No, I believe this is not an example of a chemical reaction. What we actually see here is a physical change of the solution. Since we are adding more water to an aqueous solution which is also made up mostly of water, what we are simply basically doing is dilution. Since the solution is being diluted, so definitely the color turned lighter.
what are 3 possible causes of tsunamis ?
Which monatomic ion has a charge of 1- and the condensed electron configuration [ne]3s23p6?
An ion is an atom in which the total number of electrons is not the same with the total number of protons, giving it a net positive or negative electrical charge.
The electron configuration of chlorine is [Ne]3s23p5. If a chlorine atom adds an electron to form the chloride ion (Cl-), it will have an electron configuration of [Ne]3s23p6. While Argon has no charge.
The monatomic ion with a charge of 1- and the condensed electron configuration [ne]3s23p6 is the Chloride ion (Cl-).
Explanation:The monatomic ion with a charge of 1- and the condensed electron configuration [ne]3s23p6 is the Chloride ion (Cl-).
What does it mean to say that ions are solvated when an ionic substance dissolves in water?
Identify the statement that correctly describes light and how it travels?
Draw the lewis structure with the atoms arranged as hocl. include all non-bonding electrons.
Gasohol is a fuel containing ethanol (c2h6o) that burns in oxygen (o2) to give carbon dioxide and water.
friction acts in a direction blank to the direction of the object's motion?
What is the volume of the solution that would result by diluting 80.00 ml of 9.13×10−2 m naoh to a concentration of 1.60×10−2 m ?
Final answer:
Diluting 80.00 mL of 9.13×10⁻² M NaOH to a concentration of 1.60×10⁻² M would result in 456.25 mL of the solution, calculated using the dilution formula M1V1 = M2V2.
Explanation:
The question asks about diluting a solution of NaOH from an initial concentration to a lower concentration while preserving the number of moles of solute. This is a classic chemistry problem involving the concept of molarity and dilution. The formula used to solve such problems is M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, respectively, and M2 and V2 are the molarity and volume of the final solution, respectively.
Given: M1 = 9.13×10⁻² M, V1 = 80.00 mL, M2 = 1.60×10⁻² M. We need to find V2.
Using the formula:
M1V1 = M2V2(9.13×10⁻² M)(80.00 mL) = (1.60×10⁻² M)V2Solving for V2 gives V2 = (9.13×10⁻² M ÷ 1.60×10⁻² M) × 80.00 mL = 456.25 mLTherefore, diluting 80.00 mL of 9.13×10⁻² M NaOH to a concentration of 1.60×10⁻² M would result in a volume of 456.25 mL of the solution.
What is the concentration of h+ ions in a solution of hydrochloric acid that was prepared by diluting 15.0 ml of concentrated (11.6 m ) hcl to a final volume of 500.0 ml?
Is a buffer supposed to keep the ph of a solution at 7 (neutral)?
Final answer:
Buffers maintain a steady pH in a solution but not necessarily a neutral pH of 7. They can maintain acidic, neutral, or basic pH levels depending on their composition and are essential for processes requiring stable pH conditions, such as in human blood.
Explanation:
The question about whether a buffer is supposed to keep the pH of a solution at 7 (neutral) reflects a common misconception. Buffers do not necessarily maintain a pH of 7. They are solutions that consist of a weak acid and its conjugate base and function to moderate pH changes when an acid or base is added. This helps maintain a steady pH, but the specific pH maintained by a buffer depends on the properties of the acid-base pair it is made from. For example, the pH of a buffer can be acidic, neutral, or basic, depending on its composition. The crucial function of a buffer is its capacity to absorb excess H⁺ ions or OH⁻ ions, thus preventing significant shifts in pH.
It's important to understand that the pH scale ranges from 0 to 14, with 7 being neutral. Solutions with a pH lower than 7 are considered acidic, and those with a pH higher than 7 are basic. Buffers can be designed to maintain any pH within this range, depending on the needs of the environment or process they are used in. For instance, human blood has a buffer system that maintains its pH around 7.35 to 7.45, slightly alkaline, which is crucial for physiological functions.
4HF(g)+SiO2(s)→SiF4(g)+2H2O(l)
What mass of water (in grams) is produced by the reaction of 67.0 g of SiO2 ?
The reaction between 67.0 g of silicon dioxide (SiO2) and hydrofluoric acid (HF) will produce roughly 40.16 g of water (H2O).
Explanation:The question is related to a chemical reaction between silicon dioxide (SiO2) and hydrofluoric acid (HF) which produces silicon tetrafluoride (SiF4) and water (H2O). From the balanced equation, we can see that for each mole of SiO2 reacted, 2 moles of H2O are produced. To find out the mass of water produced from 67.0 g of SiO2, we first need to determine the number of moles of SiO2 in 67.0 g. Using the molar mass of SiO2 (60.08 g/mol), we find that 67.0 g corresponds to 1.115 moles. As the reaction produces 2 moles of water for each mole of SiO2, this means we have 2 * 1.115 = 2.23 moles of water. The molar mass of water is 18.015 g/mol, so this equates to approximately 40.16 g of water.
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Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. at standard temperature and pressure (stp; 273.15 k and 1 atm, respectively), one mole of gas occupies 22.4 l of volume. what mass of methanol (ch3oh) could you form if you reacted 5.86 l of a gas mixture (at stp) that contains an equal number of carbon monoxide (co) and hydrogen gas (h2) molecules?
What is the speed of a bobsled whose distance-time graph indicates that it traveled 118m in 26s
Identify which atomic orbitals are used to construct the specified sigma bonds: g
On a molecular level, explain how pure water can act as both an acid and a base.
According to the following electron structure, how many valence electrons does carbon have? C = 1s22s22p2
2
4
6
8
The answer is 4 valence electrons
a 500 gram piece of metal has a volume of 2.75 cm3. what is the density
Write a balanced chemical equation to show the reaction of naoh with the monoprotic acid hcl.
Final answer:
The balanced chemical equation for the reaction between NaOH and HCl is NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l). It is a neutralization reaction with a one-to-one molar ratio.
Explanation:
The balanced chemical equation to show the reaction of NaOH with the monoprotic acid HCl is as follows:
NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)
This reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is a typical acid-base reaction where NaOH is the base and HCl is the acid. When NaOH and HCl react together, they form sodium chloride (NaCl) and water (H₂O). This reaction is also called a neutralization reaction and in this case, occurs in a one-to-one molar ratio where one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.
A mysterious white powder is found at a crime scene. a simple chemical analysis concludes that the powder is a mixture of sugar and morphine (c17h19no3), a weak base similar to ammonia. the crime lab takes 10.00 mg of the mysterious white powder, dissolves it in 100.00 ml water, and titrates it to the equivalence point with 2.84 ml of a standard 0.0100 m hcl solution. what is the percentage of morphine in the white powder?
The percentage of morphine in the white powder at the crime scene is 81%.
Explanation:The goal here is to find the percentage of morphine in the white powder. To do this, we first need to know the amount of morphine in moles. Since morphine is a weak base similar to ammonia, it reacts with HCl (hydrochloric acid), with one mole of morphine reacting with one mole of HCl.
The molar concentration of HCl (0.0100 M) multiplied by its volume (2.84 ml or 0.00284 L) will give us the number of moles of HCl used, which also equals the number of moles of morphine in the mixture. Therefore, number of moles of morphine = 0.0100 M x 0.00284 L = 0.0000284 moles.
Morphine's molecular weight is 285.34 g/mol, so the weight of morphine in the mixture = moles x molecular weight = 0.0000284 moles x 285.34 g/mol = 0.0081 grams or 8.1 mg. As the initial weight of the powder was 10.00 mg, the percentage of morphine in the sample is (8.1/10.00)*100 = 81%. Therefore, 81% of the mysterious white powder is morphine.
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What is the name of the compound with the chemical formula bi2s3?
Which of the following pairs of elements are likely to form ionic compounds?
Check all that apply.
lithium and chlorine
sodium and neon
potassium and oxygen
sodium and magnesium
nitrogen and chlorine
oxygen and chlorine
What is the electrostatic potential energy (in joules) between an electron and a proton that are separated by 54 pm?
The electrostatic potential energy between an electron and a proton can be calculated using the equation PE = k(q1q2)/r, where k is the Coulomb constant, q1 and q2 are the charges of the electron and proton respectively, and r is the separation between them. Plugging in the given values, the electrostatic potential energy can be calculated.
Explanation:The electrostatic potential energy between an electron and a proton can be calculated using the equation PE = k(q1q2)/r, where k is the Coulomb constant, q1 and q2 are the charges of the electron and proton respectively, and r is the separation between them.
In this case, the charge of an electron is -1.6 x 10-19 C and the charge of a proton is +1.6 x 10-19 C. The separation between them is 54 pm, which is equal to 54 x 10-12 m.
Plugging in these values, we get:
PE = (9 x 109 N m2/C2)((-1.6 x 10-19 C)(1.6 x 10-19 C))/(54 x 10-12 m)
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The electrostatic potential energy (in joules) between an electron and a proton that are separated by 54 pm is approximately [tex]- 4.25 \times 10^{-18} J[/tex].
To calculate the electrostatic potential energy between an electron and a proton that are separated by a distance of 54 picometers (pm), we can use the formula for the electrostatic potential energy [tex]E_{pot}[/tex] of two point charges:
[tex]E_{pot} = - \frac{k_e \cdot q_1 \cdot q_2}{r}[/tex]
Where:
[tex]E_{pot}[/tex] is the electrostatic potential energy,[tex]k_e[/tex] is Coulomb's constant, approximately 8.99 × 10⁹ N m²/C².[tex]q_1[/tex] and [tex]q_2[/tex] are the charges of the proton and electron, respectively. The charge of an electron (or proton) is approximately 1.6 × 10¹⁹ C.r is the distance between the charges in meters.1. Convert 54 pm to meters: 54pm = 54 × 10⁻¹² m
2. Substituting values into the equation: Since the charges of the proton and electron are equal and opposite, we have:
[tex]q_1[/tex] = + 1.6 × 10⁻¹⁹ C, [tex]q_2[/tex] = [tex]-[/tex] 1.6 × 10⁻¹⁹ CTherefore, substituting these values:
[tex]E_{pot} = - \frac{(8.99 \times 10^9) \cdot (1.6 \times 10^{-19}) \cdot (1.6 \times 10^{-19})}{54 \times 10^{-12}}[/tex]3. Calculating the potential energy:
[tex]E_{pot} = - \frac{(8.99 \times 10^9) \cdot (2.56 \times 10^{-38})}{54 \times 10^{-12}}[/tex] [tex]E_{pot} = - \frac{(2.295 \times 10^{-28})}{54 \times 10^{-12}}[/tex][tex]E_{pot} \approx - 4.25 \times 10^{-18} J[/tex]The negative sign indicates that the potential energy is attractive, which is characteristic of opposite charges (the electron and proton).
what is the type of compound of copper and oxide?
igneous rocks formed on or near Earth’s surface are considered
Answer:
Extrusive igneous rock
Explanation:
The igneous rocks that are crystallized on the earth's surface are commonly known as the extrusive igneous rock. These rocks are characterized by the presence of fine-grained crystals which is due to the rapid cooling of the magma, as it does not get enough time for the crystals to form. These are also sometimes comprised of volcanic glasses.which are formed on the surface due to the eruption of volcanoes.
When the hot intruding magma crystallizes below the earth's surface, then it is called intrusive igneous rocks. For example, granite, diorite and gabbro.
On the other hand, when the hot uprising magma crystallizes on or near the earth's surface, then it is known as extrusive igneous rocks. For example, basalt, rhyolite and andesite.
What is the name of the hybrid orbitals used by phosphorus in pcl3?
Taking into account the vapor pressure of water, how many moles of hydrogen gas, n, are present in 345 ml at 752 torr and 29 ∘c? the value of the gas constant r is 0.08206 l⋅atm/(mol⋅k). you may also find the conversion
The number of moles of hydrogen gas in 345 mL volume at 752 torr and 29 ∘C, after accounting for the vapor pressure of water, is calculated using the Ideal Gas law equation and is approximately 0.014 moles.
Explanation:To determine the number of moles of hydrogen gas in a given volume, we use the Ideal Gas Law (PV = nRT). Here, P is pressure (752 torr), V is the volume (345 mL, which is 0.345 L), T is the absolute temperature (29 + 273 = 302 K) and R is the gas constant (0.08206 L⋅atm/(mol⋅K)).
Convert the pressure from torr to atm, 752 torr is roughly equivalent to 0.9901 atm. We need to subtract this from the total pressure to account for the vapor pressure of water (approximately 25.2 torr at 26°C, or 0.0331 atm). So, the final pressure value we will use is 0.9901 atm - 0.0331 atm = 0.957 atm.
Now we substitute the values into the Ideal Gas Law: (0.957 atm) * (0.345 L) = n * (0.08206 L⋅atm/(mol⋅K)) * (302 K). Calculating the number of moles, n, we get approximately 0.014 moles of hydrogen gas present in 345 ml at the given conditions.
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A student added 25.0 uL of a solution of magnesium chloride to a microcentrifuge tube along with a color changing indicator, and titrated with 1.00 x 10−2 M EDTA to the endpoint. The color change occurred at 21.3 uL. What was the [Mg2+]?
Mg^2+ + EDTA^4- -> MgETDA^2-
number µmoles of EDTA used = 21.3 µl x 1 x 10^-2 M = 21.3 µl x 1 x 10^-2 µm/µl = 21.3 x 10^-2 = 0.213 µmoles EDTA
µmoles Mg^+2 present = 0.213 µmoles because the stoichiometry ratio of the above equation is 1:1
[Mg^+2] = 0.213 µmol / 25 µl = 0.00852 µmol/µl = 0.00852 M = 8.52 x 10^-3 M
The answer is 8.52 x 10^-3 M
If a small amount of ferrous ammonium sulfate is spilled when transferring
What is the classification for this reaction? so3 (g) + h2o (l) → h2so4 (aq)?
The reaction SO3 (g) + H2O (l) → H2SO4 (aq) is classified as an acid-base reaction, specifically demonstrating the behavior of sulfur trioxide (an acid) reacting with water (a base) to produce sulfuric acid. Also, this reaction can be considered a type of synthesis reaction.
Explanation:The equation provided, SO3 (g) + H2O (l) → H2SO4 (aq), is an example of an acid-base or a synthesis reaction. In acid-base reactions, an acid (SO3 in this case) combines with a base (H2O here) to form water and an ionic compound (H2SO4 here, a strong acid). In a more general sense, this is also a synthesis reaction because two or more simple substances (SO3 and H2O) combine to create a more complex one (H2SO4).
Moreover, taking into consideration the
acid-base behavior
of substances and their reactions, an acid would donate a proton and a base would accept it, thus, in our reaction, H2O acts as a base accepting a proton from SO3.
Additionally, the process of synthesizing sulfuric acid from sulfur dioxide and water is an important industrial method in the production of this widely used chemical.
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The reaction [tex]SO_3 (g) + H_2O (l) \rightarrow H_2SO_4(aq)[/tex] is classified as a synthesis reaction. It involves the combination of sulfur trioxide and water to form sulfuric acid. Sulfuric acid in water acts as a dibasic acid, forming bisulfate and sulfate anions.
The classification for the reaction [tex]SO_3 (g) + H_2O (l) \rightarrow H_2SO_4(aq)[/tex] is a synthesis reaction. This type of reaction occurs when two or more simple substances (in this case, sulfur trioxide and water) combine to form a more complex substance (sulfuric acid). Sulfuric acid is a strong protic acid and in water, it acts as a dibasic acid, forming bisulfate ([tex]HSO_4^-[/tex]) and sulfate ([tex]SO_4^{2-[/tex]) anions.
First Ionization:
[tex]H_2SO_4 (aq) + H_2O (l) \rightarrow H_3O^+ (aq) + HSO_4^- (aq)[/tex]
Second Ionization:
[tex]HSO_4^- (aq) + H_2O (l) \rightarrow H_3O^+ (aq) + SO_4^{2- (aq)[/tex]
In conclusion, the reaction of [tex]SO_3[/tex] with [tex]H_2O[/tex] forming [tex]H_2SO_4[/tex] is a classic example of a synthesis reaction in chemistry.
A gallon of water has a mass of 3.79 kg. how many moles of water (18.02 g/mol) is this?
A gallon of water with a mass of 3.79 kg is equal to 208.76 mol of water.
Explanation:To find out how many moles of water (H2O) are in a gallon, we need to use the molar mass of water as a conversion factor.
The molar mass of water is 18.02 g/mol. To convert the mass of water from kg to g, we can multiply the number of kg by 1000.
Therefore, a gallon of water with a mass of 3.79 kg is equal to 208.76 mol of water.