Using the wave equation, the frequency of the sound wave produced by the guitar string can be calculated by dividing the velocity (10.5 m/s) by the wavelength (0.15 m), resulting in a frequency of 70 Hz.
The student is asking about the frequency of a sound wave produced by a plucked guitar string. To calculate this, we can use the basic wave equation v = f λ, where v is the velocity of the wave, f is the frequency, and λ is the wavelength. Given the wavelengths of 0.15 m and the velocity of 10.5 m/s, we can rearrange the formula to solve for the frequency (f):
f = v / λ
f = 10.5 m/s / 0.15 m
By calculating this, we find that the frequency of the wave is 70 Hz.
which of the following is not in our solar system
star
black hole
asteroid
comet
Pamela drove her car 999999 kilometers and used 999 liters of fuel. she wants to know how many kilometers (k)(k)left parenthesis, k, right parenthesis she can drive with 121212 liters of fuel. she assumes the relationship between kilometers and fuel is proportional. answer
Pamela can drive 121,333,212 kilometers with 121212 liters of fuel, given her car's fuel efficiency is 1001 kilometers per liter.
Pamela drove her car 999999 kilometers using 999 liters of fuel. She wants to know how many kilometers (k) she can drive with 121212 liters of fuel, assuming the relationship between kilometers and fuel is proportional.
To find the number of kilometers she can drive with 121212 liters of fuel, we first need to determine her car's fuel efficiency, which is:
Fuel Efficiency (km per liter) = 999999 km / 999 liters = 1001 km per liter
Next, we use this fuel efficiency to calculate the distance she can drive with 121212 liters of fuel:
Distance (k) = Fuel Efficiency × Amount of Fuel
Distance (k) = 1001 km per liter × 121212 liters = 121333212 kilometers
Therefore, Pamela can drive 121,333,212 kilometers with 121212 liters of fuel.
What happens to an electric current when it flows through an object with resistance?
How do free-body force diagrams help you determine an object’s direction of motion?
Estimate how long it would take one person to mow a football field using an ordinary home lawn mower. state your assumptions, such as the mower moves with a 1 km/hr speed, and has a 0.5 m width.
Ans: 8 hours and 90 minutes
The length of Football field = 300ft by 160 ft.
On converting it into meter, we get length of field = 91.44 m
and the width of field = 48.8 m
Now, distance = Area moved/ width = (91.44*48.8) / 0.5 = 8924.55 m = 8.9245 km
Ans, Time taken = distance*speed = 8.9245*1 km/hr = 8 hours and 90 minutes
It would take approximately 8.96 hours for one person to mow a football field with a lawn mower that has a 0.5 meter width and moves at a speed of 1 km/hr.
To estimate how long it would take one person to mow a football field using an ordinary home lawn mower, let's look at the size of an American football field and the capacity of a standard lawn mower. An American football field is 100 yards long, not including the end zones. Since 1 yard is approximately 0.9144 meters, the length of the field is about 91.44 meters. The width of a football field is 53.3 yards, which is about 48.77 meters.
Now, considering the mower has a 0.5 meter width and moves with a speed of 1 km/hour, which equals 0.2778 meters/second (since 1 km/h equals 0.2778 m/s), it is referred to when doing calculations for velocity or speed, we need to convert the dimensions and the speed to compatible units.
The area of the football field can be calculated as 91.44 meters in length multiplied by 48.77 meters in width, resulting in approximately 4460.09 square meters. Now, we will find out how many strips of 0.5 meter width are needed to cover the width of the field: 48.77 meters / 0.5 meters = 97.54, which we round up to 98 passes. Since each pass covers a length of 91.44 meters, a single pass would take 91.44 meters / 0.2778 meters/second = 329.25 seconds. Multiplying this by the number of passes gives us the time to mow the entire field: 329.25 seconds/pass × 98 passes = 32,266.5 seconds, or approximately 8.96 hours.
A gas occupies 210 ml at -73°c. to have the same gas occupy 360 ml: should the temperature be increased or decreased? what is the new temperature? k
Answer:
1. Increased
2. 340
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Explanation:
When you encounter a yellow light as you approach an intersection what is the safest approach to take?
Final answer:
When approaching a yellow light at an intersection, the safest approach is to slow down and prepare to stop unless stopping is unsafe or impossible due to proximity. Traffic engineers take into account the 'no-win' zone to minimize the chances of an accident. Speeding up to beat the yellow light increases the risk of accidents and is not recommended.
Explanation:
Safest Approach at a Yellow Light
When you encounter a yellow light at an intersection, the safest and legally correct approach is to prepare to stop if it is safe to do so. A yellow light is a warning that the light will soon turn red. You should only proceed through the intersection if you are already so close to it that stopping would be unsafe or impossible due to the short stopping distance. It is not advisable to speed up to try to ‘beat’ the yellow light, as this can increase the risk of accidents.
Understanding Traffic Engineer Considerations
Traffic engineers design the duration of the yellow light to minimize what is known as the “no-win” zone. This is a position too far from the light to pass through the intersection before the light turns red, and too close to safely stop without entering the intersection. The appropriate “yellow time” is calculated to allow drivers in most situations to either pass through the intersection safely or to stop in time.
Special Circumstances
There can be circumstances where a driver might assess the situation differently, such as the example of driving a pregnant woman to the hospital at 4am with no other cars around. However, legally and typically for safety, the best action is to prepare to stop when you see a yellow light.
Karen is running forward at a speed of 9 m/s. She tosses her sweaty headband backward at a speed of 20 m/s. The speed of the headband, to the nearest whole number relative to a stationary observer watching Karen, is _____ m/s
Answer:
-11 m/s
Explanation:
a lot simpler than that above me
What type of electromagnetic radiation is used in communications devices such as cellular telephones?
You turn on a light and observe cockroaches scurrying to dark hiding places. wha have you observed?
The fastest way to reach maximum braking capability with, or without, abs is:
The fastest way to reach maximum braking capability, whether with or without ABS, is to firmly and rapidly apply the brakes. If the car has an ABS, the system would automatically prevent the wheels from locking up, but without it, the driver should manually pump the brakes.
Explanation:The fastest way to reach maximum braking capability, whether your vehicle contains the Anti-lock Braking System (ABS) or not, is to blast the brakes. This method is about firmly and rapidly applying the brake pedal. With ABS, the system takes over and prevents the wheels from locking up, while without ABS, the driver should pump the brakes to avoid wheel lock up. However, keep in mind that in both cases, keep your steering wheel steady and do not turn it abruptly.
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The fastest way to reach maximum braking capability is to apply the brakes as hard as possible without locking up the wheels, either manually or with ABS.
Explanation:The fastest way to reach maximum braking capability with or without ABS is to apply the brakes as hard as possible without locking up the wheels. This creates the maximum friction between the tires and the road, allowing the vehicle to decelerate quickly.
With ABS (Anti-lock Braking System), the braking system automatically modulates the brake pressure to prevent wheel lock-up, ensuring that the tires remain in contact with the road and maximizing braking efficiency.
Without ABS, the driver needs to manually pump the brakes to prevent wheel lock-up. This allows the tires to maintain traction and achieve maximum braking capability.
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Calculate the kinetic energy (in units of kj and ft-lbf) for a 908 kg automobile traveling at 89 km/hour
Kinetic
energy is the energy that is possessed by an object that is moving. It is
calculated by one-half the product of the mass and the square of the velocity
of the object. We calculate as follows:
KE = mv^2 / 2
KE = 908 kg (89 km/hr ( 1000 m / 1 km) ( 1 hr / 3600 s ))^2 / 2
KE =
277479.48 J or 204658.05 ft-lbf
Which of the following statements is an accurate description of vibrations? A. Ultrasonic vibrations have a frequency lower than the range for normal hearing. B. Infrasonic vibrations are used in sonar equipment as well as to detect flaws in steel castings. C. The frequency of infrasonic vibrations is much too high to be heard by humans. D. Neither ultrasonic nor infrasonic vibrations can be heard by humans.
D: Neither ultrasonic nor infrasonic vibrations can be heard by humans.
Answer
D. Neither ultrasonic nor infrasonic vibrations can be heard by humans.
Explanation
Human hearing is somehow limited. Frequencies below 20 Hz cannot be heard by human and sounds of frequencies above 20,000 Hz too. The sounds of frequency below 20 Hz are known as the infrasonic sounds. Those above 20,000 Hz are called Ultrasonic sounds.
How long does it take anya to cover the distance of 5.00 miles ?
To determine the time it takes to cover 5.00 miles at 9.5 mi/h, you can use the formula Time = Distance / Speed, giving approximately 31.58 minutes.
Explanation:To calculate how long it takes Anya to cover the distance of 5.00 miles, given the speed of a runner, we can use the formula:
Time = Distance / Speed
If a marathon runner averages 9.5 mi/h, we would substitute the values into the formula to find the time:
Time = 5.00 miles / 9.5 mi/h
Time = 0.5263 hours
To convert the time from hours to minutes, we multiply by 60 minutes per hour:
Time = 0.5263 hours × 60 minutes/hour
Time = 31.58 minutes
Therefore, it would take approximately 31.58 minutes for Anya to cover a distance of 5.00 miles at a speed of 9.5 mi/h.
Type the correct answer in the box. Round your answer to the nearest whole number. The mass of Venus is 4.87 × 1024 kilograms, and the mass of Jupiter is 1,898 × 1024 kilograms. The mass of Jupiter is about times the mass of Venus.
The gravitational effect on other bodies determines the weight (or the mass) of a planet. We must somehow measure the strength of its "tug" on another object in order to use gravity to find the mass of a planet. We can harness Newton's equations to deduce what the mass of the planet must be through observing the time it takes for the satellite to orbit its primary planet.
Given:
Mass of Venus = 4.87 x 1024 kg
= 4986.88
Mass of Jupiter = 1.898 x 1024 kg
= 1943.552
Mass of Jupiter compared to mass of Venus
1943.552 / 4986.88
= 0.3897330595482546
= 0.3897330595482546 x 100%
= 38.97%
So, in this problem, the mass of Jupiter is about 0.39 times the mass of Venus.
You are standing 10 meters from a light source. then, you back away from the light source until you are 20 meters away from it. from your perspective, what has happened to the intensity of the wave?
It has decreased by a factor of four
The intensity of the wave has increased by a factor of four.
What is the intensity of light?The amount of visible light emitted per unit solid angle in time. Lumens are the measurements of how much light is emitted from a source in a given second (also known as luminous power or luminous flux). The luminosity is assessed in relation to visual perception.
The inverse Square Law of Light states that light intensity falls off rapidly with distance from its source. The intensity varies with the square of the flash-to-subject distance.
( Intensity at distance 1 ) / ( Intensity at distance 2 )
= ( Distance₂²/ Distance₁² )
In our case, Distance₁=10m and Distance₂=20m, which means that the intensity of the wave has increased by a factor of four. The ratio will be calculated as:-
20²/10²= 400/100=4,
Therefore, the intensity of the wave has increased by a factor of four.
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Are you ready for a brain twister? murphy can row at 5 kmph in still water. if the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
Which distance can be most accurately measured with a ruler?
a. the size of an object under a microscope
b. the width of a book
c. the length of a river
d. the distance between two cities?
The answer is a width of a textbook. It is usually has centimeter and millimeter units on it. Since rulers are most commonly 15 or 30 cm long, it could only be used to measure the length or width of small things like small tin, or the length of a piece of paper. A length of a river and the distance between two cities cannot be measured by a ruler, there is proper equipment for that, the same goes for the size of an object under the microscope.
An fm radio station broadcasts electromagnetic radiation at a frequency of 101.7 mhz. the wavelength of this radiation is ________ m.
The force of gravity acting on a child's mass on earth is 490 newtons. What's the child's mass?
The seatbelt across your chest should have about ________ fist width of slack.
Refraction of sound waves often takes place when:
A. there are temperature differences in air
B. there are walls around a room to bounce back sound
C. sound wave frequencies are increased
D. complete sound waves slow down
Refraction of sound waves occurs when there are temperature differences in the air, causing the sound waves to change direction due to changes in speed.
Explanation:Refraction of sound waves often takes place when there are temperature differences in the air. This is option A of the student's question. The phenomenon of refraction in sound occurs when sound waves travel from one medium to another medium with a difference in temperature. This causes a change in the speed of sound wave, leading to a change in direction, or refraction. For instance, during a hot day, the air near the ground is hotter than the air above. Here, the speed of sound is faster closer to the ground, causing the sound waves to bend upwards.
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A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest whole number.
Answer:
220
Explanation:e2020
In general, what is true of the alpha star in a constellation?
Final answer:
The alpha star in a constellation is generally the brightest within that constellation, as designated by the Bayer system, using Greek letters such as Alpha Centauri or Alpha Orionis for Betelgeuse.
Explanation:
The alpha star in a constellation is named using a system introduced by Johann Bayer in 1603, which designates stars with Greek letters according to their brightness within that constellation. The alpha star is typically the brightest star in its constellation. For example, Alpha Centauri is the brightest star in the Centaurus constellation, visible from south of the equator. Similarly, Alpha Orionis, or Betelgeuse, is the brightest star in the Orion constellation. Stars like Sirius, Vega, and Altair also fall under this naming system. Apparent brightness is subject to change over long periods due to stars' space velocity, making certain stars more prominent in our skies at different times.
The designation of stars within a constellation also serves astronomy and celestial navigation, highlighting important features of the celestial sphere. Not all stars within the vicinity of the Sun are equally visible or as bright, with only a few within 26 light-years appearing among the brightest in our sky. The alpha designation helps us identify and catalogue these celestial bodies systematically.
When calculating power what two pieces of information are needed?
A. Watts and Time
B. Distance and Mass
C. Work and Mass
D. Work and Time
A movie stunt driver on a motorcycle speeds horizontally off a 50.0 m high cliff. how fast must the motorcycle leave the cliff-top if it is to land on level ground below, 90.0 m from the base of the cliff where the cameras are
Answer:
The Horizontal component of initial velocity (V0x) must be 28.18 m/s.
Explanation:
Vertical distance = y = 50m
Horizontal distance = x = 90 m
We know that,
x = x0 + V0xt
where,
x0 = Initial distance in horizontal direction = 0
V0x = x/t = 90/t ……… (i)
As,
y = y0 + V0y + ½ gt^2
where,
y0 = Initial distance in vertical direction = 0
V0y = Vertical component of initial velocity = 0
So,
t = √(50)(2)/(9.8)
t = 3.194 s
Put t = 3.194 s in equation (i),
V0x = 90/3.194
V0x = 28.18 m/s
Where did your energy come from? What types of energy conversions took place that allowed you to complete the laboratory activity? Describe the three steps energy diagram on the examples tab of energy conversions section of the why page. This is for the rube goldberg device. plzzzzz help
The volume of a gas with a pressure of 1.2 atm increases from 1.0 l to 4.0 l. what is the final pressure of the gas, assuming constant temperature? tip: use boyle's law
Answer:
Final pressure of he gas is 0.3 atm.
Explanation:
It is given that,
Initial pressure of the gas, P₁ = 1.2 atm
Initial volume of the gas, V₁ = 1 L
Final volume of the gas, V₂ = 4 L
We need to find the final pressure of the gas. It can be calculated using Boyle's law as :
[tex]P_1V_1=P_2V_2[/tex]
[tex]P_2=\dfrac{P_1V_1}{V_2}[/tex]
[tex]P_2=\dfrac{1.2\ atm\times 1\ L}{4\ L}[/tex]
[tex]P_2=0.3\ atm[/tex]
So, the final pressure of the gas at constant temperature is 0.3 atm. Hence, this is the required solution.
How many hours are required to make a 4400-km trip across the united states if you average 80 km/h?
time = distance/speed
Final answer:
The time required to make a 4400-km trip across the United States, averaging 80 km/h, is 55 hours.
Explanation:
To calculate the time required for a trip, the formula you use is time (t) equals the distance (d) divided by the average speed (v), often expressed as t = d / v. In this case, the distance of the trip is 4400 kilometers, and the average speed is 80 kilometers per hour (km/h). Therefore, the time required for the trip is calculated as follows:
Distance (d) = 4400 km
Average speed (v) = 80 km/h
Time (t) = Distance ÷ Average speed
Time (t) = 4400 km ÷ 80 km/h
Time (t) = 55 hours
The trip would take 55 hours if you average 80 km/h.
If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sample change?