Answer:
6 cups of whole milk is used for every teaspoon of salt.
Step-by-step explanation:
Given:
A recipe for ricotta cheese calls for 3/4 cup of whole milk for every 1/8 teaspoon of salt.
Now, to find the cup of whole milk should be used for every teaspoon of salt.
So, to get the cup of whole milk used we use unitary method:
For every 1/8 teaspoon of salt cup of whole milk used = 3/4 cup.
Thus for every teaspoon of salt cup of whole milk used = 3/4 ÷ 1/8.
[tex]=\frac{3}{4}\times \frac{8}{1}[/tex] (changing the division to multiplication the fraction reciprocals.)
[tex]=\frac{24}{4}[/tex]
[tex]=6\ cups.[/tex]
Therefore, 6 cups of whole milk is used for every teaspoon of salt.
What is the solution to the system of equations?
y=5x+2
3x=-y + 10
(-4,-18)
(-18,-4)
(7,1)
(1,7)
Answer:
Y = 5x + 2 . . . . . . . . . . (1)
3x = -y + 10 . . . . . . . . (2)
3x = -(5x + 2) + 10
3x = -5x - 2 + 10
3x + 5x = -2 + 10
8x = 8
x = 1
y = 5(1) + 2 = 5 + 2 = 7
Solution is (1, 7)
Step-by-step explanation:
The Solution is (1,7) is the solution to the system of equations:
y=5x+2, 3x=-y + 10
What is simplification?Simplify simply means to make it simple. In mathematics, simply or simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.
here, we have,
given that,
We need to find the solution of the system of following equations.
y= 5x + 2 eq(1)
3x = -y +10 eq(2)
We will solve the equations using Substitution method to find the values of x and y
we put value of y from eq (1) into eq (2), The eq(2) will be:
3x = - (5x + 2) + 10
3x = -5x -2 +10
3x+5x = -2+10
8x = 8
x= 1
Now, putting value of z in eq(1) to find value of y
y = 5x +2
y = 5(1) + 2
y = 5+2
y = 7
So, Solution is (1,7).
Hence, The Solution is (1,7) is the solution to the system of equations:
y=5x+2, 3x=-y + 10
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4. An investment account pays 4.6%
annual interest compounded quarterly.
If $6050 is placed in this account, find
the balance after 6 years.
A. $6810.53
B. $7420.65
C. $7960.43
D. $8134.22
Answer:
Step-by-step explanation:
Use the formula
[tex]A(t)=P(1+\frac{r}{n})^{(n)(t)}[/tex]
where A(t) is the amount after all the compounding is done, P is the initial investment, r is the interest rate as a decimal, n is the number of times the investment is compounded each year, and t is time in years. For us,
P = 6050
r = .046
n = 4
t = 6
A(t) = ?
Filling in our given info:
[tex]A(t)=6050(1+\frac{.046}{4})^{(4)(6)}[/tex]
which simplifies to
[tex]A(t)=6050(1+.0115)^{24}[/tex]
which simplifies a bit more to
[tex]A(t)=6050(1.0115)^{24}[/tex] and
A(t) = 6050(1.31577397) so
A(t) = $7960.43
which is choice C
Final answer:
The balance after 6 years is $6810.53 that is option A is correct.
Explanation:
To find the balance after 6 years, we can use the formula for compound interest: A = P(1 + r/n)^(nt).
Given that the initial principal (P) is $6050, the interest rate (r) is 4.6% (or 0.046 in decimal form), and it is compounded quarterly (n=4 times per year), we can plug in the values and solve for A.
A = $6050(1 + 0.046/4)^(4*6) = $6810.53
Therefore, the balance after 6 years is $6810.53, which corresponds to answer choice A.
A checkbook register has a balance of $158 if a deposit of $35 is made and a check for $78.96 is written find the new balance
Final answer:
The new balance in the checkbook register is $114.04.
Explanation:
To find the new balance in a checkbook register after a deposit and a check are processed, you need to add the deposit to the current balance and then subtract the amount of the check.
Initially, the checkbook register has a balance of $158.
A deposit of $35 is made, and a check for $78.96 is written.
Calculating the new balance involves the following steps:
Add the deposit of $35 to the initial balance of $158 to get $193. Subtract the amount of the check, $78.96, from the $193 to find the new balance.After completing these steps, the new balance in the register would be $193 - $78.96 = $114.04.
Balancing your checkbook regularly is essential to manage your money efficiently and to avoid fees associated with overdrafts or insufficient funds.
. (06.02) Which of these is the algebraic expression for "seven less than some number?" (3 points) Fraction 7 over h Fraction h over 7 h − 7 7 − h
Answer: H-7
Step-by-step explanation: I got it right on test! have a great day! :)
How many times will interest be added to the principal in one year if the
interest is compounded annually?
Answer:
Only 1 time
Step-by-step explanation:
When it is compound interest it can be added in the following ways:
Annually = 1 Time in a year
Semiannually = 2 Times in a year
Quarterly = 4 Times in a year
Monthly = 12 Times in a year
Answer:
2
Step-by-step explanation:
a.p.e.x
Solve the system of linear equations by graphing. y−x=17 y=4x+2
Answer:
x=5, y=22. (5, 22).
Step-by-step explanation:
y-x=17
y=4x+2
----------
4x+2-x=17
3x+2=17
3x=17-2
3x=15
x=15/3
x=5
y-5=17
y=17+5
y=22
Answer:
x = 5, y = 22 → (5, 22)Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}y-x=17&(1)\\y=4x+2&(2)\end{array}\right\\\\\\\text{substitute (2) to (1):}\\\\(4x+2)-x=17\qquad\text{combine like terms}\\\\(4x-x)+2=17\qquad\text{subtract 2 from both isdes}\\\\3x+2-2=17-2\\\\3x=15\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}=\dfrac{15}{3}\\\\x=5[/tex]
[tex]\text{Put the value of x to (2):}\\\\y=4(5)+2\\\\y=20+2\\\\y=22[/tex]
Find the volume and area for the objects shown and answer Question
Step-by-step explanation:
You must write formulas regarding the volume and surface area of the given solids.
[tex]\bold{\#1\ Rectangular\ prism:}\\\\V=lwh\\SA=2lw+2lh+2wh=2(lw+lh+wh)\\\\\bold{\#2\ Cylinder:}\\\\V=\pi r^2h\\SA=2\pi r^2+2\pi rh=2\pir(r+h)\\\\\bold{\#3\ Sphere:}\\\\V=\dfrac{4}{3}\pi r^3\\SA=4\pi r^2[/tex]
[tex]\bold{\#4\ Cone:}\\\\V=\dfrac{1}{3}\pi r^2h\\\\\text{we need calculate the length of a slant length}\ l\\\text{use the Pythagorean theorem:}\\\\l^2=r^2+h^2\to l=\sqrt{r^2+h^2}\\\\SA=\pi r^2+\pi rl=\pi r^2+\pi r\sqrt{r^2+h^2}=\pi r(r+\sqrt{r^2+h^2})\\\\\bold{\#5\ Rectangular\ Pyramid:}\\\\V=\dfrac{1}{3}lwh\\\\[/tex]
[tex]\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}[/tex]
[tex]\\\\h_2^2=\left(\dfrac{w}{2}\right)^2+h^2\to h_2=\sqrt{\left(\dfrac{w}{2}\right)^2+h^2}=\sqrt{\dfrac{w^2}{4}+h^2}=\sqrt{\dfrac{w^2}{4}+\dfrac{4h^2}{4}}\\\\h_2=\sqrt{\dfrac{w^2+4h^2}{4}}=\dfrac{\sqrt{w^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{w^2+4h^2}}{2}[/tex]
[tex]SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}[/tex]
PLEASE PLEASE HELP ME PLEASE
Which radical expressions are equivalent to
Answer:
D and E
Step-by-step explanation:
Using the rule of radicals
[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex]
Given
[tex]3^{\frac{4}{7} }[/tex]
= ([tex]\sqrt[7]{3}[/tex])^4 → D or
= [tex]\sqrt[7]{3^{4} }[/tex] = [tex]\sqrt[7]{81}[/tex] → E
You are given g(x)=4x^2 + 2x and
f(x) = the integral of g(t) from 0 to x.
How would you find f(6)?
Answer:
324
Step-by-step explanation:
Given:
[tex]g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt[/tex]
Find:
[tex]f(6)[/tex]
First, find f(x):
[tex]f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2[/tex]
Now,
[tex]f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324[/tex]
The sum of a number and -9 is -36. What is the number?
Solve for x in this equation.
x+(-9)=-36
x-9=-36
x=-27
answer: -27
What’s the surface area of the right cone below? 8;15
Answer:
Circle the 15 in the diagram, that's the correct answer
Answer:
184π units²
Step-by-step explanation:
see attached for reference
given sloped height = 15 units
base radius = 8 units
the height of the cone can be found by using the Pythagorean equation
(sloped height)² = height ² + (base radius)²
15² = h² + 8²
h² = 15²-8² = 161
h = √161
Base surface area = πr² = π 8² = 64π units²
Lateral Surface Area,
= πr √(r² + h²)
= π(8) √[ (8)² + (√161)² ]
= 8π√(64 + 161)
= 8π√225
= 8π (15)
= 120π
Surface area = base area + lateral surface area
= 64π + 120π
= 184π units²
What is the product?
(-20+5) (58-65)
10 -1004+17025-652
0-1004+ 170452-652
0-1004–7025-652
0-1004 +17025+652
The solution to the given equation (-20+5) (58-65) is 105. This is calculated by first simplifying the expressions within the brackets and then multiplying the resulting numbers.
Explanation:The student's question relates to the calculations and simplifying of expressions in mathematics. This type of operation can be found in basic algebra, and its mastery is an essential part of succeeding in mathematics.
To solve the equation given, which is (-20+5) (58-65), we'll need to separate it into two steps. First, simplify the expressions in the brackets. Therefore, -20+5 equals -15 and 58-65 equals -7. Now, substitute these values back into the equation getting -15 * -7. Multiplying these two values will give a product of 105. That is the final answer. The provided list of numbers following the initial problem statement seems to be irrelevant to this specific calculation.
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Find the altitude of a triangle whose area is 100 cm² and whose base is 20 cm.
Altitude = Cm.
Answer:
altitude = 10 cm
Step-by-step explanation:
Finding the altitude of triangle when area and base is given:
[tex]\sf \boxed{\text{\bf Area of triangle = $\dfrac{1}{2}*base*altitude$}}[/tex]
base = 20 cm
Area of a triangle = 100 sq.cm
[tex]\sf \dfrac{1}{2}*20*altitude = 100\\\\\\[/tex]
10 * altitude = 100
altitude = 100 ÷ 10
altitude = 10 cm
what is 750x+150<1,000
Answer:
1.13 repeated
Step-by-step explanation:
Answer:
1 and 100 over 750
Step-by-step explanation:
38. Emily is buying some graduation pictures. She pays $25 for the sitting and $15 for each
sheet of pictures she buys. (make a table if it helps)
a. How much does she pay for 5 sheets of pictures?!
b. How much does she pay for "x" sheets?
c. How many sheets can she buy for $145?
a. She pays $100 for 5 sheets
b. 25+15x dollars for x sheets
c. 8 sheets
Step-by-step explanation:
Given
Sitting cost = $25
Per sheet picture cost = $15
Let p be the number of sheets of pictures
Then the cost can be written as a function of p
[tex]c(p) = 25+15p[/tex]
Now,
a. How much does she pay for 5 sheets of pictures?!
Putting p = 5 in the function
[tex]c(5) = 25 + 15(5)\\= 25+75\\=100[/tex]
She will pay $100 for 5 sheets of pictures
b. How much does she pay for "x" sheets?
Putting x in place of p
[tex]c(x) = 25+15x[/tex]
c. How many sheets can she buy for $145?
We know the cost now, we have to find p so,
[tex]145 = 25+15p\\145-25 = 25+15p-25\\120 = 15p[/tex]
Dividing both sides by 15
[tex]\frac{15p}{15} = \frac{120}{15}\\p = 8[/tex]
Hence,
She can buy 8 sheets for $145
Keywords: Linear equation, Algebraic functions
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Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenuse is 12 cm,find the area common to the both triangles.
The area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.
In a 30-60-90 triangle, the ratio of the side lengths is [tex]1:\sqrt{3} :2[/tex]. Since the hypotenuse is 12 cm, we can determine the lengths of the other sides using this ratio.
The shorter leg (opposite the 30-degree angle) is (1/2) times the hypotenuse, which is (1/2) * 12 cm = 6 cm.
The longer leg (opposite the 60-degree angle) is [tex]\sqrt3[/tex] times the shorter leg, which is 6 * [tex]\sqrt{3[/tex] cm = [tex]6\sqrt3[/tex] cm.
Now, since the two triangles are congruent, the overlapping region forms an isosceles triangle with two sides measuring 6 cm (the shorter leg) and a base measuring [tex]6\sqrt3[/tex] cm (the longer leg).
The base of the isosceles triangle is [tex]6\sqrt3[/tex] cm, and since it's an isosceles triangle, the height is the same as the shorter leg, which is 6 cm.
Common Area = ([tex]6\sqrt3[/tex] cm * 6 cm) / 2 = [tex]36\sqrt3[/tex] cm² / 2 = [tex]18\sqrt3[/tex] cm².
Therefore, the area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.
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The area common to both triangles is 144 square centimeters.
To find the area common to both triangles, we need to determine the overlapping region, which is a rhombus formed by the intersection of the two 30-60-90 triangles.
First, let's consider one of the 30-60-90 triangles. The sides of a 30-60-90 triangle are in the ratio 1:√3:2. In this case, the hypotenuse is 12 cm, so the sides of the triangle are:
Shorter leg (opposite the 30-degree angle) = 12 cm / 2 = 6 cm
Longer leg (opposite the 60-degree angle) = 6 cm * √3
Now, let's look at the overlapping region, which forms a rhombus. The diagonals of a rhombus are perpendicular bisectors of each other, so each diagonal will be twice the length of the shorter leg of the 30-60-90 triangle.
Diagonal of the rhombus = 2 * 6 cm = 12 cm
The area of a rhombus can be calculated using the formula: Area = (diagonal1 * diagonal2) / 2
In this case, both diagonals are equal (12 cm each), so the area of the rhombus (and hence the common area of the triangles) is:
Area = (12 cm * 12 cm) / 2
Area = 144 cm²
So, the area common to both triangles is 144 square centimeters.
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arrange the cones in order from lease volume to greatest volume
cone with DIAMETER of 20 & height of 12
cone with DIAMETER of 18 & height of 10
cone with RADIUS of 10 & height of 9
cone with RADIUS of 11 & height of 9
Answer:
Volume of the cone in ascending order.
[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]
cone with DIAMETER of 18 & height of 10
cone with RADIUS of 10 & height of 9
cone with RADIUS of 11 & height of 9
cone with DIAMETER of 20 & height of 12
Step-by-step explanation:
Let [tex]V_{2}. V_{3}. and\ V_{4}.[/tex] be the volume of the cone.
Let d, r and h be the diameter, radius and height of the cone.
Given:
[tex]d_{1} = 20\ and\ h_{1}=12[/tex]
[tex]d_{2} = 18\ and\ h_{2}=10[/tex]
[tex]r_{3} = 10\ and\ h_{3}=9[/tex]
[tex]r_{4} = 11\ and\ h_{14}=9[/tex]
Arrange the cones in order from lease volume to greatest volume.
Solution:
The volume of the cone is given below.
[tex]V=\pi r^{2} \frac{h}{3}[/tex]----------------(1)
where: r is radius of the base of cone.
and h is height of the cone.
The volume of the cone for [tex]d_{1} = 20\ and\ h_{1}=12[/tex]
[tex]r_{1} = \frac{d_{1}}{2}[/tex]
[tex]r_{1} = \frac{20}{2}=10\ units[/tex]
[tex]V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}[/tex]
[tex]V_{1}=\pi (10)^{2} \frac{12}{3}[/tex]
[tex]V_{1}=\pi\times 100\times 4[/tex]
[tex]V_{1}=400\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]d_{2} = 18\ and\ h_{2}=10[/tex]
[tex]r_{2} = \frac{d_{2}}{2}[/tex]
[tex]r_{2} = \frac{18}{2}=9\ units[/tex]
[tex]V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}[/tex]
[tex]V_{2}=\pi (9)^{2} \frac{10}{3}[/tex]
[tex]V_{2}=\pi\times 81\times \frac{10}{3}[/tex]
[tex]V_{2}=\pi\times 27\times 10[/tex]
[tex]V_{2}=270\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]r_{3} = 10\ and\ h_{3}=9[/tex]
[tex]V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}[/tex]
[tex]V_{3}=\pi (10)^{2} \frac{9}{3}[/tex]
[tex]V_{3}=\pi\times 100\times 3[/tex]
[tex]V_{3}=\pi\times 300[/tex]
[tex]V_{3}=300\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]r_{4} = 11\ and\ h_{4}=9[/tex]
[tex]V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}[/tex]
[tex]V_{4}=\pi (11)^{2} \frac{9}{3}[/tex]
[tex]V_{4}=\pi\times 121\times 3[/tex]
[tex]V_{4}=\pi\times 363[/tex]
[tex]V_{4}=363\pi\ units^{3}[/tex]
So, the volume of the cone in ascending order.
[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]
68. Solve: 46x - 10) = 8x + 40
A 0
B.5/2
ina
c. 23
D. 5
Solve: 4(6x - 10) = 8x + 40
A 0
B.5/2
c. 23
D. 5
Answer:Option D
The solution to given equation is x = 5
Solution:Given that we have to solve the given equation
4(6x - 10) = 8x + 40
Let us solve the above expression and find value of "x"
Multiplying 4 with terms inside bracket in L.H.S we get,
24x - 40 = 8x + 40
Move the variables to one side and constant terms to other side
24x - 8x = 40 + 40
Combine the like terms,
16x = 80
[tex]x = \frac{80}{16} = 5[/tex]
Thus solution to given equation is x = 5
Is (6,2) a solution to x+5y<16 x<8
Answer:
The ordered pair is not a solution of the system of inequalities
Step-by-step explanation:
we know that
If a ordered pair is a solution of a system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
we have the system
[tex]x+5y < 16[/tex] ----> inequality A
[tex]x< 8[/tex] ----> inequality B
substitute the value of x and the value of y of the ordered pair in each inequality
ordered pair (6,2)
Verify inequality A
For x=6, y=2
[tex]6+5(2) < 16[/tex]
[tex]16 < 16[/tex] ----> is not true
so
The ordered pair not satisfy the inequality A
therefore
The ordered pair is not a solution of the system of inequalities
what is the sum of 1/2 and 0.75 ?
Answer:
The answer should be C. 1 1/4
Step-by-step explanation:
Eliminate A and B because none of them work
Eliminate E because we are using 1/4s
Eliminate D because we aren't using decimals
You can also think of a clock with adding 1/4s: 0.75 + 1/4= 1
1 + 1/4 = 1 1/4
(you can divide 1/2 into 2 one fourths)
The answer is 1 1/4 option C.
What is the sum of 1/2 and 0.75?
Simply add these two terms i.e:
1/2 + 0.75
Write 0.75 as a 75/100 and take lcm and lcm is 100.
1/2 + 75/100
On solving we get,
= ( 50 + 75 )/100
= 125/100
= 5/4
= 1 1/4
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How does 6 x 3/4 compared to 6
Answer:
6*(3/4) is 75% of 6.
Step-by-step explanation:
3/4 =0.75
Consider this:
6*1 =6, so 1=100%.
6*1/2 =6*0.5=3, so 1/2=50%.
You can then see that 6*0.75=4.5 is 75% of 6.
The regular price of a dress is $80. The price has been marked up by 23%. What is the amount of mark up?
Answer:
Step-by-step explanation:
the amount of mark up = 23% of 80
= [tex]\frac{23*80}{100}[/tex]
= 23 * 0.8 = $18.4
Aaron operates a farm stand. The supply function for grapes at the farm stand is P=Q-7, Where P is the price and Q is the quantity of baskets. If Aaron makes 15 baskets of grapes, what price will he sell the baskets of grapes at?
A. $5
B. $7
C. $15
D. $8
Answer:
Step-by-step explanation:
P = Q - 7.......Q is the quantity of baskets....and he makes 15 baskets....so sub in 15 for Q and solve for P, the price
P = 15 - 7
P = 8 <====
Answer:
D.$8
Step-by-step explanation:
Firstly, you replace Q with 15. Then you solve the equation.
P=15-7
P=8
The Green Goober, a wildly unpopular superhero, mixes 333 liters of yellow paint with 555 liters of blue paint to make 888 liters of special green paint for his costume.
Write an equation that relates y, the amount of yellow paint in liters, and b, the amount of blue paint in liters, needed to make the Green Goober's special green paint.
PLEASE ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!
The equation that relates y, the amount of yellow paint in liters, and b, the amount of blue paint in liters, needed to make the Green Goober's special green paint is y + b = 888
Solution:
Given that the Green Goober mixes 333 liters of yellow paint with 555 liters of blue paint to make 888 liters of special green paint for his costume.
Let "y" be the amount of yellow paint in liters needed to make the Green Goober's special green paint
Let "b" be the amount of blue paint in liters needed to make the Green Goober's special green paint
The required equation is:
amount of yellow paint in liters + amount of blue paint in liters = Green Goober's special green paint
y + b = 888
Where y = 333 liters and b = 555 liters ( from given information)
Thus the equation is found
Answer:
y=3/5b
Step-by-step explanation:
Please help me! I will give brainliest and 50 points if all correct!
Answer:
10. ○[tex]\displaystyle 4,85; 4\frac{17}{20}[/tex]
9. ○680%
8. ○40%
7. ○[tex]\displaystyle 60[/tex]
6. ○0,4, 40,5%, 11⁄25, 4⁄9
5. ○[tex]\displaystyle 0,928[/tex]
4. ○1%
3. ○76%
2. [tex]\displaystyle See\:above\:grid[/tex]
1. [tex]\displaystyle See\:above\:grid[/tex]
Step-by-step explanation:
10. To convert from a percentage to a decimal, move the decimal mark twice to the left; each 20 is worth 5, and since 5 by 17 is 85, you have your fractional part of 17⁄20, then attach the whole number of 4.
9. To convert from a mixed number\improper fraction to a percentage, first evaluate the fractional part for a decimal answer, then move the decimal mark twice to the right.
8. To convert from a fraction to a percentage, evaluate the fraction for a decimal answer, then move the decimal mark twice to the right.
7. [tex]\displaystyle \frac{132}{220} = \frac{3}{5} =[/tex]60%
Greatest Common Divisor [GCD]: 44
6. [tex]\displaystyle \frac{11}{25} =[/tex]44%
_
[tex]\displaystyle \frac{4}{9} =[/tex]44,4%
[tex]\displaystyle 0,4 =[/tex]40%
Now that these are all percentages, it is alot easier to order them from least to greatest.
5. To convert from a percentage to a decimal, move the decimal mark twice to the left.
4. To convert from a decimal to a percentage, move the decimal mark twice to the right.
3. Each 25 is worth 4, and since 4 by 19 is 76, you get 76%.
2. Each 25 is worth 4, and since 4 by 6 is 24, you get 24%, and this graph.
1. Each 36 is worth 2 7⁄9, and since 12 by 2 7⁄9 is 33⅓, you get 33⅓%, so you would choose this answer.
I am joyous to assist you anytime.
A surfboard has an original price of $259. It is on sale
for 55% off the original price. Find the sale price of
the surfboard.
Answer:
.45($259) = $116.55
The sale price of the surfboard is $116.55.
The graph of a proportional relationship contains the point (-30, 18)
What is the value of k for the relationship?
Enter your answer in the box as a fraction in simplest form
k=
Answer:
The answer is k = [tex]-\frac{3}{5}[/tex]
Explanation:
We know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
we have the point (-30,18)
so
x=-30, y=18
Find the value of k
[tex]k=\frac{y}{x}[/tex]
substitute
[tex]k=\frac{18}{-30}[/tex]
Simplify
Divide by 6 both numerator and denominator
[tex]k=- \frac{3}{5}[/tex]
a school ordered 3 large boxes of board markers. After giving 15 markets to each of 3 teachers, there were 90 markers left. How many markers were originally in each box?
There were 45 markers originally in each box.
Step-by-step explanation:
Given,
Boxes ordered = 3 large boxes
Markers given to one teacher = 15
Markers given to 3 teachers = 15*3 = 45 markers
Remaining markers = 90
Let,
x be the original number of markers in 3 boxes.
Total markers - markers given to teachers = markers left
[tex]x-45=90\\x=90+45\\x=135[/tex]
There were 135 markers in 3 boxes.
3 boxes = 135 markers
1 box = [tex]\frac{135}{3}=45\ markers[/tex]
There were 45 markers originally in each box.
Keywords: multiplication, addition
Learn more about multiplication at:
brainly.com/question/13076219brainly.com/question/13096001#LearnwithBrainly
How do you solve 3/4x=-24
Answer:
Step-by-step explanation:
Answer:
-32
Step-by-step explanation:
Divide both sides by 3/4 to solve for x.
－24/1*4/3 = -96/3
－96/3=－32
Question attached, please help!
Answer:
Triangle ABC is dilated is dilated with a scale factor of ⅓ with the center of dilation at the point (3,4) resulting in triangle DEC
Step-by-step explanation:
From triangle ABC,
|AC|=3 units
From triangle DEC,
|EC|= 1 unit
Since the two triangles are similar, we can find the scale factor using the ratio of the image length over the corresponding object length.
[tex]scale \: factor = \frac{ |EC| }{ |AC| } [/tex]
Let us substitute the values to get:
[tex]scale \: factor = \frac{1}{3 } [/tex]
When we trace through AD and EB, they will meet at C. Hence C(3,4) is the center of dilation.