A snowball accelerates at
23.4 m/s? when a 2.87 N
force is exerted on it. What is
the mass of the snowball?
(Unit = kg)

Because specular reflection occurs with a mirror, while diffuse reflection occurs with aluminium or iron plate

Explanation:

Reflection is a phenomenon typical of waves (such as light wave), that occurs when a wave bounces off the surface of a certain material, going back into the original medium at a certain angle, without changing speed, frequency or wavelength.

The direction of the reflected ray is given by the law of reflection, which states that:

Depending on the type of surface, two different types of reflection can occur:

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Answer:

Temperature increase = 2.1 [C]

Explanation:

We need to identify the initial data of the problem.

v = velocity of the copper sphere = 40 [m/s]

Cp = heat capacity = 387 [J/kg*C]

The most important data given is the fact that when the shock occurs kinetic energy is transformed into thermal energy, therefore it will have to be:

[tex]E_{k}=Q\\ E_{k}= kinetic energy [J]\\Q=thermal energy [J]\\Re-employment values and equalizing equations\\\\\frac{1}{2} *m*v^{2}=m*C_{p}*dT  \\The masses are canceled \\\\dT=\frac{v^{2}}{C_{p} *2} \\dT=2.1 [C][/tex]

The correct option is d. 2.1°C. The increase in temperature of the copper sphere was approximately [tex]\( 2.1 \)[/tex]°C, which corresponds to answer choice D).

Given:

- Initial kinetic energy (KE) of the copper sphere = [tex]\( \frac{1}{2} mv^2 \)[/tex]

- Specific heat capacity of copper, [tex]\( c = 387 \)[/tex] J/(kg·°C)

The entire kinetic energy is converted into thermal energy, [tex]\( Q = mc\Delta T \)[/tex], where [tex]\( \Delta T \)[/tex] is the increase in temperature.

1. Calculate the initial kinetic energy:

[tex]\[ KE = \frac{1}{2} mv^2 \][/tex]

2. Set up the equation equating kinetic energy to thermal energy:

[tex]\[ \frac{1}{2} mv^2 = mc\Delta T \][/tex]

3. Solve for [tex]\( \Delta T \)[/tex]:

[tex]\[ \Delta T = \frac{\frac{1}{2} mv^2}{mc} \][/tex]

4. Substitute the given values:

[tex]\[ \Delta T = \frac{\frac{1}{2} \times m \times (40)^2}{m \times 387} \][/tex]

5. Simplify the expression:

[tex]\[ \Delta T = \frac{800 \times m}{387 \times m} \]\[ \Delta T = \frac{800}{387} \]\[ \Delta T \approx 2.065 \ \textdegree C} \][/tex]

Rounding to one decimal place, the increase in temperature [tex]\( \Delta T \)[/tex] is approximately  [tex]\( 2.1 \)[/tex]°C.

Therefore, the increase in temperature of the copper sphere was approximately [tex]\( 2.1 \)[/tex]°C, which corresponds to answer choice D).

A copper sphere was moving at 40 m/s when it hit another object. This caused all of the KE to be converted into thermal energy for the copper sphere. If the specific heat capacity of copper is 387 J/(kg ⋅ C°), what was the increase in temperature?

a. 0.23 C°

b. 0.81 C°

c. 1.3 C°

d. 2.1 C°

Answer:

Ptolemy

Explanation:

Answer:

the name of the 2d Century Roman Scientist and Astrologer who created a set of "Handy  Tables of data to compute the position of the Sun, moon and stars" is:

Explanation:

Ptolemy lived between the year 100 and the year 170 (2nd century), time in which he contributed different bases to astronomy, geography and even astrology. In the first-mentioned area, his geocentric model can be highlighted, with which he mentioned that the Earth It was the center of the universe and therefore it was motionless in the middle of it, and other stars such as the sun or the moon revolved around it and, although in that reasoning it was wrong, it provided fairly accurate means for the time in which the displacement and retrogradation of the planets can be calculated.

Answer:

[tex]\displaystyle y_m=3.65m[/tex]

Explanation:

Motion in The Plane

When an object is launched in free air with some angle respect to the horizontal, it describes a known parabolic path, comes to a maximum height and finally drops back to the ground level at a certain distance from the launching place.

The movement is split into two components: the horizontal component with constant speed and the vertical component with variable speed, modified by the acceleration of gravity. If we are given the values of [tex]v_o[/tex] and [tex]\theta\\[/tex] as the initial speed and angle, then we have

[tex]\displaystyle v_x=v_o\ cos\theta[/tex]

[tex]\displaystyle v_y=v_o\ sin\theta-gt[/tex]

[tex]\displaystyle x=v_o\ cos\theta\ t[/tex]

[tex]\displaystyle y=v_o\ sin\theta\ t -\frac{gt^2}{2}[/tex]

If we want to know the maximum height reached by the object, we find the value of t when [tex]v_y[/tex] becomes zero, because the object stops going up and starts going down

[tex]\displaystyle v_y=o\Rightarrow v_o\ sin\theta =gt[/tex]

Solving for t

[tex]\displaystyle t=\frac{v_o\ sin\theta }{g}[/tex]

Then we replace that value into y, to find the maximum height

[tex]\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2[/tex]

Operating and simplifying

[tex]\displaystyle y_m=\frac{v_o^2\ sin^2\theta }{2g}[/tex]

We have

[tex]\displaystyle v_o=20\ m/s,\ \theta=25^o[/tex]

The maximum height is

[tex]\displaystyle y_m=\frac{(20)^2(sin25^o)^2}{2(9.8)}=\frac{71.44}{19.6}[/tex]

[tex]\displaystyle y_m=3.65m[/tex]

Answer:

Not balanced

Explanation:

The force pulling the object up is applying less force than the object pulling down, this means the object will move down

Answer:

Not balanced

Explanation:

Answer:

Yes

Explanation:

This is negative acceleration, also known as deceleration where the speed is reduced from high to low at a specific duration.

Answer:

The height from which the egg is dropped is 68.54 m.

Explanation:

Given:

Initial velocity of egg is, [tex]u=0\ m/s[/tex](Dropped means initial velocity is 0)

Time taken is, [tex]t=3.74\ s[/tex]

Acceleration experienced by egg is due to gravity, [tex]a=g=9.8\ m/s^2[/tex]

The height from which the egg is dropped is, [tex]d=?[/tex]

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

[tex]d=ut+\frac{1}{2}at^2[/tex]

Plug in all the given values and solve for 'd'. This gives,

[tex]d=0+\frac{1}{2}\times 9.8\times (3.74)^2\\\\d=\frac{1\times 9.8\times 13.9876}{2}\\\\d=\frac{137.078}{2}\\\\d=68.54\ m[/tex]

Therefore, the height from which the egg is dropped is 68.54 m.

Answer:

The force exerted on the rock by the eruption is, D. 902.5 N

Explanation:

Given data,

The mass of the rock ejected by the volcano, m = 95 kg

The acceleration of the ejected rock, a 9.5 m/s²

The force acting on an object is defined as the product of the mass and its acceleration. It is given by the relation,

                                 F = m x a

                                    = 95 x 9.5

                                    = 902.5 N

Hence, the force exerted on the rock by the eruption is, F = 902.5 N

Answer:

b. 40V , 40V

Explanation:

Connections are as per the figure.

As total current through source is 4A , current through each lamp is 1A.

As total resistance of the circuit is 10Ω ,resistance of each bulb is 40Ω because in case of a parallel circuit in which identical objects are connected , [tex]R_{eff} = \frac{R}{n}[/tex] where R is the resistance of each bulb and n is the number of bulbs.

As per Ohm's law , voltage of the source =IR = 4×10 =40V.

We can see from the figure that if the voltage across the source is 40V , the voltage across each bulb is also 40V.

Answer:

-2.5 m/s^2

Explanation:

From a velocity-time graph, the acceleration can be determined by finding the gradient of the straight line graph.

Acceleration=(Change in velocity)/(time)

Where change in velocity = final velocity-initial velocity.

Hence, from the graph,

we can see (10-40)/12 = -2.5

Answer:

-2.5

Explanation:

just did this one

Answer:

The net force acting on the body, F = 11 N

Explanation:

Given data,

The force acting on the body, f = 5 N

Another force acting on the body, f' = 6 N

The direction of both forces is in the same direction.

The net force is given by the resultant vector,

                             [tex]F= \sqrt{f^{2} + f'^{2} + 2 ff' Cos \theta}[/tex]

                             [tex]F= \sqrt{f^{2} + f'^{2} + 2 ff'[/tex]   (∵ θ = 0)

                             [tex]F=\sqrt{(f + f')^{2} }[/tex]

                             F = f + f'

                                = 5 N + 6 N

                                = 11 N

Hence, the net force acting on the body, F = 11 N

Explanation:

total consumption in a month - 1000×2×28= 56000 w-hrs

1 unit = 1Kwh

total unit in month = 56000/1000 = 56

total cost = 56×3 = 168 rs

Answer:

In space, astronauts lose fluid volume—including up to 22% of their blood volume. Because it has less blood to pump, the heart will atrophy.Under the effects of the earth's gravity, blood and other body fluids are pulled towards the lower body.

Explanation:

Answer:

Explanation:

a )

mass m = 275 kg , final velocity v = 41 m/s

distance,  s = 49.3 m

acceleration a = ?

v² = u² + 2as

41² = 2 a x 49.3

a = 17.05 m/s²

time t = v - u / a

t = 41 / 17.05

= 2.4 s

b )

force = mass x acceleration

= 275 x 17.05

= 4688.75 N

c ) maximum range = v² / g

= 41²/9.8

= 171.5 m

height ( maximum )

v² sin²45 / 2g ( at angle of projectile of 45 , range and height is maximum.)

= 41²/ 2 x 9.8

= 85.76 m

d )

Let the angle be θ

height h = v² sin²θ / 2g

50 = 41² sin²θ /2g

sin²θ  = .58

sinθ = .76

50°.

The following can happen to solar radiation when it enters Earth's atmosphere:

Answer: Option A, B, and C

Explanation:

Solar radiation causes an abnormal effect in humans, if they are exposed directly. All the solar radiation emitted by the sun, does not hit us directly. The energy while reaching us passes through different levels of spheres.

Atmosphere contains nitrogen and oxygen molecules, which absorb some of the solar radiation. And some of it is reflected back by the clouds.  And some of the remaining energy is absorbed by the surface of the earth. Likewise, almost 71% of the radiation is absorbed.

Answer: It is absorbed by Earth.

It is reflected by clouds.

It is reflected by glacial ice.

Explanation: Solar radiation is composed of electromagnetic waves that carry energy.

White or shiny surfaces usually reflect some waves (actually almost every surface reflects electromagnetic waves)

So some of the radiation is reflected by clouds or by glacial ice.

The bigest part is actually absorbed by Earth (this is why during the day the temperature increases, a biggest amount of radiation is being absorbed)

Answer:

cell wall and cell membrane

Answer:

Cell wall and Cell membrane.

Explanation:

The cell membrane controls what goes in and out of the cell

Answer:

50 J

Explanation:

Work, W=Fd where F is the applied force and d is the distance

Substituting 10 N for F and 5 m for d then work done on the book can be expressed as

W=10 N* 5 m=50 Nm= 50 J

Therefore, the work done is equivalent to 50 J

A pendulum clock runs at a rate proportional to the inverse square root of the acceleration due to gravity. Since gravity is weaker on the Moon, a clock calibrated for Earth's gravity will run slower on the Moon, taking the square root of 9.8/1.6 hours to complete one revolution, which is answer option C  the square root of 9.8/1.6 hours.

The rate at which a pendulum clock runs is inversely proportional to the square root of the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s², while on the Moon, it is about 1.63 m/s². According to the formula for the period of a pendulum (T = 2π √(L/g) where L is the length of the pendulum and g is the acceleration due to gravity), if a clock keeps correct time on Earth, on the Moon it would run at a rate that is the square root of the ratio of the accelerations (the square root of 9.8/1.63). This would mean, for every hour on Earth, the clock on the Moon would show a time of C) the square root of 9.8/1.6 hours.

Answer:

0.64 kgwt

Explanation:

You should check that the diameters of the neck and bottom are correct.  That is a very small bottle, and the neck shouldn't be bigger than the bottom.

The pressure on the cork = the pressure on the bottom

P₁ = P₂

F₁ / A₁ = F₂ / A₂

F₁ / (π r₁²) = F₂ / (π r₂²)

F₁ / r₁² = F₂ / r₂²

(1 kgwt) / (0.5 cm)² = F / (0.4 cm)²

F = 0.64 kgwt

Round as needed.

Answer:

562.5 m

Explanation:

Displacement is area under the graph of velocity.

d = 10*25 + 25^2/2 = 562.5 m

The displacement of the object is 550 meters.

The velocity graph shows that the object is moving in a positive direction for the first 25 seconds.

The velocity is constant at 10 m/s for the first 10 seconds, and then it increases to 20 m/s for the next 15 seconds.

The area under the velocity graph is equal to the displacement of the object. The area of a triangle is equal to (1/2) * base * height. In this case, the base of the triangle is 25 seconds and the height is 20 m/s.

Therefore, the area of the triangle is (1/2) * 25 * 20 = 250 m^2.

The object is also moving in a positive direction for the next 10 seconds, but the velocity is constant at 20 m/s. Therefore, the area under the velocity graph for these 10 seconds is a rectangle with a base of 10 seconds and a height of 20 m/s.

The area of the rectangle is 10 * 20 = 200 m^2.

The total area under the velocity graph is 250 m^2 + 200 m^2 = 550 m^2. Therefore, the displacement of the object is 550 meters.

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Answer:

-20°C

Explanation:

ΔQ = m c Δt

here ΔQ is heat supplied which is 10 calories , m is mass which is 2 g , c is specific heat capacity of ice which is 0.5 cal/(g C°), Δt is change in temperature which here is to be calculated.

re arranging the equation  we get

Δt = ΔQ/(mc)

   = 10/ ( 2 × 0.5)

 =  10/1

  = 10 C°

final temperature = -30 +10 = -20°C

hence option is A

Answer:Silicon

Explanation:

You add up the protons and neutrons and then look at the element paper

Answer:

Gracitational potential energy of the car is 84600J or 84.6KJ

Explanation:

Given that the formula of G.P.E is mgh. So use this formula to find gravitational potential energy :

G.P.E = mgh

m = 1800kg

g = 10m/s

h = 4.7m

G.P.E = 1800×10×4.7

= 84 600J (joules)

= 84.6KJ (kilo joules)

Explanation:

V=40m/s

Vy=V.sina=40.sin20=40 . 0.342=13.68m/s

Vx=V.cosa=40.cos20=40 . 0.766=30.64m/s

Projectile travels during 5 seconds and the ramge becomes:

x=V.t=30.64 . 5=153.2m

the ocean creates tides accosiated with the ocean

Answer:

a) Andrea's initial momentum, 200 kg m/s

b) Andrea's final momentum, 0

c) Impulse,  = - 200 Ns

d) The force that the seat belt exerts on Andrea, - 400 N

Explanation:

Given data,

The initial velocity of the car is, u = 40 m/s

The mass of Andrea, m = 50 kg

The time period of deceleration, a = 0.5 s

The final velocity of the car, v = 0

a) Andrea's initial momentum,

               p = mu

                  = 50 x 40

                  = 200 kg m/s

b) Andrea's final momentum

                  P = mv

                     = 50 x 0

                    = 0 kg m/s

c) Impulse

                   I = mv - mu

                     = 0 - 200

                    = - 200 Ns

The negative sign indicated that the momentum is decreased.

d) The force that the seat belt exerts on Andrea

                   F = (mv - mu)t

                     = (0 - 200) / 0.5

                     = - 400 Ns

Hence,the force that the seat belt exerts on Andrea is, - 400 N

Answer:

1 ) density = 1200[kg/m^3]

2)

a) wide = 0.35[m]

long = 1,1 [m]

thick  = 0.015 [m]

b)

Volume = 0.005775[m^3]

mass = 15.6 [kg]

Explanation:

1)

This problem can be solved by knowing the definition of density which is expressed as the relation between mass and volume, so that the following equation can give us the density value.

[tex]density=\frac{m}{V}\\ where:\\m= mass [kg]\\V= volume [m^3]\\replacing\\density=\frac{90}{0.075} \\density=1200 [kg/m^3][/tex]

2)

The following data is equal to:

a)

wide = 35 [cm] = 0.35[m]

long = 11 [dm] = 11 [decimeters] = 1,1 [m]

thick = 15 [mm] = 0.015 [m]

b)

We know that density is the relationship between mass and volume of a body.

So the volume will be:

volume = wide * long * thick = (0.35*1.1*0.0015) = 0.005775[m^3]

[tex]the mass will be:\\m=density*volume\\m=2700[kg/m^3]*0.005775[m^3]\\m=15.6[kg][/tex]

Answer :

(1) The density of asphalt is, [tex]1200kg/m^3[/tex]

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

Part 1 :

As we are given:

Mass of block = 90 kg

Volume of block = [tex]0.075m^3[/tex]

Formula used :

[tex]\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}[/tex]

Now put all the given values in this formula, we get:

[tex]\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3[/tex]

Thus, the density of asphalt is, [tex]1200kg/m^3[/tex]

Part 2(a) :

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

Part 2(b) :

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

[tex]\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}[/tex]

[tex]2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}[/tex]

[tex]\text{Mass of aluminium}=15.59kg[/tex]

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Answer:

denisity = 52.33 g/c[tex]m^{3}[/tex]

Explanation:

Density:

[tex]d = \frac{m}{v}[/tex]

We have that m = 785 and that v = 15 c[tex]m^{3}[/tex].

[tex]d = \frac{785}{15}[/tex]

d = 52.33 [tex]m^{3}[/tex]

The density of the object, calculated using the formula Density = Mass/Volume with the given mass of 785g and volume of 15cm³, is found to be 52.33 g/cm³.

The subject in question is about determining the density of an object, which falls under the area of Physics. In physics, density is defined as mass per unit volume, and the formula for calculating density is Density (ρ) = Mass (m)/Volume (V). In the SI system, we often use grams per cubic centimeter (g/cm³) to express the density of solids and liquids.

To apply the formula to this question, we take the mass of the object, which is given as 785g, and then divide this by the volume of the object, given as 15cm³. Thus, the calculation becomes: ρ = 785g / 15 cm³.

The calculated density, to 2 decimal places, is 52.33 g/cm³. Therefore, the object in question has a density of 52.33 g/cm³.

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