find the length of x
which transformation of the function f(x) is the rigid motion: 2f(x)+3, f(x/2)+1, 2f(x/2), or f(x-1/2)+3
The transformation of a function may lead to the rigid motion based on what type of transformation you applied in it. Thus, option D is correct.
We need to check the transformation that is the rigid motion for the function f(x).
Now, the different transformation is given below:
2f(x)+3, f(x/2)+1, 2f(x/2), f(x-1/2)+3Let us take the transformations of the function from the top to the bottom.
(1) In the first transformation, we changed our function f(x) to 2f(x)+3.
When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.
(2) In the second transformation, we changed our function f(x) to f(x/2)+1.
When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.
(3) In the third transformation, we changed our function f(x) to 2f(x/2).
When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.
(4) In the fourth transformation, we changed our function f(x) to f(x-1/2)+3.
When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and when we use addition or subtraction towards any function then the amplitude remains constant. Hence, it is a rigid motion.
Thus, option D is correct.
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What is 160/3 in simplest form
Assessment timer and count Assessment items Factor the expression. 24−18y Enter your answers in the boxes to complete the factored expression.
What is 70% of 60 dollars
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!
-6 because you keep change and flip the equation so....
8/-3 stays the same
you change the equation from a divide to a times
and u flip the -4/9 to get 9/-4
8/-3 X 9/-4
you can then just times the top and bottom to get
72/-12= -6
z - y-1/3 if y=4 and z=3
On Venus how can you overcome extreme temperature and microgravity
Starting at sea level, a submarine descended at a constant rate to a depth of −56 mile relative to sea level in 4 minutes. What was the submarine's depth relative to sea level after the first minute? Enter your answer in the box as a fraction in simplest form.
divide total depth by time:
-56 /4 =14
so it is diving at 14 miles per minute
so after the first minute it was at -14 miles
The Factors shot 5 rolls of film with 36 exposures on each roll. It cost $14.85 to process each roll. How much did it cost for each exposure? Round to the nearest cent. Please show me how you got you answer. Your options are 14.7, 710, 0.41, 271.5, 10.97, 0.48
Answer: $ 0.41
Step-by-step explanation:
Given : The Factors shot 5 rolls of film with 36 exposures on each roll.
i.e. One roll contains 36 exposures .
It cost $14.85 to process each roll.
Then, the cost to process each exposure will be :_
[tex]\$14.85\div36=\$0.4125\\\\\approx\$0.41\ \ \ \ [\text{ Rounded to the nearest penny}][/tex]
Therefore, the cost to process each exposure= $0.41
What do you get when you cross a weeping willow with a UFO
roland sold 26 candy bars during the first week. the number of candy bars he sold during the second week was 4 less than 2 times the number of candy bars he sold during the first week. the number of candy bars he sold during the third week was 6 more than 1 1/2 times the number of candy bars he sold during the second week. what was the total number of candy bars roland sold during the three weeks?
The number of candy bars Roland sold during the three weeks will be 152.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
Roland sold 26 candy bars during the first week.
The number of treats he sold during the subsequent week was 4 under twice the quantity of pieces of candy he sold during the principal week.
Then the number of candies sold in the second week will be calculated as,
⇒ 2 x 26 - 4
⇒ 48
The number of sweet treats he sold during the third week was 6 a greater number than 1 ¹/₂ time the number of pieces of candy he sold during the subsequent week. Then the number of candies sold in third week will be given as,
⇒ 48 x (1 ¹/₂) + 6
⇒ 48 x 1.5 + 6
⇒ 72 + 6
⇒ 78
The total candies are calculated as,
⇒ 26 + 48 + 78
⇒ 152
The number of candy bars Roland sold during the three weeks will be 152.
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Find the product. 7 times 300= 7 x blank hundreds
Final answer:
The product of 7 times 300 is 2100, which can be expressed as 7 times 21 hundreds when considering that 300 equals 3 hundreds.
Explanation:
The student asked to find the product of 7 times 300, which can be represented algebraically as 7 × 300. To express this in terms of hundreds, we would have 7 × 3 hundreds, since 300 is the same as 3 hundreds. Following the multiplication of 7 and 3, we get 21 hundreds, which is equal to 2100. Therefore, the completed statement would be 7 × 300 = 7 × 21 hundreds.
This multiplication utilizes the concept where multiplying by a power of ten, like hundreds (102), is equivalent to moving the decimal point to the right in this case by two places.
at antonio's pizza, a pepperoni pizza cost $6.9. Extra roppings are avalible for $0.50 each. If Greg brought a pizza for 8.45,how many extra toppings,t,did he order?
( C = 5b+200 ) this equation is used to find C, the total cost for painting a quantity of books (b) . What equation is equivanlent when solved for B in terms of C
To solve the equation C = 5b + 200 for b in terms of C, subtract 200 from both sides of the equation and then divide both sides by 5.
Explanation:To solve the equation C = 5b + 200 for b in terms of C, we need to isolate the variable b. First, subtract 200 from both sides of the equation:
C - 200 = 5b
Next, divide both sides of the equation by 5:
b = (C - 200)/5
So, the equivalent equation when solved for b in terms of C is b = (C - 200)/5.
Marlon used 3 kilograms of almonds to make 9 batches of snack mix. How many kilograms of almonds, on average, were in each batch
Help,Cause homework is hard :/
Which of the following modifications to the list of assets and liabilities below would result in an increase in net worth?
Cash of $300.
Car valued at $28,000.
Car loan of $22,000.
Motorcycle valued at $6,000.
Savings of $2,000.
Credit card balances of $4,000.
Student loan of $10,000.
a.
putting $100 in savings
b.
paying $100 on credit cards
c.
getting paid $100
d.
all of the above
The modifications made to the list of assets and liabilities that would result in an increase in net worth is Option D. Net worth is defined as the value of all the non-financial and financial assets owned by an individual or an institution.
All of the above (Putting $100 in savings, Paying $100 on credit cards and Getting paid $100)
Its the letter D ik because i just do aha
Adam says that the number 4 has four factors. Explain why this statement is incorrect.
Answer:
Sample response: The number 4 only has three factors: 1, 2, and 4. Adam probably counted the factor 2 twice.
Step-by-step explanation:
Will is w years old.
Ben is e years older.
Jan is twice as old as Ben.
Write an expression, in terms of w, for Jan’s age.
When h has the value of 4 calculate 5h-3
The length of a rectangle is 3 meters less than twice its width.
a. Write an equation to find the length of the rectangle.
What is the product in lowest terms?
5/6 x -8/15 ( / means fractions)
1.-8/9
2.-4/9
3. -1/3
4. -1/7
Do not answer if aren’t sure.
1.What is the elapsed time between 11:50 a.m. and 4:05 p.m.?
a.4 hours and 45 minutes
b.15 hours and 15 minutes
c.5 hours and 15 minutes
d.4 hours and 15 minutes
2.Which pair of times has the longest elapsed time between the two times?
a.1:05 to 6:10
b.10:15 a.m. to 3:25 p.m.
c.2:45 to 7:45
d.9:10 p.m. to 1:55 a.m.
3.If it is 12:50, what will the time be 5 hours and 20 minutes later?
a.5:30
b.5:50
c.6:10
d.6:50
4.What would the temperature be on an autumn day?
a.50°F
b.32°C
c.100°F
d.0°C
5.Convert 122°C to Fahrenheit.
a.139.6°F
b.251.6°F
c.212°F
d.218.4°F
6.Convert 124°F to Celsius.
a.50.6°C
b.85.8°F
c.98.6°C
d.165.6°C
7.What temperature is shown on the thermometer?
200°F
90°F
180°F
80°C
8.mark all that apply Which temperatures are below 108°C?
a.230°F
b.212°F
c.225°F
d.228°F
A line with a slope of 1/2 passes through the point 2,-1 what is the equation of this line
The equation of the line is [tex]\( y = \frac{1}{2}x - 2 \)[/tex].
To find the equation of a line with a given slope passing through a specific point, you can use the point-slope form of a linear equation: [tex]\( y - y_1 = m(x - x_1) \)[/tex], where ( m ) is the slope and [tex]\( (x_1, y_1) \)[/tex] is the given point.
Given that the slope [tex]\( m = \frac{1}{2} \)[/tex] and the point ( (2, -1) ), we substitute these values into the point-slope form:
[tex]\( y - (-1) = \frac{1}{2}(x - 2) \)[/tex]
This simplifies to:
[tex]\( y + 1 = \frac{1}{2}(x - 2) \)[/tex]
To remove the fraction, distribute [tex]\( \frac{1}{2} \)[/tex]:
[tex]\( y + 1 = \frac{1}{2}x - 1 \)[/tex]
Now, isolate ( y ) by subtracting 1 from both sides:
[tex]\( y = \frac{1}{2}x - 1 - 1 \)[/tex]
[tex]\( y = \frac{1}{2}x - 2 \)[/tex]
So, the equation of the line is [tex]\( y = \frac{1}{2}x - 2 \)[/tex].
Please help me with question, worth 15 points
. If the interest rate on a savings account is 0.018%, approximately how much money do you need to keep in this account for 1 year to earn enough interest to cover a single $9.99 Below-Minimum-Balance Fee?
What did Ranofer notice about the old mans hands ?
The hot summer fair is coming to town! Admission to the fair costs 12.99 and each ride costs 1.75. You have 35 to spend at the fair including admission.
The correct answer is:
12 rides
Explanation:
You have $35 to spend. Taking away the admission price, $12.99, we have
35-12.99 = $22.01 left.
Each ride costs $1.75. This means you can ride
22.01/1.75 = 12.577 or 12 rides. (This does not round up, as you would not have enough money to ride 13 rides.)
A photographer uses a light meter to measure the intensity of light from a flash bulb. The intensity for the flash bulb,I, in lux, is a function of the distance from the light, d, in meters, and can be represented by I(d)=10/d^2, d>0 determine the approximate instantaneos rate of change in the intensity of light at exactly 3m from flash bulb. determine the approximate instantaneos rate of change in the intensity of light at exactly 3m from flash bulb.
The approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is -20/27 lux per meter.
Explanation:The photographer uses a light meter to measure the intensity of light from a flash bulb. The intensity of the flash bulb, I, in lux, can be represented by the function I(d) = 10/d^2, where d is the distance from the light in meters.
To determine the approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb, we need to find the derivative of the intensity function with respect to d. Taking the derivative, we get dI/dd = -20/d^3.
Substituting d = 3 into the derivative, we get dI/dd = -20/3^3 = -20/27.
Therefore, the approximate instantaneous rate of change in the intensity of light is -20/27 lux per meter at exactly 3m from the flash bulb.
The approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is approximately -0.741 lux/m.
Explanation:To determine the instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb, we need to find the derivative of the intensity function with respect to distance.
The intensity function is given as I(d) = 10/d^2, where d is the distance from the light in meters. To find the derivative, we can use the power rule for differentiation.
Taking the derivative of the intensity function gives us: dI/d(d) = -20/d^3.
At exactly 3 meters, the instantaneous rate of change in the intensity of light can be calculated by substituting d=3 into the derivative equation: dI/d(d) = -20/3^3 = -20/27. Therefore, the approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is approximately -0.741 lux/m.