A right triangle has a hypotenuse that measures 65 in. and one side that measure 16 in. what is the length of the remaining side of the triangle?

To show that the moment generating function (mgf) of a random variable y = 2px converges to that of a chi-squared random variable with 2r degrees of freedom as p approaches 0, we need to find the mgf of y using the definition of the mgf and substitute the new random variable. Then, by applying the limit as p approaches 0, we can demonstrate the convergence.

In this question, we are asked to define a new random variable, y = 2px, and show that as p approaches 0, the moment generating function (mgf) of y converges to that of a chi-squared random variable with 2r degrees of freedom.

To show this, we need to find the mgf of y by using the definition of the mgf and substituting the new random variable.

Then, as p approaches 0, we need to simplify the mgf and show that it converges to the mgf of a chi-squared random variable with 2r degrees of freedom.

By applying the limit as p approaches 0, we can demonstrate that the mgf of y converges to the mgf of a chi-squared random variable with 2r degrees of freedom.

need to find the radius first

 area = pi*r^2

380 = PI *r^2

380/PI = r^2

r^2 = 121

r = sqrt(121) = 11 inches

 radius is 11 inches

 now calculate circumference:

 c = 2*PI*r

 C = 2 * 3.14 * 11

circumference = 69.08 = 69 inches

Answer:

  -4

Step-by-step explanation:

Use your knowledge of multiplication facts.

  [tex]\sqrt[3]{-64}=\sqrt[3]{(-4)^3}=-4[/tex]

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Your calculator may be able to do this for you.

6 pots

6 pots

6 pots

6 pots

This would be 5.55

5550÷10^3=5.55

Hope this helps

The solution involves dividing 5,550 by 1,000, which gives 5.55. The expression 10³ represents 1,000, simplifying the division. Therefore, 5,550 divided by 10 to the power of 3 equals 5.55.

To solve the problem 5,550 divided by 10 to the power of 3, follow these steps:

Therefore, 5,550 ÷ 10³ = 5.55.

Answer:

C. [tex]\frac{2}{5}[/tex]

Step-by-step explanation:

Let x be the number which is more than 0.35 but less than 0.41,

⇒ 0.35 < x < 0.41

[tex]\implies \frac{35}{100}< x < \frac{41}{100}[/tex]

[tex]\implies \frac{7}{20} < x < \frac{41}{100}[/tex]

∵ Only [tex]\frac{2}{5}[/tex] is between [tex]\frac{7}{20}[/tex] and [tex]\frac{41}{100}[/tex],

Hence, option C is correct.

Jackson walks 5/12 miles farther than Thomas to work. So, Jackson walks approximately [tex]\( \frac{5}{12} \)[/tex] miles farther than Thomas.

To find out how much farther Jackson walks to work than Thomas, we need to subtract the distance Thomas walks from the distance Jackson walks.

Thomas walks 1 1/4 miles, which is equivalent to 5/4 miles. Jackson walks 1 2/3 miles, which is equivalent to 5/3 miles.

To subtract fractions, we need a common denominator, which in this case is 12. So, 5/3 is equivalent to 20/12, and 5/4 is equivalent to 15/12.

Now, subtracting, we get 20/12 - 15/12 = 5/12 miles.

Therefore, Jackson walks 5/12 miles farther than Thomas.

Final answer:

John's weight dropped by 12.5%.

Explanation:

To calculate the percent by which John's weight dropped, we need to find the difference between his initial weight and final weight, and then divide that difference by his initial weight. We can then multiply the result by 100 to express it as a percentage.

Initial weight = 168 pounds
Final weight = 147 pounds

Difference = 168 - 147 = 21 pounds

Percent drop = (Difference / Initial weight) x 100

Percent drop = (21 / 168) x 100 = 12.5%

Therefore, John's weight dropped by 12.5%.

Final answer:

To calculate the percent by which John's weight dropped, subtract his final weight from his initial weight, and divide the difference by his initial weight, then multiply by 100. John's weight dropped by 12.5%.

Explanation:

To calculate the percent by which John's weight dropped, you need to find the difference between his initial weight and his final weight, then divide that difference by his initial weight and multiply by 100.

So, John's weight dropped by 12.5%.

Answer:

two pair of opposite equal angles

bisecting diagonals

two pair of opposite parallel sides

Answer:

[tex]\left\{\begin{matrix}x+y\geq 2\\ x< y\\ y> \frac{1}{2}\end{matrix}\right.[/tex]

Step-by-step explanation:

Let  x represents the number of hours spent practicing his backhand

Let y represents the number of hours practicing his serve.

Since we are given that Tim practices his backhand and his serve at least 2 hours each day i.e. he practices his backhand and serves for two hours or more than two hours

⇒ x+y≥2 --(a)

We are also given that He works less on his backhand than his serve

⇒x < y --(b)

And we are also given that he practices his serve more than 1/2 hour daily.

⇒ y > 1/2 --(c)

Thus the inequalities are :

[tex]\left\{\begin{matrix}x+y\geq 2\\ x< y\\ y> \frac{1}{2}\end{matrix}\right.[/tex]

Thus the Option C is correct .