An electron has an initial speed of 5.85 106 m/s in a uniform 5.55 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? s (d) What is the electron's speed when it returns to its starting point? m/s

Answer:

D. 230 N

Explanation:

The magnitude of the electric force between the two protons is given by:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

[tex]q_1 = q_2 = 1.6\cdot 10^{-19} C[/tex] is the charge of each proton

[tex]r=1\cdot 10^{-15} m[/tex] is the distance between the two protons

Substituting numbers into the formula, we find

[tex]F=(9\cdot 10^9 N m^2 C^{-2}) \frac{(1.6\cdot 10^{-19} C)^2}{(1\cdot 10^{-15} m^2)^2}=230.4 N \sim 230 N[/tex]

1 mol of oxygen molecules = 2 * 16 = 32 grams.

x mol of oxygen = 16 grams

1/x = 32/16    Cross multiply

16 = 32x        Divide by 32

16/32 = x

x = 1/2 mol

1 mol of anything has 6.02 * 10^23 somethings (molecules in this case).

1/2 mol = 6.02 *10^23 / 2

1/2 mol = 3.01 * 10^23 molecules <<<< answer  

Answer:

0.42

Explanation:

The force of friction exerted on the player is:

[tex]F_f = -\mu mg[/tex] (1)

where

[tex]\mu[/tex] is the coefficient of kinetic friction

m is the mass of the player

g is the acceleration due to gravity

According to Newton's second law,

[tex]F_f = ma[/tex] (2)

where a is the player's acceleration. Substituting (1) into (2),

[tex]a=-\mu g[/tex] (3)

So in order to find [tex]\mu[/tex], we need to find the acceleration. We know the following:

u = 3.5 m/s is the initial speed of the player

v = 0 is the final speed

d = 1.50 m is the distance travelled

So we can use the following equation

[tex]v^2-u^2 = 2ad[/tex]

and solving for a

[tex]a=\frac{v^2-u^2}{2d}=\frac{0-(3.5 m/s)^2}{2(1.50 m)}=-4.1 m/s^2[/tex]

Substituting this into (3), we find the coefficient of kinetic friction:

[tex]\mu = -\frac{a}{g}=-\frac{-4.1 m/s^2}{9.8 m/s^2}=0.42[/tex]

A force that acts among sliding parts is referred to as kinetic friction force. The coefficient of kinetic friction between him and the ground is 0.415.

A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion.

The size of the force will be determined by the kinetic friction coefficient between the two materials.

The given data in the problem is;

μ is the coefficient of kinetic friction=?

m is the mass of the player

g is the acceleration due to gravity= 9.81 m/s²

v is the speed of the player=3.5m/sec

x is the linear distance travelled=1.50 m

According to Newton's third equation of motion;

[tex]\rm v^2=u^2+2ax\\\\ \rm v^2-u^2=2ax\\\\ \rm a=\frac{ v^2-u^2}{2x} \\\\ \rm a=\frac{ 0^2-(3.5)^2}{2\times1.50}\\\\ \rm a=-4.08m/s^2[/tex]

The formula for the acceleration for the kinetic friction will be;

[tex]\rm a=\mu g \\\\ \rm \mu=\frac{a}{g} \\\\ \rm \mu=\frac{-4.08}{9*.81}\\\\ \rm \mu=0.415[/tex]

Hence the coefficient of kinetic friction between him and the ground is 0.415.

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Irregular galaxies get their odd shapes in many ways. One way irregular galaxies are formed is when galaxies collide or come close to one another, and their gravitational forces interact. Another source of irregular galaxies may be very young galaxies that have not yet reached a symmetrical state.

When galaxy's collide or close close to one another or the galaxy may be very young and haven't reached a symmetrical state

Answer:

[tex]2.6 ^{\circ}C[/tex]

Explanation:

First of all, we need to calculate the penny's kinetic energy before hitting the ground. This is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where m = 5.25 g = 0.00525 kg is the penny's mass and v = 3.27 m/s is its speed. Substituting,

[tex]K=\frac{1}{2}(0.00525 kg)(3.27 m/s)^2=0.028 J[/tex]

When the penny hits the ground, all this energy is converted into internal energy of the penny and the ground. If only half is converted into penny's internal energy, its increase in internal energy is

[tex]\Delta U= \frac{0.028 J}{2}=0.014 J[/tex]

And its formula is

[tex]\Delta U=m C_s \Delta T[/tex]

where m is the penny's mass, Cs its specific heat capacity (2.03 J/gC) and [tex]\Delta T[/tex] the increase in temperature. Solving for the last term,

[tex]\Delta T=\frac{\Delta U}{m C_s}=\frac{0.028 J}{(0.00525 kg)(2.03 J/gC)}=2.6 ^{\circ}C[/tex]

A wheelbarrow is a 2nd class lever. Your hands on the handles give the effort. The load inside the wheelbarrow is the resistance. The wheel is the fulcrum. When you lift up the handles, the load goes up in the same direction.

A wheelbarrow exemplifies a second-class lever, where the load is between the fulcrum (wheel's axle) and the input force, enabling the lifting of heavier loads through mechanical advantage.

A wheelbarrow is an example of a second-class lever. In this type of lever, the load is situated between the fulcrum and the effort force. A wheelbarrow enables the user to lift heavier loads more easily due to the arrangement of the forces involved.

A wheelbarrow is an example of a second-class lever. In this type of lever, the output force or load is located between the fulcrum (pivot point) and the input force. The fulcrum in the case of a wheelbarrow is the wheel's axle. This arrangement allows the wheelbarrow to lift heavier loads than one could manually, due to the mechanical advantage achieved by the lever's design. A key characteristic of second-class levers is that both the input and output forces are on the same side of the fulcrum, making tasks like lifting and carrying heavy materials more manageable. This principle underscores the effectiveness of simple machines in amplifying human effort to accomplish tasks more efficiently.

option B open system

because in open system energy and mass can escape from the system or can be added to it.

(a) [tex]4.26\cdot 10^5 V/m[/tex]

In a velocity selector, the speed of the beam is related to the magnitude of the electric field and of the magnetic field by the formula:

[tex]v=\frac{E}{B}[/tex]

where

E is the magnitude of the electric field

B is the magnitude of the magnetic field

In this problem, we have

[tex]B=0.115 T[/tex] (magnetic field)

[tex]v=3.7\cdot 10^6 m/s[/tex] (speed of the particles)

Solving the equation for E, we find the electric field:

[tex]E=vB=(3.7\cdot 10^6 m/s)(0.115 T)=4.26\cdot 10^5 V/m[/tex]

(b) 3.2 kV

The relationship between electric field and potential difference between the two plates is:

[tex]V=Ed[/tex]

where, in this problem:

[tex]E=4.26\cdot 10^5 V/m[/tex] is the magnitude of the electric field

[tex]d=0.75 cm=0.0075 m[/tex] is the separation between the plates

Substituting into the equation, we find the potential difference:

[tex]V=(4.26\cdot 10^5 V/m)(0.0075 m)=3195 V=3.2 kV[/tex]

To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.

To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.

Answer:

To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.

To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.

Answer:

The Biot-Savart law

Explanation:

Answer:

The Biot-Savart law

Explanation:

Answer:

2639 N

Explanation:

The impulse on the baseball is given by:

[tex]I=F \Delta t[/tex] (1)

where F is the force exerted on the ball and [tex]\Delta t[/tex] the contact time between the bat and the ball.

The impulse is also equal to the change in momentum of the ball:

[tex]I=\Delta p = m (v-u)[/tex] (2)

where m is the ball's mass, v is its final velocity, u is its initial velocity.

By using (1) and (2) simultaneously we can write an expression for F, the force exerted on the ball:

[tex]F=\frac{m(v-u)}{\Delta t}[/tex]

where:

m = 0.145 kg

u = 35.0 m/s

v = -56.0 m/s

[tex]\Delta t=5.00 \cdot 10^{-3}s[/tex]

Substituting,

[tex]F=\frac{(0.145 kg)((-56.0 m/s)-35.0 m/s)}{5.00\cdot 10^{-3} s}=-2639 N[/tex]

and the negative sign means that the force is simply in the opposite direction to the ball's initial direction.

A) [tex]2.4\cdot 10^{-6} J[/tex]

The energy stored in a capacitor is given by:

[tex]E=\frac{1}{2}\frac{Q^2}{C}[/tex]

where

Q is the charge stored

C is the capacitance

The capacitance of a parallel-plate capacitor is

[tex]C=\frac{\epsilon_0 A}{d}[/tex]

where

[tex]\epsilon_0 = 8.85\cdot 10^{-12} F/m[/tex] is the vacuum permittivity

[tex]A=6.0 cm \cdot 6.0 cm=36.0 cm^2=36\cdot 10^{-4} m^2[/tex] is the area of each plate

[tex]d=1.5 mm=0.0015 m[/tex] is the distance between the plates

Substituting,

[tex]C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0015 m}=2.1\cdot 10^{-11} F[/tex]

The charge stored on the capacitor is

[tex]Q=10 nC=10\cdot 10^{-9}C[/tex]

So, the energy stored is

[tex]E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{2.1\cdot 10^{-11} F}=2.4\cdot 10^{-6}J[/tex]

B) [tex]2.6\cdot 10^{-6}J[/tex]

This time, the separation between the plates is

d = 1.7 mm = 0.0017 m

So, the new capacitance is

[tex]C=\frac{(8.85\cdot 10^{-12} F/m)(36\cdot 10^{-4} m^2)}{0.0017 m}=1.9\cdot 10^{-11} F[/tex]

And so, the new energy stored is

[tex]E=\frac{1}{2}\frac{(10\cdot 10^{-9}C)^2}{1.9\cdot 10^{-11} F}=2.6\cdot 10^{-6}J[/tex]

C)

Energy must be conserved, so the difference between the initial energy of the capacitor and its final energy is just equal to the work done to increase the separation between the two plates from 1.5 mm to 1.7 mm (in fact, the two plates of the capacitor attract each other since they have opposite charge, so work must be done in order to increase their separation)

Final answer:

The energy stored in the capacitor initially is 2.355 × 10−9 J. After increasing the plate separation, the energy stored becomes 2.674 × 10−9 J. The difference in energy is accounted for by the work done to separate the plates, which adds to the electric potential energy.

Explanation:

Part A: Energy Stored in the Capacitor

The energy stored in a capacitor can be calculated using the formula:

U = ½ QV

where U is the stored energy, Q is the charge, and V is the potential difference across the capacitor plates. To find V, we need to use the capacitance C, which is given by:

C = ε0 (A/d)

where ε0 is the permittivity of free space (ε0 = 8.85 × 10−12 F/m), A is the area of one of the plates, and d is the separation between the plates. Substituting the values, we find:

C = 8.85 × 10−12 F/m · (0.06 m × 0.06 m) / 0.0015 m

C = 2.124 × 10−9 F

The potential difference V is found using:

V = Q/C

V = 10 × 10−9 C / 2.124 × 10−9 F

V = 4.71 V

Substituting back into the energy formula, we get:

U = ½ × 10 × 10−9 C × 4.71 V

U = 2.355 × 10−9 J

Part B: Energy Stored After Increasing Plate Separation

When the plate separation is increased, the capacitance C changes, which affects the stored energy, but the charge Q remains the same as the capacitor was disconnected from the battery. We recalculate C with the new distance:

C' = 8.85 × 10−12 F/m · (0.06 m × 0.06 m) / 0.0017 m

C' = 1.870 × 10−9 F

The stored energy now is:

U' = ½ × 10 × 10−9 C × (10 × 10−9 C / 1.870 × 10−9 F)

U' = 2.674 × 10−9 J

Part C: Accounting for Energy Difference

Since energy must be conserved, the work done to separate the plates must be accounted for. The increase in energy observed is the mechanical work done to pull the plates apart against the attractive force between them. This work is converted into additional electric potential energy stored in the capacitor as it has a larger separation and hence an increased potential difference.

Answer:

255.4 N/m

Explanation:

We can consider the system eyeball-attached to the musculature as a mass-spring system in simple harmonic motion, whose frequency of oscillation is given by

[tex]f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}[/tex]

where in this case, we know:

f = 29 Hz is the frequency of oscillation

k is the spring constant, which is unknown

m = 7.7 g = 0.0077 kg is the mass of the eyeball

Solving the equation for k, we find the spring constant of the musculature attached to the eyeball:

[tex]k=(2\pi f)^2 m=(2 \pi (29 Hz))^2 (0.0077 kg)=255.4 N/m[/tex]

To find the effective spring constant of the musculature attached to the eyeball, use the formula k = (4π²m)/(frequency²)

To determine the effective spring constant of the musculature attached to the eyeball, we can use the formula for the resonant frequency of a mass-spring system:

frequency = 1 / (2π√(m/k))

where m is the mass of the eyeball and k is the spring constant. Rearranging the formula, we can solve for k:

k = (4π2m)/(frequency2)

Plugging in the values, we have m = 7.7 g and frequency = 29 Hz:

k = (4π2(7.7 g))/(29 Hz)2

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Answer:

[tex]R_3 < R_1 < R_2[/tex]

Explanation:

The resistance of a wire is given by:

[tex]R=\frac{\rho L}{A}[/tex]

where

[tex]\rho[/tex] is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

1) The first wire has length L and cross-sectional area A. So, its resistance is:

[tex]R_1=\frac{\rho L}{A}[/tex]

2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is

[tex]R_2=\frac{2\rho L}{A}[/tex]

3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is

[tex]R_3=\frac{\rho L}{2A}[/tex]

By comparing the three expressions, we find

[tex]R_3 < R_1 < R_2[/tex]

So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).

Answer:

[tex]4.7\cdot 10^6 Pa[/tex]

Explanation:

The total force exerted by the man on the chair is equal to his weight:

[tex]F=W=mg[/tex]

where m=95.0 kg is the man's mass and g=9.8 m/s^2. Substituting,

[tex]F=(95.0 kg)(9.8 m/s^2)=931 N[/tex]

Since there are 4 legs, we can assume that the force is equally distributed over the 4 legs; so the force supported by each leg is

[tex]F=\frac{931 N}{4}=232.8 N[/tex]

The radius of each leg is [tex]r=0.400 cm=0.004 m^2[/tex], so the area of each leg is

[tex]A=\pi r^2 = \pi (0.004 m)^2=5\cdot 10^{-5} m^2[/tex]

And the pressure exerted on each leg is equal to the ratio between the force supported by each leg and the area:

[tex]p=\frac{F}{A}=\frac{232.8 N}{5\cdot 10^{-5} m^2}=4.7\cdot 10^6 Pa[/tex]

The pressure on each leg is 4655kNm-2.

The term pressure is defined as the ratio of force per unit area. Firts we have to find the force acting on the chair and the area covered by the force.

The force acting on the ground is the weight of the man and the chair.

F = W = mg = 95.0 kg * 9.8 ms-2 = 931 N.

Since this force is evenly distributed, the force on each leg = 931/4 = 232.75 N

The area of each leg = πr^2 = 3.142 * (0.4 * 10^-2)^2 = 5 * 10^-5 m^2

Pressure = force/area = 232.75 N/ 5 * 10^-5 m^2 = 4655kNm-2

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(a) 392 N/m

Hook's law states that:

[tex]F=k\Delta x[/tex] (1)

where

F is the force exerted on the spring

k is the spring constant

[tex]\Delta x[/tex] is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

[tex]F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N[/tex]

- The stretching of the spring is

[tex]\Delta x=15 cm-10 cm=5 cm=0.05 m[/tex]

Solving eq.(1) for k, we find the spring constant:

[tex]k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m[/tex]

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

[tex]F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N[/tex]

And so, the stretch of the spring is

[tex]\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm[/tex]

And since the initial lenght of the spring is

[tex]x_0 = 10 cm[/tex]

The final length will be

[tex]x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm[/tex]

(a) The spring constant of the spring is 392 N/m

(b) Length of the spring is 17.5 cm

[tex]\texttt{ }[/tex]

Hooke's Law states that the length of a spring is directly proportional to the force acting on the spring.

[tex]\boxed {F = k \times \Delta x}[/tex]

F = Force ( N )

k = Spring Constant ( N/m )

Δx = Extension ( m )

[tex]\texttt{ }[/tex]

The formula for finding Young's Modulus is as follows:

[tex]\boxed {E = \frac{F / A}{\Delta x / x_o}}[/tex]

E = Young's Modulus ( N/m² )

F = Force ( N )

A = Cross-Sectional Area ( m² )

Δx = Extension ( m )

x = Initial Length ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial length of spring = Lo = 10 cm

mass of object = m = 2.0 kg

extension of the spring = x = 15 - 10 = 5 cm = 0.05 m

mass of second object = m' = 3.0 kg

Asked:

a. spring constant of the spring = k = ?

b. length of spring = L = ?

Solution:

[tex]F = kx[/tex]

[tex]mg = kx[/tex]

[tex]k = mg \div x[/tex]

[tex]k = 2.0 ( 9.8 ) \div 0.05[/tex]

[tex]\boxed {k = 392 \texttt{ N/m}}[/tex]

[tex]\texttt{ }[/tex]

[tex]F' = kx'[/tex]

[tex]m' g = k x'[/tex]

[tex]x' = ( m' g ) \div k[/tex]

[tex]x' = ( 3.0 (9.8) ) \div 392[/tex]

[tex]x' = 0.075 \texttt{ m} = 7.5 \texttt{ cm}[/tex]

[tex]\texttt{ }[/tex]

[tex]L = Lo + x'[/tex]

[tex]L = 10 + 7.5[/tex]

[tex]\boxed {L = 17.5 \texttt{ cm}}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: College

Subject: Physics

Chapter: Elasticity

To calculate the electromagnetic energy contained in a given space just above the Earth's surface, multiply the intensity of the sunlight by the volume of the space. In this case, the energy is 8.40 × 10^3 W.

The electromagnetic energy contained in a given space can be calculated by multiplying the intensity of the sunlight by the volume of the space.

Given that the intensity of sunlight is 1.40 × 10^3 W/m² and the volume of the space is 6.00 m³, we can calculate the electromagnetic energy as follows:

Energy = Intensity × Volume

Energy = (1.40 × 10^3 W/m²) × (6.00 m³)

Energy = 8.40 × 10^3 W

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Answer:

D) Erosion and Weathering

Explanation:

Erosion forces rocks to crash together or crack apart, some rocks shatter and crumble, while others are worn away.

During erosion, exfoliation which is a type of weathering occurs in sheets along joints/ lines which runs throughout Stone Mountain. Once a sheet on the surface has been exfoliated and the sheet of rock beneath it is exposed the process begins again. This process gradually changes the way Stone Mountain looks.

A force is a vector quantity. As learned in an earlier unit, a vector quantity is a quantity that has both magnitude and direction. To fully describe the force acting upon an object, you must describe both the magnitude (size or numerical value) and the direction.

The kinetic energy of an electron accelerated through a 10 kV potential difference is 10,000 eV, with 1 eV being the energy given to a charge accelerated through 1 V.

The kinetic energy of an electron accelerated through a potential difference is directly related to the voltage it is accelerated through. If an electron is accelerated through a potential difference of 10 kV (10,000 V), then it will be given an energy of 10,000 eV since 1 eV is defined as the energy given to a fundamental charge accelerated through 1 V. Therefore, the kinetic energy of the electron in your case is 10,000 eV.

In this scenario, the potential difference represents the energy gained by the electron as it moves through the electric field. The kinetic energy is given by the product of the elementary charge and the potential difference. This is based on the fundamental relationship in electrostatics that the work done (and therefore the energy gained) by a charged particle moving through an electric field is equal to the product of the charge and the potential difference.

The agent made it since the range of his motion is greater than the width of the gorge.

The given parameters;

Assume downward motion to be negative.

The initial vertical component of the velocity in m/s;

[tex]v_0_y = v_0 \times sin(30)\\\\v_o_y = - 55 \ km/h \times sin(30) = -27.5 \ km/h = -7.64 \ m/s[/tex]

Determine the final vertical velocity of the agent;

[tex]v_y_f^2 = v_0_y^2 - 2gh\\\\v_y_f^2 = (-7.64)^2 - 2(9.8)(-100)\\\\v_y_f^2 = 2018.37\\\\v_y_f = \sqrt{2018.37} \\\\v_y_f = -44.93 \ m/s[/tex]

Determine the time of motion;

[tex]v_y_f = v_0y - gt\\\\-44.93 = -7.64 - 9.8t\\\\9.8t = 44.93 - 7.64\\\\9.8t = 37.29\\\\t = \frac{37.29}{9.8} = 3.81 \ s[/tex]

Determine the horizontal component of the initial velocity;

[tex]v_0_x = v_0 \times cos(\theta)\\\\v_0_x = 55 \ km/h \times cos(30) = 47.63 \ km/h = 13.2 \ m/s[/tex]

Determine the range of the of the agent's motion;

[tex]X = v_0_x \times t\\\\X = 13.2\ m/s \times 3.81 \ s\\\\X = 50.3 \ m[/tex]

Thus, the agent made it since the range of his motion is greater than the width of the gorge.

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Using the principles of projectile motion, we can determine that the secret agent will be able to clear the gorge and make it safely across. The agent's horizontal distance covered is 76.09 m, which is greater than the width of the gorge (43 m).

To determine if the secret agent can make it across the gorge, we need to analyze his motion using the principles of projectile motion. Since the slope is inclined at 30° below the horizontal, we can break down the velocity into horizontal and vertical components. The horizontal component remains constant, while the vertical component changes due to the acceleration due to gravity. We can use the kinematic equations to determine the time it takes for the agent to reach the other side of the gorge. If the time is less than the time it takes for the agent to fall vertically, then he will clear the gorge and land safely on the snow.

Given that the agent skis off the slope at a speed of 55 km/h, we first need to convert this to m/s. 55 km/h is equal to 15.28 m/s. The horizontal component of the velocity remains constant at 15.28 m/s. We can determine the vertical component by multiplying the speed by the sine of the angle (30°). The vertical component is therefore 7.64 m/s. Using the equation d = v*t + 0.5*a*t^2, we can solve for time using the vertical component and the vertical distance of 100 m. Plugging in the values, we get:

100 = 7.64*t + 0.5*(-9.8)*t^2

This equation simplifies to:

4.9*t^2 + 7.64*t - 100 = 0

Solving for t, we find two possible values, t = -4.22 s and t = 4.98 s. Since time cannot be negative, we discard the negative value, leaving us with t = 4.98 s. Now we need to determine the horizontal distance the agent will travel during this time. We can use the equation d = v*t, plugging in the horizontal velocity and time:

d = 15.28 m/s * 4.98 s = 76.09 m

The horizontal distance covered by the agent is 76.09 m. Since the gorge is 43 m wide, the agent will be able to clear the gorge and make it across safely. Therefore, the secret agent does make it across the gorge.

Pressure = (total force) / (Area)

10,000 Pa = (1,000 N) / (Area)

Multiply each side by (Area) :

(10,000 Pa) x (Area) = 1,000 N

Divide each side by (10,000 Pa) :

Area = (1,000 N) / (10,000 Pa)

Area = 0.1 m²

The area is in contact with the ground if A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N is 10 m².

In the physical sciences, pressure is defined as the stress at a point within a confined fluid or the perpendicular force per unit area. A 42-pound box with a bottom area of 84 square inches will impose pressure on a surface equal to the force divided by the area it is applied to, or half a pound per square inch.

Given:

The pressure exerts on the box, P = 10000 Pa

The weight of the box, F = 1000 N,

Calculate the area of contact with the ground by the formula given below,

[tex]P = F/A[/tex]

Substitute the values,

10000 = 1000 / A

A = 10 m²

Therefore, The area is in contact with the ground if A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N is 10 m².

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(a) 8927 mi/h

In order to calculate the average speed, we need to convert the time (t=5.0 y) into hours first. In 1 year, we have 365 days, each day consisting of 24 hours, so the time taken is:

[tex]t=(5.0 y)(365 d/y)(24 h/d)=43,800 h[/tex]

The distance covered by the spacecraft is

[tex]d=391 mil. mi = 391\cdot 10^6 mi[/tex]

Therefore, the average speed is just the ratio between the distance covered and the time taken:

[tex]v=\frac{d}{t}=\frac{391\cdot 10^6 mi}{43,800 h}=8,927 mi/h[/tex]

(b) 35 minutes (2097 seconds)

The transmitted signals (which is a radio wave, which is an electromagnetic wave) travels back to the Earth at the speed of light:

[tex]c=3.0\cdot 10^8 m/s[/tex]

Since 1 miles = 1609 metres, the distance covered  by the signal is

[tex]d=391\cdot 10^6 mi \cdot (1609 m/mi)=6.29\cdot 10^{11} m[/tex]

So, the time taken by the signal will be

[tex]t=\frac{d}{v}=\frac{6.29\cdot 10^{11} m}{3.0\cdot 10^8 m/s}=2097 s[/tex]

And since 1 minute = 60 sec, the time taken is

[tex]t=2097 s \cdot \frac{1}{60 s/min}\sim 35 min[/tex]

The Juno spacecraft averaged a speed of approximately 8,923 miles per hour on its trip from Earth to Jupiter. When Earth and Jupiter are closest, signals from Juno take around 35 minutes to reach Earth, with calculations based on the speed of light.

The average speed of the Juno spacecraft can be calculated by dividing the total distance traveled by the total time taken. Given that Juno traveled 391 million miles over 5 years to reach Jupiter, we first convert the time to hours (5 years = 43,800 hours if you consider a year to be 365 days) before making this calculation. Therefore, the average speed of Juno is 391,000,000 miles / 43,800 hours = approximately 8,923 miles per hour.

For part (b) of your question, the minimum time it takes for the signals from Juno to reach Earth is determined by the speed of light, which is approximately 186,282 miles per second. Thus, by dividing the smallest distance between Jupiter and Earth (391 million miles) by the speed of light, we find it takes signals around 35 minutes to travel from Juno to Earth when the two planets are closest together.

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Answer:

If an object changes speed or  direction, its velocity also changes. Any change in  velocity results in acceleration.

If an object changes speed or direction , its velocity also changes. Any change in results velocity in acceleration.

What are the term velocity and direction means and related?

Direction and Velocity are the two missing words in the sentence.

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Answer;

30.6 m

Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

thus;

S =1/2(gt²)

  = 0.5 × 9.81 × 2.5 ²

  = 30.65

  ≈ 30.6 m

The advancements in television and communication technologies during the 1950s and 1960s revolutionized entertainment, news consumption, and long-distance communication by the creation of a shared experience and offering better and cheaper services.

One of the major results of technological advancements like television and satellites revolutionizing life in the 1950s and 1960s was a transformation in modes of communication and entertainment. With the accessibility and popularity of television soaring during this period, there was a shift in the way people consumed news, entertainment and information. In the early 1950's, only around 9 percent of U.S households had a TV which rocketed to approximately 65 percent in just five years. This widespread distribution of television sets played an instrumental role in uniting people through shared experiences whether it was news broadcasts or popular TV shows. A sense of a national, and even global, community was formed through these shared experiences in real-time.

Another crucial impact was the innovations in communication technologies such as microwave transmission and satellites, allowing phone calls to be made in a wireless mode. More affordable and superior quality telephonic communication, especially for long-distance calls, was facilitated. Therefore, the technology of this era not only influenced entertainment and news consumption but also significantly improved communication.

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Answer:

KE = 0.16 J

Explanation:

As we know that total energy is always remains conserved

so here we can say that initial potential energy stored in the spring is equal to the kinetic energy of the object when it comes to relaxed state

So here we have

[tex]U = \frac{1}{2}kx^2[/tex]

here we know that

[tex]k = 125 N/m[/tex]

x = 0.05 m

now from above equation

[tex]U = \frac{1}{2}(125)(0.05)^2[/tex]

[tex]U = 0.16 J[/tex]

so total potential energy here is same as the final kinetic energy which is 0.16 J

Answer:

-4n

Explanation:

Answer:

B

Explanation

Evolution

➷ A normal atom has the same amount of electrons and protons, making it neutral. An atom develops a positive charge when it loses an electron(s). Once it loses an electron(s), there would now be more protons that electrons.

Short answer: by losing an electron(s)

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