A student assisting with the experiment would observe all of the following about the electron transport chain EXCEPT:A. Electrons are passed from carriers with lower reduction potential to those with higher reduction potential.B. The first electron carrier is also a proton pump.C. All electron carriers are mobile and hydrophobic.D. The electron carriers can transport a maximum of 2 electrons.

Answer:

See explanation below

Explanation:

The question is incomplete, however, I found a question very similar to this, and I'm assuming this is the question you are asking to answer. If it's not, please tell me which one it is. Here's a tip for you to get an idea of how to solve.

Picture 1, would be the original question. Picture 2 is the answer of it.

Now, This is a E1 reaction where this type of reactions are taking place in two steps. The first step is the formation of the carbon cation, this step is always slow. The secon step is the addition of a nucleophyle, or, in this case, formation of a pi bond, and we get a alkene.

Hope this can help you

The minor alkene product in the reaction of 2-bromobutane with methanol in the presence of HBr is trans-2-butene. The major product is cis-2-butene. The stepwise mechanism for the formation of the major product is shown above.

The reaction of 2-bromobutane with methanol in the presence of HBr is a Markovnikov addition reaction. This means that the bromide ion will add to the carbon of the 2-bromobutane molecule that is more substituted with alkyl groups. In this case, the carbon that is more substituted with alkyl groups is the secondary carbon.

The carbocation intermediate that is formed in step 1 of the mechanism is a secondary carbocation. Secondary carbocations are more stable than primary carbocations, so they are more likely to form.

In step 2 of the mechanism, the methanol molecule can attack the carbocation intermediate from either side. However, the methanol molecule is more likely to attack the carbocation intermediate from the side that is less hindered by the other alkyl groups. In this case, the side of the carbocation intermediate that is less hindered by the other alkyl groups is the side that is facing the hydrogen atom of the methanol molecule.

In step 3 of the mechanism, the proton from the HBr molecule is transferred to the oxygen atom of the methyl ether intermediate. This is a simple acid-base reaction.

The overall mechanism of the reaction is shown below:

2-bromobutane + methanol + HBr → cis-2-butene + methyl bromide + water

For more such information on: alkene

https://brainly.com/question/29120960

#SPJ6

The question is incomplete, here is a complete question.

A sled slides along a horizontal surface for which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.0m/s and at point B is 5.0m/s.

Use the impulse-momentum theorem to find how long the sled takes to travel from A to B.

Answer : The sled takes time to travel from A to B is, 1.2 seconds.

Explanation :

Impulse-momentum theorem:

Impulse = Change in momentum

[tex]\Delta P=F\times \Delta t\\\\m\nu_f-m\nu_i=F\times \Delta t\\\\m(\nu_f-\nu_i)=\mu \times m\times g\times \Delta t\\\\(\nu_f-\nu_i)=\mu \times g\times \Delta t[/tex]

where,

m = mass

g = acceleration due to gravity = [tex]9.8m/s^2[/tex]

[tex]\mu[/tex] = coefficient of kinetic friction = 0.25

[tex]\nu_f[/tex] = final velocity = 8.0 m/s

[tex]\nu_i[/tex] = initial velocity = 5.0 m/s

t = time

Now put all the given values in the above formula, we get:

[tex](\nu_f-\nu_i)=\mu \times g\times \Delta t[/tex]

[tex](8.0-5.0)=0.25\times 9.8\times \Delta t[/tex]

[tex]\Delta t=1.2s[/tex]

Therefore, the sled takes time to travel from A to B is, 1.2 seconds.

The sled is decelerating due to kinetic friction, and we can calculate this deceleration using the equations of motion and the given coefficient of kinetic friction. The normal force on the sled can also be found by dividing the frictional force by the coefficient of kinetic friction.

This problem pertains to the concept of kinetic friction and motion in Physics. We know that the sled's velocity decreases from 8.0m/s to 5.0m/s over some distance, which implies that it's decelerating due to kinetic friction. We can make use of the equation of motion v^2 = u^2 - 2*a*d where v is final velocity, u is initial velocity, a is deceleration (friction) and d is distance.

First, let's find the deceleration caused by the friction force using this equation. As we know that the frictional force can be expressed as F_kinetic = μk*m*g, where m is the mass of the sled (not given) and g is the acceleration due to gravity (9.8 m/s^2). From here, we can also find the normal force on the sled by knowing that the normal force is equal to kinetic friction divided by the coefficient of kinetic friction.

https://brainly.com/question/36370309

#SPJ3

Answer:

Ca (s) + 2H₂O (l) →  Ca(OH)₂ (aq)  +  H₂ (g)

Explanation:

When solid calcium reacts with water, it produces the correspondent hydroxid and hydrogen gas.

The hydroxid which is produced, is the calcium hydroxid which is a strong base, that's why you talk about a highly alkaline solution.

Ca (s) + 2H₂O (l) →  Ca(OH)₂ (aq)  +  H₂ (g)

Calcium hydroxide is a strong base, that dissociates in water, as this:

Ca(OH)₂  →  Ca²⁺ (aq)  + 2OH⁻ (aq)

It's a basic solution,  is providing hydroxyl ions to the medium

The balanced chemical equation for the reaction between calcium and water is: Ca (s) + 2H2O (l) --> Ca(OH)2 (s) + H2 (g). Calcium metal reacts with water to form calcium hydroxide and hydrogen gas.

The reaction between calcium and water can be represented as Ca (s) + 2H2O (l) --> Ca(OH)2 (s) + H2 (g). This balanced equation represents the reaction of calcium metal with water to form calcium hydroxide and hydrogen gas. It is a single replacement reaction where calcium displaces the hydrogen in water to form the compound calcium hydroxide and release hydrogen gas. It results in an alkaline solution because calcium hydroxide is a strong base.

https://brainly.com/question/32834309

#SPJ3

Answer: 116 calories of energy

Explanation:

A calorie is a non-standard unit of energy.

On combustion,

1 gram Carbohydrates = 4 calories,

1 gram protein = 4 calories,

1gram fat = 9 calories.

Therefore,

15 grams of carbohydrates = (15*4) = 60

5 grams of protein = (5*4) = 20

4 grams of fats = (4*9) = 36

Then add up: 60 + 20 + 36 = 116 calories of energy

Answer:

POH= 13

Explanation:

A student preparing for the experiments inadvertently adds an additional 400 mL of the same acid solution to the dissolution vessel. What will be the new pOH of this solution?

PH is the measure of the degree of acidity of a solution.

POH is the measure of the degree of alkalinity of a solution

Note that  pH + pOH = 14

if concentration remains the same, then volume changes will not affect pH.

The pH of the solution is given as

PH= -log[H+].

For this experiment, the dissolution vessel contains 0.1 M HCl, no matter the initial volume of the acid solution

For the molar concentration of the cation, we can propose that  a strong acid will  dissociate completely,

[H+] = 0.1 = 1 x 10-1 M

. substituting the concentration of the cation

PH=-log[1 x 10-1] = 1.

Note that  pH + pOH = 14 for any aqueous solution.

we say that

the pOH = 14 - pH.

pOH = 14-1 = 13.