Work done is defined as product of force and displacement of point of application of force.
So here we will have
[tex]W = F.d[/tex]
now since here after applying the force the car is not displaced from its position
So here we have
d = 0
so work done is given as
[tex]W = 900 \times 0 = 0[/tex]
so there is no work done in this case
A 3kg object moving at 15 m/s what is the momentum
p=m•v=3•15=45 kg•m/s
A 12kW motor moves a 1000kg car at what constant velocity, if the motor applies a force that equals 2000N? Also, of the motor for 2.75s, what amount of work has the motor done on the car. (Show working out)
Given data
Power = 12 KW ,
mass (m) = 1000 kg ,
Force (F) = 2000 N ,
time (t) = 2.75 s
Determine
1. Velocity (v) = ?
2. Work (W) = ?
We know that Power (P) = Rate of doing work
= ( Work ÷time) KW
Also we know that Work = F × displacement
Force = m.a N
=> 2000 = 1000 × a
=> a = 2 m/s²
And we know that acceleration (a) = rate of change of velocity
= v ÷ t
=> v = a × t
= 2 × 2.75
= 5.5 m/s
Now determine the Power P = Work done ÷ time
12 = W ÷ 2.75
W= 12 ×2.75
= 33 KJ
= 33000 J
The gravitational potential energy that an object possesses is dependent on which of the following?
Answer:
The energy depends on the object's mass, height above Earth's surface, and the gravitational acceleration constant.
Explanation:
The potential energy is a relationship as follows:
[tex]E_p = m\cdot g\cdot h[/tex]
where m is the mass of the object (kg), h is the height/altitude of the aboject measured in meters above Earth's surface, and g is the gravitational acceleration, typically take to be 9.8 m/s^2.
Gravitational potential energy is dependent on the object's mass, its height above a reference point, and the gravitational acceleration, encapsulated by the formula ΔPEg = mgh. This energy is associated with the state of separation between the object and the Earth. The difference in gravitational potential energy carries physical significance.
Explanation:The gravitational potential energy that an object possesses is dependent on multiple factors. Key among these is the mass of the object, the height above the reference point (usually Earth's surface), and the gravitational acceleration (which is approximately 9.8 m/s² near the surface of the Earth). These variables relate based on the equation ΔPEg = mgh, where ΔPEg represents the change in gravitational potential energy, m is the mass, g is the gravitational acceleration, and h is the height increase.
For instance, when we lift an object, work is done against gravity and it becomes potential energy of the object-Earth system. This energy is associated with the state of separation between two objects that attract each other by the gravitational force. Notably, it is the difference in gravitational potential energy that holds physical significance.
To illustrate, consider a roller coaster car at the top of a hill. It has gravitational potential energy due to its elevated position above Earth's surface. As it descends, this stored energy is converted into kinetic energy, or energy of motion, propelling the car downwards.
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if you throw a ball at 35° and 10 m/s what is the horizontal component of velocity
0.0m/s
10m/s
5.7m/s
8.2m/s
Answer:
8.2 m/s
Explanation:
The horizontal component of the velocity is given by:
[tex]v_x = v cos \theta[/tex]
where
v = 10 m/s is the magnitude of the velocity
[tex]\theta=35^{\circ}[/tex] is the angle at which the ball has been thrown, with respect to the horizontal
Substituting the values into the equation, we get
[tex]v_x=(10 m/s)(cos 35^{\circ})=8.2 m/s[/tex]
Final answer:
The horizontal component of velocity of a ball thrown at 35° and 10 m/s is 8.2 m/s.
Explanation:The horizontal component of the velocity of a ball thrown at an angle of 35° and a speed of 10 m/s can be found using trigonometry. The horizontal component is given by the formula:
Horizontal velocity (Vx) = Initial velocity (V0) * cos(angle)
Substituting the given values:
Vx = 10 m/s * cos(35°)
Vx ≈ 10 m/s * 0.819
Vx ≈ 8.19 m/s
Therefore, the horizontal component of velocity is approximately 8.2 m/s.
The 64.5-kg climber in is supported in the “chimney” by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.80 and 0.64, respectively. Assume the walls are vertical and that the static friction forces are both at their maximum. Ignore his grip on the rope.
Determine the minimum normal force he must exert.
Answer:
The minimum force the climber must exert is about 439N.
Explanation:
We use the relationship between friction and normal force to answer this question:
[tex]F_{friction} = \mu_{static} \cdot F_{normal}\implies F_{normal}=\frac{F_{friction}}{\mu_{static}}[/tex]
We are given the static coefficients of friction but need to determine the friction force. To do that we consider the totality of forces acting on this hapless gentleman stuck in a chimney. There is the gravity acting downward (+), then there are two friction forces acting upward (-), namely through his shoes and his back. The horizontal force exerted by the climber on both walls of the chimney is the same and is met with equally opposing normal force. Since the climber is not falling the net force in the vertical direction is zero:
[tex]F_{net} = 0 = F_g - F_{shoes}-F_{back}= mg - \mu_{shoes}F_{norm}-\mu_{back}F_{norm}\\F_{norm}=\frac{mg}{\mu_{shoes}+\mu_{back}}=\frac{64.5kg\cdot 9.8\frac{m}{s^2}}{0.8+0.64}\approx 438.96N\\[/tex]
The normal force in this equilibrium is about 439N and because we are told that the static friction forces are both at their maximum, this value is at the same time the minimum force needed for the climber to avoid starting slipping down the chimney.
The climber must exert normal forces with his shoes and back to stay stationary in the chimney, counteracting his weight through friction. Assuming an even distribution for simplicity, a normal force of at least 439.24 N at each point would be necessary to maintain his position.
Minimum Normal Force by a Climber
To determine the minimum normal force the climber must exert to stay stationary in the chimney, we first need to consider the forces acting on the climber. There are two frictional forces that counteract the climber's weight: the friction on the shoes and the friction on the back. Since we are ignoring the climber's grip on the rope, these frictional forces are the only forces preventing the climber from falling.
The climber's weight (W) is calculated by the formula W = m × g, where 'm' is the mass of the climber (64.5 kg) and 'g' is the acceleration due to gravity (9.8 [tex]m/s^2[/tex]). For the climber to remain stationary, the friction forces (f) on both the shoes and the back must equal the weight. The maximum friction force is given by f = μ × N, where 'μ' is the coefficient of friction and 'N' is the normal force.
The total normal force exerted by the climber is the sum of the normal forces from the shoes and the back. To find the minimum normal force, we set the two friction forces equal to the climber's weight:
[tex]f_{shoes} = \mu_{shoes} \times N_{shoes}\\f_{back} = \mu_{back} \times N_{back}\\W = f_{shoes} + f_{back}[/tex]
Solving for [tex]N_{shoes}[/tex] and [tex]N_{back}[/tex] gives us the total normal force required, which must be the sum of the two since they happen at different points on the climber's body.
The static coefficients of friction given are 0.80 for the shoes and 0.64 for the back. We can use these to find the normal force exerted at each point if we knew the distribution of weight between the climber's shoes and back, which isn't provided. If we assume an even distribution for simplicity, though it's not necessarily accurate, the calculation would be as follows:
W = 64.5 kg × 9.8 [tex]m/s^2[/tex] = 632.1 N
[tex]F_{shoes} + F_{back} = W\\0.80 \times N_{shoes} + 0.64 \times N_{back} = 632.1 N[/tex]
If [tex]N_{shoes}[/tex] = [tex]N_{back}[/tex] (even distribution), then [tex]N_{shoes}[/tex] = [tex]N_{back}[/tex] = 632.1 N / (0.80 + 0.64)
[tex]N_{shoes}[/tex] = [tex]N_{back}[/tex] = 632.1 N / 1.44
[tex]N_{shoes}[/tex] = [tex]N_{back}[/tex] = 439.24 N
Therefore, the climber must exert a normal force of at least 439.24 N with each his shoes and back in an ideal even distribution scenario to not fall.
how do kinetic energy,gravitational potential energy and heat due to friction change as the marble rolls down the ramp
What circular motion occurs when an object is traveling with constant speed in a circle ?
An object moving in a circle is accelerating. Accelerating objects are objects which are changing their velocity - either the speedor the direction. An object undergoing uniform circular motion is moving with a constant speed.
Uniform circular motion occurs when an object moves along a circular path at a constant speed, involving constant centripetal acceleration due to the continuous change in direction, despite the speed being unchanged.
Explanation:What circular motion occurs when an object is traveling with constant speed in a circle? The answer is uniform circular motion. This phenomenon occurs when an object moves along a circular path with a constant speed. Despite the speed being constant, the direction of the motion changes continuously, leading to a change in velocity. Since velocity is a vector quantity that depends on both speed and direction, its alteration signifies the object is accelerating. This type of acceleration is known as centripetal acceleration, which is always directed towards the center of the circle.
Three critical constants in uniform circular motion include the radius of the circular path, the magnitude of acceleration, and the speed of the object. These constants ensure the motion is uniform, meaning the object covers equal distances along the circle in equal intervals of time. While the speed remains unvaried, the acceleration involved is necessitated by the need to continuously change the direction of the velocity vector.
In summary, uniform circular motion is characterized by constant speed but changing velocity due to continual directional changes. The consistent change in direction necessitates centripetal acceleration, making the motion unique in its dynamics and effects, such as those felt on a roller coaster during rapid turns. Understanding this concept is fundamental in explaining various phenomena in physics and related fields.
Name and briefly describe the two types of interference
The two types of wave interference are constructive and destructive.
These both describe what happens when waves combine
Constructive interference is when 2 waves combine to form a wave with a larger amplitude, but this is only if both waves are both positive or both negative.
Destructive interference is when the two waves are opposite, one is negative, one is positive. They subtract forming the combined wave that has a lower amplitude.
I hope that helps u out!! :)
I SERIOUSLY can't do this type of questions so can someone solve it detailedly and putting with letters (there is a system you name conducting wires as A, B etc. I don't know what that system calls in physics)
Find the equivalent resistance with details
Answer:
4 Ohms
Explanation
(This is seriously not as hard as it looks :)
You only need two types of calculations:
replace two resistances, say, R1 and R2, connected in a series by a single one R. In this case the new R is a sum of the two: [tex]R = R_1+R_2[/tex]replace two resistances that are connected in parallel. In that case: [tex]\frac{1}{R}= \frac{1}{R_1}+\frac{1}{R_2}\\\mbox{or}\\R= \frac{R_1\cdot R_2}{R_1+R_2}[/tex]I am attaching a drawing showing the process of stepwise replacement of two resistances at a time (am using rectangles to represent a resistance). The left-most image shows the starting point, just a little bit "warped" to see it better. The two resistances (6 Ohm next to each other) are in parallel and are replaced by a single resistance (3 Ohm, see formula above) in the top middle image. Next, the two resistances (9 and 3 Ohm) are nicely in series, so they can be replaced by their sum, which is what happened going to the top right image. Finally we have two resistances in parallel and they can be replaced by a single, final, resistance as shown in the bottom right image. That (4 Ohms) is the equivalent resistance of the original circuit.
Using these two transformations you will be able to solve step by step any problem like this, no matter how complex.
1. Is this graph exponential growth or exponential decay? Explain why.
2. On what swing did the pendulum's maximum height dip below 1 in. for the first time?
1). This graph reveals exponential decay. As time goes on (moving left to right across the graph), the maximum excursion of the pendulum's swing becomes smaller and smaller. On a graph of exponential growth, it would get larger and larger as time goes on.
2). The first time the pendulum's maximum height dipped below 1 inch was on the 4th swing.
Answer:
4 swings
Explanation:
explain how attaching the key to a piece of wood could prevent the key from sinking
It could prevent the key from sinking because the wood would float.
It floats because it weighs less than amount of water it would have to push out of the glass if it sank. Wood, cork, and ice are all less dense than water, and they float; rocks are more dense, so they sink. A key would also be more dense causing it to sink.
Hope this helps,
Davinia.
Attaching the key to a piece of wood could prevent the key from sinking
because the weight of a piece of wood is light when compared to that of the
key.
The wood will however float because the weight of the wood is less than the amount of water that will be displaced.
On the other hand, the key will sink as a result of the weight of the key being
more than the amount of water that will be displaced. Attaching the key to the wood will thereby prevent it from sinking
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An isotope has the same number of but a different number of than other atoms of the same element.
1. protons 2. neutrons
Answer:
protons
neutrons
Explanation:
How fast would you have to launch a ball at 45 degrees above the horizontal to reach a height of 49 meters in the air? [Must show work]
Let say the ball is projected in air with speed "v" at an angle of 45 degree
now the two components of its velocity will be given as
[tex]v_x = vcos45 = 0.707 v[/tex]
[tex]v_y = vsin45 = 0.707 v[/tex]
now the maximum height reached by the ball is 49 m
so as it will reach to maximum height its velocity in y direction will become zero
so we can use kinematics in y direction
[tex]v_f^2 - v_i^2 = 2 a y[/tex]
[tex]0 - (0.707v)^2 = 2(-9.8)(49)[/tex]
[tex]0.5v^2 = 960.4[/tex]
[tex]v = 43.8 m/s[/tex]
so the speed with which ball is projected upwards must be 43.8 m/s
What determines the mass of an object
Answer:
Mass is a fundamental property of the object. The mass of an object is a measure of objects resistance to acceleration, sometime also called "Inertia".It is a numerical measure of its inertia. Mass measured by using balancea dog has a mass of 13kg
a. how much does the dog weigh on earth (g=9.8m/s2)?
b. what is the mass of the dog on the moon?
c. how much does the dog weigh on the moon (g=1.6m/s2)?
d. why is g different for the moon and the earth?
A: w=mg w=13(9.8) w= 127.4
B: 13kg
C: w=mg w=13(1.6) w= 20.8
D: The force of gravity is less on the moon than on earth therefore making the dog weigh less.
The dog weighs 127.4N on Earth and 20.8N on the Moon while its mass remains a constant 13kg in both places. The difference in weight is because of the difference in gravitational pull, with Earth having a larger 'g' value due to its greater mass than the Moon.
Explanation:a. The dog's weight on Earth can be calculated by the formula w = mg, where m is mass and g is gravity. Thus, it weighs 13kg × 9.8m/s² = 127.4N on Earth.
b. The mass of an object is constant, regardless of location. So, the mass of the dog on the Moon is still 13kg.
c. The dog's weight on the moon can be calculated with the same formula, but using the Moon’s gravity. Thus, it weighs 13kg × 1.6m/s² = 20.8N on the Moon.
d. The acceleration due to gravity, 'g', is different for the Earth and the Moon because it depends on the size and mass of the celestial body. The Earth has a much greater mass than the Moon, resulting in a greater gravitational pull and hence a larger value for 'g'.
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How are the energy of infrared, visible light and ultraviolet rays related? And why?
The different types of radiation are defined by the the amount of energy found in the photons. Radio waves have photons with low energies, microwave photons have a little more energy than radio waves, infrared photons have still more, then visible, ultraviolet, X-rays, and, the most energetic of all, gamma-rays
hope this helps change it up a little
The energy of these spectral bands are related through the Einstein-Planck formula:
E = h * f
with h the Planck's constant and f the frequency of the electromagnetic wave.
Since the (frequency of infrared) is < (frequency of visible) < (frequency of ultraviolet), from the Einstein-Planck relationship it follows that the (energy of infrared) < (energy of visible) < (energy of ultraviolet).
Laurie is moving a dresser with a mass of 250 kg. She does 126 J of work with a force if 14 N. How far does she move the dresser?
Answer: 9 m
Explanation:
Work is said to be done when an unbalanced force causes displacement of the body.
Force is the product of mass (m) and acceleration (a).
Work = Force × Displacement
⇒W = F.s = ma.s
It is given that mass of the dresser is, m = 250 kg
work done, W = 126 J
Force acting on the dresser, F = 14 N
we need to find displacement, s
⇒126 J = 14 N × s
⇒ s = 126 J/ 14 N = 9 m
Hence, Laurie is able to move the dresser to about 9 m.
Answer:
9 m
Explanation:
When an object moves or displaces along the direction of the applied force application of force, it is said that work is done.
We know the formula of work:
Work = force x displacement
where force = mass x acceleration
So this formula can be further broken down to :
Work = mass x acceleration x d
Putting in the given values to get:
126 = 14 x d
d = 126/14
d = 9 m
Therefore, the dresser was moved by 9m.
A barrel 1 m tall and 60 cm in diameter is filled to the top with water. What is the pressure it exerts on the floor beneath it? What could you do to reduce this pressure without removing the water?
Answer:
The pressure on the ground is about 9779.5 Pascal.
The pressure can be reduced by distributing the weight over a larger area using, for example, a thin plate with an area larger than the circular area of the barrel's bottom side. See more details further below.
Explanation:
Start with the formula for pressure
(pressure P) = (Force F) / (Area A)
In order to determine the pressure the barrel exerts on the floor area, we need the calculate the its weight first
[tex]F_g = m \cdot g[/tex]
where m is the mass of the barrel and g the gravitational acceleration. We can estimate this mass using the volume of a cylinder with radius 30 cm and height 1m, the density of the water, and the assumption that the container mass is negligible:
[tex]V = h\pi r^2=1m \cdot \pi\cdot 0.3^2 m^2\approx 0.283m^3[/tex]
The density of water is 997 kg/m^3, so the mass of the barrel is:
[tex]m = V\cdot \rho = 0.283 m^3 \cdot 997 \frac{kg}{m^3}= 282.151kg[/tex]
and so the weight is
[tex]F_g = 282.151kg\cdot 9.8\frac{m}{s^2}=2765.08N[/tex]
and so the pressure is
[tex]P = \frac{F}{A} = \frac{F}{\pi r^2}= \frac{2765.08N}{\pi \cdot 0.3^2 m^2}\approx 9779.5 Pa[/tex]
This answers the first part of the question.
The second part of the question asks for ways to reduce the above pressure without changing the amount of water. Since the pressure is directly proportional to the weight (determined by the water) and indirectly proportional to the area, changing the area offers itself here. Specifically, we could insert a thin plate (of negligible additional weight) to spread the weight of the barrel over a larger area. Alternatively, the barrel could be reshaped (if this is allowed) into one with a larger diameter (and smaller height), which would achieve a reduction of the pressure.
what is the dimension of magnetic flux
The unit of magnetic flux is 1 Weber (Wb).
One Newton is expressed in ?
Answer:
It is the SI unit of force.
Explanation:
The rate of change of momentum in the body is directly proportional to the force applied on the body. It is the second law of motion.
The mathematical form of Newton's second law is
F = m x a
where, m is the mass and a be the acceleration.
If a body of mass 1 kilogram having an acceleration of 1 m/s^2, it means the force applied on the body is 1 newton.
A lamp is 10% efficient.How much electrical energy must be supplied to the lamp each second if it produces 20 J of light energy per second?
If it produces 20J of light energy in a second, then that 20J is the 10% of the supply that becomes useful output.
20 J/s = 10% of Supply
20 J/s = (0.1) x (Supply)
Divide each side by 0.1:
Supply = (20 J/s) / (0.1)
Supply = 200 J/s (200 watts)
========================
Here's something to think about: What could you do to make the lamp more efficient ? Answer: Use it for a heater !
If you use it for a heater, then the HEAT is the 'useful' part, and the light is the part that you really don't care about. Suddenly ... bada-boom ... the lamp is 90% efficient !
The lamp is 10% efficient which means it converts only 10 % of its input energy into output. Hence, it will produce 20 J/s when an energy of 200 J/s is applied.
What is electrical energy?Electrical energy is a form of energy generated by the movement of free electrons from the valence band to the conduction band. Electrical energy can be converted to other forms of energy such as light energy, mechanical energy etc.
The efficiency of an electric device is its ratio of the input energy to the output energy. No device can be 100 % efficient because the a significant portion of the applied energy is lost in the form of heat energy.
Given that the efficiency of the lamp is 10%. Thus, it converts only 10 % of its input energy to the output. The output energy is 20 J/s. Which is 10% of 200J/s. Therefore, the energy applied here is 200 J/s.
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How does the paint on a car help to keep it from rusting?
Because the paint over the iron of the car helps to keep the iron from coming in contact with air, and that's why cars in junkyards are usually rusted, because the paint is chipped or gone.
Iron rusts because it can be contacted by water-or the moisture in the air- and the metal takes the oxygen from the water forming iron oxide-rust. Paint or plating (like chrome plating) prevents the H2O molecules from reaching the surface of the metal so it can't get the oxygen.
A block of mass 8.0 kg is held stationary on a slope whose surface is inclined 31 degrees relative to the horizontal.
When released it slides down the slope with a constant acceleration of 0.9 ms^-2.
Using your knowledge of forces, calculate the surface's coefficient of friction, μ. Assume g = 9.8 ms^-2.
Answer:
0.49
Explanation:
There are two forces acting on the block in the direction parallel to the surface of the inclined plane:
- The component of the weight of the block parallel to the incline:
[tex]mg \sin \theta[/tex]
where m = 8.0 kg is the mass of the block, g=9.8 m/s^2 and [tex]\theta=31^{\circ}[/tex] is the angle of the ramp
- The frictional force, given by:
[tex]\mu mg cos \theta[/tex]
where [tex]\mu[/tex] is the coefficient of friction.
The two forces act in opposite direction, and according to Newton's second law, their resultant is equal to the product of the mass of the block (m) and its acceleration (a):
[tex]mg sin \theta - \mu mg cos \theta = ma[/tex]
Since we knw that [tex]a=0.9 m/s^2[/tex], we can re-arrange the equation to find the coefficient of friction:
[tex]\mu = \frac{g sin \theta -a}{ g cos \theta}=\frac{(9.8 m/s^2)(sin 31^{\circ})-0.9 m/s^2}{(9.8 m/s^2)(cos 31^{\circ})}=0.49[/tex]
What is the wavelength of the wave above?
A- 0.75 cm
B- 1.5 cm
C- 2.5 cm
D- 3.5 cm
Answer ; 2.5 (C)
From the given figure it is cleat that the wave length (λ) = 2.5 cm
It is a "measure of distance between two identical crests or identical troughs in a wave.
In the figure, high points are crests and low points are troughs.
PLZ HELP!! IM DESPERATE, ASAP IF YOU CAN!
The steps in the heating of the handle of a pan held over a flame are listed below:
Step 1: Heat from the flame travels to the base of the pan
Step 2: Heat from the base of the pan travels through the pan to the part where the handle touches the pan
Step 3: Heat from one end of the handle travels to the other end
By which method is heat transferred in the three steps?
Radiation in Step 1 and conduction in Steps 2 and 3
Conduction in Step 1 and radiation in Steps 2 and 3
Conduction in Step 1 and convection in Steps 2 and 3
Convection in Step 1 and conduction in Steps 2 and 3
Your most likely answer would be D, though, I'm not too sure on it.
However, conduction is present during this process, as well for convection. Convection started up the heating process, and it caused conduction within the pan.
I'm hoping this helps you out.
Answer:
Convection in Step 1 and conduction in Steps 2 and 3
Explanation:
Convection is the fire and the clue word that led me to conduction for steps 2/3 is "touches" it was either Radiation in Step 1 and conduction in Steps 2 and 3 OR Convection in Step 1 and conduction in Steps 2 and 3 and it is not radiation because there is no electromagnetic waves in the flame so its Convection in Step 1 and conduction in Steps 2 and 3, THE LAST ONE, D
List examples of foliated and non-foliated rocks. Explain the difference between the two types of metamorphic rocks.
Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.
Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.
A collision in which kinetic energy is transferred only as kinetic energy from one object to another and is not converted in any other amount to any other form of energy
A static friction.
B kinetic energy
C elastic collision
D bouyant force
C. Elastic collision. A perfect elastic collision is on that doesn't result in any k.e loss during the collision.
Elastic collision is the correct answer C.
Which of the following explains why tides occur every 12 hours and 25 minutes?
A. Variations in the land and depth of water make the tides uneven.
B. It takes 24 hours and 50 minutes for the earth to make a complete rotation.
C. Early scientists misunderstood how to calculate tides, and their error persists to this day
D. In some seasons, the rotation of the earth is slower than others, requiring additional time.
Answer : B
A lunar day is the time it takes a specific site on the earth to rotate from exact point under the moon to the same point. Unlike the solar day, a lunar day is 24 hours 50 minutes. the lunar day is 50 minutes longer than the solar day because the moon revolves around the earth in the same direction that the earth rotates around its axis. So it takes the earth an extra 50 minutes to catch up.In lunar day coastal areas experience two high and two low tides every 24 hours and 50 minutes. High tides occur every 12 hr 25 minutes apart.Final answer:
The reason why tides occur every 12 hours and 25 minutes is that the Earth takes 24 hours and 50 minutes to align again with the Moon due to the Moon's orbit, requiring Earth to rotate a bit more each day. Option B is the correct answer.
Explanation:
Tides occur due to the gravitational pull primarily of the Moon and, to a lesser extent, the Sun on Earth's oceans. High tides occur approximately every 12 hours and 25 minutes. This is because the Moon takes 24 hours and 50 minutes to rotate once around the Earth, meaning the Earth has to rotate a little bit more each day to align with the Moon again. Since tides occur twice a day, the extra time divided by two gives us the 12 hours and 25 minutes between successive high tides.
The correct answer to why tides occur every 12 hours and 25 minutes is that the Earth has to rotate an additional distance for a location to re-align with the Moon's position due to the Moon's orbit around Earth. Therefore, option B is correct: It takes 24 hours and 50 minutes for the Earth to make a complete rotation relative to the Moon.
iron is much denser than a feather. yet a particicular sample of fathers weighs more than a simple of iron. explain how this is possible
Final answer:
A steel needle or paper clip can float on the surface of water even though steel is denser than water. This is due to surface tension, which creates an upward force that counteracts the force of gravity.
Explanation:
Although steel is denser than water, a steel needle or paper clip placed carefully lengthwise on the surface of still water can be made to float. This is possible because of a phenomenon called surface tension. Surface tension is the force that acts on the surface of a liquid and tends to minimize its area.
When a small object like a steel needle or paper clip is placed on the surface of water, the surface tension of the water molecules pulls on the object from all sides, creating an upward force that counteracts the force of gravity. As a result, the object floats on the surface of the water.
This demonstrates that density alone does not determine whether an object will float or sink. Other factors, such as surface tension, can play a significant role in determining whether an object will float or sink.
The latent heat of vaporization for ethyl alcohol is 854 J/g. The amount of energy, rounded to the nearest whole number, needed to change 5.20 grams of ethyl alcohol from a liquid to a gas is J.
Answer:
4441 J
Explanation:
The amount of energy needed to change the ethyl alcohol from liquid to gas state is given by
[tex]Q=m \lambda_v[/tex]
where
m = 5.20 g is the mass of the alcohol
[tex]\lambda_v = 854 J/g[/tex] is the latent heat of vaporization of the substance
Substituting the numbers into the formula, we find:
[tex]Q=(5.20 g)(854 J/g)=4,441 J[/tex]
Answer:
4441
Explanation: