The normal force on a car traveling inside a vertical circular track differs at the top and bottom. At the top, the normal force is in the same direction as gravity, and at the bottom, it supports the car's weight against gravity plus provides the centripetal force. To find the normal force at the bottom, one must use the equations for circular motion taking into account the gravitational force.
Explanation:To determine the normal force on the car at the bottom of the track (point A), we must consider that the car is in circular motion, and at the top and bottom of the track, the forces acting on the car are different due to its position relative to the center of the circular path.
At the top of the track, the normal force and the weight of the car both act downwards. Since the car is in circular motion and is not accelerating vertically, the net force must be equal to the centripetal force required to keep the car moving in a circle. This can be represented by the equation N + mg = mv2/r at point B, where N is the normal force, m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car and r is the radius of the circular path.
At the bottom of the track, the normal force acts upwards while the weight of the car acts downwards. The normal force at the bottom must be greater than at the top because it must support the car's weight in addition to providing the centripetal force. So, the equation at point A is N - mg = mv2/r.
From the information provided, we know that the normal force at the top is 6.00 N, the mass of the car is 0.800 kg, and the gravitational acceleration is 9.8 m/s2. By writing out both equations for the normal force at the top and bottom, and substituting the known values, we can solve for the unknown normal force at the bottom of the track.
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body diagram shows the forces acting on the cart. The mass of the cart, to the nearest whole number, is _______ kg
Answer:
Mass of the cart = 146 kg
Explanation:
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.
The cart accelerates at 1.4 m/s² horizontally.
Horizontal force = Fcosθ = 250 cos35° = 204.79N
We have F = ma
Substituting
204.79 = m x 1.4
m = 146.28 kg = 146 kg
Mass of the cart = 146 kg
Answer:
146 kg
Explanation:
Correct on Edge 2021
How do single-celled decomposers get energy? A. They make their own food. B. They use a process called budding, C. They feed on living organisms. D. They break down dead organisms.
NEED ANSWER NOW GIVING 54 POINTS
Answer:
D
Explanation:
Why is a standard system of measurement important?
A. Scientists want to share measurements data that they can understand
B. Each country wants its own set of measurement standards.
C. Measurements are seldom shared with scientists in different countries
D. Scientists speak many different languages.
The correct answer is A. Scientists want to share measurements data that they can understand
Explanation:
In science, a standard system of measurement refers to a unified set or system of units that can be used internationally to measure data related to distance, temperature, energy, mass, etc. For example, the International System of Units establishes distance should be measured in meters rather than in inches, feet, etc. This guarantees all around the word scientist use the same units and can later share measurements despite language, culture or country because by using the same units scientists can understand data. Thus, a standard system of measurement is important because "scientists want to share measurements data that they can understand ".
Elements with atomic numbers above 95 are called _____ elements
A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that line makes a 20 degree angle relative to the horizontal. what is the tension in the line?
Answer : Tension in the line = 936.7 N
Explanation :
It is given that,
Mass of student, m = 65 kg
The angle between slackline and horizontal, [tex]\theta=20^0[/tex]
The two forces that acts are :
(i) Tension
(ii) Weight
So, from the figure it is clear that :
[tex]mg=2T\ sin\ \theta[/tex]
[tex]T=\dfrac{mg}{2\ sin\theta}[/tex]
[tex]T=\dfrac{65\ kg\times 9.8\ m/s^2}{2(sin\ 20)}[/tex]
[tex]T=936.7\ N[/tex]
Hence, this is the required solution.
The tension in the line is [tex]\boxed{932.18{\text{ N}}}[/tex].
Further Explanation:
Free body diagram is the graphical representation or illustration of all the forces applied on the body with their directions. This helps us to visualize all the applied forces on the body with their directions and make us possible to solve complex problems based on kinematics.
Tension is the force exerted by the wire, cable or string like object when someone pulls it.
The force in the downward direction is due to gravity called as weight. Its magnitude depends upon the mass of the body and expressed as [tex]mg[/tex]. the term [tex]g[/tex] is called acceleration due to gravity and it has a constant value of [tex]9.81{\text{ m/}}{{\text{s}}^2}[/tex].
Given:
The mass of the student is [tex]65\text{ kg}[/tex].
The sag angle with respect to the horizontal is [tex]20^\circ[/tex].
Concept:
The student walking in the slack line exerts tension on the slack line ties with two trees. There is tension on the both side of the slack line. The horizontal component of tension both side of the slack line will be canceling each other effects and the vertical component of tension both side of the slack line is balanced by the weight of the student.
It can be expressed as:
[tex]2T\sin\theta=mg[/tex]
Here, [tex]T[/tex] is the tension, [tex]\theta[/tex] is the sag angle, [tex]m[/tex] is the mass of object and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]20^\circ[/tex] for [tex]T[/tex], [tex]65\text{ kg}[/tex] for [tex]m[/tex] and [tex]9.81{\text{ m/}}{{\text{s}}^2}[/tex] for [tex]g[/tex] in the above equation.
[tex]\begin{aligned}2T\sin 20^\circ&=\left( {65{\text{ kg}}}\right)\left( {9.81{\text{ m/}}{{\text{s}}^2}} \right) \hfill\\T&=\frac{{\left({65{\text{ kg}}} \right)\left( {9.81{\text{ m/}}{{\text{s}}^2}}\right)}}{{2\sin 20^\circ}}\hfill\\&=932.18{\text{ N}}\hfill\\ \end{aligned}[/tex]
Therefore, the tension in the line is [tex]\boxed{932.18{\text{ N}}}[/tex].
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Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
65 kg, student, walking, slackline, length, webbing, stretched, between, two, trees, sags, 20 deg, angle, relative, horizontal, tension, line, 932.18 N.
#86 can an object be moving when its acceleration is zero? can an object be accelerating when its speed is zero?
Your town is thinking about building a nuclear power plant. You will be asked to vote on it. Which source would provide the most reliable information about the safety of nuclear power plants?
Answer:
A). The nuclear regulatory commission.
Explanation:
I am taking the test rnn.
Flvs
A cart for hauling ore out of a gold mine has a mass of 435 kg, including its load. the cart runs along a straight stretch of track that is sloped 4.77° from the horizontal. a donkey, trudging along and to the side of the track, has the unenviable job of pulling the cart up the slope with a 438-n force for a distance of 193 m by means of a rope that is parallel to the ground and makes an angle of 13.3° with the track. the coefficient of friction for the cart\'s wheels on the track is 0.0167. use g = 9.81 m/s2. find the work that the donkey performs on the cart during this process.
To practice problem-solving strategy 26.1 resistors in series and parallel. two bulbs are connected in parallel across a source of emf e = 11.0 v with a negligible internal resistance. one bulb has a resistance of 3.0 Ï , and the other is 3.0 Ï . a resistor r is connected in the circuit in series with the two bulbs. what value of r should be chosen in order to supply each bulb with a voltage of 2.4 v ?
To supply each bulb with a voltage of 2.4 V, the value of resistor r should be 0.6 ohms.
Explanation:To find the value of resistor r in order to supply each bulb with a voltage of 2.4 V, we can use the formula for voltage in a series circuit:
V = V1 + V2 + Vr
Since the voltage across each bulb should be 2.4 V, we have:
2.4 V = 2.4 V + 2.4 V + Vr
Simplifying the equation, we find that the value of resistor r should be 0.6 ohms.
An elevator is accelerating upward at a rate of 3.6 m/s2. a block of mass 24 kg hangs by a low-mass rope from the ceiling, and another block of mass 90 kg hangs by a low-mass rope from the upper block. (a) what are the tensions in the upper and lower ropes?
What eyeglasses would you prescribe for persons with the following conditions:
A near point of 56.6cm?
A far point of 56.6cm?
Final answer:
A person with a near point of 56.6cm is farsighted and needs convex lenses to correct their vision.
A person with a far point of 56.6cm is nearsighted and requires diverging lenses.
Explanation:
To correct for vision where a person has a near point of 56.6cm, they are likely farsighted. Farsightedness is corrected using convex lenses that converge the light before it hits the eye. This increases the eye's focusing power to bring nearby objects into clear vision.
For a person with a far point of 56.6cm, they are suffering from myopia, or nearsightedness. They require diverging lenses, typically negative diopter lenses, to spread out the light before it reaches the eye. This extends the far point of their vision, allowing them to see distant objects more clearly.
If the eyeglasses are held 1.50 cm from the eyes, we would need to consider the vertex distance in the lens formula to calculate the required lens power. The formula to determine the lens power needed, in diopters (D), is 1/f, where f is the focal length in meters. Since the eyeglasses are not in direct contact with the eye, the formula to find the effective focal length f' when considering vertex distance d is f' = f - d.
help me please in this
Which characteristics of Earth’s orbit are in agreement with Kepler’s second law? Check all that apply.
-Earth experiences the strongest gravitational force when it is farthest from the Sun.
-Earth experiences the strongest gravitational force when it is closest to the Sun. -Earth moves the greatest distance in thirty days when it is farthest from the Sun. -Earth moves the greatest distance in thirty days when it is closest to the Sun. -----Earth travels with the slowest tangential speed when it is farthest from the Sun. --Earth travels with the slowest tangential speed when it is closest to the Sun. ----------Earth sweeps out the same area in the same time frame anywhere in its orbit
Explanation :
The angular velocity of the planet in the elliptical orbit will vary. Its shows that the planet travel slower when farther from the sun, then faster when closer to the sun.
1. Yes, Earth experiences the strongest gravitational force when it is closest to the Sun.
2. Yes, Earth moves the greatest distance in thirty days when it is closest to the Sun.
3. Yes, Earth travels with the slowest tangential speed when it is farthest from the Sun.
4. Yes, Earth sweeps out the same area in the same time frame anywhere in its orbit
Kepler's second law : Kepler describe the motion of the planets around the sun. the line joining the planet and the sun sweeps out the same area in the same time.
The characteristics of Earth’s orbit that that agree and follow the pattern of Kepler’s second law are;
Earth experiences the strongest gravitational force when it is closest to the Sun.
Earth moves the greatest distance in thirty days when it is closest to the Sun.
Earth travels with the slowest tangential speed when it is farthest from the Sun.
Earth sweeps out the same area in the same time frame anywhere in its orbit
Kepler's second law of planetary motion can be regarded as one that describe the speed of a planet which moves in an elliptical orbit around the Sun. It states that there is equal areas as well as equal times between the sun and the planet sweeps, which implies that planet experience increase in speed as it get nearer the Sun.This helps in explaining how Earth travels with the slowest tangential speed onces its moving away from the Sun.Therefore, Earth usually have strongest gravitational force as it moves close to the sun.
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a 5.00 × 105 kg rocket is accelerating straight up. Its engines produce 1.50 × 107 of thrust, and air resistance is 4.50 × 106 N. What is the rocket’s acceleration?
The rocket’s acceleration is [tex]21m/s^2[/tex]
What is acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Acceleration is vector quantities as it has both magnitude and direction.
It is given by
[tex]a = \frac{v_f-v_0}{t}[/tex]
Where,
[tex]a =[/tex] average acceleration
[tex]v_f=[/tex] final velocity
[tex]v_0=[/tex] starting velocity
[tex]t =[/tex] elapsed time
What is Thrust?The force acting on an object perpendicular to the surface is called thrust. It is vector quantity and SI Unit of thrust is Newton.
[tex]\mathbf{T}=\mathbf{v} \frac{\mathrm{d} m}{\mathrm{d} t}[/tex]
Where,
[tex]T=[/tex] thrust
[tex]v=[/tex] velocity
[tex]dm=[/tex] change of mass
[tex]dt=[/tex] change in time
Given,
Mass of rocket, [tex]m = 5*10^5Kg[/tex]
Thrust,[tex]T = 1.5*10^7N[/tex]
Air resistance [tex]F_a= 4.5*10^6N[/tex]
The net upward force will be
[tex]F_n= T-F_a\\F_n= 1.5*10^7-4.5*10^6\\F_n= 1.05*10^7N[/tex]
Using
[tex]F = ma\\a = \frac{F}{m}\\a = \frac{1.05*10^7}{5*10^5}\\a = 21 m/s^2[/tex]
Thus the acceleration is [tex]21m/s^2[/tex].
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To calculate the rocket's acceleration, subtract air resistance from the engine's thrust to get the net force and then divide it by the rocket's mass according to Newton's second law. The acceleration is found to be 21 [tex]m/s^2[/tex].
To determine the rocket's acceleration, we must apply Newton's second law of motion, which states that force equals mass times acceleration (F = ma). In this scenario, we have two forces to consider: the rocket engine's thrust and the air resistance acting against it. The net force is calculated by subtracting the air resistance from the engine's thrust.
Firstly, we must find the net force acting on the rocket. To do this, we subtract the air resistance from the thrust:
Net Force = Thrust - Air Resistance
[tex]Net Force = 1.50 X 10^7 N - 4.50 X 10^6 N\\Net Force = 10.5 X 10^6 N[/tex]
Now, using Newton's second law, we set up the equation for acceleration (a = F/m), where F is the net force and m is the mass of the rocket:
Acceleration (a) = Net Force (F) / Mass (m)
[tex]Acceleration (a) = \frac{10.5 X 10^6 N}{5.00 X 10^5 kg}\\Acceleration (a) = 21 \ m/s^2[/tex]
Thus, the acceleration of the rocket is 21 meters per second squared.
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball? (Formula: KE = 1/2mv^2 )
0.1 kg
0.2 kg
0.4 kg
0.5 kg
The mass of a soccer ball traveling at a velocity of 50 m/s and has a kinetic energy of 500 J is 0.4kg.
How to calculate mass?The mass of a soccer ball can be calculated using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a soccer ball is traveling at a velocity of 50 m/s and has a kinetic energy of 500 J. The mass of the kinetic energy is as follows:
500 = ½ × m × 50²
500 = ½ × 2500m
500 = 1250m
m = 500/1250
m = 0.4kg
Therefore, the mass of a soccer ball traveling at a velocity of 50 m/s and has a kinetic energy of 500 J is 0.4kg.
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What can accurately be said about a resultant wave that displays both reinforcement and interference? A. The component waves have different frequencies. B. Maximum interference occurs where the troughs of the two component waves are in phase. C. Molecules remain in their normal positions at spots of reinforcement. D. The crests of the two component waves are in phase where interference occurs in the resultant wave. Mark for review (Will be highlighted on the review page)
A. The component waves have different frequencies.
Explanation;interference is one of the property of waves that occurs when two waves superpose to form a resultant wave of greater, lower, or the same amplitude.Interference occurs when two waves travelling in the same medium at the same time. It may be either a constructive or a destructive interference.Constructive interference occurs when the two waves are in phase and have the same frequency, the amplitudes are therefore, reinforced resulting to a constructive interference. However, if the two waves are out phase the result will be a destructive interference.what type of energy appears when a gymnast jumps on to a spring board? Question is on energy stores!Thanks
Answer:
gravity
Explanation: Because when you are jumping
Two children fight over a 200 g stuffed bear. the 25 kg boy pulls to the right with a 15 n force and the 20 kg girl pulls to the left with a 17 n force. ignore all other forces on the bear (such as its weight). at this instant, can you say what the acceleration of the bear is?
10 m/s² to the left.
Further explanationGiven:
The mass of a stuffed bear = 200 grams = 0.2 kg.The mass of a boy = 25 kg.The mass of a girl = 20 kg.A boy pulls to the right with a 15 N force.A girl pulls to the left with a 17 N force.Question:
What the acceleration of the bear is?
This is the case for implementing Newton's second law, i.e., 'the resultant force is proportional to the acceleration'. If we also use SI units then 'the resultant force is equal to the product of the mass and the acceleration'.
[tex]\boxed{\boxed{ \ F_{net} = m \cdot a \ }}[/tex]
The net force, i.e., [tex]F_{net}[/tex] is the resultant of all forces acting on an object, measured in newtons (kgm/s²).The mass measured is kilograms.The acceleration measured in m/s².Let's calculate the net force.
Referring to the horizontal axis marked a positive to the right, then
[tex]\boxed{ \ F_{net} = 15 - 17 = - 2 \ N \ }[/tex]
A negative sign indicates that the bear is moving to the left.
We continue to calculate the bear's acceleration. Remember, the mass that is applied is the mass of the bear that is accelerating.
[tex]\boxed{ \ F_{net} = m \cdot a \rightarrow a = \frac{F_{net}}{m_{bear}} \ }[/tex]
[tex]\boxed{ \ a = \frac{2 \ kg.ms^{-2}}{0.2 \ ms^{-2}} \ }[/tex]
Thus, the magnitude and direction of the acceleration is [tex]\boxed{\boxed{ \ a = 10 \ m/s^2 \ to \ the \ left \ }}[/tex]
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The acceleration of the bear is [tex]\boxed{10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}}[/tex] and its direction of motion is towards left side.
Further explanation:
The net force acting on the bear is equal to the difference between force applied by the girl on the bear and force applied by boy on the bear.
Given:
The mass of the bear is [tex]200{\text{ g}}[/tex].
The force applied by the boy on the bear, towards right side, is [tex]15{\text{ N}}[/tex].
The force applied by the girl on the bear, towards left side, is [tex]17{\text{ N}}[/tex].
The mass of the boy is [tex]25{\text{ kg}}[/tex].
The mass of the girl is [tex]20{\text{ kg}}[/tex].
Formula and concept used:
From the Newton’s law of motion,
[tex]\sum F=ma[/tex]
Here, [tex]\sum F[/tex] is the net force acting on the object, [tex]m[/tex] is the mass of object and [tex]a[/tex] is the acceleration.
The weight of the boy and the girl will not affect the net force applied by them on the bear.
The net force applied on the bear is equal to the difference between force applied by the girl and force applied by the boy because the forces applied by the boy and girl are parallel to each other but opposite in the direction.
Therefore, from the vector law, the resultant of the parallel vectors acting opposite in direction is equal to the difference between their magnitudes. The direction of the resultant can be specified as the direction of the vector on larger magnitude.
The expression for the net force on the bear is:
[tex]\boxed{ma={F_g} - {F_b}}[/tex] …… (1)
Here, [tex]{F_g}[/tex] is the force applied by the girl, [tex]{F_b}[/tex] is the force applied by the boy, [tex]m[/tex] is the mass of bear and [tex]a[/tex] is the acceleration of the bear.
Thus, the acceleration of the bear is [tex]\boxed{10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}}[/tex] and its direction of motion is towards left side.
Calculation:
Substitute the value of [tex]{F_g}[/tex], [tex]{F_b}[/tex] and [tex]m[/tex] in equation (1).
[tex]\begin{aligned}\frac{{200}}{{1000}}a&=17 - 15 \\0.2a&=2 \\a&=10{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}} \\ \end{aligned}[/tex]
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Answer detail:
Grade: College
Subject: Physics
Chapter: Dynamics of motion
Keywords:
Two children fighting, force on the bear, acceleration, newton's law, boy, girl, pulling bear towards left, 10m/s2, 10m/s^2, 10.0m/s2 , 10.0m/s^2, mass, net force, weight, magnitude and direction.
Is it true or false that radiation transfers energy by moving matter
Radiation transfers energy through electromagnetic waves, not by moving matter.
Explanation:The statement that 'radiation transfers energy by moving matter' is false.
Radiation transfers energy through electromagnetic waves, which do not require the movement of matter. Atoms and molecules emit electromagnetic radiation as their electrons move about and collide or vibrate in place. This radiation carries energy and can be absorbed by other material.
For example, in a hot material, the individual particles vibrate or move rapidly from collisions, resulting in more energetic waves being emitted. On the other hand, cool material generates lower-energy waves due to low-energy atomic and molecular motions.
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A compact car has a maximum acceleration of 4.0 m/s2 when it carries only the driver and has a total mass of 1200 kg . you may want to review ( pages 108 - 109) . part a what is its maximum acceleration after picking up four passengers and their luggage, adding an additional 400 kg of mass?
Answer : The maximum acceleration will be 3.0 [tex] m/sec^{2} [/tex].
Explanation : We can calculate the force using the formula given below;
F = m . a ;
(F - Force; m - mass and a - acceleration);
given in the problem; mass (1) - 1200 kg; acceleration (1) - 4 [tex] m/sec^{2} [/tex]
So, on substituting we get,
F = [tex] m_{1} a_{1} [/tex] = 1200 X 4 = 4800 N; we get F = 4800 N
Now, when mass 400 kg is added then mass (2) will be 1600 kg and acceleration has to be found;
Here, the force remains the same; so it can be equated;
[tex] m_{1} a_{1} [/tex] = [tex] m_{2} a_{2} [/tex];
So, 1200 X 4 = (1200 + 400) x [tex] a_{2} [/tex]
Therefore, the answer will be [tex] a_{2} [/tex] = 3.0 [tex] m/sec^{2} [/tex]
Which statement best describes the effect of scientific advances on society?
A. They always have a positive impact on society.
B. They are inspired by the needs of society.
C. they do not affect society beyond the community level.
D. They always increase the cost of produce and technology.
The statement which best describes the effect of scientific advances on society is that they are inspired by the needs of society. Thus, the correct option for this question is B.
What is Scientific advancement?Scientific advancement may be defined as the generation or discovery of knowledge that advances the understanding of science or technology. It is also known as technological advancement. This mechanism stimulates when technologies or applied sciences become more precise, accurate, efficient, or more powerful or capable.
According to the context of this question, scientific advancement allows us to develop new technologies, solve practical problems, and make informed decisions both individually and collectively.
This is because its products are so useful, and the process of science is intertwined with those applications. This proves that it plays a major role in society. New scientific knowledge may lead to new applications.
Therefore, the correct option for this question is B.
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Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at the point of ejection are 1 meter/second and 0.5 meters/second respectively, calculate the ratio of their horizontal distances of impact.
Final answer:
The ratio of the horizontal distances of impact for the two water jets is 2.
Explanation:
To calculate the ratio of the horizontal distances of impact, we need to first find the time of flight for each water jet. The time of flight can be determined using the formula:
time = distance / velocity
For the first water jet with a height of 50 centimeters and a velocity of 1 meter/second, the time of flight is:
time 1 = 0.5 meters / 1 meter/second
= 0.5 seconds
For the second water jet with a height of 100 centimeters and a velocity of 0.5 meter/second, the time of flight is:
time 2 = 1 meter / 0.5 meter/second
= 2 seconds
Now, we can calculate the horizontal distances of impact using the formula:
distance = velocity * time
For the first water jet, the horizontal distance of impact is:
distance 1 = 1 meter/second * 0.5 seconds
= 0.5 meters
For the second water jet, the horizontal distance of impact is:
distance2 = 0.5 meter/second * 2 seconds = 1 meter
Therefore, the ratio of their horizontal distances of impact is:
ratio = distance 2 / distance 1
= 1 meter / 0.5 meters
= 2
A particular interaction force does work wint inside a system. the potential energy of the interaction is u. which equation relates u and wint
ΔU = -Wint
Consdier the work of of interaction is W =m*g*h - equation -1
and the Potential energy U.
Final Potential energy Uf =0 , And the Initial Potential Energy Ui =m*g*h
Now we will write the equation for a Change in Potential energy ΔU,
ΔU = Uf - Ui
= 0-m*g*h
ΔU = -m*g*h --Equation 2
Now compare the both equation
Wint = -ΔU
we can rewrite the above equation
ΔU = -W.
So our Answer is ΔU = -W. .
You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. both strike the wall at speed v, but while the ball bounces off with no loss of speed, the clay sticks. what is the change in momentum of the clay and ball, respectively
A roller coaster car rapidly picks up speed as it Rolls down the slope. As it starts down the slope, its speed is 4 m/s. but three seconds later, at the bottom of the slope, its speed is 22 m/s what is the average acceleration?
What is the correct reference frame for a given situation?
Your friend says that inertia is a force that keeps things in their places, either at rest or motion. do you agree? why or why not? 1. disagree; inertia is a property of matter to behave this way, not some kind of force. 2. agree; only forces can keep things in their places. 3. disagree; inertia is a force that keeps things moving. 4. all are wrong. 5. agree; inertia is not a force that keeps things moving.
Answer:
1. Disagree; inertia is a property of matter to behave this way, not some kind of force.
Explanation:
Newton's first law of motion states that a body will remain in rest or in uniform motion while no external force is applied on it. What makes things to preserve their states of motion in inertia. It can be easy to understand remembering that the mass of the objects is the measure of their inertia. Since the mass is a property of matter so is the inertia.
José has just played a long, bruising football game but feels little fatigue or discomfort. His lack of pain is most likely caused by the release of
José's lack of pain is likely due to the release of endorphins, which are natural pain relievers produced by the body during intense physical activity.
José's lack of pain after a long and bruising football game is most likely due to the release of endorphins. Endorphins are neurotransmitters produced by the central nervous system and the pituitary gland. Known as the body's natural pain relievers, they are released in response to stress or discomfort to inhibit the transmission of pain signals in the brain and produce a feeling of euphoria.
This phenomenon is often referred to as a 'runner's high' and can occur during and after intense physical activity.
How many total atoms are in 0.250 g of p2o5?
Answer:
3.71 × 10²¹ atoms
Explanation:
The molar mass of P₂O₅ is 283.89 g/mol. The moles of P₂O₅ corresponding to 0.250 g of P₂O₅ are:
0.250 g × (1 mol/283.89 g) = 8.81 × 10⁻⁴ mol
In 1 mole of P₂O₅ there are 6.02 × 10²³ molecules of P₂O₅ (Avogadro's number). In 8.81 × 10⁻⁴ moles of P₂O₅, the molecules of P₂O₅ are:
8.81 × 10⁻⁴ mol × (6.02 × 10²³ molecule/ 1 mol) = 5.30 × 10²⁰ molecule
In 1 molecule of P₂O₅, there are 7 atoms (2 atoms of P and 5 atoms of O). In 5.30 × 10²⁰ molecules of P₂O₅, the number of atoms is:
5.30 × 10²⁰ molecule × (7 atom/1 molecule) = 3.71 × 10²¹ atom
Using the mnemonic roy g. biv to remember the colors of the rainbow in the order of wavelength illustrates the use of
Final answer:
The use of the mnemonic ROY G BIV to remember the colors of the rainbow in the order of wavelength illustrates the concept of color vision in physics.
Explanation:
The use of the mnemonic ROY G BIV to remember the colors of the rainbow in the order of wavelength illustrates the concept of color vision in physics. Visible light consists of different wavelengths, and our eyes perceive these wavelengths as different colors. The mnemonic helps us remember the order of colors in the rainbow from longest to shortest wavelength: red, orange, yellow, green, blue, indigo, and violet.
For example, red light has a longer wavelength than orange light, and violet light has a shorter wavelength than green light. The mnemonic ROY G BIV is a helpful tool for remembering this sequence of colors and their corresponding wavelengths.