Answer:
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Explanation:
Because the heat of the plate will be releases warming up the air making it move faster
Atoms can be seen with the naked eye.
Atoms do not have mass.
Atoms make up every substance around you.
Answer:
Atoms make up every substance around you. True
Explanation:
Atoms can be seen with the naked eye. False because atoms are very very very smallllll....
Atoms do not have mass. False, atoms do have mass although it is very smallllllllll as welll
Atoms make up every substance around you. True, similar to how cells make up different things like tissues, and tissues make organs and so on, atoms make up everything around us.
175 mal of Cl2 gas is held in a flexible vessel at STP. If the vessel is transported to the bottom of the impact basin Hellas planitia on the surface of Mars where is 1.16 kPa and the temperature is -5.0ºC. What is the new volume of Cl2 gas in liters
Answer: it’s 15.0 L
Explanation: Trust me
Match the following: Molecule Test 9. Carbohydrates A. Biuret test 10. Starch and glycogen B. Paper test 11. Lipids C. I2KI test 12. Proteins D. Benedict test 13. Nucleic acids E. None of the above
Answer:
Carbohydrates------Benedict test
Starch and glycogen --------I2KI test
Proteins--------Biuret test
Lipids-------Paper test
Nucleic acids------None of the above
Explanation:
Benedict's Test is can be used to detect simple carbohydrates. The Benedict's test can detect reducing sugars (monosaccharide's and some disaccharides), having free ketone or aldehyde functional groups.
The Biuret Test shows the presence of peptide bonds, which are the basis for proteins. These bonds makes the blue Biuret reagent turn purple. The rest is carried out by adding an equal amount of NaOH to a solution of the food, mix carefully and add a few drops of 1% CuSO4, without shaking the mixture.
Lipids form a translucent stain on paper while starch/glycogen turns I2/KI solution blue-black
Practice the Skill 21.15b When the following ketone is treated with aqueous sodium hydroxide, the aldol product is obtained in poor yields. In these cases, special distillation techniques are used to increase the yield of aldol product. Predict the aldol addition product that is obtained, and propose a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.
Answer:
Check the explanation
Explanation:
Kindly check the attached image below for the step by step explanation to the question above.
We start in situation A with 1 mole of an ideal gas in the right bulb with the valve closed. The gas has a pressure, volume, and temperature we symbolize by pA, VA, TA. Then the gas spreads out to occupy both sides. Once it has settled down we have situation B with parameters pB, VB, TB. Since there is nothing opposing the motion of the gas into the larger volume, this is called a free expansion. How does the volume and temperature compare in systems A and B. Place the appropriate coefficient in the blank
Answer:
Free expansion is also known as the joule expansion, this happens when a gas does not have an expansion limit and its volume increases until it is allowed.
That is why as the initial volume passes at the end the pressure decreases since the molecules are more distant from each other without a barrier that stops or compresses them.
It is an irreversible process and the equation would be:
Initial pressure X Initial volume = Final pressure X Final volume
Explanation:
Where P is the pressure, V is the volume, and i and f refers to the initial and final states. Since the gas expands, Vf> Vi, which implies that the pressure drops (Pf <Pi).
A 175 ml sample of neon had its pressure changed from 75 kPa to 150 kPa. What is its new volume?
Answer:
The new volume is 87.5 ml.
Explanation:
We have,
Volume of sample of neon is 175 ml
The pressure changed from 75 kPa to 150 kPa.
We need to find new volume.
It is based on the concept of Boyle's law. Let V₂ is new volume. So,
[tex]P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{175\times 75}{150}\\\\V_2=87.5\ ml[/tex]
So, new volume is 87.5 ml.
Using Boyle's Law, the new volume of the neon gas when the pressure is changed from 75 kPa to 150 kPa is calculated to be 87.5 mL.
To find the new volume of a gas when its pressure is changed, we use Boyle's Law.
Boyle's Law states that the pressure and volume of a gas are inversely proportional when temperature and the number of gas molecules remain constant.
The formula is expressed as:
P₁V₁ = P₂V₂
In this problem:
Initial Pressure, P₁ = 75 kPaInitial Volume, V₁ = 175 mLFinal Pressure, P₂ = 150 kPaWe need to find the final volume, V₂. Rearranging Boyle's Law, we get:
V₂ = (P₁V₁) / P₂
Plugging in the values:
V₂ = (75 kPa * 175 mL) / 150 kPa
V₂ = 13125 mL / 150 kPa
V₂ = 87.5 mL
Therefore, the new volume of the neon gas sample is 87.5 mL.
Draw the major product expected when 1,3-butadiene is treated with one equivalent of HBr at 40ºC and show the mechanism of its formation. For the mechanism, include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly. Do not use abbreviations such as Me or Ph.A) Draw step 1 of the mechanism.
Answer:
The major product and the mechanism is shown below.
Explanation:
In the reaction of 1,3-butadiene, with one equivalent of HBr, the addition product 1,2 is generated primarily at 40 ° C. When 1,3-butadiene reacts with HBr, a mixture of two products is obtained. One of them, 3-bromo-1-butene, is formed by the addition of HBr to one of the double bonds of the classic structure of this compound.
In contrast, the second and major product, 1-bromo-2-butene, does not have any of the terminal double bonds but contains a double bond between the C2-C3 carbons.
The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. Deuterium, D, is an isotope of hydrogen. 2 HD(g) ⇌ H2(g) + D2(g) Kc = 0.28 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) Kc = ? The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. Deuterium, D, is an isotope of hydrogen. 2 HD(g) ⇌ H2(g) + D2(g) Kc = 0.28 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) Kc = ? 581 0.73 1.3 0.0017 2.06
Answer:
Answer choice 'D' => Kc(2) = 581
Explanation:
2HD ⇄ H₂ + D₂ => Kc(1) = [H₂][D₂]/[HD]² => 0.28
5H₂ + 5D₂ ⇄ 10HD => Kc(2) = [HD]¹⁰/[H₂]⁵[D₂]⁵ = 1/(Kc(1))⁵ = 1/(0.28)⁵ = 581
For these type problems, one should 1st write the empirical Kc expression for each equation given. Then compare the expressions and ask 'how can the 1st Kc expression be changed into the 2nd Kc expression?' Apply and substitute given Kc(1) into the Kc(2) expression and solve for numerical results.
The equilibrium constant for the second reaction 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) is 0.0017 when the equilibrium constant for the first reaction 2 HD(g) ⇌ H2(g) + D2(g) is 0.28. This is calculated by taking the first reaction's Kc and raising it to the power of 5.
Explanation:The chemical reaction you have given is a perfect example of equilibrium in chemistry. In the first reaction, 2 HD(g) ⇌ H2(g) + D2(g), the equilibrium constant Kc is already given as 0.28. If we look at the second reaction, 5 H2(g) + 5 D2(g) ⇌ 10 HD(g), we can see that it's technically the first reaction multiplied by 5. Therefore, to find Kc for the second reaction, we simply raise the Kc of the first reaction to the power of 5. So, Kc for the second reaction would be (0.28)^5 = 0.0017.
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how many liters of bromine are needed to produce 12 moles of Aluminum bromide? The density of bromine is 3.1 m/gl
Answer:
0.94 L
Explanation:
Step 1: Write the balanced reaction
2 Al + 3 Br₂ = 2 AlBr₃
Step 2: Calculate the moles of Br₂ required to produce 12 moles of AlBr₃
The molar ratio of Br₂ to AlBr₃ is 3:2. Then,
[tex]12molAlBr_3 \times \frac{3molBr_2}{2molAlBr_3} =18molBr_2[/tex]
Step 3: Calculate the mass of bromine corresponding to 18 moles
The molar mass of bromine is 159.81 g/mol. Then,
[tex]18mol \times \frac{159.81g}{mol} =2.9 \times 10^{3} g[/tex]
Step 4: Calculate the volume of bromine corresponding to 2.9 × 10³ g
The density of bromine is 3.1 g/mL. The volume of bromine is:
[tex]2.9 \times 10^{3} g \times \frac{1mL}{3.1g} \times \frac{1L}{1000mL} = 0.94 L[/tex]
Which option is true about the effect of polarity on solubility?
Select all that apply.
1-Polar solutes dissolve better in oil than water.
2-Polar solutes have the greatest solubility in nonpolar solvents.
3-Polar solutes dissolve better in water than in oil.
4-Polar solutes have the greatest solkbility in polar solvents.
Explanation:
It is known that like dissolves like. Therefore, polar solutes are soluble in polar solvents.
For example, salt is a polar compound and water is a polar solvent. Therefore, salt will dissolve in water.
On the other hand, oil is an inorganic solvent and hence, it is unable to dissolve any polar solute.
Therefore, we can conclude that following is true about the effect of polarity on solubility.
Polar solutes dissolve better in water than in oil.Polar solutes have the greatest solubility in polar solvents.Hope this helps!
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When an unsymmetrical alkene such as propene is treated with N-bromosuc- cinimide in aqueous dimethyl sulfoxide, the major product has the bromine atom bonded to the less highly substituted carbon atom. Is this Markovnikov or non-Markovnikov orientation? Explain.
Answer:
Explanation:
kindly check the file below to show the explanation . Thanks
Carbon 14 (14C) dating assumes that the carbon dioxide on Earth today has the same radioactive content as it did centuries ago. If this is true, the amount of 14C absorbed by a tree that grew several centuries ago should be the same as the amount of 14C absorbed by a tree growing today. A piece of ancient charcoal contains only 19% as much radioactive carbon as a piece of modern charcoal. How long ago was the tree burned to make the ancient charcoal given that the half-life of 14C is 5700 years?
Answer:
23388 years
Explanation:
Now we have to use the formula;
0.693/t1/2 = 2.303/t log No/N
Where
t1/2 = half life of the C-14 = 5700
t= age of the sample
No= radioactive material in a modern sample = No
N= radioactive material in a sample being studied. = 0.81No( since the amount N= No-0.19No)
Hence;
0.693/5700 = 2.303/t log No/0.81No
0.693/5700 = 2.303/t log 1/0.81
0.693/5700 = 2.303/t × 1.235
0.693/5700= 2.844/t
1.216×10^-4= 2.844/t
t= 2.844/1.216×10^-4
t= 23388 years
The pH of a solution is 6.5.
What is the pOH?
Answer:
7.5
Explanation:
pH + pOH = 14
pOH = 14 - 6.5
pOH = 7.5
The pOH of a solution, given a pH of 6.5 at temperature 25°C, is 7.5. This is calculated by subtracting the pH from 14.
Explanation:The pH and pOH of a solution are related by the equation pH + pOH = 14 at 25°C. Given that the pH of the solution is 6.5, to find the pOH you simply subtract the pH from 14. So, pOH = 14 - pH. In this case, pOH = 14 - 6.5 = 7.5. Therefore, the pOH of a solution with a pH of 6.5 is 7.5.
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Silicones can be oils or rubber-like materials depending on ________. Select one: A. the silicon-to-oxygen ratio B. the length of the chain and degree of cross-linking C. the percentage of carbon in the chain D. the oxidation state of silicon in the chain E. the percentage of sulfur in the chain
Answer: B-- the length of the chain and degree of cross-linking.
Explanation: Silicones can be oils or rubber-like materials depending on ___the length of the chain and degree of cross-linking.____
Silicone rubber is an elastomer which is composed of silicone containing silicon together with carbon, hydrogen, and oxygen. silicone rubber can be found in a wide variety of products because of its ability to withstand very high temperatures and pressures. eg cooking and food storage products; clothing apparels , automotive devices etc while
Silicone oil is a linear chain siloxane repeating units Si--0 with radical side group as such as methyl, phenyl etc bonded to it. They are oils because of they are viscose and have ability to repel. Silicone oils are mostly employed in medicine for surgical tools.
When you hear the word solution, you tend to think of a liquid. However, a solution can be a homogeneous mixture of any phase. These two questions are about a solid solution that has properties of a metal. When some atoms of the solvent are replaced by solute atoms of a similar size, the solution is called a heterogeneous alloy. an intermetallic compound. a substitutional alloy. an interstitial alloy.
Both questions are answered below:
Substitutional alloysInterstitial alloysExplanation:
Some atoms of the solvent can be replaced by atoms of relatively similar sizes, allowing for atom exchange or substitution, Whenever these atoms can be substituted within the matrix, it forms a substitutional alloy. Examples include bronze and brass.
Alternatively, some atoms are much smaller in size and cannot successfully be exchanged for the other. Instead, they get trapped within the matrix. these are called interstitial alloys, e.g steel.
Which occurs in the half-reaction Na(s) → Na+ + e−? *
A. Na(s) is reduced
B. Na(s) is oxidized
C. Na(s) gains electrons
D. Na+ is oxidized
Considering the definition of oxidation and reduction, Na(s) is oxidized.
OxidationOxidation is a reaction where an atom, ion or molecule loses electrons, increasing the oxidation state.
In other words, oxidation is the loss of electrons by a molecule, atom, or ion. An element is oxidized when it loses electrons in a reaction; increasing in the oxidation state of the atom. The higher the oxidation state of an atom, the greater the degree of oxidation.
ReductionThe reduction corresponds to the gain of electrons of an atom, ion or molecule, lowering the oxidation state.
In other words, an element is reduced when it gains electrons in a reaction, lowering its oxidation state. The lower the oxidation state of an atom, the greater the degree of reduction.
This caseYou know the half-reaction Na(s) → Na⁺ + e⁻
In this case, oxidation reaction takes place in which the oxidation of sodium changes from 0 to 1+, and the sodium loses 1 electron.
In summary, Na(s) is oxidized.
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Final answer:
Sodium (Na) is oxidized, which means it loses an electron in the half-reaction Na(s) → Na^+ + e−. This is indicative of an oxidation process at the anode.
Explanation:
In the half-reaction Na(s) → Na^+ + e−, sodium metal (Na) is losing an electron to form sodium ions (Na^+). This process is known as oxidation, which is the loss of electrons. Therefore, the correct answer to the given question is B. Na(s) is oxidized.
Oxidation occurs at the anode during a redox reaction. Comparatively, reduction, which is the gain of electrons, takes place at the cathode as in the half-reaction Y^+ (aq) + e → Y(s). The sodium atoms at the anode of an electrochemical cell would give up their electrons to become Na^+ ions, which is the process described by the given half-reaction.
Lactic acid C3H6O3 is found in sour milk where it is produced by the action of lactobacilli in lactose or the sugar in milk. The pH of a 0.045 M solution of lactic acid was determined using a pH probe and found to be 2.63. a. Calculate the equilibrium constant for this acid. b. Had you not been given the pH of the acid and you had to measure it yourself, how would the method in part 2 be applied to the determination of Ka? Would you expect an improvement in the accuracy of your result with the application of the method of this experiment? Explain why or why not.
Answer:
see explanation below
Explanation:
In this case, we need to write the overall reaction:
HC₃H₅O₃ + H₂O <-------> C₃H₅O₃⁻ + H₃O⁺
The lactic acid is a weak acid, so, when it dissociates in it's ions, part of the acid is dissociated. This depends of it's Ka to know which quantity was dissociated.
To calculate Ka, let's write an ICE chart first:
HC₃H₅O₃ + H₂O <-------> C₃H₅O₃⁻ + H₃O⁺ Ka = ?
i) 0.045 0 0
c) -y +y +y
e) 0.045 - y y y
Writting the Ka expression we have:
Ka = [C₃H₅O₃⁻] [H₃O⁺] / [HC₃H₅O₃]
Now, to calculate Ka we need the values of [C₃H₅O₃⁻] and [H₃O⁺] in equilibrium. Fortunately, we have the value of the pH, which is 2.63 and with this we can get the value of [H₃O⁺] and then, the value of y. With that value, we replace it in the Ka expression to calculate Ka:
[H₃O⁺] = 10^(-pH)
[H₃O⁺] = 10^(-2.63)
[H₃O⁺] = [C₃H₅O₃⁻] = x = 2.34x10⁻³ M
Now, let's replace this value in the Ka expression:
Ka = (2.34x10⁻³)² / (0.045 - 2.34x10⁻³)
Ka = 1.28x10⁻⁴
b) Now, let's calculate the pH with the obtained value of Ka. We will use the same expression of Ka so:
1.28x10⁻⁴ = y² / (0.045-y)
1.28x10⁻⁴ (0.045 - y) = y²
5.76x10⁻⁶ - 1.28*10⁻⁴y = y²
y² + 1.28x10⁻⁴y - 5.76x10⁻⁶ = 0
From here, we'll use the quadratic equation general formula, for solving y:
y = -1.28x10⁻⁴ ±√(1.28x10⁻⁴)² + 4 * 1 * 5.76x10⁻⁶ / 2
y = -1.28x10⁻⁴ ±√2.31x10⁻⁵ / 2
y = -1.28x10⁻⁴ ± 4.8x10⁻³ / 2
y₁ = 2.34x10⁻³ M
y₂ = -2.464x10⁻³ M
Now, as y₁ is positive this is the value that we will take.
This value would be the [H₃O⁺] in equilibrium.
The value of pH would be:
pH = -log[H₃O⁺]
pH = -log(2.34x10⁻³)
pH = 2.631
According to this value of pH we can actually expect an inprovement in the accuracy, basically because we obtain a value with more significant figures, and this are relationed with accuracy.
which reaction can be used to make 2,3 dichloropentane?
A) esterification
B) substitution
C) addition
D) etherification
Answer:
B) substitution
Explanation:
2,3 dichloropentane is a hydrocarbon that contains two chlorine atoms in its chain. It has a chemical formula: [tex]C_{5} H_{10} Cl_{2}[/tex]. In the compound, two hydrogen atoms has been substituted by two chlorine atoms.
A substitution reaction is a process by which an atom of a compound is being replaced by another atom to form a new compound due to a chemical reaction. This is one of the general properties of alkanes.
Why water pollution is a global problem
Answer:
Pollutants are typically the cause of major water quality degradation around the world. Globally, the most prevalent water quality problem is eutrophication, a result of high-nutrient loads (mainly phosphorus and nitrogen), which substantially impairs beneficial uses of water.
Explanation:
Answer:
Water pollution is caused by industrial waste, temperature rising, deforestation and many other factors. All these facts are affecting water and they happen all over the world in many large bodies of water. Thus, it is a global issue,
Explanation:
I explained it in the answer loll.
Which 0.10 M solutions will have the greatest electrical conductivity?
Complete Question: Which solution will have the greatest electrical conductivity?
A. 0.50MHCl
B. 0.10MRbOH
C. 0.50MK3PO4
D. 2.0MC6H12O6
Answer:
Option C =>0.50M K3PO4.
Explanation:
Electrical conductivity has do do with the mobility of electrons or ion, that is to say for electrical conductivity to occur there should be the movement of ions or electrons.
So, let us take option (A) and option (B) first, that is 0.50MHCl and 0.10MRbOH respectively. Both HCl and RbOH are good conductors of electricity that is to say they are both strong electrolytes. But, between the two, (that is HCl and RbOH) HCl will be better conductor of electricity that RbOH.
Option (D) is incorrect totally, and option (C) 0.50M K3PO4 is a strong electrolytes too and it will be will be the CORRECT ANSWER in this question because it gives 4 ions( K3PO4 <======> 3K^+ + PO4^-3) unlike HCl that only gives 2 ions(that is HCl <=====> H^+ + Cl^-).
Option C. 0.50M K₃PO₄.
Let's understand the concept behind electrical conductivity:
Electrical conductivity tells us how well a material will allow electricity to travel through it. It is proportional to the product of mobility and carrier concentration.
Let's look at options one by one:
In option (A) and (B) it is given 0.50M HCl and 0.10M RbOH respectively. Both HCl and RbOH are good conductors of electricity thus they both are strong electrolytes. Out of these two HCl is more stronger electrolyte than RbOH. Option (D) 2.0M C₆H₁₂O₆ -the molecule of glucose is considered as a non-electrolyte, because of its inability to dissociate into ions. Option (C) 0.50M K₃PO₄ is a strong electrolyte than HCl since K₃PO₄ is an ionic compound so it dissociates completely in water to form potassium ion and phosphate ion.K₃PO₄ can dissociate into ions which can be represented as:K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq)
So out the following options K₃PO₄ will have the greatest electrical conductivity since it is the strongest electrolyte out of the given options.
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A concentration cell is constructed with copper electrodes and Cu2+ in each compartment. In one compartment, the [Cu2+] = 1.0 × 10–3 M and in the other compartment, the [Cu2+] = 2.0 M. Calculate the potential for this cell at 25°C. The standard reduction potential for Cu2+ is +0.34 V.
a. 0.78 V
b. –0.098 V
c. –0.44 V
d. 0.44 V
e. 0.098 V
The potential of this concentration cell can be calculated using the Nernst Equation, which provides an approximation of about 0.098 V for the potential of the cell. This corresponds to choice (e).
Explanation:The potential for this concentration cell can be calculated using the Nernst equation, which incorporates the standard reduction potential and the concentrations of the reaction species in its equilibrium state. The Nernst Equation can be written as:
E = E0 - (0.05916/n) * logQ
Where E is the cell potential, E0 is the standard cell potential (+0.34 V for Cu2+/Cu), n is the number of moles of electrons exchanged in the reaction (which is 2 for this reaction), and Q is the reaction quotient, which is the ratio of concentration of products to reactants.
Since this cell involves Cu2+ being reduced to Cu, the concentration in the cell where [Cu2+]=2.0M would be considered the product, and the one where [Cu2+]=1.0×10–3M would be considered the reactant. Therefore, Q=[product]/[reactant]=2.0/ (1.0×10–3) = 2000.
Plugging these values into the Nernst Equation, we get:
E = 0.34V - (0.05916/2) * log2000
After calculation, gives us an E value of approximately V, which correlates to option (e).
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A trisubstituted cyclohexane compound is given below in its chair conformation. Draw the corresponding planar (overhead) representation, using wedge-and-dash bonds to indicate the substituent positions. To be graded properly, include the hydrogen atoms on the halogen-bearing carbon atoms. Be sure that both wedge/dash bonds are drawn on the outside of the ring, or else the stereochemistry may be interpreted as square planar. (See Hint.)
Answer:
See explaination
Explanation:
Chiral carbons are carbons that have four different groups, so C atoms 1, 4, and 5 are chiral carbons and thus H atoms are shown for those atoms.
21. A good transition state analog
A) binds covalently to the enzyme
B) binds to the enzyme more tightly than the substrate,
C) binds very weakly to the enzyme
D) is toonstable to solate
E) must be almost identical to the substrate
Answer:
hhgjghjfgjfghj
Explanation:
Which of the following statements is true?
All of the sun's radiation is reflected back into space by the Earth's atmosphere.
Air is a good insulator because the molecules in gas are very far apart.
Work can only be done by potential energy.
Total mechanical energy is calculated by subtracting kinetic energy from potential energy.
Answer:
Air is a good insulator because the molecules are far apart. This reduces mobility of air molecules hence conduction is difficult.
Explanation:
For other statements :
All the suns radiations are not reflected back to space because the ozone layer of the earth's atmosphere which regulates the intensity of radiations from the sun, it is transparent and porous hence heat and light rays from sun enter earth.Work is only done by potential energy when the body is under free fall and experiencing gravitational force, but for a body moving without influence of gravity, work is done by the force applied and the distance moved by the body. This force is called a conservative force.Total mechanical energy is given by= Kinetic energy + Potential energy
Answer:
Air is a good insulator because the molecules are far apart. This reduces mobility of air molecules hence conduction is difficult.
Explanation:
:p
Which activity is a way the circulatory system works with another body system
to maintain homeostasis?
A. breaking down food into nutrients
B. transporting hormones through the body
C. depositing fat on the inside walls of arteries
Answer:
A. breaking down food into nutrients
Explanation:
Homeostasis is the ability of the human body to regulate itself or achieve internal stability. If a body's conditions can not be regulated, it may result to the break down of its immune system leading to infections, diseases or disorder.
To maintain homeostasis, the circulatory system transports oxygen-rich blood to other parts of the body. So that the immediate condition can be regulated. It works with the respiratory system, delivering nutrients to other parts of the body. It also remove wastes from our body.
gfvygikbgkuuk uygglyh
A slice of Swiss cheese contains 48 mg of sodium
What is this mass in grams
What is this mass in ounces? (16 oz = 453.6 g)
What is this mass in pounds? (1 lb = 453.6 g)
Answer: grams=0.048g, ounces=0.0017oz, 0.00011lb
Explanation:
Stoichiometry
48 mg x 1 g
÷ 1000 mg = 0.048 g
48 mg x 1 g x 16 oz
÷ 1000 mg ÷ 453.6 g = 0.0017 oz
48 mg x 1 g x 1 lb
÷ 1000 mg ÷ 453.6 g = 0.00011 lb
A slice of Swiss cheese contains 48 mg of sodium mass in grams is 0.048 grams and mass in ounces of 0.0016 and mass in pounds of 0.0001.
What is sodium in swiss cheese?Swiss cheese is a type of cheese used on different types of food items like pizza and pasta it is a semi-solid type at room temperature and gets melted on heat and some amount of sodium is added as a preservative.
The 48 mg of sodium is converted to grams,
gram = 48mg / 1000 = 0.048
The 48 mg of sodium is converted to 16 oz = 453.6 g
ounces = 0.048 × 16/ 453.6 = 0.0016 ounces
The 48 mg of sodium is converted to1 lb = 453.6 g
pounds = 0.048 × 1/ 453.6 = 0.0001 pounds
Therefore, 0.048 grams and mass in ounces of 0.0016 and mass in pounds of 0.0001 if a slice of Swiss cheese contains 48 mg of sodium.
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A gas has a density of 2.22 g/L at 1.04 atm and a molar mass of 51.7 g/mol.
What is the temperature of the gas in Kelvin?
.
Answer:
295.4K
Explanation:
Step 1:
Obtaining an expression which relates density, pressure and temperature together.
This is can done by using the ideal gas equation as shown below:
PV = nRT........... (1)
Recall:
Number of mole (n) = mass (m) /Molar Mass (M) i.e
n = m/M
Substituting the m/M for n in equation 1 above
PV = nRT
PV = mRT/M
Divide both side by P
V = mRT/MP
Divide both side by m
V/m = RT/MP
Invert the above equation
m/V = MP/RT.....(2)
Density (D) = mass (m) /volume (V)
D = m/V
Replacing m/V with D in equation 2.
m/V = MP/RT
D = MP/RT
Step 2:
Data obtained from the question. This includes the following:
Density (D) = 2.22 g/L
Pressure (P) = 1.04 atm
Molar Mass of (M) = 51.7 g/mol.
Temperature (T) =.?
Gas constant (R) = 0.082atm.L/Kmol
Step 3:
Determination of the temperature.
D = MP/RT
2.22 = 51.7 x 1.04 / 0.082 x T
Cross multiply to express in linear form
2.22 x 0.082 x T = 51.7 x 1.04
Divide both side by 2.22 x 0.082
T = (51.7 x 1.04) /(2.22 x 0.082)
T = 295.4K
Therefore, the temperature of the gas is 295.4K
Use the pump to add 250 molecules of the heavy species gas. How does the temperature change?
Type the correct answer in each box. Use numerals instead of words.
When you begin to add the molecules, the temperature inside the container is K. After all 250 molecules have been added, the temperature inside the container is K.
Answer:
When you begin to add the molecules, the temperature inside the container is 300 K. After all 250 molecules have been added, the temperature inside the container is 300 K.
A quantity of 25.0 mL of a solution containing both Fe2+ and Fe3+ ions is titrated with 23.0 mL of 0.0200 M KMnO4 (in dilute sulfuric acid). As a result, all of the Fe2+ ions are oxidized to Fe3+ ions. Next, the solution is treated with Zn metal to convert all of the Fe3+ ions to Fe2+ ions. Finally, the solution containing only the Fe2+ ions requires 40.0 mL of the same KMnO4 solution for oxidation to Fe3+. Calculate the molar concentrations of Fe2+ and Fe3+in the original solution. The net ionic equation is Mno4- +5Fe2+ + 8H+ >>>> Mn2+ + 5Fe3+ +4H2o
The molar concentrations of Fe2+ and Fe3+ in the original solution are 18.4 mM.
Explanation:To calculate the molar concentrations of Fe2+ and Fe3+ in the original solution, we can use stoichiometry based on the net ionic equation provided:
MnO4- + 5Fe2+ + 8H+ -> Mn2+ + 5Fe3+ + 4H2O
From the equation, we can see that one mole of MnO4- reacts with 5 moles of Fe2+. In the first titration, 23.0 mL of 0.0200 M KMnO4 solution is required to react with all of the Fe2+ ions, which means there is a total of 23.0 mL x 0.0200 M = 0.460 mmol of Fe2+ in the original solution.
In the second titration, 40.0 mL of the same KMnO4 solution is required to react with all of the Fe2+ ions converted from Fe3+. This means there is a total of 40.0 mL x 0.0200 M = 0.800 mmol of Fe2+ in the original solution.
Since all of the Fe2+ ions are converted to Fe3+ in the first titration, the total amount of Fe3+ in the original solution is also 0.460 mmol.
Therefore, the molar concentrations of Fe2+ and Fe3+ in the original solution are:
[Fe2+] = 0.460 mmol / 25.0 mL = 18.4 mM
[Fe3+] = 0.460 mmol / 25.0 mL = 18.4 mM
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The pressure at the center of the earth is probably greater than 3x106 atm, and the temperature there is about 4000 °C. What is the change in the Gibbs function of reaction on going from crust to core for a reaction in which Vm = 1 cm3 mol-1 and Sm = 2.1 J K-1 mol-1
Answer:
The change in the Gibbs function of reaction on going from crust to core, dG=291442.4 J/mol
Explanation:
dG=vdp-sdT
Where T is the temperature .
P is the pressure.
S is entropy
V= 1cm3 =10-6 m3
P= 3*10∧6 atm = 3*10∧11 pa
The temperature at the center of the earth, Tc = 4*103 °C. : The temperature at the sufrace (crust) of the earth, Ts =298K.
Subistuting the values
dG = (10-6 *(3*1011-105) - (2.1(4373-298))
dG=291442.4 J/mol.