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Heat will flow from object A to object B if:

1 The molecular average kinetic energy of the two objects is the same.

2 The molecular average kinetic energy of A is higher than that of B.

3 The molecular average kinetic energy of B is higher than that of A.



I only


II only


I and III


III only

Answer:

Bubba like Billie :)

Final answer:

Newton's Third Law of Motion dictates that a force exerted on Billie by Bubba results in an equal and opposite force exerted back on Bubba, regardless of Billie's actions.

Explanation:

The scenario described involves Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. Despite Billie keeping his hands in his pockets, when Bubba pushes Billie, there is a force exerted back on Bubba, even if Billie does not actively push back. This interaction is involuntary and happens naturally due to the laws of physics.

Answer:

5 ) The mass, 6) with lubrication and using surfaces that are not rough

Explanation:

5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.

8)

Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.

[tex]F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons][/tex]

The distance between the two objects is 3.0 m

Explanation:

The magnitude of the gravitational force between two objects is given by the following equation:

[tex]F=G\frac{m_1 m_2}{r^2}[/tex]

where :

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant

[tex]m_1,m_2[/tex] are the masses of the two objects

r is the separation between the objects

In this problem, we have:

[tex]m_1 = 2 kg[/tex] is the mass of the book

[tex]m_2 = 5 kg[/tex] is the mass of the vase

[tex]F=7.41\cdot 10^{-11}N[/tex] is the force between the two objects

Re-arranging the equation and solving for r, we find the distance between the two objects:

[tex]r=\sqr{\frac{Gm_1 m_2}{F}}=\sqrt{\frac{(6.67\cdot 10^{-11})(2)(5)}{7.41\cdot 10^{-11}}}=3.0 m[/tex]

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Answer:

3.00 m

Explanation:

Answer:

J=36221 Kg.m/s

Explanation:

Impulse-Momentum Theorem

These two magnitudes are related in the following way. Suppose an object is moving at a certain speed [tex]v_1[/tex] and changes it to [tex]v_2[/tex]. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

[tex]p=mv[/tex]

The initial and final momentums are, respectively

[tex]p_1=mv_1,\ p_2=mv_2[/tex]

The change of momentum is

[tex]\Delta p=p_2-p_1=m(v_2-v_1)[/tex]

It is numerically equal to the Impulse J

[tex]J=\Delta p[/tex]

[tex]J=m(v_2-v_1)[/tex]

We are given

[tex]m=2498\ kg,\ v_1=17.1\ m/s,\ v_2=2.6\ m/s[/tex]

The impulse the car experiences during that time is

[tex]J=2498(2.6-17.1)=2498(-14.5)[/tex]

J=-36221 Kg.m/s

The magnitude of J is

J=36221 Kg.m/s

Answer:

0.308 m

Explanation:

Force = spring constant * change in length

F = k * Δx

F = 20 N

k = 65 N/m

Δx = ? m

20 = 65 * Δx

20/65 = Δx

Δx = 0.308 m

According to the question,

The force will be:

→  [tex]Force =Spring \ constant\times Change \ in \ length[/tex]

or,

→ [tex]F = k\times \Delta x[/tex]

then,

→ [tex]\Delta x = \frac{F}{k}[/tex]

By putting the values,

        [tex]= \frac{20}{65}[/tex]

        [tex]= 0.308 \ m[/tex]

Thus the above answer is right.

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The radius of planet 1 is [tex]\sqrt{3}[/tex] the radius of planet 2.

Explanation:

The gravitational force experienced by a person standing on the surface planet is given by

[tex]F=\frac{GMm}{R^2}[/tex]

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the person

R is the radius of the planet

In this problem, we know that:

Expliciting the two forces, we can write

[tex]F_1 = F_2\\\frac{GM_1 m}{R_1^2}=\frac{GM_2 m}{R_2^2}[/tex]

where [tex]R_1, R_2[/tex] are the radii of the two planets.

Substituting eq.(1) and re-arranging, we find:

[tex]\frac{G(3M_2) m}{R_1^2}=\frac{GM_2 m}{R_2^2}\\R_1^2 = 3R_2^2\\R_1 = \sqrt{3} R_2[/tex]

Which means that the radius of planet 1 is [tex]\sqrt{3}[/tex] the radius of planet 2.

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Answer:

range = x = 188 [m]

Explanation:

First we must find the velocity component on the horizontal axis or x-axis

[tex](v_{x})_{0} = 40*cos(20) \\(v_{x})_{0} = 37.58[m/s]\\[/tex]

Then using the kinematic expression that relates velocity with time, we can find the range of the projectile or the distance x.

[tex]x=(v_{x} )_{0}*t\\ x=37.58*5\\x=188[m][/tex]

Answer:

a. 60.5 kg

Explanation:

Given data,

The maximum water a boat can displace is, 60.5 ml

According to the principle of buoyancy, the weight of the floating body is equal to the weight of the liquid displaced.

Under standard temperature and pressure, a unit mass of water equals one liter.

If a boat can displace a maximum of 60.5 ml of water, then it can hold a mass of a maximum of 60.5 kg of mass.

Point of correction, acceleration is 9.81 m/s2

Answer:

5.4 Kg

Explanation:

We know that F=ma and making m the subject of the formula then

[tex]m=\frac {F}{a}[/tex] where m is the mass of the skateboard, F is the pulling force and a is the acceleration of the body

Substituting 53 N for F and 9.81 m/s2 for a then

[tex]m=\frac {53 N}{9.81 m/s2}=5.40265 Kg\approx 5.4 Kg[/tex]

The net force is 2.2 N at 80.9 degrees south of east

Explanation:

In order to find the net force, we have to resolve each force along the x-y direction, and then add the components in each direction.

Taking east as positive x-direction and north as positive y-direction, we have:

- First force:

[tex]F_{1x} = -3.0 N\\F_{1y} = 0[/tex]

- Second force:

[tex]F_{2x} = (4.0)(cos (-33^{\circ})=3.35 N\\F_{2y} = (4.0)(sin (-33^{\circ})=-2.18 N[/tex]

Therefore, the components of the net force are

[tex]F_x = F_{1x}+F_{2x}=-3.0+3.35=+0.35 N\\F_y = F_{1y}+F_{2y}=0+(-2.18)=-2.18 N[/tex]

And so, the magnitude of the net force is

[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{(0.35)^2+(-2.18)^2}=2.2 N[/tex]

And the direction is

[tex]\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-2.18}{0.35})=-80.9^{\circ}[/tex]

which means 80.9 degrees south of east.

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Answer:

A

Explanation:

i feel it is correct

in the sense that it dwpends on the presence of 4different antigens

Answer:

400 m/s

Explanation:

From the question;

We are required to calculate the speed of the wave;

Speed of the wave = 200 Hz × 2 m

                               = 400 m/s

Answer:

Kinetic energy of the girl and her bike is 5.544 kJ

Explanation:

Given that a girl is riding bike at speed of 12m/s

Also, mass of Girl is 55kg and mass of bike is 22kg

Let, Total mass of girl and bike be M=22+55=77kg

Now, Kinetic energy is given by K=[tex]\frac{1}{2} Mv^{2}[/tex]

Hence, Kinetic energy of the girl and her bike will be

K=[tex]\frac{1}{2} Mv^{2}[/tex]

K=[tex]\frac{1}{2} (77)(12)^{2}[/tex]

K=5544J

Thus, Kinetic energy of the girl and her bike is 5.544 kJ

i) The lowest temperature recorded is [tex]12^{\circ}C[/tex]

ii) All the liquid has evaporated after 140 seconds

Explanation:

i)

In this part of the problem, we have to find the lowest temperature recorded as the liquid evaporates.

In order to do that, we have to look at the graph, where we have:

- The time (in seconds) represented on the x-axis

- The temperature (in Celsius degrees) represented on the y-axis

The lowest temperature recorded corresponds to the minimum value of the variable on the y-axis. By looking at the graph, we see that the temperature starts from [tex]20^{\circ}[/tex] at time [tex]t=0[/tex], then it reaches a minimum of approximately [tex]12^{\circ}C[/tex] at about [tex]t=140 s[/tex], then it increases again. Therefore, the lowest temperature recorded is [tex]12^{\circ}C[/tex].

ii)

In this part, we have to determine how long it takes for all the liquid to evaporate.

The process of evaporation of a liquid takes place when the molecules located on the surface of the liquid, which have more kinetic energy than the other molecules, "escape" the liquid. When these molecules escape the liquid, they remove heat from the liquid (because they carry away energy): therefore, the temperature (which is a measure of the kinetic energy) at the surface of the liquid decreases. This effect is known as cooling effect of evaporation.

When this decrease in temperature stops, it means that the liquid has completely evaporated. From the graph, we see that this occurs when the time is approximately about 140 seconds.

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Answer:

A.Carbon-13

B.Yes of course

C.No

D.Not sure

Answer:

OAmalOHopeO

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

[tex]d=ut+\frac{1}{2}at^2[/tex]

where

u is the initial velocity

a is the acceleration

For car 1, we have

[tex]d_1 = u_1 t + \frac{1}{2}a_1 t^2[/tex]

where

[tex]u_1 = 7 m/s[/tex] is the initial velocity of car 1

[tex]a_1 = 0.4 m/s^2[/tex] is the acceleration of car 1

So the equation can be rewritten as

[tex]d_1 = 7t + 0.2t^2[/tex]

For car 2, we have

[tex]d_2 = u_2 t + \frac{1}{2}a_2 t^2[/tex]

where

[tex]u_2 = 4 m/s[/tex] is the initial velocity of car 2

[tex]a_2 = 0.5 m/s^2[/tex] is the acceleration of car 2

So the equation can be rewritten as

[tex]d_2= 5t + 0.25t^2[/tex]

The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

[tex]d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2[/tex]

And solving for t, we find

[tex]2t - 0.05t^2= 0\\t(2-0.05t)=0[/tex]

Which gives two solutions:

t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

[tex]d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m[/tex]

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Answer:

The acceleration of the car, is a = 4 m/s²

Explanation:

Given data,

The final velocity of the car, u = 0

The final velocity of the car, v = 20 miles/h

The time period of travel, t = 5 s

The acceleration of an object is defined as the rate of change of velocity.

From first equation of motion,

                            a = (v-u)/t

                               = (20 - 0)/5

                               = 4 m/s²

Hence, the acceleration of the car, is a = 4 m/s²

Answer:

KSHE [tex]94.7[/tex]

Explanation:

Given stations WIL [tex]92.3[/tex] and KSHE [tex]94.7[/tex]

The station number represents the frequency that waves of radio emit. They are measured in megahertz (MHZ).

Using the formula  

[tex]E=h\nu[/tex]

Where [tex]E[/tex] is energy.  

[tex]h[/tex] is Planck's constant.

[tex]\nu[/tex] is frequency.

We can see energy is directly related to frequency. A higher frequency will give higher energy.  

As channel KSHE [tex]94.7[/tex] has more frequency than channel WIL [tex]92.3[/tex].  

So, channel KSHE [tex]94.7[/tex] will have more energy.

Definition - Wave:

The wave is a type of vibration (disorder) that moves in space and matter. Wave motions pass energy from one point to other.

Explanation:

A wave is a disorder or change that gradually transfers energy from one point to another in a medium and can take the form of a flexible distortion or change in pressure, electric or magnetic current, electric potentials or temperature.

A medium passing through a wave may experience local vibrations when it passes through a wave, but the particle in the medium does not move with the waves. The disorder can take many forms, from a limited wide pulse to an infinitely long sinusoidal wave.

Answer:

C: equal to mg

Explanation:

in free-fall, gravity is always the net force on an object

The net force on an object that is thrown upward is less than mg (the object's mass times gravity). This is because the force of gravity is working against the motion of the object, making the net upward force less than the downward force of gravity.

The question is related to Physics, more specifically the concepts of forces and gravity. When an object is thrown upward, it experiences a downward force due to gravity which is equal to its mass (m) times the acceleration due to gravity (g), written as mg. Nevertheless, there is also an upward force exerted on the object, which is why it can ascend.

In the scenario described in the question, where an object is thrown straight up, the net force on an object while the object is going up is less than mg. This is because the force of gravity (mg) is effectively acting downwards, while a smaller net force is acting upwards, making the net force on the object less than mg during ascent.

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Answer:

Oxygen. When trees "breathe" they release oxygen and take in the carbon dioxide. On the other hand, when humans breathe we take in that oxygen and release carbon dioxide. In this way, we have a relationship that is mutually beneficial.

Answer:

4.4 m/s

Explanation:

Angular momentum is:

L = Iω

For a point mass, this can also be written as:

L = mvr

Angular momentum is conserved, so:

L₁ = L₂

m₁ v₁ r₁ = m₂ v₂ r₂

(2 kg) (1.1 m/s) (0.6 m) = (2 kg) v (0.15 m)

v = 4.4 m/s

Answer:

mantle

Explanation:

Answer:

The mantle. Its so hot it basically lava.

Explanation:

Answer:

Direct Current

Explanation:

The electricity only flows in one direction.

Answer:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull.

Explanation:

For projectile motion, use constant acceleration equation:

Δx = v₀ t + ½ at²

where Δx is the displacement,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

For the first object:

Δx = 60 t + ½ (-10) t²

Δx = 60 t − 5 t²

For the second object:

Δx = 0 (t−10) + ½ (-10) (t−10)²

Δx = -5 (t−10)²

When they meet, they have the same displacement, so:

60 t − 5 t² = -5 (t−10)²

60 t − 5 t² = -5 (t² − 20t + 100)

60 t − 5 t² = -5 t² + 100 t − 500

60 t = 100 t − 500

40 t = 500

t = 12.5

Plug into either of the original equations to find the displacement.

Δx = -5 (t−10)²

Δx = -5 (12.5−10)²

Δx = -31.25

The distance from the top of the cliff to the point where the objects meet is 31.25 meters.

Meterological means related to the weather.

Option C

Explanation:

Meteorological phenomenon is defined as a process taking place on earth’s surface that is related to weather, its changes and modifications. Meteorology has nothing to do with meteorites. Both land and oceans contribute equally in meteorology.

Changes in atmosphere is basically responsible for the changes in weather. Thunderstorms, blizzards, hurricanes, tornados all are within this disaster. Earthquakes etc are actually not included in this meteorology as there’s nothing related to weather that can trigger an earthquake. So earthquakes are excluded.

Answer: 286.33

Explanation:

multiplay them

The amount of energy needed to boil off the water is 5,845,000 J

Explanation:

The amount of thermal energy needed to completely boil a certain amount of a liquid substance already at boiling temperature is given by

[tex]Q=m\lambda_v[/tex]

where

m is the amount of the substance

[tex]\lambda_v[/tex] is the specific latent heat of vaporization of the substance

In this problem, the substance is water, and its mass is

m = 1.75 kg

Its specific latent heat of vaporization is

[tex]\lambda_v = 3.34\cdot 10^6 J/kg[/tex]

Assuming that the water is already at boiling temperature, therefore, the thermal energy needed to boil off the water is

[tex]Q=(1.75)(3.34\cdot 10^6)=5,845,000 J[/tex]

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Answer:

B

Explanation:

B. Edward Tolman

The psychologist known for latent learning and cognitive maps is B. Edward Tolman

The psychologist known for latent learning and cognitive maps is Edward Tolman. Tolman's various experiments with rats demonstrated that organisms can learn even if they do not receive immediate reinforcement, suggesting a cognitive aspect to comprehensive learning.

In some specific experiments, hungry rats were placed in a maze with no reward for finding their way through it. As they explored the maze, they developed a cognitive map or a mental picture of the maze layout. This is known as latent learning, which is learning that occurs but is not observable in behavior until there is a reason to demonstrate it.

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