A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the weights is to double the rotational inertia of the system. As he is rotating, the man opens his hands and drops the two weights. They fall outside the turntable. Then:
A. his angular velocity doublesB. his angular velocity remains about the sameC. his angular velocity is halvedD. the direction of his angular momentum vector changesE. his rotational kinetic energy increases

Answers

Answer 1

Answer:

Explanation:CE

Let after the fall of weight from hands , the moment of inertia reduces from 2I to I. Since no external torque is acting on the system , angular momentum will be conserved.

I₁ ω₁ = I₂ ω₂

2I ω₁ = I ω₂

2ω₁ =  ω₂

So , angular velocity will be doubled.

Option A is correct.


Related Questions

If you are going 30 miles an hour in good condition, it will take how many feet to stop .

Answers

Answer:

158400 feet per hour

Explanation:

First we find:

How many feet are in miles per hour?

Multiply your speed in miles per hour by 5,280. This is the number of feet in a mile. The result is your speed in feet per hour.

For example, 30 miles per hour times 5,280 feet per mile is 158,400 feet per hour.

Your pet hamster sits on a record player whose angular speed is constant. If he moves to a point twice as far from the center, then his linear speed
A) doubles.
B) halves.
C) remains the same.

Answers

Answer:

option A

Explanation:

given,                    

angular speed is constant

initial distance = r                

final distance (r')= 2 r

initial linear velocity = v

final linear velocity = v'

we know,                  

v = r ω......................(1)

where r is the distance

ω is the angular speed

now,            

v' = r' ω            

v' = 2 r ω        

v' = 2 v                

hence, the linear velocity doubles.

The correct answer is option A

What symbol is used to represent internal energy in the first law of thermodynamics?

A. Q
B. W
C. U
D. V

Answers

Answer:

\Delta U = Q - W

aka—^

(ΔU = Q − W)

The symbol for Internal Energy Change isΔU. It is the sum of all the microscopic energies such as: translational kinetic energy. vibrational and rotational kinetic energy.

Answer:

C. U

Explanation:

HOPE THAT HELPS :)

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