Answer:
(D) If the null hypothesis is true, there is a 24% probability of getting a sample difference in means as far or farther below 0 as the difference found in the samples.Explanation:
If the null hypothesis is true, there is a 24% probability of getting a sample difference in means as far or farther below 0 as the difference found in the samples.
What is the calculation for the given sample?H0 : μN ≤ μD
H1 : μN > μD
Right tailed
Test statistic = 1.33
Pvalue = 0.097
Fail to reject the Null
H0 : μN ≤ μD
H1 : μN > μD
The test is right tailed ; culled from the direction of the greater than sign ">"
Night students :
n1 =30 x1= 3.34 s1 = 0.02
Day students:
n2 = 30 x2 = 3.32 s2 = 0.08
The test statistic :
(x1 - x2) / √(s1²/n1) + (s2²/n2)
T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)
T = 0.02 / 0.0150554
Test statistic = 1.328
Using the conservative approach ;
df = Smaller of n1 - 1 or n2 - 1
df = 30 - 1 = 29
Pvalue(1.328, 29) = 0.097
At α = 0.10
Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student.
Therefore, If the null hypothesis is true, there is a 24% probability of getting a sample difference in means as far or farther below 0 as the difference found in the samples.
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a 150 lb man has 2 beers, determine his BAC
BAC = ?
Answer: BAC = 0.056%
Explanation:-
Data given;
Weight of the man = 150 lbs (Wt)
Number of drinks = 2 beers
We know that
A beer contains 5% (0.05) of alcohol (D)
1 bear = 12oz
So 2 beer = 2 × 12 = 24oz (A)
Derived from widmark formula;
BAC for Male = (A × D × 5.14) / ( Wt × 0.73 )
BAC for Female = (A × D × 5.14) / ( Wt × 0.66 )
WHERE
A = Alcohol consumed in ounces (oz.)
D = percentage of alcohol written as a decimal
Wt = weight of person in pounds (lbs.)
Using BAC for male
BAC for Male = (A × D × 5.14) / ( Wt × 0.73 )
We simply input our values
BAC = ( 24 × 0.05 × 5.14) / ( 150 × 0.73)
BAC = 6.168 / 109.5
BAC = 0.056%
A polling agency is investigating the voter support for a ballot measure in an upcoming city election. The agency will select a random sample of 500 voters from one region, Region A, of the city. Assume that the population proportion of voters who would support the ballot measure in Region A is 0.47.
(a) What is the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 ?
The polling agency will take another sample from a different region, Region B, of the city. The agency plans to select a random sample of 400 voters. Assume that the population proportion of voters who would support the ballot measure in Region B is 0.51.
(b) Describe the sampling distribution of the difference in sample proportions (Region B minus Region A).
(c) What is the probability that the two sample proportions will differ by more than 0.05 ?
To estimate the probability of a sample proportion being greater than 0.50 in Region A and the sampling distribution of the difference in sample proportions between two regions, we use normal approximation and the Central Limit Theorem, involving statistical calculations based on known population proportions and sample sizes.
Explanation:To answer whether a polling agency's investigation into voter support for a ballot measure will have a sample proportion greater than 0.50 in Region A and to describe the sampling distribution of the difference in sample proportions (Region B minus Region A), including the probability that the two sample proportions differ by more than 0.05, we follow a statistical approach based on the Central Limit Theorem.
For Region A, assuming a population proportion of 0.47 and a sample size of 500, the probability of the sample proportion supporting the ballot measure being greater than 0.50 can be calculated using the normal approximation. This involves finding the z-score for the sample proportion and then using the standard normal distribution to find the associated probability.
For the sampling distribution of the difference in sample proportions (Region B minus Region A), we need to combine the variances of both sample proportions due to the Central Limit Theorem. This allows us to assess the probability that the two sample proportions will differ by more than 0.05 using a similar z-score and standard normal distribution approach.
The techniques applied involve the use of normal approximation to calculate probabilities and assumes a large enough sample size for the approximation to be accurate.
An ocean basin will form in what location, relative to the major tectonic plates?
Ocean basins can form at rift basins where continental crust is pulled apart and subsequently subsides, or at subduction zones where one plate dives beneath another. Ocean basins influence the size and movement of tectonic plates and can close over time, possibly leading to supercontinent formation.
Explanation:An ocean basin is likely to form at a location where continental crust is being pulled apart due to the process of rift basin formation. As the crust on both sides of the rift subsides, the area initially becomes a narrow sea and, if rifting continues, eventually develops into an ocean basin. The East African rift basin is an example of an early stage in this process. Additionally, other types of basins such as trench basins, forearc basins, and foreland basins are associated with different tectonic settings such as subduction zones and the mass of volcanic ranges.
Ocean basins are relatively young geological features, not exceeding 180 million years in age. The formation of ocean basins can significantly influence the size of oceanic and continental plates, such as the expansion of the Atlantic Ocean due to the mid-Atlantic ridge spreading, which is not counteracted by subduction except in certain regions like the Caribbean. In contrast, the Pacific Ocean is slowly getting smaller because its formation rate is outpaced by subduction processes, such as under North America at the Cascadia Subduction Zone.
Over geological time, as oceanic crust subducts beneath continental crust, ocean basins can close, leading to continental collision and the potential formation of a supercontinent. Known cycles of supercontinent formation and breakup have occurred throughout Earth's history approximately every 500 million years.
What are the fields that have been impacted the most by these technologies?
Individual answers may vary, but your answer is expected to include some of the following points.
The impact of the Internet and the World Wide Web can be best understood by identifying the fields that have been influenced the most by these technologies. These may include education; banking, trade, and commerce; up-to-the minute weather reports; shopping; information exchange; socializing and self-expression; the arts; entertainment; navigation (maps); publishing; business networking.
The Texas Adoption Study examined what in relation to intelligence?
The Texas Adoption Project: adopted children and their intellectual resemblance to biological and adoptive parents. ... Intelligence test scores were obtained from parents and children in 300 adoptive families and compared with similar measures available for the biological mothers of the same adopted children.
What is NOT the purpose of the DSM?
Answer:
self diagnosing disorders upon yourself or others
Explanation:
The Diagnostic and Statistical Manual of Mental Disorders (DSM) is the handbook used by healthcare professionals in the United States and much of the world as the authoritative guide to the diagnosis of mental disorders. DSM contains descriptions, symptoms, and other criteria for diagnosing mental disorders.
What makes thermal imaging cameras useful?
Answer:
Image result for What makes thermal imaging cameras useful?
Thermal imaging cameras are handheld electronic devices with an integrated visual display, designed for detecting heat energy.
Explanation:
Answer:
During this pandemic thermal imaging cameras can help seek out people who are sick in public because the thermal camera shows that there body is red because there body temperature is higher. Hope this helps. *Brainliest appreciated
Explanation:
What is the focus on transcendent communication?
A)
confrontation and winning the conflict
B)
give and take to manage the conflict
C)
transforming opposing party's position
D)
redefining the issue