I shall draw this out as these tend to be answered best visually
A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with nearly the same speed with which it hit. The clay sticks to the wall. Which one of these objects experiences the greater momentum change?
Answer:
The ball experiences the greater momentum change
Explanation:
The momentum change of each object is given by:
[tex]\Delta p = m \Delta v= m (v-u)[/tex]
where
m is the mass of the object
v is the final velocity
u is the initial velocity
Both objects have same mass m and same initial velocity u. So we have:
- For the ball, the final velocity is
[tex]v=-u[/tex]
Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is
[tex]\Delta p=m(v-u)=m((-u)-u)=-2mu[/tex]
- For the clay, the final velocity is
[tex]v=0[/tex]
since it sticks to the wall. So, the change in momentum is
[tex]\Delta p = m(v-u)=m(0-u)=-mu[/tex]
So we see that the greater momentum change (in magnitude) is experienced by the ball.
The ball has more momentum as compared to clay due to its higher motion.
Which have more momentum?The ball experiences the greater momentum change because it bouce back by the wall with the same amount of force while on the other hand, the clay sticks to the wall and stopped its motion
So we can conclude that the ball has more momentum as compared to clay due to its higher motion.
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A wheelbarrow is an example of what type of lever
A wheelbarrow is a 2nd class lever. Your hands on the handles give the effort. The load inside the wheelbarrow is the resistance. The wheel is the fulcrum. When you lift up the handles, the load goes up in the same direction.
A wheelbarrow exemplifies a second-class lever, where the load is between the fulcrum (wheel's axle) and the input force, enabling the lifting of heavier loads through mechanical advantage.
Explanation:A wheelbarrow is an example of a second-class lever. In this type of lever, the load is situated between the fulcrum and the effort force. A wheelbarrow enables the user to lift heavier loads more easily due to the arrangement of the forces involved.
A wheelbarrow is an example of a second-class lever. In this type of lever, the output force or load is located between the fulcrum (pivot point) and the input force. The fulcrum in the case of a wheelbarrow is the wheel's axle. This arrangement allows the wheelbarrow to lift heavier loads than one could manually, due to the mechanical advantage achieved by the lever's design. A key characteristic of second-class levers is that both the input and output forces are on the same side of the fulcrum, making tasks like lifting and carrying heavy materials more manageable. This principle underscores the effectiveness of simple machines in amplifying human effort to accomplish tasks more efficiently.
Which type of telescope focuses star light using mirrors?
Coudé telescopes use a convex secondary mirror like a Cassegrain and an angled mirror like a Newtonian reflector to move the light rays to a focal point away from the telescope. This arrangement is useful when optical equipment is being used that is too heavy to mount directly on the telescope.
Final answer:
Reflecting telescopes, also known as reflectors, focus starlight using mirrors. The main optical element in a reflecting telescope is a concave mirror, which reflects light and forms an image at the focus. Reflecting telescopes have different options for bringing the light to a focus, such as the Cassegrain focus.
Explanation:
Reflecting telescopes, also known as reflectors, focus starlight using mirrors.
The main optical element in a reflecting telescope is a concave mirror, which is curved like the inner surface of a sphere. This mirror reflects light and forms an image at the focus of the mirror. The mirror is coated with a shiny metal, such as silver, aluminum, or occasionally gold, to make it highly reflective.
Reflecting telescopes have different options for where the light is brought to a focus. For example, with a Cassegrain focus, light is reflected by a secondary mirror down through a hole in the primary mirror to an observing station below the telescope.
50 POINTS! If the moon were twice as massive but twice as far from Earth, high tides on Earth would be – (think of it’s force)
a. higher
b. lower
c. no different
The answer would be C. If its twice as massive, AND twice as far, nothing would really change.
If the moon were twice as massive but twice as far from Earth, high tides on Earth would be lower.
Answer: Option B
Explanation:
The occurrence of high tides on Earth is due to the gravitational force of moon acting on the sea water. So the gravitational force of moon during full moon day will be maximum as the distance between Earth and Moon will be minimum during this time and thus the moon’s gravity will be pulling the sea water towards itself leading to the formation of high tides.
As the high tides are formed due to the gravitational force acting between moon and Earth, the mathematical representation will be
[tex]F=\frac{G M_{\text {moon }} M_{\text {Earth}}}{d^{2}}[/tex]
Let the F be the normal gravitational force acting between moon and Earth with [tex]M_{\text {moon }}[/tex] and [tex]M_{\text {earth }}[/tex] as the mass of moon and Earth, respectively and d be the distance of separation of moon from Earth.
Now if we consider the special case given here where the mass of moon is doubled and also the distance of separation of moon from the earth is also doubled. So the new gravitational force with the parameters and comparing we get
[tex]F^{\prime}=\frac{G M_{\text {moon }}^{\prime} M_{\text {earth }}}{d^{\prime 2}}[/tex]
[tex]F^{\prime}=\frac{2 \times G \times M_{\text {moon}} \times M_{\text {earth}}}{4 d^{2}}[/tex]
[tex]F^{\prime}=\frac{1}{2} F[/tex]
So as the gravitational force between Earth and moon will be reduced to half on doubling the distance of separation as well as mass of the moon, the occurrence of high tides will be lower with the given conditions.
using the diagram at the right and thinking of what you have already leaned about the relationship between frequency and the wavelength of a sound wave, complete the two sentences here:
a. as a moving sound source approaches a stationary observer, the frequency of the sound increases, therefore the wavelength is_________(longer or shorter)
b. As the sound source moves away from the observer, the pitch of the sound __________ and the wavelength ___________.
a. as a moving sound source approaches a stationary observer, the frequency of the sound increases, therefore the wavelength is shorter
Explanation:
This effect is known as Doppler effect. When a moving sound source approaches a stationary observer, the wavefronts of the wave appear to be closer to each other: as a result, the frequency of the sound wave appears to be increased. The wavelength of the sound is inversely proportional to the frequency:
[tex]\lambda=\frac{v}{f}[/tex]
where v is the speed of the wave and f the frequency: therefore, as the frequency increases, the wavelength gets shorter.
b. As the sound source moves away from the observer, the pitch of the sound decreases and the wavelength increases
Explanation:
When the sound source moves away from the observer, the effect is opposite: the wavefronts appear to spread apart from each other, so the frequency of the sound appears to decreases, and as a result, the wavelength increases.
The pitch of a sound is related to how we perceive the sound, and it is directly proportional to the frequency: therefore, since the frequency decreases, the pitch decreases as well.
In the nucleus of an atom, two protons are separated are by a distance of 1*10^-15m. What is the magnitude of the electric force between them?
A. 115N
B. 720N
C. 142N
D. 230N
Answer:
D. 230 N
Explanation:
The magnitude of the electric force between the two protons is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
[tex]q_1 = q_2 = 1.6\cdot 10^{-19} C[/tex] is the charge of each proton
[tex]r=1\cdot 10^{-15} m[/tex] is the distance between the two protons
Substituting numbers into the formula, we find
[tex]F=(9\cdot 10^9 N m^2 C^{-2}) \frac{(1.6\cdot 10^{-19} C)^2}{(1\cdot 10^{-15} m^2)^2}=230.4 N \sim 230 N[/tex]
A typical american family uses 1000 kwh of electricity pro 30 days. you may want to review ( pages 847 - 849) . part a what is the average rms current in the 190 v power line to the house?
=25.99 ohms
Explanation;A month has 30 days equivalent to 720 hours.
1000 kwh is equivalent to 1000000 watt,
Then 1000000 watt divided by 720
wattage per hour=1388.9
Therefore;
Wattage/hr divided by line voltage is equivalent av. current
= 1388.9 W/hr ÷ 190 v
= 7.31 amperes
Assuming that the load is 'resistive' and not inductive
Resistance is voltage divided by current;
= 190/7.31
=25.99 ohms
Oxygen is a diatomic gas. How many oxygen molecules are in 16 grams of oxygen?
1 mol of oxygen molecules = 2 * 16 = 32 grams.
x mol of oxygen = 16 grams
1/x = 32/16 Cross multiply
16 = 32x Divide by 32
16/32 = x
x = 1/2 mol
1 mol of anything has 6.02 * 10^23 somethings (molecules in this case).
1/2 mol = 6.02 *10^23 / 2
1/2 mol = 3.01 * 10^23 molecules <<<< answer
What causes irregular galaxies to be irregular
Irregular galaxies get their odd shapes in many ways. One way irregular galaxies are formed is when galaxies collide or come close to one another, and their gravitational forces interact. Another source of irregular galaxies may be very young galaxies that have not yet reached a symmetrical state.
When galaxy's collide or close close to one another or the galaxy may be very young and haven't reached a symmetrical state
An electron in a TV picture tube is accelerated through a potential difference of 10 kV before it hits the screen. What is the kinetic energy of the electron in electron volts?(1 eV = 1.6 ? 10 -19 J)
The kinetic energy of an electron accelerated through a 10 kV potential difference is 10,000 eV, with 1 eV being the energy given to a charge accelerated through 1 V.
Explanation:The kinetic energy of an electron accelerated through a potential difference is directly related to the voltage it is accelerated through. If an electron is accelerated through a potential difference of 10 kV (10,000 V), then it will be given an energy of 10,000 eV since 1 eV is defined as the energy given to a fundamental charge accelerated through 1 V. Therefore, the kinetic energy of the electron in your case is 10,000 eV.
In this scenario, the potential difference represents the energy gained by the electron as it moves through the electric field. The kinetic energy is given by the product of the elementary charge and the potential difference. This is based on the fundamental relationship in electrostatics that the work done (and therefore the energy gained) by a charged particle moving through an electric field is equal to the product of the charge and the potential difference.
A parallel-plate capacitor is constructed from two 6.0 cm × 6.0 cm electrodes spaced 1.5 mmapart. The capacitor plates are charged to ± 10 nC , then disconnected from the battery.Part AHow much energy is stored in the capacitor?Express your answer using two significant figures.
Part B
Insulating handles are used to pull the capacitor plates apart until the spacing is 1.7 mm . Now how much energy is stored in the capacitor?Express your answer using two significant figures.
Part CEnergy must be conserved. How do you account for the difference between A and B?
A) [tex]2.4\cdot 10^{-6} J[/tex]
The energy stored in a capacitor is given by:
[tex]E=\frac{1}{2}\frac{Q^2}{C}[/tex]
where
Q is the charge stored
C is the capacitance
The capacitance of a parallel-plate capacitor is
[tex]C=\frac{\epsilon_0 A}{d}[/tex]
where
[tex]\epsilon_0 = 8.85\cdot 10^{-12} F/m[/tex] is the vacuum permittivity
[tex]A=6.0 cm \cdot 6.0 cm=36.0 cm^2=36\cdot 10^{-4} m^2[/tex] is the area of each plate
[tex]d=1.5 mm=0.0015 m[/tex] is the distance between the plates
Substituting,
[tex]C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0015 m}=2.1\cdot 10^{-11} F[/tex]
The charge stored on the capacitor is
[tex]Q=10 nC=10\cdot 10^{-9}C[/tex]
So, the energy stored is
[tex]E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{2.1\cdot 10^{-11} F}=2.4\cdot 10^{-6}J[/tex]
B) [tex]2.6\cdot 10^{-6}J[/tex]
This time, the separation between the plates is
d = 1.7 mm = 0.0017 m
So, the new capacitance is
[tex]C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0017 m}=1.9\cdot 10^{-11} F[/tex]
And so, the new energy stored is
[tex]E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{1.9\cdot 10^{-11} F}=2.6\cdot 10^{-6}J[/tex]
C)
Energy must be conserved, so the difference between the initial energy of the capacitor and its final energy is just equal to the work done to increase the separation between the two plates from 1.5 mm to 1.7 mm (in fact, the two plates of the capacitor attract each other since they have opposite charge, so work must be done in order to increase their separation)
Final answer:
The energy stored in the capacitor initially is 2.355 × 10−9 J. After increasing the plate separation, the energy stored becomes 2.674 × 10−9 J. The difference in energy is accounted for by the work done to separate the plates, which adds to the electric potential energy.
Explanation:
Part A: Energy Stored in the Capacitor
The energy stored in a capacitor can be calculated using the formula:
U = ½ QV
where U is the stored energy, Q is the charge, and V is the potential difference across the capacitor plates. To find V, we need to use the capacitance C, which is given by:
C = ε0 (A/d)
where ε0 is the permittivity of free space (ε0 = 8.85 × 10−12 F/m), A is the area of one of the plates, and d is the separation between the plates. Substituting the values, we find:
C = 8.85 × 10−12 F/m · (0.06 m × 0.06 m) / 0.0015 m
C = 2.124 × 10−9 F
The potential difference V is found using:
V = Q/C
V = 10 × 10−9 C / 2.124 × 10−9 F
V = 4.71 V
Substituting back into the energy formula, we get:
U = ½ × 10 × 10−9 C × 4.71 V
U = 2.355 × 10−9 J
Part B: Energy Stored After Increasing Plate Separation
When the plate separation is increased, the capacitance C changes, which affects the stored energy, but the charge Q remains the same as the capacitor was disconnected from the battery. We recalculate C with the new distance:
C' = 8.85 × 10−12 F/m · (0.06 m × 0.06 m) / 0.0017 m
C' = 1.870 × 10−9 F
The stored energy now is:
U' = ½ × 10 × 10−9 C × (10 × 10−9 C / 1.870 × 10−9 F)
U' = 2.674 × 10−9 J
Part C: Accounting for Energy Difference
Since energy must be conserved, the work done to separate the plates must be accounted for. The increase in energy observed is the mechanical work done to pull the plates apart against the attractive force between them. This work is converted into additional electric potential energy stored in the capacitor as it has a larger separation and hence an increased potential difference.
Several paper clips dangle from the north pole of a magnet. The induced pole in the bottom of the lowermost paper clip is a
A) north pole.
B) south pole.
C) north or south pole - no difference really.
I wanna say it’s B.
Trying to escape his pursuers, a secret agent skis off a slope inclined at 30° below the horizontal at 55 km/h. to survive and land on the snow 100 m below, he must clear a gorge 43 m wide. does he make it? ignore air resistance.
The agent made it since the range of his motion is greater than the width of the gorge.
The given parameters;
inclination of the slope, Ф = 30°velocity of the agent, v = 55 km/h vertical distance below the snow, h = 100 mwidth of the gorge the agent must cross, w = 43 mAssume downward motion to be negative.
The initial vertical component of the velocity in m/s;
[tex]v_0_y = v_0 \times sin(30)\\\\v_o_y = - 55 \ km/h \times sin(30) = -27.5 \ km/h = -7.64 \ m/s[/tex]
Determine the final vertical velocity of the agent;
[tex]v_y_f^2 = v_0_y^2 - 2gh\\\\v_y_f^2 = (-7.64)^2 - 2(9.8)(-100)\\\\v_y_f^2 = 2018.37\\\\v_y_f = \sqrt{2018.37} \\\\v_y_f = -44.93 \ m/s[/tex]
Determine the time of motion;
[tex]v_y_f = v_0y - gt\\\\-44.93 = -7.64 - 9.8t\\\\9.8t = 44.93 - 7.64\\\\9.8t = 37.29\\\\t = \frac{37.29}{9.8} = 3.81 \ s[/tex]
Determine the horizontal component of the initial velocity;
[tex]v_0_x = v_0 \times cos(\theta)\\\\v_0_x = 55 \ km/h \times cos(30) = 47.63 \ km/h = 13.2 \ m/s[/tex]
Determine the range of the of the agent's motion;
[tex]X = v_0_x \times t\\\\X = 13.2\ m/s \times 3.81 \ s\\\\X = 50.3 \ m[/tex]
Thus, the agent made it since the range of his motion is greater than the width of the gorge.
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Using the principles of projectile motion, we can determine that the secret agent will be able to clear the gorge and make it safely across. The agent's horizontal distance covered is 76.09 m, which is greater than the width of the gorge (43 m).
Explanation:To determine if the secret agent can make it across the gorge, we need to analyze his motion using the principles of projectile motion. Since the slope is inclined at 30° below the horizontal, we can break down the velocity into horizontal and vertical components. The horizontal component remains constant, while the vertical component changes due to the acceleration due to gravity. We can use the kinematic equations to determine the time it takes for the agent to reach the other side of the gorge. If the time is less than the time it takes for the agent to fall vertically, then he will clear the gorge and land safely on the snow.
Given that the agent skis off the slope at a speed of 55 km/h, we first need to convert this to m/s. 55 km/h is equal to 15.28 m/s. The horizontal component of the velocity remains constant at 15.28 m/s. We can determine the vertical component by multiplying the speed by the sine of the angle (30°). The vertical component is therefore 7.64 m/s. Using the equation d = v*t + 0.5*a*t^2, we can solve for time using the vertical component and the vertical distance of 100 m. Plugging in the values, we get:
100 = 7.64*t + 0.5*(-9.8)*t^2
This equation simplifies to:
4.9*t^2 + 7.64*t - 100 = 0
Solving for t, we find two possible values, t = -4.22 s and t = 4.98 s. Since time cannot be negative, we discard the negative value, leaving us with t = 4.98 s. Now we need to determine the horizontal distance the agent will travel during this time. We can use the equation d = v*t, plugging in the horizontal velocity and time:
d = 15.28 m/s * 4.98 s = 76.09 m
The horizontal distance covered by the agent is 76.09 m. Since the gorge is 43 m wide, the agent will be able to clear the gorge and make it across safely. Therefore, the secret agent does make it across the gorge.
A device experiences a voltage drop of 5.0 V across it while a current of 10.0 mA flows through it. How much power does it dissipate? Show all work and include units of measure.
Answer:
0.05 W
Explanation:
The power dissipated by a device can be written as
[tex]P=VI[/tex]
where
P is the power dissipated
V is the voltage drop on the device
I is the current flowing through the device
In this problem, we have
V = 5.0 V is the voltage drop across the device
I = 10.0 mA = 0.01 A is the current through it
By applying the formula, we find the power dissipated:
[tex]P=(5.0 V)(0.01 A)=0.05 W[/tex]
The net force acting on the box is 18 N. What is the force of friction? –22 N –4 N 4 N 22 N
Answer:
-4n
Explanation:
Answer:
B
Explanation
Evolution
A Baseball player rounds third base and is heading for home when he is signalled by the base coach to slide. The player has a speed of 3.5 m/s when he begins to slide and he travels through a linear distance of 1.50 m before coming to rest. Determine the coefficient of kinetic friction between him and the ground.
Answer:
0.42
Explanation:
The force of friction exerted on the player is:
[tex]F_f = -\mu mg[/tex] (1)
where
[tex]\mu[/tex] is the coefficient of kinetic friction
m is the mass of the player
g is the acceleration due to gravity
According to Newton's second law,
[tex]F_f = ma[/tex] (2)
where a is the player's acceleration. Substituting (1) into (2),
[tex]a=-\mu g[/tex] (3)
So in order to find [tex]\mu[/tex], we need to find the acceleration. We know the following:
u = 3.5 m/s is the initial speed of the player
v = 0 is the final speed
d = 1.50 m is the distance travelled
So we can use the following equation
[tex]v^2-u^2 = 2ad[/tex]
and solving for a
[tex]a=\frac{v^2-u^2}{2d}=\frac{0-(3.5 m/s)^2}{2(1.50 m)}=-4.1 m/s^2[/tex]
Substituting this into (3), we find the coefficient of kinetic friction:
[tex]\mu = -\frac{a}{g}=-\frac{-4.1 m/s^2}{9.8 m/s^2}=0.42[/tex]
A force that acts among sliding parts is referred to as kinetic friction force. The coefficient of kinetic friction between him and the ground is 0.415.
What is kinetic friction?A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion.
The size of the force will be determined by the kinetic friction coefficient between the two materials.
The given data in the problem is;
μ is the coefficient of kinetic friction=?
m is the mass of the player
g is the acceleration due to gravity= 9.81 m/s²
v is the speed of the player=3.5m/sec
x is the linear distance travelled=1.50 m
According to Newton's third equation of motion;
[tex]\rm v^2=u^2+2ax\\\\ \rm v^2-u^2=2ax\\\\ \rm a=\frac{ v^2-u^2}{2x} \\\\ \rm a=\frac{ 0^2-(3.5)^2}{2\times1.50}\\\\ \rm a=-4.08m/s^2[/tex]
The formula for the acceleration for the kinetic friction will be;
[tex]\rm a=\mu g \\\\ \rm \mu=\frac{a}{g} \\\\ \rm \mu=\frac{-4.08}{9*.81}\\\\ \rm \mu=0.415[/tex]
Hence the coefficient of kinetic friction between him and the ground is 0.415.
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Fill in the blanks to complete the statements. If an object changes speed or , its velocity also changes. Any change in results in acceleration.
Answer:
If an object changes speed or direction, its velocity also changes. Any change in velocity results in acceleration.
If an object changes speed or direction , its velocity also changes. Any change in results velocity in acceleration.
What are the term velocity and direction means and related?
Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of timeDirection means the path along which something moves, lies, or points I'm coming from the opposite direction.The direction of the velocity vector is simply the same as the direction that an object is moving. It would not matter whether the object is speeding up or slowing down. If an object is moving rightwards, then its velocity is described as being rightwards.Direction and Velocity are the two missing words in the sentence.
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Jamal read a story on the Internet called "Barking Dogs Don't Bite." In the story, the main character told everyone that a dog that barks will not bite. Jamal remembered that he had been bitten the previous summer by a dog that first barked at him. What can Jamal conclude?
Force is a vector because it has both size and
A force is a vector quantity. As learned in an earlier unit, a vector quantity is a quantity that has both magnitude and direction. To fully describe the force acting upon an object, you must describe both the magnitude (size or numerical value) and the direction.
A hydraulic jack is used to lift a car in order to change a tire. The car exerts a force of 9,800 N toward the ground due to the force of gravity. To begin to lift the car, a hydraulic jack must produce of force. To keep the car in position once it is lifted, the jack must produce of force.
To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.
To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.
Answer:
To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.
To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.
A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N, how much area is in contact with the ground?
10,000,000 m2
0.1 m2
11,000 m2
10 m2
Pressure = (total force) / (Area)
10,000 Pa = (1,000 N) / (Area)
Multiply each side by (Area) :
(10,000 Pa) x (Area) = 1,000 N
Divide each side by (10,000 Pa) :
Area = (1,000 N) / (10,000 Pa)
Area = 0.1 m²
The area is in contact with the ground if A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N is 10 m².
What is pressure?In the physical sciences, pressure is defined as the stress at a point within a confined fluid or the perpendicular force per unit area. A 42-pound box with a bottom area of 84 square inches will impose pressure on a surface equal to the force divided by the area it is applied to, or half a pound per square inch.
Given:
The pressure exerts on the box, P = 10000 Pa
The weight of the box, F = 1000 N,
Calculate the area of contact with the ground by the formula given below,
[tex]P = F/A[/tex]
Substitute the values,
10000 = 1000 / A
A = 10 m²
Therefore, The area is in contact with the ground if A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N is 10 m².
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How does an atom develop a positive charge
➷ A normal atom has the same amount of electrons and protons, making it neutral. An atom develops a positive charge when it loses an electron(s). Once it loses an electron(s), there would now be more protons that electrons.
Short answer: by losing an electron(s)
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A stone is dropped down a well and hits the water 2.50 s later. What is the depth from the edge of the well to the water? 61.3, 12.3, 30.6
Answer;
30.6 m
Explanation;
All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².
Distance traveled by an object falling down under a constant acceleration will be given the formula;
s = ut² + 1/2(gt²); but u the initial velocity is o
thus;
S =1/2(gt²)
= 0.5 × 9.81 × 2.5 ²
= 30.65
≈ 30.6 m
The red light emitted by a helium–neon laser has a wavelength of 632.8 nm. What is the frequency of the light waves?
f = 4.74 × 10 ^14 Hz
hope this helps:)
The frequency of the red light waves emitted by a helium–neon laser is 4.74 × 10^14 Hartz.
What is frequency?In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.
After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration.
Given that:
The red light emitted by a helium–neon laser has a wavelength of 632.8 nm.
We know that speed of light : c = 3×10^8 meter/second.
In wave motion:
speed = frequency × wavelength
⇒ frequency = speed/wavelength
= ( 3×10^8 meter/second)/( 632.8 nm)
= 4.74 × 10^14 Hartz.
Hence, the frequency of the light waves be 4.74 × 10^14 Hartz.
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please help on this one?
option B open system
because in open system energy and mass can escape from the system or can be added to it.
In August 2011, the Juno spacecraft was launched from Earth with the mission of orbiting Jupiter in 2016. The closest distance between Jupiter and Earth is 391 million miles. (a) If it takes 5.0 years for Juno to reach Jupiter, what is its average speed in mi/hr over this period? (b) Once Juno reaches Jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft to Earth?
(a) 8927 mi/h
In order to calculate the average speed, we need to convert the time (t=5.0 y) into hours first. In 1 year, we have 365 days, each day consisting of 24 hours, so the time taken is:
[tex]t=(5.0 y)(365 d/y)(24 h/d)=43,800 h[/tex]
The distance covered by the spacecraft is
[tex]d=391 mil. mi = 391\cdot 10^6 mi[/tex]
Therefore, the average speed is just the ratio between the distance covered and the time taken:
[tex]v=\frac{d}{t}=\frac{391\cdot 10^6 mi}{43,800 h}=8,927 mi/h[/tex]
(b) 35 minutes (2097 seconds)
The transmitted signals (which is a radio wave, which is an electromagnetic wave) travels back to the Earth at the speed of light:
[tex]c=3.0\cdot 10^8 m/s[/tex]
Since 1 miles = 1609 metres, the distance covered by the signal is
[tex]d=391\cdot 10^6 mi \cdot (1609 m/mi)=6.29\cdot 10^{11} m[/tex]
So, the time taken by the signal will be
[tex]t=\frac{d}{v}=\frac{6.29\cdot 10^{11} m}{3.0\cdot 10^8 m/s}=2097 s[/tex]
And since 1 minute = 60 sec, the time taken is
[tex]t=2097 s \cdot \frac{1}{60 s/min}\sim 35 min[/tex]
The Juno spacecraft averaged a speed of approximately 8,923 miles per hour on its trip from Earth to Jupiter. When Earth and Jupiter are closest, signals from Juno take around 35 minutes to reach Earth, with calculations based on the speed of light.
Explanation:The average speed of the Juno spacecraft can be calculated by dividing the total distance traveled by the total time taken. Given that Juno traveled 391 million miles over 5 years to reach Jupiter, we first convert the time to hours (5 years = 43,800 hours if you consider a year to be 365 days) before making this calculation. Therefore, the average speed of Juno is 391,000,000 miles / 43,800 hours = approximately 8,923 miles per hour.
For part (b) of your question, the minimum time it takes for the signals from Juno to reach Earth is determined by the speed of light, which is approximately 186,282 miles per second. Thus, by dividing the smallest distance between Jupiter and Earth (391 million miles) by the speed of light, we find it takes signals around 35 minutes to travel from Juno to Earth when the two planets are closest together.
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The principle that predicts the magnitude of the force due to currents in a magnetic field is:
Answer:
The Biot-Savart law
Explanation:
The Biot-Savart Law describes the magnetic field created by a current-carrying wire, and allows the calculation of its strength at various points.To calculate the magnetic field resulting from a current distribution involves the vector product, and is normally a calculus problem when the distance from the current to the field point is continuously changing.The relationship between the magnetic field contribution and its source current element is called the Biot-Savart law.Answer:
The Biot-Savart law
Explanation:
What kind of destructive force or forces will most likely change the way Stone Mountain looks over the next million years? A) volcanoes B) landslides C) erosion and weathering D) earthquakes and faulting
Answer:
D) Erosion and Weathering
Explanation:
Erosion forces rocks to crash together or crack apart, some rocks shatter and crumble, while others are worn away.
During erosion, exfoliation which is a type of weathering occurs in sheets along joints/ lines which runs throughout Stone Mountain. Once a sheet on the surface has been exfoliated and the sheet of rock beneath it is exposed the process begins again. This process gradually changes the way Stone Mountain looks.
Which type of electromagnetic wave travels through space the slowest?
All electromagnetic waves travel at the same speed, (as long as they're all in the same medium).
The speed at which they travel is what we call "the speed of light". But it's also the speed of infrared, the speed of microwave, the speed of radio, the speed of X-ray, etc.
The required, no electromagnetic wave travels slower than any other electromagnetic wave through space.
What is the refraction of electromagnetic waves?When an electromagnetic wave enters a medium other than a vacuum, such as air or water, its speed can be slowed due to the medium's properties.
In a vacuum, all electromagnetic waves travel at the speed of light, which is approximately 299,792,458 meters per second (or about 186,282 miles per second). As a result, no electromagnetic wave travels through space faster than any other electromagnetic wave.
However, this slowing of the wave is known as refraction. The amount of slowing depends on the wavelength of the wave, with longer wavelengths being more affected than shorter wavelengths by refraction. This means that in a medium other than a vacuum, electromagnetic waves with longer wavelengths, such as radio waves, may travel more slowly than electromagnetic waves with shorter wavelengths, such as visible light or X-rays.
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What happens to the particles of a substance as its temperature increases?
Answer :They move faster
They move faster and depending on the substance they evaporate or start to melt and release the liquid within.
Answer:
they move faster
Explanation: