A tennis pro charges $15 per hour for tennis lessons for children and $30 per hour for tennis lessons for adults. The tennis pro is practicing A) first-degree price discrimination. B) second-degree price discrimination. C) third-degree price discrimination. D) fourth-degree price discrimination. E) fifth-degree price discrimination.

Answer:

The sentence is following with "are made from mostly silicon material".

Explanation:

Silicon is extracted and refined by the use of electrical energy. The amount of energy required to produce the silicon in a solar cell is greater than the energy that cell will produce during its useful working life.

The initial horizontal velocity of the soccer ball is 16.5 m/s

Explanation:

When we throw a ball, there is a constant velocity horizontal motion and there is an accelerated vertical motion. These components act independently of each other.  Horizontal motion is constant velocity motion.

            [tex]v_{x f}=v_{x i}=v_{x}[/tex]

[tex]a_{x}=0[/tex], so [tex]x=v_{i x} t+\left(\frac{1}{2}\right) a_{x} t^{2}[/tex] for horizontal motion

[tex]y=v_{i y} t+\left(\frac{1}{2}\right) a_{y} t^{2}[/tex] for vertical motion

Given:

x = 35 m

[tex]a_{x}=0 \mathrm{m} / \mathrm{s}^{2}[/tex]

Need to find [tex]v_{i x}[/tex]

y = - 22 m

[tex]v_{i y}=0 \mathrm{m} / \mathrm{s}[/tex]

[tex]a_{y}=-9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]  (negative sign indicates downward motion)

By substituting all known values, we can solve for 't' value as below

[tex]y=v_{i y} t+\left(\frac{1}{2}\right) a_{y} t^{2}[/tex]

[tex]-22=0(t)+\left(0.5 \times-9.8 \times t^{2}\right)[/tex]

[tex]t^{2}=\frac{-22}{0.5 \times-9.8}=\frac{-22}{-4.9}=4.4897[/tex]

Taking square root, we get  t = 2.12 seconds

Now, substitute these to find initial horizontal velocity

[tex]x=v_{i x} t+\left(\frac{1}{2}\right) a_{x} t^{2}[/tex]

[tex]35=v_{i x}(2.12)+\left(0.5 \times 0 \times(2.12)^{2}\right)[/tex]

[tex]35=v_{i x}(2.12)+0[/tex]

[tex]v_{i x}=\frac{35}{2.12}=16.5 \mathrm{m} / \mathrm{s}[/tex]

To hold the oil drop steady, the electrical force must match its weight. The voltage required to generate this force can be determined, and hence the charge on each plate, using given constants and the weight of the drop. The upper plate should be positive as the drop has excess electrons.

Firstly, we need to find the weight of the oil drop because it will be opposing the electrical force to keep the drop suspended. The mass can be found by converting the micrograms into kilograms (1 microgram = 10^-9 kg). So, the weight (W) of the oil drop will be the mass times gravity. W = 0.025 * 10^-9 *9.8 = 2.45 * 10^-10 N.

The electrical force that will hold the drop steady will exactly equal this weight. Since F = qE where F is the force, q is the charge, and E is the field strength, and E = V/d (where V is potential difference and d is distance), we can put these together to find the voltage that will create this field. V = Fd/q = Wd/q . All that's left is to plug all the given values in: the number of excess electrons in the oil drop times the elementary charge (1.6*10^-19 C), which gives us the total charge on the drop.

As for which plate must be positive, it would be the one opposing the negative charge of the oil drop to suspend it, therefore, the upper plate must be positive.

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Answer:

b. a cathode-ray tube.

Answer:

[tex]331665750000\ m/s^2[/tex]

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = [tex]1.989\times 10^{30}\ kg[/tex]

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

[tex]g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2[/tex]

The gravitational acceleration at the surface of such a star is [tex]331665750000\ m/s^2[/tex]

[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s[/tex]

The velocity of the object would be 3257806.62409 m/s

(a) the acceleration due to gravity is 3.3 × 10¹¹ m/s²

(b) the final velocity of the object is 3.26 × 10⁶ m/s

Given that the neutron star has a mass equal to Sun, M = 2 × 10³⁰ kg

Radius of the star is R = 20 km = 20 × 10³

The weight on the surface of a neutron star that has the same mass as our Sun and a diameter of 21.0 km will be 8.29 × 10¹³ N

(a) The gravitational force on the surface of the neutron star is given by:

F = GMm/R²

mg = GMm/R²

where G is the gravitational constant

M is the mass of the body

m is the mass of the person

and, R is the radius of the body

So,

g = GM/R²

g = (6.67 × 10⁻¹¹)( 2 × 10³⁰)/ (210 × 10³)²

g = 3.3 × 10¹¹ m/s²

(b) According to the third equation of motion:

v² = u² + 2gh

v² = 2gh , since u = 0 as the object is at rest initially

v = [tex]\sqrt{2\times3.3\times10^{11}\times16}[/tex]

v = 3.26 × 10⁶ m/s

Learn more about gravitational force:

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Answer:

initial and final temperatures of both the water and metal, mass of the metal, and mass of the water

Explanation:

Heat lost by the metal, [tex]Q = mc(t_{2} - t_{1})[/tex]

Heat gained by the water in the calorimeter, [tex]Q_{w} = m_{w}c_{w}(t_{2w} - t_{1w})[/tex]

For energy to be conserved in the system, the heat lost by the metal will equal the heat gain by the water in the calorimeter.

        [tex]mc(t_{2} - t_{1}) = m_{w}c_{w}(t_{2w} - t_{1w})[/tex]

Where,

m is the mass of the metal

c is specific heat capacity of the metal

t₂ is the final temperature of the metal

t₁ is the initial temperature of the metal

[tex]m_{w} [/tex] is the mass of the water

[tex]c_{w} [/tex] is specific heat capacity of water

[tex]t_{2w} [/tex] is the final temperature of water

[tex]t_{1w} [/tex] is the initial temperature of water

From the question given, specific heat capacity of the water is known, the quantities to be measured are;

Initial and final temperatures of both the water and metal,

Mass of the metal, and mass of the water

Answer:

Option e.

In this case the work is done on the ball by nonconservative forces  that resulted in the ball having less total mechanical energy after the bounce.

Explanation:

Answer:The answer can be calculated by doing thefollowing steps;

Explanation:

The density of the unknown liquid can be calculated by finding the mass of the liquid and dividing it by the volume. The mass of the liquid is 37.13 g and the volume is 48.1 mL. Thus, the density is 0.772 g/mL.

The density of a substance is calculated by dividing its mass by its volume. Here, the mass of the unknown liquid can be calculated by subtracting the weight of the empty graduated cylinder from the weight of it filled with the liquid. That is, mass = 92.39 g - 55.26 g = 37.13 g. The volume of the liquid is given as 48.1 mL. Therefore, the density can be calculated as follows:

Density = mass/volume

= 37.13 g / 48.1 mL = 0.772 g/mL

This means the density of the unknown liquid is 0.772 g/mL.

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Answer: v² = u² + 2as  

2as = v² - u²  

a = (v² - u²) / 2s  

a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m)  

a = (400 m²/s² - 36 m²/s²) / (100 m)  

a = (364 m²/s²) / (100 m)  

a = 3.64 m/s²

Explanation:

Answer:1m/s^-2

Explanation:V=u+at where;

V(final velocity)=50m/s

U(Initial velocity)=20m/s

a(acceleration)=?

t(time)=30seconds

Therefore; 50=20+a(30)

Collect like terms

50-20=30a

30=30a

Divide both side by 30

a=1ms^-2

Answer: Jane 6ft from fulcrum

John 4 ft from fulcrum

Explanation: You use the law of moment of force.

That is Clockwise moment equals anti clockwise moment.

Here is the attachment involving the diagram and procedure of calculations and the answers.

The small child should sit 1.30 m away from the pivot point on the seesaw to maintain balance.

The small child should sit 1.30 m away from the pivot point on the seesaw to maintain balance.

Answer:

[tex]\overrightarrow{F} = -\left ( 15x^{4}y-3 \right )\widehat{i}-3x^{5}\widehat{j}[/tex]

Explanation:

[tex]U = 3x^{5}y-3x[/tex]

Force is defined as the

[tex]\overrightarrow{F} = -\frac{dU}{dx}\widehat{i}-\frac{dU}{dy}\widehat{j}[/tex]

[tex]\frac{dU}{dx}=15x^{4}y-3[/tex]

[tex]\frac{dU}{dy}=3x^{5}[/tex]

So, force is given by

[tex]\overrightarrow{F} = -\left ( 15x^{4}y-3 \right )\widehat{i}-3x^{5}\widehat{j}[/tex]

Answer:

southwest

Explanation:

Here, all the particles have same charge this means that only repulsive force is acting on the particles according to Coulomb's laws.

One particle is 1 m to my north and another particle is to my east.

The particle to my north will push the positive charge I am holding to the south and the particle to my east will push the positive charge I am holding to the west.

Hence, the resultant direction of the force will be southwest.

The balloon accelerated because of Newton's third law of motion. When the air in the balloon is forcefully ejected, the balloon experiences an equal and opposite force, causing it to accelerate in the opposite direction.

The acceleration of the balloon when it slips from Miko's hand is due to Newtons third law of motion. This law states that for every action, there is an equal and opposite reaction. In this case, when the air is forcefully ejected or escapes from the balloon, the balloon experiences an equal and opposite force which causes it to shoot off or accelerate in the opposite direction of the escaping air. This is the same principle that explains the propulsion of rockets and the recoil of guns.

You can visualize the movement of the balloon somewhat like the exploding fireworks shown in figure 9.31. The fireworks explode and eject matter in all directions - and its center of mass behaves similarly to the balloon's - accelerated by the ejection of matter. The balloon, like the firework, would keep the parabolic path of flight as long as there was matter (or in the balloon's case, air) pushing it forward. Once all of the air has escaped, the balloon starts to fall due to gravity, like any other free-falling object.

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Answer:

Resistance will become 4 times the previous value

Explanation:

We have given current in the circuit i = 2.4 A

According to ohm's law current in the circuit is given by [tex]I=\frac{V}{R}[/tex]

So [tex]2.4=\frac{V}{R}[/tex]............eqn 1

Now voltage is increased to 4 times so new voltage = 4 V

And current in the circuit is same as 2.4 A

We have to fond the resistance so that after increasing voltage current will be same

So [tex]2.4=\frac{4V}{R_{unknown}}[/tex]..........eqn 2

Dividing eqn 1 and 2

[tex]1=\frac{V}{R}\times \frac{R_{unkown}}{4V}[/tex]

[tex]R_{unknown}=4R[/tex]

So resistance will become 4 times the previous value

Answer:

It should increase to four times its value.

Explanation:

Answer:

C. The swimmer should swim northeast.

Explanation:

A swimmer expects to reach to the eastern bank of a river by swimming whose stream flows from north to south. Then in order to reach the directly opposite bank of the river when standing on the western bank, the swimmer must swim towards northeast direction so that the resultant of the velocity of flow and the velocity of swimming results in a net velocity towards the east direction.

[tex]sp^3[/tex] hybridization and 1 lone pair is exhibited by the nitrogen atom in the following substance pairs are present on the nitrogen.

b. [tex]sp^3[/tex] hybridization and 1 lone pair

Explanation:

The Nitrogen particle is [tex]sp^3[/tex] hybridized with one crossover orbital involved by the solitary pair. Likewise, nitrogen is [tex]sp^3[/tex] hybridized which implies that it has four [tex]sp^3[/tex] half and half orbitals. The sub-atomic structure of water is predictable with a tetrahedral game plan of two solitary sets and two holding sets of electrons. Two of the [tex]sp^3[/tex] hybridized orbitals cover with s orbitals from hydrogens to frame the two N-H sigma bonds.

Nitrogen utilizes [tex]sp^3[/tex] orbitals to accomplish this geometry. Three of the mixtures are utilized to frame bonds to hydrogen and the fourth contains the solitary pair. Whereas lone pairs are the pairs of electron on atoms that don't take an interest in the holding bonding of two atoms. To distinguish solitary matches in a particle, make sense of the number of valence electrons of the molecule and subtract the number of electrons that have partaken in the holding.

Hybridization of nitrogen depends on its bonding context; sp hybridization leads to a linear geometry, whereas sp³ hybridization results in a trigonal pyramidal geometry with one lone pair, as seen in ammonia.

The question is asking about the hybridization of nitrogen in various substances. Hybridization describes the mixing of atomic orbitals to form new hybrid orbitals that can accommodate bonding and lone pairs in molecules. For a nitrogen atom with sp hybridization, the molecule usually has a linear geometry, as in the case of hydrogen cyanide (HCN). Here, nitrogen has one sp hybrid orbital with a lone pair and one with a sigma bond, while the two p orbitals form pi bonds, resulting in a triple bond.

In cases where nitrogen is sp³ hybridized, the nitrogen atom can form three sigma bonds with its sp³ hybrid orbitals and retain one lone pair, giving a trigonal pyramidal geometry. An example of this is in ammonia (NH₃), where the nitrogen atom is bonded to three hydrogen atoms and has one lone pair.

A star goes through multiple stages of life represented on the H-R Diagram, from the main sequence stage to a red giant, then a brief stable period after a helium flash, back to a giant, and finally, death. The 'main-sequence turnoff' on the H-R diagram marks where stars begin to leave the main sequence. These stages occur faster for more massive stars.

Stars progress through various stages on the H-R diagram as they age. Initially, in the main sequence stage, stars start by fusing hydrogen in their cores. The most massive stars evolve into red giants and supergiants less than a million years after they reach the main sequence, moving up and to the right on the diagram. After, lower mass stars also begin their departure from the main sequence.

During the next phase of evolution, a star experiences a helium flash which causes a change in its internal structure, leading to a brief period of stability. Following the exhaust of the central helium, the star turns into a giant again and its position on the H-R diagram shifts to high luminosity and low temperature. During the final stage of the star's life, it depletes its inner resources and begins to die.

This process of evolution is faster for more massive stars, as the rate at which they go through each stage of life is higher. The main-sequence turnoff point on the H-R diagram denotes the location where stars begin to leave the main sequence and transform towards the red giant region. It is lower on the H-R diagram and the mass of the stars is lower in older clusters.

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Explanation:

The life span of a star is quite as many more than 10 billion years. During these many years it would pass through different stages of its life,  from nebula to ( perhaps, the current stage) supernova to neutron star or Black Hole.

The stages of the life of star over a span of 13 billion year can be summarized as

the transition stages are

Nebula → Blue star → Blue-white super-giant  star → Supernova → Neutron star →Black Hole.

Answer:

3.51724 blocks

2.48275 blocks

Explanation:

L = Length of one block

t = Time taken by both person

[tex]Distance=Speed\times Time[/tex]

[tex]1.2t+1.7t=6L\\\Rightarrow 2.9t=6L\\\Rightarrow t=\dfrac{6}{2.9}L[/tex]

Distance that I walk

[tex]s=1.7t\\\Rightarrow s=1.7\times \dfrac{6}{2.9}L\\\Rightarrow s=3.51724L[/tex]

The Distance that I will walk is 3.51724 blocks

Distance my friend will walk

[tex]s=1.2t\\\Rightarrow s=1.2\times \dfrac{6}{2.9}L\\\Rightarrow s=2.48275L[/tex]

Distance my friend will walk is 2.48275 blocks

To determine the restaurant where you and your friend will arrive at the same instant, we can use the equation distance = speed × time.

To determine the restaurant where you and your friend will arrive at the same instant, we can use the equation distance = speed × time. Let's assume the distance between the buildings is 6 blocks, which is the same for both of you. We'll call the time it takes for both of you to reach the restaurant 't'. For you, the distance covered will be 6 blocks at a speed of 1.7 m/s, so your equation will be 6 = 1.7t. For your friend, the equation will be 6 = 1.2t.

Solving these equations, we find that t = 3.53 seconds for you and t = 5 seconds for your friend. Since you want to arrive at the same instant, you need to use the higher time, which is 5 seconds. Thus, the restaurant where you and your friend can meet at the same instant is located 5 seconds away from both of your buildings.

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Answer:

The moment of inertia about the rotation axis is 145.35 kg.m²

Explanation:

Given:

Mass of each seat = 6.4 kg

length of rods attached to the seat = radius of the seat from center = 1.5m

Moment of inertia = M₁r²

Moment of inertia about the first child:

total mass at that point = mass of the child + mass of the seat

                                      = 16kg + 6.4 kg = 22.4 kg

Moment of inertia at the point where the first child sits = 22.4 *1.5²

= 50.4 kg.m²

Moment of inertia about the second child:

total mass at that point = mass of the child + mass of the seat

                                       = 23kg + 6.4 kg = 29.4 kg

Moment of inertia at the point where the second child sits = 29.4 *1.5²

= 66.15 kg.m²

Moment of inertia about the two empty seats:

Moment of inertia about the two seats = 2(6.4*1.5²)

= 28.8 kg.m²

Moment of inertia about the rotation axis = Moment of inertia about the point of two children + moment of inertia about the two seat

= (50.4 + 66.15 + 28.8) kg.m²

= 145.35 kg.m²

Therefore, the moment of inertia about the rotation axis is 145.35 kg.m²

The moment of inertia about the rotation axis is 145.35 kgm2.

Given that the mass m_s of the seat is 6.4 kg, length r of the rod is 1.5 m. The masses of two children is m1 = 16 kg and m2 = 23 kg.

The moment of inertia about the first child is calculated given below.

[tex]MI _1 = (m_s+m_1)r^2[/tex]

[tex]MI_1 = (6.4+16)\times 1.5^2[/tex]

[tex]MI_1 = 50.4 \;\rm kg m^2[/tex]

The moment of inertia about the second child is calculated given below.

[tex]MI _2= (m_s+m_2)r^2[/tex]

[tex]MI_2 = (6.4+23)\times 1.5^2[/tex]

[tex]MI_2 = 66.15 \;\rm kg m^2[/tex]

The moment of inertia about the two empty seats is calculated given below.

[tex]MI_s = 2(m_sr^2)[/tex]

[tex]MI_s = 2 ( 6.4\times 1.5^2)[/tex]

[tex]MI_s = 28.8 \;\rm kgm^2[/tex]

The moment of inertia about the rotation axis is the total sum of the moment of inertia about the point of two children and the moment of inertia about the two seats.

[tex]MI = MI_1 +MI_2+MI_s[/tex]

[tex]MI = 50.4 + 66.15 + 28.8[/tex]

[tex]MI = 145.35 \;\rm kgm^2[/tex]

Therefore, the moment of inertia about the rotation axis is 145.35 kgm2.

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Answer: b. PREVALENCE

Explanation:

Prevalence can be defined as the proportion of individuals in a population having a disease or common characteristic. Prevalence of a particular disease is number of people in a population who have develop a disease at a particular time.

It can be expressed in form of proportion Which equals the number of developed cases at a particular time divided by the total number of population.

Answer

given,

acceleration, a = 5 g =  5 x 9.8 = 49 m/s²

speed of sound, v = 331 m/s

speed , v = 3 Mach = 3 x 331 m/s = 993 m/s

time, t = 5.2 s

a) Calculating the time period of black out.

  time required by the aircraft to black out

 using equation of motion

  v = u + a t

 initial velocity = 0 m/s

  993 = 0 + 49 t

   t = 20.26 s

the required time to reach 3 Mach speed is more than the given time hence, pilot will black out.

b) now, calculating the maximum speed it can reach in 5.2 s

 using equation of motion

  v = u + a t

 initial velocity = 0 m/s

  v = 0 + 49 x 5.2

 v = 254.8 m/s

Answer:

increase

Explanation:

think of climbing a mountain. the higher you go the harder it is to breathe. its because air pressure is increasing

Answer:

decrease.

Explanation:

The air pressure is given by

P = h x d x g

where, h is the height of air column above the surface and g be the acceleration due to gravity and d be the density of air.

As we go up, the height of air column decreases, density of air decreases and acceleration due to gravity also decreases, so the value of pressure decreases at altitudes.

Answer:

a) 31.02 m/s

b) - 653.24 m/s²

c) 50 ms

Explanation:

a) For a vertical movement, let's suppose that the woman fell by the rest, thus she's initial velocity v0 = 0 m/s. If she makes a distance (S) of 161 ft = 49.1 m, thus, her final velocity at the box, v is:

v² = v0² +2aS

The acceleration is the gravity acceleration, 9.8 m/s².

v² = 2*9.8*49.1

v² = 962.36

v =√962.36

v = 31.02 m/s

b) She crushes the box until she stops, so her final velocity will be 0 m/s. The initial velocity is now 31.02 m/s, and S = 29 in = 0.7366 m

0 = 31.02² + 2a*0.7366

-1.4732a = 962.36

a = - 653.24 m/s² (the negative signal indicates that she's dessacelaranting)

c) The time can be calculate by:

v = v0 + at

0 = 31.02 -653.24*t

653.24t = 31.02

t = 0.05 s = 50 ms

Answer:

Length of the stake will be 0.3623 m

Explanation:

We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J

Average resistive force acting on the floor is equal to F = 828 N

We have to find the length of the stake

We know that work done is given by

W = Fd, here W is work done , F is average force and d is the length of the stake

So 300 = 828×d

d = 0.3623 m

So length of the stake will be 0.3623 m

The length of the stake is approximately 0.362 meters.

To solve this problem, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done to drive the stake into the ground is equal to the potential energy gained by the stake when it is fully driven into the ground.

The work done (W) is given as 0.30 kJ, which is equal to 0.30 * 10^3 J.

The resistive force (F) is given as 828 N.

The distance (d) over which the work is done is the length of the stake.

We can use the formula for work:

[tex]\[W = F \cdot d\][/tex]

Rearranging the formula to solve for \(d\):

[tex]\[d = \frac{W}{F}\][/tex]

Substituting the given values:

[tex]\[d = \frac{0.30 \times 10^3 \, J}{828 \, N}\][/tex]

[tex]\[d = 0.362 \, m\][/tex]

Answer:

C

Explanation:

The answer is polarization. In a normal molecule the positive and negative charges are distributed in a way that it makes a continuous distribution with no net force. but when you apply an external electric force, the opposite charges go to the opposite ends of the molecule making them a polarized molecule.

This is called polarization.

I hope it helps you.

Thank you.  

Answer:

410.254 N

Explanation:

Force: This can be defined as the product of the mass of a body. The Unit of force is Newton (N)

Deduced from the question,

Force applied to the box to start it moving = Force of friction.

Fₐ = F

Where Fₐ = Force applied to the box to start it moving, F = Force of friction.

But,

F = μR.......................... Equation 1

Where R = normal reaction, μ = coefficient of static friction.

R = W =  mg ( on a level surface)

Where m = mass of the box = 123 kg, g = acceleration due to gravity = 9.81 m/s²

R = 123×9.81

R = 1206.63 N.

Also, μ = 0.34

Substituting into equation 1

F = 1206.63×0.34

F = 410.254 N.

Thus the force applied to the box to start it moving = 410.254 N

The question requires arranging substances by density, a fundamental physics concept, calculated as mass divided by volume. Understanding densities, from light gases to dense neutron stars, is essential in both everyday applications and advanced scientific fields.

The question involves arranging substances in order of increasing density based on given masses and volumes. Density is the measure of how much mass is contained in a given volume, and this concept is fundamental in physics. By calculating the density of each substance using the formula density = mass/volume (expressed in g/cm³ for solids and liquids or g/L for gases), we can compare the densities of the substances and arrange them accordingly. It is crucial to recognize that the density of a material is a characteristic property that can help in identifying the material and understanding its behavior in different environments.

Density plays a significant role in various applications, such as determining whether an object will float or sink in a fluid, in material selection for construction, and in understanding the structure of the universe, from the density of air we breathe (1.2 g/L) to the dense core of neutron stars reaching up to 10¹⁵ g/cm³.

To arrange the substances in order of increasing density, we need to calculate the density of each substance using the formula [tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]

Then, we compare the calculated densities to determine their relative order.

Here's how the substances could be ranked:

1. Helium gas: Since helium gas is the least dense substance, it will have the lowest density.

2. Cork: Cork typically has a low density compared to other materials.

3. Water: Water has a moderate density, higher than helium gas and cork.

4. Aluminum: Aluminum generally has a higher density than water.

5. Iron: Iron is denser than aluminum, making it the densest substance among the listed ones.

By comparing the calculated densities, we can arrange the substances in increasing order of density from lowest to highest: helium gas, cork, water, aluminum, and iron.

Answer:

20.6m

Explanation:

The mass is useless in this case.  

Kinetic Energy = Potential Energy

g is acceleration due to gravity.

(1/2)mv² = mgh (m's drop out)

(1/2)v² = gh

(1/2)(20.1²) = 9.81(h)

h = (20.1 x 20.1)/9.81 x 2

20.61 meters