explanation:
None of the units mentioned - the mile, the ounce, the dollar, or the pound - are based on the metric system. These are all part of the English (Imperial) system of measurement that is primarily used in the United States. The metric system units for length, mass, and volume would be the meter (m), kilogram (kg), and liter (L), respectively. Meanwhile, the mile, ounce, and pound pertain to customary units of length and mass used in the U.S. which are based on the system developed in England. In contrast, the dollar is a unit of currency and not a unit of measurement for physical quantities.
When dealing with units used in science, the metric system is generally preferred because it facilitates easier conversion and calculation due to its base 10 structure. For example, a meter is approximately 1.1 yards, a kilogram is equivalent to about 2.2 pounds, and the second is the same in both the metric and American systems. In science, SI (International System of Units) units are used, which are metric units.
What parts are found in an electric generator? Check all that apply
An electric generator primarily consists of wire loops which rotate within a magnetic field, generating an AC voltage that drives an AC current. The mechanical energy to rotate the wire loops can be derived from various sources like hydropower, fossil fuels, or wind energy. Another important component is the commutator or slip rings.
Explanation:The essential parts of an electric generator are the wire loops and a magnetic field. An external source provides mechanical energy that drives the wire loops to rotate within the magnetic field. This mechanical action generates an alternating current (AC) voltage which in turn drives an AC current through the wire loops.
The source of this mechanical energy can be various, such as falling water (used in hydroelectric power), steam produced by the burning of fossil fuels (used in coal or natural gas power plants), or the kinetic energy of the wind (used in wind turbines). Another key part of the electric generator is the commutator or slip rings, which help in transferring the produced electric current from the rotating part of the generator to the stationary part.
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How is the Sun similar to the stars that can be seen at night?
A) The Sun makes light energy.
B) The Sun takes light energy from space.
C) The Sun warms the Earth with its light.
D) The Sun reflects light from the planets.
Answer:
A
Explanation:
Answer:
A
Explanation:
cuz it is
What is magnetism ?
Hello There!
As you already know, magnetism is invisible. Magnetism comes from minerals that are found in the Earth. The earth has so many minerals so our planet is basically a giant magnet. The most common mineral that can be made into a magnet is Iron.
A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases.
Explanation:
It is given that,
A spaceship hovering over the surface of Venus drops an object from a height of 17 m, h = 17 m
Acceleration due to gravity on the surface of Venus, [tex]g'=8.87\ m/s^2[/tex]
The second equation of motion is given by :
[tex]s=ut+\dfrac{1}{2}gt^2[/tex], u = 0
[tex]s=\dfrac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\dfrac{2s}{g'}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 17}{8.87}}[/tex]
t' = 1.95 s..............(1)
Acceleration due to gravity on the surface of Earth, [tex]g=9.8\ m/s^2[/tex]
Again using second equation of motion to find the time taken on the surface of earth.
[tex]s=ut+\dfrac{1}{2}gt^2[/tex], u = 0
[tex]s=0+\dfrac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\dfrac{2\times 17}{9.8}}[/tex]
t = 1.86.................(2)
Change in time, [tex]\Delta t=t'-t=1.95-1.86=0.089\ s[/tex]
So, on the surface of earth it will taken 0.089 seconds more. Hence, this is the required solution.
Final answer:
When an object is dropped from a height on Venus, it takes longer to reach the surface compared to Earth due to the smaller acceleration due to gravity on Venus. It takes approximately 1.56 times longer for the object to reach the surface on Venus than on Earth.
Explanation:
When an object is dropped from a height on Venus, it will take longer to reach the surface compared to dropping the same object from the same height on Earth. This is because the acceleration due to gravity on Venus is smaller than on Earth. Gravity on Venus is about 0.904 times the gravity on Earth.
To calculate the time taken to reach the surface on Venus, we can use the equation:
t = sqrt((2h) / g)
Where h is the height and g is the acceleration due to gravity.
Let's assume the acceleration due to gravity on Earth is 9.8 m/s^2 and the acceleration due to gravity on Venus is 0.904 times that value. Plugging in the values, we get:
time on Venus = sqrt((2 * 17) / (0.904 * 9.8))
Simplifying the equation, we find that it takes approximately 1.56 times longer for the object to reach the surface when dropped on Venus compared to Earth.
A boy pushes a toy car with the force of 50N. The force of friction as the car moves is 5N. What is the net force on the car
Explanation:
The first Newton Law of Motion states that an object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless a force is applied to it and changes its state of rest or motion.
According to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.
So, in the case of the toy car the forces acting on it (considering there is equilibrium between the normal force and the weight of the toy) are:
F1=50 N in the direction of the movement of the car
F2=-5 N (in the opposite direction of the movement of the car, that s why it has the negative sign)
Therefore the net force F is:
F=F1+F2=50N - 5 N
F=45N
What state of matter has the most energy
Answer:
gas particles have the greatest amount of energy
Matt (m = 80 kg) and Trey (m = 90 kg) slide across an ice skating rink and collide with each other.
Before the collision, Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west.
After the collision, Matt is moving 1.5 m/s to the west.
a. What was the total momentum of the system before the collision? (1 point)
(80kg)(3m/s)+(90)(-2m/s)=60N*s
Answer:
Total momentum of the system before the collision is 60 kg-m/s.
Explanation:
Given that,
Mass of Matt, m = 80 kg
Mass of Trey, m' = 90 kg
Initial speed of the Matt before the collision, u = 3 m/s (east)
Initial speed of the Trey before the collision, u = -2 m/s (west)
After the collision, Matt is moving 1.5 m/s to the west.
We need to find the total momentum of the system before the collision. We know that the momentum is given by the product of mass and velocity. Initial momentum is given by :
[tex]p_i=mu+m'u'\\\\p_i=80\times 3+90\times (-2)\\\\p_i=60\ kg-m/s[/tex]
So, the total momentum of the system before the collision is 60 kg-m/s. Hence, this is the required solution.
PLEASE HELP APEX
in an isolated system, two cars, each with a mass of 1,100 kg, collide. car 1 is initially at rest, while car 2 was moving at 10m/s. what is the magnitude of their combined momentum after the collision?
Answer:
A
Explanation:
Momentum before = momentum after
(1,000 kg) (0 m/s) + (1,000 kg) (10 m/s) = p
10,000 kg m/s = p
Answer is A.
Answer: The answer is A.
Okey, here we need to use the conservation of momentum!
(in the text and the image the masses are different, i will use the one of the image)
the total momentum before the collision is:
P = momentum of car 1 + momentum of car 2 = 0m/s*1000 kg + 10 m/s*1000 kg.
so the initial momentum is 10000 kg*m/s.
Because the system is isolated, and we will think that there is no loss of energy because of friction or anything like that, the momentum will conservative after the collision ( in a real situation the cars will absorb some of the energy in the collision).
So using the conservation of momentum, the momentum after the collision must be the same as before, so the answer is A = 10000 kg*m/s.
The main characteristic of all vertebrates is the presence of
a. cartilage
b. a large brain
c. a backbone
d. an exoskeleton
I got it. The answer was B
Answer:
c
Explanation:
backbone is the correct answer
If a foam cube 20 cm on a side has a density of 300kg/m^3 is placed in fresh water, how much of the cube will be underwater?
Answer:
6 cm
Explanation:
The weight of the water displaced equals the weight of the cube.
mg = ρVg
m = ρV
The mass of the cube is its density times its volume, and volume of a cube is the side length cubed.
The volume of the water displaced is the area times the depth.
(300 kg/m³ * (0.20 m)³) = (1000 kg/m³) ((0.20 m)² h)
2.4 kg = 40 kg/m h
h = 0.06 m
h = 6 cm
So 6 cm of the cube will be underwater.
A train travels 53 kilometers in 2 hours, and then 54 kilometers in 4 hours. What is
its average speed?
Your Answer:
Answer
units
Average speed = (total distance) / (time to cover the distance)
total distance = (53 km + 54 km) = 107 km
time = (2 hr + 4 hr) = 6 hours
Average speed = (107 km) / (6 hrs)
Average speed = (107/6) (km/hrs)
Average speed = 17.833... km/hr
How much force was applied to an object if was moved 2 meters and the work done on the object was 8 joules?
A.) 0.25 N
B.) 4 N
C.) 6 N
D.) 16 N
Answer:
The answer is 4N or B
Explanation:
Just the equation W = F x D.
We have W = 8 J and D = 2 m using algebra ....
8J/2m = F ... F = 4.
Answer:
B 4N
Explanation:
Someone places a chocolate bar near a working radar set that is used to locate ships and airplanes. Which best describes what is likely to happen to the chocolate bar?
A.It changes color as it absorbs visible light from the radar set.
B.It softens and melts as it absorbs microwaves from the radar set.
C.It becomes radioactive after it absorbs gamma rays from the radar set.
D.It begins to fluoresce after it absorbs ultraviolet light from the radar set.
Answer:
B. it softens and melts as it absorbs microwaves from the radar set.
Explanation:
Answer:
The Answer is defiantly B
Explanation:
I just know it is
How many chlorine atoms are needed on the left in order to balance this chemical equation?
__ Ag __ Cl → __ AgCl2
Answer:
2
Explanation:
There are 2 chlorine atoms in AgCl₂. So to balance the equation, there needs to be 2 atoms on the left side as well.
Final answer:
The question likely contains a typo, as AgCl2 is not a standard chemical compound. Assuming a standard compound AgCl, the balanced equation would require two silver atoms and one chlorine molecule to produce two units of AgCl.
Explanation:
The chemical equation provided in the question seems to have a typo since AgCl2 is not a common chemical compound, as silver typically forms AgCl. Assuming the intention was to balance a reaction forming AgCl, the balanced equation would look like this:
[tex]2 Ag (s) + Cl_2 (g) - > 2 AgCl (s)[/tex]Here, you need two silver (Ag) atoms and one chlorine (Cl2) molecule to produce two units of AgCl. Each chlorine molecule provides two chlorine atoms, which combine with the two silver atoms to form two AgCl units.
If the typo is ignored and we consider AgCl2, balancing a non-standard chemical equation may not be possible since the compound is not representative of known stable silver chlorides.