A tow truck charges a service fee of $50 and an additional fee of $1.75 per mile. What distance was Marcos's car towed if he received a bill for $71?

Answer:

C. [tex]x\leq 5[/tex]; Lisa can buy 5 pounds or less of tomatoes.

Step-by-step explanation:

We have been given an inequality [tex]1.20x+1.80\leq 7.80[/tex], where x is the number of pounds of tomatoes. The inequality represents amount spend by Lisa on tomatoes and loaf. We are asked to find number of pounds that Lisa can buy.

First of all, we will subtract 1.80 from both sides of our inequality.

[tex]1.20x+1.80-1.80\leq 7.80-1.80[/tex]

[tex]1.20x\leq 6.00[/tex]

Now, we will divide both sides of our inequality by 1.20.

[tex]\frac{1.20x}{1.20}\leq \frac{6.00}{1.20}[/tex]

[tex]x\leq 5[/tex]

Therefore, Lisa can buy 5 pounds or less of tomatoes and option C is the correct choice.

Answer:ANSWER

The correct answer is C

EXPLANATION

is just the y-value of the point where

That is, the image of 1.

If we were given the function

,we would have plug in 1 to find

Since the function is not given, we were given the graph so that we trace

from it.

So we read from the grid to find that y-value .

Each grid is one unit. So moving one unit on the x-axis and two units on the y-axis will give us the point

This means that,

ANSWER The correct answer is C EXPLANATION [tex]B(1)[/tex] is just - 1

Step-by-step explanation:

Answer:

The decay factor is 0.88.

Step-by-step explanation:

The general form of an exponential decay function is

[tex]f(x)=ab^x[/tex]

Where, a is initial value and b is decay factor.

It is given a new truck that sells for $29,000 depreciates (decreases in value) 12% each year.

The initial value is $29,000 and decay factor is

[tex]1-r=1-\frac{12}{100}=1-0.12=0.88[/tex]

The exponential function is

[tex]f(x)=29000(0.88)^x[/tex]

Therefore the decay factor is 0.88.

The decay factor b for the truck, which depreciates 12% each year, is 0.88.

The decay factor, b, for the truck's depreciation can be calculated using the formula for exponential decay:

b = 1 - r

where r is the annual depreciation rate. In this case, the annual depreciation rate is given as 12%, or 0.12 in decimal form.

Now, let's calculate the decay factor:

b = 1 - 0.12

b = 0.88

So, the decay factor for the truck's depreciation is 0.88.

The decay factor is used to calculate the value of the truck after n years by raising b to the power of n and multiplying it by the initial value of the truck. The formula for the value of the truck after n years is:

[tex]\[ V(n) = P \cdot b^n \][/tex]

where P is the initial price of the truck, b is the decay factor, and n is the number of years.

In this case, the initial price P is $29,000, and the decay factor b is 0.88. If we want to find the value of the truck after, say, 5 years, we would use the formula:

[tex]\[ V(5) = 29000 \cdot (0.88)^5 \][/tex]

However, the question only asks for the decay factor, which we have already determined to be 0.88.

Answer: C) mC > mA > mB is correct regarding the angles of the  triangle ABC.

Step-by-step explanation:

Given: In Δ ABC, the side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3.

AB=4p-1 , AC=p+4 , BC=3p

where p+4 < 3p        [as p≥3]

3p < 4p-1          [as p≥3]

⇒  4p-1> 3p > p+4

⇒AB>BC>AC

Angle opposite to AB ,BC and AC is m∠C ,m∠A and m∠B.

Therefore mC > mB > mA    [∵Angle opposite to greater side is greater]

Thus , mC > mA > mB is correct regarding the angles of the  triangle ABC.

Answer:

C

Step-by-step explanation:

The total cost of the power tools set if Jackson must pay off the tools within two years after the deferment period is  $2,644.82.

To find the total cost of the power tools set after the deferred payment period, we need to consider both the initial cost of the tools and the interest accrued during the deferment period and the subsequent payment period.

First, let's calculate the interest accrued during the deferment period:

Interest = Principal × Rate × Time

Interest = $1,543 × 23.76% × (6/12)   (since the deferment period is 6 months)

Interest = $1,543 × 0.2376 × 0.5

Interest = $183.78

Now, add this interest to the initial cost of the power tools:

Total cost after deferment = Initial cost + Interest

Total cost after deferment = $1,543 + $183.78

Total cost after deferment = $1,726.78

Next, we need to calculate the total amount Jackson must pay off within two years after the deferment period. This includes the principal amount and the interest accrued during the payment period. We'll use the formula for calculating the total payment for a loan with compound interest:

[tex]\[A = P(1 + r/n)^{nt}\][/tex]

Where:

A = Total amount to be paid

P = Principal amount (initial cost after deferment)

r = Annual interest rate (as a decimal)

n = Number of times interest is compounded per year

t = Time in years

In this case, we'll compound interest annually, so (n = 1), and (t = 2) years.

[tex]\[A = $1,726.78(1 + 0.2376/1)^{1*2}\][/tex]

[tex]\[A = $1,726.78(1 + 0.2376)^2\][/tex]

[tex]\[A = $1,726.78(1.2376)^2\][/tex]

[tex]\[A = $2,644.82\][/tex]

So, the total cost of the power tools set if Jackson must pay off the tools within two years after the deferment period is  $2,644.82.

To solve the problem, set up and solve an algebraic equation. Find the value of x, then use it to determine the number of years it will take for you to be twice as old as your brother.

To solve this problem, we can use algebraic equations. Let's assume the age of your brother is x. Since you are four times as old as your brother, your age would be 4x. In two years, your age would be 4x + 2, and your brother's age would be x + 2. According to the problem, 4x + 2 = 3(x + 2). We can solve this equation to find x, and then determine the number of years it will take for you to be twice as old as your brother.

By simplifying the equation, we get 4x + 2 = 3x + 6. Subtracted 3x from both sides, we get x + 2 = 6. Subtracting 2 from both sides, we get x = 4.

So, your brother's age is currently 4 and your age is currently 16. To determine the number of years it will take for you to be twice as old as your brother, we need to find the value of y that satisfies the equation 2(4 + y) = 16 + y. By solving this equation, we'll find that it will take 8 years for you to be twice as old as your brother.

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Option: A is the correct answer.

              The axis of symmetry is:

                      A.    x=3/2      

We are given a graph as:

[tex]y+3x-6=-3(x-2)^2+4[/tex]

and

[tex]y=-3(x-2)^2+4+6-3x[/tex]

and

[tex]y=-3[(x-2)^2+x]+10\\\\i.e.\\\\y=-3[x^2+4-4x+x]+10\\\\i.e.\\\\y=-3[x^2-3x+4]+10[/tex]

This equation could also be written in the form:

[tex]y=-3[x^2-3x+4-\dfrac{9}{4}+\dfrac{9}{4}]+10\\\\i.e.\\\\y=-3[(x-\dfrac{3}{2})^2+4-\dfrac{9}{4}]+10\\\\i.e.\\\\y=-3[(x-\dfrac{3}{2})^2+\dfrac{7}{4}]+10\\\\i.e.\\\\y=-3(x-\dfrac{3}{2})^2-3\times \dfrac{7}{4}+10\\\\i.e.\\\\y=-3(x-\dfrac{3}{2})^2+\dfrac{19}{4}[/tex]

Now, we know that for any general equation of the type:

[tex]y=a(x-h)^2+k[/tex]

The axis of symmetry of the graph of the equation is:

[tex]x=h[/tex]

Here we have:

[tex]h=\dfrac{3}{2}[/tex]

            Hence, the answer is: Option: A

this was correct on my test, hope it helps! ;)

(Brainliest would help a lot btw)

Option: B is the correct answer.

B.  The number of excluded values of a rational expression cannot exceed the degree of the denominator.

We know that a rational expression is a expression of the form:

[tex]\dfrac{p(x)}{q(x)}[/tex]

where p(x) and q(x) are polynomials.

Excluded value--

The excluded value of a rational expression are the values where the denominator of the expression is zero.

Also, the number of zeros of a polynomial is always less than or equal to degree of the polynomial.

Hence, the  number of excluded values of a rational expression cannot exceed the degree of the denominator.

         The answer is:

            Option: B

abcdefghijklmnopqrstuvwxyz

The graph of y = x⁴ is also a parabola that opens upward and it is an even function.

The blue graph represents a quadratic function and the red graph represents a biquadratic function.

A function can be defined as the outputs for a given set of inputs.

The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.

We also know that graph of a quadratic function y = x² is a parabola,

Now, the graph of y = x⁴ will also be a parabola,

and it is more steeper or has a greater slope than the graph y = x² as the independent variable has a larger exponent value it is also an even function that is symmetric about the y-axis.

learn more about the graph of functions here :

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Answer:

[tex]r>\frac{4 +\sqrt{23732} }{154} \approx1.03\\[/tex]

Step-by-step explanation:

The area of the rectangular rug is given by this equation:

[tex]77r^2-4r-77[/tex]

The area must be a number greater than 0 since a negative area, or an area equal to 0 wouldn't have much sense. So:

[tex]77r^2-4r-77>0[/tex]

Let's find the roots of this equation using the quadratic formula:

[tex]r=\frac{-b\pm \sqrt{b^2-4ac} }{2a} =\frac{-(-4)\pm\sqrt{(-4)^2-(4)(77)(-77)} }{2(77)} \\\\r=\frac{4 \pm \sqrt{23732} }{154} \\\\r_1=\frac{4 +\sqrt{23732} }{154} \approx1.03\\\\r_2=\frac{4 - \sqrt{23732} }{154} \approx-0.97[/tex]

Now, let's evaluate the area for [tex]r>r_1[/tex] for example r=1.05:

[tex]A=77(1.05)^2-4(1.05)-77=3.6925>0[/tex]

The result is greater than zero, so for [tex]r>r_1[/tex] the values make sense.

Now let's evaluate the area for [tex]r_2<r<r_1[/tex] for example r=0.5 and r=-0.7:

[tex]A=77(0.5)^2-4(0.5)-77=-59.75<0\\\\A=77(-0.7)^2-4(-0.7)-77=-36.47<0[/tex]

The result is less than zero, so for [tex]r_2<r<r_1[/tex] the values don't make sense.

Now, let's evaluate the area for [tex]r<r_2[/tex] for example r=-1:

[tex]A=77(-1)^2-4(-1)-77=4>0[/tex]

The result is greater than zero, so for [tex]r<r_2[/tex] the values make sense

However, since negative values of r wouldn't make much sense (I never heard about of -8 inches for example) the possible dimensions of the​ rug are just:

[tex]r>\frac{4 +\sqrt{23732} }{154} \approx1.03\\[/tex]

To find the total amount of money in nickels, quarters, and dimes, we need to add the value of each coin together. In this case, the total amount of money is represented by the expression 60x + 50 cents.

To find the total amount of money, we need to determine the value of each coin in cents. A nickel is worth 5 cents, a quarter is worth 25 cents, and a dime is worth 10 cents.

The total amount of money in x nickels is 5x cents. The total amount of money in (x+2) quarters is 25(x+2) cents. The total amount of money in 3x dimes is 30x cents.

Adding these values together, we can find the total amount of money:

Total amount of money = 5x + 25(x+2) + 30x cents Now, simplify the expression:

Total amount of money = 5x + 25x + 50 + 30x cents

Total amount of money = 60x + 50 cents

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Answer:

62.1371 miles/hr

Step-by-step explanation:

The posted speed limit in many parts in Europe = 100 kilometers per hour

We have to convert the speed limit into miles per hour.

As we know, 1 kilometer = 0.621371 miles

Therefore, 100 kilometers = 100 × 0.621371

                                           = 62.1371 miles

The equivalent speed of 100 km/hr is 62.1371 miles/hr.

Number of days Julia took to learn 145 word is 21 days.

Given that, Julia knows 19 latin words. Each day, she learns 6 new words.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the number of days be x.

Here, 145-19=126

Number of days = 126/6

= 21

Therefore, number of days Julia took to learn 145 word is 21 days.

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Answer:

40 farms

Step-by-step explanation:

Given :

A mango farm contains 1250 mango trees.

Each tree produces an average of 160 mangoes .

To Find : No. of mango farms needed to produce 8,000,000 mangoes .

Solution :

1 farm contains 1250 mango trees

Each tree produces an average of 160 mangoes .

1250 trees produces mangoes = 1250 *160 = 200000.

⇒ 1 farm produces 200000 mangoes

Now to calculate  mango farms are needed to produce 8,000,000 mangoes .

No. of Farm produces 200000 mangoes = 1

So, farms needed to produce  8,000,000 mangoes  = 8000000/200000 = 40 farms.

Thus 40 farms are required to produce 8,000,000 mangoes during the summer.

A bar graph would be the best way to summarize this information for display the data.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

Andrea surveyed her classmates asking what type of pets they have.

Hence To show this on graph bar graph would be the best way to summarize this information for display the data.

Because, Bar graphs show comparisons between distinct categories and display changes over time.

Thus, A bar graph would be the best way to summarize this information for display the data.

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The fish swims 264 yards per minute faster than the boy.

To find out how much faster the fish swims than the boy in yards per minute, we first need to convert both speeds to yards per minute. Since 3 feet is equal to 1 yard, we can convert the fish's speed of 4.4 feet per second to yards per minute by multiplying it by (3 feet/1 yard) × (60 seconds/1 minute) = 4.4 × 3 × 60 yards per minute = 792 yards per minute. Similarly, the boy's speed of 12 miles per hour can be converted to yards per minute by multiplying it by (5280 feet/1 mile) × (1 yard/3 feet) × (1 hour/60 minutes) = 12 × 5280/3/60 yards per minute = 1056 yards per minute.

To find out how much faster the fish swims than the boy, we subtract the boy's speed from the fish's speed: 792 - 1056 = -264 yards per minute. Therefore, the fish swims 264 yards per minute faster than the boy.

Answer:

false

Step-by-step explanation:

Answer:

1. Using your straightedge, draw a reference line, if one is not provided.

2. Copy the side of the square onto the reference line, starting at a point labeled A'.

3. Construct a perpendicular at point B' to the line through ab2.

4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.

5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.

6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.

7. Connect points A' to D, D to C, and C to B' to form a square.

Step-by-step explanation: