A mobile phone is pulled northward by a force of 10 n and at the same time pulled southward by another force of 15 n. the resultant force on the phone is

Final answer:

The planet which is approximately 20 times farther from the Sun than Earth is Uranus, orbiting the Sun at an average distance of about 19.8 AU.

Explanation:

The question at hand is: Which planet is approximately 20 times farther from the sun than Earth is? To answer this, we can refer to the concept that the light a planet receives from the Sun decreases with the square of the distance from the Sun. Considering the average distance from Earth to the Sun is about 150 million kilometers (1 Astronomical Unit, AU), a planet that is 20 times farther from the Sun would be at 20 AU.

In our solar system, the planet that falls into this category is Uranus, which orbits the Sun at an average distance of approximately 19.8 AU. This makes Uranus about 20 times farther from the Sun than Earth is, hence receiving much less sunlight compared to Earth.

In comparing a kilogram of feathers and a kilogram of bricks, they have the same mass but do not have the same volume or density. Bricks are more dense than feathers.

The comparison between a kilogram of feathers and a kilogram of bricks deals with two primary concepts: mass and density. When we are comparing a kilogram of feathers and a kilogram of bricks, they have the same mass because a kilogram is a measure of mass. Therefore, option (a) is correct.

However, they do not have the same volume and the density of each is different. Density is defined as mass per unit volume. Bricks are denser than feathers. This means that for a given mass, bricks take up less space or volume than feathers. Therefore, neither option (b) nor options (c) and (d) are correct.

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Answer:

Density, d = 0.5 g/mL

Explanation:

It is given that,

Mass of the unknown liquid, m = 6 g

Volume of unknown liquid, V = 12 mL

Density is defined as the mass of the liquid divided by its volume. Mathematically, it is given by :

[tex]d=\dfrac{m}{V}[/tex]

[tex]d=\dfrac{6\ g}{12\ mL}[/tex]

d = 0.5 g/mL

So, the density of the unknown liquid is 0.5 g/ml. Hence, this is the required solution.

The efficiency of a machine is calculated by dividing the useful output energy by the total input energy and multiplying by 100%. In this case, the efficiency of the machine is 50%.

The efficiency of a machine is calculated using the formula: Efficiency = (useful output energy / total input energy) * 100%. In your case, the useful energy output of the simple machine is 100 J, while the total energy input is 200 J. So, the efficiency of your machine is (100 J / 200 J) * 100%, which gives 50%. Therefore, the efficiency of your machine is 50%.

Remember, efficiency in real machines will always be less than 100 percent. This is due to factors such as friction and air resistance which convert some of the work into unavailable heat. Also, note that the work, denoted as W, can indeed be calculated as a force multiplied by a distance, even if these quantities may not always be as obvious as they are in the case of a lever or pulley, for instance.

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Final answer:

In a compound microscope, the ocular lens is located near the eye for viewing and the objective lens is closer to the specimen for initial magnification.

Explanation:

The two lenses located in a compound microscope used in most classrooms today are the ocular lens and the objective lens. The ocular lens, or eyepiece, is found at the top of the microscope and is the lens that you look through with your eye. It often contains multiple lenses within a cylindrical barrel and contributes to magnifying the image. The second lens, known as the objective lens, is located closer to the specimen. It is a convex lens with a short focal length that provides the initial magnification, typically ranging from 5× to 100×. The objectives are commonly mounted on a revolving nosepiece and are designed to be parfocal, allowing the sample to remain in focus when switching between different objective lenses. Both the ocular and objective lenses work together to produce a highly magnified, enlarged image that is far enough from the observer to be easily viewed.

The relevant equations we can use in this problem are:

d = v0 t + 0.5 a t^2

v^2 = v0^2 + 2 a d

a. how high does it go?

We are to find for the distance d. The formula is:

v^2 = v0^2 + 2 a d

where v is final velocity = 0 at the peak, v0 = 25 m/s, a is negative gravity since opposite to direction = - 9.8 m/s^2, d is height achieved = ?

0 = (25)^2 + 2 (-9.8) d

d = 31.89 m

Therefore the maximum height is about 31.89 meters

b. how long is it in the air

We use the formula:

d = v0 t + 0.5 a t^2

in going up, a = -g = -9.8 m/s^2, find for time t:

31.89 = 25 t + 0.5 (- 9.8) t^2

-4.9 t^2 + 25 t = 31.89

t^2 – 5.1 t = 6.51

Completing the square:

(t – 2.55)^2 = 6.51 + 6.5025

t – 2.55 = ± 3.61

t = -1.06, 6.16

Since time cannot be negative, therefore:

t = 6.16 seconds

However this is not the total time yet, because this only accounts for the time going up.

The time going up and going down are equal therefore:

t(total) = 2 t

t(total) = 12.32 seconds

Therefore the foul ball spent 12.32 seconds in the air.

Answer:88 days

Explanation: The sidereal.orbital period is calculated from observations. Mercury is observed to come into

superior conjunction with the Sun every 116 days. This is called the "Mercury's synodic year". The sum of the inverse of earth's sidereal year and merciry's synod year equals the inverse of mercury's sidereal year. That is:

1/365.24 + 1/116 = 1/P where P is mercurry's sidereal year.

Therefore, P equals 88 days.

A total of 1.4 × 10⁵ Joule energy was dissipated by friction

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Let's recall Kinetic Energy Formula as follows:

[tex]Ek = \frac{1}{2}mv^2[/tex]

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

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Given:

mass of skier = m = 66 kg

height of trail = h = 230 m

velocity of skier = v = 11.0 m/s

Asked:

work done by friction = W = ?

Solution:

[tex]W = Ep - Ek[/tex]

[tex]W = mgh - \frac{1}{2}mv^2[/tex]

[tex]W = 66(9.8)(230) - \frac{1}{2}(66)(11.0)^2[/tex]

[tex]W = 148764 - 3993[/tex]

[tex]W = 144771[/tex]

[tex]W \approx 1.4 \times 10^5 \texttt{ Joule}[/tex]

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A total of 1.4 × 10⁵ Joule energy was dissipated by friction

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Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Answer:

conduction

Explanation:

educere

The number of neutrons varies among isotopes, even when the number of protons is the same.

Different nuclear species of the same element are known as isotopes.

They both belong to the same chemical element since they have the same atomic number (number of protons in their nuclei) and position in the periodic table, but they have distinct nucleon numbers (mass numbers) because they have different numbers of neutrons in their nuclei.

Although the chemical properties of each isotope of a particular element are almost identical, they differ in their atomic weights and physical characteristics.

To learn more about isotopes, click:

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The state that Patriacia and Pharao might be when they were commitment to a career field even though they don't know what they want to do in their career path is state of identity moratorium.

An identity moratorium  can be regarded as the  the process involving finding a sense of oneself.

This is because they are in a period of active searching for themselves and  to determine who they really are.

Learn more about identity moratorium at;

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Only about 11% of the volume of the iceberg is exposed.

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The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

[tex]\large {\boxed {P = F \div A} }[/tex]

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

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Given:

Density of Ice = ρ_ice = 0.92 g/cm³

Densiy of Seawater = ρ_seawater = 1.03 g/cm³

Asked:

Volume of the exposed iceberg = ΔV = ?

Solution:

We will use Archimedes' principle to solve the problem as follows:

[tex]w = F[/tex]

[tex]mg = \rho_{seawater} g V'[/tex]

[tex]\rho_{ice} \ g V = \rho_{seawater} \ g V'[/tex]

[tex]V' = ( \rho_{ice} \div \rho_{seawater} ) V[/tex]

[tex]V' = (0.92 \div 1.03) V[/tex]

[tex]V' = \frac{92}{103} V[/tex]

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[tex]\Delta V = V - V'[/tex]

[tex]\Delta V = V - \frac{92}{103} V[/tex]

[tex]\Delta V = \frac{11}{103}V[/tex]

[tex]\Delta V \approx 11 \% V[/tex]

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Grade: High School

Subject: Physics

Chapter: Pressure

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure

The earth's velocity as it orbits the sun is about 2.99 * 10⁴ m/s. The angular velocity is approximately 7.27 *10⁻⁷ rad/s, and the centripetal acceleration is around 5.93 m/s².

The earth's velocity (V), angular velocity (ω), and centripetal acceleration (A) can be calculated using the radius of the earth's orbit (r) around the sun and the period of orbit (T).

1. Earth's velocity:
As the earth orbits the sun, it covers a distance of 2πr (the circumference of a circle) in one complete orbit (T). Using the formula V = Δd/Δt, where Δd is the displacement in distance and Δt is the change in time, we can find earth's velocity to be approximately 2π* (1.5 *10¹¹ m)/(1 year) = 2.99 * 10⁴ m/s.

2. Angular velocity:
The earth's angular velocity can be determined by angular displacement over time. Since the earth completes 2π radians in one period of orbit (1 year), ω = Δθ/Δt = 2π/T , which when converted to SI units is approximately 7.27 *10⁻⁷ rad/s.

3. Centripetal acceleration:
Centripetal acceleration is determined using the formula A = V²/r. Using V = 2.99 * 10⁴ m/s and r = 1.5 * 10¹¹ m, we find A is approximately 5.93 m/s².

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Answer : The unbalanced force necessary to produce the movement is, 117.6 N

Solution :

Force : It is defined as the force is equal to the product of the mass of an object and the acceleration of an object.

Formula used :

[tex]F=m\times a[/tex]

where,

F = force

m = mass = 98 Kg

a = acceleration = [tex]1.2m/s^2[/tex]

Now put all the given values in the above formula, we get the unbalanced force necessary to produce the movement.

[tex]F=(98Kg)\times (1.2m/s^2)=117.6\text{ Kg }m/s^2=117.6N[/tex]

Therefore, the unbalanced force necessary to produce the movement is, 117.6 N

The unbalanced force necessary to produce the movement of a 98-kilogram man accelerating forward at a rate of 1.2 m/s² is 117.6 Newtons.

The unbalanced force necessary to produce the movement of a 98-kilogram man accelerating forward at a rate of 1.2 m/s² can be calculated using Newton's second law of motion:

F = m x a

Where F is the force, m is the mass, and a is the acceleration.

Substituting the given values:

F = 98 kg x 1.2 m/s²

F = 117.6 N

Therefore, the unbalanced force necessary to produce the movement is 117.6 Newtons.

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Answer:

"Stocks" type of investment offers both capital gains and interest income .

Explanation:

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This hypothesis and explanation highlight the effects of magnetic and electric fields, showing how they can be demonstrated using various methods like the right-hand rule. Evidence of a magnetic field near a current-carrying wire can be seen with iron filings or a compass, and the direction of magnetic fields and forces can be determined using specific rules. The hypothesis predicts which materials are magnetic due to their atomic structure.

If a magnetic field is applied to a current-carrying conductor, then the direction of the magnetic field around the conductor can be determined using the right-hand rule because the magnetic field generated by the current follows a specific pattern established by electromagnetic theory.

1. Evidence of a Magnetic Field Around a Current-Carrying Wire: When a current flows through a wire, it creates a magnetic field around it. This can be demonstrated using iron filings or a magnetic compass placed near the wire. The pattern of the iron filings or the direction of the compass needle will show the presence of the magnetic field.

2. Using the Right-Hand Rule: To determine the direction of the magnetic field around a current-carrying conductor, use your right hand: point your thumb in the direction of the current, and the curl of your fingers around the wire will point in the direction of the magnetic field.

Hypothesis: If a magnet is brought near various materials, then only certain materials will exhibit magnetism because magnetic properties are specific to materials with particular atomic structures, such as iron, cobalt, and nickel.

Effects of Magnetic Fields on Moving Charges: A moving charge in a magnetic field experiences a force perpendicular to both its velocity and the magnetic field direction. To determine the direction of this force, use the right-hand rule: point your fingers in the direction of the velocity, orient your palm to face the magnetic field direction, and your thumb will point in the direction of the force.

Magnetic Force Calculation: The force (F) on a moving charge (q) in a magnetic field (B) with velocity (v) is given by the equation F = q(v x B). This ensures that the force is perpendicular to both the velocity of the charge and the magnetic field.

Answer:

0.0043 or 4.3 × 10-3 seconds

Explanation:

Period= 1/frequency

[tex]T=\frac{1}{2.3*10^{2} Hz} = 0.0043[/tex] seconds

0.0043 seconds can be expressed in C.N as 4.3 × 10-3 seconds