Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first. alice reaches the surface of the lake first. alice and tom will reach the surface of the lake at the same time.

Answers

Answer 1

Alice and Tom reach the lake simultaneously due to gravity's independence from their initial horizontal velocities. The correct answer is (E).

Let us consider the concept of horizontal motion and vertical motion of a projectile (in this case, Alice and Tom) are independent of each other when there is no air resistance.

This means that the horizontal velocity does not affect the vertical motion.

Both Alice and Tom are subject to the same gravitational acceleration, and since they are both falling vertically, they will reach the surface of the lake at the same time.

So, the correct answer is (E). Alice and Tom will reach the surface of the lake at the same time.

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Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below.

(A) alice and tom dive from an overhang into the lake below.

(B) tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s.

(c) neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first.

(D) alice reaches the surface of the lake first.
(E) alice and tom will reach the surface of the lake at the same time.

Answer 2

Both Alice and Tom will reach the surface of the lake at the same time because their times to hit the water depend only on the vertical distance and gravitational acceleration.

Alice and Tom both dive from the same overhang into a lake below.

Although Alice takes a running start and has an initial horizontal velocity of 25 m/s, the time it takes both of them to reach the lake is the same. This is because the vertical motion for both divers is under uniform acceleration due to gravity, which is not affected by their horizontal velocities.The time it takes to reach the surface is dictated by the height of the overhang and gravity alone.

Both Alice and Tom experience the same vertical acceleration and fall the same vertical distance, hence, they will both reach the surface of the lake at the same time.

Determine the vertical motion of each diver, which is independent of horizontal motion.Use the kinematic equation for vertical motion: h = 1/2 * g * t².Since both Alice and Tom start from the same height and are only influenced by gravity (9.8 m/s²), their times to hit the water are the same.

Related Questions

A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km away. The tractor beam exerts a constant force of 4.0 ✕104 N on the shuttlecraft. Both spacecraft are initially at rest. How far does the starship move as it pulls the shuttlecraft aboard?

Answers

Refer to the diagram shown below.

m₁ = 8.5 x 10⁶ kg, the mass of the starship
m₂ = 10⁴ kg, the mass of the shuttlecraft
a₁ =  the acceleration of the starship
a₂ = the acceleration of the shuttle
F = 4 x 10⁴ N, the pulling force

Let y =  distance traveled by the starship
Let x =  distance traveled by the shuttlecraft
If t =  the time of travel, then
y = 0.5a₁t²                  (1)
x = 0.5a₂t²                  (2)

F = m₁a₁ = m₂a₂         (3)
Also,
x + y = 14000 m          (4)

From (2), obtain
a₁ = (4 x 10⁴ N)/(8.5 x 10⁶ kg) = 4.706 x 10⁻³ m/s²
a₂ = (4 x 10⁴ N)/(10⁴ kg) = 4 m/s²

From (1), (2) and (4), obtain
0.5*(t s)²*(4 + 4.706 x 10⁻³ m/s²) = 14000 m
2.002353t² = 14000
t² = 6991.774 s²
t = 83.617 s

Therefore
x = 0.5*4*6991.774 = 13984 m = 13.984 km
y = 0.5*4.706 x 10⁻³*6991.774 = 16.452 m

The starship moves only about 16.5 m while pulling in the shuttlecraft by 13.98 km.

Answer: The starship moves by 16.5 m (nearest tenth)
Final answer:

By applying conservation of momentum and kinematic equations, we find the distance the starship moves as a result of exerting a force on the shuttlecraft via a tractor beam. The steps involve calculating the acceleration of the shuttlecraft, determining the time to cover the initial distance, and then using the momentum relation to find the velocity and distance moved by the starship.

Explanation:

The question involves applying the concept of conservation of momentum to find out how far the starship moves as it pulls a shuttlecraft on board. Since both spacecraft are initially at rest and the force is exerted for the same amount of time on both, their momenta are equal and opposite. We can set up the equation based on conservation of momentum:

m1⋅v1 = m2⋅v2

Where m1 and v1 are the mass and velocity of the starship, and m2 and v2 are the mass and velocity of the shuttlecraft, respectively. Because the tractor beam exerts a constant force, we can calculate the acceleration of the shuttlecraft (a = F/m), and then using the kinematic equation, determine the time (t) it takes for the shuttle to cover the distance:



s = 0.5⋅a⋅t^2



With t known, we can calculate the velocity of the shuttlecraft (v2) at the moment it reaches the starship:



v2 = a⋅t



Using the velocities and rearranging the conservation of momentum equation, we find:



m1⋅v1 = m2⋅(a⋅t)



Finally, we solve for the distance the starship moves (d1) using the velocity we found for v1, and the time:



d1 = 0.5⋅(v1⋅t)



This provides the answer to how far the starship moves as a result of pulling in the shuttlecraft with its tractor beam.

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What radius should the satellite move at in its orbit? (measured frrom the center of mars.)?

Answers

R = GM/V² = 7.178E6 m
Final answer:

To determine the radius at which a satellite should move in its orbit around Mars, you can use Newton's Law of Universal Gravitation and the centripetal force equation. By setting the gravitational force equal to the centripetal force, you can solve for the radius of the orbit.

Explanation:

The radius at which a satellite should move in its orbit around Mars can be determined using Newton's Law of Universal Gravitation and the centripetal force equation. The centripetal force required for the satellite to stay in orbit is provided by the gravitational force between the satellite and Mars. To find the radius, you can set the gravitational force equal to the centripetal force and solve for the radius.

Step-by-step:

Identify the known quantities: the mass of Mars (M), the radius of Mars (r), and the period of the satellite's orbit (T).Use the centripetal force equation: Fc = (mv2)/r, where Fc is the centripetal force, m is the mass of the satellite, v is the satellite's velocity, and r is the radius of the orbit.Use Newton's Law of Universal Gravitation: Fg = (GMm)/r2, where Fg is the gravitational force between the satellite and Mars, G is the gravitational constant, and M is the mass of Mars.Set the centripetal force equal to the gravitational force: (mv2)/r = (GMm)/r2.Cancel out the common factors: v2/r = (GM)/r2.Solve for r: v2 = GM/r.Substitute the known values and solve for r: r = (GM/v2).

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An airplane went from 120 m/s to 180 m/s in 4.0 seconds. What was its acceleration?

Answers

15 m/s^2 The first thing to calculate is the difference between the final and initial velocities. So 180 m/s - 120 m/s = 60 m/s So the plane changed velocity by a total of 60 m/s. Now divide that change in velocity by the amount of time taken to cause that change in velocity, giving 60 m/s / 4.0 s = 15.0 m/s^2 Since you only have 2 significaant figures, round the result to 2 significant figures giving 15 m/s^2

85) List and discuss the structures of a long bone. 86) Discuss the organization of the five regions of the spine. 87) Explain how atlas and axis are different from other vertebrae. Discuss the roles they play in the body. 88) Differentiate among the three types of joints based on structural and functional classification. Provide examples of each type of joint.

Answers

85)
The bone structure from outside would be periosteum, cortical, cancellous then medulla. Periosteum is the area outside the bone that will supply nutrition into the outer part of the bone. Cortical is the layer where bone mineral deposition is intense. In this part, the bone is compact and hard. This is the part of the bone that has great strength.
Cancellous is part of the bone where it is not too hard but not too soft. Mineralization is not so dense like cortical layer. That makes this part looks spongy. 
In the medulla, most part is made from connective tissue and blood vessels. This part is responsible for the bone vascularization, which means the supply of mineral to the outer part is coming from the medulla. Mineralization is not much in the medulla, makes it not strong. Medulla or marrow also makes blood cells.

86)
The region of the spine would be cervical(neck), thoracal(chest), lumbar(back), sacrum then coccyx. The vertebrae in the neck are smaller since it did not need much strength but need more mobility. Lower part on the thoracal and lumbar is bigger and have a bigger process that will further stabilize the vertebrae. Thoracal vertebrae have a part on their side where the ribs attached. Sacrum shape was a kinda weird because it needs to be able to connect with the pelvis to make buttock. Coccyx the tailbone look like just a small remnant and doesn't seem to have a function in human.

87)
Axis is the name of cervical 2nd vertebral which was located below the atlas, 1st cervical vertebrae. Both of them doesn't have spinal processes that were stabilizing the side of vertebrae Axis also has an odontoid peg which will make the joint with atlas more flexible.
This effect makes the neck can turn to side easily. It also makes neck more mobile vertically, make a nodding movement is possible.
88)
Thre kind of joints would be: Synarthrosis, amphiarthrosis, and diarthrosis.
In synarthrosis, the joint mostly made by fibrous so that it can move. The example of this joint would be suture in the skull. In children, the skull joint is not closed to permit the head to grow but in the adult, it is closed. 
Amphiarthrosis joint permits a small movement. This included the intervertebral disc.
Diarthrosis permit a wide degree of movement. This joint is more complex because it has the synovial membrane. The complex structure makes the joints more durable to shock. This was vital because organ with this join used frequently. The example of this joints would be femur and pelvic(hip) joints. Joints in arm and leg mostly diarthrosis joint.

The gas tank of a certain luxury automobile holds 22.3 gallons according to the owner’s manual. if the density of gasoline is 0.8206 g/ml, determine the mass in kilograms and pounds of the fuel in a full tank.

Answers

The mass of the fuel in the tank can be calculated by multiplying the volume in full tank to the density of the gasoline. First convert 22.3 gallons to ml by multiplying it with 3785.412 since the conversion factor is 1 gallon= 3785.412 ml. Then multiply the volume with the density. Since the density is in g/ml, you would get a value in grams so convert it to kg by dividing it with 1000. The convert the value in kg to lb multiply the value by 2.2. The values are 69.27 kg and 152.72 lb. 

Final answer:

The mass of the fuel in a full 22.3-gallon tank of gasoline, given a density of 0.8206 g/mL, is approximately 69.211 kg or 152.497 lb.

Explanation:

To determine the mass of the fuel in a full tank, you first need to convert the volume from gallons to milliliters (mL), since the density of gasoline is given in grams per mL.

One gallon is approximately 3785.41 mL. Therefore, a 22.3-gallon tank would hold 22.3 * 3785.41 = 84392.263 mL of fuel.

The mass of the fuel can then be calculated using the formula density = mass/volume. Rearranging the formula gives mass = density * volume. By subbing in the values, we get mass = 0.8206 g/mL * 84392.263 mL = 69211.294528 g.

To convert the mass to kilograms, we divide by 1000 (since there are 1,000 grams in a kilo). This gives us approximately 69.211 kg.

To convert the mass to pounds, we multiply by 2.20462 (since there are 2.20462 pounds in a kilo). This gives us approximately 152.497 lb.

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did a reaction happen in the erlenmeyer flask? how can you tell?

Answers

cause i saw it and i know it

Final answer:

To determine if a reaction happened in an Erlenmeyer flask, you can observe indicators such as color change, formation of a precipitate, and gas evolution.

Explanation:

In order to determine if a reaction happened in the Erlenmeyer flask, you can observe several indicators:

Change in color: If the original reactants and the product have different colors, it suggests that a reaction took place.Formation of a precipitate: If a solid substance appears in the solution, it indicates the formation of a new compound.Gas evolution: If bubbles or a gas is produced, it signifies that a reaction occurred.

Additionally, other observations such as the release of energy (exothermic reaction) or absorption of energy (endothermic reaction) can provide further evidence of a reaction.

According to a newspaper account, a paratrooper survived a training jump from 1200 ft when his parachute failed to open but provided some air resistance by ï¬apping unopen in the wind. allegedly he hit the ground at 100 mi/h after falling 8 seconds. test the accuracy of this account.

Answers

Final answer:

Determining the plausibility of a paratrooper hitting the ground at 100 mi/h after an 8-second fall involves examining the concept of terminal velocity and the effects of air resistance on falling objects.

Explanation:

The question concerns a paratrooper's descent with a malfunctioning parachute and whether it's plausible for him to hit the ground at 100 mi/h after falling for 8 seconds. To test the accuracy of this account, we must look at the forces involved and the terminal velocity a parachutist can reach. For example, a skydiver with a mass of 75 kg can achieve a terminal velocity of about 350 km/h in a headfirst position, which corresponds to minimizing the area and therefore the drag. Transitioning to a spread-eagle position can decrease this velocity to about 200 km/h, increasing air resistance due to a larger cross-sectional area. However, after a parachute opens, the terminal velocity becomes much smaller. This means that if the parachute provided any air resistance, it's unlikely the paratrooper would be traveling at 100 mi/h (which is approximately 160 km/h) after just 8 seconds.

The paratrooper's reported fall seems plausible as the calculated average acceleration, considering air resistance, is 5.59 m/s².

A paratrooper is reported to have survived a fall from 1200 ft after his parachute failed to open. To verify this account, let's calculate the following:

1. Terminal Velocity Calculation

The paratrooper fell for 8 seconds and allegedly hit the ground at 100 mi/h.

First, convert the velocity and time:

Velocity, v = 100 mi/h = 44.7 m/s

Time, t = 8 s

2. Average Acceleration

We can use the equation of motion, v = u + at where:

u = initial velocity (0, since he started from rest)

v = final velocity (44.7 m/s)

a = acceleration

t = time (8 s)

Rearranging for acceleration, we get:

a = (v - u) / t = 44.7 m/s / 8 s = 5.59 m/s2

3. Free Fall and Air Resistance

In a vacuum, the paratrooper would fall under a gravitational acceleration of 9.8 m/s². Given our acceleration is 5.59 m/s², air resistance played a significant role, slowing his acceleration.

Conclusion

The report's accuracy seems plausible given the average acceleration calculated. However, other factors like the angle of impact and ground conditions would also have contributed to his survival.

Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates uniformly at a rate of 3.8 m/s2 for 4.6 seconds. It then continues at a constant speed for 9.2 seconds, before applying the brakes such that the car’s speed decreases uniformly coming to rest 257.71 meters from where it started. The yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop.
How fast is the blue car going 2.8 seconds after it starts?

Answers

First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used is

For constant acceleration:
a = v,final - v,initial /t

The solutions is as follows:

 a = v,final - v,initial /t
 3.8 = (v - 0)/2.8 s
 v = 10.64 m/s
 After 2.8 seconds, the speed of the blue car is 10.64 m/s.
Final answer:

The blue car accelerates at 3.8 m/s² from rest. After 2.8 seconds, its speed is calculated using the formula v = u + at. The car's speed at that moment is 10.64 m/s.

Explanation:

To determine how fast the blue car is going 2.8 seconds after it starts, we use the formula for final velocity in uniformly accelerated motion, which is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Here, the initial velocity u is 0 m/s since the car starts from rest, the acceleration a is given as 3.8 m/s2, and the time t is 2.8 seconds.

Plugging the values into the formula gives us:

v = 0 m/s + (3.8 m/s2)(2.8 s) = 10.64 m/s.

Thus, the blue car is traveling at a speed of 10.64 meters per second after 2.8 seconds from the start.

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A spelunker is surveying a cave. she follows a passage 170 m straight west, then 250 m in a direction 45â east of south, and then 280 m at 30â east of north. after a fourth unmeasured displacement, she finds herself back where she started.

Answers

im not sure but is the magnitude 160.8?

An infant's pulse rate is measured to be 127 ± 4 beats/min. what are the uncertainty and the percent uncertainty in this measurement?

Answers

The uncertainty in the measurement is ± 4 beats/min, and the percent uncertainty is approximately 3.15%.

The reported pulse rate for an infant is 127 ± 4 beats/min. Here,  "± 4 beats/min" refers to the degree of uncertainty of the measurement.

1. Uncertainty: The uncertainty of a measurement is the range of values ​​in which the true value is expected to fall. In this example the uncertainty is ± 4 beats/min.

2.Percent Uncertainty: Uncertainty as a percentage is calculated by multiplying the ratio of the uncertainty in the measured value by 100. Uncertainty is expressed as a fraction of the measured value.

Percent Uncertainty = (Uncertainty / Measured Value) × 100

Using the given values:

Uncertainty = ± 4 beats/min

Measured Value = 127 beats/min

Percent Uncertainty = (4 / 127) × 100 ≈ 3.15%

So, the uncertainty in the measurement is ± 4 beats/min, and the percent uncertainty is approximately 3.15%.

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Final answer:

The uncertainty in the infant's pulse rate measurement is ± 4 beats/min. To calculate the percent uncertainty, divide the uncertainty by the measured value (127 beats/min), giving a percent uncertainty of 3.15%.

Explanation:

The uncertainty in the infant's pulse rate is given as ± 4 beats/min. The percent uncertainty can be calculated by dividing the uncertainty by the measured value and then multiplying by 100 to get the answer in percent.

To calculate the percent uncertainty:

Divide the absolute uncertainty by the measured value: 4 beats/min ÷ 127 beats/min. Multiply the result by 100 to convert it to a percentage: (4 beats/min ÷ 127 beats/min) × 100.

Performing these calculations:

(4 ÷ 127) × 100 = 3.15%

Therefore, the percent uncertainty in the measurement of the infant's pulse rate is 3.15%.

What is the volume of a rock with a density of 3.00 g/cm3 and a mass of 600g?

Answers

The equation of D = m/V

Where D = density
m = mass
and V = volume

We are solving for V, so with the manipulation of variables we multiply V on both sides giving us 
V(D) = m 
now we divide D on both sides giving us
V = m/D 

We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3  or 200mL

a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
 
If you wish to change it to L, you'd have to convert. 

How do aerobic and anaerobic respiration compare?

Answers

anaerobic exercises do not need a lot of energy and no not make you short of breath, aerobic exercises make you short of breath and require more energy 

Alright well aerobic respiration is very efficient and produces a large amount of energy while in the other hand anaerobic respiration is not very efficient and produces a large amount of energy.

Well Hope this helps have a nice day :)

If for 1.00 inch there are 2.54 cm, then how many centimeters are in 4.00 ft

Answers

121.92 is the answer I believe

To convert 4.00 feet to centimeters, multiply 4.00 feet by 12 inches per foot to get inches, then multiply the result by 2.54 to convert inches to centimeters. The result is 121.92 centimeters.

To convert 4.00 feet to centimeters, you can use the conversion factors and the chain link method. First, you need to know the basic conversion factors, which are 2.54 cm in 1 inch and 12 inches in 1 foot. Using these conversions:

Convert feet to inches: 4.00 ft ×12 in/ft = 48.00 in

Then convert inches to centimeters: 48.00 in ×2.54 cm/in = 121.92 cm

Therefore, there are 121.92 centimeters in 4.00 feet.

Henry takes a boat ride for 15 minutes to reach his destination. If the boat was traveling at 6 meters/second, how far did the boat travel?

Answers

Do 6 * 60 * 15
The answer is 5,400
The boat traveled 5,400 meters or 5.4 km (3.355 mi)

Answer: The distance traveled by boat is 5400 meters.

Explanation:

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

[tex]\text{Spped of the boat}=\frac{\text{Distance traveled}}{\text{Time taken}}[/tex]

We are given:

Speed of the boat = 6 m/s

Time taken = 15 mins = 900 s     (Conversion factor:   1 min = 60 s)

Putting values in above equation, we get:

[tex]6m/s=\frac{\text{Distance traveled by boat}}{900s}\\\\\text{Distance traveled by boat}=(6m/s\times 900s)=5400m[/tex]

Hence, the distance traveled by boat is 5400 meters.

This igneous rock contains flattened pieces of pumice and small crystals of quartz and feldspar. what type of eruption probably formed this rock?

Answers

Final answer:

The igneous rock in question, characterized by the presence of flattened pumice and small quartz and feldspar crystals, was likely formed by an explosive volcanic eruption. This is evidenced by the extrusive nature of pumice and the rapid cooling inferred from the small crystal sizes.

Explanation:

The igneous rock described contains flattened pieces of pumice and small crystals of quartz and feldspar. The presence of pumice, which is a vesicular felsic igneous extrusive rock with a very low density such that it can float on water, indicates that the rock was formed during an explosive volcanic eruption. This type of eruption releases lava that cools very quickly on the surface of the Earth, trapping gases within the rock and creating the vesicles or holes that define pumice. Hence, the rock exhibits characteristics of an extrusive igneous rock.

Moreover, the small crystal sizes of quartz and feldspar suggest rapid cooling as well. Large crystals are typically indicative of slow cooling within the Earth's crust, a feature of intrusive igneous rocks like granite. Given these characteristics, it is evident that the rock formed from an explosive eruption, which would have caused the rapid cooling and trapping of gas that are evident in the presence of pumice.

An increase in wind speed will cause the temperature of a leaf to ______. assume all other parameters of the leaf environment remain unchanged.

Answers

decrease. as the temperature is effected by 1. air humidity 2. air movement 3. light and so on

state and explain guass law?

Answers

"Gauss's Law. The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. ,"  Source:    hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html

If you would like more info please look at the website. Im only in middle school, so I am sorry if this is not what you were looking for.....

Final answer:

Gauss's Law is a fundamental principle in Physics that relates the electric flux through a closed surface to the net electric charge enclosed by the surface. It states that the electric flux is proportional to the total charge enclosed by the surface divided by the permittivity of free space.

Explanation:

Gauss's Law is a fundamental principle in Physics that relates the electric flux through a closed surface to the net electric charge enclosed by the surface. It states that the electric flux is proportional to the total charge enclosed by the surface divided by the permittivity of free space. Mathematically, it can be written as:

Σi E⟀Ai = Γenclosed / ε0

Where Σi E⟀Ai is the sum of the dot products of the electric field and the area vectors of small surface elements, Γenclosed is the net electric charge enclosed by the surface, and ε0 is the permittivity of free space.

What volume of .2500 m cobalt iii chloride is required to react completely with 25 ml of .0315 m calcium hydroxide?

Answers

f 0.0315 M calcium hydroxide?Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react

could you mark as brailiest

What is the earth's average velocity for one year?

Answers

The Earth's average velocity relative to the Sun as measured during a tropical year, which is the time measured between two consecutive March equinoxes, is 2.988589 x 10^4 m/s.

Light from the sun reaches earth in about 8.3 minutes the speed of light is 3.00×10^8 m/s what is the distance from the sun to earth?

Answers

Set up a unit conversion problem, arrange units to convert minutes to seconds, then cancel all time units.

8.3 minutes x (60 seconds/1 minute) x ( 3.00x10^8 meters/1 second) = 149,400,000,000 meters

Since the time is the term with the fewest number of significant figures (2), your answer should only be expressed with two sig figs as well.

1.5x10^11 m

Your skeleton. It is there for support, protection, and movement. But you could not move your bones without the help of your ______________ system. A) digestive B) gland C) immune D) muscular\

Answers

I believe the answer is D.) the muscular system
The answer would be 
D) muscular

What is the weight in newtons of an object that has a mass of 610 mg?

Answers

To answer this question, you need to know the gravity power used for this equation. Let assume the gravity is 9.8N/kg. Then to find the mass, you need to multiply the weight with gravitational acceleration. The equation would be:

mass= weight x gravity
mass= 610mg x 10^-6 kg/mg x 9.8N/kg= 5978 x 10^-6= 5.978 x 10^-3

When the space shuttle coasts in a circular orbit at constant speed about the earth, is it accelerating? if so, in what direction?

Answers

Yes. Acceleration means any change in speed or direction of motion. When an object coasts in a circular orbit at constant speed around the Earth, its direction is constantly changing. The acceleration is "CENTRIPETAL", which points toward the center of the circle.

Yes, there is centripetal acceleration, whose direction is radially inwards, towards the center of the Earth.

How to get the acceleration?

Remember that if an object is not accelerating, then it will remain at rest or will move with a constant velocity. Remember that velocity is defined by a magnitude (the speed) and a direction.

Now, in the case of a circular orbit, the speed is constant, but the direction of motion is not, so the velocity is not constant. So yes, we have acceleration.

That acceleration is called centripetal acceleration, and always appears when we have circular motion, is an acceleration that points inwards, to the center of the circle.

So in the case of the space shuttle that orbits Earth, the acceleration's direction would be radially inwards, towards the center of the Earth.

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The value of the electrical charge on particles is never a whole number true or false

Answers

The value of the electrical charge on particles is never a whole number true or false - TRUE

The cable is drawn into the motor with an acceleration of 7 m/s2 determine the time needed for the load at b to attain a speed of 10 m/s, starting from rest.

Answers

Final answer:

Using the basic equation of motion v = u + at, and considering the load starts from rest (u=0), we find it takes approximately 1.43 seconds for the load to attain a speed of 10 m/s when accelerating uniformly at 7 m/s².

Explanation:

The student wants to know the amount of time it takes for a load at point B to achieve a speed of 10 m/s, given that it starts from rest and accelerates uniformly at a rate of 7 m/s². This problem can be solved using one of the basic equations of motion, specifically, the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the load is starting from rest, u = 0. Hence, the equation becomes v = at. Substituting the given values (v = 10 m/s, a = 7 m/s²), we can solve for t = v / a, which gives t = 10 / 7 = 1.43 seconds. So, it will take approximately 1.43 seconds for the load to attain a speed of 10 m/s.

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A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the same spot and travels in a circle, the work the seat performs on her in one complete rotation is

Answers

Final answer:

In a circular motion with constant speed, such as a child on a merry-go-round, the work done over one complete rotation is zero, as there is no change in kinetic energy.

Explanation:

The question is regarding the concept of work done in a circular motion in the context of a merry-go-round. In the system described, the child has a constant speed on the circular path which indicates that the net work done by the forces acting on the child, including the seat, over a complete round of the merry-go-round is zero. This is consistent with the fact that work done is change in kinetic energy and since the child's speed is constant, there is no change in kinetic energy.

The child's inertia plays a role in maintaining her circular path but it does not contribute to work done, as it is a quantity of mass' resistance to change in motion and does not imply a force.

Learn more about Work Done in Circular Motion here:

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True or False A scientific theory generally is accepted as false until it is proved?

Answers

false it can not be proven or disproven

43.278 kg - 28.1 g use significant figures rule

Answers

You cannot directly subtract the given values because their units are different. To be consistent, let's convert kilograms to grams with the conversion that 1,000 g = 1 kg.

43.278 kg(1,000 g/1 kg) - 28.1 g = 43249.9 grams

In subtraction, you will base the number of significant figures to the least of the given data. Since 28.1 has 3 significant figures, the answer should also contain 3 significant figures. Thus, it is much more convenient to report it in terms of kilograms.

43249.9 grams * 1 kg/ 1,000 g = 43.2 kg

Jennifer works for an automaker and tests the safety performance of cars. She watches a 2,000-kilogram car crash into a wall with a force of 30,000 newtons. What’s the acceleration of the car at impact? Use .

Answers

15 m/s^2

For this problem, everything becomes clear once you look at the units involved. You have 2000 kg  and 30000 newtons and want to get acceleration.
First, express all the units in their most basic form.
kg, newton = kg*m/s^2, acceleration = m/s^2

So looking at kg, and kg*m/s^s, what math operation can be done to convert those 2 units into m/s^2?

You can't add or subtract since you're not allowed to mix units while adding or subtracting. You could try multiplying, but that would give you
kg * kg*m/s^2 = kg^2m/s^2
which isn't what you want to do. So it looks like you need to divide.
If you divide the kg by the kg*m/s^2, you'll get s^2/m which isn't correct either. But if you divide kg*m/s^2 by kg, the kilograms cancel out and you're left with m/s^2 which is exactly what you want. So do

30000 kg*m/s^2 / 2000 kg = 15 m/s^2.

Just remember to take a close look at the units of the numbers you're manipulating and perform the operations that will result in the correct units for the answer. I've caught myself making errors quite a few times in the past by doing that and getting nonsense units in the result telling me that I did the wrong thing. There's a good reason to use those units to help you.

Answer:

15 meters/second^2

Explanation:

I got this question on a test and this was the right answer

What potential difference is needed to accelerate a he+ ion (charge +e, mass 4u) from rest to a speed of 1.8×106 m/s ?

Answers

Final answer:

The potential difference needed to accelerate a He+ ion to a specific speed can be calculated using kinetic energy and charge, with the equation V = ½mv² / q, where m is the mass of the ion, v is the velocity, and q is the charge.

Explanation:

The student has asked what potential difference is needed to accelerate a He+ ion (charge +e, mass 4u) from rest to a speed of 1.8×106 m/s. The kinetic energy gained by the ion when it's accelerated through a potential difference (V) is equal to the charge of the ion (q) times the potential difference (V). Thus, we use the equation KE = qV and also know that KE can be expressed as ½mv2. Therefore, we can set these equations equal to solve for V:

V = ½mv2 / q

Where m is the mass of the He+ ion, v is the final velocity, and q is the charge of the ion. For He+ ion, q is +e, which is 1.602×10−19 C because it has one fewer electron than a normal helium atom. The mass of a He+ ion can be converted to kilograms by multiplying the atomic mass unit (u) with the conversion factor (1 u = 1.6605×10−27 kg), so for 4u, it would be 4×1.6605×10−27 kg.

Plugging these values into the equation, we can calculate the required potential difference to achieve the given speed.

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