A restaurant uses 8 1/4 pounds of carrots to make 6 carrot cakes. Frank wants to use the same recipe. How many pounds of carrots does Frank need to make one carrot cake?

Answers

Answer 1
1.375 lbs of carrots
Answer 2

Frank needs [tex]\( \frac{11}{8} \)[/tex] pounds of carrots to make one carrot cake.

To find out how many pounds of carrots Frank needs to make one carrot cake, we first need to determine how many pounds of carrots are used per carrot cake in the original recipe.

Given that the restaurant uses 8(1)/(4) pounds of carrots to make 6 carrot cakes, we divide the total pounds of carrots by the number of cakes to find the amount per cake.

[tex]\( \text{Carrots per cake} = \frac{8\frac{1}{4}}{6} \)[/tex]

First, we convert the mixed number [tex]\(8\frac{1}{4}\)[/tex] to an improper fraction:

[tex]\(8\frac{1}{4} = \frac{(8 \times 4) + 1}{4} = \frac{33}{4}\)[/tex]

Then, divide by 6:

[tex]\( \frac{33}{4} \div 6 = \frac{33}{4} \times \frac{1}{6} = \frac{33}{24} = \frac{11}{8} \)[/tex]

So, Frank needs [tex]\( \frac{11}{8} \)[/tex] pounds of carrots to make one carrot cake.


Related Questions

Based on a sample survey, a company claims that 75% of their customers are satisfied with their products. Out of 1,176 customers, how many would you predi be satisfied?

Answers

Just multiply 1176 by the probability of satisfaction, which is 0.75:

0.75(1176) = 882

An equivalent equation has been written by multiplying the second equation by 2. 4x – 9y = 7 4x – 9y = 7 2(–2x + 3y = 4) → –4x + 6y = 8

Answers

my best guess is 
x=3/2y-2
y=2/3x+4/3
depends on which one you are solving for

Answer: answer is (-19/2,-5)


Step-by-step explanation:


Miss Martin has 7000 in her savings account. Alonso has 1/10 as much money in his account as Miss Martin. How much money does Alonso have in his account.

Answers

Alonso has $700! (7000/10 or 7000*.1)

Between white pair of numbers is a product of 200 and 89 and 7

Answers

[tex]\bf 200\cdot 89\cdot 7\implies 124600 \\\\\\ \boxed{124599}\text{\textemdash\textemdash\textemdash\textemdash\textemdash}124600\text{\textemdash\textemdash\textemdash\textemdash\textemdash}\boxed{124601}[/tex]

-4(n - 6) = 12

Solve the Equation.

Answers

-4(n - 6) = 12

n - 6 = -12/4   divide both sides by -4

n - 6 = -3

n = -3 + 6    add both sides by 6

n = 3

hope that helps, God bless!

At what points does the curve r(t) = ti + (4t â t2)k intersect the paraboloid z = x2 + y2? (if an answer does not exist, enter dne.)

Answers

Final answer:

To find the intersection points of the curve r(t) with the paraboloid z = x^2 + y^2, we substituted the parametric forms into the equation and solved for t, yielding the points (0, 0, 0) and (2, 0, 4).

Explanation:

The student is asking about the intersection points of a curve r(t) with a paraboloid defined by z = x2 + y2. To find these points, we must substitute the parametric forms of x, y, and z from the curve into the equation of the paraboloid and solve for t.

Given the curve r(t) = ti + (4t - t2)k, we can identify the components of the curve as x(t) = t and z(t) = 4t - t2. The y-component is missing, which implies that y = 0. Now, substituting x(t) into the paraboloid equation, we get:

z = x2 + y2

4t - t2 = t2 + 02

By solving for t, we can determine the intersection points. Simplifying the equation, we get:

0 = 2t2 - 4t

Which gives us the solutions t = 0 and t = 2. Substituting these back into r(t) gives the intersection points (0, 0, 0) and (2, 0, 4).

Glenn invested $22,000 at 7% interest compounded annually. How much interest will Glenn earn in 3 years?


$19,826.24

$20,837.25

$2340.23

$4950.95

Answers

Given:
P = $22,000, the principal
r = 7% =0.07, the rate
n = 1, annual compounding
t = 3 years

The value after 3 years is
[tex]A=P(1+ \frac{r}{n} )^{nt}[/tex]
That is,
A = 22000(1.07)³ = $26,950.95
Interest earned = $26,950.95 - $22,000 = $4,950.95

Answer: $4,950.95

The normal body temperature of a camel is 37°C. This temperature varies by up to 3°C throughout the day. Write and solve an absolute value inequality that represents the range of normal body temperatures (in degrees Celsius) of a camel throughout the day.

Answers

The range of normal body temperatures for a camel throughout the day is from 34°C to 40°C, inclusive.

To represent the range of normal body temperatures for a camel throughout the day, we'll use an absolute value inequality. Given that the normal body temperature is 37°C and it varies by up to 3°C, we can express this as:

|T - 37| ≤ 3

Where T represents the temperature of the camel throughout the day. This inequality ensures that the temperature remains within 3 degrees above or below the normal body temperature of 37°C.

To solve this inequality, we'll consider two cases:

1. When T - 37 is positive:

T - 37 ≤ 3

T ≤ 40

2. When T - 37 is negative:

-(T - 37) ≤ 3

-T + 37 ≤ 3

-T ≤ -34

T ≥ 34

Combining the two cases, the range of normal body temperatures for a camel throughout the day is 34°C to 40°C.

jake rounded 18,752 to the nearest ten thousand which is his number

Answers

The nearest ten thousand is 20,000

20,000 is the Answer. Hope this helps.

Expressions that simplify to the same expression are called ____

Answers

Equivalent Expressions

Answer:

They are called equivalent expressions since they are two expression that equal the same thing.

If this helped then please mark as brainliest.

Use the definition of the derivative to find the derivative of: f(t)=14−5tf(t)=14−5t.
f′(t)=
f′(t)=

Answers

[tex]\bf f(t)=14-5t\qquad \qquad \stackrel{d e f in i tion~of~a~derivative}{\lim\limits_{h\to 0}~\cfrac{f(t+h)-f(t)}{h}} \\\\\\ \lim\limits_{h\to 0}~\cfrac{[14-5(t+h)]~~-~~[14-5t]}{h}\implies \lim\limits_{h\to 0}~\cfrac{\underline{14-5t}-5h\underline{-14+5t}}{h} \\\\\\ \lim\limits_{h\to 0}~\cfrac{-5\underline{h}}{\underline{h}}\implies -5[/tex]

20 points!!!
Solve this system of lineal equations.separate the x- and y- values with a comma
12x=54-6y
-17x=-62-6y

Answers

The answer is:  {4, 1} .
________________________________________________________
Explanation:
________________________________________
Given the equations:
________________________________________
      "12x = 54 − 6y ;
     "-17x = -62 − 6y ;
_________________________________________
Multiply the second equation (both sides) by "-1" ;
___________________________________________
  -1*{-17x = -62 − 6y} ;

to get: 

17x = 62 + 6y ;
___________________________________________
{Note: The reason we do this is that we notice the TWO "-6y" values; and by multiplying one of the entire equations by "-1" ; we can change said equation to an equation with a "(+6y)" value; and the "(+6y)" and the "(-6y)" values cancel out to "zero" ; providing an opportunity to isolate "x"; and to solve for "x".}.
___________________________________________
Now, rewrite the two equations:
___________________________________________

       12x = 54 − 6y ;
       17x = 62 +  6y ;
___________________________________________
↔  Rewrite; and then add the two together:

       6y + 62 = 17x 
      -6y + 54 = 12x 
____________________
       0  +  116 = 29x ;

↔ 29x = 116 ;

Divide EACH SIDE of the equation by "29" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
________________________________________________
   29x / 29 = 116 / 29  ;
________________________________________________
to get:
________________________________________________
           x  = 4 .
______________________________________________
Now that we have the value for "x" , which is "4" ; let us plug in "4" for "x" for either of the original two equations, to solve for "y".  In fact, let us try substituing "4" for "x" ;  for BOTH of the two original equations; to see if the value is correct.
_____________________________________________
Our original two given equations are:
_____________________________________________
      "12x = 54 − 6y ;

     "-17x = -62 − 6y ;
_____________________________________________
 Let us start with the first equation:
 ________________________
      " 12x = 54 − 6y " ;
__________________________________
When "x = 4" ; what does "y" equal ?

Plug in "4" for "x" ; to solve for "y" ;

  12(4) = 54 − 6y ;

→ 48 = 54 − 6y ;

Subtract "54" from EACH SIDE of the equation;

→ 48 − 54 = 54 − 6y − 54 ;

to get:

→  -6 = -6y ; 

→ Divide EACH side of the equation by "-6" ; to isolate "y" on one side of the equation ; and to solve for "y" ; 

→ -6/-6 = -6y / -6 ;

to get:

1 = y ;  ↔ y = 1 ;  So, we have:  x = 4, y = 1 ;  or,  {4, 1}.
______________________________________________
Let us check to see, if the second (orginal equation) holds true when "x = 4" and "y = 1 " ;
______________________________________________
The second "original equation" given is:
______________________________________________
       " -17x = -62 − 6y " ;
______________________________________________
   →    -17(4) = ?  -62  − 6(1) ?

    →  -68 = ? -62 − 6 ?

    →  -68 = ? -68 ?  Yes!
________________________________________________________
The answer is:  {4, 1} .
________________________________________________________

How many variables are displayed in a scatter plot

Answers

Image result for How many variables are displayed in a scatter plot
two variables
BACK.
Scatter plots are an awesome way to display two-variable data (that is, data with only two variables) and make predictions based on the data. These types of plots show individual data values, as opposed to histograms and box-and-whisker plots.

Help me answer this? Thanks :)

Answers

An expression is undefined when you divide by zero. A simple example is 1/0 which in english is "one over zero"

You cannot have zero in the denominator. Something like 0/1 is allowed as it is equal to 0. In other words, 0/1 = 0. But 1/0 is not allowed. 

Write the slope intercept form of the equation of the line through the given points.
Explanation, please! Thank you!

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 1}}\quad ,&{{ -2}})\quad % (c,d) &({{ 1}}\quad ,&{{ 3}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{3-(-2)}{1-1}\implies \stackrel{und efined}{\cfrac{3+2}{0}}[/tex]

hmmm, the slope is undefined, that means, is a vertical line then, check the picture below.

Find and sketch the domain of the function. f(x, y, z) = 4 − x2 − y2 − z2

Answers

wages wages wages wages wages wages wages wages wages wages wages wages 

The domain of the function [tex]\(f(x, y, z) = 4 - x^2 - y^2 - z^2\)[/tex] is the set of all real numbers for [tex]\(x\)[/tex], [tex]\(y\),[/tex] and [tex]\(z\)[/tex].

To find and sketch the domain of the function [tex]\(f(x, y, z) = 4 - x^2 - y^2 - z^2\)[/tex], we need to determine the set of values for [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex] for which the function is defined, i.e., the values that do not lead to any mathematical inconsistencies.

In this case, the function involves three variables, and it is defined for all real values of [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex]. There are no restrictions on the domain because the square of a real number is always non-negative. Thus, [tex]\(x^2\)[/tex], [tex]\(y^2\)[/tex], and [tex]\(z^2\)[/tex] are non-negative for any real \(x\), \(y\), and \(z\).

In interval notation, we can express this as:

[tex]\[\text{Domain} = (-\infty, \infty) \times (-\infty, \infty) \times (-\infty, \infty)\][/tex]

This domain represents the entire three-dimensional space, and the function is defined for all points within this space. As such, sketching the domain involves visualizing the entire 3D space, which is an unbounded region without any specific shape or boundary.

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General house cleaning (sweeping the floor vacuuming laundry) can burn 470 calories every two hour determine the unit rate

Answers

470/2 = 235. 235c/h is the unit rate.

Answer:

The unit rate is 235 calories per hour.

Step-by-step explanation:

General house cleaning (sweeping the floor vacuuming laundry) can burn 470 calories every two hour determine the unit rate.

Unit rate means we have to find the calories burned in 1 hour.

Hence, calories burned in 1 hour = [tex]\frac{470}{2}= 235[/tex]

Answer :

The unit rate is 235 calories per hour.

Daily output of marathon's garyville, lousiana, refinery is normally distributed with a mean of 232,000 barrels of crude oil per day with a standard deviation of 7,000 barrels. (a) what is the probability of producing at least 232,000 barrels?

Answers

50% A normal distribution is symmetric about the mean. That means that no matter what the standard deviation of a statistic, if it is normally distributed half of the time it will above the mean and half will be below. 232000 barrels is the mean and half of the time production will be above that value.

A pile of coins, consisting of quarters and half dollars, it worth $11.75. If there are 2 more quarters than half dollars, how many of each are there?

Answers

Let the number of half dollars be x,

number of quarters = x + 2
amount of half dollars = 0.5x
amount of quarters = 0.25(x + 2)
= 0.25x + 0.5
total amount = 0.5x + 0.25x + 0.5
= 0.75x + 0.5
0.75x + 0.5 = 11.75
0.75x = 11.25
x = 15
number of quarters = x + 2
= 15 + 2
= 17

There are 17 quarters and 15 half dollars.

Let the number of half dollars be x,

number of quarters = x + 2

amount of half dollars = 0.5x

amount of quarters = 0.25(x + 2)

= 0.25x + 0.5

total amount = 0.5x + 0.25x + 0.5

= 0.75x + 0.5

0.75x + 0.5 = 11.75

0.75x = 11.25

x = 15

number of quarters = x + 2

= 15 + 2

= 17

There are 17 quarters and 15 half dollars.

What does e equal in e/2 < 3? Please help. I need a quick answer.

Answers

2.718 ≈e that is the answer to your question.

You have diving lessons every fifth day and swimming lessons every third day. Today you have both lessons. In how many days will you have both lessons on the same day again?

Answers

16 days
 because 8 +8 = 16  5+3=8

Find the rate of change of q with respect to p when p = 20 q 2 + 5 .

Answers

Final answer:

The rate of change of q with respect to p is the derivative of q with respect to p. However, the function seems to be incorrect as p is expressed as a function of q, not the other way around. The derivative of a typical function q = 20p^2 + 5 would be 40p.

Explanation:

The rate of change of q with respect to p is found by taking the derivative of the given function with respect to p. The function given is p = 20q^2 + 5. Unfortunately, we cannot find the derivative of p with respect to q. Instead, it seems more likely that we need to find the derivative of q with respect to p, which is typically what is intended when asked for the rate of change of one variable with respect to another. If the function was q = 20p^2 + 5, then, the derivative (rate of change) would be dq/dp = 40p. Although in your question, there may be an error as typically we would expect q to be expressed as a function of p.

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7,746.90 times x = 7,901.84 what's x

Answers

7,746.90 times x  = 7,901.84

 divide both sides by x

 x = 7,901.84 / 7,746.90

x = 1.020000258

 round to 1.02

the sinclair family live 5.4 miles from southside middle school. how many feet away do they live?

Answers

Final answer:

The Sinclair family lives 28,512 feet away from Southside Middle School, calculated by multiplying 5.4 miles by the number of feet in one mile, which is 5,280 feet.

Explanation:

The Sinclair family lives 5.4 miles from Southside Middle School. To convert this distance from miles to feet, we use the conversion factor that 1 mile is equal to 5,280 feet. To find the distance in feet, we multiply the number of miles by the number of feet in one mile:

5.4 miles  imes 5,280 feet/mile = 28,512 feet.

Therefore, the Sinclair family lives 28,512 feet away from Southside Middle School.

what is 645 round to the nearest ten

Answers

The answer is 650 have a nice day
645 rounded to the nearest ten is 650

hope this helps

solve the equation .......x/9 = 2/45 +x/10

Answers

Hello Joseph!

[tex] \frac{x}{9} = \frac{2}{45} + \frac{x}{10} Simplify both sides... 1/9 x = 2/45 + 1/10 x 1/9 x - 1/10 x = 2/45 1/90 x = 2/45 x = 2/45 * 90 x=180/45 x=4[/tex]

1 1/4mi = ft, can someone explain this to me

Answers

first off, we'll convert the mixed fraction to "improper" and check about, keeping in mind that, there are 5280 feet in 1mile.

[tex]\bf \stackrel{mixed}{1\frac{1}{4}~mi}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}~mi}\\\\ -------------------------------[/tex]

[tex]\bf \begin{array}{ccll} feet&miles\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 5280&1\\ f&\frac{5}{4} \end{array}\implies \cfrac{5280}{f}=\cfrac{1}{\quad \frac{5}{4}\quad }\implies \cfrac{5280}{f}=\cfrac{\frac{1}{1}}{\quad \frac{5}{4}\quad } \\\\\\ \cfrac{5280}{f}=\cfrac{1}{1}\cdot \cfrac{4}{5}\implies \cfrac{5280}{f}=\cfrac{4}{5}\implies \cfrac{5280\cdot 5}{4}=f\implies 6600=f[/tex]

Alex was hired to unpack 576 items of glass wear, at five cents per piece unpacked. For every item broken in the process, however, Alex had to pay $1.98. At the end of the job, Alex received $22.71. How many items did Alex break.

Answers

576*0.05= $28.80.
Guess and check: 1.98*5=9.9
28.80-9.9=18.9- too much
1.98*3=5.94
28.80-5.94=22.86- this is the closest

So he must have broken 3 items.
Hope this helps!

Can u plz mark me as brainliest? I really need it!

Alex broke 3 glasses during the unpacking of the glasses.

As mentioned in the question, Alex was hired to unpack 576 items of glass wear, at five cents per piece unpacked. For every item broken in the process, however, Alex had to pay $1.98. At the end of the job, Alex received $22.71.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

The total amount earned for 576 glasses is given as,
= 576 × 0.05
= $28.80.

Amount earned = $22.71
Amount paid by Alex for the broken glass = $28.80 - $22.71 = 6.09
Total glass broked = 6.09 / 1.98 ≈ 3

Thus, Alex broke 3 glasses during the unpacking of the glasses.

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Which graph represents the solution set of the system of inequalities? {3y≥x−93x+y>−3

Answers

That is the correct graph that represents

{3y≥x−9 3x+y>−3



hope i helped =D

we have

[tex]3y\geq x-9[/tex] ----> inequality A

The solution of the inequality A is the shaded area above the solid red line

See the attached figure N [tex]1[/tex]

[tex]3x+y> -3[/tex] ----> inequality B              

The solution of the inequality B is the shaded area above the dotted blue line

See the attached figure N [tex]2[/tex]

The solution of the system of inequalities is the shaded area between the solid red line and the dotted blue line

See the attached figure N [tex]3[/tex]

therefore

the answer in the attached figure


how do you know that the decimal for 2/11 repeats without end

Answers

because u just put the 2.11 in that order
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