Ajar contains 12 caramels, 7 mints and 16
dark chocolates. What is the probability of
selecting a mint expressed as a fraction?

Answer:

- 13

Step-by-step explanation:

f(1) = 7

f(n) = f(n − 1) – 4

f(₂) = f(1) – 4 = 7 - 4 = 3

f(₃) = f(₂) – 4 = 3 - 4 = -1

f(₄) = f(3) – 4 = (-1) - 4 = - 5

f(₅) = f(₄) – 4 = (- 5) - 4 = - 9

f(₆) = f(₅) – 4 = (- 9) - 4 =  - 13

The value of f(6) is -13, calculated based on the provided recursive formula where each term is four less than the previous.

We are given that f(1) = 7, and the recursive equation for n is f(n) = f(n − 1) – 4. Since the equation shows that each next term is four less than the previous one, we can calculate the following iterations:

So, the value of f(6) is -13.

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Answer:

6

Step-by-step explanation:

Step-by-step explanation:

5-in 5-in five interest answer

Answer:

x = 70

Step-by-step explanation:

First to make the equation easy, divide 42 by 3 to get what 1/7 of Z equals.

42 / 3 = 14

Now to get 5/7 of Z, just multiply 14 by 5.

14 x 5 = 70

x = 70

Hope this helped.

Answer:

70

Step-by-step explanation:

convert the decimal & solve for Z.

(3/7)Z = 42

(0.4286)Z = 42

Z = 98

Now,

(5/7)Z = ?

putting the value of Z

(0.714) (98) = 70

The required values are WZ = 13.75 and YZ = 27.

A perpendicular bisector is defined as a line that divides an angle into two equal angles. Draw the given angle first, then cut it in half, and then draw the angle's bisector.

As per question 1,

We have been given that ZX is the perpendicular bisector of WY

YZ = 13.75

13.75 + 13.75 = 27.5

27.5 / 2 = 13.75

WZ = 13.75

As per question 2,

We have been given that ZX is the perpendicular bisector of WY

WZ = 4n - 13 and YZ = n + 17

To find YZ

According to the property of the perpendicular bisector,

WZ = YZ

4n - 13 = n + 17

4n - n = 17 + 13

3n = 30

n = 30/3

n = 10

Substitute the value of n = 10 in YZ = n + 17

So, YZ = 10 + 17 = 27

Thus, the required values are WZ = 13.75 and YZ = 27.

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Answer: Molly will have to save $10 each week for 9 weeks to get $189.

Step-by-step explanation:

Start at $99, count $10 every week until you get $189. Your answer is 9 weeks.

Question:

If m (x) = StartFraction x + 5 Over x minus 1 EndFraction and n(x) = x – 3, which function has the same domain as (m circle n) (x)?

h (x) = StartFraction x + 5 Over 11 EndFraction

h (x) = StartFraction 11 Over x minus 1 EndFraction

h (x) = StartFraction 11 Over x minus 4 EndFraction

h (x) = StartFraction 11 Over x minus 3 EndFraction

Answer:

Option C: [tex]h(x)=\frac{11}{x-4}[/tex] has the same domain as [tex]$(m \circ n)(x)$[/tex]

Explanation:

It is given that [tex]m(x)=\frac{x+5}{x-1}[/tex] and [tex]n(x)=x-3[/tex]

Let us find the domain of [tex]$(m \circ n)(x)$[/tex]

[tex]$\begin{aligned}(m \circ n)(x) &=m(n(x))\\&=m(x-3) \\ &=\frac{(x-3)+5}{(x-3)-1} \\ &=\frac{x+2}{x-4} \end{aligned}$[/tex]

Now, let us equate the denominator equal to zero to determine the domain.

[tex]$x-4=0$[/tex]

     [tex]x=4[/tex]

Thus, the function becomes undefined at the point [tex]x=4[/tex]

Hence, the domain of [tex]$(m \circ n)(x)$[/tex] is [tex]$(-\infty, 4) \cup(4, \infty)$[/tex]

Now, we shall find the function which has the same domain as [tex]$(m \circ n)(x)$[/tex]

Option A: [tex]h(x)=\frac{x+5}{11}[/tex]

The function h(x) has the domain of set of all real numbers [tex]$-\infty<x<\infty$[/tex]

Thus, the interval [tex](-\infty,\infty)[/tex] is not the same domain as [tex]$(-\infty, 4) \cup(4, \infty)$[/tex]

Hence, Option A is not the correct answer.

Option B: [tex]h(x)=\frac{11}{x-1}[/tex]

Equating the denominator equal to zero, the function becomes undefined at the point [tex]x=1[/tex]

Thus, the function h(x) has the domain of [tex]$(-\infty,-1) \cup(-1, \infty)$[/tex] is not the same domain as [tex]$(-\infty, 4) \cup(4, \infty)$[/tex]

Hence, Option B is not the correct answer.

Option C: [tex]h(x)=\frac{11}{x-4}[/tex]

Equating the denominator equal to zero, the function becomes undefined at the point [tex]x=4[/tex]

Thus, the function h(x) has the domain of [tex]$(-\infty, 4) \cup(4, \infty)$[/tex] is the same domain as [tex]$(-\infty, 4) \cup(4, \infty)$[/tex]

Hence, Option C is the correct answer.

Option D: [tex]h(x)=\frac{11}{x-3}[/tex]

Equating the denominator equal to zero, the function becomes undefined at the point [tex]x=3[/tex]

Thus, the function h(x) has the domain of [tex]$(-\infty,3) \cup(3, \infty)$[/tex] is not the same domain as [tex]$(-\infty, 4) \cup(4, \infty)$[/tex]

Hence, Option D is not the correct answer.

Answer:

It’s C

Step-by-step explanation:

Answer:

6/10,9/15,12/20,15/25

Step-by-step explanation:

(a) The simplified expression is [tex]\[-0.49 \cdot |x|^{18.5} \cdot i\][/tex]. (b) The simplified expression remains [tex]\[15\sqrt{x} + 0.16c^{12}\][/tex].

Let's simplify the given expressions step-by-step.

a) Simplify [tex]\(\sqrt{x} \cdot 0.49x^{18}\) for \(x < 0\)[/tex]

Since [tex]\(x < 0\), \(x\)[/tex] is negative. This affects the interpretation of [tex]\(\sqrt{x}\)[/tex] in the real numbers because the square root of a negative number is not real. However, if we consider complex numbers, we need to include the imaginary unit [tex]\(i\).[/tex]

Given:

[tex]\[\sqrt{x} \cdot 0.49x^{18}\][/tex]

First, let's express [tex]\(\sqrt{x}\)[/tex] in terms of the imaginary unit:

[tex]\[\sqrt{x} = \sqrt{|x|} \cdot i\][/tex]

Next, rewrite \(x^{18}\):

[tex]\[x^{18} = (x^2)^9 \\= |x|^{18} \cdot (-1)^9 \\= -|x|^{18}\][/tex]

Thus, the expression becomes:

[tex]\[\sqrt{|x|} \cdot i \cdot 0.49 \cdot -|x|^{18}\][/tex]

Simplify the coefficients and combine terms:

[tex]\[0.49 \cdot -1 = -0.49\\\sqrt{|x|} \cdot |x|^{18} = |x|^{\frac{1}{2}} \cdot |x|^{18} = |x|^{18.5}\][/tex]

Therefore, the simplified expression is:

[tex]\[-0.49 \cdot |x|^{18.5} \cdot i\][/tex]

b) Simplify [tex]\(15\sqrt{x} + 0.16c^{12}\)[/tex]

Here, [tex]\(x\) and \(c\)[/tex] can be anything.

Given:

[tex]\[15\sqrt{x} + 0.16c^{12}\][/tex]

There are no common factors to combine these terms, so the expression is already simplified. The terms involve different variables and exponents, and cannot be further simplified together.

So the simplified expression remains [tex]\[15\sqrt{x} + 0.16c^{12}\][/tex]

a) The simplified expression is [tex]\[-0.49 \cdot |x|^{18.5} \cdot i\].[/tex]

b) The expression remains as usual given in the question:

[tex]\[15\sqrt{x} + 0.16c^{12}\][/tex]

C(2,-3)

That is your answer

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My answer might be wrong

Answer:

Credit Card

Step-by-step explanation:

This is most likely a credit card.

You only need to put a special code in when you're inputting a credit cards pin number.

it is c my dudes yes hes yes

Answer:

936

Step-by-step explanation:

1 x 12 x 13 x 6= 936

Here is some evidence

Answer:36

Step-by-step explanation: L•w/2 = A for triangular

Answer:

The length of the rectangle is 70 cm

The width of the rectangle is 32 cm

Step-by-step explanation:

Given:

perimeter of the rectangle  =   204 feet

Its length is six feet longer that twice its width

To Find:

The  dimensions of the rectangle = ?

Solution:

Let the width of the rectangle be x

Then its length  is six feet longer that twice its width.

That is length  = 6 + 2x

Now we know that the perimeter of the rectangle is

perimeter =  2(length + width)

204 = 2(6+2x+x)

204 = 2(6+3x)

204 = 12 +6x

204 - 12 = 6x

192 =  6x

x =[tex]\frac{192}{6}[/tex]

x = 32

Thus the width is 32 cm

Its length is  

=6 + 2x

=6 + 2(32)

=6 + 64

= 70 cm

Answer:

It would be 97.50 square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

75.9 yodels = 1 deckle.

7400 yodels² = [tex]7400\div 75.9[/tex]

                       = [tex]97.50\ deckels ^2.[/tex]

Therefore, it would be 97.50 square deckles.

The area is approximately 1.286 deckles².

To convert the area from square yodels to square deckles, we need to use the given conversion factor: 1 deckle = 75.9 yodels.

First, we'll find out how many yodels one square deckle is by squaring the conversion factor.

1. Calculate the area of one square deckle in yodels: (75.9 yodels)² = 5752.81 yodels².

2. Convert the given area of the sports area from yodels² to deckles²: 7400 yodels² ÷ 5752.81 yodels²/deckle² ≈ 1.286 deckles².

Therefore, the sports area covering 7400 yodels² is approximately 1.286 square deckles.

Answer:

0.5 50/100 0.50

Step-by-step explanation:

Answer:

225

Step-by-step explanation:

Total number of students =300

75% have had algebra

Number of students that have had algebra will be

= 75%/100% x 300

= 0.75 x 300

= 225

So, 225 of the 300 students have had algebra

Answer:225 students

There are 2 simple ways to get the answer.

The probability of drawing two black balls from a bag containing 5 white and 5 black balls is 2/9 (approximately 0.22) if you do not replace balls after drawing them, and 1 if you replace any white balls that are drawn.

This question relates to the concept of probability in mathematics. The total number of balls in your bag is 10 (5 white balls and 5 black balls). If you want to draw two black balls, the probability will change based on the conditions of the question.

a) For the first draw, there are 5 black balls out of a total of 10 balls, so the probability is 5/10 or 0.5. If a black ball is drawn in the first draw, there are now 9 total balls and 4 of them are black, so the probability for the second black ball is 4/9. For both balls to be black, multiply the individual probabilities: (5/10) * (4/9) = 20/90 = 2/9 approximately equal to 0.22.

b) If you draw two balls and put back any white balls, then redraw until you have two balls, you are essentially ensuring that white balls are not counted. In this case, every draw will either be a black ball or a redraw with a white ball, so the probability is essentially 1 that you will eventually draw a black ball. Therefore, the probability of drawing two black balls using this method is (1/1) * (1/1) = 1.

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Answer:

x = 12

Step-by-step explanation:

Answer:

N

Step-by-step explanation:

The height of the liquid in the new cylinder is about 1.72 cm

Step-by-step explanation:

The formula of the volume of a cylinder is V = πr²h, where

∵ The volume of the liquid = 36 cm³

∵ The liquid is poured into another cylinder with radius 3 cm

∵ The radius of the base = 3 cm

- To find the height of the liquid in the new cylinder equate the rule

   of the volume by 36

∵ V = πr²h

∴ π(3)²h = 36

∴ 9πh = 36

- Divide both sides by 9π

∴ h = 1.273239545

The height of the liquid in the new cylinder is about 1.72 cm

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Answer:

If you can't afford a new laptop computer, then you haven't got 400$.

Step-by-step explanation:

The contrapositive is:

If A implies B then not B implies not A.

Answer:

81.9 hours.

Step-by-step explanation:

5 work sites take   31.5 hours to prepare, so

1   work sites take   31.5 / 5 hours to prepare, and

13  work sites take .  (31.5  * 13) / 5  hours to prepare

=  409.5 / 5

=  81.9 hours.

Answer: Yes it is

Step-by-step explanation: In mathematics, a function is a relation between sets that associates to every element of a first set exactly one element of the second set

Answer:  

yes

hope this helps

Answer:

B

Step-by-step explanation:

The opposite of negative one half is the one half and the opposite of 5/2 is -5/2, or -2.5

Check the picture below.

Answer:

If you mean Area=2 and Area=36units times 2 and Area=64units times 2, then the answer is that A = 64units times 2 would be the largest square.

Step-by-step explanation:

The larger the area, the larger the square. The first square has an area of 2. The second square has an area of 72, and the third square has an area of 128, so the third square is the biggest.

Rate of change of the function: 60

Step-by-step explanation:

The exponential function in this problem is

[tex]f(x)=2^{x+3}[/tex]

The rate of change of a function between a certain interval [tex]x_1 \leq x \leq x_2[/tex] is given by

[tex]r=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

where

[tex]f(x_1)[/tex] is the value of the function calculated in [tex]x_1[/tex]

[tex]f(x_2)[/tex] is the value of the function calculated in [tex]x_2[/tex]

In this problem, the interval is

[tex]1\leq x \leq 5[/tex]

So we have:

[tex]f(x_1)=f(1)=2^{1+3}=2^4=16[/tex]

and

[tex]f(x_2)=f(5)=2^{5+3}=256[/tex]

Therefore, the rate of change is:

[tex]r=\frac{256-16}{5-1}=60[/tex]

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Answer:

Step-by-step explanation:

Supplementary: ADC

Complementary: AC

Adjacent: ABC

Hope this helps.

Distributive property: 5y-3y-6

Combine like terms: 2y-6

So there's your answer

To simplify the given expression, distribute the -3 to both terms inside the parentheses, then combine like terms.

To simplify the expression 5y - 3(y + 2), we need to follow the order of operations, which is parentheses first, then multiplication and division, and finally addition and subtraction.

First, distribute the -3 to both terms inside the parentheses:

5y - 3 * y - 3 * 2

Now, simplify each term:

5y - 3y - 6

Combine like terms:

2y - 6

This is the simplified form of the given expression.

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Answer:

Step-by-step explanation: combine like terms 7y minus 2y is 5y then combine 3 plus 6 which is 9 then u get 3x+5y+9