A writer charges $5 per word plus a start up fee of $50 per article.

Answer:

AC = BD = 1 unit

Step-by-step explanation:

 Given : length of diagonal of rectangle ABCD  [tex]AC=\frac{3y}{5}[/tex] and [tex]BD=3y-4[/tex]

We have to find the length of diagonal.

We know In rectangle diagonal are of equal lengths.

Therefore, for rectangle ABCD diagonals AC= BD

Substitute the values, we get,

[tex]\frac{3y}{5}=3y-4[/tex]

Cross multiply , we get

[tex]3y=5(3y-4)[/tex]

On simplyfy , we get

[tex]3y=15y-20[/tex]

Solve for y , we get

[tex]15y-3y=20[/tex]

[tex]12y=20[/tex]

Divide both side by 12, we get,

[tex]y=\frac{20}{12}=\frac{10}{6}[/tex]

Thus, put the values of y in AC and BD to find the length of diagonals , we get,

[tex]AC=\frac{3y}{5}=\frac{3}{5}\times\frac{10}{6}=1[/tex]

Similarly for BC, we get,

[tex]BD=3y-4=3(\frac{10}{6})-4=5-4=1[/tex]

Thus, AC = BD = 1 unit

To show that the point (7/25, 24/25) is on the unit circle, we need to demonstrate that its distance from the origin is equal to 1.

To show that the point (7/25, 24/25) is on the unit circle, we need to demonstrate that its distance from the origin is equal to 1.

The distance between two points, (x1, y1) and (x2, y2), is given by the formula: √((x2-x1)² + (y2-y1)²).

In this case, the distance between the point (7/25, 24/25) and the origin (0, 0) can be calculated as: √((7/25-0)² + (24/25-0)²) = √((49/625) + (576/625)) = √(625/625) = 1.

Since the distance between the given point and the origin is indeed equal to 1, we can conclude that the point is on the unit circle.

Quadratic functions are functions that has a degree of 2. The factored form of the function is (2x-10)(x+8)

Quadratic functions are functions that has a degree of 2. Given the function below;

2x^2 + 6x - 80

Factorize

2x^2+16x - 10x - 80

Group

(2x^2+16x)-(10x+80)

Factor out the GCF

2x(x + 8)-10(x+8)

(2x-10)(x+8)

Hence the factored form of the function is (2x-10)(x+8)

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Answer:

Step-by-step explanation:

The given sequence is:

1,6,11,16,...

Since, the sequence is Arithmetic progression, therefore

The general term for the sequence is:

[tex]A_{n}=a+(n-1)d[/tex]

where a is the first term of the sequence and d is common difference.

Substituting the given values, we get

[tex]A_{n}=1+(n-1)5[/tex]

[tex]A_{n}=1+5n-5[/tex]

[tex]A_{n}=5n-4[/tex]

which is the required general term.

Thus, option B is correct.

Answer: a

Step-by-step explanation: that person coulda said that

To find the missing number in the proportion 7 / 35 = ? / 28, we can use the concept of cross-multiplication. The missing number is 5.6.

To find the missing number in the proportion 7 / 35 = ? / 28, we can use the concept of cross-multiplication. Cross-multiplication involves multiplying the numerator of one fraction by the denominator of the other fraction, and then setting the two products equal to each other. In this case, we have 7 * 28 = ? * 35. Solving for the missing number, we get:

So, the missing number is 5.6.

The function h(x) has the greatest y-intercept of 8, as it crosses the y-axis at the highest point.

The function that has the greatest y-intercept is the one that crosses the y-axis at the highest value. The y-intercept is the point where the graph of a function intersects the y-axis, which is when x = 0. So, to find the function with the greatest y-intercept, we need to evaluate the y-value when x = 0 for each function.

Let's consider the functions f(x), g(x), and h(x). If f(x) has an equation of y = 3x + 5, g(x) has an equation of y = x - 2, and h(x) has an equation of y = -2x + 8, we can plug in x = 0 and see which function gives us the greatest y-value.

For f(x), when x = 0, y = 3(0) + 5 = 5. For g(x), when x = 0, y = 0 - 2 = -2. And for h(x), when x = 0, y = -2(0) + 8 = 8. Thus, h(x) has the greatest y-intercept because it crosses the y-axis at the highest point, which is 8.

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Answer:

A number and three is at most 3.

Step-by-step explanation:

Answer:

1 gal

Step-by-step explanation:

Answer:

B) $4

Step-by-step explanation:

I had the same thing. Please mark as Brainiest Answer.

Answer:

Both posters ARE accurate representations of the painting

Step-by-step explanation:

Gradpoint

The triangle with side lengths of 14 cm, 48 cm, and 50 cm is a right triangle.

The lengths of the sides of the triangle are 14 cm, 48 cm, and 50 cm. To classify the triangle, we need to determine if it is acute, obtuse, or right.

Using the Pythagorean theorem, we can check if it satisfies the condition for a right triangle. If the square of the length of the longest side (50 cm) is equal to the sum of the squares of the other two sides (14 cm and 48 cm), then it is a right triangle.

In this case, (50)^2 = (14)^2 + (48)^2, which is true. Therefore, the triangle is a right triangle.

Final answer:

A triangle with side lengths of 14 cm, 48 cm, and 50 cm is classified as an acute triangle.

Explanation:

A triangle with side lengths of 14 cm, 48 cm, and 50 cm can be classified as an acute triangle.

To determine this, we need to check if the square of the longest side (50 cm) is less than the sum of the squares of the other two sides (14 cm and 48 cm).

502 < 142 + 482

2500 < 196 + 2304

2500 < 2500

This inequality is not true, so the triangle is not obtuse or right. Thus, it is classified as an acute triangle.

Answer:

41.57 unit²

Step-by-step explanation:

We know,

Area of a regular hexagon = [tex]3\times (sidelength)\times (apothem)[/tex].

The length of the apothem = [tex]2\sqrt{3}[/tex] units.

Since, we know, 'a regular hexagon splits into 6 identical equilateral triangles'.

As, the apothem of the regular hexagon = height of the equilateral triangle

So, height of the equilateral triangle = [tex]2\sqrt{3}[/tex] units.

As, in the equilateral triangle, 'One of the side length is the S, other will be [tex]\frac{S}{2}[/tex] and height is [tex]2\sqrt{3}[/tex] units'.

So, using Pythagoras Theorem, we have,

[tex]hypotenuse^{2}=perpendicular^{2}+base^{2}[/tex]

i.e. [tex]S^{2}=(\frac{S}{2})^{2}+(2\sqrt{3})^{2}[/tex]

i.e. [tex]S^{2}=\frac{S^2}{4}+12[/tex]

i.e. [tex]S^{2}-\frac{S^2}{4}=12[/tex]

i.e. [tex]\frac{3S^2}{4}=12[/tex]

i.e. [tex3S^2=48[/tex]

i.e. [texS^2=16[/tex]

i.e. S= 4 units

That is, the side length of the hexagon = 4 units.

Thus, the area of the hexagon is given by,

Area of a regular hexagon = [tex]3\times (4)\times (2sqrt{3})[/tex]

i.e. Area of a regular hexagon = [tex]12\times (2sqrt{3})[/tex]

i.e. Area of a regular hexagon = [tex]24sqrt{3}[/tex]

i.e. Area of a regular hexagon = 41.57 unit²

Hence, the area of the regular hexagon is 41.57 unit².

To find the area of the region defined by the function y = 6 sin(x) + sin(6x) from x = 0 to x = pi, we need to calculate the definite integral of the function over this interval. Using a graphing utility, we can plot the function and verify the result.

To find the area of the region defined by the function y = 6 sin(x) + sin(6x) from x = 0 to x = pi, we need to calculate the definite integral of the function over this interval.

Using a graphing utility, we can plot the function and verify the result. The integral will give us the area under the curve.

A graphing utility like Desmos or Wolfram Alpha can be used to plot the function and find the area under the curve.

The cost of 1.1 kilograms of hamburger meat at $5.00 per kilogram is $5.50

Multiply the weight of the meat (1.1 kg) by the price per kilogram ($5.00):

1.1 kg x $5.00/kg = $5.50.

Therefore, it cost Isabella $5.50 to buy 1.1 kilograms of top-quality hamburger meat.

To find 2x, we first need to solve for x in the equation 3x - 1 = 11. We isolate x by adding 1 to both sides and divide by 3 to obtain x = 4. Finally, multiplying x by 2 gives us 2x = 8.

To solve the equation 3x - 1 = 11 for 2x, we need to isolate x first. Adding 1 to both sides, we get 3x = 12. Dividing both sides by 3, we find that x = 4. Now, to find 2x, we simply multiply x by 2, which gives us 2(4) = 8.

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Answer:

14 questions.

Step-by-step explanation:

We have been given that your teacher tells you to do questions 28 through 41 in your math book for homework. We are asked to find he total number of questions.

Since we need to solve questions 28 through 41, this means we have to solve question number 28 and 41 as well.

We know that 28-37 would be 10 questions and 38-41 would be 4 questions.

[tex]\text{Total questions}=10+4[/tex]

[tex]\text{Total questions}=14[/tex]

Therefore, you need to solve 14 questions to complete the homework.