Answer:
Her centripetal acceleration during the turn at each end of the track is [tex]0.432\, \frac{m}{s^{2}}[/tex]
Step-by-step explanation:
Total distance covered in one round , D= 400 m
Time taken to cover one round , T = 1 min 40 s = 100 sec
Speed of runner , [tex]V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}[/tex]
Now centripetal acceleration is given by
[tex]a_c=\frac{V^{2}}{R}[/tex]
where [tex]V= 4.0\frac{m}{s}[/tex]
[tex]Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m[/tex]
[tex]\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}[/tex]
Thus her centripetal acceleration during the turn at each end of the track is [tex]0.432\, \frac{m}{s^{2}}[/tex]
The centripetal acceleration of runner at each end of track is [tex]\boxed{0.432{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] .
Explanation:
It is given that the diameter of oval track that consists of two half circles at each end is [tex]74{\text{ m}}[/tex] .
The distance runner runs once around the track is [tex]400{\text{ m}}[/tex] . The runner covers one round of track in [tex]1{\text{ m}}[/tex] and [tex]40{\text{ s}}[/tex] .
Our aim is obtain the value of centripetal acceleration for runner at each track.
The expression for centripetal acceleration is shown below.
[tex]{a_c}=\frac{{{v^2}}}{R}[/tex] …… (1)
Here, [tex]v[/tex] is the speed of the runner and [tex]R[/tex] is the radius of track.
The speed of the runner is the ratio of distance she takes to cover the track to the time taken by her.
The time in seconds is calculated as,
[tex]\begin{aligned}t&=60{\text{ s}}+40{\text{ s}}\\&=100{\text{ s}}\\\end{aligned}[/tex]
The distance covered is [tex]400{\text{ m}}[/tex] , so the speed calculated is shown below.
[tex]\begin{aligned}{\text{speed}}&=\frac{{{\text{distance}}}}{{{\text{time}}}}\\&=\frac{{400{\text{ m}}}}{{100{\text{ s}}}}\\&=4{\text{ }}{{\text{m}}\mathord{\left/{\vphantom {{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]
The radius of track calculated is shown below.
[tex]\begin{aligned}R&=\frac{d}{2}\\&=\frac{{74{\text{ m}}}}{2}\\&=37{\text{ m}}\\\end{aligned}[/tex]
Substitute [tex]4[/tex] for [tex]v[/tex] and [tex]37[/tex] for [tex]R[/tex] in equation (1) to obtain the centripetal acceleration [tex]{a_c}[/tex] .
[tex]\begin{aligned}a_{c}&=\frac{(4\text{ m/s})^{2}}{37\text{ m}}\\&=\frac{16}{37}\text{ m/s}^{2}\\&=0.432\text{ m/s}^{2}\end{aligned}[/tex]
Therefore, the centripetal acceleration [tex]{a_c}[/tex] is [tex]0.432{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}[/tex] .
Thus, the centripetal acceleration of runner at each end of track is [tex]\boxed{0.432{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] .
Learn More:
1. Centripetal Force https://brainly.com/question/6372960
2. Velocity and Momentum https://brainly.com/question/11896510
3. Centripetal force on orbit https://brainly.com/question/7420923
Answer Details:
Grade: High School
Subject: Physics
Chapter: Circular Motion
Keywords:
Track, running, diameter, circle, runner, distance, moves, constant, speed, centripetal, acceleration, force, motion, uniform, radius, velocity and oval.
Which does not describe the same situation?
Answer:
4. Option 3rd.
Step-by-step explanation:
In this question, three options are given.
We need to describe the same situation.
First option: y = 3 + 6x
this equation represent the equation of a line. In that line all the points are related with each other with same relation.
So, this equation describe the same situation.
Second equation:
y is two more than six times x.
We write this situation in equation form.
y = 6x + 2
this is also describe the same situation.
Third option:
this table shows the x-y relation table.
Here no two points are describe the same situation.
So, option 3rd doesn't describe same situation.
Question 5:
Please share the options
Answer:
Step-by-step explanation:
It is A
Is 1.34 a non-terminating decimal
what is the sum of the measures of interior angles of a 15-sides polygon
Answer:
2340
Step-by-step explanation:
A P E X
If EF=2x-5, FG=3x-6, and EG=19 find the values of x, EF, and FG. The drawing is not to scale.
a. x = 6, EF = 17, FG = 24
b. x = 1, EF = 7, FG = 12
c. x = 1, EF = -3, FG = -3
d. x = 6, EF = 7, FG = 12
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When exchanging from your currency to another country’s currency using a foreign rate exchange table, you should ____.
If m<1 is twice the measure of its complement (<2), then determine the measure of each angle.
Can someone help me with this question?
A shop makes $37.50 for selling 15 calendars. If the shop wants to make $2450, how many calendars does it need to sell?
The shop needs to sell 980 calendars to make $2450.
To find out how many calendars the shop needs to sell to make $2450, we first determine the price per calendar by dividing the total amount made from selling a batch of calendars by the number of calendars in that batch. The shop makes $37.50 from selling 15 calendars, so each calendar is sold for $37.50 / 15 = $2.50. To reach the goal of $2450, we need to calculate the number of calendars by dividing the target amount by the price per calendar.
$2450 / $2.50 = 980 calendars
A restaurant bill before tax is 65.50.if the sales tax is 8% and the a 18% tip is added what is the total cost
bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye. the table gives the probabilities of each outcome. what is the probability that bill will get the next arrow in the inner or outer ring?express your answer as a decimal
add the 2 probabilities together:
0.297 + 0.423 = 0.72
Answer is C
To determine the probability that Bill will hit the inner or outer ring, you would subtract the probability of hitting the bull's-eye from 1, assuming there are no other sections on the target. If the probability of hitting the bull's-eye is 0.70, the combined probability for the inner or outer ring would be 0.30.
Explanation:The question asks about the probability that Bill will hit either the inner or outer ring on an archery target, knowing that he hits the bull's-eye with certain probabilities. To find this probability, we need additional information that specifies the probabilities of hitting the inner and outer rings. Assuming we know the probabilities of all possible outcomes (inner ring, outer ring, and bull's-eye), we would add together the probabilities of hitting the inner and outer rings to get the total probability of hitting one of those two sections.
If hitting the bull's-eye has a probability of 0.70 (70%), and since the sum of all possible probabilities must equal 1 (100%), the combined probability of hitting either the inner or outer ring would be 1 - 0.70 = 0.30 or 30%. This assumes there are no other sections to hit on the target. The probability in decimal form would be 0.30.
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1. Choose the equation of the vertical line passing through the point (−2, 3).
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x = 3
y = −2
x = −2
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{8, 10, 4, 6, −9}
{−4, 1, 5, 8}
{−4, 8, 5, 1, 5}
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Consider a machine that exchange quarters for dollar bills. Inserting one dollar bill returns four quarters and you may insert up to five one dollar bills at a time. Is 7 a possible input for the relation this change machine represents ?
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the value of a new automobile depreciates 15% during the first year, and 16% during the second year. What is its depreciated value at the end of the second year if its original cost was $15,000
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Answer: $ 33264
Step-by-step explanation:
Since, the original price of the car = $ 29,700
Marked up price = 12 % greater than the original price of the car
= Original price of the car + 12% of the original price of the car
= 29700 + 12% of 29700
= 29700 + 0.12 × 29700
= 29700 + 3564
= 33264
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Answer:
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The polygon ABCD showed in the image attached is first reflected across the y = x line, from the second quadrant to the fourth quadrant. This reflection will result like the second image.
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Let us say that the square have edge = sqrt(pi), then its area is pi since A = edge^2, and therefore the diagonal is pi*sqrt(2).
Meanwhile the circle of radius 1 has area pi since area of circle is A = pi *radius^2.
Therefore we get that the diagonal of the square divided by the radius is:
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C.) A compass is used to copy an angle.
D.) There are no differences.
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Answer:
Step-by-step explanation:
2) let the two numbers be x and y
x-y =15
(taking x to be big)
x = 3 (y)+1
i.e. x-3y =1
Subtracting we get
2y =14 or y =7
x =15+7 =22
Larger number is 22 and smaller number is 7
-----------------------------------
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Let Alysha be x years old then Bryce would be x+2
Sum of their ages
=x+x+2 =28
2x+2 =28
2x=26
x=13
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