A trisubstituted cyclohexane compound is given below in its chair conformation. Draw the corresponding planar (overhead) representation, using wedge-and-dash bonds to indicate the substituent positions. To be graded properly, include the hydrogen atoms on the halogen-bearing carbon atoms. Be sure that both wedge/dash bonds are drawn on the outside of the ring, or else the stereochemistry may be interpreted as square planar. (See Hint.)

Answer: 5535.1KJ/mol

Explanation:The equation for breaking of all the bonds in the benzene is written as follows:

C_6 H_6(g) --> 6C(g) +6H (g)

∆H_rxn= ∑moles of product X∆H_PRODUCT -∑moles of reactants x ∆H_REACTANT  

={6mols X ∆H_°f(C) + 6mols X ∆H_°f(H)} –{1 mol ∆H_°fC_6 H_6 (g)

={6 X 217.74+ 6X 718.4} – {82.9}KJ/mol

= 5618.04 – 82.9 KK/mol

=5535.1KJ/mol

b) The equation for the breaking of the carbon-carbon bonds in benzene is illustrated below as

C_6 H_6(g) --> 6C---H (g)

A) The standard enthalpy change for the reaction is ; 5535.1 KJ/mol

B) The chemical equation for the reaction that corresponds to breaking just the carbon-carbon bonds is  :  C₆H₆(g) --> 6C---H(g)

A) The standard enthalpy change for the reaction which represents breaking of all bonds

Reaction equation ; C₆H₆(g) --> 6C(g) +  6H (g)

∆H = ∑ ( moles of product * ∆Hpro ) - ( moles of reactant * ∆H reactant )

      = ( 6 * 217.94  +  6 *  718.4 ) –  ( 82.9)   KJ/mol

      = ( 5618.04 ) - ( 82.9 ) = 5535.1  KJ/mol

B) The chemical equation for the reaction that corresponds to breaking the carbon-carbon bonds

chemical equation  = C₆H₆(g) --> 6C---H(g)

Hence we can conclude that The answers to your questions are 5535.1 KJ/mol and C₆H₆(g) --> 6C---H(g)

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Answer:

5L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

A 2.5 liter sample of gas is STP. When the temperature is raised to 546 K and the pressure remains constant the new volume of the gas will be 5 L.

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Pressure

V = Volume

n = number of moles  

R = Ideal gas constant

T = Temperature

STP is Standard Temperature and Pressure. At STP the temperature is 273 K or 0°C and the standard pressure is 1 atm.

Now, according to question the pressure is constant, then

At constant pressure

V ∝ T

[tex]\frac{V_1}{V_2} = \frac{T_1}{T_2}[/tex]

[tex]\frac{2.5\ L}{V_2} = \frac{273\ K}{546\ K}[/tex]

[tex]V_{2} = \frac{546 \times 2.5\ L}{273}[/tex]

V₂ = 5 L

Thus, from the above conclusion we can say that A 2.5 liter sample of gas is STP. When the temperature is raised to 546 K and the pressure remains constant the new volume of the gas will be 5 L.

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Answer:

27.7 KJ

Explanation:

Q= mC dT

m= 1900 g+0.580 g= 1900.58 g

Q= (1900.58 g * 3.21 KJ/ gK* 4.542 K)

Q=27710 J= 27.7 KJ

Answer:

C) 27.7 kJ

Explanation:

Answer:

Magnesium chloride and water  

Explanation:

Mg(OH)₂ + 2HCl ⟶                MgCl₂                +   2H₂O

                                    magnesium chloride        water

Answer:

See explaination

Explanation:

methyl-3-nitrobenzoate = 3-NO2-C6H4-COOCH3

Singlet at 4 ppm = CH3 from ester (COOCH3)

Triplet at 7.6 ppm = Aromatic, H5 proton

Doublet at 8.2 ppm - Aromatic, H4 and H6 protons

Singlet at 8.8 ppm - Aromatic, H2 proton

See attached file for diagrammatic representation and further solution.

Methylbenzoate has 8 distinct carbon environments, therefore it would show 8 distinct 13C NMR signals. Methyl-3-nitrobenzoate, due to its symmetrical structure, has 7 distinct carbon environments, therefore it would show 7 distinct 13C NMR signals.

The product, methyl-3-nitrobenzoate, and the reactant, methylbenzoate, are both organic compounds, and their 13C NMR signals can be determined by the number of carbon environments they have.

Methylbenzoate has 8 distinct carbon environments: benzoate carbon framework (7) + methyl group (1). Hence, in the 13C NMR spectroscopy, methylbenzoate would show 8 distinct signals.

Methyl-3-nitrobenzoate on the other hand, due to the introduction of the nitro group, creates symmetry which changes the carbon environments, thus, it has 7 distinct carbon environments: nitrobenzoate carbon framework (6) + methyl group (1). So, methyl-3-nitrobenzoate would show 7 distinct signals in its 13C NMR spectroscopy.

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Answer:

1.  Saturated hydrocarbons may be cyclic or acyclic molecules.

2.  An unsaturated hydrocarbon molecule contains at least one double bond.

Explanation:

Hello,

In this case, hydrocarbons are defined as the simplest organic compounds containing both carbon and hydrogen only, for that reason we can immediately discard the third statement as ethylenediamine is classified as an amine (organic chain containing NH groups).

Next, as saturated hydrocarbons only show single carbon-to-carbon bonds and carbon-to-hydrogen bonds, they may be cyclic (ring-like-shaped) or acyclic (not forming rings), so first statement is true

Finally, since we can find saturated hydrocarbons which have single carbon-to-carbon and carbon-to-hydrogen bonds only and unsaturated hydrocarbons which could have double or triple bonds between carbons and carbon-to-hydrogen bonds, the presence of at least one double bond makes the hydrocarbon unsaturated.

Therefore, first and second statements are correct.

Best regards.

Final answer:

Statements 1 and 2 are correct regarding saturated hydrocarbons being cyclic or acyclic and unsaturated hydrocarbons containing at least one double bond. Statement 3 is incorrect because ethylenediamine is not a hydrocarbon.

Explanation:

To address which statements concerning hydrocarbons are correct:

Saturated hydrocarbons may indeed be cyclic or acyclic molecules. When cyclic, they have the general formula CnH₂n, such as cycloalkanes, which are saturated compounds. Acyclic saturated hydrocarbons, also known as alkanes, have single bonds only and follow the general formula CHn₂+2.

An unsaturated hydrocarbon molecule contains at least one double or triple bond. Molecules with one or more double bonds are alkenes, with the simplest being ethene (or ethylene), C₂H₄.

Ethylenediamine, H₂NCH₂CH₂NH₂, is not an example of a saturated hydrocarbon. It contains amine groups (NH₂) and therefore is not a hydrocarbon.

Hence, statements 1 and 2 are correct, while statement 3 is incorrect.

Final answer:

In the galvanic cell, the reduction of Br₂ to 2Br⁻ occurs at the cathode, while the oxidation of 2NO to N₂O₄ occurs at the anode. The cathode is the silver electrode and the anode is the copper electrode. The silver electrode is the positive electrode and the copper electrode is the negative electrode.

Explanation:

In the galvanic cell powered by the redox reaction between Br₂ and 2NO, the half-reaction that takes place at the cathode is the reduction of Br₂ to 2Br⁻. The half-reaction that takes place at the anode is the oxidation of 2NO to N₂O₄.

For the electrode assignment, the cathode is the electrode where reduction occurs, so it is the silver electrode. The anode is the electrode where oxidation occurs, so it is the copper electrode.

The positive electrode in this galvanic cell is the cathode, which is the silver electrode, and the negative electrode is the anode, which is the copper electrode.

Answer: There are 6.725 mols

Explanation:

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Answer:

1. Hot water

2. A pile of wood shavings

Explanation:

Sugar can dissolve more quickly in hot water than in cold water because there is more energy in hot water molecules. Because they are moving faster, they have more energy to break the bonds that hold sugar together. There is also more energy available to break the hydrogen bonds that hold water together.

Wood shavings have a greater contact surface than the solid hunk of wood, which is why they have a higher calorific value and then they will catch fire more easily.

Answer:

pH is 8.52

Explanation:

According to the working in the photo

Answer:

I have the same question

Explanation:

Answer:

The mass of water = 219.1 grams

Explanation:

Step 1: Data given

Mass of aluminium = 32.5 grams

specific heat capacity aluminium = 0.921 J/g°C

Temperature = 82.4 °C

Temperature of water = 22.3 °C

The final temperature = 24.2 °C

Step 2: Calculate the mass of water

Heat lost = heat gained

Qlost = -Qgained

Qaluminium = -Qwater

Q = m*c*ΔT

m(aluminium)*c(aluminium)*ΔT(aluminium) = -m(water)*c(water)*ΔT(water)

⇒with m(aluminium) = the mass of aluminium = 32.5 grams

⇒with c(aluminium) = the specific heat of aluminium = 0.921 J/g°C

⇒with ΔT(aluminium) = the change of temperature of aluminium = 24.2 °C - 82.4 °C =  -58.2 °C

⇒with m(water) = the mass of water = TO BE DETERMINED

⇒with c(water) = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = 24.2 °C - 22.3 °C = 1.9 °C

32.5 * 0.921 * -58.2 = -m * 4.184 * 1.9

-1742.1 = -7.95m

m = 219.1 grams

The mass of water = 219.1 grams

To calculate the mass of water in the calorimeter, you equalize the heat gained by the water to the heat lost by the heated aluminum (since energy is conserved). You then rearrange the resulting equation to solve for water mass, substituting the known values into the equation.

This question is related to the concept of heat transfer in Physics. Here, we are dealing with a piece of aluminium that was heated and then dropped into a calorimeter with water. We want to find the mass of the water contained in the calorimeter.

The heat lost by aluminum will be the heat gained by the water, so we should equalize the heat gained and lost: (mass of Aluminum)*aluminum heat capacity*(Initial temperature-Final temperature) = (water mass)*water heat capacity*(final temperature-initial temperature).

To find the mass of the water, rearrange the equation to solve for it: Mass_water = (mass of Aluminum * aluminum heat capacity * (Initial temperature - Final temperature)) / (water heat capacity * (final temperature - initial temperature)). Plugging in the known values and working through the math should yield the mass of the water in the calorimeter.

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Answer:  The mass of sodium hydroxide is 10 grams.

Explanation:  the atomic weight: 39.997 g/mol

Answer:

The pressure equilibrium constant  is  [tex]K_p = 323[/tex]

Explanation:

From the question we are told that

    The volume of the flask is  [tex]V = 50 mL = 50 *10^{-3} L[/tex]

    The pressure of sulfur dioxide is  [tex]P_s = 3.7 \ atm[/tex]  

     The pressure of  oxygen gas [tex]P_o = 2.3 \ atm[/tex]

     The pressure of sulfur trioxide at equilibrium is [tex]P_t = 2.2 \ atm[/tex]

The chemical equation for this reaction is

          [tex]2 SO_2_{(g)} + O_2_{(g)}[/tex]    ⇄   [tex]2SO_3_{(g)}[/tex]

The partial pressure of  oxygen at  equilibrium is mathematically evaluated as

         [tex]P_p__{O}} = P_o - P_t[/tex]

Substituting values

         [tex]P_p__{O}} = 2.3 -2.2[/tex]

         [tex]P_p__{O}} = 0.1 \ atm[/tex]

The partial pressure of  sulfur dioxide  at  equilibrium is mathematically evaluated as

         [tex]P_p__{s}} = P_s - P_t[/tex]

Substituting values

         [tex]P_p__{S}} = 3.7 -2.2[/tex]

         [tex]P_p__{O}} = 1.5 \ atm[/tex]

From the chemical equation  pressure constant is mathematically represented as

           [tex]K_p = \frac{[P_t]^2}{[P_p__{o}} ]^2 [P_p__{s}}]}[/tex]

Substituting values

          [tex]K_p = \frac{[2.2]^2}{[ 0.1 ]^2 [{ 1.5}]}[/tex]

          [tex]K_p = 323[/tex]

Answer:

A tetrahedral bent molecular geometry involves four electron pairs including two lone pairs and two bonding groups while a trigonal planar bent molecular geometry involves three electron pairs two bonding groups and one lone pair.

Explanation:

According to valence shell electron pair repulsion theory, the number of electron pairs on the central atom of a molecule influences its shape. It follows that, the shape of a molecule is a consequence of arrangement of valence shell electron pairs. Electron pairs must be positioned as far apart in space as possible.

Electron pairs may be bonding pairs or lone pairs. The repulsion between two lone pairs is greater than the repulsion between a lone pair and a bond pair which in turn is greater than the repulsion between two bond pairs. Hence the presence of lone pairs causes much distortion of the expected molecular geometry of the molecule as predicted by VSEPR theory. This distortion usually leads to the assumption of a bent geometry, depending on the expected geometry of the molecule based on VSEPR theory.

A tetrahedral bent molecular geometry involves four electron pairs including two lone pairs and two bonding groups while a trigonal planar bent molecular geometry involves three electron pairs; two bonding groups and one lone pair. For a bent tetrahedral geometry, the bond angle is much less than 109° while for a bent trigonal planar geometry, the bond angle is much less than 120°.

The difference between tetrahedral bent and trigonal planar bent molecular geometries lies in the number of electron pairs around the central atom and the resulting shape.

In a tetrahedral bent geometry, the central atom is surrounded by four electron pairs, which are arranged around the atom in a tetrahedral shape. This arrangement leads to bond angles of approximately 109.5 degrees.

An example of a molecule with a tetrahedral bent shape is water (H2O), where the central oxygen atom has two bonded pairs and two lone pairs of electrons. The lone pairs exert greater repulsion than the bonded pairs, causing the bond angles to be slightly less than the ideal tetrahedral angle, resulting in a bent shape.

On the other hand, in a trigonal planar bent geometry, the central atom is surrounded by three electron pairs, which are arranged in a plane around the atom in a trigonal planar shape.

This arrangement leads to bond angles of approximately 120 degrees. However, when one or more of these electron pairs are lone pairs, the geometry can become bent due to the lone pair-bond pair repulsion being greater than bond pair-bond pair repulsion.

An example of a molecule with a trigonal planar bent shape is sulfur dioxide (SO2), where the central sulfur atom has two bonded pairs and one lone pair of electrons. The presence of the lone pair causes the molecule to have a bent shape with bond angles less than 120 degrees.

 In summary, the key differences are:

- Tetrahedral bent involves four electron pairs with a tetrahedral arrangement, while trigonal planar bent involves three electron pairs with a trigonal planar arrangement.

- Tetrahedral bent typically results from two bonded pairs and two lone pairs, leading to a bond angle of slightly less than 109.5 degrees.

- Trigonal planar bent typically results from two bonded pairs and one lone pair, leading to a bond angle of less than 120 degrees.

Therefore, the main difference is the number of electron pairs and the resulting molecular shape and bond angles.

Option 4. All living organisms are composed of cells. The component of cell theory that is supported by the diagram is option 4.

The cell theory, which is a fundamental concept in biology, states the following:

All living organisms are composed of one or more cells: This means that cells are the basic structural and functional units of all living things.

The cell is the basic unit of life: Cells are the smallest units that can carry out all the processes necessary for life, including metabolism and reproduction.

All cells arise from pre-existing cells: New cells are produced by the division of existing cells, and no new cells are spontaneously generated.

From the diagram, the first image is a simple unicellular organism and the others are multicellular organism tissues. These shows that all living things are made up of cell/cells depending on the complexity of the organism.

Complete question

Answer:

[tex]n=0.286mol[/tex]

Explanation:

Hello,

In this case, we consider oxygen as an ideal gas, for that reason, we use yhe ideal gas equation to compute the moles based on:

[tex]PV=nRT\\\\n=\frac{PV}{RT}[/tex]

Hence, at 3.50 atm and 25 °C for a volume of 2.00 L we compute the moles considering absolute temperature in Kelvins:

[tex]n=\frac{3.50atm*2.00L}{0.082\frac{atm*L}{mol*K}(25+273)K} \\\\n=0.286mol[/tex]

Best regards.

Final answer:

The volume of a 40.0-L sample of fluorine gas heated from 363 K to 459 K can be found using Charles's Law. After setting up the equation from Charles's Law and solving for the new volume (V2), we find that the volume at the higher temperature is 50.5 L.

Explanation:

To determine the new volume of fluorine gas when heated from 363 K to 459 K, we can use Charles's Law, which states that for a given mass of an ideal gas at constant pressure, the volume is directly proportional to its absolute temperature. Specifically, the formula is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

In this case, the initial volume (V1) is 40.0 L and the initial temperature (T1) is 363 K. The final temperature (T2) is 459 K. Plugging these values into the formula, we have:

40.0 L / 363 K = V2 / 459 K

Multiplying both sides by 459 K to solve for V2 gives us:

V2 = (40.0 L x 459 K) / 363 K

Upon calculation, V2 = 50.5 L. Therefore, the new volume occupied by the sample at 459 K is 50.5 liters.

Answer: Schedule (2) two drug

Explanation: Although it’s virtually difficult or impossible to design a set of defining drug classification standards because even experts have struggled on which drugs should be and not be on a particular schedule but drugs are generally categorised based on their abuse rate (misuse and physical dependency) and their medical use. Drugs with no medical use and higher abuse rate which has physical and mental implications are placed under schedule one, drugs with medical use but also higher abuse rate with physical and mental implications are placed under schedule two, drugs with lower or moderate abuse rate are placed under schedule three, drugs with low potential for dependency are place under schedule four and drugs which are mostly use for antidiarrheal, analgesic and antitussive are placed under schedule five.

Chang's drug has medical use because it was prescribed by his doctor, it also has a high abuse rate because he started overdosing on them which led to a severe physical and mental implications.

Therefore Cheng's drugs will mostly likely be categorised as a schedule (2) two drug.

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to the question above.

Answer:

The correct equation to calculate the heat of this reaction is:

ΔH = m*s*∆T

Explanation:

During any chemical reaction, heat can either be absorbed from the environment or released to the environment through the reaction. The heat exchange between a chemical reaction and its environment is known as the reaction enthalpy, or H. However, H cannot be measured directly; the change in temperature of a reaction over time is used to find the enthalpy change over time (denoted as ΔH).

In general ΔH = m*s*∆T, where m is the mass of the reactants, s is the specific heat of the product, and ΔT is the change in the reaction temperature.

Answer:

See explaination

Explanation:

For a reversible reaction, the equilibrium constant for a backward reaction is reciprocal.

If the coefficients in a balanced equation are multiplied by a factor, n, the equilibrium expression is raised to the nth power.

K' = (K)^n

In the second reaction the value kf n is 2. The first reaction is multiplied by 2.

See attachment for further solution

Answer: -9  8  48  -6

Explanation: trust me

Answer:

Oxidation number of Fe(iron) on right side of reaction arrow = (+2)

Explanation:

NADH+H+ + FMN   FMNH2 + NAD+

FMNH2 - Reduced FMN (1,5-Dihydroriboflavin 5'-(dihydrogen phosphate)

The reactant that is reduced is Flavin mononucleotide(FMN)

QH2 + 2cyt c(fe³+)  ----------------------->  Q + 2Cytc ( fe²+) + 2H+

Oxidation number of Fe(iron) on right side of reaction arrow = (+2)

The equation of the transfer of two electrons from NADH to FMN is given below:

NADH + H⁺ + FMN ⟶ NAD⁺ + FMNH₂

The oxidation number of iron on the right side of the reaction arrow is +2 (Fe²⁺)

In the electron transport chain, electrons are passed from electron carriers such as NADH through various carriers and eventually to oxygen. Water and energy in the form of ATP is produced.

The electron carriers are organized into complexes; Complex I, II, III, and IV

In complex I, also known as NADH Dehydrogenase, electrons are passed from NADH to ubiquinone through an FMN-containing flavoprotein and several iron-sulfur centers.

The equation below shows how two electrons are passed from NADH to FMN:

NADH + H⁺ + FMN ⟶ NAD⁺ + FMNH₂

In complex III, electrons are transferred from coenzyme Q to cytochrome c, a single electron-carrier which contains iron. The equation for the electron transfer is given below:

QH₂ + 2 cyt c ( Fe³⁺) ⟶ Q + 2 cyt c ( Fe²⁺ ) + 2H⁺

In the reaction above, the two electron-carrier ubiquinone transfers its two electrons to two molecules of the one electron-carrier cytochrome c containing iron in the oxidized iron (iii) state, Fe³⁺. The electrons accepted reduces the Fe³⁺ in cytochrome c to Fe²⁺.

Therefore, the oxidation number of iron on the right side of the reaction arrow (reduced cytochrome c) is +2.

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Answer:

It is the sum of internal energies of two or more substances

Explanation:

Answer:

C. It is the portion of internal energy that can be transferred from one substance to another.

Explanation:

the other one was incorrect so this one was what it was

Answer: c) This process is an example of sublimation.

Explanation:

When liquid is further heated, the molecules gain more kinetic energy and molecules move farther and convert to gaseous state and the process is called vaporization.

Sublimation is a process of converting a substance from solid state to gaseous state without the formation of liquid at constant temperature.

Deposition is a process of converting a substance from gaseous state to solid state without the formation of liquid at constant temperature.

In liquid the particles are loosely packed as the inter molecular forces of attraction are not that strong. As they are cooled, the kinetic energy of the molecules decreases and thus the molecules start getting closer and convert to solid state. The process is called freezing.

Answer:

The true statements include;

- The sample is initially a gas.

- The final state of the substance is a solid.

- One or more phase changes will occur.

The untrue/false statements include;

- The liquid initially present will vaporize.

- The final state of the substance is a liquid.

Explanation:

A couple pieces of informatton on Fluorine is imitially provided.

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K

So, a question is now attached about a sample of Fluorine. A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K.

We are then told to examine a group of options to find the ones that are correct/apply.

Taking the options one at a time

- The sample is initially a gas.

The initial state of the Fluorine sample has its temperature at 90.3 K, which is above the gas' boiling point. Hence, the sample can be concluded to initially be a gas.

- The liquid initially present will vaporize.

The sample doesn't initially contain liquid. And even of it did, the temperature is cooled, not heated , Hence, this statement is wrong.

- The final state of the substance is a solid.

The sample of Fluorine moves from a temperature higher than boiling point (85.0 K), with the sample in gaseous form, to one that is at a lower temperature (49.3 K) than the gas' normal melting point (53.5 K).

At temperatures lower than melting point, a substance exists in the solid form. Hence, this statement is true. The final state of the substance is solid.

- One or more phase changes will occur.

In moving from 90.3 K to 49.3 K for the sample and passing through the substance's boiling and melting points (85.0 K and 53.5 K respectively) along the way, it is logical to conclude that there would be one or more phase changes will occur. This statement is true.

- The final state of the substance is a liquid.

This is false as we already established that the final state of the substance is a solid. Hence, this statement is false.

Hope this Helps!!!

Final answer:

At 1.00 atm, fluorine starts as a gas at 90.3 K, then condenses to a liquid as it cools, and finally becomes a solid at 49.3 K, indicating that both condensation and freezing phase changes occur.

Explanation:

The substance fluorine has different states at various temperatures and pressures. To determine the state changes of fluorine when cooling from a temperature of 90.3 K to 49.3 K at constant pressure of 1.00 atm, we refer to the given melting and boiling points of fluorine. According to the information:

Normal melting point: 53.5 K

Normal boiling point: 85.0 K

At the starting temperature of 90.3 K and 1.00 atm, fluorine is above the boiling point, so the sample is initially a gas. As the temperature cools to below the boiling point but still above the melting point, any liquid that may be present will not vaporize; instead, the gas will condense to form a liquid. Since the final temperature of 49.3 K is below the melting point of 53.5 K, the final state of the substance is a solid. Throughout this process, one or more phase changes will occur; specifically, the gas will condense to a liquid and then freeze into a solid. Therefore, the final state of the substance will not remain a liquid; this statement is false.

Final answer:

To calculate the length of each edge of the cube that would store your yearly CO2 emissions, convert the emissions from kg to metric tons and use the density of carbon dioxide at STP to find the volume. The length of each edge would be approximately 17.9 meters.

Explanation:

To calculate the length of each edge of the cube that would store your yearly CO2 emissions, we first need to convert the emissions from kg to metric tons. Since the average CO2 emissions per person per year is 10,000 kg, this is equal to 10 metric tons (1 metric ton = 1000 kg).

Next, we need to find the volume of the cube. The formula for the volume of a cube is V = s^3, where s represents the length of each edge.

Let's use the given data to solve for s:

CO2 emissions per person per year: 10 metric tons

Density of CO2 at STP: 1.98 kg/m³ (source: https://pubchem.ncbi.nlm.nih.gov/compound/carbon_dioxide)

Using the density, we can convert the metric tons of CO2 to the corresponding volume in cubic meters:

10 metric tons * 1000 kg/metric ton = 10,000 kg

10,000 kg / 1.98 kg/m³ ≈ 5,051.51 m³

Now, let's solve for s:

s^3 = 5,051.51 m³

s ≈ 17.9 meters (rounded to one decimal place)

Therefore, each edge of the cube that would store your yearly CO2 emissions at STP would be approximately 17.9 meters long.

Answer:Then a few days later the activity of the sample will be due to have more of Nuclides Y than X

Explanation:

This is because  half life of nuclide X is about a day which is less than Y having half life of about a week, After a few days, we would observe that  X would have  disintegrated more while Y will still be predominant since it disintegrate slower than X. The time it takes for X to disintegrate will always be faster than Y.

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 ×  10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺  (because 1 Cu²⁺  needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺  = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 ×  10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 ×  10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 ×  10⁻¹⁹/0.20357

[OH⁻] = 1.13 ×  10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M