Alcohols are organic compounds that contain a. carbon and oxygen only. c. carbon, oxygen, and hydrogen. b. carbon and hydrogen only. d. carbon, nitrogen, and hydrogen.

A Solar power engineer is most likely to work with renewable energy sources, specifically solar energy, which is a key focus for sustainable development in the energy sector.

The type of engineer who would most likely work with a renewable energy source is a C. Solar power engineer. A solar power engineer specializes in working with systems designed to harness the sun's energy, which is an abundant renewable resource. Mentioned in the given information, solar energy physics involves the study and improvement of technologies for converting sunlight into electrical energy. Harnessing solar energy helps sustain our energy needs without the pollution caused by burning fossil fuels like coal or the use of non-renewable sources such as petroleum. As we prioritize renewables amid climate concerns, solar power engineers and solar energy physicists are integral to the field of renewable energy development.

The type of engineer most likely to work with renewable energy is a Solar power engineer, as they specialize in solar energy conversion technologies to harness solar power, a key renewable resource.

Which type of engineer would most likely work with a renewable energy source? Among the options provided, a Solar power engineer (Option C) is directly associated with renewable energy, specifically involving the technology of solar energy conversion. Solar power engineers focus on designing, developing, and managing solar energy systems to harness the power of the sun and convert it into electricity or heat. Their work is crucial for the advancement and implementation of solar technology, which plays a significant role in the shift towards more sustainable and renewable energy sources.

Furthermore, according to the U.S. Department of Energy, Earth receives enough sunlight each hour to power the entire globe for a year. While converting all of this energy is not possible currently, the role of solar energy physicists and engineers includes exploring and improving upon solar energy conversion technologies to harness more of this abundant resource.

The need for energy and the direction towards renewable sources is creating demand for engineers specialized in alternatives to traditional fossil fuels, such as those focused on solar power. Engineers such as Geophysical engineers and Water resources engineers may work with renewable sources like geothermal and hydropower respectively, but the correct answer for the question, which specifies a renewable energy source, would be Solar power engineer.

1) Magnitude

Let's take south as positive y-direction and east as positive x-direction. Then we have to resolve both displacements into their respective components:

[tex]d_{1x} = -(3.5 km) cos 55^{\circ}=-2.0 km[/tex]

[tex]d_{1y} = (3.5 km) sin 55^{\circ}=2.87 km[/tex]

[tex]d_{2x} = (2.7 km) sin 16^{\circ}=0.74 km[/tex]

[tex]d_{2y} = (2.7 km) cos 16^{\circ}=2.60 km[/tex]

So, the components of the total displacement are

[tex]d_x = d_{1x}+d_{2x}=-2.0 km +0.74 km=-1.26 km[/tex] east (so, 1.26 km west)

[tex]d_y=d_{1y}+d_{2y}=2.87 km + 2.60 km=5.47 km[/tex] south

So, the magnitude of the resultant displacement is

[tex]d=\sqrt{d_x^2+d_y^2}=\sqrt{(1.26)^2+(5.47)^2}=5.61 km[/tex]

2) Direction

the direction of the hiker's displacement is

[tex]\theta= arctan(\frac{d_y}{d_x})=arctan(\frac{5.47}{1.26})=arctan(4.34)=77.0^{\circ}[/tex] south of west.

The magnitude of the hiker's resultant displacement is 5.8 km south of west.

To find the magnitude of the hiker's resultant displacement, we need to first find the x and y components of the displacement vectors.

Path 1, the hiker walks 3.5 km in a direction of 55° south of west. The x component of this displacement is -3.5 * cos(55°) = -2.503 km, and the y component is -3.5 * sin(55°) = -2.845 km.

Path 2, the hiker walks 2.7 km in a direction of 16° east of south. The x component of this displacement is 2.7 * sin(16°) = 0.732 km, and the y component is -2.7 * cos(16°) = -2.606 km.

The total x component is -2.503 + 0.732 = -1.771 km, and the total y component is -2.845 - 2.606 = -5.451 km. Using the Pythagorean theorem, the magnitude of the resultant displacement is sqrt((-1.771)^2 + (-5.451)^2) = 5.797 km.

The direction can be found using the inverse tangent function, atan((-5.451)/(-1.771)) = 73°. Since the displacement is south of west, the direction is 180 - 73 = 107° south of west.

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IT IS 0.7 THANK YOU. Also if your not sure if your answer is right or not don't put it down cause other people look at it and enter it and get a bad grade cause of your selfish ahh. Thank you

Answer:

B: Fnety = (FT)(sin 32°) – Fg

Explanation:

Since the two trains are passing in opposite directions, so this means that their relative velocities will be the sum of the two trains that is: 

relative velocity = (13 + 28) = 41m/s

a. The passengers aboard on train B will see that train A is moving at 41m/sec due east

b. The passengers aboard on train A will see that train B is moving at 41m/sec due west

Answer:

B and C

Explanation:

The cables holding the traffic lights cannot be exactly horizontal due to Newton's Second Law. An upward component of tension is required to balance the weight of the traffic light, preventing a completely horizontal placement.

Your objective to have the cables exactly horizontal is unfortunately not feasible due to the principles of physics, specifically Newton's Second Law. According to Newton's second law, there has to be an upward component of tension in the cable that counterbalances the weight of the traffic light. This means that the cable can't be placed horizontally as some part of the tension must always act vertically to balance the gravity acting on the traffic light. If we tried to set the cable perfectly horizontally, without the upward component of tension, the traffic light would not hold in place and would fall due to gravity.

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The power must a motor generate to transport the man and chair is  1300 W.

If an object is lifted, work is done against gravitational force. The object gains energy.

The equation for calculating gravitational potential energy is

GPE =mgh

where, GPE is the gravitational potential energy, m is the mass, h is the change in height and g is the acceleration due to gravity.

Given is the mass of chair =200kg and mass of man =60 kg, then the total mass to be lifted is

m = 200 +60 = 260 kg.

height to be raised h =5m and time taken t  = 10s.

GPE = 260 x 10 x 5

GPE = 13000 J

Power to be generated P = GPE/t

Put the values, we get

P = 13000 / 10 = 1300 W

Thus, the power must be generated is 1300W.

Learn more about gravitational potential energy.

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The shell dropped by the seagull is moving at a speed of approximately 14 m/s when it hits the rocks. This is calculated through the conversion of potential energy to kinetic energy, using the relevant physics formula.

Based on the principles of kinetic and potential energy transformation in Physics, we can estimate the speed at which the shell will hit the rocks. When the seagull drops the shell, it initially has potential energy which is converted into kinetic energy as it falls under the gravity. This can be calculated using the equation v² = 2gy, where v indicates the final velocity, g is the acceleration due to gravity approximated as 9.8 m/s² and y is the height from which the object is dropped.

Replacing the known values: v² = 2*9.8m/s²*10m. Therefore, v = √(2*9.8m/s²*10m). This calculation results with a final velocity of about 14 m/s. This means the shell is moving at a speed of 14 m/s when it hits the rocks.

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The  [tex]{{\text{K}}_{\text{a}}}[/tex] of bromocresol purple is [tex]\boxed{{\text{0}}{\text{.000001}}}[/tex].

Further explanation:

Indicator:

An indicator is any substance that indicates the presence or absence of a chemical species such as an acid or an alkali in the solution, usually by a color change. Methyl orange, methyl yellow, thymol blue, bromocresol purple are some examples of indicators.

Bromocresol purple (BCP) is an example of pH indicator and is a dye of the triphenylmethane family. It is also known as 5’, 5”-dibromo-o-cresolsulfophthalein. It is yellow below pH 5.2 and its color becomes violet above pH 6.8.

pH:

The acidic strength of an acid can be determined by pH value. The negative logarithm of hydronium ion concentration is defined as pH of the solution. Lower the pH value of an acid, the stronger will be the acid. Acidic solutions are likely to have pH less than 7. Basic or alkaline solutions have pH more than 7. Neutral solutions have pH equal to 7.

The formula to calculate pH of an acid is as follows:

[tex]{\text{pH}}=-{\text{log}}\left[{{{\text{H}}^ + }}\right][/tex]                                                              …… (1)

Here,

[tex]\left[{{{\text{H}}^ + }}\right][/tex] is hydrogen ion concentration.

The general dissociation reaction of BCP is as follows:

 [tex]{\text{HBCP}}\rightleftharpoons{{\text{H}}^ + }+{\text{BC}}{{\text{P}}^ - }[/tex]

Here,

HBCP is the indicator in undissociated form.

[tex]{{\text{H}}^ + }[/tex] is hydrogen ion.

[tex]{\text{BC}}{{\text{P}}^ - }[/tex] is the indicator in ionized form.

The formula to calculate the equilibrium constant of HBCP is as follows:

[tex]{{\text{K}}_{\text{a}}}=\dfrac{{\left[ {{{\text{H}}^ + }}\right]\left[ {{\text{BC}}{{\text{P}}^ - }} \right]}}{{\left[{{\text{HBCP}}}\right]}}[/tex]      ...... (2)

Here,

 [tex]{{\text{K}}_{\text{a}}}[/tex]is the dissociation constant of HBCP.

 [HBCP] is the concentration of undissociated bromocresol purple.

 [tex]\left[ {{{\text{H}}^ + }}\right][/tex] is hydrogen ion concentration.

 [tex]\left[{{\text{BC}}{{\text{P}}^ - }}\right][/tex] is the concentration of dissociated bromocresol purple.

Rearrange equation (1) to calculate [tex]\left[ {{{\text{H}}^ + }}\right][/tex] .

[tex]\left[ {{{\text{H}}^ + }}\right]={10^{ - {\text{pH}}}}[/tex]       ...... (3)                                                                     …… (3)

Bromocresol purple is an indicator whose pH ranges from 5.2 to 6.8. So its mid pH can be calculated as follows:

[tex]\begin{aligned}{\text{pH}}&=\dfrac{{5.2 + 6.8}}{2}\\&=\frac{{12}}{2}\\&=6\\\end{aligned}[/tex]

So the pH of BCP is 6.

Substitute 6 for pH in equation (3).

[tex]\begin{aligned}\left[ {{{\text{H}}^ + }}\right]&={10^{ - 6}}\\&=0.000001\;{\text{M}}\\\end{aligned}[/tex]

At the endpoint,  [HBCP] becomes equal to [tex]\left[{{\text{BC}}{{\text{P}}^ - }}\right][/tex] . So equation (2) becomes,

[tex]{{\text{K}}_{\text{a}}}=\left[ {{{\text{H}}^ + }}\right][/tex]                                      …… (4)

Substitute 0.000001 M for [tex]\left[{{{\text{H}}^ + }}\right][/tex] in equation (4).

 [tex]{{\text{K}}_{\text{a}}}=0.000001[/tex]

So the value of [tex]{{\mathbf{K}}_{\mathbf{a}}}[/tex]  for bromocresol purple is 0.000001.

Learn more:

1. Which indicator would be the best for the given titration? https://brainly.com/question/9236274

2. Example of physical change: https://brainly.com/question/1119909

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mixture

Keywords: pH, ka, indicator, BCP, bromocresol purple, H+, 0.000001, 0.000001 M, 6, 5.2, 6.8, dissociation constant, undissociated, dissociated.

Answer:

Explanation:

D

Answer:

The horizontal component of a projectile's acceleration is zero

Explanation:

When calculating all the different components of a projectile (acceleration, initial velocity, final velocity, etc.), you need to break it up into its X and Y directions.

During free fall, the only force acting on the projectile is gravity, and since gravity acts down (in the Y direction), there is no force acting in the X direction. Hence, the acceleration in the X direction is zero.

The distance from the center of the earth that you will get, given that you leave the surface of the earth with a velocity of 5534 m/s, is [tex]6.5099\times10^6\ m[/tex]

How to calculate the distance from the earth you will get to?

The distance from the center of the earth that you will get, knowing that you leave the surface of the earth with a velocity of 5534 m/s can be calculated as shown below:

[tex]d = \frac{GM}{2v^2} \\\\d = \frac{6.67428\times10^{-11}\ \times\ 5.9742\times10^{24}}{2\ \times\ 5534^2} \\\\d = 6.5099\times10^6\ m[/tex]

From the above calculation, we can conclude that the distance you will get is [tex]6.5099\times10^6\ m[/tex]

Jumping, throwing, and weight lifting Olympic events would be drastically altered by the Moon's lower gravity in a hypothetical lunar Olympics. Athletes could jump higher and throw further due to gravity being 1/6th of earth's. Similarly, weights would feel lighter during weight lifting.

In the context of the lunar olympics, it's critical to understand how the Moon's lower gravity would drastically impact certain sports events. The Moon's gravity is about 1/6th of Earth's gravity, which would significantly influence events involving lifting, jumping and throwing.

Jumping events would drastically change because the lower gravity would allow participants to jump about six times higher than on Earth. Throwing events would also see remarkable enhancements as objects would travel a greater distance before dropping.

Moreover, Weight lifting would be greatly impacted as the same weights would feel much lighter on the Moon. Interestingly, sports such as bicycling, swimming on a level track, and running races on a level track would not be significantly affected because these activities are less dependent on gravity relative to the others mentioned. Nonetheless, athletes might perform differently due to the reduced atmospheric pressure and possible difficulties in maintaining balance because of lower gravity.

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Final answer:

The lunar olympics would see drastic changes in events such as jumping, throwing, and weight lifting due to the Moon's 1/6th Earth gravity, while bicycling would be less affected. Swimming would also change, but it assumes the presence of water in a lunar environment.

Explanation:

The "lunar olympics" concept highlights how sports would be drastically affected by the Moon's reduced gravity. Given that gravity on the Moon is about 1/6th of that on Earth, events such as jumping, throwing things, and weight lifting would be greatly altered. With lower gravity, athletes could jump much higher, throw objects much farther, and lift heavier weights with less effort, compared to Earth. Running races might see a difference in athletes' strides and suspension period off the ground, potentially leading to faster times. However, activities like bicycling would be less affected as they rely more on the rider's strength and endurance than on gravitational forces. Swimming is not practical without substantial water, which is currently not present on the Moon, but if somehow managed in a dome, the reduced gravity could affect water dynamics and a swimmer's buoyancy, thereby affecting the execution of strokes and turns.

Regarding the equation C₂H₄ + O₂ ⇒ 2 H₂O + 2 CO₂, it is true that only the oxygen needs to be balanced. There are equal numbers of hydrogen and carbon.

According to the law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Thus, equations need to be balanced so the same number of atoms are on both sides.

How does the law of conservation of mass apply to this reaction:

C₂H₄ + O₂ ⇒ 2 H₂O + 2 CO₂?

Regarding the equation C₂H₄ + O₂ ⇒ 2 H₂O + 2 CO₂, it is true that only the oxygen needs to be balanced. There are equal numbers of hydrogen and carbon.

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Answer: the answer is The law of conservation of mass has already been applied. There is an equal number of each element on both sides of the equation.

Explanation: i hope this helps:)

the answer should be:

When the buoyant force is equal to the force of gravity

The mass of the bicycle rim, given the moment of inertia and the diameter, is calculated using the formula m = 2I/R². The resulting mass is approximately 4.71 kg.

The moment of inertia (I) of a cylinder rotating about its central axis is given by this formula: I = 1/2 mR², where m is mass and R is radius (which is half of the diameter).

For this problem, we have I = 0.25 kg⋅m² (moment of inertia) and R = 0.325 m (because the diameter is 0.65 m so the radius would be 0.325 m), so we can rearrange the formula to solve for m (mass): m = 2I/R².

Plug in the given values and calculate the mass: m = 2×0.25 kg⋅m² / (0.325 m)² = 4.71 kg. So, the mass of the rim is approximately 4.71 kg.

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he speed of the student relative to shore is

v_ up = v- vs

v _down = v+ vs

The time required to travel distance d upstream
is

t_up = d/ v_up = d/ v- vs

(2)

The time required to swim the same distance d downstream is

t_down = d/ v_down = d/ v+ vs

D)To move in a circle requires an acceleration and therefore a net force. This force is supplied by the slingshot.