A sequence of transformations maps ∆ABC onto ∆A″B″C″. The type of transformation that maps ∆ABC onto ∆A′B′C′ is a_______
.When ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″, _______vertex
of ∆A″B″C″ will have the same coordinates as B′.
Answers
Answer:The first one is a Reflection
The second one is B
Step-by-step explanation:
Related Questions
how many times is 2 bigger than 0.2
Answers
Is the term (x + 2) a factor of the polynomial shown below?
ƒ(x)=x^4+5x^3+10x^2+20x+24
A. Yes, the remainder is 48.
B. Yes, the remainder is 0. ...?
Answers
Every ten years, the bureau of the census counts the number of people living in the united states. in 1790, the population of the u.s. was 3.93 million. by 1800, this number had grown to 5.31 million.
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1.An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object’s position from the top of the tower at 1.0 s intervals. Make a position-time graph for the object’s motion. In your response, show what you are given, the equation that you used, any algebra required, a table of data, and your graph.
g = 9.8 m/s2
Answers
Answer:
Position of ball from top of tower after 1 second is 4.9 m
Position of ball: [tex]y=-4.9t^2+122.5[/tex]
Step-by-step explanation:
An object falls from rest on a high tower and takes 5.0 s to hit the ground.
Initial speed, u = 0Height of tower, [tex]h_0[/tex]Acceleration due to gravity, [tex]g=9.8\ m/s^2[/tex]Let position of object from top of tower be y
Using formula, v =u - gt
[tex]v=0-9.8\times 5[/tex]
[tex]v=49\ m/s[/tex]
Speed of object when hit the ground.
Height of tower, H₀
[tex]H_0=\dfrac{49^2-0}{2\times 9.8}=122.5\ m[/tex]
Velocity of ball after 1 s
[tex]v=0-9.8\times 1[/tex]
[tex]v=-9.8\ m/s[/tex]
Using formula, [tex]s=\dfrac{v^2-u^2}{2g}[/tex]
[tex]y=\dfrac{9.8^2-0^2}{2\times 9.8}[/tex]
[tex]y=4.9\ m[/tex] From top of tower
Now find position of ball from top of tower.
[tex]y=-\dfrac{1}{2}\times 9.8\times t^2+122.5[/tex]
[tex]y=-4.9t^2+122.5[/tex]
Please find the attachment for graph.
An Airplane travels about 1500km in a straight line between Toronto and Winnipeg . However, the plane must climb to 10 000 m during the first 200km. Then it must descend 10 000 m during the final 300km
1. How much Distance do the climb and desent add to the flight? ...?
Answers
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
Answer:
Climbing and descending add to the flight 416 m
Step-by-step explanation:
The plane must climb to 10 km during the first 200 km. This forms a right triangle, where 10 and 200 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:
√(10² + 200²)
The plane must descend 10 km during the final 300km. This forms a right triangle, where 10 and 300 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:
√(10² + 300²)
If the airplane climbed during 300 km and descended during 200 km, then during 1500 - 200 - 300 = 1000 km it doesn't climb or descend.
The distance added by climbing and descending is:
1000 + √(10² + 200²) + √(10² + 300²) - 1500 = 0.416 km or 416 m
solve for m : -3(m-2n)= 5m
Answers
-3m + 6n = 5m
6n = 5m + 3m
6n = 8m
6n/8 = m
3n/4 = m
m = 3n/4
-3(m-2n)=5m (distribute the negative 3)
-3m+6n=5m (add 3m to both sides)
6n= 8m (now divide by 8 to solve for m)
6n/8=m you can simplify
3/4n=m
the diameter of a cone-shaped container is 4 inches, and its height is 6 inches .How much grater is the volume of a cylinder-shaped container with the same diameter and height?
Answers
The volume of the cone would be
[tex]V = \frac{1}{3} \pi r^2h \\ \\ V = \frac{1}{3} \pi (2in)^2(6in) = 8 \pi\ in^3[/tex]
The volume of a cylinder with the same dimensions would be
[tex]V = \pi r^2h \\ V = \pi (2in)^2(6in) = 24 \pi in^3[/tex]
The cylinder is 24 - 8 = 16 cubic inches greater.
Answer:The radius r used in below equations would equal 2in because it is half the given diameter of 4in.
The volume of the cone would be
The volume of a cylinder with the same dimensions would be
The cylinder is 24 - 8 = 16 cubic inches greater.
Step-by-step explanation:
How many thirds are in 3 hours?
Answers
There are 9 thirds in 3 hours, since each hour is made up of 3 thirds.
Explanation:To find out how many thirds are in 3 hours, we consider that 1 hour is equal to 3 thirds (since 1 divided by 1/3 equals 3). Therefore, if 1 hour equals 3 thirds, then 3 hours would contain 3 times as many thirds. We calculate this as follows:
1 hour = 3 thirds
3 hours = 3 hours × 3 thirds/hour = 9 thirds
Thus, there are 9 thirds in 3 hours.
a line passes through the point (2, 3) and has a slope of -2. which is the equation of the line in point-slope form?
Answers
The equation of the line in point-slope form is y = -2x + 7.
To find the equation of the line passing through the point (2, 3) with a slope of -2, we can use the point-slope form of a linear equation:
[tex]\[y - y_1 = m(x - x_1)\][/tex]
where m is the slope and [tex]\((x_1, y_1)\)[/tex] is a point on the line.
Given that the point [tex]\((x_1, y_1)\)[/tex] is (2, 3) and the slope m is -2, we substitute these values into the point-slope form:
y - 3 = -2(x - 2)
Now, we can simplify the equation:
y - 3 = -2x + 4
Next, we can move the constant term to the other side:
y = -2x + 4 + 3
y = -2x + 7
So, the equation of the line in point-slope form is y = -2x + 7.
How do i do this problem x-2y=1,for y?
Answers
subtract x
-2y = 1-x
divide by -2
y = x-1
2
convert the fractions to decimals.
3/20
7/50
9/25
4/15
1/9
9/40
5/16
7/9
13/20
37/50
11/30
19/40
Answers
7/50: 0.14
9/25: 0.36
4/15: 0.266667
1/9: 0.111111
9/40: 0.225
5/16: 0.3125
7/9: 0.777778
13/20: 0.65
37/50: 0.74
11/30: 0.366667
19/40: 0.475
Which is the correct description of the transformation of figure QRST to figure QꞌRꞌSꞌTꞌ?
A. a 90° counterclockwise rotation around point R of pre-image QRST
B. a 180° clockwise rotation around point R of pre-image QRST
C. a 90° clockwise rotation around point R of pre-image QRST
D. a reflection across point R of pre-image
Answers
Answer:
D. a reflection across point R of pre-image
Step-by-step explanation:
Considering this question is over 4 years old I highly doubt you're going to see this question, or maybe you're not even in school anymore. Even after all that being said, I'm still going to ask this:
May I have brainliest please? :)
A convenience store sells 1/3 pound of one brand of trail mix for $1.50 and 1/2 pound of another brand of trail mix for $2.15. which brand has a lower price per pound? explain your reasoning.
Answers
What number could we multiply 1/3 by to get 1?
3 is the answer! 3 * 1/3 = 3/3 = 1
Multiply the price by 3.
1.50 * 3 = $4.50
What number can make 1/2 a whole number? 2.
2 * 1/2 = 2/2 = 1
Multiply the price by 2.
2.15 * 2 = $4.30
So, the price per pound for the first brand of trail mix is $4.50
And for the second brand of trail mix is $4.30
The second brand is cheaper by the pound... But maybe you should go with the slightly more expensive trail mix... Might be better... Or not.
Students spend an average of $5.50 to buy materials for science olympiad if they each build three mouse trap cars what was the unit cost per car
Answers
The correct unit cost per car is $1.83.
To find the unit cost per car, we need to divide the total cost by the number of cars built. Since each student builds three mouse trap cars and spends an average of $5.50, the total cost for one student is $5.50.
Let's denote the unit cost per car as [tex]\( C \)[/tex]. The equation representing the total cost for one student is:
[tex]\[ 3C = \$5.50 \][/tex]
Now, we solve for [tex]\( C \)[/tex] to find the unit cost per car:
[tex]\[ C = \frac{$5.50}{3} \][/tex]
[tex]\[ C = $1.8333... \][/tex]
Rounding to two decimal places, the unit cost per car is approximately $1.83.
Valeriya wants to determine the likely voting outcome for the new town council election. Which sample is likely to yield the most biased results?
A. every tenth person working for the largest corporation in town
B. ten people chosen at random from each page of the town’s phone list
C. every tenth person walking down Main Street in town on a variety of days and times of the day
D. ten eligible voters chosen at random from each of the different neighborhoods in town
Answers
Answer:
A. Every tenth person working for the largest corporation in town
Step-by-step explanation:
We are given that,
'Valeriya wants to determine the likely voting outcome for the new town council election'.
It is required to find the most biased outcome.
Now, from the options, we see that,
'Every tenth person working for the largest corporation in town'.
will yield the most biased result, as the people working in the largest corporation may have different opinions and benefits.
So, it is most likely that the voting result for this sample may result in the outcome beneficial to only the people working in the large corporations and not for others.
Thus, sample A will yield a most biased result.
A salesperson at a furniture store earns a 3% commission on all sales. How much commission does the salesperson earn on a $1400 sale?
Answers
The answer is $42.
What is equivalent to 4/16 as a whole number?
Answers
A bank account has a beginning balance of $560.00. After 6 months, the balance in the account has increased to $572.60. What interest rate is being earned annually on this account?
Answers
A = P(1 + r/n)ⁿˣ
A - the final amount
P - the principal (the initial amount)
r - the annual interest rate
n - the number of times that interest is compounded per year
x - the number of years
We have:
A = $572.60
P = $560.00
r = ?
n = 2
x = 1
572.60 = 560 * (1 + r/2)²*¹
572.60 = 560 * (1 + r/2)²
572.60 : 560 = (1 + r/2)²
572.60 = 1² + 2 * 1 * r/2 + (r/2)²
1.0225 = 1 + r + r²/4
4 * 1.0225 = 4 * 1 + 4 * r + 4 * r²/4
4.09 = 4 + 4r + r²
0 = 4 + 4r + r² - 4.09
0 = r² + 4r - 0.09
r² + 4r - 0.09 = 0
[tex]r _{1,2} = \frac{-4+/- \sqrt{4^{2} -4*1*(-0.09)} }{2*1} = \frac{-4+/- \sqrt{16+0.36} }{2}= \frac{-4+/- \sqrt{16.36} }{2}= \\ \\ = \frac{-4+/-4.04}{2} \\ \\ r_1 = \frac{-4-4.04}{2} =-4.02 \\ \\ r_2 = \frac{-4+4.04}{2} =-0.02[/tex]
The rate cannot be negative, so it is 0.02
Which theorem or postulate justifies that angle HEF~angle HGE ?
A. AA similarity postulate
B. SAS similarity theorem
C. SSS similarity theorem
D. SSA similarity theorem
Answers
Answer:
Option A is correct.
AA similarity postulate justifies that [tex]\triangle HEF \sim \triangle HGE[/tex]
Step-by-step explanation:
The sum of the measures of a angles in a triangle add up to 180 degree.
In the triangle HGE:
[tex]\angle EHG+\angle EGH+\angle GEH = 180^{\circ}[/tex]
Substitute the given values;
[tex]90^{\circ}+37^{\circ}+\angle GEH = 180^{\circ}[/tex]
[tex]127^{\circ}+\angle GEH = 180^{\circ}[/tex]
Simplify:
[tex]\angle GEH = 180 -127 = 53^{\circ}[/tex]
In triangle HEF and triangle HGE
[tex]\angle FHE = \angle GHE = 90^{\circ}[/tex] [Angle]
[tex]\angle EFH = \angle GEH = 53^{\circ}[/tex] [Angle]
AA (Angle-Angle) similarity postulates states that two triangle are similar if they have two corresponding angles that are congruent or equal.
by AA similarity postulates;
[tex]\triangle HEF \sim \triangle HGE[/tex]
Is the ordered pair a solution to the system of linear equations?
Select Yes or No.
Yes No
Ordered pair: (−2,2)(−2,2)
System of equations:
−7x+2y=0
6x+6y=0
Answers
Doomtown is 300 miles due west of Sagebrush and Joshua is due west of Doomtown. At 9 a.m. Mr. Archer leaves Sagebrush for Joshua. At 1 p.m. Mr. Sassoon leaves Doomtown for Joshua. If Mr. Archer travels at an average speed 20 mph faster than Mr. Sassoon and they each reach Joshua at 4 p.m., how fast is each traveling?
Answers
Mr. Archer was going at a speed of approximately 67 mph and Mr. Sassoon was going at a speed of 47 mph (rounded to the nearest whole number).
Explanation:This problem is a typical distance-rate-time problem. Firstly, we can infer based on the travel times for Mr. Archer and Mr. Sassoon that Mr. Archer traveled for 7 hours (from 9 am to 4 pm) and Mr. Sassoon traveled for 3 hours (from 1 pm to 4 pm) to reach Joshua.
Equalizing the distance travelled by both individuals, we have: its clear that 20 mph * 7 hours = Mr. Sassoon's speed * 3 hours. From this, we can easily infer that Mr. Sassoon's speed is [tex]20*7/3 = 46.67[/tex] mph
Since Mr. Archer travelled 20 mph faster than Mr.Sassoon, Mr.Archer's speed was [tex]46.67 + 20 = 66.67[/tex] mph. Therefore, Mr. Archer was going at a speed of approximately 67 mph and Mr. Sassoon was going at a speed of 47 mph (rounded to the nearest whole number).
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Grammy's Apple Orchard is selling apple cider in 34.7 ounce bottles for $2.09. Grammys competitor is selling 24.6 ounce bottles of cider for $1.99. Who is selling at the lower price?
Answers
1.99 / 24.6 = 0.08
cheapest is the 34.7 oz for 2.09
What number divide evenly into 125 ?
Answers
2/5, 9/10, 7/5, 19/10, 12/5
Find the common difference between the terms of the following arithmetic sequence. ...?
Answers
4/10 , 9/10 , 14/10 , 19/10 , 24/10
From that sequence, we can see that the difference is 5/10 or a 1/2
hope this helps
A rectangle's width is 6 feet less than its length. If the area of the rectangle is 247 square feet, what is its length, in feet?
Answers
Answer:
Length is 19 feet.
Width is 13 feet.
Step-by-step explanation:
Let the length of the rectangle be = L feet
The width is 6 feet less than its length, so width is = L-6 feet
The area of the rectangle is 247 square feet, means length x width = 247
[tex]L(L-6)=247[/tex]
[tex]L^{2} -6L=247[/tex]
[tex]L^{2} -6L-247=0[/tex]
Now here a = 1, b = -6 and c = -247
So, putting these in quadratic equation formula, we get
[tex]L=\frac{-(-6)+\sqrt{(-6)^{2}-(4)*(1)*(-247) } }{2*1}[/tex]
This gives L=19 or -13
As it is a dimension, so we will neglect the negative value.
Hence, L = 19 feet
Width = [tex]19-6[/tex] = 13 feet
How many zeros does the function f(x) = 2x14 − 14x6 + 27x3 − 13x + 12 have?
Answers
A semiconductor manufacturing company employs 1,000 people. The average weekly salary of each employee is $750.
Select the graph that correctly shows the total cost to the company of paying its employees during a year.
Answers
Answer:
Graph A is the correct choice.
Step-by-step explanation:
Let x be the number of weeks.
We have been given that a semiconductor manufacturing company employs 1,000 people. The average weekly salary of each employee is $750.
Let us find the weekly salary for 1000 employees by multiplying 1000 by $750.
[tex]\text{The weekly salary for 1,000 employees}=1,000\times \$750[/tex]
[tex]\text{The weekly salary for 1,000 employees}=\$750,000[/tex]
Let us find amount of salaries after 52 weeks as 1 year equals 52 weeks.
[tex]\text{The amount of salaries after 52 weeks for 1,000 employees}=52*\$750,000[/tex]
[tex]\text{The amount of salaries after 52 weeks for 1,000 employees}=\$39000000[/tex]
Since at week 0, the salaries for 1000 employees will be also 0, so point (0,0) will be on the line of our graph.
Now let see which of our given graphs has point (0,0) and (52,39000000).
We can see that graph A has y-value 39 million on x equals 52, therefore, Graph A is the correct choice.
What is .66667 as fraction
Answers
The decimal .66667 is approximately equivalent to the fraction 2/3. It is understood by recognizing that fractions are essentially divisions, and .66667 is the result of 2 divided by 3.
Explanation:The decimal value of .66667 can be expressed as a fraction. In this case, .66667 is approximately equal to 2/3. To derive this, understand that fractions are a division operation. The decimal .66667 is a result of division where the numerator is smaller than the denominator, which is a characteristic of fractions between 0 and 1. So, if you divide 2 by 3, you will get 0.66667 proving that .66667 is a representation of the fraction 2/3.
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Xavier watched 3/5 of a movie. The entire length of the movie is 2 1/2 hours long. How much of the movie did he watch?
A:1 1/4 hours
B:1 1/2 hours
C:2 1/3 hours
Answers
3/5 * 5/2 =
15/10 =
1 1/2 hrs <==
A discount period is always greater than the credit period true or false ...?
Answers
Generally the discount period will be less than the credit period, however each time period is set by businesses at their own discretion so no generalized statement can be fully made.