A saturated straight-chain hydrocarbon with two carbons is ____.

Answer: water freezing.

Explanation:

In this problem, we can formulate two equations.

First, the overall mass balance of the ointment. The mass of 30% salicylic acid ointment plus the mass of petrolatum must be 50 grams.

x + p = 50

Where x is the mass of 30% salicylic acid ointment and p is the mass of petrolatum

Second, the component mass balance of salicylic acid:

0.3 * x = 50 * 0.05

x = 8.33 g

Therefore the mass of petrolatum to be used is:

x + p = 50

p = 50 – x

p = 50 – 8.33

p = 41.67 g

Answer:

41.7

Actually there are three established rules on counting how many significant figures are in a number:

Rule 1: Positive integers are always significant.

Rule 2: Any zeros between two significant digits are always significant.

Rule 3: A final zero or trailing zeros after the decimal point are always significant.

Since the given number is 10.0010 g, the two 1’s is under Rule 1, the three 0’s between the two 1’s is under Rule 2, and the zero after the last 1 is under Rule 3. Therefore all the digits are significant.

Answer: So the number of significant figures in the measurement is 6.

Answer: Option (c) is the correct answer.

Explanation:

When [tex]Al(NO_{3})_{3}[/tex] reacts with CaO then it results in the formation of aluminium oxide and calcium nitrate.

The chemical reaction equation will be as follows.

[tex]2Al(NO_{3})_{3} + 3CaO \rightarrow Al_{2}O_{3} + 3Ca(NO_{3})_{2}[/tex]

Thus, we can conclude that out of the given options [tex]Al_{2}O_{3}[/tex] is one of the products produced when [tex]Al(NO_{3})_{3}[/tex] and CaO react together.

The concentration of the acid is the same as that of the base.

If equal volumes of acid and base are required, you can conclude that the concentrations must be the same.

To find the density of sulfur dioxide (SO2) at 1.2 atmospheres and 271 Kelvin, we can use the ideal gas law equation. We need to know the molar mass of sulfur dioxide, which is 64.06 g/mol. Using the ideal gas law equation, we can calculate the volume of SO2 and find the density.

To find the density of sulfur dioxide (SO2) at 1.2 atmospheres and 271 Kelvin, we can use the ideal gas law equation:

density = (mass of SO2) / (volume of SO2)

We need to know the molar mass of sulfur dioxide, which is 64.06 g/mol. We also need to convert the given pressure to Pascals (Pa) and temperature to Kelvin (K).

Using the ideal gas law equation, we can calculate the volume of SO2:

volume of SO2 = (mass of SO2) / (density)

Finally, we substitute the given values into the equation to find the density:

density = mass of SO2 / volume of SO2

To find the number of chlorine atoms in 5.0 g of chloral hydrate, calculate the moles of chloral hydrate and then use Avogadro's number to find the atoms. There are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.

The question asks us to determine the number of chlorine atoms in 5.0 g of chloral hydrate. To find this, we need the molar mass of chloral hydrate (C₂H₃Cl₃O₂) and the molar mass of chlorine. The atomic mass of chlorine is 35.45 u. Chloral hydrate contains three chlorine atoms per molecule.

First, calculate the molar mass of chloral hydrate:

Total molar mass = 165.394 u.

Next, we calculate the amount (in moles) of chloral hydrate:

5.0 g / 165.394 g/mol = 0.0302 mol. Since each molecule of chloral hydrate contains three chlorine atoms, we multiply the number of moles by Avogadro's number (6.022 x 10²³ atoms/mol) and then by three:

0.0302 mol x 3 x 6.022 x 10²³ atoms/mol = 5.46 x 10²²  chlorine atoms.

Therefore, there are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.

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An alpha emission is one in which an atomic nucleus emits an alpha particle (helium nucleus). Therefore in this reaction, the products of the decay are Helium and another element X. Helium has an atomic mass and atomic number of 4 and 2 respectively, therefore the complete reaction is:

U-234 (92) ---> He-4 (2) + X

Since atomic mass and number must be conserved therefore X = X-230 (90)

U-234 (92) ---> He-4 (2) + X-230 (90)

The element with atomic number of 90 is Thorium. Therefore the other product is Thorium-230 (90).

U-234 (92) ---> He-4 (2) + Th-230 (90)

Final answer:

To produce 30.6 moles of water vapor from the reaction of hydrogen gas with excess carbon dioxide, 30.6 moles of hydrogen gas are required according to the balanced chemical equation with a 1:1 molar ratio of hydrogen to water.

Explanation:

To determine how many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need the balanced chemical equation for the reaction between hydrogen gas (H2) and carbon dioxide (CO2) to produce water (H2O) and carbon monoxide (CO).

To determine the number of moles of hydrogen gas needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need to use the balanced chemical equation for the reaction.

The balanced equation is:

2H2(g) + CO2(g) -> 2H2O(g)

From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of carbon dioxide to produce 2 moles of water vapor. Therefore, the ratio of hydrogen gas to water vapor is 2:2.

Since we are given that 30.6 moles of water vapor are produced, we can calculate the moles of hydrogen gas as:

(30.6 moles of water vapor) x (2 moles of hydrogen gas / 2 moles of water vapor) = 30.6 moles

Therefore, 30.6 moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor.

H2(g) + CO2(g) → H2O(g) + CO(g)

From the balanced equation, we see that the molar ratio of hydrogen gas to water vapor is 1:1. Therefore, to produce 30.6 moles of water vapor, 30.6 moles of hydrogen gas are needed:

30.6 moles H2O × 1 mole H2/1 mole H2O = 30.6 moles H2

Thus, 30.6 moles of hydrogen gas are required to react with excess carbon dioxide to produce 30.6 moles of water vapour.

Ten molecules of water are required to completely hydrolyze a polymer of 11 monomers.

A polymer can be described as a macromolecule which essentially is a combination of many subunits. From Polypropylene which is used widely around the world as plastic to the strand of our DNA, which is a naturally occurring biopolymer.

Polymers can be naturally found in plants and animals called natural polymers or can be man-made called synthetic polymers. Different types of polymers posses different physical and chemical properties.

Semisynthetic polymers are those which can be derived from naturally occurring polymers and can undergo further modification such as cellulose nitrate, and cellulose acetate.

Polymers can be broken down into monomers is called hydrolysis of polymer, which is a reaction in which a water molecule is utilized during the breakdown.

Given polymer has 11 monomers which are connected with each other through 10 bond links that can be broken by ten water molecules.

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The electron lost to form a potassium ion from a potassium atom is from the 4s orbital. Its set of quantum numbers, which describe its state, are (4,0,0,±1/2).

The electron lost to form the potassium (K) ion from the K atom would be the electron in the highest energy level, or the outermost shell, of the atom. This shell, also called the valence shell, contains only one electron for Potassium. This electron can be characterized by its four quantum numbers: the principal quantum number (n), the azimuthal quantum number (l), the magnetic quantum number (m), and the spin quantum number (ms).

For potassium, this electron resides in the 4s orbital. So the set of quantum numbers for this electron would be: n=4 (fourth energy level), l=0 (s orbital), m=0 (orientation of the orbital), and ms=±1/2 (two possible spin states). Thus, the set of quantum numbers for the electron lost to form the K ion from the K atom is (4,0,0,±1/2).

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Answer: The volume of water that must be added will be 1.417 L.

Explanation:

Concentration of a substance is defined as mass of solute (in grams) present in the given volume of a solution (in L).

The equation representing concentration is given as:

[tex]\text{Concentration of solute}=\frac{\text{Mass of solute}}{\text{Volume of solvent}}[/tex]

We are given:

Concentration = 3.81 g/L

Mass of sodium nitrate = 5.40 g

Putting values in above equation, we get:

[tex]3.81g/L=\frac{5.40g}{\text{Volume of water}}\\\\\text{Volume of water}=1.417L[/tex]

Hence, the volume of water that must be added will be 1.417 L.

B. mass being converted to energy when protons and neutrons bind together in a nucleus

The solubility product (Ksp) of barium chromate (BaCrO₄) is approximately 1.227 × 10⁻¹⁰.

Given information,

Solubility of barium chromate = 2.81 × 10⁻³ g/l

The molar solubility (S) is the number of moles of the compound that dissolve per liter of solution.

Molar mass of BaCrO₄ = (atomic mass of Ba) + (atomic mass of Cr) + 4 (atomic mass of O)

Molar mass of BaCrO₄ = 137.33 + 51.996 + 4 × 16.00

Molar mass of BaCrO₄= 137.33 + 51.996 + 64.00

Molar mass of BaCrO₄= 253.326 g/mol

Molar solubility (S) = (mass of BaCrO₄/ molar mass of BaCrO₄)

S = (2.81 × 10⁻³)/(253.326 )

S = 1.108 × 10⁻⁵ mol/L

Since the stoichiometric coefficients of BaCrO₄ are 1 for both barium ions (Ba²⁺) and chromate ions (CrO₄²⁻), the solubility product can be calculated as:

Ksp = [Ba²⁺][CrO₄²⁻]

Ksp ≈ 1.108 × 10⁻⁵  × 1.108 × 10⁻⁵

Ksp = 1.227 × 10⁻¹⁰

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The molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.

The molar solubility of BaF2 in pure water can be calculated using the solubility product constant (Ksp) of BaF2. The equation for the dissolution of BaF2 is BaF2 → Ba²+ + 2F¯. The Ksp expression for BaF2 is Ksp = [Ba²+][F¯]². Since there is a 1:2 stoichiometric relationship between BaF2 and fluoride ions in solution, the molar solubility of BaF2 can be represented as x, which gives the concentrations of Ba²+ and F¯ as x and 2x, respectively. Substituting these values into the Ksp expression, we get:

Ksp = (x)(2x)² = 4x³ = 2.45 x 10⁻⁵

Solving for x, we find that the molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.