A rectangular room measures 13 feet by 132 inches. Find the area in square feet.

The percent of change from 14 inches to 26 inches is approximately 85.71 percent, calculated by using the formula for percent of change which is [(change in quantity)/(original quantity)] × 100.

To find the percent of change from one value to another, you apply the formula [(change in quantity)/(original quantity)] × 100. In this instance, the original quantity is 14 inches and it changed to 26 inches. Therefore, the change in quantity is 26 - 14 = 12 inches.

Now, substitute these values into the formula: (12/14) × 100 = 85.71% (approximately). This means the change from 14 inches to 26 inches represents an approximately 85.71 percent increase.

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Without the height of the popcorn machine, the exact length cannot be calculated. The length is three-quarters of the height. If the height were known, the length would be determined by multiplying the height by 3/4.

To determine the length of the popcorn machine, we need to know the height of the machine since the length is expressed as a fraction of the height. Without the height measurement, we cannot calculate a specific length. However, if we were provided with the height (let's call it H), then we could easily find the length by multiplying the height by 3/4:

Length = (3/4) × H

For example, if the height of the popcorn machine were 4 feet, then the length would be calculated as follows:

Length = (3/4) × 4 feet = 3 feet

Therefore, the length of the popcorn machine is three-quarters of whatever its height is.

Nathan can completely fill a bag of mixed nuts by calculating the total weight of the nuts, then dividing that total by 1.2 kg, which is the weight of nuts per bag. Any decimal in the result would be rounded down to give the number of full bags.

To determine the number of bags of mixed nuts Nathan can completely fill, you first need to calculate the total weight of all the nuts he bought. This is done by adding up the masses of all the different nuts mentioned in the table.

Let's assume that Nathan's total weight of nuts is 'T'. His plan is to fill each bag with 1.2 kg of nuts, thus the number of full bags he can make, denoted as 'B', is the total weight divided by the weight per bag. In other words, B = T / 1.2.

A key fact here is that this calculation will give a decimal if 'T' is not a multiple of 1.2. However, since he cannot create partial bags, you would round down any decimal to get the number of complete bags.

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Answer:

Step-by-step explanation:

If Stephen divided 46.8 by 0.5, the right quotient would be:

[tex]\frac{46.8}{0.5} = 93.6[/tex]

Therefore, the correct quotient would be 93.6, because if Stephen multiply 93.6 times 0.5, it would result in 46.8.

Remember that the quotient is basically the result of a division or fraction.

Joan completed 12 free throws. Tabitha completed 8, half of 4 more than Joan's total. Equation: (1/2)(4+n)=8. Solve: n=12.

Let's break down the problem step by step:

1. Let's denote the number of free throws Joan completed as n.

2. According to the given information, Tabitha completed 8 shots.

3. It's also mentioned that Tabitha completed half of 4 more than Joan completed. So, the number of shots Tabitha completed is [tex]\( \frac{1}{2}(4 + n) \)[/tex].

4. Since Tabitha completed 8 shots, we can write the equation:

[tex]\[ \frac{1}{2}(4 + n) = 8 \][/tex]

5. Now, let's solve for n:

[tex]\[ \frac{1}{2}(4 + n) = 8 \][/tex]

4 + n = 16 (multiplying both sides by 2 to eliminate the fraction)

n = 16 - 4

n = 12

So, the number of free throws, n, that Joan completed is indeed 12..

Final answer:

To do twice of p minus q, multiply p by 2 and then subtract q. For example, if p is 5 and q is 3, the result would be 7 (since 2*5 - 3 equals 10 - 3 equals 7).

Explanation:

To calculate twice of p minus q, first you need to understand that 'twice of p' means 2 times p, which is written as 2p. Then, you subtract q from this result. The algebraic expression for this calculation is 2p - q.

Here is an example, if p equals 5 and q equals 3, then twice of p minus q would be calculated as follows:

Twice of p is 2 times 5, which equals 10.

Then, subtract q (which is 3) from this result: 10 - 3 equals 7.

Therefore, twice of p minus q would be 7 when p is 5 and q is 3.

Two hundred percent (200%) is equivalent to whole number 2.

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given:

We have the percentage 200%.

Converting percentage to whole number,

200/100,

= 2

2 is equivalent to 200%.

Therefore, 2 is equivalent to 200%.

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Answer: 10

How many hours will it take Kelli and Karl to earn the same amount of money? i took the k12 quiz

Answer:

The vertices of image are (5,1), (2,-5) and (-4,-5).

Step-by-step explanation:

The vertices of triangle are (5,-1), (3,-5) and (-1,-5).

If a figure dilated by scale factor k centered at (a,b), then

[tex](x,y)\rightarrow (k(x-a)+a,k(y-b)+b)[/tex]

The figure after a dilation with a scale factor of 3/2 centered at (5, −5).

[tex](x,y)\rightarrow (\frac{3}{2}(x-5)+5,\frac{3}{2}(y+5)-5)[/tex]

The coordinates of image are

[tex](5,-1)\rightarrow (\frac{3}{2}(5-5)+5,\frac{3}{2}(-1+5)-5)\rightarrow (5,1)[/tex]

[tex](3,-5)\rightarrow (\frac{3}{2}(3-5)+3,\frac{3}{2}(-5+5)-5)\rightarrow (2,-5)[/tex]

[tex](-1,-5)\rightarrow (\frac{3}{2}(-1-5)+5,\frac{3}{2}(-5+5)-5)\rightarrow (-4,-5)[/tex]

Therefore vertices of image are (5,1), (2,-5) and (-4,-5).

The fraction of the pie given to his friend is [tex]\frac{1}{2}[/tex]

The leftover given to his friends will be determined adding the portion Christine and her brother ate which are [tex]\frac{1}{6}[/tex] and [tex]\frac{1}{3}[/tex] respectively, then subtracted from the whole portion.

= [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{3}[/tex] (The lowest common denominator of 6 and 3 = 6)

= (1 x 1) + (2 x 1) /6

= (1) + (2) / 6

= 1 + 2 / 6

= [tex]\frac{3}{6}[/tex]

Thus, total portion of the pie eaten by Christine and her brother = [tex]\frac{3}{6}[/tex] . Also the fraction of the whole portion of the pie = [tex]\frac{6}{6}[/tex]  

Determining the portion given to the friend =

Subtracting [tex]\frac{6}{6}[/tex] – [tex]\frac{3}{6}[/tex]

= [tex]\frac{6}{6}[/tex] – [tex]\frac{3}{6}[/tex] (The lowest common denominator of 6 and 6 = 6)

= (1 x 6) – (1 x 3) / 6

= (6) – (3) / 6

= 6 – 3 / 6

= [tex]\frac{3}{6}[/tex]

= [tex]\frac{1}{2}[/tex] (further broken down to this)

Therefore the fraction given to the friend is [tex]\frac{1}{2}[/tex].

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the value of the fraction when x = 2 and y = 3 is approximately [tex]\( \frac{1}{31.6} \).[/tex]

To find the value of the fraction [tex]\( \frac{1}{2x^3 + 5.2y} \) when \( x = 2 \) and \( y = 3 \)[/tex], we substitute these values into the expression:

[tex]\[ \frac{1}{2(2)^3 + 5.2(3)} \][/tex]

[tex]\[ = \frac{1}{2(8) + 5.2(3)} \][/tex]

[tex]\[ = \frac{1}{16 + 15.6} \][/tex]

[tex]\[ = \frac{1}{31.6} \][/tex]

So, the value of the fraction when x = 2 and y = 3 is approximately [tex]\( \frac{1}{31.6} \).[/tex]

The probable question maybe:

What is the value of fraction 1 over 2x^3 + 5.2y when x = 2 and y = 3?

Linear function f with f(-3) = 1 and f(13) = 5 is given by   [tex]\rm f(x) = \dfrac{1}{4}x + \dfrac{7}{4}[/tex]  and this can be determined by using the given data.

Given :

f(-3) = 1 and f(13) = 5.

The generalised linear function is given by:

f(x)  = ax + b   --- (1)

Now, it is given that (f(-3) = 1) that means at (x = -3) the above function is equal to 1.

f(-3) = a(-3) + b

    1  = -3a + b

b = 1 + 3a   ---- (2)

Now, it is also given that (f(13) = 5) that means at (x = 13) the function (f(x) = ax + b) is equal to 5.

f(13) = 13a + b

5 = 13a + b

Now, put the value of 'b' in the above equation.

5 = 13a + 1 + 3a

4 = 16a

[tex]\rm a = \dfrac{1}{4}[/tex]

Now, put the value of 'a' in equation (2).

[tex]b = 1 +3\times \dfrac{1}{4}[/tex]

[tex]b = \dfrac{7}{4}[/tex]

Now, put the value of a and b in equation (1).

[tex]\rm f(x) = \dfrac{1}{4}x + \dfrac{7}{4}[/tex]

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