A car slows down from 23 m/s to rest in a distance of 85 m. what was its acceleration, assmed constant

At the edge of the cliff, the speed of the car will have two components. The x-component, horizontal, is equal to 27 m/s while the y-component, vertical, is equal to zero. With this, the car is seemingly in free-fall.

 The equation that would allow us to answer the question above is,

    d = (V₀)t + 0.5gt²

where d is distance, V₀ is the initial velocity, g is the acceleration due to gravity and t is the time. Substituting the known values,

    73 = (0)(t) + 0.5(9.8 m/s²)(t²)

Vo  equals zero because we only consider the y-component of the vector. Solving for the value of t will give us an answer of 3.86 s.

Answer: 3.86 seconds

To calculate the time it takes for the car to hit the ground when driving horizontally off a cliff, you can use the equation of motion for vertical motion and solve for time. The equation is y = yo + vot + 1/2at^2, where yo is the initial vertical position, vo is the initial vertical velocity, a is the acceleration due to gravity, and t is the time taken. Plug in the given values and solve for t.

To calculate the time it takes for the car to hit the ground, we can use the equation of motion for vertical motion: y = yo + vot + 1/2at^2. Since the car is driving horizontally, the initial vertical velocity vo is equal to zero, and the initial vertical position yo is equal to the height of the cliff, which is 73 meters. The acceleration due to gravity a is approximately -9.8 m/s^2 (negative because it acts in the opposite direction of the car's motion). Plugging in these values, we get:

y = 73 + 0t - 1/2(9.8)t^2

We can solve this equation for t by setting y equal to zero (since the car hits the ground), and solving the resulting quadratic equation. The positive solution will give us the time it takes for the car to hit the ground.

Let me calculate that for you.

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The speed of an average oxygen molecule in a room can be estimated using the root-mean-square velocity formula, which indicates that at a room temperature of 300 K, the average speed of oxygen molecules is a few hundred meters per second.

To estimate the speed of an average oxygen molecule in the room at room temperature, we use the concept of root-mean-square (rms) velocity, which is derived from the kinetic theory of gases. At a temperature of about 300 K (room temperature), the kinetic energy of all gas molecules is the same, meaning that lighter molecules move faster than heavier ones. While the molar mass of oxygen is 32.0 g/mol, nitrogen, which composes the majority of air, has a molar mass of 28.02 g/mol. Thus, at the same temperature, oxygen molecules will move more slowly on average than nitrogen molecules.

For oxygen at 300 K, the average speed can be found using the root-mean-square velocity formula: v_rms = \sqrt{(3kT/m)}, where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of a single oxygen molecule. Since the ratio of the molar masses of oxygen and nitrogen is 16.00 to 14.01 and knowing that nitrogen molecules are lighter, they will have a higher average speed compared to oxygen molecules at the same temperature. By using the rms velocity equation, one can calculate that oxygen molecules have an average speed of a few hundred meters per second at room temperature.

final velocity = initial velocity + (acceleration x time) 
3.9 m/s = 0 m/s + (acceleration x 0.11 s) 
3.9 m/s / 0.11 s = acceleration 
30.45 m/s^2 = acceleration 

distance = (initial velocity x time) + 1/2(acceleration)(time^2) 
distance (0 m/s x 0.11 s) + 1/2(30.45 m/s^2)(0.11s ^2) 
distance = 0.18 m

Answer:

(a). The acceleration is  35.5 m/s².

(b). The distance is 0.214 m.

Explanation:

Given that,

Speed = 3.9 m/s

Time = 0.11 s

We need to calculate the acceleration

Using formula of acceleration

[tex]a = \dfrac{v_{f}-v_{i}}{t}[/tex]

Put the value into the formula

[tex]a =\dfrac{3.9-0}{0.11}[/tex]

[tex]a=35.5\ m/s^2[/tex]

We need to calculate the distance

Using equation of motion

[tex]s = ut+\dfrac{1}{2}at^2[/tex]

Put the value in the equation

[tex]s =0+\dfrac{1}{2}\times35.5\times(0.11)^2[/tex]

[tex]s=0.214\ m[/tex]

Hence, (a). The acceleration is  35.5 m/s².

(b). The distance is 0.214 m.

Only a portion of shortwave radiation from the sun reaches earth's surface mainly due to atmospheric scattering and absorption. The atmosphere's molecules, dust, and aerosols scatter radiation, while gases like oxygen and ozone absorb particularly harmful ultraviolet rays.

Only some of shortwave radiation from the sun reaches the earth's surface due to daily and seasonal variations in the sun's angle above the horizon, the distance between the sun and the earth, and the atmosphere's composition. The leading cause of this radiation loss is atmospheric scattering and absorption.

The atmosphere is made up of molecules, dust, and aerosols which scatter the incoming radiation in different directions. Some of this scattered radiation ends up traveling back out into space. Moreover, atmospheric gases such as oxygen and ozone also absorb a significant portion of shortwave radiation, particularly harmful ultraviolet (UV) rays. This combination of scattering and absorption prevents a significant amount of shortwave radiation from reaching the earth's surface.

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Atmospheric absorption and scattering cause the loss of short wave radiation from the sun, preventing some of it from reaching Earth's surface.

The leading cause of the loss of shortwave radiation from the sun reaching Earth's surface is atmospheric absorption and scattering. When sunlight passes through the Earth's atmosphere, various gases, aerosols, and clouds absorb and scatter shortwave radiation. Water vapor, carbon dioxide, ozone, and particulates absorb specific wavelengths of solar radiation. Additionally, molecules and small particles in the atmosphere scatter sunlight in different directions, leading to diffuse sky radiation.

This absorption and scattering phenomenon cause a significant portion of shortwave radiation to be dispersed or absorbed by the atmosphere before it reaches the Earth's surface. The remaining radiation, once it penetrates the atmosphere, contributes to heating the Earth's surface and drives various processes, such as weather patterns and the Earth's climate system.

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Final answer:

The volume gained by a person who gains 11.4 lbs of pure fat is approximately 5746.06 cm³, calculated by converting the weight to kilograms and using the density of body fat to find the volume.

Explanation:

To determine the volume gained by a person who gains 11.4 lbs of pure fat, we must first convert the weight gained into kilograms knowing that 1 lb = 0.453592 kg. Therefore, 11.4 lbs equals approximately 5.17145 kg.

Next, we use the fact that the density of body fat is typically around 0.9 g/cm³ (or 900 kg/m³). Thus, the volume V of the fat gained can be found using the formula for density ρ = mass (m) / volume (V), or V = m / ρ.

Substituting the values:

V = 5171.45 g / (0.9 g/cm³)

V ≈ 5746.06 cm³

Therefore, the volume increase from gaining 11.4 lbs of pure fat is approximately 5746.06 cm³.

This question involves the concept of charge.

The magnitude of the charge on the sphere is "9.728 x 10⁻⁷ C".

The magnitude of charge on the sphere can be given by the product of the number of excess electrons present on the sphere and the charge on the single electron. Mathematically,

q = ne

where,

Therefore,

q = (6.08 x 10¹²)(1.6 x 10⁻¹⁹ C)

q = 9.728 x 10⁻⁷ C

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Answer:

Erosion is the constant gnawing, erosion and degradation that occurs on the earth's surface. That is, when external geological forces, such as rivers, glaciers, flowing water, winds or waves, carry along and gnaw rock particles and move material from one location on the earth's surface to another.

The rate of erosion is influenced by climate, topography, the extent of vegetation cover and the properties of the loads. Deforestation and cultivation methods that change the soil structure, for example, make the soil harder so that it does not drain away water so quickly, can increase the erosion rate and cause major damage. It is estimated that 30-40 billion tonnes of land is eroded each year from the world's agricultural areas.

The difference in height between both players, Arabella and Boris, is given by [tex]D(t) = h_A(t) - h_B (t)[/tex]

This problem is a 1-dimensional free fall type of problem, it's one dimensional since both players only move in 1 dimension (meaning vertically), and it is a free fall problem since, when both players leave the ground, the only force which is apllied over them is the force excerted by gravity.

To solve our problem, let's suppose that both players jump from a point called the origin, meaning a point where we consider that their vertical displacement is 0 (in this case, the floor would be considered as the origin). Besides that, let's suppose that we start counting the time at the moment when Arabella makes her jump, and let's say that both players jump with velocity V. Therefor from the equations from kinematics about free falling objects we can write an expression for the height of Arabella over time as:

[tex]h_A (t) = V \cdot t - \frac{g \cdot t^2}{2}[/tex]

Which is an equation valid since the time Arabella jumps until she gets back on the ground, in math terms this would be written as that the equation is valid over the interval [tex]0\leq t\leq \frac{2 \cdot V}{g}[/tex]. At all other times the height of Arabella would be zero (since she is on the ground).

We can write the same for Boris, though his equation is shifted in time by his reaction time [tex]t_r[/tex]:

[tex]h_B (t) = V \cdot (t-t_r) - \frac{g \cdot (t-t_r)^2}{2}[/tex]

Which is valid over the interval [tex]t_r \leq t\leq t_r + \frac{2 \cdot V}{g}[/tex], and zero everywhere else (since Boris is touching the ground at all other moments). Putting all the pieces together, we can get a piecewise function that expresses the difference in height between both players:

[tex]D(t) = h_A(t) - h_B (t) = V \cdot t - \frac{g \cdot t^2}{2} [/tex] for all [tex]0 \leq t \leq t_r[/tex]

[tex]D(t) = h_A(t) - h_B (t) = V \cdot t - \frac{g \cdot t^2}{2} - (V \cdot (t-t_r) - \frac{g \cdot (t-t_r)^2}{2}) =  V \cdot t_r - g \cdot t_r \cdot t + \frac{g \cdot t_r^2}{2} [/tex] for all [tex]t_r \leq t \leq \frac{2 \cdot V}{g}[/tex]

[tex]D(t) = h_A(t) - h_B (t) = - V \cdot (t-t_r) + \frac{g \cdot (t-t_r)^2}{2} [/tex] for all [tex]\frac{2 \cdot V}{g} \leq t \leq t_r + \frac{2 \cdot V}{g}[/tex]

Here is a list of well explained free falling problems, similar to yours:

Free fall, parabolic motion, kinematics

Vertical displacement when [tex]t=t_r[/tex] is [tex]\b{\boxed{\sqrt{2gH}\left(t\right)-\dfrac{1}{2}g{t^2}}}[/tex] and vertical displacement when [tex]{t_r}<t[/tex] is [tex]\b{\fbox{\begin\{t({\sqrt{2gH}+\dfrac{g(t_r-2t)}{2})}\end{minispace}}}[/tex].

Further Explanation:

Arabella and Boris are of same height and jumps with the same initial velocity. Therefore, both can jump to height [tex]H[/tex].

The energy of both the players Arabella and Boris at ground level and height [tex]H[/tex] is constant.

Concept:

Applying conservation of energy at ground and height [tex]H[/tex]:

[tex]mgH=\dfrac{1}{2}m{v_0}^2[/tex]

Rearrange the above equation for initial velocity [tex]v_0[/tex]:

[tex]v_0=\sqrt{2gH}[/tex]

To calculate the height of both players, we can apply the equation of law of motion.

For a given initial velocity [tex]v_0[/tex], acceleration [tex]g[/tex], the height of the Arabella in time [tex]t[/tex]:

[tex]\boxed{{h_a}\left(t\right) ={h_0}+{v_0}t-\dfrac{1}{2}g{t^2}}[/tex]

The reaction time for Boris is [tex]t_r[/tex]. Therefore, to reach the height time taken by her is [tex](t-t_r)[/tex] .

For a given initial velocity [tex]v_0[/tex], acceleration [tex]g[/tex], the height of the Boris in time [tex](t-t_r)[/tex]:

[tex]\boxed{{h_b}(t)={h_0}+{v_0}(t-t_r)+\dfrac{1}{2}g(t-t_r)^2}[/tex]

It is given that Boris jumps before Arabella reaches the maximum height. Therefore, reaction time for Boris cannot be greater than total time.

Case I:

For [tex]t=t_r[/tex], we get [tex]{h_b}(t)={h_0}[/tex] .

Therefore, the vertical displacement is:

[tex]\begin{aligned}D(t)&={h_a}(t)-{h_b}(t)\\&={h_0}+{v_0}t-\dfrac{1}{2}g{t^2}-{h_0}\\&={v_o}t-\dfrac{1}{2}g{t^2}\\&=\sqrt{2gH}(t)-\dfrac{1}{2}g{t^2}\end{gathered}[/tex]

Case II:

For [tex]{t_r}<t[/tex], the vertical displacement is:

[tex]\begin{aligned}D(t)&={h_a}(t)-{h_b}(t)\\&={t_r}({\sqrt{2gH}+\dfrac{g(t_r-2t}{2})\end{aligned}[/tex]  

Thus, vertical displacement when [tex]t=t_r[/tex] is [tex]\b{\boxed{\sqrt{2gH}\left(t\right)-\dfrac{1}{2}g{t^2}}}[/tex] and vertical displacement when [tex]{t_r}<t[/tex] is [tex]\b{\fbox{\begin\{t({\sqrt{2gH}+\dfrac{g(t_r-2t)}{2})}\end{minispace}}}[/tex].

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Two, basketball, player, same, height, initial, velocity, vertical, distance, Arabella, Boris, high, above, D(t)=Ha(t) – Hb(t), function, reaction, ground, reaches and time.

We are given that: 
Speed of sound in air = 343.06 m/s and frequency f = 349.23Hz. 
Calculating for wavelength using the formula:

Wavelength λ = c / f

wavelength λ = 343.06 / 349.23 = 0.98233 m = 98.233 cm

Final answer:

To find the average velocity of any object, use the formula Vavg = (Vo + V) / 2 for constant acceleration or calculus methods for variable acceleration. Average velocity is a vector quantity that represents the total displacement per unit time and is directly proportional to displacement, highlighting its linear relationship.

Explanation:

To write an equation for average velocity that would work for finding the average velocity of any object, we need to understand that average velocity is a vector quantity defined as the total displacement divided by the total time taken for that displacement.

The formula for average velocity, Vavg, when acceleration is constant can be written as Vavg = (Vo + V) / 2, where Vo is the initial velocity and V is the final velocity. For variable acceleration, calculus is used to find the instantaneous velocity at any given point, which can be then integrated over a time interval to get the average velocity.

The relationship between displacement (x), average velocity (Vavg), and time (t) can be demonstrated by the linear equation x = xo + Vavg t, where xo represents initial position. This indicates that displacement is a linear function of average velocity.

It is A. Im taking the test right now.

Answer :(A) Velocity on the y-axis, time on the x-axis

Explanation :

It is given that, Larry and Balky started the marble at the top of the ramp and set up photogates to collect data as the marble rolled down the ramp.

Acceleration is defined as the rate of change of velocity.

Instantaneous acceleration is defined as the slope of the tangent line. It is also defined as the rate of change of velocity at a particular instant.

To find instantaneous acceleration, it should be a velocity - time graph with velocity on the y-axis and time on the x-axis.

So, the correct option is (A) "Velocity on the y-axis, time on the x-axis".

The part of the ignition system that amplifies the electric voltage is the coil as it is described to be something that is joined in a shape of a spiral or rings in a specific machine or vehicle, amplifying electricity.

He was the first to use scientific experiments to learn about atoms.

just confirming, all credits go to the other answer

Answer : Distance covered is 220 miles.

Explanation :

It is given that,

Speed of Marcus's Honda Prelude, [tex]v=55\ miles/hour[/tex]

Time duration, [tex]t=4\ hours[/tex]

We know that the speed of an object is defined as the distance travelled per unit time.

[tex]v=\dfrac{d}{t}[/tex]

or

[tex]d=v\times t[/tex]

[tex]d=55\ miles/hour\times 4\ hours[/tex]

[tex]d=220\ miles[/tex]

Hence, this is the required solution.      

A SULFATE  IS THE CORRECT ANSWER

The formula for calculating the momentum of a moving object is P = mv, where P is momentum, m is mass, and v is velocity. Momentum is a vector, having both magnitude and direction, and is measured in kg m/s. A larger or faster-moving object will have greater momentum.

The momentum of a moving object, including a car, can indeed be calculated by multiplying the mass of the object by its velocity, as encapsulated in the formula P = mv, where P represents momentum, m represents mass, and v represents velocity. Momentum is a vector quantity, meaning it has both magnitude and direction.

As such, if a car's velocity is in a negative direction (i.e., opposite to the direction of motion), its momentum will also be in a negative direction. Conversely, if the car's velocity is positive, its momentum will also be positive. The SI unit for momentum is kg m/s.

To illustrate this concept, consider a car of mass 1400 kg moving at a speed of 15 m/s. The momentum of this car would be calculated as 1400 kg * 15 m/s = 21000 kg m/s. This example demonstrates that a larger, faster-moving object will have greater momentum than a smaller, slower-moving object.

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Answer:

The guy above me is incorrect

Explanation:

Answer : Gravity

Explanation :  Matter comes together to form stars under the force of gravity. Gravity is a force that causes all object to attract each other . This force dependent on their masses and their distance.

So, we can say that scientist know the force of gravity is responsible for clumping matter together to form the first stars after the big bang.