Answer:
0.035 N
Explanation:
Density = mass/volume
D = m/v
m = D× v ..................... Equation 1
Where D = density of the ping-pong, v = volume of the ping-pong, m = mass of the ping-pong
Note: The ping-pong is spherical in shape.
v = 4/3πr²
Where r = radius, π = pie
d = 1.99 cm, π = 3.14
v = 4/3(1.99/2)²(3.14)
v = 4.12 cm³
Also D = 0.121 g/cm³
Therefore,
m = 0.121(4.12)
m = 0.499 g
W = mg
Where W = weight of the ping-pong
W = (0.499/1000)×9.81
W = 0.005 N.
From Archimedes principle,
Upthrust = density of water × volume of water displaced × acceleration due to gravity.
U = D'vg/1000...................... Equation 2
Note: The volume of water displaced is equal to the volume of the ping-pong.
given: v = 4.12 cm³, g = 9.81 m/s², D' = 1 g/cm³
Substitute into equation 2
U = 1(4.12)(9.81)/1000
U = 0.04 N
The force required to hold the ball completely submerged under water = U-W
= 0.04-0.005 = 0.035 N
Energizer batteries would be classified as which type of product? a. Shopping b. Convenience c. Industrial service d. Unsought e. Specialty
Answer:
i believe it would be classified as A shopping
A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original direction of the cue ball and 2.0 N·s perpendicular to that direction. What is the momentum of the cue ball after the collision?
Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,P₁ = 9 N.s
momentum of nine ball in x- direction, P₂ = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
P₁ + p = x + P₂
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 = x + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'₁ + p = y + P'₂
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .
[tex]P = \sqrt{x^2+y^2}[/tex]
[tex]P = \sqrt{7^2+(-2)^2}[/tex]
P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
The momentum of the cue ball after the collision is calculated to be 6.2 N·s in based on the conservation of momentum.
Explanation:This physics problem involves the principle of conservation of momentum. Initially, the cue ball has a momentum of 9.0 N·s. After the collision, the nine-ball has a momentum of 2.0 N·s in the original direction and another 2.0 N·s in a perpendicular direction. To find the momentum of the cue ball after the collision, we need to take into account that the total momentum of the system is conserved before and after the collision.
In this case, the total initial momentum is the momentum of the cue ball, which is 9.0 N·s. After the collision, the total momentum should still be 9.0 N·s. The sum of the momenta of the nine-ball (which is the square root of the sum of the squares of the two momentum components, due to the Pythagorean theorem) is 2.8 N·s. Therefore, the momentum of the cue ball after the collision will be the total initial momentum minus the momentum of the nine-ball after the collision, which gives us 9.0 N·s - 2.8 N·s = 6.2 N·s.
To solve this problem, we can use the principle of conservation of momentum. Before the collision, we have the momentum of the cue ball which is 9.0 N·s. After the collision, we have the momentum of the nine-ball which is 2.0 N·s in the original direction of the cue ball and 2.0 N·s perpendicular to that direction. Since momentum is conserved, the total momentum before the collision is equal to the total momentum after the collision. Therefore, the momentum of the cue ball after the collision is the difference between the total momentum before the collision and the momentum of the nine-ball after the collision.
To calculate the momentum of the cue ball after the collision, we subtract the momenta of the nine-ball from the initial momentum of the cue ball. The momentum of the cue ball after the collision is therefore 9.0 N·s - (2.0 N·s + 2.0 N·s) = 5.0 N·s in the original direction of the cue ball.
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An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point a distance 34.0 m below its starting point at a time 5.00 s after it leaves the thrower's hand. Air resistance may be ignored.
A) What is the initial speed of the egg?
B) How high does it rise above its starting point?
C) What is the magnitude of its velocity at the highest point?
E) What are the magnitude and direction of its acceleration at the highest point?
Part A. The initial speed of the egg is 17.7 m/s.
Part B. The maximum height of the egg is 15.98 m.
Part C. The magnitude of the velocity at its highest point is 0 m/s.
Part E. The magnitude and direction of the acceleration in the upward direction is 9.8 m/s2.
Velocity and AccelerationGiven that the distance traveled by the egg is 34 m in time 5 seconds.
The distance at its initial point will be zero.
Part A
The initial speed of the egg can be calculated by the position equation of the egg.
[tex]x = x_0 + v_0t + \dfrac {1}{2}at^2[/tex]
Where x is the initial position of the egg that is 0 m, x_0 is the final position that is 34 m in time t = 5 s, v_0 is the initial speed and a is the acceleration. Since the egg is thrown vertically, hence the acceleration of the egg is similar to the gravitational acceleration.
[tex]0 = 34 + v\times 5 + \dfrac {1}{2}\times(- 9.8)\times 5^2[/tex]
[tex]v = \dfrac {122.5 - 34}{5}[/tex]
[tex]v = 17.7 \;\rm m/s[/tex]
The initial speed of the egg is 17.7 m/s.
Part BThe maximum height for the egg can be calculated by the equation given below.
[tex]v^2 = v_0^2 + 2gh[/tex]
For the highest point, the final speed v will be zero and the initial speed v_0 is 17.7 m/s. Hence,
[tex]0 = (17.7)^2 + 2\times (-9.8)\times h[/tex]
[tex]19.6 h = 313.29[/tex]
[tex]h = 15.98 \;\rm m[/tex]
The maximum height of the egg will be 15.98 m.
Part CThe velocity of the object thrown at a height will be zero at its highest point. Hence the velocity of the egg will be zero at its highest point.
Velocity [tex]v_h[/tex] = 0 m/s
Part EThe egg is thrown vertically upward, hence its acceleration is similar to the gravitational acceleration.
Acceleration a = 9.8 m/s2
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One drawback of dams is that they can flood land upstream from the dam and reduce water flow downstream from the dam. Question 2 options: True False
Answer:
True
Explanation:
It can cause flooding and destruction of habitat because of dammed rivers create large reservoirs upstream which can spill out to the surrounding during heavy rainfall causing flooding and destruction of natural habitat.
An electrical engineer wants to build an electrical circuit with a 3-volt battery connected in series to a light bulb with a resistance of 6 ohms. How much current will be flowing through the light bulb if this circuit is built?
Answer:
0.5A
Explanation:
GIVEN THAT:
V = 3 V
R =6 ohms
V=IR
I =V/R
I = 3/6 =0.5 A
A conical paper cup is 10 cm tall with a radius of 10 cm. The bottom of the cup ispunctured so that the water leaks out at a rate of 16p3 cm³/sec. At what rate is the waterlevel changing when the water level is 3 cm?
Answer:
0.59 cm
Explanation:
height of cup (h) = 10 cm
radius of cup (r) = 10 cm
rate of change of water level (V') = 16π/3 [tex]cm^{3} /sec[/tex]
rate of change of height (h) = 3 cm
the ratio of the height to radius (h:r) = 10:10
h/r = 10/10
h/r = 1
r=h
formula for volume of a volume (v) = [tex]\frac{1}{3}[/tex].π[tex]r^{2}[/tex]h
substituting r=h into the formula above we have
v = [tex]\frac{1}{3}[/tex].π[tex]h^{2}[/tex]. h = [tex]\frac{1}{3}[/tex].π[tex]h^{3}[/tex]
differentiating the above we have
v' = 3([tex]\frac{1}{3}[/tex]π[tex]h^{2}[/tex])h' = π[tex]h^{2}[/tex].h'
rearranging the above we have
h' = v' / (π[tex]h^{2}[/tex])
where
v' = rate of change of water levelh' = rate of change of water levelh = water levelh' = ((16 x π) / 3) ÷ ( π x [tex]3^{2}[/tex])
h' = ((16 x 3.142) / 3) ÷ ( 3.142 x [tex]3^{2}[/tex])
h' = 16.76 / 28.28
h' = 0.59 cm
Because it implies royal status, the granary at the Conical tower and circular wall of Great Zimbabwe is most similar to what object?
Answer:
The Commemorative head of a king (Oba)
Explanation:
The commemorative head of a king is similar to the other features mentioned in the question due to their royal statuses. These features are idolized by the people in their respective societies. The 'Oba' for example is respected by the people of Benin and he makes the rules and regulations for the people. When he dies, his eldest son usually takes his position.
Answer:
The Commemorative head of a king (Oba)
Explanation:
I took the test B )
If a force of 2n does work at the rate of -2sqrt2 w on an object moving iwth a speed of 2m/s the ale between the fore and teh velocity vector must be ______
Answer:
The value of the angle theta = 135degree, which is option c.
Explanation :
These are the options given in the question
a) 45 degrees
b)120 degrees
c)135 degrees
d)150 degrees
e) it is impossible to deliver a negative power.
The concept of work done on an object is applied here.
work = Fd
F = ma
work = mad
Work is a form of energy transferred by an object after the application of a force that act on the object. A step by step explanation is as attached below.
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator and a 70 kg person that is 0.5 meters from the refrigerator.
Answer:
3.735×10⁻⁶ N
Explanation:
From newton' s law of universal gravitation,
F = Gmm'/r² .............................. Equation 1
Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.
Given: m = 70 kg, m' = 200 kg, r = 0.5 m
Constant: G = 6.67×10⁻¹¹ Nm²/kg².
F = (6.67×10⁻¹¹×70×200)/0.5²
F = 93380×10⁻¹¹/0.25
F = 373520×10⁻¹¹
F = 3.735×10⁻⁶ N
Hence the force between the person and the refrigerator = 3.735×10⁻⁶ N
Suppose an electron is moving with a constant velocity until it encounters a positively charged sphere on its right. How does the sphere alter the trajectory of the electron?
a. It has no effect on the trajectory of the electron
b. It deflects the electron to the right.
c. It deflects the electron to the left.
d. Impossible to tell
Answer:
b. It deflects the electron to the right.
Explanation:
Since the sphere is positively charged and electron has negative charge, it will be attracted toward the sphere and hence,
The electron is deflected to the right as the positively charged sphere on its right
So, the 2nd option is correct.
Explain the mathematical equation for KVL (The voltage of a circuit through each component in that circuit is proportional to the resistance).
Explanation:
Kirchhoffs Voltage Rule, or KVL, explains that "the overall voltage throughout the circuit in any closed loop network is equal to the sum of all voltage decreases inside the same loop" which is equivalent to zero. In other words, the mathematical sum of all within the loop voltages must be equal to zero.
Which of the following are core capabilities for a response?
a. Cybersecurity; community resilience; and housing
b. Forensics and attribution; physical protective measures; and economic recovery
c. Interdiction and disruption; access control; and threats/hazards identification
d. Critical transportation; situation assessment; and mass care services
Answer:
d. Critical transportation; situation assessment; and mass care services
Explanation:
The correct answer is option d which is Critical transportation: Situation assessment and mass care services are core capabilities for response.
As we know that critical transportation are very important factor which control capability for responses. Due to fast transportation a life can be saved, people can be out of danger in the situation of natural calamity.
A 5 kg box is sliding across a level floor. The box is acted upon by a force of 27 newtons east and a frictional force of 17 newtons west. What is the magnitude of the acceleration of the box? Type only numbers. Do not include the units of m/s2.
Answer:
The acceleration of the box is 2.
Explanation:
According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.
Net force = Mass × Acceleration
So [tex]Acceleration = \frac{Net force}{Mass}[/tex]
Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.
Net force = 27-17 = 10 N.
Thus, [tex]Acceleration = \frac{10 N}{5 kg}[/tex]
So 2 [tex]m/s^{2}[/tex] is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.
How did new technology such as the telescope and new theories such as Pascal's Law laid the foundation of the Scientific Revolution? *
Answer:
"Scientists used them to create new theories"
Explanation:
The Scientific Revolution was a sequence of actions that manifest the development of contemporary science through the early contemporary period, when advances in mathematics, physics, astronomy, biology and chemistry altered the opinions of civilization around nature. The scientific revolution denotes to the quick developments in European scientific, mathematical, and political assumed, grounded on a new philosophy of experimentation and a belief in growth that defined Europe in the 16th and 17th centuries.
Final answer:
The telescope and Pascal's Law played a significant role in laying the foundation of the Scientific Revolution. The telescope allowed for groundbreaking observations of the solar system and the universe, while Pascal's Law led to advancements in fluid mechanics and hydraulic engineering.
Explanation:
The new technology, such as the telescope, and new theories, such as Pascal's Law, played a significant role in laying the foundation of the Scientific Revolution.
Firstly, the invention of the telescope in 1608 allowed astronomers like Galileo Galilei to make groundbreaking observations of the solar system and the universe, leading to the development of new theories and understandings of celestial bodies.
Secondly, Pascal's Law, formulated by Blaise Pascal, established the principle that pressure exerted on a fluid is transmitted uniformly in all directions, which laid the foundation for the field of fluid mechanics and led to advancements in hydraulic engineering and other areas.
You are given two infinite, parallel wires each carrying current I. The wires are separated by a distance d, and the current in the two wires is flowing in the same direction. This problem concerns the force per unit length between the wires.
What is the force per unit length F/L between the two wires?
Express your answer in terms of I, d, and constants such as μ0 and π.
Answer:
[tex]\dfrac{F}{L}=\dfrac{\mu_oI^2}{2\pi d}[/tex]
Explanation:
If the current flowing in two wires is I and they are separated by a distance of d. We know that the magnetic field due to a wire is given by :
[tex]B=\dfrac{\mu_oI}{2\pi d}[/tex]
Where
d is the separation between wires
The magnetic force between the wires is given by :
[tex]F=BIL[/tex]
I is the current in wire
L is the length of the wires
[tex]F=\dfrac{\mu_oI^2L}{2\pi d}[/tex]
The magnetic force per unit length is given by :
[tex]\dfrac{F}{L}=\dfrac{\mu_oI^2}{2\pi d}[/tex]
So, the force per unit length F/L between the two wires is [tex]\dfrac{\mu_oI^2}{2\pi d}[/tex]. Hence, this is the required solution.
A 0.71 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a)1.4 m from the source and (b)2.6 m from the source.
Answer:
(a) 2.88×10⁻² W/m²
(b) 8.36×10⁻³ W/m²
Explanation:
The intensity of sound from an isotropic point source, with distance L is given as
I = P/(4πL²) .................................... Equation 1
Where I = intensity of sound, P = Power from the source, L = length, π = pie.
(a)
1.4 m from the source.
I = P/(4πL²)
Given: P = 0.71 W, L = 1.4 m, π = 3.14.
Substitute into equation 1
I = 0.71/(4×3.14×1.4²)
I = 0.71/24.6176
I = 0.0288 W/m².
I = 2.88×10⁻² W/m²
(b) 2.6 m from the source.
Given: P = 0.71 W, L = 2.6 m, π = 3.14
Substitute into equation 1
I = 0.71/(4×3.14×2.6²)
I = 0.71/84.9056
I = 0.00836 W/m²
I = 8.36×10⁻³ W/m²
Speed is an important component of which of the following sports? A. tennis B. soccer C. swimming D. all of the above Please select the best answer from the choices provided. A B C D
Answer: D. all of the above
Explanation:
The speed is important in tennis, so you can win easily, speed is important in soccer to collect the ball quickly and reach the goal, speed is necessary for swimming as the first person wins the game so, option D is correct.
What is speed?A moving object's rate of change in distance traveled is measured as speed. Speed is a scalar, which implies it is a measurement with a magnitude but no direction.
A thing that moves quickly and with high speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time. An object with zero speed does not move at all.
Speed shortens the time needed to complete a task or travel between two locations. The spare time can then be applied to other tasks. The Earth's orbit around the Sun is maintained by speed.
Thus, speed is important in all the games mentioned here.
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Ball 1, with a mass of 150 g and traveling at 15 m/s , collides head on with ball 2, which has a mass of 350 g and is initially at rest.A) What are the final velocities of each ball if the collision is perfectly elastic?B) What are the final velocities of each ball if the collision is perfectly inelastic?
Answer: A. Vb1 = -6m/s , Vb2 = 9m/s.
B. Vb1 = 4.5m/s , Vb2 = 4.5m/s
Explanation: A. In a perfectly elastic collision the objects involved moved with a different velocity after collision. Also kenitic energy is conserved. In other to get the different velocity of ball 1 (Vb1) and ball 2 (Vb2) after collision, we apply the following formula
Vb1 = {{m1 - m2}*V1}/{m1 +m2}
Vb2 = {{2m1}*V1}/{m1 + m2}
Where V1 = velocity of ball 1 before collision=15m/s
m1 = mass of ball 1
m2 = mass of ball 2.
Substituting in the above equation:
Vb1 = {{0.15kg - 0.35kg}*15}/{0.15 + 0.35}
= {{-0.2}*15}/0.5
= -3/0.5
= -6m/s
Also,
Vb2 = {{2*0.15kg}*15m/s}/{0.15kg + 0.35kg}
={0.3kg*15m/s}/0.5kg
=4.5/0.5
=9m/s
B. In a perfectly inelastic collision the object involved move with a common velocity after collision.
We have that ,
m1*V1 + m2*v2 = {m1 + m2} V¹
Where V¹ is the final velocity of both balls after a perfectly inelastic collision.
NOTE: v2 here is 0m/s since ball 2 was at rest before collision.
So we have,
0.15kg*15m/s + 0.35kg*0m/s = {0.15kg + 0.35kg}*V¹
2.25 kgm/s = 0.5kg* V¹
Making V¹ subject of formula we have,
V¹ = 2.25kgm per sec/0.5kg
=4.5m/s. vb1 = Vb2 = V¹
NOTE also that the mass of the balls from the question were given in gram hence we converted to kilogram the standard unit for mass by dividing by 1000.
Answer:
For both ball 1 and ball 2, the change in velocity is less in an inelastic collision.
Explanation:
a short simple answer
Two identical speakers, with the same phase constant, are arranged along a 1D track. One speaker remains at the origin. The other speaker can slide along the track to any position x. You are on the track at x=10 m. You hear interference maxima when the adjustable speaker's position is 0.6 m and 1.2 m and at no points in between. What is the frequency of the sound from the speakers in Hz?
Answer:
[tex]f=571.67\ Hz[/tex]
Explanation:
Given:
Two identical speakers have the same phase constant.One of the speaker remains origin.The other speaker moves linearly from origin to x=10mposition of maxima of the interference, [tex]x_1=0.6\ m[/tex]position of next maxima of the interference, [tex]x_2=1.2\ m[/tex]Therefore we have the wavelength of the wave as the distance between the two consecutive maxima:
[tex]\lambda=1.2-0.6[/tex]
[tex]\lambda=0.6\ m[/tex]
We have the speed of sound in the air as:
[tex]v=343\ m.s^{-1}[/tex]
Therefore the frequency of sound:
[tex]f=\frac{v}{\lambda}[/tex]
[tex]f=\frac{343}{0.6}[/tex]
[tex]f=571.67\ Hz[/tex]
The frequency of the sound from the speaker is 571.67 Hz.
How do you calculate the frequency?Given that the phase constant of speakers is the same, the position of one speaker is at origin, the position of another speaker from the origin is 10 m.
The position of maxima interference is at 0.6 m and 1.2 m. Hence the wavelength of the wave is equivalent to the difference between the two consecutive maxima interference.
[tex]\lambda = 1.2 - 0.6[/tex]
[tex]\lambda = 0.6 \;\rm m[/tex]
We know that the speed v of the sound in the air is 343 m/s. Hence the frequency of the sound is calculated as given below.
[tex]f = \dfrac {v}{\lambda}[/tex]
[tex]f = \dfrac { 343}{0.6}[/tex]
[tex]f = 571.67\;\rm Hz[/tex]
Hence we can conclude that the frequency of the sound from the speaker is 571.67 Hz.
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A least squares regression line was created to predict the Exam 3 score of STA 2023 students based on their Exam 1 score. The study found that the value of R-squared was 28.8% and the least squares regression line was yhat=50.57+0.4845x. What is the correlation coefficient, r?
1.0.54
2.-0.54
3.5.37
4.-5.37
5.0.08
6.-0.08
Answer: Option (1) is the correct answer.
Explanation:
Formula to calculate correlation coefficient is as follows.
Correlation coefficient = [tex]\sqrt{R^{2}}[/tex]
As the slope for given equation is positive so, it means that the correlation will also be positive in nature.
Therefore, we will calculate the value of correlation coefficient as follows.
Correlation coefficient = [tex]\sqrt{R^{2}}[/tex]
= [tex]\sqrt{(0.288)^{2}}[/tex]
= 0.54
Thus, we can conclude that the correlation coefficient, r is 0.54.
If you very lightly touch a guitar string at its midpoint, you can hear a tone that is one octave above the fundamental for that string.Explain?
Answer:
Change, increase in note frequency of the sound that comes as a result of the reduction in the vibrating length (wavelength) when the string movement is slightly restricted at its midpoint
Explanation:
When the midpoint of a vibrating guitar string is lightly touched it reduces the wavelength of the guitar string sound, halving it and such increases the the frequency inversely by a factor of 2
The relationship
f = vw/λ, for sound wave where vw is the speed of sound, frequency, f and λ is the wavelength
Frequency varies inversely with wavelength
An Octave
is the frequency vibration of sound-wave twice that of its lower note
A floating ball normally weighs 5.5 N. The acceleration of gravity is 9.8 m/s 2 . What is the size of the buoyant force that acts on it?
Answer:
5.5 N
Explanation:
Weigh of floating ball=5.5 N
Acceleration due to gravity=9.8 [tex]m/s^2[/tex]
We have to find the size of the buoyant force that acts on it.
We know that
Buoyant force is that force which act in upward direction and exert by fluid and opposes the weight of an immersed object.
Therefore,
Buoyant force=Weight of ball
Buoyant force=5.5 N
Hence, the size of buoyant force acts on the ball=5.5 N
Given the ball's weight of 5.5 N, the buoyant force is also 5.5 N.
To determine the buoyant force acting on a floating ball, we can use the principles of buoyancy and the given information about the ball's weight. The ball's weight in air is 5.5 N, and we know the acceleration due to gravity (g) is 9.8 m/s².
For a floating object, the buoyant force (Fb) is equal to the weight of the object when it is floating. Therefore, since the ball is floating, the buoyant force must equal the weight of the ball:
Buoyant force Fb = Weight of the ball
Given that the weight of the ball is 5.5 N, the buoyant force acting on the ball is:
Fb = 5.5 N
This force is what keeps the ball afloat in the fluid.
A ball that is thrown upwards from the ground will eventually reach its highest point and fall back to the ground. Which of the following quantities will be constant over the course of this up and down motion?
a. The ball's position.b. The ball's speed.c. The ball's acceleration.d. Nonsense! None of these are constant.
Answer:
option (c)
Explanation:
When an object thrown upwards, the value of acceleration acting on the object is acceleration due to gravity which is always acting towards the earth.
As it falls downwards, the acceleration is again equal to the acceleration due to gravity.
So, the ball's acceleration is constant.
Final answer:
The acceleration of the ball remains constant throughout its up and down motion since it is solely influenced by gravity, which provides an acceleration of approximately 9.81 m/s² downward
Explanation:
When a ball is thrown upwards from the ground and then falls back down, the acceleration of the ball is what remains constant throughout its motion. This is due to gravity, which acts downward on the ball with an acceleration denoted as "g". While the ball's position and speed are changing throughout the motion, its acceleration due to gravity remains constant at approximately 9.81 m/s2 (on Earth), regardless of its state of motion. Therefore, the quantity that remains constant over the course of this up and down motion is the ball's acceleration.
A 3-kg object is moving at 5.0 m/s. An 12-N force is applied in the direction of motion and then removed after the object has traveled an additional 6.0 m. What is the work done by this force?
Answer:
The work done by the force is 109.5 Joules.
Explanation:
It is given that,
Mass of the object, m = 3 kg
Speed of the object, v = 5 m/s
Force applied on the object, F = 12 N
Distance covered by the object, d = 6 m
The work done by this force is given by the sum of kinetic energy and potential energy as per work energy theorem as :
[tex]W=K+P[/tex]
[tex]W= \dfrac{1}{2}mv^2+Fd[/tex]
[tex]W=\dfrac{1}{2}\times 3\times (5)^2+12\times 6[/tex]
W = 109.5 Joules
So, the work done by the force is 109.5 Joules. Hence, this is the required solution.
Particle 1 carrying -4.0 μC of charge is fixed at the origin of an xy coordinate system, particle 2 carrying +8.0 μC of charge is located on the x axis at x = 4.0 m , and particle 3, identical to particle 2, is located on the x axis at x = -4.0 m . What is the vector sum of the electric forces exerted on particle 3? Determine the x and y components of the vector sum.
To find the vector sum of the electric forces exerted on particle 3, calculate the electric forces exerted by particle 1 and particle 2 and add them as vectors. Use Coulomb's law to find the electric forces. Add the x and y components of the forces to get the vector sum.
Explanation:To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric forces exerted on particle 3 by particle 1 and particle 2 and then add them together as vectors. The electric force exerted on particle 3 by particle 1 can be found using Coulomb's law, which states that electric force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Calculate the electric force exerted on particle 3 by particle 1 using Coulomb's law: F1 = (k * q1 * q3) / r13^2Next, calculate the electric force exerted on particle 3 by particle 2 using Coulomb's law: F2 = (k * q2 * q3) / r23^2Add the x-components and y-components of the electric forces to get the vector sum: Fx = F1x + F2x and Fy = F1y + F2yBy substituting the given values into the equations, you can calculate the x and y components of the vector sum of the electric forces exerted on particle 3.
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Final answer:
To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric force between particle 3 and both particle 1 and particle 2. The electric force between two charges is given by Coulomb's Law. By plugging in the charges and distances, we can calculate the electric forces and find the vector sum.
Explanation:
To find the vector sum of the electric forces exerted on particle 3, we need to calculate the electric force between particle 3 and both particle 1 and particle 2. The electric force between two charges is given by Coulomb's Law:
F = k * (|q1| * |q2|) / r^2
Where F is the electric force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges. Since particle 1 is fixed at the origin, the distance between particle 3 and particle 1 is |-4.0 m| = 4.0 m. Similarly, the distance between particle 3 and particle 2 is |4.0 m - (-4.0 m)| = 8.0 m. Plugging in the values, we can calculate the electric forces between particle 3 and both particle 1 and particle 2.
Let's calculate:
F3-1 = (9 * 10^9 N.m^2/C^2) * (|-4.0 μC| * |8.0 μC|) / (4.0 m)^2
F3-2 = (9 * 10^9 N.m^2/C^2) * (|-4.0 μC| * |8.0 μC|) / (8.0 m)^2
Now, we can find the vector sum of the electric forces by adding the x-components and the y-components of both forces.
Why do most aircraft tire manufacturers recommend that the tubes in newly installed tires be first inflated, fully deflated, and then reinflated to the correct pressure?
Answer:
1. This is to allow the tube of the tire to position itself properly inside the tire.
2. Inflating,deflating and reinflating aircraft tires help to eliminate all the air between the tube and the inside of the tire.
3. It helps to test the entire tube and tire assembly for any leaks.
Explanation:
1. refers to all liquid fresh water located above ground.
2. Precipitation that infiltrates Earth's surface and percolates downward becomes .
3. A is a large body of water that has extensive areas of open water, some of which is too deep for photosynthetic life.
4. A meanders across land and structures the landscape.
5. A is the entire land area that supplies a river or stream with water from precipitation.
6. A has water-saturated soil, shallow standing water, and ample vegetation.
Answer:
1- Surface water
2- Groundwater
3- Lake
4- River
5- Watershed/Catchment basin
6- Wetland
Explanation:
Surface water refers to all the water bodies that are present on the surface of the earth. This includes rivers, streams, ponds, lakes. Groundwater refers to the subsurface flow of water. When precipitation occurs, the water percolates downward through the rocks in the region where the rocks are porous and permeable, and this water then becomes groundwater. A lake is usually defined as a large water body that is comprised of nutrient minerals and has extensive areas of open water. The depth of the lakes from one place to another and some are so deep that sunlight cannot penetrate into the deeper zone and the plants cannot carry out the process of photosynthesis. A river is defined as a water body that flows from a region of higher elevation to the region of lower elevation and it flows across the land surface and configures the landscape. Catchment basin is usually defined as a large area in which the precipitation occurs and the waters are accumulated and flow downward and mix up with the river channel and streams. Wetlands are usually defined as an ecosystem that is comprised of shallow standing water, and a sufficient amount of vegetation.The questions are defining concepts involved in the study of Geography, specifically hydrology. These concepts include surface water, groundwater, a lake, a river, a watershed, and a wetland.
Explanation:The series of questions relates to the nature and characteristics of different water bodies and water-related geographical phenomena.
1. Surface water refers to all liquid fresh water located above ground.
2. Precipitation that infiltrates Earth's surface and percolates downward becomes groundwater.
3. A lake is a large body of water that has extensive areas of open water, some of which is too deep for photosynthetic life.
4. A river meanders across land and structures the landscape.
5. A watershed is the entire land area that supplies a river or stream with water from precipitation.
6. A wetland has water-saturated soil, shallow standing water, and ample vegetation.
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What is the estimated fraction of total energy used in the production and manufacturing of materials by the manufacturing industry in the United States?
Answer: 1/2
Explanation:
The total energy consumption in the United States of America has been estimated to be about 101.3quadrillion Btu( British thermal unit). The United States of America uses a mix energy source for energy Production which includes PRIMARY, SECONDARY, RENEWABLE,FOSSIL FUELS.
Five basic energy consumption sectors have been categorized in the United States,which includes ELECTRIC POWER, INDUSTRIAL, COMMERCIAL, RESIDENTIAL AND TRANSPORTATION. Of the estimated 101.3(quads) about 1/2 of 101.3(quads) are used for the production and manufacturing of materials by the manufacturing industry.
Sound travels at a speed of about 344 m/s in air. You see a distant flash of lighting and hear the thunder arrive 7.6 seconds later. How many miles away was the lighting strike? (assume the light takes essentially no time to reach you.)
Express your answer to two significant figures and include the appropriate units.
Answer:
0.056 miles away
Explanation:
From sound wave,
v = 2x/t .................................. Equation 1
Where v = velocity of sound in air, x = distance of echo, t = time.
making x the subject of the equation,
x = 2v/t........................... Equation 2.
Given: v = 344 m/s, t = 7.6 s.
Substituting into equation 2
x = 2(344)/7.6
x = 90.53 m.
x = 90.53/1609.344
x = 0.056 mile.
Thus the lighting strike 0.056 miles away
"determine the resultant internal loadings acting at the cross sections at points f and g of the frame. set θ = 27º and t = 178 lb."
Hi you didn't provide any images to solve the question, hence I am going to solve a different question of same concept so you can have an idea how to tackle such types of questions.(please refer to the attachment for question)
Answer:
Please refer to the attachment for answers and explanation
Explanation:
Please refer to the attachment for answers and explanation
To determine the resultant internal loadings at the cross sections, we need to consider the external and internal forces. Trigonometric principles can be used to calculate the magnitudes and directions of the loadings. More information about the frame is needed for a precise analysis.
In order to determine the resultant internal loadings acting at the cross sections at points F and G of the frame, we need to consider the external forces applied to the frame, as well as the internal forces generated within the frame due to those external forces. These internal forces include axial forces, shear forces, and bending moments.
Given that θ = 27º and t = 178 lb, we can use trigonometric principles to determine the magnitudes and directions of the internal loadings at points F and G.
For a more specific and accurate analysis, it would be helpful to have more information about the frame, such as its shape, structural elements, and boundary conditions. Without that information, it is not possible to provide a more detailed answer at this time.
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