A=2πr^2+2πrh Solve for π

Answer:

12 hours 15 min

Step-by-step explanation:

Melissa has 14 reports to file.

She file 70% of report. She takes average of 1 hour and 15 minutes for each report.

First we find number of reported by Melissa.

Number of reported = 70% of 14

                                        = 9.8

1 hour 15 min [tex]=\dfrac{5}{4}[/tex] hours

For 1 report of file [tex]=\dfrac{5}{4}[/tex] hours

For 9.8 reports of file [tex]=9.8\times \dfrac{5}{4}\approx 12.25[/tex] hours

She will take 12.25 hours to report 70% of them.

12.25 hours = 12 hours 15 min

Hence, Melissa will take 12 hours 15 min to file 70% of report.

we know that

An equilateral triangle is a regular polygon, because all sides are equal

In a regular polygon the area is equal to

[tex]A=\frac{1}{2}*apothem*perimeter[/tex]

in this problem we have

[tex]apothem=2.16\ cm\\ perimeter=22.45\ cm[/tex]

substitute in the formula

[tex]A=\frac{1}{2}*2.16*22.45[/tex]

[tex]A=24.2\ cm^{2}[/tex]

therefore

the answer is

the area of the triangle is [tex]24.2\ cm^{2}[/tex]

The area of an equilateral triangle rounded to the nearest tenth is 24.2 [tex]cm^2[/tex].

Given the following data:

An equilateral triangle can be defined as a type of triangle or regular polygon that has equal length of sides.

Mathematically, the area of an equilateral triangle is given by this formula:

[tex]Area = \frac{1}{2} \times apothem \times perimeter[/tex]

Substituting the given parameters into the formula, we have;

[tex]Area = \frac{1}{2} \times 2.16 \times 22.45\\\\Area = \frac{1}{2} \times 48.492[/tex]

Area = 24.246 ≈ 24.2 [tex]cm^2[/tex].

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Answer:

The answer for the area of the parking lot is 27,000m²

Step-by-step explanation:

Given that the shape of the parking lot is a rectangle we can model the area using the formula for area of a rectangle Which is

A= length *width

Step two :

Given length 20cm

Width 6cm

Furthermore the scale is

1cm:15m

That is 1cm represents 15m on paper

Therefore the length in meters

=20*15=300m

Width in meter

=6*15=90m

Area =300*90

Area =27,000m²

Answer:

0.71

Step-by-step explanation:

Final answer:

There are a total of 93 musicians in both the String and Brass sections of the Symphony Orchestra, with 29 in the Brass and 64 in the String section.

Explanation:

To determine how many musicians are in both the String and Brass sections of the Symphony Orchestra, we start by noting that there are 29 musicians in the Brass section. Since there are 35 more musicians in the String section, we add 35 to the number of Brass musicians to find the total in the String section:

To find the enrollment this year, calculate 12% of last year's enrollment and add it to the enrollment from last year. The enrollment this year is 17,360.

To find the enrollment this year, we need to calculate 12% of last year's enrollment and add it to the enrollment from last year.

Therefore, the enrollment this year is 17,360.

The total number of candies are 3¹² if there are  (3⁶)² . 3⁰ candies in a store; the answer is 3¹² candies option (D) 3¹² is correct.

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

It is given that:

The number expression is:

= (3⁶)² . 3⁰

As we know, from the properties of the integer exponent:

After using the properties of the integer exponent:

(3⁶)² = 3¹²

3⁰ = 1

(3⁶)² . 3⁰ = 3¹²

Thus, the total number of candies are 3¹² if there are  (3⁶)² . 3⁰ candies in a store; the answer is 3¹² candies option (D) 3¹² is correct.

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A peptide bond forms between two amino acids by a dehydration synthesis reaction. The number of peptide bonds in a polypeptide is always one less than the total number of amino acids. Therefore, in a polypeptide with 45 amino acids, there would be 44 peptide bonds.

A peptide bond is a chemical bond that forms between two amino acids when a carboxyl group of one amino acid reacts with the amino group of the other amino acid, releasing a molecule of water. This is a dehydration synthesis reaction, and it is how amino acids are linked together to form a polypeptide.

In a polypeptide chain, the number of peptide bonds present is always one less than the total number of amino acids. This is because each amino acid has one peptide bond with the next amino acid in the chain, except the last one. Hence, for 45 amino acids, there would be 44 peptide bonds.

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Answer:

Barney can make 3 costumes

Step-by-step explanation:

T = 16 1/5 = 81/5 yards

O = 5 2/2 = 27/5 yards/costume.

We have the total fabric (T) and the unitari costume requirement (O). Now, if we want to know the amount of costumes that Barney can make, we can divide total fabric (T) by the unitari costume requirement (O), the result will be the amount of costumes (A).

[tex]A = \frac{T}{O}=\frac{\frac{81}{5}}{\frac{27}{5}} =\frac{81*5}{5*27} =\frac{81}{27}\\A = \frac{81}{27} =\frac{9}{3} = 3 costumes[/tex]

Finally, we can conclude that Barney can make 3 costumes. 

Ratios and rates are used in Mathematics to solve various problems. They are used in unit conversions through conversion factors, in dimensional analysis, in calculation of relative rates of reaction, and in data measurements for statistical analysis.

Using ratios and rates in Mathematics can be extremely useful to solve a wide range of problems. Ratios are a way to compare two or more quantities, and rates are ratios that compare two different units.

For example, conversion factors, generated from ratios of equivalent quantities with different measurement units, can be very helpful in unit conversions. If we know that 2.54 cm is equivalent to 1 inch, we can set up a ratio of 2.54 cm/1 in. and use it as a conversion factor.

Dimensional Analysis is another technique where ratios play a vital role. It involves using rates or conversion factors to convert units. With practice, we can develop good estimation skills with dimensional analysis, guiding us whether our solution seems reasonable or not.

In addition, ratios can be used in Relative Rates of Reaction in Chemistry, where the rate of a reaction may be expressed as the change in concentration of any reactant or product. Depending on the stoichiometry of the reaction, we can relate reactants and products rates to each other.

Moreover, ratios are employed in data measurements, providing detailed information in fields like Statistics. For example, to analyse the data such as exam scores, we can order the results, calculate the differences, and express the results in ratio form.

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