Final answer:
The first stone takes 2.00 seconds to reach the ground. The height of the building can be calculated using h = (1/2)gt^2. The speed of the first stone just before it hits the ground is given by v = gt.
Explanation:
Question:
A stone is dropped from the roof of a building; 2.00s after that, a second stone is thrown straight down with an initial speed of 25.0m/s, and the two stones land at the same time. How long did it take the first stone to reach the ground? How high is the building? What are the speeds of the two stones just before they hit the ground?
Answer:
For the first stone to reach the ground at the same time as the second stone, it must take 2.00 seconds. This is because both stones land at the same time, and the second stone was thrown after 2.00 seconds. The height of the building can be calculated using the equation h = (1/2)gt^2, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time (2.00 seconds). The speed of the first stone just before it hits the ground is calculated using the equation v = gt, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time (2.00 seconds). The speed of the second stone just before it hits the ground is given as 25.0 m/s.
The term sink refers to _____.
If 8.800 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temperature of the water?
the final temperature of the water is approximately [tex]\(4.009 C\)[/tex].
To find the final temperature of the water after adding the heat produced from burning 8.800 g of [tex]\(C_6H_6\)[/tex] (benzene), we'll use the concept of heat transfer and the specific heat capacity of water.
The heat released from the combustion of [tex]\(C_6H_6\)[/tex] will be transferred to the water, causing its temperature to increase. We'll use the equation:
Q = mcΔT
Where:
- Q is the heat transferred (in Joules)
- m is the mass of the water (in grams)
- c is the specific heat capacity of water (4.18 J/g°C)
- ΔT is the change in temperature of the water (in °C)
First, we need to calculate the heat released from burning [tex]\(C_6H_6\)[/tex].
Given:
- Mass of [tex]\(C_6H_6\)[/tex] burned, [tex]\(m_{C_6H_6} = 8.800 \, g\)[/tex]
- Heat of combustion of [tex]\(C_6H_6\)[/tex], [tex]\(ΔH_{comb} = -3263 \, kJ/mol\)[/tex]
Using the molar mass of [tex]\(C_6H_6\) (\(M_{C_6H_6} = 78.11 \, g/mol\))[/tex], we can find the number of moles of [tex]\(C_6H_6\)[/tex] burned and then calculate the heat released.
Next, we'll use the equation for heat transfer to find the change in temperature of the water, and then add this change to the initial temperature of the water to get the final temperature.
Let's calculate step by step.
Step 1: Calculate the heat released from burning [tex]\(C_6H_6\)[/tex].
1. Find the number of moles of [tex]\(C_6H_6\)[/tex]:
[tex]\[n_{C_6H_6} = \frac{m_{C_6H_6}}{M_{C_6H_6}} = \frac{8.800 \, g}{78.11 \, g/mol} \approx 0.1128 \, mol\][/tex]
2. Calculate the heat released from burning [tex]\(C_6H_6\)[/tex] using its molar enthalpy of combustion:
[tex]\[Q_{comb} = n_{C_6H_6} \times ΔH_{comb} = 0.1128 \, mol \times (-3263 \, kJ/mol)\][/tex]
[tex]\[Q_{comb} = -368.112 \, kJ\][/tex]
Step 2: Calculate the change in temperature of the water.
1. Use the equation for heat transfer:
[tex]\[Q_{water} = mcΔT\][/tex]
Where [tex]\(Q_{water}\)[/tex] is the heat absorbed by water, \(m\) is the mass of water, c is the specific heat capacity of water, and \(ΔT\) is the change in temperature of water.
2. Rearrange the equation to solve for [tex]\(ΔT\)[/tex]:
[tex]\[ΔT = \frac{Q_{comb}}{mc}\][/tex]
Given:
- [tex]\(m_{water} = 5691 \, g\)[/tex]
- [tex]\(c_{water} = 4.18 \, J/g°C\)[/tex]
3. Substitute the values and calculate \(ΔT\):
[tex]\[ΔT = \frac{-368.112 \times 10^3 \, J}{(5691 \, g) \times (4.18 \, J/g°C)}\][/tex]
[tex]\[ΔT \approx -16.991°C\][/tex]
Step 3: Find the final temperature of the water.
Given:
- Initial temperature of water, [tex]\(T_{initial} = 21°C\)[/tex]
The final temperature [tex](\(T_{final}\))[/tex] of the water can be found by adding the change in temperature [tex](\(ΔT\))[/tex] to the initial temperature [tex](\(T_{initial}\))[/tex]:
[tex]\[T_{final} = T_{initial} + ΔT\][/tex]
[tex]\[T_{final} = 21°C - 16.991°C\][/tex]
[tex]\[T_{final} \approx 4.009°C\][/tex]
Therefore, the final temperature of the water is approximately [tex]\(4.009 C\)[/tex].
how does the structure of covalent bonds affects their structure.
The acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on Earth’s surface. The weight of a space probe on the surface of Mars is about
Final answer:
On Mars, the acceleration due to gravity is about one-third of that on Earth, which means an object weighs significantly less on Mars compared to its weight on Earth.
Explanation:
The question pertains to the acceleration due to gravity on the surface of Mars compared to Earth. On Mars, the acceleration due to gravity is about one-third of that on Earth. Specifically, the gravitational acceleration on Mars is approximately 3.71 m/s², while on Earth, it is about 9.81 m/s². Thus, an object on Mars weighs significantly less than it does on Earth. For example, if a space probe weighs 100 pounds on Earth, on Mars, it would weigh roughly 38 pounds because the acceleration due to gravity on Mars is 0.38 that of Earth's gravity. This difference significantly impacts how objects move and respond to forces on Mars compared to Earth.
Which of the following is a heterogeneous mixture?
A) vinegar and water
B) milk
C) Oil and vinegar
D) Air
Ne(g) effuses at a rate that is ______ times that of xe(g) under the same conditions.
Ne (g) effuses at a rate that is [tex]\boxed{{\text{2}}{\text{.6}}}[/tex] times that of Xe (g) under the same conditions.
Further Explanation:
Graham’s law of effusion:
Effusion is the process by which molecules of gas travel through a small hole from high pressure to the low pressure. According to Graham’s law, the effusion rate of a gas is inversely proportional to the square root of the molar mass of gas.
The expression for Graham’s law is as follows:
[tex]\boxed{{\text{R}}\propto\dfrac{1}{{\sqrt {{\mu }} }}}[/tex]
Here,
R is the rate of effusion of gas.
[tex]{{\mu }}[/tex] is the molar mass of gas.
Higher the molar mass of the gas, smaller will be the rate of effusion and vice-versa.
The rate of effusion of Ne is expressed as follows:
[tex]{{\text{R}}_{{\text{Ne}}}} \propto \dfrac{1}{{\sqrt {{{{\mu }}_{{\text{Ne}}}}} }}[/tex]
......(1)
Here,
[tex]{{\text{R}}_{{\text{Ne}}}}[/tex] is the rate of effusion of Ne.
[tex]{{{\mu }}_{{\text{Ne}}}}[/tex] is the molar mass of Ne.
The rate of effusion of Xe is expressed as follows:
[tex]{{\text{R}}_{{\text{Xe}}}}\propto\dfrac{1}{{\sqrt{{{{\mu }}_{{\text{Xe}}}}}}}[/tex]
......(2)
Here,
[tex]{{\text{R}}_{{\text{Xe}}}}[/tex] is the rate of effusion of Xe.
[tex]{{{\mu }}_{{\text{Xe}}}}[/tex] is the molar mass of Xe.
On dividing equation (1) by equation (2),
[tex]\dfrac{{{{\text{R}}_{{\text{Ne}}}}}}{{{{\text{R}}_{{\text{Xe}}}}}}=\sqrt {\dfrac{{{{{\mu }}_{{\text{Xe}}}}}}{{{{{\mu }}_{{\text{Ne}}}}}}}[/tex] ......(3)
Rearrange equation (3) to calculate [tex]{{\text{R}}_{{\text{Ne}}}}[/tex].
[tex]{{\text{R}}_{{\text{Ne}}}}=\left( {\sqrt {\dfrac{{{{{\mu }}_{{\text{Xe}}}}}}{{{{{\mu }}_{{\text{Ne}}}}}}} } \right){{\text{R}}_{{\text{Xe}}}}[/tex] ......(4)
The molar mass of Ne is 20.17 g/mol.
The molar mass of Xe is 131.29 g/mol.
Substitute these values in equation (4).
[tex]\begin{aligned}{{\text{R}}_{{\text{Ne}}}}&= \left({\sqrt {\frac{{{\text{131}}{\text{.29}}}}{{{\text{20}}{\text{.17}}}}} } \right){{\text{R}}_{{\text{Xe}}}}\\&= \left( {\sqrt {6.50917} } \right){{\text{R}}_{{\text{Xe}}}}\\&= 2.5513{{\text{R}}_{{\text{Xe}}}}\\&\approx 2.6{{\text{R}}_{{\text{Xe}}}}\\\end{aligned}[/tex]
Therefore the rate of effusion of Ne is 2.6 times the rate of effusion of Xe.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Ideal gas equation
Keywords: Effusion, rate of effusion, molar mass, Ne, Xe, 2.6 times, Graham’s law, inversely proportional, square root.
Neon effuses faster than xenon due to its lighter molar mass, and the effusion rate for neon will be larger than that for xenon, resulting in a smaller effusion time for neon.
Explanation:The student's question pertains to the comparison of the effusion rates of neon (Ne) and xenon (Xe) gases under the same conditions. The effusion rate of a gas is inversely proportional to the square root of its molar mass, according to Graham's law of effusion. Given that neon is lighter than xenon, it will effuse at a faster rate. Using the provided effusion time calculations, if it takes 243 seconds for xenon to effuse, then by solving for the time it would take for the same amount of neon to effuse using the ratio of the square roots of their molar masses, we determine the time for neon to be approximately 95.3 seconds.
This result is expected because the lighter a gas is, the faster it should effuse, making the effusion rate for neon larger than that for xenon, and consequently, the time for effusion is smaller for neon than xenon as presented in the example calculation.
Name all of the alkene isomers, c6h12, that contain a methylene group.
Actually, a methylene group is simply any compound which contains a C=C double bond group and the rest are single bonded carbon groups. Some example of the isomers of C6H12 which contains methylene group is:
1-hexene
2,3-dimethyl-2-butene
2,3-dimethyl-1-butene
2-methyl-2-pentene
trans-2-hexene
4-methyl-1-pentene
cis-2-hexene
trans-3-hexene
2-ethyl-1-butene
2-methyl-1-pentene
3,3-dimethyl-1-butene
4-methyl-cis-2-pentene
cis-3-methyl-2-pentene
trans-3-methyl-2-pentene
What is the most common type of climate/ecosystem found in the Congo River basin?
What types of scientific field quantities are there
Could you please help
Calculate the number of Li atoms in 5.1 moles of Li
The number of Li atoms in 5.1 moles of Li is 3.07 x 10²⁴ atoms.
What are atoms?Atoms are defined as the smallest piece of matter that can be separated without sending electrically charged particles flying.
It can also be defined as the smallest piece that carries an element's characteristics. Subatomic particles, which make up an atom, are uncreatable.
There are various types of atoms.
DescriptionStableIsotopesRadioactive IonsAntimatterIn a chemical reaction, atoms cannot be formed or destroyed since they are indivisible units. The mass and chemical characteristics of each atom of a specific element are the same. Different elements' atoms have varying weight and chemical characteristics. Compounds are created when atoms combine in ratios of small whole numbers.
Moles of Li = 5.1 x 6.022 x 10²³
= 3.07 x 10²⁴ atoms.
Thus, the number of Li atoms in 5.1 moles of Li is 3.07 x 10²⁴ atoms.
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A student makes observations when water is added to a blue solution of copper sulfate. The student makes only 1 observation: the solution changes to a lighter shade of blue. Is this an example of a chemical reaction? Explain your reasoning.
No, I believe this is not an example of a chemical reaction. What we actually see here is a physical change of the solution. Since we are adding more water to an aqueous solution which is also made up mostly of water, what we are simply basically doing is dilution. Since the solution is being diluted, so definitely the color turned lighter.
A 31.1 g wafer of pure gold, initially at 69.3 _c, is submerged into 64.2 g of water at 27.8 _c in an insulated container. what is the final temperature of both substances at thermal equilibrium?
The final temperature at thermal equilibrium can be calculated using the concept of conservation of energy and the specific heat capacities of gold and water.
Explanation:To find the final temperature of the gold and water system when they reach thermal equilibrium, we need to apply the concept of conservation of energy. This concept suggests that in an isolated system, the heat lost by the hot object (the gold) will be equal to the heat gained by the cold object (the water). Since the system is at equilibrium, the heat lost is equal to the heat gained, hence the formula: Cgold × mgold × (Tinitial, gold - Tfinal) = -Cwater × mwater × (Tfinal - Tinitial, water), where Cgold and Cwater are the specific heat capacities of gold and water, T is the temperature and m is the mass.
We also need to know the specific heat capacities of gold and water. The specific heat capacity of gold is 0.129 J/g °C and for water, it's 4.18 J/g °C. Substituting those values along with the original temperatures and masses, we can solve for the final temperature, Tfinal.
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Bismuth oxide reacts with carbon to form bismuth metal: bi2o3(s) + 3c(s) → 2bi(s) + 3co(g) when 689 g of bi2o3 reacts with excess carbon, (a) how many moles of bi form? 2.957 mol bi (b) how many grams of co form? g co
CO mass = 4,435. 18 = 79,839 grams
Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements etc.
In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example the substance level or molecular formula of hydrate.
In stockiometry therein includes
relative atomic mass (Ar) and relative molecular mass (Mr)
Mr. AxBy = (x.Ar A + y. Ar B)
Reactions that occur:
Bi₂O₃ (s) + 3C (s) → 2Bi (s) + 3CO (g)
We specify mole Bi₂O₃Mr Bi₂O₃ = 2. ar bi + 3. Ar O
Mr Bi₂O₃ = 2. 209 + 3. 16
Mr. Bi₂O₃= 466
mole Bi₂O₃ = gram / Mr
mole = 689/466
mole 1.4785
A. Comparison of Bi reaction coefficients: Bi₂O₃ = 1: 2, then Bi moles = 2. 1,4785 = 2, 957Comparison of Bi reaction coefficients: Bi₂O₃ = 1: 2,
B. While the number of moles CO = 3 x 1.4785 = 4,435Mr. CO = 12 + 16 = 18
mass CO = mole. Mr
CO mass = 4,435. 18 = 79,839 grams
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The scattering of light by a colloidal suspension is called the
Answer: The correct answer is Tyndall effect.
Explanation:
Colloids are defined as the mixtures where the size of the particle is within the range of 2nm to 1000 nm. In these mixtures, physical boundary is seen between the dispersed phase and dispersed medium.
Tyndall effect is defined as the effect in which scattering of light takes place by the particles present in a colloid or in very fine suspension.
For Example: Scattering of sunlight by clouds
Thus, the correct answer is Tyndall effect.
The scattering of light by a colloidal suspension is known as the Tyndall effect.
What does this mean?When a beam of light passes through a colloidal solution or a suspension, the suspended particles disperse and scatter the light.
This scattering is more pronounced when the suspended particles are larger in size compared to the wavelength of the light. The scattered light becomes visible, creating a cone or beam of light that is observable in the direction of the incident light. The Tyndall effect is often used to study and characterize colloidal systems, as it provides valuable information about particle size, concentration, and overall dispersion.
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For the following reaction, what volume of NOBr can be produced from 3.8 L of Br2 (measured at the same temperature and pressure), assuming an excess of NO?
2NO(g)+Br2(g)=2NO(Br)2
Answer:
[tex]7.6LNOBr[/tex]
Explanation:
Hello,
In this case, since no temperature and pressure are known, one could develop the stoichiometric relationship for 1 mole of [tex]Br_2[/tex] per 2 moles of [tex]NOBr[/tex] in terms of volume as shown below because of the Avogadro's law (change in mole proportional to the change in volume at constant both pressure and temperature):
[tex]3.8LBr_2*\frac{2LNOBr}{1LBr_2} =7.6LNOBr[/tex]
Best regards.
How many moles of o2 are required for the complete reaction of 54.7 g of c2h4 to form co2 and h2o?
5.862 moles of O₂
Further explanationGiven:
Combustion of 54.7 g of C₂H₄ to form CO₂ and H₂O.
Question:
How many moles of O₂ are required for the complete reaction of combustion of C₂H₄?
The Process:
Relative atomic mass: C = 12 and H = 1.Relative molecular mass (Mr) of C₂H₄ = 2(12) + 4(1) = 28.Let us convert mass to mole for C₂H₄.
[tex]\boxed{ \ n = \frac{mass}{Mr} \ } \rightarrow \boxed{ \ n = \frac{54.7}{28} = 1.954 \ moles \ }[/tex]
The combustion reaction of C₂H₄ (ethylene, also named ethene) can be expressed as follows:
[tex]\boxed{ \ C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O \ }[/tex] (the reaction is balanced)
According to chemical equation above, proportion between C₂H₄ and O₂ is 1 to 3. Therefore, we can count the number of moles of O₂.
[tex]\boxed{ \ \frac{n(O_2)}{n(C_2H_4)} = \frac{3}{1} \ }[/tex]
[tex]\boxed{ \ n(O_2) = \frac{3}{1} \times n(C_2H_4) \ }[/tex]
[tex]\boxed{ \ n(O_2) = \frac{3}{1} \times 1.954 \ moles \ }[/tex]
Thus, the number of moles of O are required for the complete reaction of the combustion of C₂H₄ is 5.862 moles.
_ _ _ _ _ _ _ _ _
Notes:
If we want to calculate the mass of O₂, then we use the number of moles of O₂ that have been obtained.
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The molar concentration of an unknown copper (ii) sulfate solution can be determined by reacting it with excess zinc, calculating the moles of copper obtained and hence the moles of copper sulfate, and subsequently the molar concentration.
Explanation:An alternate method for determining the molar concentration of an unknown sample of copper (ii) sulfate solution involves a series of calculative steps. Firstly, we must know the stoichiometric factor between the copper (ii) sulfate and a known substance. In this case, we can use the reaction of copper sulfate with excess zinc metal as a reference in a standard data.
Here's how to calculate: Upon reaction of a known mass of copper sulfate with excess zinc metal, a certain mass of copper metal is obtained. Using this equation:CuSO4 (aq) + Zn (s).
Step 1: Calculate the number of moles of copper obtained from the mass using the molar mass of copper. Step 2: This number of moles is the same as the moles of copper sulfate in your sample because of the 1:1 stoichiometry in the reaction. Step 3: Determine the molar concentration (M) of the solution by using the formula M = moles of solute / volume of solution (in liters). If the volume of the solution is unknown, you can use other identifying tests, such as a titration.
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To determine the molar concentration of copper (II) sulfate solution, an alternate method can be used. This method involves finding the mass of CuSO4, converting it to moles using Avogadro's number, and then dividing the moles by the volume of the solution to calculate the molar concentration.
Explanation:An alternate method for determining the molar concentration of the unknown copper (II) sulfate solution can be done using the standard data. One way to do this is by finding the mass of CuSO4 and using Avogadro's number to convert it to moles. Then, divide the moles of CuSO4 by the volume of the solution in liters to calculate the molar concentration.
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If the caffeine concentration in a particular brand of soda is 4.05 mg/oz, drinking how many cans of soda would be lethal? Assume 10.0 grams of caffeine is a lethal dose, and there are 12 oz in a can.
Please explain the steps you used.
In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Part B, you found the amount of product (1.40 mol P2O5 ) formed from the given amount of oxygen and excess phosphorus. Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.
The number of moles of P2O5 produced from the given amounts of phosphorus and oxygen is equal to the number of moles of phosphorus or oxygen used.
Explanation:To determine the number of moles of P2O5 produced from the given amounts of phosphorus and oxygen, you need to compare the amounts of each reactant used in Part A and Part B. Based on the given information, it is stated that in Part A, 1.80 mol of P2O5 is formed from a given amount of phosphorus and excess oxygen. In Part B, 1.40 mol of P2O5 is formed from a given amount of oxygen and excess phosphorus. Since the stoichiometry of the reaction is a 1:1 ratio between P2O5 and phosphorus, we can conclude that 1.80 mol of phosphorus is required to produce 1.80 mol of P2O5. Similarly, 1.40 mol of oxygen is required to produce 1.40 mol of P2O5. Therefore, the number of moles of P2O5 produced from the given amounts of phosphorus and oxygen is equal to the number of moles of phosphorus or oxygen used, which is 1.80 mol and 1.40 mol respectively.
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How many milliliters of 0.150 m h2so4 are required to react with 2.05 g of sodium hydrogen cabronate?
Which carboxylic acid has the lowest boiling point?
According to the forces of attraction, the carboxylic acid with lowest boiling point is methanoic acid.
What are forces of attraction?Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
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How many calcium ions are in 0.3 mol of cacl2?
Caffeine (c8h10n4o2) is a weak base with a pkb of 10.4. part a calculate the ph of a solution containing a caffeine concentration of 430 mg/l .
Concentration of caffeine
is 430 mg/L = 0.43g/L
The molar mass of caffeine is 194.19 g/mol
Therefore the molarity is:
Molarity = (0.43/194.19)
mol/L
Molarity = 0.002214 mol/L
Molarity = 0.002214 M
Given pKb = 10.4:
Kb = 10^-pKb = 10^ -10.4 = 3.981 x 10^ -11
Kb is equivalent to:
Kb = [caffeine H+][OH-] / [caffeine]
3.981 x 10^ -11 = [caffeine H+][OH-] / (0.002214)
[caffeineH+][OH-] = 8.815 x 10^ -14
But since:
[caffeineH+] = [OH-]
Hence,
[OH-]^2 = 8.815 x 10^ -14
[OH-] = 2.969 x 10^ -7
The formula for pH is:
pH = 14 + log [OH-]
pH = 7.47The pH of a solution containing a caffeine concentration of 430 mg/L is 4.75.
Explanation:To calculate the pH of a caffeine solution, we can first use the provided pKb (10.4) to find the Kb, using the equation Kb = 10^(-pKb). We can then use the Kb to find the concentration of OH-, represented by the equilibrium C8H10N4O₂ (aq) + H₂O(1) ⇒ C8H10N4O₂H+ (aq) + OH¯ (aq). By inserting the equilibrium concentrations into the Kb expression and solving, we can find the OH- concentration.
The pH of a solution containing a caffeine concentration of 430 mg/L can be calculated using the equilibrium constant expression for caffeine. The equilibrium equation is: C8H10N4O2(aq) + H2O(l) ⇌ C8H10N4O2H+(aq) + OH-(aq). By substituting the given concentrations into the expression, the pH can be determined. The equation gives a pH of 4.75 for the solution.
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replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Calculate the amount if energy saved over 10 h when one 60 W incandescent lightbulb is replaced with an equivalent 18 W compact fluorescent lightbulb
By replacing one 60W incandescent lightbulb with an 18W compact fluorescent lightbulb, you would save 420 watt-hours of energy over 10 hours.
To calculate the amount of energy saved over 10 hours when one 60W incandescent lightbulb is replaced with an 18W compact fluorescent lightbulb, we need to find the energy consumed by each type of bulb and then calculate the difference.
Energy consumed by a bulb can be calculated using the formula:
Energy (in watt-hours) = Power (in watts) × Time (in hours)
Let's calculate the energy consumed by each bulb:
For the 60W incandescent lightbulb:
Energy consumed = 60W × 10 hours = 600 watt-hours
For the 18W compact fluorescent lightbulb:
Energy consumed = 18W × 10 hours = 180 watt-hours
Now, let's calculate the energy saved:
Energy saved = Energy consumed by incandescent bulb - Energy consumed by compact fluorescent bulb
Energy saved = 600 watt-hours - 180 watt-hours
Energy saved = 420 watt-hours
So, by replacing one 60W incandescent lightbulb with an 18W compact fluorescent lightbulb, you would save 420 watt-hours of energy over 10 hours.
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Why would gamma radiation be used in diagnostic imaging rather than alpha or beta radiation?
The pH of a vinegar solution is 4.15. What is the H+ concentration of the solution
The [tex]{{\text{H}}^+}[/tex] concentration of vinegar solution is [tex]\boxed{{\text{0}}{\text{.0000708 M}}}[/tex]
Further Explanation:
An acid is a substance that has the ability to donate [tex]{{\mathbf{H}}^{\mathbf{+}}}[/tex]ions or can accept electrons from the electron-rich species. The general dissociation reaction of acid is as follows:
[tex]{\text{HA}}\to{{\text{H}}^+}+{{\text{A}}^-}[/tex]
Here, HA is an acid.
The acidic strength of an acid can be determined by pH value. The negative logarithm of hydronium ion concentration is defined as pH of the solution. Lower the pH value of an acid, the stronger will be the acid. Acidic solutions are likely to have pH less than 7. Basic or alkaline solutions have pH more than 7. Neutral solutions have pH equal to 7.
Vinegar contains acetic acid [tex]\left({{\text{C}}{{\text{H}}_3}{\text{COOH}}}\right)[/tex], water and some traces of other chemicals and flavors.
The formula to calculate pH is as follows:
[tex]{\text{pH}}=-{\text{log}}\left[{{{\text{H}}^+}}\right][/tex] …… (1)
Here,
[tex]\left[{{{\text{H}}^+}}\right][/tex] is hydrogen ion concentration.
On rearranging equation (1), we get:
[tex]\left[{{{\text{H}}^+}}\right]={10^{-{\text{pH}}}}[/tex] …… (2)
The pH of vinegar is 4.15.
Substitute 4.15 for pH in equation (2)
[tex]\begin{gathered}\left[{{{\text{H}}^+}}\right]={10^{-4.15}}\\=0.0000707946\\\approx0.0000708\;{\text{M}}\\\end{gathered}[/tex]
So the concentration of [tex]{{\mathbf{H}}^{\mathbf{+}}}[/tex] ion in vinegar is 0.0000708 M.
Learn more:
1. The reason for the acidity of water https://brainly.com/question/1550328
2. Reason for the acidic and basic nature of amino acid. https://brainly.com/question/5050077
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Acid, base and salts.
Keywords: pH, neutral, acidic, basic, alkaline, 4.15, vinegar, acetic acid, water, chemicals, negative logarithm, H+, 0.0000708 M, pH more than 7, pH less than 7, pH equal to 7.
Considering light at the two ends of the visible light spectrum, violet light has a _____ wavelength and a _____ photon energy than red light.
Final answer:
Violet light has a shorter wavelength and higher photon energy compared to red light, with violet having the shortest wavelengths and red the longest within the visible spectrum.
Explanation:
Considering light at the two ends of the visible light spectrum, violet light has a shorter wavelength and a higher photon energy than red light. In the visible light spectrum, violet light has the shortest wavelengths (approximately 400 nm) and thus carries the most energy. Conversely, red light has the longest wavelengths (approximately 700 nm) and carries the least amount of energy.
Sunlight, for example, which is blackbody radiation, peaks in the visible spectrum and has more intensity in the red than in the violet, giving the sun a yellowish appearance. The high energy of violet photons is why dyes that absorb violet light fade more quickly, and when you observe faded posters, the blues and violets are the last to fade.
After reviewing your answers to questions 2 and 4 above, would you define boiling point and melting point as a periodic table family trend (vertical groups), period trend (horizontal rows), or neither? Explain your answer
Complete combustion of 7.40 g of a hydrocarbon produced 22.4 g of CO2 and 11.5 g of H2O. What is the empirical formula for the hydrocarbon?
Show work please?