A newborn weighing 9 lb 14 oz (4479 g) is delivered by cesarean due to cephalopelvic disproportion. The Apgar scores are 7 at 1 minute and 9 at 5 minutes. Which nursing action should be taken after the initial physical assessment?

Answer: 1.34A

Explanation:

Since the wire will break if it exceeds 1.90A current, this will be the maximum current needed.

The root mean square current

Irms = I0/√2

Where I0 is the maximum current given

Irms = 1.90/√2

Irms = 1.34A

Answer:

Angle of reflection will be [tex]40^{\circ}[/tex]

Explanation:

We have given angle of incidence from the smooth surface is [tex]40^{\circ}[/tex]

So angle of incidence = [tex]40^{\circ}[/tex]

We have to find the angle of reflection

From l;aw of reflection we know that angle of reflection is equal to the angle of incidence

So angle of reflection will be equal to [tex]40^{\circ}[/tex]

Answer:

40 degrees

Explanation:

got it right

Answer:

D

Explanation:

According to research and data, the average cost for a severe injury in a collision is $247,000.

These include traumatic brain injury, severe damage to limbs which could result to loss of the limbs, spinal cord injuries that could result to partial or total paralysis as well as internal damage to organs in the collision.

Answer:

lithosphere and asthenosphere

Explanation:

Lithosphere is the part of the earth surface which is rigid and hard. It consists of whole crust and the upper mantle.It comprises of number of plates called plate tectonic.

The asthenosphere is the Earth's upper mantle's extremely viscous, mechanically fragile and ductile area. This sits below the lithosphere, some 80 to 200 km below the ground at depths. The boundary between lithosphere and asthenosphere is commonly referred to as LAB.

Answer:

3 Hz

Explanation:

A beat is the pattern of interference among two waves with frequencies which are different.

The difference of the frequencies of the waves gives us the beat frequency.

Here, one frequency is [tex]f_1=440\ Hz[/tex], the other frequency is [tex]f_2=443\ Hz[/tex]

So, the beat frequency

[tex]\Delta f=|f_1-f_2|\\\Rightarrow \Delta f=|440-443|\\\Rightarrow \Delta f=3\ Hz[/tex]

The beat frequency that is produced is 3 Hz

The beat frequency is the difference between two interfering frequencies. In this case, it's the absolute difference between the violin string's frequency (443 Hz) and the electronic tuner's frequency (440 Hz), which results in a beat frequency of 3 Hz.

In the context of music and acoustics, a beat frequency is the pulsating sound that results when two slightly different frequencies interfere with each other. It can be calculated by taking the absolute difference between the two frequencies. So when a violinist is tuning his violin and compares a string's frequency (443 Hz) with that of an electronic tuner (440 Hz), the beat frequency produced would be 443 Hz - 440 Hz = 3 Hz.

This means that the violinist would hear an oscillating sound 3 times per second due to the interference of the two frequencies. Just like a piano tuner, the violinist would then adjust the tuning of the string until this beat frequency is minimized, signifying that the string's frequency matches that of the tuner.

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Answer:

B. 10 cubic inches

Explanation:

Boyle's Law: States that the volume of a given mass of gas is inversely proportional to its pressure provided that temperature is constant.

Mathematically, Boyle's law can be expressed as

P₁V₁ =P₂V₂......................... Equation 1

making V₂ the subject of formula in the equation above,

V₂ = P₁V₁/P₂ ..................... Equation 2

P₁ =initial pressure, V₁ = initial volume, P₂ = final pressure, V₂ = final Volume.

Given: P₁ = 5 psi, V₁ = 20 cubic inches, P₂ = 10 psi.

Substituting these values into equation 2

V₂ = (5 × 20)/10

V₂  = 10 cubic inches.

Therefore the new volume = 10 cubic inches

The right option is B. 10 cubic inches.

The correct answer is C; Bicycles.

Further Explanation:

In major cities, in the United States, have implemented signal lights specifically designed for bicycle riders. The riders also have their own designated bike lanes in many large cities. Drivers in vehicles, are to give the right of way to people on bicycles.

Bicycle riders are to follow the same laws and laws specifically for the riders or they can face fines and tickets.

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Answer:

The worker completed the circuit.

Explanation:

Thinking process:

Electricity is the flow of electrons in a circuit. There is one condition for the electrons to flow - the completion of a circuit. In order for that to be established, there must be a side with low electron concentration or affinity for electrons.

The earth has an infinite affinity for electrons. Thus, earth wires are used to channel an excess amount of electrons there. This prevents the short circuiting injuring a person. Hence, a three-pin plug.

Because there was not insulation, like rubber, an alternative pathway could not be found for electrons. Hence the worker was electrocuted as the electric current passed through him.

The electrocution occurred due to a lack of proper safety measures, specifically an improper grounding connection. When the bare, energized conductor of the fan connected with the ladder, the electrical current sought the path of least resistance to ground which included the worker's body.

The factors contributing to the fatal electrocution in this scenario are mainly faulty or inadequate safety measures and the behavior of electricity. Electricity always seeks the path of least resistance to the ground and in the absence of a proper ground wire connection, the electricity from the exposed conductor of the extension cord sought alternative grounding routes, in this case, through the worker's body.

Thermal and shock hazards are two primary dangers of electricity. A thermal hazard can cause fires due to excessive electric power resulting in unwanted thermal effects. A shock hazard is where electric current passes through a person, potentially causing harm ranging from a mild shock to death.

The system lacked a vital safety feature, which is a functioning ground connection. A three-wire system that includes live, neutral, and ground wires helps to avoid such scenarios. With a proper ground connection, any fault currents would be safely directed to the ground, and a circuit breaker would usually trip, cutting off the electricity. In this case, the lack of a proper ground connection contributed to the fatal electrocution.

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Answer:

Normal Magnetic Polarity

Explanation:

Normal Magnetic polarity.

The polarity can be either normal or reversed Natural polarity is where the north magnetic points (roughly) towards the north pole. ... The reversed polarity is in the opposite direction and the northern end of the magnetic field is near the current southern pole.

Answer:

We can explain it in term of center of mass and torque. When the sprinters start their race then the ground exerts the force towards the center of mass and thats how the torque can be prevented from acting on the sprinter.In this way the crouched position allows them to accelerate quickly without tipping over backward.

Explanation:

Applying Newton's laws of motion, the water droplets will continue in the direction they were moving at the moment of detachment, thus will travel in straight-line paths. This assumes that the effect of gravity is negligible.

The subject of this question lies in the vicinity of Physics, specifically, the principles of Newton's laws of motion and projectile motion. To answer the question, when the dog shakes and the droplets leave the fur, the motion of these droplets will be in straight-line paths (Option B).

Let's consider why this happens. The movement of the water droplets is set in motion by the dog's shake, and upon detachment from the fur, the droplets will continue in the direction they were moving at the moment of detachment, following Newton's first law of motion. As we're assuming negligible gravity during this short time, the droplets will not fall towards the earth, hence move in straight-line paths rather than parabolic arcs.

It's important to remember the core tenets of Newton's laws of motion. An object at rest will stay at rest, and an object in motion will continue in a straight line unless acted upon by an external force.

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Answer:

TRUE.   The weight component is responsible for acceleration and therefore the increase in vehicle speed,

Explanation:

Let's write Newton's second law for the car down a slope

Y Axis

         N-Wy = 0

         N = Wy

X axis

        Wx -fr= m a

Using trigonometry

        sin θ = Wx / W

        cos θ = Wy / W

         Wx = W sin θ

         Wy = W cos θ

We replace

             W sin θ - fr = m a

The weight component is responsible for acceleration and therefore the increase in vehicle speed,

fr is the force of car brakes

Consequently, of the above TRUTH

Explanation:

It is known that entropy is the degree of randomness. More is the speed of molecules of a substance more will be its degree of randomness. Hence, more will be the entropy of substance.

When we place a teaspoon of sugar in the bottom of a glass of water, it will dissolve completely over time. This dissolution will cause the sugar molecules to spread out in the water.

And, with time water will evaporate and this will lead to the formation of crystals again. This reappearance of sugar crystals will cause a decrease in entropy as there occurs decrease in randomness.

But this decrease in entropy is balanced by increase in the entropy of water molecules as they are evaporating.

The process of sugar dissolving and reappearing in water can be explained in terms of entropy.

The process described in the question can be explained in terms of entropy, which is a measure of the disorder or randomness in a system. When the teaspoon of sugar is placed in the water, the sugar crystals break down and mix with the water molecules, increasing the entropy of the system. With time, the water molecules continue to move and mix, increasing the disorder even further.

However, if the water is left to evaporate, the water molecules will escape into the air, and the sugar molecules will not be able to dissolve in the evaporating water. As a result, the sugar crystals will eventually reappear.

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Answer:

She was obese and had a diet high in salt intake.

Explanation:

higher blood pressure is condition known as hypertension which is the main cause of many heart problems which can be life threatening. In obese people. high level of fats inside the blood vessels which can cause blockage inside and can lead to heart problems.

high concentration of salts intake also disturbs the salts concentration in the blood vessels. The disturbance in salt concentration is the function of the kidney to remove it. the increase concentration also  cause increase in blood pressure which leads to hypertension.  

Answer:

She had a diet high in salt intake.

Explanation:

Sodium is medically known to raise blood pressure.

Washing hands and mosquitos are not related to blood pressure.

There is no vaccination against high blood pressure.

An object of weight 10 N that is falling on the ground, and it experiences a 10 N air resistance, then the net force on the object will be 0 N.

A force in physics is an input that has the power to change an object's motion.

A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces. Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.

According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.

As per the given information in the question,

Weight of the object = 10 N

Friction due to air resistance = 10 N

Then, the net force will be,

10 N - 10 N = 0 N

Therefore, the net force will be 0 N.

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The net force on the object is zero.

When an object is falling, it experiences two main forces: gravity (its weight) pulling it downward and air resistance pushing upward. In this case, the object has a weight of 10 N (newtons), which is a force acting downward due to gravity, and it encounters 10 N of air resistance, which is a force acting upward against the motion of the falling object.

To find the net force on the object, you need to calculate the difference between the two forces:

Net Force = Weight - Air Resistance

Net Force = 10 N - 10 N

Net Force = 0 N

So, the net force on the object is 0 N. This means that the forces of gravity and air resistance are equal in magnitude and opposite in direction, resulting in a net force of zero. In this situation, the object is in a state of dynamic equilibrium, and its velocity remains constant (it doesn't accelerate further).

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Answer:

e. design programming

Explanation:

The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).

The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).

STEPS:

Build a time diagram (moments of beginning and slack of activities).

Establish the times of each activity.

Analyze project costs and adjust clearances (minimum cost project).

The electric potential difference is the electric potential energy per unit charge

Explanation:

First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance [tex]r[/tex] from a positive charge of magnitude [tex]q[/tex] is given by

[tex]V(r) = \frac{kq}{r}[/tex]

where k is the Coulomb's constant.

Now we can define the electric potential energy and the electric potential difference:

The electric potential energy is also defined as the work done on a charge q moved through a potential difference of [tex]\Delta V[/tex]. Consequently, the potential difference [tex]\Delta V[/tex] represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference [tex]\Delta V[/tex].

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Final answer:

Electric potential energy is related to the energy of a charge's position in a field, whereas electric potential difference, or voltage, relates to the work required to move a charge between two points in a field.

Explanation:

Electric potential energy is a measure of the potential energy stored in a system of charges based on their positions, much like gravitational potential energy in a system of masses. On the other hand, electric potential difference, often referred to as voltage, is the work needed to move a charge between two points in an electric field without producing an acceleration. An analogy that can be helpful in differentiating the two is thinking of electric potential energy as the energy associated with the charge's position, similar to a rock perched on a hill, while electric potential difference relates to the effort required to move a rock up or down that hill.

Answer:

A). Enough to fly to the first point of intended landing and to fly after that for 45 minutes at normal cruising speed

Explanation:

Here are Fuel requirements for flight in VFR conditions

No person may begin a flight in an airplane under VFR conditions unless  there is enough fuel to fly to the first point of intended landing and, assuming normal cruising speed -

Answer: sensory, motor, associative

Explanation:

When a star is moving away from an observer at a constant speed, the wavelengths of the absorption lines in its spectrum appear to shift to longer wavelengths. This is known as the redshift.

When a star is moving away from an observer at a constant speed, the wavelengths of the absorption lines in its spectrum appear to shift to longer wavelengths. This phenomenon is known as the redshift. Redshift occurs because the motion of the star causes the wavelengths of light to stretch as the star moves away, just like the stretching of sound waves when a source moves away from an observer.

As the star gets farther and farther away, the amount of redshift increases, meaning the wavelengths of the absorption lines will shift even further towards the longer end of the spectrum. This shift in wavelengths can be measured using spectroscopy and is an important tool in determining the motion and distance of celestial objects. One example of redshift is the expansion of the universe itself, where galaxies are moving away from each other due to the expansion of space. The redshift of the light from distant galaxies provides evidence for this cosmic expansion.

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The wavelengths of absorption lines from a star moving away at a constant speed increase, exhibiting a redshift due to motion.

As a star moves away at a constant speed, the wavelengths of its absorption lines shift toward the red end of the spectrum. This is known as "redshift." It occurs because of the Doppler effect, where the motion of the source (star) affects the observed wavelength of light. When the star moves away, the observed wavelengths of light become longer, causing a redshift.

The Doppler effect explains that when an object is moving away from an observer, the waves it emits, including light, get stretched out, causing a shift to longer wavelengths. This redshift is used in astronomy to measure the recessional velocity of celestial objects, helping us determine the expansion of the universe and the distances between objects.

Redshift also plays a crucial role in the Hubble's law, which is fundamental in cosmology for understanding the universe's expansion.

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Answer:

C: look left then right then left again

Explanation:

At an intersection, there three routes, the left, the right and straight ahead.

For a car stopped at an intersection, once the light turn green, it is advisable that the driver should watch the left and right then left again before accelerating. This is because there might be any car coming from any of the sides unnoticed which might leads to accident especially the first side u looked at (left) must be take much cognisance of hence the need to look left again before accelerating.

Final answer:

When stopped at an intersection and your light turns green, you should A. look right and then left before accelerating.

Explanation:

When stopped at an intersection and your light turns green, you should look left, then right, then left again before accelerating. This practice ensures that you are aware of any vehicles that may not have stopped at their red light or are trying to beat a yellow light, as well as any pedestrians or cyclists that may be crossing.

Remember that while traffic signals are there to regulate flow, driver vigilance is crucial in preventing accidents and ensuring safety. Thus, it is important to check both directions to ensure the intersection is clear before proceeding. Safe driving practices include being cautious and aware of potential risks on the road.

Answer:

a.V(t/365)=30,000(0.89)^(t/365).

b. V(5)=$17000

Explanation:

An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

i will like to work back from te question by solving questin 2 first

V(t) = 30,000(0.89)^t

let t=5

V(5) = 30,000(0.89)^5

V(5)=$17000

2.yearly depreciation will be

30,000(0.89)^1

26700=it amounts to tis after a year,

so it depreciates by 3300 for one year

daily depreciation will be 3300/365 ,

since there are 365 days in a year

$9.041

the equation that satisfy this is

V(t/365)=30,000(0.89)^(t/365).

Final answer:

Mathematically, an automobile depreciating at 11% annually can be modeled for daily depreciation, but for the calculation of value after 5 years, we use the original annual model V(t) = 30,000(0.89)^t to find the car is worth approximately $13,000.

Explanation:

The student's question about the depreciation of an automobile can be classified under Mathematics, specifically dealing with exponential decay and depreciation models. To find the daily depreciation rate equivalent to 11% annual depreciation, we can use the formula for continuous compounding, where the annual rate is converted into a daily rate using the expression (1 + annual rate)^(1/365) - 1. However, since the problem does not ask for continuous daily depreciation but rather the equivalent discrete daily rate, we can instead divide the annual rate by 365, assuming each day the car depreciates by an equal fraction of the annual rate. Therefore, the daily depreciation rate would be 11% / 365.

However, because the student is seeking the value of the car after 5 years, we can directly use the provided equation V(t) = 30,000(0.89)^t, where t is the number of years. After 5 years, this gives us V(5) = 30,000(0.89)^5. Calculating this we get V(5) ≈ $13,000 when rounded to the nearest thousand.

Final answer:

When equal forces of 3.0 newtons are applied on both ends of a spring with an equilibrium length of 2.0 meters, the resulting length of the spring remains 2.0 meters because the forces cancel each other out.

Explanation:

To find the resulting length of the spring, we should first determine the amount of stretch or compression caused by the forces applying on the spring. Since Alice and Bob are both pulling with a force of 3.0 newtons each in opposite directions, the net force on the spring is zero. Therefore, the spring neither stretches nor compresses from its equilibrium length.

The spring has an equilibrium length of 2.0 meters and remains at this length because the forces applied by Alice and Bob cancel each other out. So, the resulting length of the spring when 3.0 newtons is applied at each end in opposite directions is 2.0 meters, which is answer (B).

The question relates to Simple Harmonic Motion of a mass-spring system, and asks to calculate the period of the motion. The approach involves the use of Hooke's law and Newton's second law, and understanding that at maximum amplitude, gravitational potential energy converts to elastic potential energy.

The question discusses a concept in physics known as Simple Harmonic Motion, specifically in relation to a mass attached to a spring. The object of unknown mass is hung on the unstretched spring, let go and then allowed to move down under the force of gravity. This object comes to rest for the first time when it has moved to its maximum amplitude, which is given as 2.75 cm. The period of the motion is what we are required to find.

The period of oscillation for a simple harmonic oscillator (in this case, a mass-spring system) can be calculated using the formula T = 2π√(m/k), where m is the mass and k is the spring constant. However, from the given information, we do not have the mass or the spring constant and need an alternative approach.

Let's use Hooke's law (F = kx) and Newton's second law (F = ma). We know that at the maximum amplitude, all the gravitational potential energy is converted to elastic potential energy. We can write mgx = 0.5 kx^2, where g is the acceleration due to gravity and x is the displacement (2.75 cm). From here we can calculate k. Then we substitute this value of k obtained into the formula for T, we could then find the period of the motion of the object.

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An autotransformer is a type of electrical transformer that has only one winding, and portions of the same winding act as both the primary and secondary winding sides of the transformer. A 33.9 kVA autotransformer is needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, using the co-ratio method.

To determine the size of an autotransformer needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, we can use the co-ratio method.

The co-ratio is the ratio of the number of turns on the primary winding to the number of turns on the secondary winding of the transformer.

Secondary voltage: 480 V

Load voltage: 277 V

Load current: 100 kVA

To calculate the co-ratio, we can use the formula:

Co-ratio = Secondary voltage / Load Voltage

Co-ratio = 480 V / 277 V

Co-ratio ≈ 1.734

The co-ratio is approximately 1.734. To determine the size of the autotransformer needed, we can use the formula:

Size of autotransformer = Load kVA / (Co-ratio)²

Size of autotransformer = 100 kVA / (1.734)²

Size of autotransformer ≈ 33.9 kVA

Therefore, a 33.9 kVA autotransformer is needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, using the co-ratio method.

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To supply a 100 kilovolt-ampere load with 277 volts from a 480-volt secondary, an autotransformer that is roughly 1.73 times smaller than the original isolated type transformer is required. The size calculation is derived from the co-ratio (the ratio of primary to secondary voltages), which here equals to 480/277 = 1.73.

The subject in question is regarding the use of an autotransformer, specifically, what size is needed to reduce the voltage from 480 volts to 277 volts in order to supply a 100 kilovolt-ampere load. First, we need to handle the co-ratio. The co-ratio of a transformer is the ratio of primary to secondary voltages, often used to calculate the size of a transformer. In this case the co-ratio would be 480/277 = 1.73.

Utilizing the transformer equation, we can comprehend that the voltage reduction from 480 to 277 volts that undergoes in an autotransformer proposes a comparable reduction in size of the transformer. Based on this, the autotransformer needed should be around 1.73 times smaller than the original isolated type transformer.

As a brief primer on the functioning of the transformers, they operate on the principle of electromagnetic induction and are used in power distribution systems to step-up or step-down the voltages. This allows the efficient transmission of power over long distances and also the provision of the correct voltage levels suitable for different uses.

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Answer:

[tex]\frac{R}{1} = \frac{44}{9}\ohm[/tex]

Explanation:

Let us imagine that there are three wire of length equal length having equal resistances each of 44/3 Ω

Now connect these wires in parallel to so that their equivalent resistance is R.

then

[tex]\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}[/tex]

[tex]\frac{1}{R} = \frac{3}{44}+\frac{3}{44}+\frac{3}{44}[/tex]

[tex]\frac{1}{R} = \frac{9}{44}[/tex]

⇒[tex]\frac{R}{1} = \frac{44}{9}\ohm[/tex]

Answer:

4.89 Ω

Explanation:

we know that resistance is directly proportional to length. hence as the wire is cut in three pieces, the resistance of each piece becomes one-third of the original resistance of the wire.

[tex]R[/tex] = Resistance of wire = 44 Ω

[tex]r[/tex] = resistance of each piece

Resistance of each piece  is given as

[tex]r = \frac{R}{3}\\r = \frac{44}{3}[/tex]

The three pieces are connected in parallel,

[tex]R_{p}[/tex] = Resistance of parallel combination of three pieces

Resistance of parallel combination is given as

[tex]\frac{1}{R_{p}}= \frac{1}{r} +  \frac{1}{r} +  \frac{1}{r} \\\frac{1}{R_{p}}= \frac{3}{r}\\R_{p}= \frac{r}{3}\\R_{p} = \frac{\frac{44}{3} }{3}\\R_{p} = \frac{44}{9} \\R_{p} = 4.89 ohm[/tex]

Explanation:

The primary to secondary voltage ratio is given as 4:1 .

That is

                 [tex]\frac{V_p}{V_s}=\frac{4}{1}=4[/tex]

We need to find what is the secondary voltage if the primary voltage is 460 volts.

That is

                    [tex]V_p=460V[/tex]

Substituting in ratio equation

                    [tex]\frac{V_p}{V_s}=4\\\\\frac{460}{V_s}=4\\\\V_s=\frac{460}{4}\\\\V_s=115V[/tex]

The secondary voltage is 115 V.                  

Final answer:

To find the secondary voltage in a transformer with a primary to secondary voltage ratio of 4:1 and a primary voltage of 460 volts, divide the primary voltage by 4, resulting in a secondary voltage of 115 volts.

Explanation:

To solve for the secondary voltage in a transformer when given a voltage ratio of 4:1 and a primary voltage of 460 volts, we can use the transformer equation.

This equation states the ratio of the secondary voltage (Vs) to the primary voltage (Vp) is equal to the ratio of the number of turns in the secondary coil (Ns) to the number of turns in the primary coil (Np).

In this question, the primary to secondary voltage ratio is 4:1. If the primary voltage (Vp) is 460 volts, we can calculate the secondary voltage (Vs) by dividing the primary voltage by the ratio, which in this case is 4. Therefore, Vs = 460 / 4 = 115 volts.

Answer:

2 & 3

Explanation:

Since they are all vector quantities, if they remain in a closed system where no external force acts on the system, the vector sum of the momentum remains constant.

When there is no loss or gain in the total vector sum of the energy of the system means it's energy is conserved.

Answer: a. high capillary action.

Explanation:

Water can pile up a short distance above a container's rim due to high capillary action. Capillarity is process by which water falls or rise through a narrow capillary tube. The concept allows water to rise to a certain height through the container before dropping.

Answer:

If you were to look for a cut on the palmar surface of a dog's leg then you should look at the back area of the front leg below the carpus.

Explanation:

Final answer:

To find a cut on the palmar surface of a dog's leg, you would check the underside of the foreleg where the paw pads are located.

Explanation:

If you want to locate a cut on the palmar surface of a dog's leg, you would look at the underside of the dog's foreleg. In humans, the palmar surface refers to the palm of the hand, and similarly, in quadrupeds like dogs, it refers to the analogous area - the bottom of their paws on the forelegs, where dogs have pads that contact the ground. This is analogous to the palm of the human hand although covered with different skin and touch pads.